Assignment Submission Assignment, you submit answers by question by .pdf
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The document describes the assignment submission process, detailing how to submit answers to complex number questions. It provides specific examples of converting complex numbers between rectangular and polar forms, along with the necessary calculations. The content emphasizes the scoring mechanism based on submitted answers.
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![Assignment Submission Assignment, you submit answers by question by question parts. The
number of submissions remaining for each question part only changes if you submit or change
the answer. Assignment Scoring Assignment submission is used for your score. The complex
number z = -1 + i in polar form is z =. The complex number z = 2(cos(pi/6) + i sin(pi/6)) in
rectangular form is z = ___________. The complex number graphed below can be expressed in
rectangular form as z = or in polar form as z = _________.
Solution
a)given z =-1+ 1i
r =[(-1)2+12]
r=2
=tan-1(1/-1)
=-tan-1(1/1)
=-(/4)
=(3/4)
z=2 [cos(3/4) +i sin(3/4)]
====================================
b)z=2 [cos(/6) +i sin(/6)]
z=2 [(3 /2) +i(1/2)]
z=3 +i1
z=3 +i
c) z =(1+ 1i)
z=2 [cos(/4) +i sin(/4)]](https://image.slidesharecdn.com/assignmentsubmissionassignmentyousubmitanswersbyquestionby-230703010525-ce9590e9/85/Assignment-Submission-Assignment-you-submit-answers-by-question-by-pdf-1-320.jpg)
Assignment Submission Assignment, you submit answers by question by .pdf
- 1. Assignment Submission Assignment, you submit answers by question by question parts. The number of submissions remaining for each question part only changes if you submit or change the answer. Assignment Scoring Assignment submission is used for your score. The complex number z = -1 + i in polar form is z =. The complex number z = 2(cos(pi/6) + i sin(pi/6)) in rectangular form is z = ___________. The complex number graphed below can be expressed in rectangular form as z = or in polar form as z = _________. Solution a)given z =-1+ 1i r =[(-1)2+12] r=2 =tan-1(1/-1) =-tan-1(1/1) =-(/4) =(3/4) z=2 [cos(3/4) +i sin(3/4)] ==================================== b)z=2 [cos(/6) +i sin(/6)] z=2 [(3 /2) +i(1/2)] z=3 +i1 z=3 +i c) z =(1+ 1i) z=2 [cos(/4) +i sin(/4)]