C programs

C Practical Programs
Vikram Neerugatti, Assistant Professor, SVCET, Chittoor Page 1
C programs
Week 1:
a) Write a C program to exchange the values between two variables with and without using
temporary variable.
Program code:
/* using temporary variable */
#include <stdio.h>
int main()
{
doublefirstNumber, secondNumber, temporaryVariable;
printf("Enter first number: ");
scanf("%lf", &firstNumber);
printf("Enter second number: ");
scanf("%lf",&secondNumber);
// Value of firstNumber is assigned to temporaryVariable
temporaryVariable = firstNumber;
// Value of secondNumber is assigned to firstNumber
firstNumber = secondNumber;
// Value of temporaryVariable (which contains the initial value of firstNumber) is assigned to
secondNumber
secondNumber = temporaryVariable;
printf("nAfter swapping, firstNumber = %.2lfn", firstNumber);
printf("After swapping, secondNumber = %.2lf", secondNumber);
return 0;
}
Output:
Enter first number: 1.20
Enter second number: 2.45
After swapping, firstNumber = 2.45
After swapping, secondNumber = 1.20
/*without using temporary variable */
#include <stdio.h>
int main()
{
doublefirstNumber, secondNumber;
printf("Enter first number: ");
scanf("%lf", &firstNumber);
printf("Enter second number: ");

scanf("%lf",&secondNumber);
// Swapping process
firstNumber = firstNumber - secondNumber;
secondNumber = firstNumber + secondNumber;
firstNumber = secondNumber - firstNumber;
printf("nAfter swapping, firstNumber = %.2lfn", firstNumber);
printf("After swapping, secondNumber = %.2lf", secondNumber);
return 0;
}
Output:
Enter first number: 10.25
Enter second number: -12.5
After swapping, firstNumber = -12.50
After swapping, secondNumber = 10.25
b) Write a C program to find the sum of individual digits of a positive integer.
Program Code:
#include<stdio.h>
int main()
{
intn,sum=0,m;
printf("Enter a number:");
scanf("%d",&n);
while(n>0)
{
m=n%10;
sum=sum+m;
n=n/10;
}
printf("Sum is=%d",sum);
return 0;
}
Output:
Enter a number:654
Sum is=15
c) Write a C program to generate all the factors of 4 and 7 between 1 and n and count their value,
where n is a value supplied by the user.
#include <stdio.h>

int main()
{
int number, i;
printf("Enter a positive integer: ");
scanf("%d",&number);
printf("Factors of 4 are: ", number);
for(i=1; i<= number; ++i)
{
if (4%i == 0)
{
printf("%d ",i);
}
}
printf("Factors of 7 are: ", number);
for(i=1; i<= number; ++i)
{
if (7%i == 0)
{
printf("%d ",i);
}
}
return 0;
}
Output:
Enter a positive integer: 10
The Factors of 4 are: 1 2 4
The factors of 7 are: 1 7
Week 2:
a) Write a C program to compute the factorial of a given number.
Program Code:
#include <stdio.h>
int main()
{
int n, i;
unsigned long long factorial = 1;
printf("Enter an integer: ");
scanf("%d",&n);
// show error if the user enters a negative integer
if (n < 0)

printf("Error! Factorial of a negative number doesn't exist.");
else
{
for(i=1; i<=n; ++i)
{
factorial *= i; // factorial = factorial*i;
}
printf("Factorial of %d = %llu", n, factorial);
}
return 0;
}
Output:
Enter an integer: 10
Factorial of 10 = 3628800
b) Write a C program to compute the Sine function.
Program Code:
/*
* C program to find the value of sin(x) using the series
* up to the given accuracy (without using user defined function)
* also print sin(x) using library function.
*/
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
void main()
{
int n, x1;
float accuracy, term, denominator, x, sinx, sinval;
printf("Enter the value of x (in degrees) n");
scanf("%f", &x);
x1 = x;
/* Converting degrees to radians */
x = x * (3.142 / 180.0);
sinval = sin(x);
printf("Enter the accuracy for the result n");
scanf("%f", &accuracy);
term = x;

sinx = term;
n = 1;
do
{
denominator = 2 * n * (2 * n + 1);
term = -term * x * x / denominator;
sinx = sinx + term;
n = n + 1;
} while (accuracy <= fabs(sinval - sinx));
printf("Sum of the sine series = %f n", sinx);
printf("Using Library function sin(%d) = %fn", x1, sin(x));
}
Output:
Enter the value of x (in degrees)
60
Enter the accuracy for the result
0.86602540378443864676372317075294
Sum of the sine series = 0.855862
Using Library function sin(60) = 0.866093
Week 3:
a) Write a C program to generate the first n terms of the Fibonacci sequence.
Program code:
#include <stdio.h>
int main()
{
int t1 = 0, t2 = 1, nextTerm = 0, n;
printf("Enter a positive number: ");
scanf("%d", &n);
// displays the first two terms which is always 0 and 1
printf("Fibonacci Series: %d, %d, ", t1, t2);
nextTerm = t1 + t2;
while(nextTerm<= n)
{
printf("%d, ",nextTerm);
t1 = t2;
t2 = nextTerm;
nextTerm = t1 + t2;
}
return 0;

}
Output:
Enter a positive integer: 100
Fibonacci Series: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89,
b) Write a C program to reverse the digits of a given integer
Program code:
#include <stdio.h>
int main()
{
int n, reversedNumber = 0, remainder;
printf("Enter an integer: ");
scanf("%d", &n);
while(n != 0)
{
remainder = n%10;
reversedNumber = reversedNumber*10 + remainder;
n /= 10;
}
printf("Reversed Number = %d", reversedNumber);
return 0;
}
Output:
Enter an integer: 2345
Reversed Number = 5432
Week 4
a) Write a C program to covert the given decimal number into its equivalent binary, octal and
hexadecimal number.
Program Code:
#include<stdio.h>
#include<stdlib.h>
void conversion(intnum, int base)
{
int remainder = num % base;
if(num == 0)
{
return;

}
conversion(num / base, base);
if(remainder < 10)
{
printf("%d", remainder);
}
else
{
printf("%c", remainder - 10 + 'A' );
}
}
int main()
{
intnum, choice;
printf("nEnter a Positive Decimal Number:t");
scanf("%d", &num);
while(1)
{
printf("n1. Decimal To Binary Conversion");
printf("n2. Decimal To Octal Conversion");
printf("n3. Decimal To Hexadecimal Conversion");
printf("n4. Quit");
printf("nEnter Your Option:t");
scanf("%d", &choice);
switch(choice)
{
case 1: printf("nBinary Value:t");
conversion(num, 2);
break;
case 2: printf("nOctal Value:t");
conversion(num, 8);
break;
case 3: printf("nHexadecimal Value:t");
conversion(num, 16);
break;
case 4: exit(0);
default: printf("Enter a correct inputn");
}
}
printf("n");

return 0;
}
Output:
Enter a positive Decimal Number:
1.Decimal To Binary Conversion
2.Decimal To Octal Conversion
3.Decimal To Hexadecimal Conversion
4.Quit
Enter your Option: 1
Binary Value: 1010
4.Quit
Enter Your option: 2
Octal Value: 12
4.Quit
Enter your option: 3
Hexadecimal Value : A
4.Quit
Enter your option: 4
b) Write a C program to calculate the following: Sum=1-x2/2! +x4/4!-x6/6!+x8/8!-x10/10!.
Program Code:
// C program to get the sum of the series
#include <math.h>
#include <stdio.h>
// Function to get the series
double Series(double x, int n)
{

double sum = 1, term = 1, fct, j, y = 2, m;
// Sum of n-1 terms starting from 2nd term
inti;
for (i = 1; i< n; i++) {
fct = 1;
for (j = 1; j <= y; j++) {
fct = fct * j;
}
term = term * (-1);
m = term * pow(x, y) / fct;
sum = sum + m;
y += 2;
}
return sum;
}
// Driver Code
int main()
{
double x = 9;
int n = 10;
printf("%.4f", Series(x, n));
return 0;
}
Output:
-5.1463
c)Write a C program, which takes two integer operands and one operator from the user,
performs the operation and then prints the result.
Program Code:
#include<stdio.h>
int main()
{
inta,b,res;
char c;
printf ("Enter any one operator +, -, *, / n");
scanf("%c", &c);

printf ("n Enter two numbers n");
scanf ("n %d n %d",&a, &b);
switch(c)
{
case '+': res=a+b;
printf("n The sum is %d",res);
break;
case '-': res=a-b;
printf("n The difference is %d",res);
break;
case '*': res=a*b;
printf("n The product is %d",res);
break;
case '/': res=a/b;
printf("n The quotient is %d",res);
break;
default: printf ("n Invalid entry");
}
return 0;
}
Output:
Case 1:
Enter any one operator +, -, *, /
+
Enter two numbers
5
3
The sum is 8
Case 2:
Enter any one operator +, -, *, /

/
Enter two numbers
100
20
The quotient is 5
Week 5
a) Write C program to display the result of a student by considering the standard grades.
Program code:
#include<stdio.h>
void main()
{
int marks;
printf("Enter your marks ");
scanf("%d",&marks);
if(marks<0 || marks>100)
{
printf("Wrong Entry");
}
else if(marks<50)
{
printf("Grade F");
}
else if(marks>=50 && marks<60)
{
printf("Grade D");
}
{
printf("Grade C");
}
{
printf("Grade B");
}

{
printf("Grade A");
}
else
{
printf("Grade A+");
}
}
Output:
Enter your marks 67
Grade C
press any key to continue.
b)Write a C Program to find both largest and smallest in the given list of integers.
Program code:
#include<stdio.h>
int main()
{
inti, n, lar,sm, elem;
printf ("Enter total number of elements n");
scanf ("%d", &elem);
printf ("Enter first number n");
scanf ("%d", &n);
lar = n;
sm=n;
for (i=1; i<= elem -1 ; i++)
{
printf ("n Enter another number n");
scanf ("%d",&n);
if (n>lar)
lar=n;
if (n<sm)
sm=n;
}
printf ("n The largest number is %d", lar);
printf ("n The smallest number is %d", sm);
return 0;
}
Output:
Enter total number of elements
10
Enter first number
3
Enter another number
8
12

42
89
45
236
890
411
328
The largest number is 890
The smallest number is 3
Week 6
a) Write a C program to generate Pascal’s triangle.
Program Code:
#include <stdio.h>
int main()
{
int rows, cal = 1, space, i, j;
printf("Enter number of rows: ");//enter number of rows for generating the pascal triangle
scanf("%d",&rows);
for(i=0; i<rows; i++) // outer loop for displaying rows
{
for(space=1; space <= rows-i; space++) // space for every row starting
printf(" ");
for(j=0; j <= i; j++) // inner loop for displaying the pascal triangle of numbers
{
if (j==0 || i==0) // either outer loop value or inner-loop value is "0 " it prints 1
cal = 1;
else
cal = cal*(i-j+1)/j; //calculate the coefficient
printf("%4d", cal);

}
printf("n");
}
return 0;
}
Output:
Enter number of rows: 5
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
b) Write a C program to construct a pyramid of numbers
Program Code:
#include<stdio.h>
#include<stdlib.h>
int main(){
inti,j,k,l,n;
system("cls");
printf("enter the range=");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
for(j=1;j<=n-i;j++)
{
printf(" ");
}
for(k=1;k<=i;k++)
{
printf("%d",k);
}
for(l=i-1;l>=1;l--)
{
printf("%d",l);

}
printf("n");
}
return 0;
}
Output:
enter the range= 4
1
121
12321
1234321
Week 7
a)Write a c program
1) To find square root of a given integer.
Program Code:
/**
* C program to find square root of a number
*/
#include <stdio.h>
#include <math.h>
int main()
{
doublenum, root;
/* Input a number from user */
printf("Enter any number to find square root: ");
scanf("%lf", &num);
/* Calculate square root of num */
root = sqrt(num);
/* Print the resultant value */
printf("Square root of %.2lf = %.2lf", num, root);
return 0;
}
Output:

Enter any number to find square root: 144
Square root of 144.00=12.00
2) To find the smallest Divisor of a number
Program Code:
// C++ program to count the number of
// subarrays that having 1
#include <bits/stdc++.h>
using namespace std;
// Function to find the smallest divisor
intsmallestDivisor(int n)
{
// if divisible by 2
if (n % 2 == 0)
return 2;
// iterate from 3 to sqrt(n)
for (inti = 3; i * i<= n; i += 2) {
if (n % i == 0)
returni;
}
return n;
}
// Driver Code
int main()
{
int n = 31;
cout<<smallestDivisor(n);
return 0;
}
Output:
31
3) To raise the number to large power.
Program Code:
#include <stdio.h>

int main()
{
int base, exponent;
longlong result = 1;
printf("Enter a base number: ");
scanf("%d", &base);
printf("Enter an exponent: ");
scanf("%d", &exponent);
while (exponent != 0)
{
result *= base;
--exponent;
}
printf("Answer = %lld", result);
return 0;
}
Output:
Enter a base number: 3
Enter an exponent: 4
Answer = 81
4)To generate the prime numbers from 1 to n
Program Code:
/**
* C program to print all prime numbers between 1 to n
*/

#include <stdio.h>
int main()
{
inti, j, end, isPrime; // isPrime is used as flag variable
/* Input upper limit to print prime */
printf("Find prime numbers between 1 to : ");
scanf("%d", &end);
printf("All prime numbers between 1 to %d are:n", end);
/* Find all Prime numbers between 1 to end */
for(i=2; i<=end; i++)
{
/* Assume that the current number is Prime */
isPrime = 1;
/* Check if the current number i is prime or not */
for(j=2; j<=i/2; j++)
{
/*
* If i is divisible by any number other than 1 and self
* then it is not prime number

*/
if(i%j==0)
{
isPrime = 0;
break;
}
}
/* If the number is prime then print */
if(isPrime==1)
{
printf("%d, ", i);
}
}
return 0;
}
Output:
Find Prime numbers between 1 to 10
All prime numbers between 1 to 10 are:
2 3 5 7
Week 8
1)C program to computer prime factor of an integer
Program code:
// Program to print all prime factors

# include <stdio.h>
# include <math.h>
// A function to print all prime factors of a given number n
voidprimeFactors(int n)
{
// Print the number of 2s that divide n
while (n%2 == 0)
{
printf("%d ", 2);
n = n/2;
}
// n must be odd at this point. So we can skip
// one element (Note i = i +2)
for (inti = 3; i<= sqrt(n); i = i+2)
{
// While i divides n, print i and divide n
while (n%i == 0)
{
printf("%d ", i);
n = n/i;
}
}

// This condition is to handle the case when n
// is a prime number greater than 2
if (n > 2)
printf ("%d ", n);
}
/* Driver program to test above function */
int main()
{
int n = 315;
primeFactors(n);
return 0;
}
Output:
3 3 5 7
2)
C program to generate pseudorandom number in c
Program code:
#include <stdio.h>
#include <stdlib.h>
int main() {
int c, n;
printf("Ten random numbers in [1,100]n");

for (c = 1; c <= 5; c++) {
n = rand() % 100 + 1;
printf("%dn", n);
}
return 0;
}
Output:
3569
254
57
5
9675
3)
C Program to find GCD of two numbers
Program code:
#include <stdio.h>
int main()
{
int n1, n2, i, gcd;
printf("Enter two integers: ");
scanf("%d %d", &n1, &n2);
for(i=1; i<= n1 &&i<= n2; ++i)
{

// Checks if i is factor of both integers
if(n1%i==0 && n2%i==0)
gcd = i;
}
printf("G.C.D of %d and %d is %d", n1, n2, gcd);
return 0;
}
Output:
Enter two positive integers: 81
153
GCD = 9
4)
C program to compute nth Fibonacci number
Program code:
/*
* C Program to find the nth number in Fibonacci series using recursion
*/
#include <stdio.h>
intfibo(int);
int main()
{
intnum;
int result;

printf("Enter the nth number in fibonacci series: ");
scanf("%d", &num);
if (num< 0)
{
printf("Fibonacci of negative number is not possible.n");
}
else
{
result = fibo(num);
printf("The %d number in fibonacci series is %dn", num, result);
}
return 0;
}
intfibo(intnum)
{
if (num == 0)
{
return 0;
}
else if (num == 1)
{
return 1;
}
else
{

return(fibo(num - 1) + fibo(num - 2));
}
}
Output:
Enter the nth number in fibonacci series: 8
The 8 number in fibonacci series is 21
Week 9
1) To find the both the largest and smallest number in the a list of integers
Program code:
#include<stdio.h>
int main()
{
inti, n, lar,sm, elem;
printf ("Enter total number of elements n");
scanf ("%d", &elem);
printf ("Enter first number n");
scanf ("%d", &n);
lar = n;
sm=n;
for (i=1; i<= elem -1 ; i++)
{
printf ("n Enter another number n");
scanf ("%d",&n);
if (n>lar)

lar=n;
if (n<sm)
sm=n;
}
printf ("n The largest number is %d", lar);
printf ("n The smallest number is %d", sm);
return 0;
}
Output:
Enter total number of elements
10
Enter first number
3
8
12
42
89
45
236

890
411
328
The largest number is 890
The smallest number is 3
2)
a.)c program to find the addition of two matrices
Program code:
#include <stdio.h>
int main(){
int r, c, a[100][100], b[100][100], sum[100][100], i, j;
printf("Enter number of rows (between 1 and 100): ");
scanf("%d", &r);
printf("Enter number of columns (between 1 and 100): ");
scanf("%d", &c);
printf("nEnter elements of 1st matrix:n");
for(i=0; i<r; ++i)
for(j=0; j<c; ++j)
{
printf("Enter element a%d%d: ",i+1,j+1);
scanf("%d",&a[i][j]);

}
printf("Enter elements of 2nd matrix:n");
for(i=0; i<r; ++i)
for(j=0; j<c; ++j)
{
printf("Enter element a%d%d: ",i+1, j+1);
scanf("%d", &b[i][j]);
}
// Adding Two matrices
for(i=0;i<r;++i)
for(j=0;j<c;++j)
{
sum[i][j]=a[i][j]+b[i][j];
}
// Displaying the result
printf("nSum of two matrices: n");
for(i=0;i<r;++i)
for(j=0;j<c;++j)
{
printf("%d ",sum[i][j]);
if(j==c-1)
{
printf("nn");
}
}

return 0;
}
Output:
Enter number of rows (between 1 and 100): 2
Enter number of columns (between 1 and 100): 3
Enter elements of 1st matrix:
Enter element a11: 2
Enter elements of 2nd matrix:
Enter element a11: -4
Sum of two matrices:
-2 8 7
10 8 6
b)c program for multiplication of two matrices

Program code:
#include <stdio.h>
int main()
{
int a[10][10], b[10][10], result[10][10], r1, c1, r2, c2, i, j, k;
printf("Enter rows and column for first matrix: ");
scanf("%d %d", &r1, &c1);
printf("Enter rows and column for second matrix: ");
scanf("%d %d",&r2, &c2);
// Column of first matrix should be equal to column of second matrix and
while (c1 != r2)
{
printf("Error! column of first matrix not equal to row of second.nn");
printf("Enter rows and column for first matrix: ");
scanf("%d %d", &r1, &c1);
printf("Enter rows and column for second matrix: ");
scanf("%d %d",&r2, &c2);
}
// Storing elements of first matrix.
printf("nEnter elements of matrix 1:n");
for(i=0; i<r1; ++i)
for(j=0; j<c1; ++j)
{
printf("Enter elements a%d%d: ",i+1, j+1);
scanf("%d", &a[i][j]);

}
// Storing elements of second matrix.
printf("nEnter elements of matrix 2:n");
for(i=0; i<r2; ++i)
for(j=0; j<c2; ++j)
{
printf("Enter elements b%d%d: ",i+1, j+1);
scanf("%d",&b[i][j]);
}
// Initializing all elements of result matrix to 0
for(i=0; i<r1; ++i)
for(j=0; j<c2; ++j)
{
result[i][j] = 0;
}
// Multiplying matrices a and b and
// storing result in result matrix
for(i=0; i<r1; ++i)
for(j=0; j<c2; ++j)
for(k=0; k<c1; ++k)
{
result[i][j]+=a[i][k]*b[k][j];
}
// Displaying the result
printf("nOutput Matrix:n");

for(i=0; i<r1; ++i)
for(j=0; j<c2; ++j)
{
printf("%d ", result[i][j]);
if(j == c2-1)
printf("nn");
}
return 0;
}
Output:
Enter rows and column for first matrix: 3
2
Enter rows and column for second matrix: 3
2
Error! column of first matrix not equal to row of second.
Enter rows and column for first matrix: 2
3
Enter rows and column for second matrix: 3
2
Enter elements of matrix 1:
Enter elements a11: 3
Enter elements a12: -2

Enter elements of matrix 2:
Enter elements b11: 2
Enter elements b21: -9
Output Matrix:
24 29
6 25
Week 10
a)Write a C program that uses functions to perform the following operations:
i) Reading a complex number ii) Writing a complex number
iii) Addition of two complex numbers iv) Multiplication of two complex numbers
Program code:
#include <stdio.h>
#include <conio.h>
struct complex
{
float real, imag;
}a, b, c;
struct complex read(void);

void write(struct complex);
struct complex add(struct complex, struct complex);
struct complex sub(struct complex, struct complex);
struct complex mul(struct complex, struct complex);
struct complex div(struct complex, struct complex);
void main ()
{
clrscr();
printf("Enter the 1st complex numbern ");
a = read();
write(a);
printf("Enter the 2nd complex numbern");
b = read();
write(b);
printf("Additionn ");
c = add(a, b);
write(c);
printf("Substractionn ");
c = sub(a, b);
write(c);
printf("Multiplicationn");
c = mul(a, b);
write(c);
printf("Divisionn");
c = div(a, b);

write(c);
getch();
}
struct complex read(void)
{
struct complex t;
printf("Enter the real partn");
scanf("%f", &t.real);
printf("Enter the imaginary partn");
scanf("%f", &t.imag);
return t;
}
void write(struct complex a)
{
printf("Complex number isn");
printf(" %.1f + i %.1f", a.real, a.imag);
printf("n");
}
struct complex add(struct complex p, struct complex q)
{
struct complex t;
t.real = (p.real + q.real);
t.imag = (p.imag + q.imag);
return t;
}

struct complex sub(struct complex p, struct complex q)
{
struct complex t;
t.real = (p.real - q.real);
t.imag = (p.imag - q.imag);
return t;
}
struct complex mul(struct complex p, struct complex q)
{
struct complex t;
t.real=(p.real * q.real) - (p.imag * q.imag);
t.imag=(p.real * q.imag) + (p.imag * q.real);
return t;
}
struct complex div(struct complex p, struct complex q)
{
struct complex t;
t.real = ((p.imag * q.real) - (p.real * q.imag)) / ((q.real * q.real) + (q.imag * q.imag));
t.imag = ((p.real * q.real) + (p.imag * q.imag)) / ((q.real * q.real) + (q.imag * q.imag));
return(t);
}
Output:
Enter the real part
2
Enter the imaginary part

4
Complex number is
2.0 + i4.0
Enter the real part
4
Enter the imaginary part
2
Complex number is
4.0 + i2.0
Addition
Complex number is
6.0 + i6.0
Subtraction
Complex number is
-2.0 + i2.0
Multiplication
Complex number is
0.0 + i20.0
Division
Complex number is
0.6 + i0.8
b) Write a C Program to find whether the given string is a palindrome or not.
Program code:
#include <stdio.h>
#include <string.h>

// A function to check if a string str is palindrome
voidisPalindrome(char str[])
{
// Start from leftmost and rightmost corners of str
int l = 0;
int h = strlen(str) - 1;
// Keep comparing characters while they are same
while (h > l)
{
if (str[l++] != str[h--])
{
printf("%s is Not Palindrome", str);
return;
}
}
printf("%s is palindrome", str);
}
// Driver program to test above function
int main()
{
isPalindrome("abba");
isPalindrome("abbccbba");

isPalindrome("geeks");
return 0;
}
Output:
abba is palindrome
abbccbba is palindrome
geeks is Not Palindrome
week 11
1)
a) To insert a sub-string in to a given main string from a given position.
Program code:
#include<stdio.h>
#include<conio.h>
#include<string.h>
void main()
{
char str1[20], str2[20];
int l1, l2, n, i;
clrscr();
puts("Enter the string 1n");
gets(str1);
l1 = strlen(str1);
puts("Enter the string 2n");
gets(str2);
l2 = strlen(str2);

printf("Enter the position where the string is to be insertedn");
scanf("%d", &n);
for(i = n; i< l1; i++)
{
str1[i + l2] = str1[i];
}
for(i = 0; i< l2; i++)
{
str1[n + i] = str2[i];
}
str2[l2 + 1] = '0';
printf("After inserting the string is %s", str1);
getch();
}
Output:
Enter the string 1
sachin
Enter the string 2
tendulkar
Enter the position where the string is to be inserted
4
After inserting the string is sachtendulkarin
b)To delete n Characters from a given position in a given string.
Program code:
#include<stdio.h>

#include<conio.h>
#include<string.h>
void main()
{
charstr[20];
inti, n, l, pos;
clrscr();
puts("Enter the stringn");
gets(str);
printf("Enter the position where the characters are to be deletedn");
scanf("%d", &pos);
printf("Enter the number of characters to be deletedn");
scanf("%d", &n);
l = strlen(str);
for(i = pos + n; i< l; i++)
{
str[i - n] = str[i];
}
str[i - n] = '0';
printf("The string is %s", str);
getch();
}
Output:
Enter the string
sachin

Enter the position where characters are to be deleted
2
Enter the number of characters to be deleted
2
The string is sain
2)
write-a-c-program-to-count-the-lines-words-and-characters-in-a-given-text
Program code:
#include <stdio.h>
#include <conio.h>
#include <string.h>
void main()
{
charstr[100];
inti = 0, l = 0, f = 1;
clrscr();
puts("Enter any stringn");
gets(str);
for(i = 0; str[i] !='0'; i++)
{
l = l + 1;
}
printf("The number of characters in the string are %dn", l);
for(i = 0; i<= l-1; i++)
{

if(str[i] == ' ')
{
f = f + 1;
}
}
printf("The number of words in the string are %d", f);
getch();
}
Output:
Enter any string
abcdefghijklmnopqrstuvwxyz
The number of characters in the string are 34
The number of words in the string are 9
Week 12
a) Write a C program to display the contents of a file.
Program code:
#include<stdio.h>
#include<conio.h>
FILE *fp1,*fp2;
char c;
void main()
{
clrscr();
printf("enter the textn");
fp1 = fopen("abc.txt", "w");
while((c = getchar()) != EOF)
putc(c, fp1);
fclose(fp1);
fp1 = fopen("abc.txt","r");
fp2=fopen("xyz.txt","w");
while(!feof(fp1))
{

c = getc(fp1);
putc(c,fp2);
}
fclose(fp1);
fclose(fp2);
printf("the copied data is n");
fp2 = fopen("xyz.txt", "r");
while(!feof(fp2))
{
c = getc(fp2);
printf("%c", c);
}
getch();
}
Output:
enter the text
engineering students are very good.
^Z
the copied data is
engineering students are very good.
b) Write a C program to merge two files into a third file
Program code:
#include<stdio.h>
void concatenate(FILE *fp1, FILE *fp2, char *argv[], intargc);
int main(intargc, char *argv[]){
FILE *fp1, *fp2;
concatenate(fp1, fp2, argv, argc);
return 0;
}
void concatenate(FILE *fp1, FILE *fp2, char **argv, intargc){
inti, ch;
fp2 = fopen("files", "a");
for(i = 1; i<argc - 1; i++){
fp1 = fopen(argv[i], "r");
while((ch = getc(fp1)) != EOF)
putc(ch, fp2);
}

}
Output:
File1:
studentboxoffice.in.
File2:
This is Computer Programming Lab.
File 3:
studentboxoffice.in. This is Computer Programming Lab
week 13
a)
Write a C program using command line arguments to search for word in file and replace it with the
specific word.
Program code:
// C program to search and replace
// all occurrences of a word with
// other word.
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
// Function to replace a string with another
// string
char *replaceWord(const char *s, const char *oldW,
const char *newW)
{
char *result;
inti, cnt = 0;
intnewWlen = strlen(newW);
intoldWlen = strlen(oldW);
// Counting the number of times old word
// occur in the string
for (i = 0; s[i] != '0'; i++)
{
if (strstr(&s[i], oldW) == &s[i])
{
cnt++;
// Jumping to index after the old word.
i += oldWlen - 1;
}
}
// Making new string of enough length
result = (char *)malloc(i + cnt * (newWlen - oldWlen) + 1);

i = 0;
while (*s)
{
// compare the substring with the result
if (strstr(s, oldW) == s)
{
strcpy(&result[i], newW);
i += newWlen;
s += oldWlen;
}
else
result[i++] = *s++;
}
result[i] = '0';
return result;
}
// Driver Program
int main()
{
charstr[] = "xxforxx";
char c[] = "xx";
char d[] = "Geeks";
char *result = NULL;
// oldW string
printf("Old string: %sn", str);
result = replaceWord(str, c, d);
printf("New String: %sn", result);
free(result);
return 0;
}
Output:
Old string: xxforxx
New String: GeeksforGeeks
b)
1)To write macro definition to test whether a character is lowercase or not.
Program code:
#include <stdio.h>
//#define IS_UPPER_CASE(n) ((n) >= ‘A’ && (n) <= ‘Z’)
#define IS_LOWER_CASE(n) ((n) >= ‘a’ && (n) <= ‘z’)
//#define IS_ALPHABETIC(n) (IS_UPPER_CASE(n) || IS_LOWER_CASE(n))
void main()
{
char CH=’a’;
clrscr();
if(IS_LOWER_CASE(CH))

printf(“nYES, CHARACTER IS A LOWER CASE CHARACTER”);
else
printf(“nNO, CHARACTER IS NOT A LOWER CASE CHARACTER”);
getch();
}
Output:
YES, CHARACTER IS A LOWER CASE CHARACTER
2)To check whether a character is alphabet or not.
Program code:
#include <stdio.h>
int main()
{
char c;
printf("Enter a character: ");
scanf("%c",&c);
if( (c>='a' && c<='z') || (c>='A' && c<='Z'))
printf("%c is an alphabet.",c);
else
printf("%c is not an alphabet.",c);
return 0;
}
Output:
Enter a character: *
* is not an alphabet
3) c program to find the largest of two numbers
Program code:
/* C Program to Find Largest of Two numbers */
#include <stdio.h>
int main() {
int a, b;
printf("Please Enter Two different valuesn");
scanf("%d %d", &a, &b);
if(a > b)
{
printf("%d is Largestn", a);
}
else if (b > a)
{
printf("%d is Largestn", b);
}
else
{
printf("Both are Equaln");
}
return 0;

}
Output:
Please Enter Two different values
65 5
65 is Largest
c) Write a C program to concatenate two strings using command line arguments.
Program code:
// C program to concatenate the two Strings
// using command line arguments
#include <stdio.h>
#include <stdlib.h> /* atoi */
#include <string.h>
// Function to concatenate the Strings
char* concat(char dest[], char src[])
{
// Appends the entire string
// of src to dest
strcat(dest, src);
// Return the concatenated String
returndest;
}
// Driver code
int main(intargc, char* argv[])
{
// Check if the length of args array is 1
if (argc == 1)
printf("No command line arguments found.n");
else {
// Get the command line arguments
// and concatenate them
printf("%sn", concat(argv[1], argv[2]));
}
return 0;
}
Output:
./main
No command line arguments found
./main hello world
helloworld
./main Geeks ForGeeks
GeeksForGeeks

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