exponential_growth_and_decay_models_notes_ppt.ppt
- 2. If a quantity increases by the same proportion r in each unit of time, then the quantity displays exponential growth and can be modeled by the equation y C r t ( ) 1 Where C = initial amount r = growth rate (percent written as a decimal) t = time where t ≠0 (1+r) = growth factor where 1 + r > 1
- 3. EXPONENTIAL GROWTH MODEL WRITING EXPONENTIAL GROWTH MODELS A quantity is growing exponentially if it increases by the same percent in each time period. C is the initial amount. t is the time period. (1 + r) is the growth factor, r is the growth rate. The percent of increase is 100r. y = C (1 + r)t
- 4. You deposit $1500 in an account that pays 2.3% interest compounded yearly, 1) What was the initial principal (P) invested? 2) What is the growth rate (r)? The growth factor? 3) Using the equation A = P(1+r)t, how much money would you have after 2 years if you didn’t deposit any more money? 3) A P r A A t ( ) ( . ) $ . 1 1500 1 0 023 1569 79 2 1) The initial principal (P) is $1500. 2) The growth rate (r) is 0.023. The growth factor is 1.023.
- 5. If a quantity decreases by the same proportion r in each unit of time, then the quantity displays exponential decay and can be modeled by the equation y C r t ( ) 1 Where C = initial amount r = growth rate (percent written as a decimal) t = time where t ≠ 0 (1 - r) = decay factor where 1 - r < 1
- 6. WRITING EXPONENTIAL DECAY MODELS A quantity is decreasing exponentially if it decreases by the same percent in each time period. EXPONENTIAL DECAY MODEL C is the initial amount. t is the time period. (1 – r) is the decay factor, r is the decay rate. The percent of decrease is 100r. y = C (1 – r)t
- 7. You buy a new car for $22,500. The car depreciates at the rate of 7% per year, 1) What was the initial amount invested? 2) What is the decay rate? The decay factor? 3) What will the car be worth after the first year? The second year? 1) The initial investment was $22,500. 2) The decay rate is 0.07. The decay factor is 0.93. 3 1 22 500 1 0 07 20 925 1 ) ( ) , ( . ) $ , y C r y y t y C r y y t ( ) , ( . ) $ . 1 22 500 1 0 07 19460 25 2
- 8. Writing an Exponential Growth Model A population of 20 rabbits is released into a wildlife region. The population triples each year for 5 years.
- 9. A population of 20 rabbits is released into a wildlife region. The population triples each year for 5 years. b. What is the population after 5 years? Writing an Exponential Growth Model SOLUTION After 5 years, the population is P = C(1 + r)t Exponential growth model = 20(1 + 2)5 = 20 • 35 = 4860 Help Substitute C, r, and t. Simplify. Evaluate. There will be about 4860 rabbits after 5 years.
- 10. A Model with a Large Growth Factor GRAPHING EXPONENTIAL GROWTH MODELS Graph the growth of the rabbit population. SOLUTION Make a table of values, plot the points in a coordinate plane, and draw a smooth curve through the points. t P 4860 60 180 540 1620 20 5 1 2 3 4 0 0 1000 2000 3000 4000 5000 6000 1 7 2 3 4 5 6 Time (years) Population P = 20(3)t Here, the large growth factor of 3 corresponds to a rapid increase
- 11. Writing an Exponential Decay Model COMPOUND INTEREST From 1982 through 1997, the purchasing power of a dollar decreased by about 3.5% per year. Using 1982 as the base for comparison, what was the purchasing power of a dollar in 1997? SOLUTION Let y represent the purchasing power and let t = 0 represent the year 1982. The initial amount is $1. Use an exponential decay model. = (1)(1 – 0.035)t = 0.965t y = C(1 – r)t y = 0.96515 Exponential decay model Substitute 1 for C, 0.035 for r. Simplify. Because 1997 is 15 years after 1982, substitute 15 for t. Substitute 15 for t. The purchasing power of a dollar in 1997 compared to 1982 was $0.59. 0.59
- 12. Graphing the Decay of Purchasing Power GRAPHING EXPONENTIAL DECAY MODELS Graph the exponential decay model in the previous example. Use the graph to estimate the value of a dollar in ten years. SOLUTION Make a table of values, plot the points in a coordinate plane, and draw a smooth curve through the points. 0 0.2 0.4 0.6 0.8 1.0 1 12 3 5 7 9 11 Years From Now Purchasing Power (dollars) 2 4 6 8 10 t y 0.837 0.965 0.931 0.899 0.867 1.00 5 1 2 3 4 0 0.7 0.808 0.779 0.752 0.726 10 6 7 8 9 Your dollar of today will be worth about 70 cents in ten years. y = 0.965t Help
- 13. 1)Make a table of values for the function using x-values of –2, -1, 0, 1, and Graph the function. Does this function represent exponential growth or exponential decay? y x 1 6
- 14. x y x 1 6 2 1 6 6 2 2 1 1 6 6 1 1 0 1 6 0 1 1 6 1 2 1 6 2 y 36 6 1 1 6 1 36 This function represents exponential decay.
- 15. 2) Your business had a profit of $25,000 in 1998. If the profit increased by 12% each year, what would your expected profit be in the year 2010? Identify C, t, r, and the growth factor. Write down the equation you would use and solve.
- 16. C = $25,000 T = 12 R = 0.12 Growth factor = 1.12 y C r y y y t ( ) $ , ( . ) $ , ( . ) $ , . 1 25 000 1 0 12 25 000 112 97 399 40 12 12
- 17. 3) Iodine-131 is a radioactive isotope used in medicine. Its half-life or decay rate of 50% is 8 days. If a patient is given 25mg of iodine-131, how much would be left after 32 days or 4 half- lives. Identify C, t, r, and the decay factor. Write down the equation you would use and solve.
- 18. C = 25 mg T = 4 R = 0.5 Decay factor = 0.5 y C r y mg y mg y mg t ( ) ( . ) ( . ) . 1 25 1 0 5 25 0 5 1 56 4 4
- 19. GRAPHING EXPONENTIAL DECAY MODELS EXPONENTIAL GROWTH AND DECAY MODELS y = C (1 – r)t y = C (1 + r)t EXPONENTIAL GROWTH MODEL EXPONENTIAL DECAY MODEL 1 + r > 1 0 < 1 – r < 1 CONCEPT SUMMARY An exponential model y = a • bt represents exponential growth if b > 1 and exponential decay if 0 < b < 1. C is the initial amount. t is the time period. (1 – r) is the decay factor, r is the decay rate. (1 + r) is the growth factor, r is the growth rate. (0,C) (0,C)