Day 3 ­ Absolute Value


 Absolute Value:




     | 3 | = ______             | ­ 3 | = _______


 Now, in reverse...

    | x | = 3         ­5   ­4    ­3   ­2   ­1   0   1   2   3   4   5




                                                                        1
Ex 1:   2| x | ­ 4  = 10


1st   Isolate Absolute 
      Value Expression

2nd   Split into two 
      different equations

3rd   Solve each 
      equation separately

4th   Check both solutions **




                                                           2
Ex 2:   ½| x + 4 |  = x
1st   Isolate Absolute 
      Value Expression


2nd   Split into two 
      different equations

3rd   Solve each 
      equation separately

4th   Check both solutions **




                                                          3
Ex 3:   | x + 8 |  + 4 = 3x

 1st   Isolate Absolute 
       Value Expression

2nd   Split into two 
      different equations

3rd   Solve each 
      equation separately

4th   Check both solutions **




                                                              4
1.   |­3x| = 27            ­9, 9

    2.   5 |x + 1| + 6 = 21        ­4, 2

       3.    |x | + 3 = 2x             3 
      4.   |6x + 7| ­ 2 = 5x    no solution


5.   |3 x + 5| ­ 2x = 3x + 4      ½ 

  6.   2 |x + 3| ­ 4x = 12        ­ 3 




                                               5

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Algebra 2 Notes 1-3

  • 1. Day 3 ­ Absolute Value Absolute Value: | 3 | = ______ | ­ 3 | = _______ Now, in reverse... | x | = 3 ­5 ­4 ­3 ­2 ­1 0 1 2 3 4 5 1
  • 2. Ex 1: 2| x | ­ 4  = 10 1st   Isolate Absolute  Value Expression 2nd   Split into two  different equations 3rd   Solve each  equation separately 4th   Check both solutions ** 2
  • 3. Ex 2: ½| x + 4 |  = x 1st   Isolate Absolute  Value Expression 2nd   Split into two  different equations 3rd   Solve each  equation separately 4th   Check both solutions ** 3
  • 4. Ex 3: | x + 8 |  + 4 = 3x 1st   Isolate Absolute  Value Expression 2nd   Split into two  different equations 3rd   Solve each  equation separately 4th   Check both solutions ** 4
  • 5. 1.   |­3x| = 27 ­9, 9 2.   5 |x + 1| + 6 = 21 ­4, 2 3.    |x | + 3 = 2x 3  4.   |6x + 7| ­ 2 = 5x no solution 5.   |3 x + 5| ­ 2x = 3x + 4    ½  6.   2 |x + 3| ­ 4x = 12 ­ 3  5