SlideShare a Scribd company logo
3
Most read
6
Most read
9
Most read
𝐏𝐓𝐒 𝟑
Bridge to Calculus Workshop
Summer 2020
Lesson 13
Midpoint and Distance
Formulas
“Instead of concentrating just on
finding good answers to questions,
it's more important to learn how to
find good questions!”
- Donald E. Knuth-
Lehman College, Department of Mathematics
Midpoint Formula (1 of 4)
The midpoint 𝑥 of the line segment joining two points 𝑥1
and 𝑥2 on a number line is given by:
Example 1. Find the midpoint 𝑥 of the line segment
joining the points 𝑥 = 3 and 𝑥 = −1 on the number line.
Solution. Using the midpoint formula:
𝑥 =
𝑥1 + 𝑥2
2
𝑥 =
𝑥1 + 𝑥2
2
=
3 + (−1)
2
=
2
2
= 1
Lehman College, Department of Mathematics
Midpoint Formula (2 of 4)
Let 𝑥1 and 𝑥2 be two points on a number line. Without
loss of generality, let 𝑥1 < 𝑥2.
Now, Let 𝑥 be the midpoint of the line segment [𝑥1, 𝑥2].
It follows that the distance from 𝑥1 to 𝑥 must equal the
distance from 𝑥 to 𝑥2. That is:
𝑥 − 𝑥1 = 𝑥2 − 𝑥
𝑥 − 𝑥1 + 𝑥 = 𝑥2 − 𝑥 + 𝑥
2𝑥 − 𝑥1 = 𝑥2
2𝑥 − 𝑥1 + 𝑥1 = 𝑥2 + 𝑥1
Lehman College, Department of Mathematics
Midpoint Formula (3 of 4)
From the previous slide:
In the coordinate plane, the midpoint (𝑥, 𝑦) of the line
segment joining the points (𝑥1, 𝑦1) and (𝑥2, 𝑦2) is given
by the formula:
Example 2. Find the midpoint 𝑥, 𝑦 of the line segment
joining the points (−2, 3) and (6, −5) in the plane.
2𝑥 − 𝑥1 + 𝑥1 = 𝑥2 + 𝑥1
2𝑥 = 𝑥1 + 𝑥2
𝑥 =
𝑥1 + 𝑥2
2
𝑥, 𝑦 =
𝑥1 + 𝑥2
2
,
𝑦1 + 𝑦2
2
Lehman College, Department of Mathematics
Midpoint Formula (4 of 4)
Example 2. Find the midpoint 𝑥, 𝑦 of the line segment
joining the points (−2, 3) and (6, −5) in the plane.
Solution. Using the midpoint formula:
𝑥, 𝑦 =
𝑥1 + 𝑥2
2
,
𝑦1 + 𝑦2
2
=
−2 + 6
2
,
3 + (−5)
2
=
4
2
,
−2
2
= 2, −1
Lehman College, Department of Mathematics
Distance Formula (1 of 4)
The distance 𝑑 between two points 𝑥1 and 𝑥2 on a
number line is given by:
Example 3. Determine the distance 𝑑 between the
points 𝑥 = −3 and 𝑥 = −7 on a number line.
Solution. Use the distance formula:
𝑑 = | 𝑥2 − 𝑥1|
𝑑 = | 𝑥2 − 𝑥1|
= −3 − (−7) = −3 + 7 = 4 = 4
Lehman College, Department of Mathematics
Distance Formula (2 of 4)
Let 𝐴(𝑥1, 𝑦1) and 𝐵(𝑥2, 𝑦2) be two points in the plane.
Denote the distance between 𝐴 and 𝐵 by 𝑑 = 𝑑 𝐴, 𝐵 .
Construct horizontal and vertical lines to meet at 𝐶.
Determine the lengths of the legs of right triangle 𝐴𝐵𝐶.
Lehman College, Department of Mathematics
Distance Formula (3 of 4)
How do we determine the distance 𝑑(𝐴, 𝐵)?
Use the Pythagorean Theorem to determine 𝑑(𝐴, 𝐵):
𝑑2
= 𝑥2 − 𝑥1
2
+ 𝑦2 − 𝑦1
2
𝑑(𝐴, 𝐵) = 𝑥2 − 𝑥1
2 + 𝑦2 − 𝑦1
2
Lehman College, Department of Mathematics
Distance Formula (4 of 4)
Example 4. Find the distance between the points
𝐴(2, 5) and 𝐵 4, −1 in the coordinate plane.
Solution. Using the distance formula, we have:
𝑑(𝐴, 𝐵) = 𝑥2 − 𝑥1
2 + 𝑦2 − 𝑦1
2
= 4 − 2 2 + −1 − 5 2
= 2 2 + −6 2
= 4 + 36 = 40
= 4 ⋅ 10 = 4 ⋅ 10
= 2 10
Lehman College, Department of Mathematics
Distance Formula (4 of 4)
Example 5. Find the distance between the points
𝐴(−5, 2) and 𝐵 −1, −2 in the coordinate plane.
Solution. Using the distance formula, we have:
𝑑(𝐴, 𝐵) = 𝑥2 − 𝑥1
2 + 𝑦2 − 𝑦1
2
= −5 − (−1) 2 + 2 − (−2) 2
= −4 2 + 4 2
= 16 + 16 = 32
= 16 ⋅ 2 = 16 ⋅ 2
= 4 2

More Related Content

PDF
Diabetes melitus.pdf
PPTX
TATALAKSANA GIZI ANAK BAITA SERTA STUNTING DAN WASHTING FIX.pptx
PDF
Chapter 2 ee202 boolean part a
PPTX
Lesson 14: Equation of a Circle
PPTX
Lesson 17: Quadratic Functions
PDF
Module 5 (Part 3-Revised)-Functions and Relations.pdf
PPTX
Lesson 10: Solving Quadratic Equations
PPTX
Lesson 2: Final Exam Review (Part 1)
Diabetes melitus.pdf
TATALAKSANA GIZI ANAK BAITA SERTA STUNTING DAN WASHTING FIX.pptx
Chapter 2 ee202 boolean part a
Lesson 14: Equation of a Circle
Lesson 17: Quadratic Functions
Module 5 (Part 3-Revised)-Functions and Relations.pdf
Lesson 10: Solving Quadratic Equations
Lesson 2: Final Exam Review (Part 1)

Similar to Lesson 13: Midpoint and Distance Formulas (20)

PDF
2.1 Rectangular Coordinates
PDF
Functions and their Graphs (mid point)
PPTX
P1-Chp2-Quadratics.pptx
PPTX
Conic sections circles - STEM TEACH
PPTX
Week_3-Circle.pptx
PPTX
Mathematics 10.pptx
PDF
Tool mathematics l4
PDF
Ch 1 Final 10Math.pdf
PDF
Q33_LE_Mathematics 8_Lesson 5_Week 5.pdf
PDF
elemetary algebra review.pdf
PPTX
Quadratic Equations in One Variables.pptx
PPTX
Lesson 9: Linear Relations and Lines
PDF
MATH-9-LESSON-4.geuirguiegduiewghdeuiewghhyixgyipdf
PDF
10.1-introduction-to-complex-numbers.pdf
PDF
Comparative analysis of x^3+y^3=z^3 and x^2+y^2=z^2 in the Interconnected Sets
PDF
Smart sol
PDF
Smart sol
PPTX
Lesson 3: Problem Set 4
PDF
4 ESO Academics - UNIT 04 - EQUATIONS AND INEQUATIONS
PPTX
SESSION 2_COMPLETING THE SQUARE.pptx
2.1 Rectangular Coordinates
Functions and their Graphs (mid point)
P1-Chp2-Quadratics.pptx
Conic sections circles - STEM TEACH
Week_3-Circle.pptx
Mathematics 10.pptx
Tool mathematics l4
Ch 1 Final 10Math.pdf
Q33_LE_Mathematics 8_Lesson 5_Week 5.pdf
elemetary algebra review.pdf
Quadratic Equations in One Variables.pptx
Lesson 9: Linear Relations and Lines
MATH-9-LESSON-4.geuirguiegduiewghdeuiewghhyixgyipdf
10.1-introduction-to-complex-numbers.pdf
Comparative analysis of x^3+y^3=z^3 and x^2+y^2=z^2 in the Interconnected Sets
Smart sol
Smart sol
Lesson 3: Problem Set 4
4 ESO Academics - UNIT 04 - EQUATIONS AND INEQUATIONS
SESSION 2_COMPLETING THE SQUARE.pptx
Ad

More from Kevin Johnson (20)

PPTX
Lesson 22: Polynomial Long Division
PPTX
Lesson 21: More Algebra
PPTX
Lesson 20: Trigonometric Functions of Any Angle Part 1
PPTX
Lesson 19: Exponential and Logarithmic Functions
PPTX
Lesson 18: Rational Exponents
PPTX
Lesson 16: More Inequalities
PPTX
Lesson 15: Geometry
PPTX
Lesson 12: Right Triangle Trigonometry
PPTX
Lesson 11: Functions and Function Notation
PPTX
Lesson 8: Rational Functions
PPTX
Lesson 7: Graphing Inequalities
PPTX
Lesson 6: Factoring Polynomials
PPTX
Lesson 5: Polynomials
PPTX
Lesson 4: Decimal to Scientific Notation
PPTX
Lesson 2: Inequalities
PPTX
Lesson 3: Exponential Notation
PPTX
Lesson 1: The Real Number System
PPTX
MAT-314 Midterm Exam 2 Review
PPTX
Section 11: Normal Subgroups
PPTX
Section 10: Lagrange's Theorem
Lesson 22: Polynomial Long Division
Lesson 21: More Algebra
Lesson 20: Trigonometric Functions of Any Angle Part 1
Lesson 19: Exponential and Logarithmic Functions
Lesson 18: Rational Exponents
Lesson 16: More Inequalities
Lesson 15: Geometry
Lesson 12: Right Triangle Trigonometry
Lesson 11: Functions and Function Notation
Lesson 8: Rational Functions
Lesson 7: Graphing Inequalities
Lesson 6: Factoring Polynomials
Lesson 5: Polynomials
Lesson 4: Decimal to Scientific Notation
Lesson 2: Inequalities
Lesson 3: Exponential Notation
Lesson 1: The Real Number System
MAT-314 Midterm Exam 2 Review
Section 11: Normal Subgroups
Section 10: Lagrange's Theorem
Ad

Recently uploaded (20)

PPTX
Science Quipper for lesson in grade 8 Matatag Curriculum
PDF
lecture 2026 of Sjogren's syndrome l .pdf
PDF
Looking into the jet cone of the neutrino-associated very high-energy blazar ...
PPTX
BODY FLUIDS AND CIRCULATION class 11 .pptx
PPT
6.1 High Risk New Born. Padetric health ppt
DOCX
Q1_LE_Mathematics 8_Lesson 5_Week 5.docx
PDF
Formation of Supersonic Turbulence in the Primordial Star-forming Cloud
PDF
The Land of Punt — A research by Dhani Irwanto
PPTX
The Minerals for Earth and Life Science SHS.pptx
PPTX
BIOMOLECULES PPT........................
PPTX
Introduction to Cardiovascular system_structure and functions-1
PPTX
Hypertension_Training_materials_English_2024[1] (1).pptx
PDF
Worlds Next Door: A Candidate Giant Planet Imaged in the Habitable Zone of ↵ ...
PPTX
perinatal infections 2-171220190027.pptx
PDF
. Radiology Case Scenariosssssssssssssss
PPTX
TOTAL hIP ARTHROPLASTY Presentation.pptx
PDF
BET Eukaryotic signal Transduction BET Eukaryotic signal Transduction.pdf
PDF
The scientific heritage No 166 (166) (2025)
PPTX
ognitive-behavioral therapy, mindfulness-based approaches, coping skills trai...
PPT
veterinary parasitology ````````````.ppt
Science Quipper for lesson in grade 8 Matatag Curriculum
lecture 2026 of Sjogren's syndrome l .pdf
Looking into the jet cone of the neutrino-associated very high-energy blazar ...
BODY FLUIDS AND CIRCULATION class 11 .pptx
6.1 High Risk New Born. Padetric health ppt
Q1_LE_Mathematics 8_Lesson 5_Week 5.docx
Formation of Supersonic Turbulence in the Primordial Star-forming Cloud
The Land of Punt — A research by Dhani Irwanto
The Minerals for Earth and Life Science SHS.pptx
BIOMOLECULES PPT........................
Introduction to Cardiovascular system_structure and functions-1
Hypertension_Training_materials_English_2024[1] (1).pptx
Worlds Next Door: A Candidate Giant Planet Imaged in the Habitable Zone of ↵ ...
perinatal infections 2-171220190027.pptx
. Radiology Case Scenariosssssssssssssss
TOTAL hIP ARTHROPLASTY Presentation.pptx
BET Eukaryotic signal Transduction BET Eukaryotic signal Transduction.pdf
The scientific heritage No 166 (166) (2025)
ognitive-behavioral therapy, mindfulness-based approaches, coping skills trai...
veterinary parasitology ````````````.ppt

Lesson 13: Midpoint and Distance Formulas

  • 1. 𝐏𝐓𝐒 𝟑 Bridge to Calculus Workshop Summer 2020 Lesson 13 Midpoint and Distance Formulas “Instead of concentrating just on finding good answers to questions, it's more important to learn how to find good questions!” - Donald E. Knuth-
  • 2. Lehman College, Department of Mathematics Midpoint Formula (1 of 4) The midpoint 𝑥 of the line segment joining two points 𝑥1 and 𝑥2 on a number line is given by: Example 1. Find the midpoint 𝑥 of the line segment joining the points 𝑥 = 3 and 𝑥 = −1 on the number line. Solution. Using the midpoint formula: 𝑥 = 𝑥1 + 𝑥2 2 𝑥 = 𝑥1 + 𝑥2 2 = 3 + (−1) 2 = 2 2 = 1
  • 3. Lehman College, Department of Mathematics Midpoint Formula (2 of 4) Let 𝑥1 and 𝑥2 be two points on a number line. Without loss of generality, let 𝑥1 < 𝑥2. Now, Let 𝑥 be the midpoint of the line segment [𝑥1, 𝑥2]. It follows that the distance from 𝑥1 to 𝑥 must equal the distance from 𝑥 to 𝑥2. That is: 𝑥 − 𝑥1 = 𝑥2 − 𝑥 𝑥 − 𝑥1 + 𝑥 = 𝑥2 − 𝑥 + 𝑥 2𝑥 − 𝑥1 = 𝑥2 2𝑥 − 𝑥1 + 𝑥1 = 𝑥2 + 𝑥1
  • 4. Lehman College, Department of Mathematics Midpoint Formula (3 of 4) From the previous slide: In the coordinate plane, the midpoint (𝑥, 𝑦) of the line segment joining the points (𝑥1, 𝑦1) and (𝑥2, 𝑦2) is given by the formula: Example 2. Find the midpoint 𝑥, 𝑦 of the line segment joining the points (−2, 3) and (6, −5) in the plane. 2𝑥 − 𝑥1 + 𝑥1 = 𝑥2 + 𝑥1 2𝑥 = 𝑥1 + 𝑥2 𝑥 = 𝑥1 + 𝑥2 2 𝑥, 𝑦 = 𝑥1 + 𝑥2 2 , 𝑦1 + 𝑦2 2
  • 5. Lehman College, Department of Mathematics Midpoint Formula (4 of 4) Example 2. Find the midpoint 𝑥, 𝑦 of the line segment joining the points (−2, 3) and (6, −5) in the plane. Solution. Using the midpoint formula: 𝑥, 𝑦 = 𝑥1 + 𝑥2 2 , 𝑦1 + 𝑦2 2 = −2 + 6 2 , 3 + (−5) 2 = 4 2 , −2 2 = 2, −1
  • 6. Lehman College, Department of Mathematics Distance Formula (1 of 4) The distance 𝑑 between two points 𝑥1 and 𝑥2 on a number line is given by: Example 3. Determine the distance 𝑑 between the points 𝑥 = −3 and 𝑥 = −7 on a number line. Solution. Use the distance formula: 𝑑 = | 𝑥2 − 𝑥1| 𝑑 = | 𝑥2 − 𝑥1| = −3 − (−7) = −3 + 7 = 4 = 4
  • 7. Lehman College, Department of Mathematics Distance Formula (2 of 4) Let 𝐴(𝑥1, 𝑦1) and 𝐵(𝑥2, 𝑦2) be two points in the plane. Denote the distance between 𝐴 and 𝐵 by 𝑑 = 𝑑 𝐴, 𝐵 . Construct horizontal and vertical lines to meet at 𝐶. Determine the lengths of the legs of right triangle 𝐴𝐵𝐶.
  • 8. Lehman College, Department of Mathematics Distance Formula (3 of 4) How do we determine the distance 𝑑(𝐴, 𝐵)? Use the Pythagorean Theorem to determine 𝑑(𝐴, 𝐵): 𝑑2 = 𝑥2 − 𝑥1 2 + 𝑦2 − 𝑦1 2 𝑑(𝐴, 𝐵) = 𝑥2 − 𝑥1 2 + 𝑦2 − 𝑦1 2
  • 9. Lehman College, Department of Mathematics Distance Formula (4 of 4) Example 4. Find the distance between the points 𝐴(2, 5) and 𝐵 4, −1 in the coordinate plane. Solution. Using the distance formula, we have: 𝑑(𝐴, 𝐵) = 𝑥2 − 𝑥1 2 + 𝑦2 − 𝑦1 2 = 4 − 2 2 + −1 − 5 2 = 2 2 + −6 2 = 4 + 36 = 40 = 4 ⋅ 10 = 4 ⋅ 10 = 2 10
  • 10. Lehman College, Department of Mathematics Distance Formula (4 of 4) Example 5. Find the distance between the points 𝐴(−5, 2) and 𝐵 −1, −2 in the coordinate plane. Solution. Using the distance formula, we have: 𝑑(𝐴, 𝐵) = 𝑥2 − 𝑥1 2 + 𝑦2 − 𝑦1 2 = −5 − (−1) 2 + 2 − (−2) 2 = −4 2 + 4 2 = 16 + 16 = 32 = 16 ⋅ 2 = 16 ⋅ 2 = 4 2