SlideShare a Scribd company logo
Geometry : Right Triangles
Data Sufficiency – Question 9
Question
a, b, and c are sides of a right triangle. What is the area of
the triangle?
Statement 1 : a = 4
Statement 2 : a + b + c = 12
◴Step 1 : When is the data sufficient?
What information do we need to get the answer?
Answer these questions before analyzing the statements.
What is the area of the triangle?
When is the data sufficient?
The data is sufficient
when we are able to
find a unique value for
the area of the right
triangle.
Answer these questions before analyzing the statements.
What is the area of the triangle?
When is the data sufficient? What information is needed?
The data is sufficient
when we are able to
find a unique value for
the area of the right
triangle.
Base and height of the
triangle.
Answer these questions before analyzing the statements.
What is the area of the triangle?
When is the data sufficient? What information is needed?
The data is sufficient
when we are able to
find a unique value for
the area of the right
triangle.
Base and height of the
triangle.
1. Check to see whether
more than one triangle is
possible with the data
given.
2. Sides of triangles need not
be integers. i.e., sides of
right triangles that are not
Pythagorean triplets exist.
Watch out for
◴Step 2: Evaluate statement (1) ALONE
02 Statement 1: a = 4
Statement 1: a = 4; Statement 2: a + b + c = 12.
What is the area of the triangle?
02 Statement 1: a = 4
·
We cannot find the area of the right triangle with information about
only one of the sides and no other information about the triangle.
Statement 1: a = 4; Statement 2: a + b + c = 12.
What is the area of the triangle?
02 Statement 1: a = 4
·
We cannot find the area of the right triangle with information about
only one of the sides and no other information about the triangle.
Statement 1: a = 4; Statement 2: a + b + c = 12.
What is the area of the triangle?
Choices narrow
down to B, C or E.
Eliminate
choices A and D
Statement 1 alone is NOT sufficient
◴Step 3: Evaluate statement (2) ALONE
03 Statement 2: a + b + c = 12
· The sides of the triangle could be 3, 4, 5 or the sides could be in the ratio of 1 : 1 : 2
with a perimeter of 12.
Statement 1: a = 4; Statement 2: a + b + c = 12.
What is the area of the triangle?
03 Statement 2: a + b + c = 12
· The sides of the triangle could be 3, 4, 5 or the sides could be in the ratio of 1 : 1 : 2
with a perimeter of 12.
Statement 1: a = 4; Statement 2: a + b + c = 12.
What is the area of the triangle?
· The area will be different for both the right triangles with the same perimeter.
03 Statement 2: a + b + c = 12
· The sides of the triangle could be 3, 4, 5 or the sides could be in the ratio of 1 : 1 : 2
with a perimeter of 12.
Statement 1: a = 4; Statement 2: a + b + c = 12.
What is the area of the triangle?
· The area will be different for both the right triangles with the same perimeter.
·
We cannot find a unique value for the area of the right triangle with
information about only the perimeter of the triangle.
03 Statement 2: a + b + c = 12
· The sides of the triangle could be 3, 4, 5 or the sides could be in the ratio of 1 : 1 : 2
with a perimeter of 12.
Statement 1: a = 4; Statement 2: a + b + c = 12.
What is the area of the triangle?
· The area will be different for both the right triangles with the same perimeter.
·
We cannot find a unique value for the area of the right triangle with
information about only the perimeter of the triangle.
Choices narrow down to C or E.
Eliminate choice B
Statement 2 alone is NOT sufficient
◴Step 4: Combine the two statements
04 a = 4 and a + b + c = 12. Check whether more than one triangle exists.
· If a = 4 and a + b + c = 12, then b + c = 8. So, b = 8 - c
Statement 1: a = 4; Statement 2: a + b + c = 12.
What is the area of the triangle?
04 a = 4 and a + b + c = 12. Check whether more than one triangle exists.
· If a = 4 and a + b + c = 12, then b + c = 8. So, b = 8 - c
Statement 1: a = 4; Statement 2: a + b + c = 12.
What is the area of the triangle?
· One of b or c is the hypotenuse as the hypotenuse is the longest side of a right triangle and
a which measures 4 cannot be the longest side of a right triangle whose perimeter is 12.
04 a = 4 and a + b + c = 12. Check whether more than one triangle exists.
· If a = 4 and a + b + c = 12, then b + c = 8. So, b = 8 - c
Statement 1: a = 4; Statement 2: a + b + c = 12.
What is the area of the triangle?
· One of b or c is the hypotenuse as the hypotenuse is the longest side of a right triangle and
a which measures 4 cannot be the longest side of a right triangle whose perimeter is 12.
· Applying Pythagoras theorem,
42 + c2 = (8 – c)2.
16 + c2 = 64 + c2 – 16c
Or 16c = 80. So, c = 5.
And b = 8 – c = 8 – 5 = 3.
Using the two statements we
have found all 3 sides. So, we
can find a unique value for
the area.
04 a = 4 and a + b + c = 12. Check whether more than one triangle exists.
· If a = 4 and a + b + c = 12, then b + c = 8. So, b = 8 - c
Statement 1: a = 4; Statement 2: a + b + c = 12.
What is the area of the triangle?
· One of b or c is the hypotenuse as the hypotenuse is the longest side of a right triangle and
a which measures 4 cannot be the longest side of a right triangle whose perimeter is 12.
· Applying Pythagoras theorem,
42 + c2 = (8 – c)2.
16 + c2 = 64 + c2 – 16c
Or 16c = 80. So, c = 5.
And b = 8 – c = 8 – 5 = 3.
Using the two statements we
have found all 3 sides. So, we
can find a unique value for
the area.
Correct answer : Choice C.Statements TOGETHER are sufficient
More Hard Math Questions
Visit www.q-51.com
Queries, feedback?
Reach us at info@4gmat.com
GMAT Classes @ Chennai, India
Weekend and weekday GMAT classes by US
B School graduates, GMAT 98%lers.
chennai.4gmat.com or +91 95000 48484
GMAT Classes @ Bangalore, India
Weekend classes by US B school graduates.
bangalore.4gmat.com or +91 74060 48484

More Related Content

PDF
Hard GMAT Math Question - Absolute Value
 
PDF
GMAT Geometry - Hard Math Problem
 
PPTX
Ratio and proportion
PPT
Trig For Dummies By Adrian P.
DOCX
Lesson exemplar in writing the equation needed in solving the right triangle
PPTX
Trigonometric Identities.
PPT
Pythagorean theorem and distance formula
PDF
4.11.4 Trigonometry
Hard GMAT Math Question - Absolute Value
 
GMAT Geometry - Hard Math Problem
 
Ratio and proportion
Trig For Dummies By Adrian P.
Lesson exemplar in writing the equation needed in solving the right triangle
Trigonometric Identities.
Pythagorean theorem and distance formula
4.11.4 Trigonometry

What's hot (20)

ODP
Trigonometry
PDF
How to calculate the area of a triangle
PDF
Obj. 22 Triangle Inequalities
PPT
004 pythagorean thm
PPT
Trigonometry ratios in right triangle
PDF
Evidence for Pi
PPT
Right triangles
PDF
TRIANGLE INEQUALITY THEOREM
PDF
Ch4.6 Triangle Inequalities
PPT
Grade 10 Trig.
PPT
Trigonometry
PPTX
Geometry - Equilateral triangle and circle
PDF
4.11.3 Similar Right Triangles
PPTX
Geometry - Right triangle properties
PPTX
Trigonometric identities
PDF
Trigonometric Functions
PPTX
Inequalities in a triangle
PPTX
Matt’s potw solution
PDF
2.5.5 Triangle Inequalities
PDF
2.5.4 Hinge Theorem
Trigonometry
How to calculate the area of a triangle
Obj. 22 Triangle Inequalities
004 pythagorean thm
Trigonometry ratios in right triangle
Evidence for Pi
Right triangles
TRIANGLE INEQUALITY THEOREM
Ch4.6 Triangle Inequalities
Grade 10 Trig.
Trigonometry
Geometry - Equilateral triangle and circle
4.11.3 Similar Right Triangles
Geometry - Right triangle properties
Trigonometric identities
Trigonometric Functions
Inequalities in a triangle
Matt’s potw solution
2.5.5 Triangle Inequalities
2.5.4 Hinge Theorem
Ad

Similar to Difficult GMAT Geometry Data Sufficiency - Q51 Series (20)

PPT
Geometry unit 8.1
PPT
Lesson 5 4
DOC
Module 1 similarity
DOC
Gmat quant topic 5 geometry solutions
PPTX
G8 Math Q4 - Week 1 - Illustrating the triangle inequality.pptx
PPTX
Power point pythagorean theorem revised
PDF
Module 3 similarity
PDF
Module 1 similarity
PDF
imc-2018-s.pdf
PDF
Module 4 geometry of shape and size
DOCX
2012 Mathacre JV Written Test
PPTX
Formulae GCSE Mathematics
PPT
C:\Documents And Settings\Michael Taylor\Desktop\Formula
DOCX
GREKing: The most repeated type of quants problem.
PDF
Pre-Assessment-Activity.pdf
DOCX
Tcs paper
DOCX
Tcs paper
PPT
Core 4 Parametric Equations 2
DOCX
ag assign1.0.docx
PPTX
10 pythagorean theorem, square roots and irrational numbers
Geometry unit 8.1
Lesson 5 4
Module 1 similarity
Gmat quant topic 5 geometry solutions
G8 Math Q4 - Week 1 - Illustrating the triangle inequality.pptx
Power point pythagorean theorem revised
Module 3 similarity
Module 1 similarity
imc-2018-s.pdf
Module 4 geometry of shape and size
2012 Mathacre JV Written Test
Formulae GCSE Mathematics
C:\Documents And Settings\Michael Taylor\Desktop\Formula
GREKing: The most repeated type of quants problem.
Pre-Assessment-Activity.pdf
Tcs paper
Tcs paper
Core 4 Parametric Equations 2
ag assign1.0.docx
10 pythagorean theorem, square roots and irrational numbers
Ad

Recently uploaded (20)

PDF
A GUIDE TO GENETICS FOR UNDERGRADUATE MEDICAL STUDENTS
PDF
Computing-Curriculum for Schools in Ghana
PPTX
Tissue processing ( HISTOPATHOLOGICAL TECHNIQUE
PDF
Anesthesia in Laparoscopic Surgery in India
PDF
Chapter 2 Heredity, Prenatal Development, and Birth.pdf
PDF
What if we spent less time fighting change, and more time building what’s rig...
PDF
Complications of Minimal Access Surgery at WLH
PDF
2.FourierTransform-ShortQuestionswithAnswers.pdf
PDF
Supply Chain Operations Speaking Notes -ICLT Program
PDF
STATICS OF THE RIGID BODIES Hibbelers.pdf
PPTX
202450812 BayCHI UCSC-SV 20250812 v17.pptx
PDF
Practical Manual AGRO-233 Principles and Practices of Natural Farming
PPTX
school management -TNTEU- B.Ed., Semester II Unit 1.pptx
PDF
OBE - B.A.(HON'S) IN INTERIOR ARCHITECTURE -Ar.MOHIUDDIN.pdf
PPTX
Orientation - ARALprogram of Deped to the Parents.pptx
PDF
Classroom Observation Tools for Teachers
PPTX
master seminar digital applications in india
PDF
Yogi Goddess Pres Conference Studio Updates
PDF
grade 11-chemistry_fetena_net_5883.pdf teacher guide for all student
PPTX
Cell Structure & Organelles in detailed.
A GUIDE TO GENETICS FOR UNDERGRADUATE MEDICAL STUDENTS
Computing-Curriculum for Schools in Ghana
Tissue processing ( HISTOPATHOLOGICAL TECHNIQUE
Anesthesia in Laparoscopic Surgery in India
Chapter 2 Heredity, Prenatal Development, and Birth.pdf
What if we spent less time fighting change, and more time building what’s rig...
Complications of Minimal Access Surgery at WLH
2.FourierTransform-ShortQuestionswithAnswers.pdf
Supply Chain Operations Speaking Notes -ICLT Program
STATICS OF THE RIGID BODIES Hibbelers.pdf
202450812 BayCHI UCSC-SV 20250812 v17.pptx
Practical Manual AGRO-233 Principles and Practices of Natural Farming
school management -TNTEU- B.Ed., Semester II Unit 1.pptx
OBE - B.A.(HON'S) IN INTERIOR ARCHITECTURE -Ar.MOHIUDDIN.pdf
Orientation - ARALprogram of Deped to the Parents.pptx
Classroom Observation Tools for Teachers
master seminar digital applications in india
Yogi Goddess Pres Conference Studio Updates
grade 11-chemistry_fetena_net_5883.pdf teacher guide for all student
Cell Structure & Organelles in detailed.

Difficult GMAT Geometry Data Sufficiency - Q51 Series

  • 1. Geometry : Right Triangles Data Sufficiency – Question 9
  • 2. Question a, b, and c are sides of a right triangle. What is the area of the triangle? Statement 1 : a = 4 Statement 2 : a + b + c = 12
  • 3. ◴Step 1 : When is the data sufficient? What information do we need to get the answer?
  • 4. Answer these questions before analyzing the statements. What is the area of the triangle? When is the data sufficient? The data is sufficient when we are able to find a unique value for the area of the right triangle.
  • 5. Answer these questions before analyzing the statements. What is the area of the triangle? When is the data sufficient? What information is needed? The data is sufficient when we are able to find a unique value for the area of the right triangle. Base and height of the triangle.
  • 6. Answer these questions before analyzing the statements. What is the area of the triangle? When is the data sufficient? What information is needed? The data is sufficient when we are able to find a unique value for the area of the right triangle. Base and height of the triangle. 1. Check to see whether more than one triangle is possible with the data given. 2. Sides of triangles need not be integers. i.e., sides of right triangles that are not Pythagorean triplets exist. Watch out for
  • 7. ◴Step 2: Evaluate statement (1) ALONE
  • 8. 02 Statement 1: a = 4 Statement 1: a = 4; Statement 2: a + b + c = 12. What is the area of the triangle?
  • 9. 02 Statement 1: a = 4 · We cannot find the area of the right triangle with information about only one of the sides and no other information about the triangle. Statement 1: a = 4; Statement 2: a + b + c = 12. What is the area of the triangle?
  • 10. 02 Statement 1: a = 4 · We cannot find the area of the right triangle with information about only one of the sides and no other information about the triangle. Statement 1: a = 4; Statement 2: a + b + c = 12. What is the area of the triangle? Choices narrow down to B, C or E. Eliminate choices A and D Statement 1 alone is NOT sufficient
  • 11. ◴Step 3: Evaluate statement (2) ALONE
  • 12. 03 Statement 2: a + b + c = 12 · The sides of the triangle could be 3, 4, 5 or the sides could be in the ratio of 1 : 1 : 2 with a perimeter of 12. Statement 1: a = 4; Statement 2: a + b + c = 12. What is the area of the triangle?
  • 13. 03 Statement 2: a + b + c = 12 · The sides of the triangle could be 3, 4, 5 or the sides could be in the ratio of 1 : 1 : 2 with a perimeter of 12. Statement 1: a = 4; Statement 2: a + b + c = 12. What is the area of the triangle? · The area will be different for both the right triangles with the same perimeter.
  • 14. 03 Statement 2: a + b + c = 12 · The sides of the triangle could be 3, 4, 5 or the sides could be in the ratio of 1 : 1 : 2 with a perimeter of 12. Statement 1: a = 4; Statement 2: a + b + c = 12. What is the area of the triangle? · The area will be different for both the right triangles with the same perimeter. · We cannot find a unique value for the area of the right triangle with information about only the perimeter of the triangle.
  • 15. 03 Statement 2: a + b + c = 12 · The sides of the triangle could be 3, 4, 5 or the sides could be in the ratio of 1 : 1 : 2 with a perimeter of 12. Statement 1: a = 4; Statement 2: a + b + c = 12. What is the area of the triangle? · The area will be different for both the right triangles with the same perimeter. · We cannot find a unique value for the area of the right triangle with information about only the perimeter of the triangle. Choices narrow down to C or E. Eliminate choice B Statement 2 alone is NOT sufficient
  • 16. ◴Step 4: Combine the two statements
  • 17. 04 a = 4 and a + b + c = 12. Check whether more than one triangle exists. · If a = 4 and a + b + c = 12, then b + c = 8. So, b = 8 - c Statement 1: a = 4; Statement 2: a + b + c = 12. What is the area of the triangle?
  • 18. 04 a = 4 and a + b + c = 12. Check whether more than one triangle exists. · If a = 4 and a + b + c = 12, then b + c = 8. So, b = 8 - c Statement 1: a = 4; Statement 2: a + b + c = 12. What is the area of the triangle? · One of b or c is the hypotenuse as the hypotenuse is the longest side of a right triangle and a which measures 4 cannot be the longest side of a right triangle whose perimeter is 12.
  • 19. 04 a = 4 and a + b + c = 12. Check whether more than one triangle exists. · If a = 4 and a + b + c = 12, then b + c = 8. So, b = 8 - c Statement 1: a = 4; Statement 2: a + b + c = 12. What is the area of the triangle? · One of b or c is the hypotenuse as the hypotenuse is the longest side of a right triangle and a which measures 4 cannot be the longest side of a right triangle whose perimeter is 12. · Applying Pythagoras theorem, 42 + c2 = (8 – c)2. 16 + c2 = 64 + c2 – 16c Or 16c = 80. So, c = 5. And b = 8 – c = 8 – 5 = 3. Using the two statements we have found all 3 sides. So, we can find a unique value for the area.
  • 20. 04 a = 4 and a + b + c = 12. Check whether more than one triangle exists. · If a = 4 and a + b + c = 12, then b + c = 8. So, b = 8 - c Statement 1: a = 4; Statement 2: a + b + c = 12. What is the area of the triangle? · One of b or c is the hypotenuse as the hypotenuse is the longest side of a right triangle and a which measures 4 cannot be the longest side of a right triangle whose perimeter is 12. · Applying Pythagoras theorem, 42 + c2 = (8 – c)2. 16 + c2 = 64 + c2 – 16c Or 16c = 80. So, c = 5. And b = 8 – c = 8 – 5 = 3. Using the two statements we have found all 3 sides. So, we can find a unique value for the area. Correct answer : Choice C.Statements TOGETHER are sufficient
  • 21. More Hard Math Questions Visit www.q-51.com Queries, feedback? Reach us at info@4gmat.com GMAT Classes @ Chennai, India Weekend and weekday GMAT classes by US B School graduates, GMAT 98%lers. chennai.4gmat.com or +91 95000 48484 GMAT Classes @ Bangalore, India Weekend classes by US B school graduates. bangalore.4gmat.com or +91 74060 48484