Cu(H2O)42+(aq) + 4CN-(aq) = Cu(CN)42-(aq) +4 H2O(l)Cu+2 is a Lew.pdf
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The document discusses the equilibrium reaction between cu(h2o)42+ and cn- to form cu(cn)42- and water, highlighting the roles of each component. Cu+2 acts as a Lewis acid due to its vacant d-orbitals, while cn- and h2o function as Lewis bases, donating electron pairs. The reaction illustrates the acid-base interactions involving transition metal complexes and coordinating ligands.
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Cu(H2O)42+(aq) + 4CN-(aq) = Cu(CN)42-(aq) +4 H2O(l)Cu+2 is a Lew.pdf
- 1. Cu(H2O)42+(aq) + 4CN-(aq) <=> Cu(CN)42-(aq) +4 H2O(l) Cu+2 is a Lewis acid as it has vacantd-orbitals that can accomodate an electron pair(Electron pairacceptor) CN- is a Lewis base as it has lone pair ofelectron that is donated to Cu+2 in the reaction(Electron pair donor) H2O is a Lewis base as the Oxygen atom haslone pair of electrons and therefre, it acts as an electronpair donor. Solution Cu(H2O)42+(aq) + 4CN-(aq) <=> Cu(CN)42-(aq) +4 H2O(l) Cu+2 is a Lewis acid as it has vacantd-orbitals that can accomodate an electron pair(Electron pairacceptor) CN- is a Lewis base as it has lone pair ofelectron that is donated to Cu+2 in the reaction(Electron pair donor) H2O is a Lewis base as the Oxygen atom haslone pair of electrons and therefre, it acts as an electronpair donor.