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Fourier Series ,Fourier
Fourier Series ,Fourier
Integral, Fourier
Integral, Fourier
Transform
Transform
Introduction
Jean Baptiste Joseph Fourier
(Mar21st 1768 –May16th 1830)
French mathematician, physicist
Main Work:
(The Analytic Theory of Heat)
•Any function of a variable, whether continuous or
discontinuous, can be expanded in a series of sines of
multiples of the variable (Incorrect)
•The concept of dimensional homogeneity in
equations
•Proposal of his partial differential equation for
conductive diffusion of heat
Discovery of the "greenhouse effect“
•Fourier series is very useful in solving ordinary and
partial differential equation.
http://en.wikipedia.org/wiki/Joseph_Fourier
Even, Odd, and Periodic Functions
Even, Odd, and Periodic Functions
0

T
f 
 
Fourier Series of a Periodic Function
Fourier Series of a Periodic Function
Definition : A Fourier series may be defined as an expansion of a
function in a series of sines and cosines such as ,
The coefficients are related to the periodic function f(x)
by definite integrals:
Henceforth we assume f satisfies the following (Dirichlet)
conditions:
(1) f(x) is a periodic function;
(2) f(x) has only a finite number of finite discontinuities;
(3) f(x) has only a finite number of extrem values, maxima and
minima in the interval [0,2p].
EULER’S FORMULA
EULER’S FORMULA
The formula for a Fourier series is: N
We have formulae for the coefficients (for the derivations see the
course notes):
One very important property of sines and cosines is their orthogonality,
expressed by:



























n
n
n
n
T
x
n
b
T
x
n
a
a
x
f
1
0
2
sin
2
cos
)
(





2
2
0 )
(
1
T
T
dx
x
f
T
a 








2
2
2
cos
)
(
2
T
T
n dx
T
x
n
x
f
T
a










2
2
2
sin
)
(
2
T
T
n dx
T
x
n
x
f
T
b






















 m
n
T
m
n
dx
T
x
m
T
x
n
T
T
2
0
2
sin
2
sin
2
2


n
m
dx
T
x
m
T
x
n
T
T
,
all
for
0
2
sin
2
cos
2
2

















These formulae are used in the derivation of the formulae for
Example – Find the coefficients for the Fourier series of:
Find
)
(
)
2
(
0
0
)
(
x
f
x
f
x
x
x
x
x
f















0
a
n
n b
a ,
Find ,
0
a



2
2
0 )
(
1
T
T
dx
x
f
T
a 






dx
x
f
a )
(
2
1
0




 0
0
1
xdx
a
2
0


 a
f (x) is an even function so:






dx
x
f
a )
(
2
1
0




 0
0 )
(
1
dx
x
f
a

 0
2
0
2
1








x
a
Find n
a









2
2
2
cos
)
(
2
T
T
n dx
T
x
n
x
f
T
a












 


dx
x
n
x
f
an
2
2
cos
)
(
1
Since both functions are even their product is even:
 






dx
nx
x
f
an cos
)
(
1  




 0
cos
2
dx
nx
x
an
n
b









2
2
2
sin
)
(
2
T
T
n dx
T
x
n
x
f
T
b












 


dx
x
n
x
f
bn
2
2
sin
)
(
1
 






dx
nx
x
f
bn sin
)
(
1
0

 n
b
So we can put the coefficients back into the Fourier series formula:



























n
n
n
n
T
x
n
b
T
x
n
a
a
x
f
1
0
2
sin
2
cos
)
(


 
   















n
n
n
nx
n
x
f
1
2
cos
1
1
2
2
)
(


    





 x
x
x
f 3
cos
9
4
0
cos
4
2
)
(



Summary of finding coefficients
Summary of finding coefficients
function
even
function
odd
function
neither
0
a
n
a
n
b
0
)
(
1 2
2
0 
 

T
T
dx
x
f
T
a









2
2
2
cos
)
(
2
T
T
n dx
T
x
n
x
f
T
a

Though maybe easy to find
using geometry









2
2
2
sin
)
(
2
T
T
n dx
T
x
n
x
f
T
b










2
2
2
sin
)
(
2
T
T
n dx
T
x
n
x
f
T
b

0
0
0
)
(
1 2
2
0 
 

T
T
dx
x
f
T
a









2
2
2
cos
)
(
2
T
T
n dx
T
x
n
x
f
T
a

Though maybe easy to find
using geometry
0
Half range Expansions
Half range Expansions
It often happens in applications, especially when we solve partial
differential equations by the method of separation of variables, that we
need to expand a given function f in a Fourier series, where f is
defined only on a finite interval.
We define an “extended function”, say fext, so that fext is periodic in the
domain of -∞< x < ∞, and fext=f(x) on the original interval 0<x<L.
There can be infinite number of such extensions.
Four extensions: half- and quarter- range cosine and sine extensions,
which are based on symmetry or antisymmetry about the endpoints
x=0 and x=L.
HRC (half range cosines)
HRC (half range cosines)
fext is symmetric about x=0 and
also about x=L. Because of its
symmetry about x=0, fext is an
even function, and its Fourier
series will contain only cosines, no sines. Further, its
period is 2L, so L is half the period.
Fourier-Series SAMPLE PRESENTATION FOR LEARNING
HRS (half range sines)
HRS (half range sines)
Complex exponential form of Fourier
Complex exponential form of Fourier
series
series
Fourier-Series SAMPLE PRESENTATION FOR LEARNING
Fourier-Series SAMPLE PRESENTATION FOR LEARNING
PARSEVAL’S FORMULA
PARSEVAL’S FORMULA
(
1
)
If a function has a Fourier series given by
then Bessel's inequality becomes an equality known as Parseval's
theorem. From (1),
Integrating
so
Math for CS Lecture 11 19
Fourier Integral
Fourier Integral
If f(x) and f’(x) are piecewise continuous in every finite interval, and f(x) is
absolutely integrable on R, i.e.
converges, then
Remark: the above conditions are sufficient, but not necessary.
 


















 dw
dt
t
f
e
e
x
f
x
f iwt
iwx
)
(
2
1
)]
(
)
(
[
2
1

DIFFERENT FORMS OF FOURIER
DIFFERENT FORMS OF FOURIER
INTEGRAL THEOREM
INTEGRAL THEOREM
Complex or exponential form
Complex or exponential form
INFINITE FOURIER TRANSFORM
INFINITE FOURIER TRANSFORM
Fourier Sine Transform
)
(
ˆ
of
transform
sine
Fourier
inverse
the
is
)
(
)
sin(
)
(
ˆ
2
)
sin(
)
(
)
(
f(x)
of
transform
sine
Fourier
the
called
is
)
(
ˆ
by x
replaced
been
has
,
)
sin(
)
(
2
)
(
2
)
(
ˆ
)
(
ˆ
2
Define
.
)
sin(
)
(
2
)
(
where
,
)
sin(
)
(
)
(
:
f(x)
function
odd
an
for
Similarly,
0
0
0
0
0
w
f
x
f
dw
wx
w
f
dw
wx
w
B
x
f
w
f
v
dx
wx
x
f
w
B
w
f
w
f
B(w)
dv
wv
v
f
w
B
dw
wx
w
B
x
f
S
S
S
S
S






















Math for CS Lecture 11 24
Properties of Fourier transform
Properties of Fourier transform
1 Linearity:
For any constants a, b the following equality holds:
2 Scaling:
For any constant c, the following equality holds:
)
(
)
(
)}
(
{
)}
(
{
)}
(
)
(
{ w
bG
w
aF
t
g
bF
t
f
aF
t
bg
t
af
F 




)
(
|
|
1
)}
(
{
c
w
F
c
ct
f
F 
Math for CS Lecture 11 25
3. Time shifting:
proof:
4. Frequency shifting:
Proof:
)
(
)}
(
{ 0
0 w
F
e
t
t
f
F iwt



du
e
u
f
e
dt
e
t
t
f
t
t
f
F iwu
iwt
iwt 









 


 )
(
)
(
)}
(
{ 0
0
0
)
(
)}
(
{ 0
0
w
w
F
t
f
e
F iwt


)
(
)
(
)}
(
{ 0
0
0
w
w
F
dt
e
t
f
e
t
f
e
F iwt
iwt
t
iw


 





)
(
2
)}
(
{ w
f
t
F
F 
 






 dw
e
w
F
w
f
F
t
f iwt
)
(
2
1
)}
(
{
)
( 1

)}
(
{
)
(
2
1
)
(
2 t
F
F
dt
e
t
F
w
f itw


 






Math for CS Lecture 11 26
6. Modulation:
Proof:
Using Euler formula, properties 1 (linearity) and 4 (frequency shifting):
)]
(
)
(
[
2
1
)}
sin(
)
(
{
)]
(
)
(
[
2
1
)}
cos(
)
(
{
0
0
0
0
0
0
w
w
F
w
w
F
t
w
t
f
F
w
w
F
w
w
F
t
w
t
f
F








)]
(
)
(
[
2
1
)}]
(
{
)}
(
{
[
2
1
)}
cos(
)
(
{
0
0
0
0
0
w
w
F
w
w
F
t
f
e
F
t
f
e
F
t
w
t
f
F t
iw
t
iw





 
Periodically forced oscillation: mass-spring
Periodically forced oscillation: mass-spring
system
system
m = mass
c = damping factor
k = spring constant
F(t) = 2L- periodic forcing function
mx’’(t) + cx’(t) + k x(t) = F(t)
http://www.jirka.org/diffyqs/
Differential Equations for Engineers
m F(t)
k
The particular solution xp of the above equation is periodic with
the same period as F(t) .
The coefficients are k=2, and m=1 and c=0 (for simplicity). The
units are the mks units (meters-kilograms- seconds). There is a
jetpack strapped to the mass, which fires with a force of 1
newton for 1 second and then is off for 1 second, and so on.
We want to find the steady periodic solution.
The equation is:
x’’ + 2x = F(t)
Where F(t) => 0 if -1<t<0
1 if 0<t<1
THANK YOU
THANK YOU

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Fourier-Series SAMPLE PRESENTATION FOR LEARNING

  • 1. Fourier Series ,Fourier Fourier Series ,Fourier Integral, Fourier Integral, Fourier Transform Transform
  • 2. Introduction Jean Baptiste Joseph Fourier (Mar21st 1768 –May16th 1830) French mathematician, physicist Main Work: (The Analytic Theory of Heat) •Any function of a variable, whether continuous or discontinuous, can be expanded in a series of sines of multiples of the variable (Incorrect) •The concept of dimensional homogeneity in equations •Proposal of his partial differential equation for conductive diffusion of heat Discovery of the "greenhouse effect“ •Fourier series is very useful in solving ordinary and partial differential equation. http://en.wikipedia.org/wiki/Joseph_Fourier
  • 3. Even, Odd, and Periodic Functions Even, Odd, and Periodic Functions 0  T f   
  • 4. Fourier Series of a Periodic Function Fourier Series of a Periodic Function Definition : A Fourier series may be defined as an expansion of a function in a series of sines and cosines such as , The coefficients are related to the periodic function f(x) by definite integrals: Henceforth we assume f satisfies the following (Dirichlet) conditions: (1) f(x) is a periodic function; (2) f(x) has only a finite number of finite discontinuities; (3) f(x) has only a finite number of extrem values, maxima and minima in the interval [0,2p].
  • 5. EULER’S FORMULA EULER’S FORMULA The formula for a Fourier series is: N We have formulae for the coefficients (for the derivations see the course notes): One very important property of sines and cosines is their orthogonality, expressed by:                            n n n n T x n b T x n a a x f 1 0 2 sin 2 cos ) (      2 2 0 ) ( 1 T T dx x f T a          2 2 2 cos ) ( 2 T T n dx T x n x f T a           2 2 2 sin ) ( 2 T T n dx T x n x f T b                        m n T m n dx T x m T x n T T 2 0 2 sin 2 sin 2 2  
  • 6. n m dx T x m T x n T T , all for 0 2 sin 2 cos 2 2                  These formulae are used in the derivation of the formulae for Example – Find the coefficients for the Fourier series of: Find ) ( ) 2 ( 0 0 ) ( x f x f x x x x x f                0 a n n b a ,
  • 7. Find , 0 a    2 2 0 ) ( 1 T T dx x f T a        dx x f a ) ( 2 1 0      0 0 1 xdx a 2 0    a f (x) is an even function so:       dx x f a ) ( 2 1 0      0 0 ) ( 1 dx x f a   0 2 0 2 1         x a
  • 8. Find n a          2 2 2 cos ) ( 2 T T n dx T x n x f T a                 dx x n x f an 2 2 cos ) ( 1 Since both functions are even their product is even:         dx nx x f an cos ) ( 1        0 cos 2 dx nx x an n b          2 2 2 sin ) ( 2 T T n dx T x n x f T b                 dx x n x f bn 2 2 sin ) ( 1         dx nx x f bn sin ) ( 1 0   n b
  • 9. So we can put the coefficients back into the Fourier series formula:                            n n n n T x n b T x n a a x f 1 0 2 sin 2 cos ) (                        n n n nx n x f 1 2 cos 1 1 2 2 ) (              x x x f 3 cos 9 4 0 cos 4 2 ) (   
  • 10. Summary of finding coefficients Summary of finding coefficients function even function odd function neither 0 a n a n b 0 ) ( 1 2 2 0     T T dx x f T a          2 2 2 cos ) ( 2 T T n dx T x n x f T a  Though maybe easy to find using geometry          2 2 2 sin ) ( 2 T T n dx T x n x f T b           2 2 2 sin ) ( 2 T T n dx T x n x f T b  0 0 0 ) ( 1 2 2 0     T T dx x f T a          2 2 2 cos ) ( 2 T T n dx T x n x f T a  Though maybe easy to find using geometry 0
  • 11. Half range Expansions Half range Expansions It often happens in applications, especially when we solve partial differential equations by the method of separation of variables, that we need to expand a given function f in a Fourier series, where f is defined only on a finite interval. We define an “extended function”, say fext, so that fext is periodic in the domain of -∞< x < ∞, and fext=f(x) on the original interval 0<x<L. There can be infinite number of such extensions. Four extensions: half- and quarter- range cosine and sine extensions, which are based on symmetry or antisymmetry about the endpoints x=0 and x=L.
  • 12. HRC (half range cosines) HRC (half range cosines) fext is symmetric about x=0 and also about x=L. Because of its symmetry about x=0, fext is an even function, and its Fourier series will contain only cosines, no sines. Further, its period is 2L, so L is half the period.
  • 14. HRS (half range sines) HRS (half range sines)
  • 15. Complex exponential form of Fourier Complex exponential form of Fourier series series
  • 18. PARSEVAL’S FORMULA PARSEVAL’S FORMULA ( 1 ) If a function has a Fourier series given by then Bessel's inequality becomes an equality known as Parseval's theorem. From (1), Integrating so
  • 19. Math for CS Lecture 11 19 Fourier Integral Fourier Integral If f(x) and f’(x) are piecewise continuous in every finite interval, and f(x) is absolutely integrable on R, i.e. converges, then Remark: the above conditions are sufficient, but not necessary.                      dw dt t f e e x f x f iwt iwx ) ( 2 1 )] ( ) ( [ 2 1 
  • 20. DIFFERENT FORMS OF FOURIER DIFFERENT FORMS OF FOURIER INTEGRAL THEOREM INTEGRAL THEOREM
  • 21. Complex or exponential form Complex or exponential form
  • 23. Fourier Sine Transform ) ( ˆ of transform sine Fourier inverse the is ) ( ) sin( ) ( ˆ 2 ) sin( ) ( ) ( f(x) of transform sine Fourier the called is ) ( ˆ by x replaced been has , ) sin( ) ( 2 ) ( 2 ) ( ˆ ) ( ˆ 2 Define . ) sin( ) ( 2 ) ( where , ) sin( ) ( ) ( : f(x) function odd an for Similarly, 0 0 0 0 0 w f x f dw wx w f dw wx w B x f w f v dx wx x f w B w f w f B(w) dv wv v f w B dw wx w B x f S S S S S                      
  • 24. Math for CS Lecture 11 24 Properties of Fourier transform Properties of Fourier transform 1 Linearity: For any constants a, b the following equality holds: 2 Scaling: For any constant c, the following equality holds: ) ( ) ( )} ( { )} ( { )} ( ) ( { w bG w aF t g bF t f aF t bg t af F      ) ( | | 1 )} ( { c w F c ct f F 
  • 25. Math for CS Lecture 11 25 3. Time shifting: proof: 4. Frequency shifting: Proof: ) ( )} ( { 0 0 w F e t t f F iwt    du e u f e dt e t t f t t f F iwu iwt iwt                ) ( ) ( )} ( { 0 0 0 ) ( )} ( { 0 0 w w F t f e F iwt   ) ( ) ( )} ( { 0 0 0 w w F dt e t f e t f e F iwt iwt t iw          ) ( 2 )} ( { w f t F F           dw e w F w f F t f iwt ) ( 2 1 )} ( { ) ( 1  )} ( { ) ( 2 1 ) ( 2 t F F dt e t F w f itw          
  • 26. Math for CS Lecture 11 26 6. Modulation: Proof: Using Euler formula, properties 1 (linearity) and 4 (frequency shifting): )] ( ) ( [ 2 1 )} sin( ) ( { )] ( ) ( [ 2 1 )} cos( ) ( { 0 0 0 0 0 0 w w F w w F t w t f F w w F w w F t w t f F         )] ( ) ( [ 2 1 )}] ( { )} ( { [ 2 1 )} cos( ) ( { 0 0 0 0 0 w w F w w F t f e F t f e F t w t f F t iw t iw       
  • 27. Periodically forced oscillation: mass-spring Periodically forced oscillation: mass-spring system system m = mass c = damping factor k = spring constant F(t) = 2L- periodic forcing function mx’’(t) + cx’(t) + k x(t) = F(t) http://www.jirka.org/diffyqs/ Differential Equations for Engineers m F(t) k
  • 28. The particular solution xp of the above equation is periodic with the same period as F(t) . The coefficients are k=2, and m=1 and c=0 (for simplicity). The units are the mks units (meters-kilograms- seconds). There is a jetpack strapped to the mass, which fires with a force of 1 newton for 1 second and then is off for 1 second, and so on. We want to find the steady periodic solution. The equation is: x’’ + 2x = F(t) Where F(t) => 0 if -1<t<0 1 if 0<t<1

Editor's Notes

  • #19: Outline: Central Scientific Problem – Artificial Intelligence Machine Learning: Definition Specifics Requirements Existing Solutions and their limitations Multiresolution Approximation: Limitation Our Approach. Results. Binarization. Plans.
  • #24: Outline: Central Scientific Problem – Artificial Intelligence Machine Learning: Definition Specifics Requirements Existing Solutions and their limitations Multiresolution Approximation: Limitation Our Approach. Results. Binarization. Plans.
  • #25: Outline: Central Scientific Problem – Artificial Intelligence Machine Learning: Definition Specifics Requirements Existing Solutions and their limitations Multiresolution Approximation: Limitation Our Approach. Results. Binarization. Plans.
  • #26: Outline: Central Scientific Problem – Artificial Intelligence Machine Learning: Definition Specifics Requirements Existing Solutions and their limitations Multiresolution Approximation: Limitation Our Approach. Results. Binarization. Plans.