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Carrier Farrag
Method
PresentedBy:
Soumik Sadman Anwar
3rd Year (Hons.), Roll: SH-105
Department of Statistics,
University of Dhaka
Contents
Introduction
Uses
Process
Formulae
Assumption
Calculation
Introduction
A mathematical graduation of census age
distribution proposed by Carrier and
Farrag (1959)
Why Use Carrier-
Farrag Method
Carrier-Farrag method ensures
smoother values than that of
quadratic interpolation by handling
the problem of massive age
shifting
Process
Quinary
Age
Group
Denary Age
Group
Formulae
Elementary Differential Equations
Let, 𝑢𝑖 = Population in the quinary age groups 5(x+i) to 5(x+i)+4
𝑈𝑖 = Population in the denary age group such that,
𝑼𝒊 = 𝒖𝒊 + 𝒖𝒊+𝟏
Calculating Denary age group from Quinary age group
Enumerated Population
Age in years Quinary age group Denary age group
(1) (2) (3)
5-9 4655 9270
10-14 4615
15-19 4374 8508
20-24 4134
25-29 3572 6301
30-34 2729
35-39 2288 4495
40-44 2207
45-49 1886 3210
50-54 1324
55-59 1204 2207
60-64 1003
65-69 602 1164
70-74 562
Assumptions
We assume, 𝑢𝑖 is a second degree function of i.
So, 𝑢𝑖+1 = 𝑢𝑖 + ∆𝑢𝑖
If i=0, 𝑢1 = 𝑢 𝑜 + ∆𝑢 𝑜
i=1, 𝑢2 = 𝑢1 + ∆𝑢1 = 𝑢 𝑜 + 2∆𝑢 𝑜 + ∆2
𝑢 𝑜
i=2, 𝑢3 = 𝑢2 + ∆𝑢2 = 𝑢 𝑜 + 3∆𝑢 𝑜 + 3∆2
𝑢 𝑜
i=3, 𝑢4 = 𝑢3 + ∆𝑢3 = 𝑢 𝑜 + 4∆𝑢 𝑜 + 6∆2
𝑢 𝑜
i=4, 𝑢5 = 𝑢4 + ∆𝑢4 = 𝑢 𝑜 + 5∆𝑢 𝑜 + 10∆2
𝑢 𝑜
Here, we ignore the higher terms of ∆
Calculation
We know, 𝑈𝑖 = 𝑢𝑖 + 𝑢𝑖+1
Putting, i=0, 𝑈0 = 𝑢0 + 𝑢1
i=2, 𝑈2 = 𝑢2 + 𝑢3 = 2𝑢 𝑜 + 5∆𝑢 𝑜 + 4∆2
𝑢 𝑜

1
2
𝑈2 = 𝑢 𝑜 +
5
2
∆𝑢 𝑜 + 2∆2
𝑢 𝑜 … … …(𝑖)
i=4, 𝑈4 = 𝑢4 + 𝑢5 = 2𝑢 𝑜 + 9∆𝑢 𝑜 +
16∆2
𝑢 𝑜
So, 𝑈0 - 𝑈4 = −8∆𝑢 𝑜 - 16∆2
𝑢 𝑜

1
16
(𝑈0 - 𝑈4) = −
1
2
∆𝑢 𝑜 - ∆2
𝑢 𝑜… … … (ii)
By, (i) + (ii), we get,
1
2
𝑈2 +
1
16
(𝑈0 - 𝑈4) = 𝑢 𝑜 + 2∆𝑢 𝑜 + ∆2 𝑢 𝑜 = 𝑢2
By, (i) + (ii), we get,
1
2
𝑈2 -
1
16
(𝑈0 - 𝑈4) = 𝑢 𝑜 + 3∆𝑢 𝑜 + 3∆2 𝑢 𝑜= 𝑢3
So, the key formulae are,
𝒖 𝟐 =
𝟏
𝟐
𝑼 𝟐 +
𝟏
𝟏𝟔
(𝑼 𝟎 - 𝑼 𝟒)
𝒖 𝟑 =
𝟏
𝟐
𝑼 𝟐 -
𝟏
𝟏𝟔
(𝑼 𝟎 - 𝑼 𝟒)
Drawbacks
1st and last two quinary age group data cannot
be graduated
Thank You

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Carrier Farrag Method

  • 1. Carrier Farrag Method PresentedBy: Soumik Sadman Anwar 3rd Year (Hons.), Roll: SH-105 Department of Statistics, University of Dhaka
  • 3. Introduction A mathematical graduation of census age distribution proposed by Carrier and Farrag (1959)
  • 4. Why Use Carrier- Farrag Method Carrier-Farrag method ensures smoother values than that of quadratic interpolation by handling the problem of massive age shifting
  • 6. Formulae Elementary Differential Equations Let, 𝑢𝑖 = Population in the quinary age groups 5(x+i) to 5(x+i)+4 𝑈𝑖 = Population in the denary age group such that, 𝑼𝒊 = 𝒖𝒊 + 𝒖𝒊+𝟏
  • 7. Calculating Denary age group from Quinary age group Enumerated Population Age in years Quinary age group Denary age group (1) (2) (3) 5-9 4655 9270 10-14 4615 15-19 4374 8508 20-24 4134 25-29 3572 6301 30-34 2729 35-39 2288 4495 40-44 2207 45-49 1886 3210 50-54 1324 55-59 1204 2207 60-64 1003 65-69 602 1164 70-74 562
  • 8. Assumptions We assume, 𝑢𝑖 is a second degree function of i. So, 𝑢𝑖+1 = 𝑢𝑖 + ∆𝑢𝑖 If i=0, 𝑢1 = 𝑢 𝑜 + ∆𝑢 𝑜 i=1, 𝑢2 = 𝑢1 + ∆𝑢1 = 𝑢 𝑜 + 2∆𝑢 𝑜 + ∆2 𝑢 𝑜 i=2, 𝑢3 = 𝑢2 + ∆𝑢2 = 𝑢 𝑜 + 3∆𝑢 𝑜 + 3∆2 𝑢 𝑜 i=3, 𝑢4 = 𝑢3 + ∆𝑢3 = 𝑢 𝑜 + 4∆𝑢 𝑜 + 6∆2 𝑢 𝑜 i=4, 𝑢5 = 𝑢4 + ∆𝑢4 = 𝑢 𝑜 + 5∆𝑢 𝑜 + 10∆2 𝑢 𝑜 Here, we ignore the higher terms of ∆
  • 9. Calculation We know, 𝑈𝑖 = 𝑢𝑖 + 𝑢𝑖+1 Putting, i=0, 𝑈0 = 𝑢0 + 𝑢1 i=2, 𝑈2 = 𝑢2 + 𝑢3 = 2𝑢 𝑜 + 5∆𝑢 𝑜 + 4∆2 𝑢 𝑜  1 2 𝑈2 = 𝑢 𝑜 + 5 2 ∆𝑢 𝑜 + 2∆2 𝑢 𝑜 … … …(𝑖) i=4, 𝑈4 = 𝑢4 + 𝑢5 = 2𝑢 𝑜 + 9∆𝑢 𝑜 + 16∆2 𝑢 𝑜 So, 𝑈0 - 𝑈4 = −8∆𝑢 𝑜 - 16∆2 𝑢 𝑜  1 16 (𝑈0 - 𝑈4) = − 1 2 ∆𝑢 𝑜 - ∆2 𝑢 𝑜… … … (ii)
  • 10. By, (i) + (ii), we get, 1 2 𝑈2 + 1 16 (𝑈0 - 𝑈4) = 𝑢 𝑜 + 2∆𝑢 𝑜 + ∆2 𝑢 𝑜 = 𝑢2 By, (i) + (ii), we get, 1 2 𝑈2 - 1 16 (𝑈0 - 𝑈4) = 𝑢 𝑜 + 3∆𝑢 𝑜 + 3∆2 𝑢 𝑜= 𝑢3 So, the key formulae are, 𝒖 𝟐 = 𝟏 𝟐 𝑼 𝟐 + 𝟏 𝟏𝟔 (𝑼 𝟎 - 𝑼 𝟒) 𝒖 𝟑 = 𝟏 𝟐 𝑼 𝟐 - 𝟏 𝟏𝟔 (𝑼 𝟎 - 𝑼 𝟒)
  • 11. Drawbacks 1st and last two quinary age group data cannot be graduated