![2/3
ee HCLQ =
[ ] eaPe HKKNLL +−= *2
357*5 === LLe
2/3
)7*5(2.26500 eH=
41.842/3
=eH
24.19=eH](https://image.slidesharecdn.com/assignmentno4-150302123237-conversion-gate02/85/ogee-design-12-320.jpg)
![[ ] eaPe HKKNLL +−= *2
[ ]201.001.0*4235 +−=eL
= 29.4
2/3
eeHCLQ =
2/3
)4.29(2.26500 eH=](https://image.slidesharecdn.com/assignmentno4-150302123237-conversion-gate02/85/ogee-design-14-320.jpg)
ogee design
- 1. Design of ogee spillwayDesign of ogee spillway
- 2. Offsets and Risers onOffsets and Risers on Upstream Face :Upstream Face : 13/2/14 Prepared by v.h,khokhani, assistant professor, DIET 2
- 3. PracticalProfileofSpillwaYPracticalProfileofSpillwaY When the profile for the crest of theWhen the profile for the crest of the ogee spillway is plotted over theogee spillway is plotted over the triangular profile the section of atriangular profile the section of a gravity dam (non-overflowgravity dam (non-overflow section) ,it is found that it goessection) ,it is found that it goes beyond vie downstream face of thebeyond vie downstream face of the dam , thu requiring thickening ofdam , thu requiring thickening of the section for the spillway .the section for the spillway .
- 5. However,this extra concrete can beHowever,this extra concrete can be saved by shifting the curve of thesaved by shifting the curve of the nappe in a backward direction untilnappe in a backward direction until this curve becomes tangential to thethis curve becomes tangential to the downstream face of the dam .downstream face of the dam .
- 7. Offsets and Risers onOffsets and Risers on Upstream FaceUpstream Face 13/2/14 Prepared by v.h,khokhani, assistant professor, DIET 7
- 8. Factors affecting on spill wayFactors affecting on spill way
- 9. Design of spillwayDesign of spillway Design an ogee spillway forDesign an ogee spillway for concrete gravity dam, for theconcrete gravity dam, for the following data :following data : (1) Average river bed level = 250.0(1) Average river bed level = 250.0 mm (2) R.L. of spillway crest =350.0 m(2) R.L. of spillway crest =350.0 m 13/2/14 Prepared by v.h,khokhani, assistant professor, DIET 9
- 10. (3) Slope of d/s face of gravity dam(3) Slope of d/s face of gravity dam = 0.75 H : 1 V= 0.75 H : 1 V (4) Design discharge = 6500 cumecs(4) Design discharge = 6500 cumecs (5) Length of spillway = 5 spans(5) Length of spillway = 5 spans with a clear width of 7 m each.with a clear width of 7 m each. (6) Thickness of each pier = 2.0 m(6) Thickness of each pier = 2.0 m 13/2/14 Prepared by v.h,khokhani, assistant professor, DIET 10
- 11. Step-1 : Computation ofStep-1 : Computation of design headdesign head HHdd = H= Hee + H+ Haa Where HWhere Haa = V= Vaa 22 /2g/2g 13/2/14 Prepared by v.h,khokhani, assistant professor, DIET 11
- 12. 2/3 ee HCLQ = [ ] eaPe HKKNLL +−= *2 357*5 === LLe 2/3 )7*5(2.26500 eH= 41.842/3 =eH 24.19=eH
- 13. 50.19=eH 100250350 =−=h 33.112.5 5.19 100 ≥== dH h 7.112.6 5.19 5.19100 ≥= + = + d d H Hh VELOCITY APPROACH CAN BE NEGLECTED EFFECT ON DISCHARGE COEFFICIENT IS NEGLECTED
- 14. [ ] eaPe HKKNLL +−= *2 [ ]201.001.0*4235 +−=eL = 29.4 2/3 eeHCLQ = 2/3 )4.29(2.26500 eH=
- 16. 24.27 85.1 85.0 x dx dy = 85.0 0678.0 x dx dy = Comparing both dy/dx we get x = 33.26 and Y =24.01 24.27 85.1 X Y =
- 17. X Y 1 0.036 2 0.132 3 0.265 4 0.477 5 0.720 6 1.01 7 1.343 8 1.719 9 2.138 10 2.598 14 4.843 18 7.709 22 11.175 26 15.22 30 19.836 33.6 24.463
- 18. u/s profile :u/s profile : 625.085.1 )832.5(365.172.2)832.5(05.0 +−++= xxy
- 19. This curve will extend up to,This curve will extend up to, X=-0.27*21.6 = - 5.832 625.085.1 )832.5(365.172.2)832.5(05.0 +−++= xxy
- 22. Design of d/s bucket :Design of d/s bucket : The radius of the bucket isThe radius of the bucket is generally kept equal to,generally kept equal to, The bucket will subtend an angle ofThe bucket will subtend an angle of 60° at the centre.60° at the centre.
- 23. Examples - mahajanExamples - mahajan An ogee spillway has 2.8 m headAn ogee spillway has 2.8 m head above the crest .Depth of flow at theabove the crest .Depth of flow at the toe of spillway is measured equal totoe of spillway is measured equal to 0.7 m. The tail watcr depth is 4.0m.0.7 m. The tail watcr depth is 4.0m. Suggest the type of energySuggest the type of energy dissipater and give its dimensiondissipater and give its dimension Assume coefficient C as 2.2 in theAssume coefficient C as 2.2 in the equation = CHequation = CH3/23/2
- 24. DATADATA Head over spillway H=2.8mHead over spillway H=2.8m Initial depth y1 = 0.7mInitial depth y1 = 0.7m Tail water depth y 2 =4.0mTail water depth y 2 =4.0m Discharge coefficient C=2.2Discharge coefficient C=2.2
- 25. STEP 1 Will be to find outSTEP 1 Will be to find out sequent depth.sequent depth. q=CHq=CH3/23/2 Q = 2.2 * 2.8Q = 2.2 * 2.83/23/2 = 10.30 M= 10.30 M33 /S/M/S/M Pre jump DepthPre jump Depth VV11 = q/y= q/y11 = 10.30/ 0.7= 10.30/ 0.7