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Force system in spaceEquilibrium of Concurrent Forces in SpaceStaticsOf rigid bodies
EQUILIBRIUM is defined as that condition when the resultant of the system of force is zero.StaticsOf rigid bodiesEquilibrium Equations;
Example:The framework shown is composed of three members AB, AC & AD. Points B & C are in the same horizontal plane. Points C & D are in the same vertical plane. At A a 1000lb force acts in a direction parallel to the x-axis. Point B is located at the origin, A(0,+20,0),D(-10,6,5) & C(-10,0,-10)Neglecting the weights of the members, determine the forces in AB, AC & AD.y1000 lbA20 ftC10 ftDB10 ftxo10 ft5 ft6 ftz
Example:The framework shown is composed of three members AB, AC & AD. Points B & C are in the same horizontal plane. Points C & D are in the same vertical plane. At A a 1000lb force acts in a direction parallel to the x-axis. Point B is located at the origin, A(0,+20,0),D(-10,6,5) & C(-10,0,-10)Neglecting the weights of the members, determine the forces in AB, AC & AD.y1000 lbA20 ftCzCxC10 ftCyDxDBxo10 ft5 ft6 ftDzByDyz
yYc1000 lb0(10)(15)-Dx+(1000)=A=Dx667 lb20 ftx = 10 ftCzCx15 fty = 20 – 6 = 14 ftz = 5 ftC10 ftCy10 ftDxDBd = 17.916 ftxo10 ft6 ft5 ftDy = 933 lbDzByDyDz = 333 lbzAD = 1192 lb T

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Force system in space

  • 1. Force system in spaceEquilibrium of Concurrent Forces in SpaceStaticsOf rigid bodies
  • 2. EQUILIBRIUM is defined as that condition when the resultant of the system of force is zero.StaticsOf rigid bodiesEquilibrium Equations;
  • 3. Example:The framework shown is composed of three members AB, AC & AD. Points B & C are in the same horizontal plane. Points C & D are in the same vertical plane. At A a 1000lb force acts in a direction parallel to the x-axis. Point B is located at the origin, A(0,+20,0),D(-10,6,5) & C(-10,0,-10)Neglecting the weights of the members, determine the forces in AB, AC & AD.y1000 lbA20 ftC10 ftDB10 ftxo10 ft5 ft6 ftz
  • 4. Example:The framework shown is composed of three members AB, AC & AD. Points B & C are in the same horizontal plane. Points C & D are in the same vertical plane. At A a 1000lb force acts in a direction parallel to the x-axis. Point B is located at the origin, A(0,+20,0),D(-10,6,5) & C(-10,0,-10)Neglecting the weights of the members, determine the forces in AB, AC & AD.y1000 lbA20 ftCzCxC10 ftCyDxDBxo10 ft5 ft6 ftDzByDyz
  • 5. yYc1000 lb0(10)(15)-Dx+(1000)=A=Dx667 lb20 ftx = 10 ftCzCx15 fty = 20 – 6 = 14 ftz = 5 ftC10 ftCy10 ftDxDBd = 17.916 ftxo10 ft6 ft5 ftDy = 933 lbDzByDyDz = 333 lbzAD = 1192 lb T