If an image is represented using 400 x 300 pixels and each pixel is .pdf
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An image with 400 x 300 pixels requires a total of 1200 bytes for representation, as each pixel uses 8 bits or 1 byte. Converting this to kilobytes, the data required is approximately 1.17 kb. Therefore, the exact amount of data needed to represent the image is 1.17 kilobytes.
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If an image is represented using 400 x 300 pixels and each pixel is .pdf
- 1. If an image is represented using 400 x 300 pixels and each pixel is represented using 8 bits, what will be the exact amount of data needed in kilobytes to represent in the image? Solution there are 1200 pixels in total. Each pixel is represented requires 8 bit for its representation which 1 byte of data. Now for 1200 pixels we require 1200 bytes of data to represent a 400x300 pixel image. 1 byte = 1/1024kb 1200 byte = 1200*(1/1024) = 1.17 kb data is required to present an image.