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Wave Propagation, Huygens’
Principle, and Interference
Physics 101 LO
By Elaine Lee
Huygens’s
Principle
Any point on a wave front can be
considered to be point source
producing spherical secondary
wavelets. The tangential surface of
the secondary wavelets predict
the new position of the wave front
over time.
Christiaan Huygens. Digital image. Molecular Expressions. N.p., n.d. Web. 12 Mar. 2015.
This principle can be applied to all waves.
Plane Waves:
-have wave fronts that are
parallel to each other
Spherical Waves:
- have spherical wave fronts that
are centered on the point source
To Apply Huygens’ Principle:
1. Draw a set of equally spaced points on the wave front.
2. Using each point as the center of a secondary wavelet, draw a set of spherical
wavelets with the same radius.
3. Predict the resulting wave front by drawing tangents to the spherical waves.
Huygens' Principle. Digital image. Oocities. N.p., n.d. Web. 12 Mar. 2015. Huygens' Principle. Digital image. Cliffsnotes. N.p., n.d. Web. 12 Mar. 2015.
INTERFERENCE
-separated by intervals of
space and time
INTERFERENCE- separated by intervals of space
COMPARING THE PHASE DIFFERENCE OF ONE DIMENSIONAL WAVES TO 3D WAVES
 Consider waves with the same frequency and wavelength
One Dimensional Waves:
(waves propagate in one direction)
-have fixed phase differences
that are independent of time and position
(depends on the difference between phase
constants of the two waves)
Three Dimensional Waves:
(waves propagate in different directions)
-have relative phases that vary with position
E.g. phase constant difference of pi/3 rad
positions where the waves are perfectly out of
phase
positions where the waves are perfectly in
phase
Crests of
waves
Crests of
waves
Hawkes, Iqbal, Mansour, Milner-Boloton, and Williams. Wave Interference Diagrams. Digital image. N.P., n.d. Web. 12 Mar 2015.
Interference is a phenomenon in which two
waves superimpose to form a resultant
wave of greater or lower amplitude
Two Point Source Interference Pattern
Crests
Troughs
Constructive Interference
Destructive Interference
Line of Constructive Interference
Two Point Source Interference Pattern. Digital image. Physicsclassroom. N.p., n.d. Web. 12 Mar. 2015.
DESTRUCTIVE INTERFERENCE:
The path difference (∆d) between the two
sources must be a half-integer multiple of
the wavelength (i.e. an odd number of half
wavelengths)
NOTE: Path difference is the difference in
distance travelled by the two waves from
their respective sources to a given point
NOTE: destructive interference can be
observed when 2 waves out of phase by pi
General Condition For:
E.g. ∆d = 4λ – 3.5λ = 0.5λ
Two Point Source Interference. Digital image. Physicsclassroom. N.p., n.d. Web. 12 Mar. 2015.
General Condition For:
CONSTRUCTIVE INTERFERENCE:
The path difference between the two
sources must be an integer multiple of the
wavelength
NOTE: the paths individually do not have to
be integer multiples of the wavelength
NOTE: constructive interference can be
observed when 2 waves are in phase
The function of a spherical wave is given by
We can neglect the phase constant if both
waves are in phase

NOTE: if d1 = d2 = d, simply add the two
waves to find the resultant wave
E.g. ∆d = 7λ – 6λ = 1λ
E.g. ∆d = 7.5λ – 6.5λ = 1λ
Two Point Source Interference. Digital image. Physicsclassroom. N.p., n.d.
Web. 12 Mar. 2015
QUESTION 1:
What is the path difference between the two
sources to point A? Is there constructive
interference or destructive interference at Point
A?
Two Point Source Interference Pattern. Digital image. Physicsclassroom. N.p., n.d. Web. 12 Mar. 2015.
QUESTION 1 ANSWER:
The red lines indicate the paths travelled by the two waves from their respective sources to
a Point A. The distance between each red dot is one wavelength (crest to crest).
∆d = d2 – d1 = 6λ – 5λ = 1λ
The path difference between the two sources to Point A is an integer multiple of the
wavelength, thus Point A is a point of constructive interference.
QUESTION 2:
At which points would constructive interference
occur? How many of the labeled points represent
nodes?
Two Point Source Interference Pattern. Digital image. Physicsclassroom. N.p., n.d. Web. 12 Mar. 2015.
QUESTION 2 ANSWER:
Constructive interference would occur at
Point A and Point B because both points are
at locations where a crest meets a crest.
Four out of the six points represent nodes.
Points C, D, E and F are points where crests
and troughs meet.
Interference- separated by intervals of time
Beats are periodic fluctuations heard in the
intensity of a sound when two sound waves of
very similar frequencies interfere with one
another
 The rate at which amplitude increases and
decreases as a function of time is proportional to
the frequency difference
Beat Frequency:
the rate at which the volume is heard to be
oscillating from high to low volume
E.g. If three complete cycles of high and low
volumes are heard every second, the beat
frequency is 3 Hz.
 The beat frequency is equal to the difference in
frequency of the two tones that interfere to
produce beats.
QUESTION 3:
A guitarist plays a 110 Hz tone while his
friend simultaneously plays a tone with a
frequency of 115 Hz. How many beats will
be heard over a period of 15 seconds?
QUESTION 3 ANSWER:
The beat frequency is equal to the difference
in frequency of the two tones that interfere to
produce beats.
The beat frequency will be 5 Hz.
( 115 Hz – 110 Hz = 5 Hz )
Thus, in 15 seconds, there should be 75 beats.
( 5 Hz x 15s = 75 beats)

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Physics 101 Huygens' Principle and Interference

  • 1. Wave Propagation, Huygens’ Principle, and Interference Physics 101 LO By Elaine Lee
  • 2. Huygens’s Principle Any point on a wave front can be considered to be point source producing spherical secondary wavelets. The tangential surface of the secondary wavelets predict the new position of the wave front over time. Christiaan Huygens. Digital image. Molecular Expressions. N.p., n.d. Web. 12 Mar. 2015.
  • 3. This principle can be applied to all waves. Plane Waves: -have wave fronts that are parallel to each other Spherical Waves: - have spherical wave fronts that are centered on the point source To Apply Huygens’ Principle: 1. Draw a set of equally spaced points on the wave front. 2. Using each point as the center of a secondary wavelet, draw a set of spherical wavelets with the same radius. 3. Predict the resulting wave front by drawing tangents to the spherical waves. Huygens' Principle. Digital image. Oocities. N.p., n.d. Web. 12 Mar. 2015. Huygens' Principle. Digital image. Cliffsnotes. N.p., n.d. Web. 12 Mar. 2015.
  • 5. INTERFERENCE- separated by intervals of space COMPARING THE PHASE DIFFERENCE OF ONE DIMENSIONAL WAVES TO 3D WAVES  Consider waves with the same frequency and wavelength One Dimensional Waves: (waves propagate in one direction) -have fixed phase differences that are independent of time and position (depends on the difference between phase constants of the two waves) Three Dimensional Waves: (waves propagate in different directions) -have relative phases that vary with position E.g. phase constant difference of pi/3 rad positions where the waves are perfectly out of phase positions where the waves are perfectly in phase Crests of waves Crests of waves Hawkes, Iqbal, Mansour, Milner-Boloton, and Williams. Wave Interference Diagrams. Digital image. N.P., n.d. Web. 12 Mar 2015.
  • 6. Interference is a phenomenon in which two waves superimpose to form a resultant wave of greater or lower amplitude
  • 7. Two Point Source Interference Pattern Crests Troughs Constructive Interference Destructive Interference Line of Constructive Interference Two Point Source Interference Pattern. Digital image. Physicsclassroom. N.p., n.d. Web. 12 Mar. 2015.
  • 8. DESTRUCTIVE INTERFERENCE: The path difference (∆d) between the two sources must be a half-integer multiple of the wavelength (i.e. an odd number of half wavelengths) NOTE: Path difference is the difference in distance travelled by the two waves from their respective sources to a given point NOTE: destructive interference can be observed when 2 waves out of phase by pi General Condition For: E.g. ∆d = 4λ – 3.5λ = 0.5λ Two Point Source Interference. Digital image. Physicsclassroom. N.p., n.d. Web. 12 Mar. 2015.
  • 9. General Condition For: CONSTRUCTIVE INTERFERENCE: The path difference between the two sources must be an integer multiple of the wavelength NOTE: the paths individually do not have to be integer multiples of the wavelength NOTE: constructive interference can be observed when 2 waves are in phase The function of a spherical wave is given by We can neglect the phase constant if both waves are in phase NOTE: if d1 = d2 = d, simply add the two waves to find the resultant wave E.g. ∆d = 7λ – 6λ = 1λ E.g. ∆d = 7.5λ – 6.5λ = 1λ Two Point Source Interference. Digital image. Physicsclassroom. N.p., n.d. Web. 12 Mar. 2015
  • 10. QUESTION 1: What is the path difference between the two sources to point A? Is there constructive interference or destructive interference at Point A? Two Point Source Interference Pattern. Digital image. Physicsclassroom. N.p., n.d. Web. 12 Mar. 2015.
  • 11. QUESTION 1 ANSWER: The red lines indicate the paths travelled by the two waves from their respective sources to a Point A. The distance between each red dot is one wavelength (crest to crest). ∆d = d2 – d1 = 6λ – 5λ = 1λ The path difference between the two sources to Point A is an integer multiple of the wavelength, thus Point A is a point of constructive interference.
  • 12. QUESTION 2: At which points would constructive interference occur? How many of the labeled points represent nodes? Two Point Source Interference Pattern. Digital image. Physicsclassroom. N.p., n.d. Web. 12 Mar. 2015.
  • 13. QUESTION 2 ANSWER: Constructive interference would occur at Point A and Point B because both points are at locations where a crest meets a crest. Four out of the six points represent nodes. Points C, D, E and F are points where crests and troughs meet.
  • 14. Interference- separated by intervals of time Beats are periodic fluctuations heard in the intensity of a sound when two sound waves of very similar frequencies interfere with one another  The rate at which amplitude increases and decreases as a function of time is proportional to the frequency difference
  • 15. Beat Frequency: the rate at which the volume is heard to be oscillating from high to low volume E.g. If three complete cycles of high and low volumes are heard every second, the beat frequency is 3 Hz.  The beat frequency is equal to the difference in frequency of the two tones that interfere to produce beats.
  • 16. QUESTION 3: A guitarist plays a 110 Hz tone while his friend simultaneously plays a tone with a frequency of 115 Hz. How many beats will be heard over a period of 15 seconds?
  • 17. QUESTION 3 ANSWER: The beat frequency is equal to the difference in frequency of the two tones that interfere to produce beats. The beat frequency will be 5 Hz. ( 115 Hz – 110 Hz = 5 Hz ) Thus, in 15 seconds, there should be 75 beats. ( 5 Hz x 15s = 75 beats)