Computer Programming Code Sample

MIDTERM EXAM FOR
PROGRAMMING 2

Batch 3
Design a program that will accept
a maximum of 5 customers.

If your choice is 1: -------------- void ADD()
First name:
• printf("FIRST NAME:"); scanf("%s",&name[x]); getchar();
Name of item:
• printf(“ITEM NAME:"); scanf("%s",&item[x]); getchar();
Price:
• printf("PRICE:"); scanf("%d",&price[x]);
Quantity:
• printf("QUANTITY:"); scanf("%d",&qty[x]);
• Clear the previous display ----------------- clrscr();
• Accept the following:

Then compute for total amount,
where total amount is:
price * quantity.
• totalAmt[x]=price[x]*qty[x];

• If total amount is lesser than or equal to 1000, give 5% discount.
Compute for total discounted amount, where:
Total Discounted Amount is Total Amount – Discounted Amount.
Display Total Discounted Amount.
• Else if total amount is greater than 1000, but less than or equal to 2000,
give 10% discount. Compute for total discounted amount, where:
• Else if total amount is greater than 2000, but less than 5000, give 15%
discount. Compute for total discounted amount, where:
• Else give 20% discount. Compute for total discounted amount, where:
Display Total Discounted Amount

If (totalAmt[x]<=1000)
{ dc[x] = totalAmt[x] * 0.05;
disc[x] = totalAmt[x] - dc[x];
printf ("TOTAL DISCOUNTED AMOUNT: %f", disc[x]); }
else if (totalAmt[x]>1000 && totalAmt[x]<=2000)
printf ("TOTAL DISCOUNTED AMOUNT: %f", disc[x]); }
else if (totalAmt[x]>2000&&totalAmt[x]<5000)
printf ("TOTAL DISCOUNTED AMOUNT: %f",disc[x]); }
else
printf ("TOTAL DISCOUNTED AMOUNT: %f",disc[x]); }

After all the inputs, ask “DO YOU
WANT TO GO TO MAIN MENU? 1
for YES | 2 for NO”…
• If 1 go to Main Menu or Main Display
 if(opt==1) { MAIN(); }
• If 2 Exit
 else { exit(0);}

If your choice is 2: -------------- void EDIT()
• Display “NO RECORDS AVAILABLE” if no information of
entrepreneurs that were added.
• Else, display all information of customer.
• If you wish to edit the information of customer, display “DO
YOU WANT TO EDIT INFORMATION?
1 for YES | 2 for NO”
• If you entered 1, accept a number from list you want to edit.
Display EDIT MENU.
• Choose what field of information you would like to edit.

• If your choice is 1, then EDIT the FIRST NAME only
• If your choice is 2, EDIT the ITEM NAME
• If your choice is 3, EDIT the QUANTITY
• If your choice is 4, EDIT the PRICE
• After all the inputs, ask “DO YOU WANT TO GO TO MAIN
MENU? 1 for YES | 2 for NO…
 if(opt==1) { MAIN(); }
• If 2 Exit

EDIT INFORMATION
FIRST NAME ITEM QUANTITY PRICE TOTAL AMOUNT TOTAL DISCOUNTED AMOUNT
1. Khatt bag 2 950 19,000 18,620
2. Jenny pen 5 100 500 495
Do you want to edit information? 1 for YES | 2 for NO: 1
Enter a number from the list: 1
Choose what field to edit:
• FIRST NAME
• NAME OF ITEM
• QUANTITY
• PRICE
ENTER YOUR CHOICE: 1
************************** EDIT CUSTOMER’S INFORMATION ************************
ENTER FIRST NAME: firstname
Do you want to go to Main Menu? 1 for YES | 2 for NO:

void EDIT()
{ clrscr();
if(x==0)
{ printf("NO RECORDS AVAILABLE!"); }
else
{ printf("ALL INFORMATION of CUSTOMER");
printf("FIRST NAME ITEM QTY PRICE AMOUNT DISCOUNTED AMT");
for (y=1; y<=x; y++)
{
printf("%d. %s %s %d %d %d %f",y, name[y],item[y],qty[y],price[y],totalAmt[y],disc[y]); }
printf("DO YOU WANT TO EDIT INFORMATION? 1 for YES | 2 for NO:");scanf("%d",&num);
if(num==1)
{ printf ("ENTER A NUMBER FROM THE LIST: "); scanf("%d",&number);
printf (“ CHOOSE WHAT FIELD TO EDIT:");
printf (“ 1. FIRST NAME");
printf (“ 2. NAME OF ITEM");
printf (“ 3. QUANTITY");
printf (“ 4. PRICE");
printf (" ENTER YOUR CHOICE: "); scanf("%d",&ch);
switch(ch)

switch(ch)
{ clrscr();
case 1: printf (“ ENTER FIRST NAME:"); scanf("%s",&name[number]); getchar();
break;
case 2: printf (“ ENTER NAME OF ITEM:"); scanf("%s",&item[number]); getchar();
break;
case 3: printf (“ ENTER QUANTITY:"); scanf("%d",&qty[number]);
break;
case 4: printf (“ ENTER PRICE:"); scanf("%d",&price[number]);
break;
}
printf("DO YOU WANT TO GO TO MAIN? 1 for YES | 2 for NO:");scanf("%d",&opt);
if(opt==1)
{ MAIN(); }
else { exit(0); }
else
{ exit(0); }
}}

If your choice is 3: -------------- void Display()
• Display “NO RECORDS AVAILABLE” if no information of
entrepreneurs that were added.
• Else, display all information of customer.
• If you wish to edit the information of customer, display “DO
YOU WANT TO EDIT INFORMATION?
1 for YES | 2 for NO”
 if(opt==1) { MAIN(); }
• If 2 Exit

void Display()
{
clrscr();
printf("DISPLAY INFORMATION");
if(x==0)
{ printf (“NO RECORDS AVAILABLE!"); }
else
{
printf (“ FIRST NAME ITEM QTY PRICE AMOUNT DISCOUNTED AMT");
for (y=1; y<=x; y++)
{
printf("%d. %s %s %d %d %d %f",y, name[y],item[y],qty[y],price[y],totalAmt[y],disc[y]); }
printf(" DO YOU WANT TO GO TO MAIN? 1 for YES, 2 for EXIT: ");
scanf("%d",&opt);
if(opt==1)
{ MAIN(); }
else
{ exit(0); }
}}

Computer Programming Code Sample

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Computer Programming Code Sample