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MINI PROJECT
             CSE205
TOPIC:Graphical reperesntation of stack



Submitted by:
SANJAY KUMAR CHAKRAVARTI
ROLL:A28
SEC:K2R13
                      Submitted to:
                  Miss.Deepika sukhija
                      Dept. cse
                      Lpu,phagwara
Acknowledgement


Apart from the efforts of me, the success of this project depends largely on the
encouragement and guidelines of many others. I take this opportunity to express
my gratitude to the people who have been instrumental in the successful
completion of this project.

I would like to show my greatest appreciation to Miss. Deepika sukhija I can’t say
thank you enough for his tremendous support and help. I feel motivated and
encouraged every time I attend his meeting. Without his encouragement and
guidance this project would not have materialized.

The guidance and support received from all the team members including Mr.
sanjeev kumar and Mr. Abhay kumar who contributed and are contributing to this
project, was vital for the success of the project. I am grateful for their constant
support and help.
CONTENT


TOPIC                                                   PAGE NO.
 .
1 ABSTRACT-------------------------------------------------- 04

2. INTRODUCTION------------------------------------------- 05
3.SOURCE CODE---------------------------------------------- 06-18
4.OUTPUTS------------------------------------------------------ 19-21
4.REFRENCES-------------------------------------------------- 22
ABSTRACT

This project was very important for me. In this project I have
show a graphical view of stacks for better understanding. It will
gives you many features as listed below:
  1. Graphical view
  2. Simple programming language
  3. Source code contains comments line where needed
  4. A best approach with graphics programming
INTRODUCTION


The Stack is a Memory Area where you can store data there and can get
back them again. In computer science, a stack is a last in, first out
(LIFO) abstract data type and linear data structure . A stack can have
any abstract data type as an element , but is characterized by two
fundamental operations, called PUSH and POP. The push operation adds
a new item to the top of the stack, or initializes the stack if it is empty. If
the stack is full and does not contain enough space to accept the given
item, the stack is then considered to be in an overflow state. The pop
operation removes an item from the top of the stack. A pop either
reveals previously concealed items, or results in an empty stack, but if
the stack is empty then it goes into underflow state (It means no items
are present in stack to be removed). A stack is a restricted data
structure , because only a small number of operations are performed on
it. The nature of the pop and push operations also means that stack
elements have a natural order. Elements are removed from the stack in
the reverse order to the order of their addition: therefore, the lower
elements are those that have been on the stack the longest.
Source code


#include<iostream.h>     //for cin, cout

#include<conio.h>      //for getche()

#include<ctype.h>      //for tolower() function

#include<stdlib.h>     //for itoa()

#include<GRAPHICS.H>          //to load graphics driver

#include<dos.h>    //for delay() function
/*_________________________________________________________________
________*//*_______________________________________________________
__________________*///These Functions prototypes are, for stack function.

int col=60 , row = 417 ,n ,x=60 , y=417 ,size=10
,arr[10]={12,56,23,46,32,89,11,99,12,66} , count = 0, top = 0;   //Global
Variables

char string[45];

void push( );

void pop( );

void stack();
void loadgraph();



void main()

{

clrscr();

char ch;

struct fillsettingstype fillinfo;



loadgraph();

setbkcolor(0);

setcolor(2);

do

{

rectangle(2,2,620,410);

rectangle(4,4,618,408);

line(0,30,620,30);

getfillsettings(&fillinfo);

line(0,32,620,32);

line(100,32,100,410);

moveto(180,15);

outtext("SANJAY KUMAR CHAKRAVARTI");

// circle(300,120,110);
setbkcolor(12);

gotoxy(37,5);

cout<<"Menu";

gotoxy(30,6);

cout<<"Stack        [s]";

gotoxy(30,8);

cout<<"Exit        [x]";

gotoxy(30,10);

cout<<"Enter Option [ ]";

ch=getche();

ch = tolower(ch);

gotoxy(30,15);

if(ch=='s')

stack();



}while(ch!='x');

cleardevice();

closegraph();

}

void loadgraph()

{

    clrscr();

    int driver = DETECT, mode, errorcode;
initgraph(&driver, &mode, "c:tcbgi");

    errorcode = graphresult();

    if (errorcode != grOk)

     {

     cout<<"Graphics error: n"<<(grapherrormsg(errorcode));

     cout<<"Press any key to halt:";

     getch();

     exit(1);

     }

}

void stack()

{

    cleardevice();

     moveto(400,60);

    outtext("STACK'S OPERATIONS");

    moveto(400,80);

    outtext("PUSH            [p]");

    moveto(400,100);

    outtext("POP         [o]");

    moveto(400,120);

    outtext("EXIT        [x]");

    moveto(300,125);

    outtext("Top");
itoa(top,string,10);

line(150,0,150,415);

outtextxy(308,450,string);

setbkcolor(3);

setcolor(14);

outtextxy(55,26,"NOW STACK:");

line(30,40,30,440);

int r=40;

for(int i = 1 ;i<12 ;i++)

{

    line(30,r,110,r);

    r+=40;

}

line(110,40,110,440);

r = 55;

for( i = 10 ;i>=1 ;i--)

{

    moveto(10,r);

    itoa(i,string,10);

    outtext(string) ;

    r+=40;

}

line(165,440,210,440);
line(165,440,165,460);

 line(210,440,210,460);

 line(165,460,210,460);

 setfillstyle(0, getmaxcolor());

char ch[2];

 do

  {

   moveto(400,140);

   outtext("ENTER OPTION ");

   ch[0]=getche();

   ch[0] = tolower(ch[0]);

   if(ch[0]=='p')

  { outtext("p");

      delay(500);

      bar(getx()-30,gety(),getx()+2,gety()+20);

if(size<1)

        {

        for(int i = 0 ;i<4 ; i++){

            moveto(420,170);

            outtext("Stack Overflow ");

            delay(1000);

            setfillstyle(0, getmaxcolor());

            bar(420 ,165 ,630 ,180);
delay(500);}

       }

else if( size>1)



       {

        size--;

        top++;

        push();

        bar(290,440,350,479);

        itoa(top,string,10);

        outtextxy(308,447,string);

        }}//end of Nested if

 else if(ch[0]=='o')




 {



     outtext("o");

     delay(500);

     bar(getx()-30,gety(),getx()+10,gety()+20);

if(size==10)

       {

        for(int i = 0 ;i<4 ; i++){
moveto(410,170);

            outtext("Stack, Underflow ");

            delay(1000);

            setfillstyle(0, getmaxcolor());

            bar(330 ,165 ,630 ,180);

            delay(500); }

            }

     else

            {

            top--;

            pop();

            bar(290,440,350,479);

            itoa(top,string,10);

            outtextxy(308,447,string);

            }

            }

}

while(ch[0]!='x');

}



void push()

{

    int a=178 , b=425       ;
moveto(178,447);

 itoa(arr[count],string,10);

 outtext(string);

 delay(10);

 bar(170,446,208,455);

 itoa(arr[count+1],string,10);

 moveto(178,447);

 outtext(string);

 moveto(a,b);

while(gety()!=y)

  {

   setfillstyle(0, getmaxcolor());

   circle(a+6,b+3,12);

   itoa(arr[count],string,10);

   outtext(string);

   delay(10);

   setfillstyle(0, getmaxcolor());

   bar(170 ,gety()-20 ,200 ,gety()+14);

   moveto(a,b);

   b--;

  }

 setfillstyle(0, getmaxcolor());

 circle(a+6,b+3,9);
outtext(string);

 moveto(125,b);

for(int j =0 ;j<6 ; j++)

   {

  outtext("<<--");

  delay(100);

  setfillstyle(0, getmaxcolor());

  bar(getx()-3 ,gety() ,getx() ,gety()+8);

  delay(100);

   }

delay(100);

 setfillstyle(0, getmaxcolor());

 bar(getx()-48 ,gety() ,getx() ,gety()+8);

delay(100);     delay(200);

while(getx()!=x+60)

   {

   setfillstyle(0, getmaxcolor());

   circle(a+6,b+3,9);

   itoa(arr[count],string,10);

   outtext(string);

   delay(10);

   setfillstyle(0, getmaxcolor());

   bar(getx()-20 ,gety()-10 ,getx()+70 ,gety()+20);
moveto(a,b);

         a--;

     }

    delay(100);

    moveto(60,gety());

    outtext(string);

    count++;

    y = y-40;

}

void pop()

{

    int a=120, b ;

    y = y + 40 ;

    b=y         ;

    moveto(120,y);

for(int j=0 ;j<6 ; j++)

     {

     outtext("®");

     delay(100);

     setfillstyle(0, getmaxcolor());

     bar(getx()-3 ,gety() ,getx() ,gety()+8);

     delay(100);

     }
delay(100);

setfillstyle(0, getmaxcolor());

bar(getx()-48 ,gety() ,getx() ,gety()+8);

delay(200);

moveto(60,gety());

setfillstyle(0, getmaxcolor());

bar(getx()-10 ,gety()-3 ,getx()+20 ,gety()+8);

delay(500);

while(getx()!=178)

 {

 setfillstyle(0, getmaxcolor());

 circle(a+6,b+3,12);

 moveto(a,gety());

 itoa(arr[count-1],string,10);

 outtext(string);

 delay(10);

 setfillstyle(0, getmaxcolor());

 bar(getx()-25 ,gety()-10 ,getx()+30 ,gety()+20);

 a++;

 }

delay(500);

while(gety()!=430)

 {
setfillstyle(0, getmaxcolor());

    circle(a+21,b+3,7);

    moveto(178,b);

    itoa(arr[count-1],string,10);

    outtext(string);

    delay(10);

    setfillstyle(0, getmaxcolor());

    bar(getx()-30 ,gety()-10 ,getx()+20 ,gety()+9);

    b++;

    }

    delay(10);

    moveto(178,447);

    bar(170,446,208,455);

    count--;

    moveto(178,447);

    itoa(arr[count],string,10);

    outtext(string);

    size++;

}
OUTPUTS

1.Menu list:




2.Operations in stack:
3.Push Operation:




4.Pop Operations:
Graphical representation of Stack
REFRENCES

1. http://en.wikipedia.org/wiki/Stack_(abstract_data_type)

2. www.cprogrramming.com/stack_graphics

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Graphical representation of Stack

  • 1. MINI PROJECT CSE205 TOPIC:Graphical reperesntation of stack Submitted by: SANJAY KUMAR CHAKRAVARTI ROLL:A28 SEC:K2R13 Submitted to: Miss.Deepika sukhija Dept. cse Lpu,phagwara
  • 2. Acknowledgement Apart from the efforts of me, the success of this project depends largely on the encouragement and guidelines of many others. I take this opportunity to express my gratitude to the people who have been instrumental in the successful completion of this project. I would like to show my greatest appreciation to Miss. Deepika sukhija I can’t say thank you enough for his tremendous support and help. I feel motivated and encouraged every time I attend his meeting. Without his encouragement and guidance this project would not have materialized. The guidance and support received from all the team members including Mr. sanjeev kumar and Mr. Abhay kumar who contributed and are contributing to this project, was vital for the success of the project. I am grateful for their constant support and help.
  • 3. CONTENT TOPIC PAGE NO. . 1 ABSTRACT-------------------------------------------------- 04 2. INTRODUCTION------------------------------------------- 05 3.SOURCE CODE---------------------------------------------- 06-18 4.OUTPUTS------------------------------------------------------ 19-21 4.REFRENCES-------------------------------------------------- 22
  • 4. ABSTRACT This project was very important for me. In this project I have show a graphical view of stacks for better understanding. It will gives you many features as listed below: 1. Graphical view 2. Simple programming language 3. Source code contains comments line where needed 4. A best approach with graphics programming
  • 5. INTRODUCTION The Stack is a Memory Area where you can store data there and can get back them again. In computer science, a stack is a last in, first out (LIFO) abstract data type and linear data structure . A stack can have any abstract data type as an element , but is characterized by two fundamental operations, called PUSH and POP. The push operation adds a new item to the top of the stack, or initializes the stack if it is empty. If the stack is full and does not contain enough space to accept the given item, the stack is then considered to be in an overflow state. The pop operation removes an item from the top of the stack. A pop either reveals previously concealed items, or results in an empty stack, but if the stack is empty then it goes into underflow state (It means no items are present in stack to be removed). A stack is a restricted data structure , because only a small number of operations are performed on it. The nature of the pop and push operations also means that stack elements have a natural order. Elements are removed from the stack in the reverse order to the order of their addition: therefore, the lower elements are those that have been on the stack the longest.
  • 6. Source code #include<iostream.h> //for cin, cout #include<conio.h> //for getche() #include<ctype.h> //for tolower() function #include<stdlib.h> //for itoa() #include<GRAPHICS.H> //to load graphics driver #include<dos.h> //for delay() function /*_________________________________________________________________ ________*//*_______________________________________________________ __________________*///These Functions prototypes are, for stack function. int col=60 , row = 417 ,n ,x=60 , y=417 ,size=10 ,arr[10]={12,56,23,46,32,89,11,99,12,66} , count = 0, top = 0; //Global Variables char string[45]; void push( ); void pop( ); void stack();
  • 7. void loadgraph(); void main() { clrscr(); char ch; struct fillsettingstype fillinfo; loadgraph(); setbkcolor(0); setcolor(2); do { rectangle(2,2,620,410); rectangle(4,4,618,408); line(0,30,620,30); getfillsettings(&fillinfo); line(0,32,620,32); line(100,32,100,410); moveto(180,15); outtext("SANJAY KUMAR CHAKRAVARTI"); // circle(300,120,110);
  • 8. setbkcolor(12); gotoxy(37,5); cout<<"Menu"; gotoxy(30,6); cout<<"Stack [s]"; gotoxy(30,8); cout<<"Exit [x]"; gotoxy(30,10); cout<<"Enter Option [ ]"; ch=getche(); ch = tolower(ch); gotoxy(30,15); if(ch=='s') stack(); }while(ch!='x'); cleardevice(); closegraph(); } void loadgraph() { clrscr(); int driver = DETECT, mode, errorcode;
  • 9. initgraph(&driver, &mode, "c:tcbgi"); errorcode = graphresult(); if (errorcode != grOk) { cout<<"Graphics error: n"<<(grapherrormsg(errorcode)); cout<<"Press any key to halt:"; getch(); exit(1); } } void stack() { cleardevice(); moveto(400,60); outtext("STACK'S OPERATIONS"); moveto(400,80); outtext("PUSH [p]"); moveto(400,100); outtext("POP [o]"); moveto(400,120); outtext("EXIT [x]"); moveto(300,125); outtext("Top");
  • 10. itoa(top,string,10); line(150,0,150,415); outtextxy(308,450,string); setbkcolor(3); setcolor(14); outtextxy(55,26,"NOW STACK:"); line(30,40,30,440); int r=40; for(int i = 1 ;i<12 ;i++) { line(30,r,110,r); r+=40; } line(110,40,110,440); r = 55; for( i = 10 ;i>=1 ;i--) { moveto(10,r); itoa(i,string,10); outtext(string) ; r+=40; } line(165,440,210,440);
  • 11. line(165,440,165,460); line(210,440,210,460); line(165,460,210,460); setfillstyle(0, getmaxcolor()); char ch[2]; do { moveto(400,140); outtext("ENTER OPTION "); ch[0]=getche(); ch[0] = tolower(ch[0]); if(ch[0]=='p') { outtext("p"); delay(500); bar(getx()-30,gety(),getx()+2,gety()+20); if(size<1) { for(int i = 0 ;i<4 ; i++){ moveto(420,170); outtext("Stack Overflow "); delay(1000); setfillstyle(0, getmaxcolor()); bar(420 ,165 ,630 ,180);
  • 12. delay(500);} } else if( size>1) { size--; top++; push(); bar(290,440,350,479); itoa(top,string,10); outtextxy(308,447,string); }}//end of Nested if else if(ch[0]=='o') { outtext("o"); delay(500); bar(getx()-30,gety(),getx()+10,gety()+20); if(size==10) { for(int i = 0 ;i<4 ; i++){
  • 13. moveto(410,170); outtext("Stack, Underflow "); delay(1000); setfillstyle(0, getmaxcolor()); bar(330 ,165 ,630 ,180); delay(500); } } else { top--; pop(); bar(290,440,350,479); itoa(top,string,10); outtextxy(308,447,string); } } } while(ch[0]!='x'); } void push() { int a=178 , b=425 ;
  • 14. moveto(178,447); itoa(arr[count],string,10); outtext(string); delay(10); bar(170,446,208,455); itoa(arr[count+1],string,10); moveto(178,447); outtext(string); moveto(a,b); while(gety()!=y) { setfillstyle(0, getmaxcolor()); circle(a+6,b+3,12); itoa(arr[count],string,10); outtext(string); delay(10); setfillstyle(0, getmaxcolor()); bar(170 ,gety()-20 ,200 ,gety()+14); moveto(a,b); b--; } setfillstyle(0, getmaxcolor()); circle(a+6,b+3,9);
  • 15. outtext(string); moveto(125,b); for(int j =0 ;j<6 ; j++) { outtext("<<--"); delay(100); setfillstyle(0, getmaxcolor()); bar(getx()-3 ,gety() ,getx() ,gety()+8); delay(100); } delay(100); setfillstyle(0, getmaxcolor()); bar(getx()-48 ,gety() ,getx() ,gety()+8); delay(100); delay(200); while(getx()!=x+60) { setfillstyle(0, getmaxcolor()); circle(a+6,b+3,9); itoa(arr[count],string,10); outtext(string); delay(10); setfillstyle(0, getmaxcolor()); bar(getx()-20 ,gety()-10 ,getx()+70 ,gety()+20);
  • 16. moveto(a,b); a--; } delay(100); moveto(60,gety()); outtext(string); count++; y = y-40; } void pop() { int a=120, b ; y = y + 40 ; b=y ; moveto(120,y); for(int j=0 ;j<6 ; j++) { outtext("®"); delay(100); setfillstyle(0, getmaxcolor()); bar(getx()-3 ,gety() ,getx() ,gety()+8); delay(100); }
  • 17. delay(100); setfillstyle(0, getmaxcolor()); bar(getx()-48 ,gety() ,getx() ,gety()+8); delay(200); moveto(60,gety()); setfillstyle(0, getmaxcolor()); bar(getx()-10 ,gety()-3 ,getx()+20 ,gety()+8); delay(500); while(getx()!=178) { setfillstyle(0, getmaxcolor()); circle(a+6,b+3,12); moveto(a,gety()); itoa(arr[count-1],string,10); outtext(string); delay(10); setfillstyle(0, getmaxcolor()); bar(getx()-25 ,gety()-10 ,getx()+30 ,gety()+20); a++; } delay(500); while(gety()!=430) {
  • 18. setfillstyle(0, getmaxcolor()); circle(a+21,b+3,7); moveto(178,b); itoa(arr[count-1],string,10); outtext(string); delay(10); setfillstyle(0, getmaxcolor()); bar(getx()-30 ,gety()-10 ,getx()+20 ,gety()+9); b++; } delay(10); moveto(178,447); bar(170,446,208,455); count--; moveto(178,447); itoa(arr[count],string,10); outtext(string); size++; }