Chapter 2 angular kinetics

Dr. Eiman Sumayyah
DPT, MSPT, CNDP, COMPT, CNT(Bobath), MRP Specialist, Cardio & ICU PT

 Angular kinetics explains the causes of rotary motion
 The net torque acting on an object creates an angular acceleration inversely
proportional to the angular inertia called the moment of inertia
 Angular kinetics is quite useful because it explains the causes of joint rotations
and provides a quantitative way to determine the center of gravity of the human
body.
 The application of angular kinetics is illustrated with the principles of Inertia and
Balance.

 Another important principle to understand in the modification of motion is
Inertia.
 Inertia can be defined as the property of all objects to resist changes in their state
of motion.
 Newton's first law of motion outlines the principle of inertia

 Balance is a person's ability to control their body position relative to some base of
support
 A handstand is a difficult gymnastic skill not only because of the muscular
strength required, but also because of the small base of support in the anterior
and posterior directions.
 Athletes in the starting blocks for sprints choose body postures with less stability
in favor of increased mobility in the direction of the race.

 The rotating effect of a force is called a torque or moment of force.
 Vector
 Torque is calculated as the product of force (F) and the moment arm. The moment
arm or leverage is the perpendicular displacement (d⊥) from the line of action of
the force and the axis of rotation.

 The biceps femoris pictured in
Figure has moment arms that
create hip extension and knee
flexion torques.
 An important point is that the
moment arm is always the
shortest displacement between
the force line of action and axis
of rotation

 In algebraic terms, the formula for torque is T = F • d⊥, so that typical units of
torque are N•m and lb•ft.
 Counter-Clockwise Torque is positive
 Clockwise torque is negative
 Note that the size of the force and the moment arm are equally important in
determining the size of the torque created.
 This has important implications for maximizing performance in many activities.

 A person wanting to create more torque can increase the applied force or increase
their effective moment arm.
 Increasing the moment arm is often easier and faster than months of conditioning

 Figure illustrates two positions
where a therapist can provide
resistance with a hand dynamometer
to manually test the isometric
strength of the elbow extensors.
 By positioning their arm more distal
(position 2), the therapist increases
the moment arm and decreases the
force they must create to balance the
torque created by the patient and
gravity.

 A biomechanics student takes a break from
her studies to bring a niece to the
playground. Let's calculate the torque the
student creates on the merry go-round by the
force F1 illustrated in Figure.
 Thirty pounds of force times the moment
arm of 4 feet is equal to 120 lb•ft of torque.
This torque can be considered positive
because it acts counterclockwise.
 If on the second spin the student pushes
with the same magnitude of force (F2) in a
different direction, the torque and angular
motion created would be smaller because of
the smaller moment arm (dB).

 Good examples of torque measurements in exercise science are the joint torques
measured by isokinetic dynamometers.

 The state of an object's rotation depends on the balance of torques created by the
forces acting on the object.
 Remember that summing or adding torques acting on an object must take into
account the vector nature of torques.
 All the muscles of a muscle group sum together to create a joint torque in a
particular direction.
 These muscle group torques must also be summed with torques from antagonist
muscles, ligaments, and external forces to determine the net torque at a joint.

 Figure illustrates the forces of the
anterior deltoid and long head of the
biceps in flexing the shoulder in the
sagittal plane.
 If ccw torques are positive, the
torques created by these muscles
would be positive. The net torque of
these two muscles is the sum of
their individual torques, or 6.3 N•m
(60 • 0.06 + 90 • 0.03 = 6.3 N•m).
 If the weight of this person's arm
multiplied by its moment arm
created a gravitational torque of –16
N•m, what is the net torque acting
at the shoulder?

 Assuming there are no other shoulder flexors or extensors active to make forces,
we can sum the gravitational torque (–16 N•m) and the net muscle torque (6.3
N•m) to find the resultant torque of –9.7 N•m.
 This means that there is a resultant turning effect acting at the shoulder that is
an extension torque, where the shoulder flexors are acting eccentrically to lower
the arm.

 Torques can be summed about any axis, but be sure to multiply the force by the
moment arm and then assign the correct sign to represent the direction of rotation
before they are summed.

 What are the two most important parameters that determine the size of a torque
or moment of force?

 Calculate the shoulder flexion torque required to hold an 80-lb barbell just above
your chest in a bench press. The horizontal distance from your shoulder axis to
the bar bell is 0.9 feet

 ANGULAR INTERIA
 NEWTON'S ANGULAR ANALOGUES
 EQUILIBRIUM
 CENTER OF GRAVITY
 APPLICATION OF PRINCIPLE OF BALANCE

Chapter 2 angular kinetics

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Chapter 2 angular kinetics