About ellipse, an example of
learning shifts on Internet
Danut Dragoi, PhD
California
01/26/2017
2
Dandelin spheres (1822!)
3
Eccentricity ratio
-If the point P is on ellipse and point
J is the projection of point P on line
t, and J' is the projection of P on line
t', (PJ=d, PJ'=d', d+d'=const).
-Triangles PJS and PTJ' are similar
(S is on the small circle and ST line
goes through V, PF=PS as tangents
to a sphere, JS || J'T), we have the
eccentricity equations:
PF/PJ=PS/PJ=PT/PJ'=PF'/PJ'. If
MN=2a, FF'=2c, and P is chosen to
be on either M or N point, d is now
an unknown, we have the equation:
(a-c)/d=(a+c)/(2a+d)----------(1)
From Equation (1) d=(a*a/c)-a and
e=(a-c)/[(a*a/c)-a)]=c/a, e<1.
4
Eccentricity as a function of the radii
of Dandelin's Spheres
If we note with r1
and r2
, r2
>r1
, the radii of the Dandelin's
spheres and d the distance between their centers (do
not confuse this d with the variable PJ=d in slide #3)
we can easily calculate FF' and MN as:
FF'=SQRT(d2
-(r2
+r1
)2
)=2c--------------(2)
MN=SQRT(d2
-(r2
-r1
)2
)=2a--------------(3)

And the eccentricity e as:
e=SQRT(d2
-(r2
+r1
)2
)/SQRT(d2
-(r2
-r1
)2
)-----(4)
5
Position of the directrix as a function
of the radii of Dandelin's Spheres

Since a and c are known, Equations 2 and 3
provide b=SQRT(a*a-c*c)

In the slide #4 we found the directrix located
outside the ellipse at the distance [(a*a/c)-a]
symmetrically from M and N points (see slide
#3). Is convenient to refer to the distance from
the focus points, [(a*a/c)-a]+(a-c), therefore:
MJ=NJ'=(a*a-c*c)/c=
=(1/4)*[(r2+r1)*(r2+r1)-(r2-r1)*(r2-r1)]/c=
=2r1r2/SQRT[d*d-(r2+r1)*(r2+r1)]---------(5)
6
Types of sections in a double cone
that can be treated with the model
described in here for ellipse
Circle-------Ellipse-----Hyperbola--Parabola
http://math2.org/math/algebra/conics.htm
7
Conclusion

Using the learning shifts suggested in a
previous posting, link below,
the Internet is found very helpful on fully
describing the ellipse utilizing the synthetic
geometry in space and plane.

The method shown could be applied easily to
other conics, hyperbola, and parabola.
https://www.linkedin.com/pulse/learning-shifts-internet-era-danut-dragoi?trk=mp-reader-
card

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Ellipse as an-example-learning- shifts-on-internet-era

  • 1. About ellipse, an example of learning shifts on Internet Danut Dragoi, PhD California 01/26/2017
  • 3. 3 Eccentricity ratio -If the point P is on ellipse and point J is the projection of point P on line t, and J' is the projection of P on line t', (PJ=d, PJ'=d', d+d'=const). -Triangles PJS and PTJ' are similar (S is on the small circle and ST line goes through V, PF=PS as tangents to a sphere, JS || J'T), we have the eccentricity equations: PF/PJ=PS/PJ=PT/PJ'=PF'/PJ'. If MN=2a, FF'=2c, and P is chosen to be on either M or N point, d is now an unknown, we have the equation: (a-c)/d=(a+c)/(2a+d)----------(1) From Equation (1) d=(a*a/c)-a and e=(a-c)/[(a*a/c)-a)]=c/a, e<1.
  • 4. 4 Eccentricity as a function of the radii of Dandelin's Spheres If we note with r1 and r2 , r2 >r1 , the radii of the Dandelin's spheres and d the distance between their centers (do not confuse this d with the variable PJ=d in slide #3) we can easily calculate FF' and MN as: FF'=SQRT(d2 -(r2 +r1 )2 )=2c--------------(2) MN=SQRT(d2 -(r2 -r1 )2 )=2a--------------(3)  And the eccentricity e as: e=SQRT(d2 -(r2 +r1 )2 )/SQRT(d2 -(r2 -r1 )2 )-----(4)
  • 5. 5 Position of the directrix as a function of the radii of Dandelin's Spheres  Since a and c are known, Equations 2 and 3 provide b=SQRT(a*a-c*c)  In the slide #4 we found the directrix located outside the ellipse at the distance [(a*a/c)-a] symmetrically from M and N points (see slide #3). Is convenient to refer to the distance from the focus points, [(a*a/c)-a]+(a-c), therefore: MJ=NJ'=(a*a-c*c)/c= =(1/4)*[(r2+r1)*(r2+r1)-(r2-r1)*(r2-r1)]/c= =2r1r2/SQRT[d*d-(r2+r1)*(r2+r1)]---------(5)
  • 6. 6 Types of sections in a double cone that can be treated with the model described in here for ellipse Circle-------Ellipse-----Hyperbola--Parabola http://math2.org/math/algebra/conics.htm
  • 7. 7 Conclusion  Using the learning shifts suggested in a previous posting, link below, the Internet is found very helpful on fully describing the ellipse utilizing the synthetic geometry in space and plane.  The method shown could be applied easily to other conics, hyperbola, and parabola. https://www.linkedin.com/pulse/learning-shifts-internet-era-danut-dragoi?trk=mp-reader- card