Linear Quadratic Equation - 16
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The document presents a quadratic equation problem where a and b are roots of the equation x^2 - 6x + 4 = 0. It is given that a^2 = 6a - 4 and b^2 = 6b - 4. The value of (2a+1)*(2b+1) is calculated by using the properties that a + b = 6 and ab = 4. The final expression is simplified to 29.
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Linear Quadratic Equation - 16
- 2. Linear Quadratic Equation a2 = 6a - 4, b2 = 6b – 4, what is the value of (2a+1)*(2b+1) (a) 17 (b) 13 (c) 29 (d) 28 (e) 16
- 3. Linear Quadratic Equation Solution: a2 = 6a – 4 b2 = 6b – 4 a, b are roots of the equation x2 – 6x + 4 = 0 a + b = 6 ab = 4 (2a + 1)(2b + 1) = 4ab + 2(a + b) + 1 = 4 x 4 x 2 6 + 1 = 16 + 12 + 1 a2 = 6a - 4, b2 = 6b – 4, what is the value of (2a+1)*(2b+1)
- 4. Linear Quadratic Equation Answer choice (C) a2 = 6a - 4, b2 = 6b – 4, what is the value of (2a+1)*(2b+1)
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