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MARKS SCHEME FOR ADD MATHS PAPER 1 TRIAL SPM (SBP) 2010


                                                           Sub-    Markah
    No.                                   Penyelesaian
                                                          markah   penuh
1    (a)     3                                            1
                                                                     2
     (b)     -1                                           1

             3x 2 − 6 x + 1                               2
2                      2
             3( x − 1) − 2
     (a)
                                                          B1

                                                                     4
                       4                                  2
             1 ,
                       3
     (b)
             3x 2 − 6 x + 1 + 3 = x                       B1


3            33
     (a)                                                  1
                                                                     4
             0 , −2                                       2
     (b)     2 x 2 + 5x = x                               B1


              p < −8 ,         p>8                        3

4            ( p ) 2 − 4(1)(16) < 0                       B2         3
             x 2 + px + 16 = 0                            B1


             1
5    (a)                                                  1
             2
                                                                     2
                   1
     (b)     x=                                           1
                   2

                                      1                   3
             k = −8 and , h = −
                                      4
6            k = −8 or hk = 2                             B2
                                                                     3
                           2
             2( x + 2) − 8                                B1
OR

                                 1                                     3
           k = −8 and h = −
                                 4
                                                                       B2
           4hk = 8    or      2h k − 8 = 0
                                2 2


           2 x 2 + 4hkx + 2h 2 k 2 + k                                 B1




           0.4195
                                                                       3
           4 2 x = 3.2                                                 B2
7                                                                           3
                 1 
           4 2 x  + 1 = 4                                            B1
                 4 


           6r + 2 − 8 p
            3 log m 5    log m m     4 log m 3
                      +           −
           log m m log m m log m m                                     3

             3 log 5        log m         4 log 3                      B2
8                     or            or            (any base) or             3
           log m          log m          log m
            log 125 + log m or log m − log 81 or log 125 + log 81 or   B1
                          1
             log m m =
                          2


           h = 12                                                      2
9    (a)
           h + 1 − (2h − 6) = h − 4 − (h + 1)                          B1
                                                                            3

     (b)   -5                                                          1


           5.85                                                        3
10         r = 2.5                                                     B2
                                                                            3
                  3
           0.6r = 9.375                                                B1
3
           0.75 or
                              4                             2
11   (a)         9         27          81
           T1 =    or T2 =    or T3 =     or any relevant   B1
                16         64         256
           terms
                                                                 4
                                                            2
           2.25
             9
     (b)    16                                              B1
               3
           1−
               4


           2.44                                             2
12   (a)
           2 x + 30.5 = 55.5 or radius = 12.5               B1

                                                                 4
           190.625
           1                                                2
     (b)
             (12.5) 2 (2.44)                                B1
           2


                   5
           m=−                                              2
13   (a)           2
           (5 i − 12 j ) = λ (m i + 6 j )                   B1
             ~            ~       ~   ~
                                                                 3

           5 i − 12 j
             ~            ~                                 2
     (b)
                 13
           Magnitude = 13                                   B1


           − 6 b+ 12 a                                      2
                 ~            ~
14   (a)   →         →
           SP + PQ                                          B1

                                                                 4
           8 a+ 2 b                                         2
             ~        ~
     (b)   →   1              
           QS =  − 12 a + 6 b 
               3      ~     ~                             B1
m = -6 and n = 6
           m = -6 or n = 6
            2−0 1
                 =                         4
           12 − 6 n                        B3
           and
               1    m                      B2
           0 = ×6+
15
               6    6                           4

            2−0 1
                 =
           12 − 6 n
           or                              B1
               1    m
           0 = ×6+
               6    6


               32       23
           r =     ,t =
                3       5
               2( 4) + 3( r )              3
           8=                 and
                     5
               2(1) + 3(7)                 B2
           t =
                     5


16   (a)                                        3

              2(4) + 3(r )
           8=              or
                    5
              2(1) + 3(7)
           t=
                   5                       B1




           41.810 ,90 0 ,270 0 and         4
                    0
           138.19
           41.810 and
17                                         B3   4
           90 0
           2 cos x(3 sin x − 2) = 0        B2
           3 × 2 sin x cos x − cos x = 0
                                           B1
6( x 2 + 3)(5 x 2 + 3)        2
18                                            2
           6 x( x 2 + 3) 2               B1


           h =1                          2
19                                            2
           4(−1) + h = −3                B1

                 2
           m=
                 3                       3
           25m m
              − − 10 = −3m               B2
20          2  2                              3
                     5
            mx 2 
                  − 2(5) = −3m         B1
            2 1

           K = 41.53                     1

           L = 37.5                      1
21                                            4
           G = 26
                                         1
           F = 54                        1
22   (a)   792                           1


           160                           2    3
     (b)
           4C1 × 6C 3 × 2C1              B1

23   (a)   720
                                         1

           260                                3
                                         2
     (b)
           6! × 3P1                      B1


           0.008491                      2
24   (a)
           10C 5 × (0.15) 5 × (0.85) 5   B1
                                              4
           0.8202                        2
     (b)
           P(X=0)+P(X=1)+P(X=2)          B1
25   (a)    0.0571
                                        1

            81.84                            3
                                        2
     (b)    85 − µ
                   = 1.58               B1
              2

            TOTAL MARKS/JUMLAH MARKAH        80




END OF MARKS SCHEME

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5 marks scheme for add maths paper 1 trial spm

  • 1. MARKS SCHEME FOR ADD MATHS PAPER 1 TRIAL SPM (SBP) 2010 Sub- Markah No. Penyelesaian markah penuh 1 (a) 3 1 2 (b) -1 1 3x 2 − 6 x + 1 2 2 2 3( x − 1) − 2 (a) B1 4 4 2 1 , 3 (b) 3x 2 − 6 x + 1 + 3 = x B1 3 33 (a) 1 4 0 , −2 2 (b) 2 x 2 + 5x = x B1 p < −8 , p>8 3 4 ( p ) 2 − 4(1)(16) < 0 B2 3 x 2 + px + 16 = 0 B1 1 5 (a) 1 2 2 1 (b) x= 1 2 1 3 k = −8 and , h = − 4 6 k = −8 or hk = 2 B2 3 2 2( x + 2) − 8 B1
  • 2. OR 1 3 k = −8 and h = − 4 B2 4hk = 8 or 2h k − 8 = 0 2 2 2 x 2 + 4hkx + 2h 2 k 2 + k B1 0.4195 3 4 2 x = 3.2 B2 7 3 1  4 2 x  + 1 = 4 B1 4  6r + 2 − 8 p 3 log m 5 log m m 4 log m 3 + − log m m log m m log m m 3 3 log 5 log m 4 log 3 B2 8 or or (any base) or 3 log m log m log m log 125 + log m or log m − log 81 or log 125 + log 81 or B1 1 log m m = 2 h = 12 2 9 (a) h + 1 − (2h − 6) = h − 4 − (h + 1) B1 3 (b) -5 1 5.85 3 10 r = 2.5 B2 3 3 0.6r = 9.375 B1
  • 3. 3 0.75 or 4 2 11 (a) 9 27 81 T1 = or T2 = or T3 = or any relevant B1 16 64 256 terms 4 2 2.25 9 (b) 16 B1 3 1− 4 2.44 2 12 (a) 2 x + 30.5 = 55.5 or radius = 12.5 B1 4 190.625 1 2 (b) (12.5) 2 (2.44) B1 2 5 m=− 2 13 (a) 2 (5 i − 12 j ) = λ (m i + 6 j ) B1 ~ ~ ~ ~ 3 5 i − 12 j ~ ~ 2 (b) 13 Magnitude = 13 B1 − 6 b+ 12 a 2 ~ ~ 14 (a) → → SP + PQ B1 4 8 a+ 2 b 2 ~ ~ (b) → 1  QS =  − 12 a + 6 b  3 ~ ~ B1
  • 4. m = -6 and n = 6 m = -6 or n = 6 2−0 1 = 4 12 − 6 n B3 and 1 m B2 0 = ×6+ 15 6 6 4 2−0 1 = 12 − 6 n or B1 1 m 0 = ×6+ 6 6 32 23 r = ,t = 3 5 2( 4) + 3( r ) 3 8= and 5 2(1) + 3(7) B2 t = 5 16 (a) 3 2(4) + 3(r ) 8= or 5 2(1) + 3(7) t= 5 B1 41.810 ,90 0 ,270 0 and 4 0 138.19 41.810 and 17 B3 4 90 0 2 cos x(3 sin x − 2) = 0 B2 3 × 2 sin x cos x − cos x = 0 B1
  • 5. 6( x 2 + 3)(5 x 2 + 3) 2 18 2 6 x( x 2 + 3) 2 B1 h =1 2 19 2 4(−1) + h = −3 B1 2 m= 3 3 25m m − − 10 = −3m B2 20 2 2 3 5  mx 2    − 2(5) = −3m B1  2 1 K = 41.53 1 L = 37.5 1 21 4 G = 26 1 F = 54 1 22 (a) 792 1 160 2 3 (b) 4C1 × 6C 3 × 2C1 B1 23 (a) 720 1 260 3 2 (b) 6! × 3P1 B1 0.008491 2 24 (a) 10C 5 × (0.15) 5 × (0.85) 5 B1 4 0.8202 2 (b) P(X=0)+P(X=1)+P(X=2) B1
  • 6. 25 (a) 0.0571 1 81.84 3 2 (b) 85 − µ = 1.58 B1 2 TOTAL MARKS/JUMLAH MARKAH 80 END OF MARKS SCHEME