Bca 2nd sem-u-1.2 digital logic circuits, digital component

Digital Logic Circuits, Digital
Component and Data
Representation
Course: BCA-2nd Sem
Subject: Computer Organization
And Architecture
Unit-1
1

What is Computer Organization?[1]
… a very wide semantic gap between the intended behavior and the workings of
the underlying electronic devices that will actually do all the work.
The forerunners to modern computers attempted to assemble the raw devices
(mechanical, electrical, or electronic) into a separate purpose-built machine for
each desired behavior.
Electronic
Devices
Desired
Behavior

Role of General Purpose Computers[1]
A general purpose computer is like an island that helps
span the gap between the desired behavior (application)
and the basic building blocks (electronic devices).
Electronic
Devices
Desired
Behavior
General
Purpose
Computer
computer
organization
software

Computer Architecture - Definition
• Computer Architecture = ISA + MO
• Instruction Set Architecture
– What the executable can “see” as underlying hardware
– Logical View
• Machine Organization
– How the hardware implements ISA ?
– Physical View

Impact of changing ISA
• Early 1990’s Apple switched instruction set
architecture of the Macintosh
– From Motorola 68000-based machines
– To PowerPC architecture
• Intel 80x86 Family: many implementations of
same architecture
– program written in 1978 for 8086 can be run on
latest Pentium chip

Factors affecting ISA ???
Computer
Architecture
Technology Programming
Languages
Operating
Systems
History
Applications

ISA: Critical Interface
instruction set
software
hardware
Examples: 80x86 50,000,000 vs. MIPS 5500,000 ???

Designing Computers
• All computers more or less based on the same
basic design, the Von Neumann Architecture!

The Von Neumann Architecture
• Model for designing and building computers,
based on the following three characteristics:
1) The computer consists of four main sub-systems:
• Memory
• ALU (Arithmetic/Logic Unit)
• Control Unit
• Input / Output System (I/O)
2) Program is stored in memory during execution.
3) Program instructions are executed sequentially.

The Von Neumann
Architecture[1]
Memory
Processor (CPU)
Input-Output
Control Unit
ALU
Store data and program
Execute program
Do arithmetic/logic operations
requested by program
Communicate with
"outside world", e.g.
• Screen
• Keyboard
• Storage devices
• ...
Bus

Bca 2nd sem-u-1.2 digital logic circuits, digital component

Memory Subsystem
• Memory, also called RAM (Random Access
Memory),
– Consists of many memory cells (storage units) of a fixed
size.
Each cell has an address associated with it: 0, 1, …
– All accesses to memory are to a specified address.
A cell is the minimum unit of access (fetch/store a complete
cell).
– The time it takes to fetch/store a cell is the same for all cells.
• When the computer is running, both
– Program
– Data (variables)
are stored in the memory.

14
RAM[1]
• Need to distinguish between
– the address of a memory cell and
the content of a memory cell
• Memory width (W):
– How many bits is each memory
cell, typically one byte (=8 bits)
• Address width (N):
– How many bits used to represent
each address, determines the
maximum memory size = address
space
– If address width is N-bits, then
address space is 2N (0,1,...,2N-1)
...
0
1
2
2N-1
1 bit
W
0000000000000001
N
2N

Memory Size / Speed
• Typical memory in a personal computer (PC):
– 64MB - 256MB
• Memory sizes:
– Kilobyte (KB) = 210 = 1,024 bytes ~ 1
thousand
– Megabyte(MB) = 220 = 1,048,576 bytes ~ 1
million
– Gigabyte (GB) = 230 = 1,073,741,824
bytes ~ 1 billion
• Memory Access Time (read from/ write to memory)
– 50-75 nanoseconds (1 nsec. = 0.000000001 sec.)
• RAM is
– volatile (can only store when power is on)
– relatively expensive

Operations on Memory
• Fetch (address):
– Fetch a copy of the content of memory cell with the specified
address.
– Non-destructive, copies value in memory cell.
• Store (address, value):
– Store the specified value into the memory cell specified by
address.
– Destructive, overwrites the previous value of the memory cell.
• The memory system is interfaced via:
– Memory Address Register (MAR)
– Memory Data Register (MDR)
– Fetch/Store signal

Structure of the Memory
Subsystem[2]
• Fetch(address)
– Load address into MAR.
– Decode the address in MAR.
– Copy the content of memory cell
with specified address into MDR.
• Store(address, value)
– Load the address into MAR.
– Load the value into MDR.
– Decode the address in MAR
– Copy the content of MDR into
memory cell with the specified
address.

Input / Output Subsystem
• Handles devices that allow the computer system
to:
– Communicate and interact with the outside world
•Screen, keyboard, printer, ...
– Store information (mass-storage)
•Hard-drives, floppies, CD, tapes, …
• Mass-Storage Device Access Methods:
– Direct Access Storage Devices (DASDs)
•Hard-drives, floppy-disks, CD-ROMs, ...
– Sequential Access Storage Devices (SASDs)
•Tapes (for example, used as backup devices)

I/O Controllers
• Speed of I/O devices is slow compared to
RAM
– RAM ~ 50 nsec.
– Hard-Drive ~ 10msec. = (10,000,000 nsec)
• Solution:
– I/O Controller, a special purpose processor:
•Has a small memory buffer, and a control logic to control
I/O device (e.g. move disk arm).
•Sends an interrupt signal to CPU when done read/write.
– Data transferred between RAM and memory buffer.
– Processor free to do something else while I/O
controller reads/writes data from/to device into I/O
buffer.

Structure of the I/O Subsystem[2]

The ALU Subsystem
• The ALU (Arithmetic/Logic Unit) performs
– mathematical operations (+, -, x, /, …)
– logic operations (=, <, >, and, or, not, ...)
• In today's computers integrated into the CPU
• Consists of:
– Circuits to do the arithmetic/logic operations.
– Registers (fast storage units) to store intermediate
computational results.
– Bus that connects the two.

Structure of the ALU[2]
• Registers:
– Very fast local memory cells, that
store operands of operations and
intermediate results.
– CCR (condition code register), a
special purpose register that stores
the result of <, = , > operations
• ALU circuitry:
– Contains an array of circuits to do
mathematical/logic operations.
• Bus:
– Data path interconnecting the
registers to the ALU circuitry.

The Control Unit
• Program is stored in memory
– as machine language instructions, in binary
• The task of the control unit is to execute
programs by repeatedly:
– Fetch from memory the next instruction to be
executed.
– Decode it, that is, determine what is to be done.
– Execute it by issuing the appropriate signals to
the ALU, memory, and I/O subsystems.
– Continues until the HALT instruction

Machine Language Instructions
• A machine language instruction consists of:
– Operation code, telling which operation to
perform
– Address field(s), telling the memory addresses
of the values on which the operation works.
• Example: ADD X, Y (Add content of memory
locations X and Y, and store back in memory location Y).
• Assume: opcode for ADD is 9, and addresses X=99,
Y=100
00001001 0000000001100011 0000000001100100
Opcode (8 bits) Address 1 (16 bits) Address 2 (16 bits)

Instruction Set Design
• Two different approaches:
– Reduced Instruction Set Computers (RISC)
•Instruction set as small and simple as possible.
•Minimizes amount of circuitry --> faster computers
– Complex Instruction Set Computers (CISC)
•More instructions, many very complex
•Each instruction can do more work, but require more
circuitry.

Typical Machine Instructions
• Notation:
– We use X, Y, Z to denote RAM cells
– Assume only one register R (for simplicity)
– Use English-like descriptions (should be binary)
• Data Transfer Instructions
– LOAD X Load content of memory location X to R
– STORE X Load content of R to memory location X
– MOVE X, Y Copy content of memory location
X to loc. Y (not absolutely necessary)

Machine Instructions (cont.)
• Arithmetic
– ADD X, Y, Z CON(Z) = CON(X) + CON(Y)
– ADD X, Y CON(Y) = CON(X) + CON(Y)
– ADD X R = CON(X) + R
– similar instructions for other operators, e.g. SUBTR,OR,
...
• Compare
– COMPARE X, Y
Compare the content of memory cell X to the content of
memory cell Y and set the condition codes (CCR)
accordingly.
– E.g. If CON(X) = R then set EQ=1, GT=0, LT=0

Machine Instructions (cont.)
• Branch
– JUMP X Load next instruction from memory loc. X
– JUMPGT X Load next instruction from memory loc. X
only if GT flag in CCR is set, otherwise
load statement from next sequence loc.
as usual.
•JUMPEQ, JUMPLT, JUMPGE, JUMPLE,JUMPNEQ
• Control
– HALT Stop program execution.

Example
• Pseudo-code: Set A to B + C
• Assuming variable:
– A stored in memory cell 100, B stored in
memory cell 150, C stored in memory cell 151
• Machine language (really in binary)
– LOAD 150
– ADD 151
– STORE 100
– or
– (ADD 150, 151, 100)

Structure of the Control Unit[3]
• PC (Program Counter):
– stores the address of next instruction to fetch
• IR (Instruction Register):
– stores the instruction fetched from memory
• Instruction Decoder:
– Decodes instruction and activates necessary circuitry
Instruction
Decoder
IR
+1
PC

How does this all work together?
• Program Execution:
– PC is set to the address where the first program
instruction is stored in memory.
– Repeat until HALT instruction or fatal error
Fetch instruction
Decode instruction
Execute instruction
End of loop

Program Execution (cont.)
• Fetch phase
– PC --> MAR (put address in PC into MAR)
– Fetch signal (signal memory to fetch value into
MDR)
– MDR --> IR (move value to Instruction Register)
– PC + 1 --> PC (Increase address in program counter)
• Decode Phase
– IR -> Instruction decoder (decode instruction in IR)
– Instruction decoder will then generate the signals to
activate the circuitry to carry out the instruction

Program Execution (cont.)
• Execute Phase
– Differs from one instruction to the next.
• Example:
– LOAD X (load value in addr. X into register)
•IR_address -> MAR
•Fetch signal
•MDR --> R
– ADD X
•left as an exercise

Instruction Set for Our Von Neumann Machine
Opcode Operation Meaning
0000 LOAD X CON(X) --> R
0001 STORE X R --> CON(X)
0010 CLEAR X 0 --> CON(X)
0011 ADD X R + CON(X) --> R
0100 INCREMENT X CON(X) + 1 --> CON(X)
0101 SUBTRACT X R - CON(X) --> R
0101 DECREMENT X CON(X) - 1 --> CON(X)
0111 COMPARE X If CON(X) > R then GT = 1 else 0
If CON(X) = R then EQ = 1 else 0
If CON(X) < R then LT = 1 else 0
1000 JUMP X Get next instruction from memory location X
1001 JUMPGT X Get next instruction from memory loc. X if GT=1
... JUMPxx X xx = LT / EQ / NEQ
1101 IN X Input an integer value and store in X
1110 OUT X Output, in decimal notation, content of mem. loc. X
1111 HALT Stop program execution

Fundamental Components of
Computer[3]
• The CPU (ALU, Control Unit, Registers)
• The Memory Subsystem (Stored Data)
• The I/O subsystem (I/O devices)
I/O Device
Subsystem
Address Bus
Data Bus
Control Bus
CPU
Memory
Subsystem

Each of these Components are
connected through Buses.
• BUS - Physically a set of wires. The
components of the Computer are connected to
these buses.
• Address Bus
• Data Bus
• Control Bus

Address Bus
• Used to specify the address of the memory
location to access.
• Each I/O devices has a unique address.
(monitor, mouse, cd-rom)
• CPU reads data or instructions from other
locations by specifying the address of its
location.
• CPU always outputs to the address bus and
never reads from it.

Data Bus
• Actual data is transferred via the data bus.
• When the cpu sends an address to memory, the
memory will send data via the data bus in
return to the cpu.

Control Bus
• Collection of individual control signals.
• Whether the cpu will read or write data.
• CPU is accessing memory or an I/O device
• Memory or I/O is ready to transfer data

I/O Bus or Local Bus
• In today’s computers the the I/O controller will
have an extra bus called the I/O bus.
• The I/O bus will be used to access all other I/O
devices connected to the system.
• Example: PCI bus

Bus Organisation[3]
Processor
Control
Datapath
Memory Devices
Input
Output
Cache
Registers
Bus

Fundamental Concepts
 Processor (CPU): the active part of the computer,
which does all the work (data manipulation and
decision-making).
 Datapath: portion of the processor which contains
hardware necessary to perform all operations
required by the computer (the brawn).
 Control: portion of the processor (also in
hardware) which tells the datapath what needs to
be done (the brain).

Fundamental Concepts (2)
 Instruction execution
cycle: fetch, decode,
execute.
 Fetch: fetch next instruction
(using PC) from memory
into IR.
 Decode: decode the
instruction.
 Execute: execute
instruction.
Instruction
Fetch
Instruction
Decode
Operand
Fetch
Execute
Result
Store
Next
Instruction

Fundamental Concepts (3)
 Fetch: Fetch next instruction into IR (Instruction
Register).
 Assume each word is 4 bytes and each instruction is
stored in a word, and that the memory is byte
addressable.
 PC (Program Counter) contains address of next
instruction.
IR  [[PC]]
PC [PC] + 4

Single Bus Organization[4]
Data line
Address line
PC
MAR
MDR
Y
Internal
processor bus
Z
MUX
A
ALU
B
Constant 4
Select
Add
Sub
XOR
:
ALU
control
lines Carry-in
IR
RO
R(n–1)
:
:
TEMP
Instruction
decoder and
control logic
. . .
Control signals

Instruction Cycles
• Procedure the CPU goes through to process an
instruction.
• 1. Fetch - get instruction
• 2. Decode - interperate the instruction
• 3. Execute - run the instruction.

Timing Diagram:
Memory Read [4]
• Address is placed at beginning of clock
• after one clock cycle the CPU asserts the read.
• Causes the memory to place its data onto the data bus.
• CLK : System Clock used to synchronize
CLK
AddressBus
Bus
Read
Data

Timing Diagram :
Memory Write [4]
• CPU places the Address and data on the first clock cycle.
• At the start of the second clock the CPU will assert the
write control signal.
• This will then start memory to store data.
• After some time the write is then deasserted by the CPU
after removing the address and data from the subsystem.
CLK
AddressAddress Bus
Data Bus
Read
Data

I/O read and Write Cycles
• The I/O read and Write cycles are similar to
the memory read and write.
• Memory mapped I/O : Same sequences as
input output to read and write.
• The processor treats an I/O port as a memory
location.
• This results in the same treatment as a memory
access.

Technology Trends
• Processor
– logic capacity: about 30% per year
– clock rate: about 20% per year
• Memory
– DRAM capacity: about 60% per year (4x every 3 years)
– Memory speed: about 10% per year
– Cost per bit: improves about 25% per year
• Disk
– capacity: about 60% per year
– Total use of data: 100% per 9 months!
• Network Bandwidth
– Bandwidth increasing more than 100% per year!

i4004
i8086
i80386
Pentium
i80486
i80286
SU MIPS
R3010
R4400
R10000
1000
10000
100000
1000000
10000000
100000000
1965 1970 1975 1980 1985 1990 1995 2000 2005
Transistors
i80x86
M68K
MIPS
Alpha
° In ~1985 the single-chip processor (32-bit) and the single-board computer
emerged
° In the 2002+ timeframe, these may well look like mainframes compared
single-chip computer (maybe 2 chips)
DRAM
Year Size
1980 64 Kb
1983 256 Kb
1986 1 Mb
1989 4 Mb
1992 16 Mb
1996 64 Mb
1999 256 Mb
2002 1 Gb
uP-Name
Microprocessor Logic Density
DRAM chip capacity
Technology Trends[4]

Technology Trends
Smaller feature sizes – higher speed, density

Technology Trends
Number of transistors doubles every 18 months
(amended to 24 months)

References
1. Computer Organization and Architecture, Designing
for performance by William Stallings, Prentice Hall
of India.
2. Modern Computer Architecture, by Morris Mano,
Prentice Hall of India.
3. Computer Architecture and Organization by John P.
Hayes, McGraw Hill Publishing Company.
4. Computer Organization by V. Carl Hamacher,
Zvonko G. Vranesic, Safwat G. Zaky, McGraw Hill
Publishing Company.

Bca 2nd sem-u-1.2 digital logic circuits, digital component

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Bca 2nd sem-u-1.2 digital logic circuits, digital component