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Multiplexing and Spreading
Data Communication and
Computer Networks
Presentation By:-
Pawan Singh Raikhola
2
Sharing Medium
M
U
X
D
E
M
U
X
 A link is divided into channels
n signals
(input)
n signals
(output)
1 link, n channels
Multiplexer Demultiplexer
3
Frequency Division Multiplexing (FDM)
 Medium BW > Channel BW
 Each signal is modulated to a different
carrier frequency
 E.g., broadcast radio
 Channel allocated even if no data
An analog multiplexing technique to combine signals
4
Conceptual View of FDM
Channel
3
Channel
2
Channel
1
f1
f2
f3
5
FDM: Multiplexing Process
6
FDM: Demultiplexing Process
7
Guard Bands
 Strips of unused bandwidth to prevent signals from
overlapping
FDM
3 kHz
f
FDM
(no guard band)
FDM
(with guard band)
f
3 kHz 3 kHz 3 kHz
f
3 kHz 3 kHz 3 kHz
f
3 kHz
f
3 kHz 3 kHz 3 kHz
8
FDM: Example 1
Five voice channels, each with 3-kHz
bandwidth, are to be multiplexed together.
If there is a need for a guard band of 1.5 kHz,
what is the minimum bandwidth of the link?
f
3 kHz 3 kHz 3 kHz 3 kHz 3 kHz
1.5 kHz 1.5 kHz 1.5 kHz 1.5 kHz
21 kHz
9
FDM: Example 2
Four digital-data channels, 1 Mbps each,
use a satellite channel of 1 MHz. Design an
appropriate configuration using FDM
10
Analog Hierarchy
F
D
M F
D
M
F
D
M
F
D
M
5
groups
…
10
supergropus
6
master
groups
group
supergroup
master
group
Jumbo
group
4 kHz
4 kHz
4 kHz
…
12
voice
channels
 Used by AT&T
48 kHz
12 voice channels
240 kHz
60 voice channels
2.52 MHz
600 voice channels
16.984 MHz
3600 voice channels
11
The Advanced Mobile Phone System (AMPS) uses two
bands. The first band of 824 to 849 MHz is used for
sending, and 869 to 894 MHz is used for receiving.
Each user has a bandwidth of 30 kHz in each direction.
How many people can use their cellular phones
simultaneously?
Solution
Each band is 25 MHz. If we divide 25 MHz by 30 kHz, we
get 833.33. In reality, the band is divided into 832
channels. Of these, 42 channels are used for control,
which means only 790 channels are available for cellular
phone users.
Example
12
Multiplexer Demultiplexer
Wavelength Division Multiplexing (WDM)
 WDM is a special case of FDM
1
2
3
1
2
3
1+2+3
Fiber-optic cable
WDM WDM
1
2
3
1
2
3
1+2+3
An analog multiplexing technique to combine optical signals
13
 Medium Data Rate > Signal Data Rate
 Multiple digital signals interleaved in time
 Time slots
 are preassigned to sources and fixed
 are allocated even if no data
 do not have to be evenly distributed among sources
Time Division Multiplexing (TDM)
T
D
M
A
B
C
A
B
C
A
B
C
A
B
C
Frame
Time slot
A digital multiplexing technique to combine data
one unit
14
Conceptual View of TDM
Channel
3
Channel
2
Channel
1
Channel
3
Channel
2
Channel
1
Channel
3
Channel
2
Channel
1
2
3 1
M
U
X
1
2
3
2
3 1
2
3 1
1
2
3
D
E
M
U
X
Data flow
15
TDM Frames
 A frame consists of one complete cycle of
time slots
16
TDM: Example
Four 1-Kbps connections are multiplexed together.
A unit is 1 bit. Find:
(1) the duration of 1 bit before multiplexing,
(2) the transmission rate of the link,
(3) the duration of a time slot, and
(4) the duration of a frame?
17
Empty Slot
18
Synchronization
B
C A 1
… 1 0 1 0 …
Synchronization pattern
 Multiplexer and demultiplexer must be
synchronized
 Framing bits are used to provide synchronization
B
C A 0 B
C A 1 B
C A 0
framing bit
19
Synchronization: Example
 Identify all the framing bits from this bit
sequence output by a multiplexer
 2 channels
 1 unit = 2 bits
0 0 0 1 1 0 1 1 1 0 0 0 0 1 0 0 1 0 1 1
20
Multi-Level Multiplexing
21
TDM of Different Data Rates
 Data rate from one source may be faster than the others
 More than one time slot can be assigned to certain sources
4 kbps
4 kbps
8 kbps 16 kbps
MUX
A
B
C
1 frame
B
C A
B
Note: assume 1 unit = 1 bit
4 kbps
4 kbps
8 kbps
4 kbps
4 kbps
16 kbps
MUX
A
B
C
22
TDM of Different Data Rates
5 kbps
3 kbps
8 kbps
A
B
A
B A A A A
B B
B B B
A A A A A
1 frame
A
B A A A A
B B
MUX
Note: assume 1 unit = 1 bit
23
5 kbps
3 kbps
A
B
6 kbps
Bit Padding
 Different data rates may not be integer
multiples of each other
 Solution – Bit padding
9 kbps
Bit
Padding
MUX
A A
B A A
B
B A
A A
B
3000 cycles/s
Extra bit
1 ms
Note: assume 1 unit = 1 bit
A A
B A A
B
B A
A A
A A
A
B
B
B
24
Digital Signal (DS) Hierarchy
T
D
M
T
D
M
T
D
M
DS-1
DS-2
DS-3
DS-4
DS-0
T
D
M
DS-0
…
24
channels
1.544 Mbps
24 DS-0
6.312 Mbps
4 DS-1
44.376 Mbps
7 DS-2
274.176 Mbps
6 DS-3
64 kbps
1 kbps = 1,000 bps
1 Mbps = 1,000 kbps
25
DS Services and T Lines
Service Line
Rate
(Mbps)
Voice
Channels
DS-1 T-1 1.544 24
DS-2 T-2 6.312 96
DS-3 T-3 44.736 672
DS-4 T-4 274.176 4032
 DS-0, DS-1, etc, are services
 T lines are used to implement these services
26
T Lines and Analog Signals
27
T-1 Frame Structure
28
E Lines
 European's version of T lines
 Also used in Thailand
E Line
Rate
(Mbps)
Voice
Channels
E-1 2.048 30
E-2 8.448 120
E-3 34.368 480
E-4 139.264 1920
29
Inverse Multiplexing
Inverse
DEMUX
Inverse
MUX
high-speed line high-speed line
low-speed lines
30
Spread Spectrum
 Spread signal to use larger bandwidth
 To prevent eavesdropping
 To reduce effect from interference
31
Frequency-Hopping SS
 "FHSS" – Frequency-Hopping Spread Spectrum
 Used in Bluetooth technology
32
FHSS Cycles
33
Direct-Sequence SS
 "DSSS" – Direct-Sequence Spread Spectrum
 Used in Wireless LANs
34
DSSS and Interference
Narrow Band Signal
Frequency
Amplitude
Narrow Band Interference
Spread Spectrum Signal
35
DSSS Example

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Multiplexing and spreading

  • 1. Multiplexing and Spreading Data Communication and Computer Networks Presentation By:- Pawan Singh Raikhola
  • 2. 2 Sharing Medium M U X D E M U X  A link is divided into channels n signals (input) n signals (output) 1 link, n channels Multiplexer Demultiplexer
  • 3. 3 Frequency Division Multiplexing (FDM)  Medium BW > Channel BW  Each signal is modulated to a different carrier frequency  E.g., broadcast radio  Channel allocated even if no data An analog multiplexing technique to combine signals
  • 4. 4 Conceptual View of FDM Channel 3 Channel 2 Channel 1 f1 f2 f3
  • 7. 7 Guard Bands  Strips of unused bandwidth to prevent signals from overlapping FDM 3 kHz f FDM (no guard band) FDM (with guard band) f 3 kHz 3 kHz 3 kHz f 3 kHz 3 kHz 3 kHz f 3 kHz f 3 kHz 3 kHz 3 kHz
  • 8. 8 FDM: Example 1 Five voice channels, each with 3-kHz bandwidth, are to be multiplexed together. If there is a need for a guard band of 1.5 kHz, what is the minimum bandwidth of the link? f 3 kHz 3 kHz 3 kHz 3 kHz 3 kHz 1.5 kHz 1.5 kHz 1.5 kHz 1.5 kHz 21 kHz
  • 9. 9 FDM: Example 2 Four digital-data channels, 1 Mbps each, use a satellite channel of 1 MHz. Design an appropriate configuration using FDM
  • 10. 10 Analog Hierarchy F D M F D M F D M F D M 5 groups … 10 supergropus 6 master groups group supergroup master group Jumbo group 4 kHz 4 kHz 4 kHz … 12 voice channels  Used by AT&T 48 kHz 12 voice channels 240 kHz 60 voice channels 2.52 MHz 600 voice channels 16.984 MHz 3600 voice channels
  • 11. 11 The Advanced Mobile Phone System (AMPS) uses two bands. The first band of 824 to 849 MHz is used for sending, and 869 to 894 MHz is used for receiving. Each user has a bandwidth of 30 kHz in each direction. How many people can use their cellular phones simultaneously? Solution Each band is 25 MHz. If we divide 25 MHz by 30 kHz, we get 833.33. In reality, the band is divided into 832 channels. Of these, 42 channels are used for control, which means only 790 channels are available for cellular phone users. Example
  • 12. 12 Multiplexer Demultiplexer Wavelength Division Multiplexing (WDM)  WDM is a special case of FDM 1 2 3 1 2 3 1+2+3 Fiber-optic cable WDM WDM 1 2 3 1 2 3 1+2+3 An analog multiplexing technique to combine optical signals
  • 13. 13  Medium Data Rate > Signal Data Rate  Multiple digital signals interleaved in time  Time slots  are preassigned to sources and fixed  are allocated even if no data  do not have to be evenly distributed among sources Time Division Multiplexing (TDM) T D M A B C A B C A B C A B C Frame Time slot A digital multiplexing technique to combine data one unit
  • 14. 14 Conceptual View of TDM Channel 3 Channel 2 Channel 1 Channel 3 Channel 2 Channel 1 Channel 3 Channel 2 Channel 1 2 3 1 M U X 1 2 3 2 3 1 2 3 1 1 2 3 D E M U X Data flow
  • 15. 15 TDM Frames  A frame consists of one complete cycle of time slots
  • 16. 16 TDM: Example Four 1-Kbps connections are multiplexed together. A unit is 1 bit. Find: (1) the duration of 1 bit before multiplexing, (2) the transmission rate of the link, (3) the duration of a time slot, and (4) the duration of a frame?
  • 18. 18 Synchronization B C A 1 … 1 0 1 0 … Synchronization pattern  Multiplexer and demultiplexer must be synchronized  Framing bits are used to provide synchronization B C A 0 B C A 1 B C A 0 framing bit
  • 19. 19 Synchronization: Example  Identify all the framing bits from this bit sequence output by a multiplexer  2 channels  1 unit = 2 bits 0 0 0 1 1 0 1 1 1 0 0 0 0 1 0 0 1 0 1 1
  • 21. 21 TDM of Different Data Rates  Data rate from one source may be faster than the others  More than one time slot can be assigned to certain sources 4 kbps 4 kbps 8 kbps 16 kbps MUX A B C 1 frame B C A B Note: assume 1 unit = 1 bit 4 kbps 4 kbps 8 kbps 4 kbps 4 kbps 16 kbps MUX A B C
  • 22. 22 TDM of Different Data Rates 5 kbps 3 kbps 8 kbps A B A B A A A A B B B B B A A A A A 1 frame A B A A A A B B MUX Note: assume 1 unit = 1 bit
  • 23. 23 5 kbps 3 kbps A B 6 kbps Bit Padding  Different data rates may not be integer multiples of each other  Solution – Bit padding 9 kbps Bit Padding MUX A A B A A B B A A A B 3000 cycles/s Extra bit 1 ms Note: assume 1 unit = 1 bit A A B A A B B A A A A A A B B B
  • 24. 24 Digital Signal (DS) Hierarchy T D M T D M T D M DS-1 DS-2 DS-3 DS-4 DS-0 T D M DS-0 … 24 channels 1.544 Mbps 24 DS-0 6.312 Mbps 4 DS-1 44.376 Mbps 7 DS-2 274.176 Mbps 6 DS-3 64 kbps 1 kbps = 1,000 bps 1 Mbps = 1,000 kbps
  • 25. 25 DS Services and T Lines Service Line Rate (Mbps) Voice Channels DS-1 T-1 1.544 24 DS-2 T-2 6.312 96 DS-3 T-3 44.736 672 DS-4 T-4 274.176 4032  DS-0, DS-1, etc, are services  T lines are used to implement these services
  • 26. 26 T Lines and Analog Signals
  • 28. 28 E Lines  European's version of T lines  Also used in Thailand E Line Rate (Mbps) Voice Channels E-1 2.048 30 E-2 8.448 120 E-3 34.368 480 E-4 139.264 1920
  • 30. 30 Spread Spectrum  Spread signal to use larger bandwidth  To prevent eavesdropping  To reduce effect from interference
  • 31. 31 Frequency-Hopping SS  "FHSS" – Frequency-Hopping Spread Spectrum  Used in Bluetooth technology
  • 33. 33 Direct-Sequence SS  "DSSS" – Direct-Sequence Spread Spectrum  Used in Wireless LANs
  • 34. 34 DSSS and Interference Narrow Band Signal Frequency Amplitude Narrow Band Interference Spread Spectrum Signal