Index+log(koleksi final)
- 1. BA101 – index exercise 2 Solve the equations using index method: xii. log 2 6 x log 2 ( x 3) 2 x 6 1 i. 52 n 1 25n 1 125n 1 53n 6 xiii. 125 x 2 x 2 3 25 2 x 4 8n 4 ii. p3 q 2n p 2n xiv. log 2 (4 x 1) 3 log 2 x x 1 3n 4 2 q 1 iii. 32 m 5 n 10 5 2mn 2 Given that log 7 5 0.83 and log 7 6 0.92 ,find iv. 32 n (81n 1 )(9 2 3n ) 1 the value of the following without using a 2 3 4 calculator (a b ) v. a2 i. log 7 30 1.75 (a 3b 6 ) 2 1 82 n 43n ii. log 7 1 0.09 vi. 2 3n 5 2 n 16 2 n 2 Given that log 2 3 1.59 and log 2 5 2.32 ,find vii. 22 x 4 1 the value of the following without using a 16 x 2 Simplify the logarithmic equations below: calculator 1 1 i. log 2 45 5.50 i. log a 2 log b log c a c 3 3 log b 2 ii. log 2 0.6 0.73 ii. 4 log x 2 log y log x 4 log z log x y 3 2 Given that log2 a = m and log 2 b = n. Write z4 2a iii. 3 log b 4 log a 2 log z a4 log2 in terms of m and n. 1 m n log b3 z 2 b Find the value of x: Given that log 3 2 m and log 3 5 n, write i. log 50 log x 2 log(2 x 1) x 2 3 log1.2 in terms of m and n 1 m n ii. log 3 (3 2 x) 3 x 12 iii. log 5 (5 x 4) 2 log 5 3 log 5 4 x 8 iv. log x 8 5 log x 4 x 2 If log 5 3 0.682 ,find the value of this equation: x 2x v. 2 4 16 x 4 3 4 2 5 log 5 2 log 5 log 5 0.318 1 8 5 5 vi. 3x 1 27 x x 3 9 4 1 vii. 128 x 7 2x viii. 27 x 9 x 2 3 ix. 32 x 4 x 36 x 1 x. 3 log x 4 log x 2 5 x 2 4x x 2 xi. 8 4 x 2 5