Lesson template of aswathy
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This document presents an innovative mathematics lesson plan about the concept of pi (π). The lesson begins by dividing students into groups to measure circles' radii, diameters, and circumferences. By comparing these measurements, students discover that a circle's circumference is equal to 2πr and its diameter is twice its radius. The teacher then introduces π as the fixed number obtained by dividing a circle's circumference by its diameter. Through examples, students calculate π to be approximately 3.14. The lesson concludes by having students apply these concepts to find π given other circle measurements.
Lesson template of aswathy
- 1. INNOVATIVE LESSON TEMPLATE Presented by Aswathy Ajayan Mathematics Reg. No. 13973004 KUCTE, KOLLAM
- 2. Name of the teacher Aswathy Ajayan Std & Div IX Name of the School Period Subject Mathematics Strength Std & Div IX Time 40` Unit Circles Date Topic A new number CURRICULAR OBJECTIVES To convey the concept “휋” CONTENT ANALYSIS TERMS : Circle, radius, diameter, perimeter FACTS : The radius of a circle is half of its diameter The circled measurement of a circle is its circumference When we divide the circumference of a circle with its diameter we got the constant number, 휋 A circle with radius ‘r’ , whose circumference is 2 휋r. 4
- 3. CONCEPT : The concept ‘휋’ FORMULAE : 휋 = 퐶푖푟푐푢푚푓푒푟푒푛푐푒 푑푖푎푚푒푡푒푟 SYMBOLS : r radius, 휋 = 22 7 ≅ 3.141 LEARNING OUTCOME Students will be able to; 1. Recalls about circle 2. Recognizes radius of circle and diameter of circle. 3. Understands the concept of 휋 4. Exemplify different situations to analyze the concept. 5. Apply the above concept in familiar situation. 6. Accept the beauty of mathematical principles.
- 4. PRE-REQUISITES The pupil knows about, Circle Radius Mathematical calculations TEACHING LEARNING RESOURCES Chart showing definition Ordinary classroom teaching aids.
- 5. CLASS ROOM INTERACTION PROCEDURE RESPONSES Introduction Activity No. 1 Teacher divides the whole class into 4 groups and giving the models of circle to each group. Teacher asks students to find out the radius, diameter and the relations between them PRESENTATION Activity No. 2 Then the teacher gives thread to each group and to find out the circumference using the thread. Activity No. 3 Teacher gives activity cards to each group and asks to find out the radius, diameter, circumference and 푐푖푟푢푚푓푒푟푒푛푐푒 푑푖푎푚푡푒푟 They measures the radius and diameter and find out that 2xradius = diameter Students find out the circumference using thread and scale Students find out each measurement 2 8 12 2 2 10 14
- 6. Activity No. 4 Teacher concluding the measurements in the black board Group Radius Diameter Circumference 푐푖푟푐푢푚푓푒푟푛푐푒 푑푖푎푚푒푡푒푟 I 2 4 12.5 3.14 II 3 6 18.84 3.14 Teacher asks to find out the principle From this teacher concluded that when we divide circumference with diameter we will get a fixed number, this number is denoted as 휋 in Greek letter, William Johns coined this name in AD 1707 , the value of this number is 22/7 and find decimal value is 3.14. Teacher shows the chart and gives the note. The fixed number 흅 When we divide the circumference of a circle with its diameter we will get a fixed number. This fixed number is denoted by the Greek letter ‘휋′ Students said that when we divide circumference with diameter we will get a fixed number
- 7. APPLICATION The circumference of a circle is 25.12 cm, diameter is 8 cm, then find the value of 휋? What is to be find out? What is the value of circumference? How much is the diameter? Then what is the radius? How can we find out the value of 휋? Then find out the value Is the value right or not? The value of 휋 25.12 cm 8 cm 4 cm Divide the circumference with diameter. 휋 = 25.12 8 = 3.14 푐푚 Right
- 8. Review What will get from the division of circumference of a circle with diameter. What is the value of 휋? Follow up activity Construct a circle with radius 7cm. find out the diameter circumference and divide these values to find out 휋?