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Interval and Radius of
Convergence
A Practice Problem
State the interval and the radius of convergence
of the power series below:
• 𝑛=1
∞ 𝑥 𝑛
𝑛∙3 𝑛
Step 1:
• Use the Ratio Test! • lim
𝑛→∞
𝑥 𝑛+1
(𝑛+1)3 𝑛+1 ∙
𝑛3 𝑛
𝑥 𝑛
• = lim
𝑛→∞
𝑥𝑛
3(𝑛+1)
• =
𝑥
3
< 1
• -3 < x < 3
Step 2:
• Test the endpoints! • At x = -3: 𝑛=1
∞ (−1) 𝑛
𝑛
; this series
converges by the AST
• At x = 3: 𝑛=1
∞ 1
𝑛
; this series
diverges because it is the harmonic
series
Step 3:
• Write the interval! • [-3, 3)
Step 4:
• Identify the length of the radius of
convergence!
• R = 3

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Interval of Convergence

  • 1. Interval and Radius of Convergence A Practice Problem
  • 2. State the interval and the radius of convergence of the power series below: • 𝑛=1 ∞ 𝑥 𝑛 𝑛∙3 𝑛
  • 3. Step 1: • Use the Ratio Test! • lim 𝑛→∞ 𝑥 𝑛+1 (𝑛+1)3 𝑛+1 ∙ 𝑛3 𝑛 𝑥 𝑛 • = lim 𝑛→∞ 𝑥𝑛 3(𝑛+1) • = 𝑥 3 < 1 • -3 < x < 3
  • 4. Step 2: • Test the endpoints! • At x = -3: 𝑛=1 ∞ (−1) 𝑛 𝑛 ; this series converges by the AST • At x = 3: 𝑛=1 ∞ 1 𝑛 ; this series diverges because it is the harmonic series
  • 5. Step 3: • Write the interval! • [-3, 3)
  • 6. Step 4: • Identify the length of the radius of convergence! • R = 3