Planet Motion Features Disproves Newton Theory (Revised)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Planet Motion Features Disproves Newton Theory (Revised)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –17th
September 2021
Abstract
Paper hypothesis
- The Solar Planet Motion Use Different Rates Of Time, Which Disproves (Newton
Theory Of The Sun Mass Gravity)
- The Planets Motions Using Of Different Rates Of Time Prove (Light Motion
Effect on Planet Motion)
Paper hypothesis Explanation
- 3 New Features Of The Solar Planet Motion Be Discovered Later Which Are:
- (1) The Solar Planets Motions Use Different Rates Of Time
- (2) The Solar Planets Motions Be Integrated In One Unified Motion
- (3) The Solar System Distances Be Created In A Network Form.
- The solar planets motions data analysis proves that, the previous 3 features are
facts and effect on the planets motions.
- The 3 features give us another vision about the solar system motion and disproves
Newton Theory of the sun mass gravity. Also they disprove the planet motion
Independency Concept which is inherited from Newton Theory.
Paper Objective
(1) The paper discussion proves that, the 3 features are facts effect on the solar
planets motions.
(2) The paper discussion disproves Newton Theory Of The Sun Mass Gravity And
The Planet Motion Independency Concept.

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(3) The paper discussion shows, these 3 features effect on the planets motions as a
result of Light Motion Effect On Planets Motions.
Paper Conclusions
- Matter And Space Are Created Out Of Light
- The Solar System Is Created Out Of One Light Beam.
Notice
- No Critic is provided against the mass gravity concept – the critic is against The
sun mass gravity as a reason for the solar planets motion – because – the sun is
created after the solar planets- and based on that – The solar planets be created and
moving before the sun creation. Newton Theory Is Wrong.
Please scan the figure (ORCID)

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Paper Contents
Subject Page No.
1- Introduction 5
2- Methodology 8
3- The Solar Planets Motions Use Different Rates Of Time 11
3-1 Preface 11
3-2 The Rule to Define Planet Motion Rate Of Time 12
3-3 The Rule Using for The Solar Planets Motions 13
3-4 How to know if these rates of time are real? 16
4- The Solar Planets Rates Of Time Analysis 18
4-1 Preface 19
4-2 Venus Motion Rate of time 20
4-3 Earth Motion Rate of time 21
4-4 Mars Motion Rate of time 22
4-5 Jupiter Motion Rate of time 23
4-6 Saturn Motion Rate of time 24
4-7 Uranus Motion Rate of time 25
4-8 Neptune Motion Rate of time 26
4-9 Pluto Motion Rate of time 27
4-10 The General Discussion 28
5- Planets Unified General Motion 33
5-1 The Planets Unified General Motion Description 34
5-2 The Solar Planets Motions Are Complementary One Another 36
5-3 The Solar Planets Move An Unified Motion (A Team Motion) 40
6- Jupiter orbital Circumference Analysis 45
6-1 Preface 46
6-2 Jupiter orbital Circumference Analysis 47
7- Jupiter Motion Analysis 61
7-1 Preface 62
7-2 Jupiter Orbital Period Analysis 63
7-3 Jupiter Orbital Circumference More Discussion 71
7-4 Mars Rotation Period Analysis 75
8- Mercury Motion Distance During Its Day Period 86
8-1 Preface 87
8-2 Why Mercury Jupiter Distance =720.7 mkm? 88
8-3 Pluto Motion For A Distance =720.7 mkm 92
8-4 Jupiter Motion In A Comparison With Light Motion 98
9- The Solar System Historical Development 103
9-1 Preface 104
9-2 Mars Migration Theory 106
9-3 Pluto Migration Theory 109

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9-4 Planets Migration Theories Proves 111
10- The Sun Age Description 114
10-1 The Sun Circles The Earth 115
10-2 The Rate (1.0725) 116
10-3 The Sun Diameter Analysis 120
10-4 The Sun Rays Analysis 123
Paper Part No. (II) The Solar System Creation Theory 128
11- The Solar System Creation Theory 129
11-1 Preface 130
11-2 The Solar System Creation Theory 132
11-3 The Inner Planets Motions Reason 137
11-4 Light Beam (1.16 mkm/sec) Proves Discussion 141
11-5 Saturn Motion More Analysis 179
11-6 Equal Distances Method 186
12-The Solar System Distances Be Created In A Network Form 192
12-1 Preface 193
12-2 The Continuum effect Through the Solar System Distances 195
12-3 The Solar System Distances Distribution 200
12-4 The Solar System Distances Dependency On One Another 204
13- The Planets Motions Rates Of Time (More Discussion) 206
13-1 Preface 207
13-2 Mercury Pluto Motions Rate of Time 208
13-3 Mercury Saturn Motions Rate of Time 212
13-4 Earth, its moon And Pluto Motions Rates Of Time 215
13-5 Earth And Saturn Motions Rates Of Time 224
Appendix No. (1) The Moon Orbital Motion Equation 225
References and Biography 240

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1-Introdcution
- The paper provides new discovered features which changes our vision toward the
solar system motion. let's discuss one feature of them
- (Feature No.1) The Solar Planets Motions Use Different Rates Of Time
- What does that mean (Different Rates Of Time)?
- It means, the clock works differently from one planet to another. for example , one
hour of Mercury motion be = 24.6 hours of Jupiter motion….
- That means,
- While 1 hour of clock passes on Mercury, 24.6 hours on clock passes on Jupiter
- The different rates of time is a meaning we have learnt from special theory of
relativity, and the different rates of time needs high velocity motion (as the theory
tells). So how the solar planets moving by low velocities can use different rates of
time?
- This is done almost by the sun effect on the planets days periods creation. I can't
explain clearly how this is done, but the different rates of time is a fact found in the
planets motions data.
- I want to say that,
- The paper doesn't provide a theory trying to prove it. the paper basic task is to
analyze the planets motions data, and when we do that, we will find the different
rates of time be used usually in the planets motions known data. because of that,
the question (how the planet can use different rate of time?) is another question,
we may deal with it later. But our basic task now is that to prove the fact (for
example) 1 hour of Mercury Motion = 24.6 hours of Jupiter motion. we need to
prove this fact as first and then we need to discover the planets motions rates of
time map and by that we will have a map for the planets motions rates of time.

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- The paper is consisted of 2 parts
- THE FIRST PART OF THE PAPER
- This part analyzes the planets motions data to prove that the 3 features are facts.
- And by data analysis we discover that, the planets use different rates of time
among themselves. For example (1h of Mercury motion =61 h of Saturn motion)
and (1h of Venus Motion = 47.8 h of Saturn motion). we should discover how to
calculate these rates of time and how to prove that they are facts.
- We do that in point no. (3) and (4) of this paper
- The 2nd
feature is (the solar planets motions be integrated into one unified motion)
- We prove this feature in point no. (5) of this paper.
- This feature tells, the solar planets be similar to train carriages move together one
unified motion – or they are similar to machine of gears and each planet is one
gear in it – also the solar planets be similar to 9 waterwheels rotate on one canal by
effect of water motion.
- The 3rd
feature which is (the solar system distances be created in a network form),
this feature we discuss in Part no. (II) of this paper. (point no. 12)
- Now
- We need to know, why the planets motions enjoy these new features? The answer
is that, the planets motions be effected by light motion. that because the solar
planets and their distances be created out of one light beam and they move in
accompanying with this light beam. That's the reason why planet motion shows
light motion features, among which the three features we discuss in this paper.
- In Points no. (6, 7 and 8) we analyze Jupiter motion and its orbital circumference
to show that the planet motion depends on a light beam motion
- Points no. (9 and 10) discover the historical events in the solar system because
these historical events effect on the planets current motions.

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- THE SECOND PART OF THE PAPER
- In this part we proves that a light beam motion is accompanying with the solar
planets motions and effect on them. (Point no. 11)
- That's why we discuss the 3rd
feature (the network of distances) in Part No. (II) of
this paper. Because the distance network shows a direct effect of light motion on
the solar planets motions (Point no. 12)
- Appendix no. 1 provides The Earth Moon Orbital Motion Equation
- I wish the respectful reader will enjoy the reading
- Best Greetings

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- 2- Methodology
- I use the planets motions data analysis in comparison with the theories which try to
explain the planets motions- let's use one example to explain how this method
works?
- Example No. 1
- Newton told us– The planet motion be independent from all other planets motions
- This is the theory – let's see some planets motions data for a comparison
- Data
(1)
Saturn Orbital Distance = Saturn Uranus Distance
= Mars Orbital Circumference
= Pluto Neptune Distance (error 1.5%)
= Pluto eccentricity Distance (error 1.5%)
= Neptune Orbital Distance/π
= Uranus Orbital Distance /2
(2)
Mercury Neptune Distance = Saturn Pluto Distance
Jupiter Pluto Distance = Uranus Neptune Circumference
Earth Neptune Distance = Mercury Saturn Circumference (0.5%)
(3)
Jupiter Mercury Distance = 2 Mercury Orbital Circumference
Jupiter Venus Distance = Venus Orbital Circumference (1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (1.2%)
(Earth and Jupiter at 2 different sides from the sun)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (0.8%)
Pluto Orbital Distance = Earth Orbital Circumference x 2π
Why These Distances Are Equal?

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- The solar system has around (45 distances) and these distance are around (25
distances) why they are equal one another? Can Planets Independent Motions
Cause These Distances Equality?
- In some desert someone sees a mirage and thought it's a water! How can we prove
to him that this is a mirage and Not a water?
- Newton told that, Planets Motions be Independent From One Another, and as a
result - The solar system distances be created based on each other in a Network
form where more than 50% of all distances are equal one another!!
- I try to show that – it was not so great job to disprove Newton Theory – but the
book removes the planets motions data – this is the question – why?
- The planets creations and motions data should be similar to a creature genes which
can tell us how this planet be created and moving – so whatsoever the theory be
the planets motions data be more important than it – and by that – even if Newton
was correct, there's no reason to remove the planets motions data from the book
- The planets motions data is a method almost used by Kepler –
- Let's use one more example
- Example No. 2
- 778.6 mkm = 1.0725 x 720.7 mkm (Mercury Jupiter Distance)
- 720.7 mkm = 1.0725 x 671 mkm (Venus Jupiter Distance)
- 671 mkm = 1.0725 x 629 mkm (Earth Jupiter Distance)
- 629 mkm = (1.0725)2
x 550.7 mkm (Mars Jupiter Distance)
- 550.7 mkm = (1.0725) x 511 mkm
- 4900 mkm = (1.0725) x 4495.1 mkm (Neptune Orbital Distance) (1.6%)
- 1375 mkm = (1.0725) x 1284 mkm (Earth Saturn Distance)
- 4900 mkm = Jupiter orbital circumference
- 1375mkm = Mercury Saturn Circumference

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- The previous distances are 13 distances (30%) of all distances- they are example of
many others- the question is why they are rated with the same one rate (1.0725)?
- I try to show, some geometrical force moves through the planets motions data.
This force is stronger than any planet motion and force all of them to use the same
one rate – No Independent Motion Be Found Here – the data simply disproves
Newton Theory
- The previous data is example for wide range of data – I add some more of them
here to show the strong force range of using this rate (1.0725)
- (28.3 deg / 26.7 deg) =(26.7 deg /25.2 deg) = (25.2 deg /23.4 deg) = (122.5 /115.2)
= (1.0725)
- Where
- 28.3 degrees = Neptune Axial Tilt
- 26.7 degrees = Saturn Axial Tilt
- 25.2 degrees = Mars Axial Tilt
- 23.4 degrees = Earth Axial Tilt
- 115.2 degrees = 90 degrees + 25.2 degrees (Mars Axial Tilt)
- 122.5 degrees = Pluto Axial Tilt.
- Shortly
- The planets data analysis put the data in comparison with the theories to test the
theory sufficiency.

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3- The Solar Planets Motions Use Different Rates Of Time
3-1 Preface
3-2 The Rule to Define Planet Motion Rate Of Time
3-3 The Rule Using for The Solar Planets Motions
3-4 How to know if these rates of time are real?
3-1 Preface
- In this point
- We define the rule by which we can discover the planets motions rates of time
- And we test this rule to know if it work with all planets or not

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3-2 The Rule to Define Planet Motion Rate Of Time
- Let's provide a rule to define the solar planets motions rates of time and then we
should test this rule to know if it works sufficiently – base on that –we can create a
list of the motions rats of time among the solar planets and base on this list we
should to know why the planets motions use different rates of time and how these
rates effect on the solar planets motions –
- Let's provide the rule at first in following:
- The required period by a planet motion to pass a distance = its orbital distance, this
period should be in comparison with 671 hours of Mercury Motion.
- Based on this comparison this planet motion rate of time with Mercury be defined
- Based on that,
- To define a planet motion rate of time, we need 3 steps:
(1) To Define The Required Period This Plant Needs To Pass A Distance = This
Planet Orbital Distance
(2) To Compare This Period with 671 hours of Mercury Motion
(3) Based on this comparison, the rate of time between Mercury and this planet
motions be defined.
- Let's Use This Rule In The Next Point For The Solar Planets Motions.

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3-3 The Rule Using for The Solar Planets Motions
(1)
Venus needs 859 hours to pass a distance = 108.2 mkm (Venus orbital distance)
In comparison with 671 h of Mercury Motion,
The rate of time be (1h of Mercury motion = 1.279 h of Venus Motion)
(2)
Earth needs 1394.5 hours to pass a distance = 149.6 mkm (Earth orbital distance)
The rate of time be (1h of Mercury motion = 2.078 h of Earth Motion)
(1394.5 hours =58.1 days)
(3)
Mars needs 2626.8 hours to pass a distance = 227.9 mkm (Mars orbital distance)
The rate of time be (1h of Mercury motion = 3.91 h of Mars Motion)
(2626.8 hours = 109.4 days)
(4)
Jupiter needs 16510 hours to pass a distance = 778.6 mkm (Jupiter orbital distance)
The rate of time be (1h of Mercury motion = 24.6 h of Jupiter Motion)
(16510 hours =687.9 days)
(5)
Saturn needs 41051 hours to pass a distance = 1433.5 mkm (Saturn orbital distance)
The rate of time be (1h of Mercury motion = 61.18 h of Saturn Motion)
(41051 hours =1710.5 days)

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(6)
Uranus needs 117340 hours to pass a distance =2872.5 mkm (Uranus orbital distance)
The rate of time be (1h of Mercury motion = 174.87 h of Uranus Motion)
(117640 hours = 4890 days)
(7)
Neptune needs 231229.4 hours to pass a distance =4495.1 mkm (Neptune orbital
distance) - In comparison with 671 h of Mercury Motion,
The rate of time be (1h of Mercury motion = 344.6 h of Neptune Motion)
(231229.4 hours = 9634.6 days)
(8)
Pluto needs 349055 hours to pass a distance =5906 mkm (PLUTO orbital distance) -
The rate of time be (1h of Mercury motion = 520.2 h of Pluto Motion)
(349055 hours = 14544 days)
(9) (The Earth Moon)
The Earth moon daily displacement =88000 km
The moon needs 40800 hours to pass a distance =149.6 mkm (Earth orbital distance) -
The rate of time be (1h of Mercury motion = 60.8 h of The moon Motion)
(40800 hours = 1700 days)

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NOW WE HAVE A LIST
MERCURY MOTION LIST
1 hour of Mercury motion = 1.279 h of Venus Motion
1 hour of Mercury motion = 2.078 h of Earth Motion
1 hour of Mercury motion = 3.91 h of Mars Motion
1 hour of Mercury motion = 24.6 h of Jupiter Motion
1 hour of Mercury motion = 61.1 h of Saturn Motion
1 hour of Mercury motion = 174.8 h of Uranus Motion
1 hour of Mercury motion = 344.6 h of Neptune Motion
1 hour of Mercury motion = 520.2 h of Pluto Motion
1 hour of Mercury motion = 60.8 h of The Earth Moon Motion
- The list tells, Saturn and the Moon use the same rate of time!! Why?

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3-4 How To Know If These Rates Of Time Are Real?
I-Data
(3-4-a)
10747 days = 365.25 days x 29.4
II-Discussion
- We have seen that the Earth moon and Saturn use the same rate of time, if the rule
we use is a correct one – now let's try to know –why Saturn and the moon use the
same rate of time and if this rate is a correct one –
(A)
- 1 hour of Mercury motion = 2.078 hours of Earth motion
- and
- 1 hour of Mercury motion = 60.8 hours of The moon motion
- Based on that,
- 1 hour of Earth motion = (60.8 /2.078) = 29.3 hours of The moon motion
- If this rate is a correct one, that means, one day of Earth equal (29.3 days) of the
moon (the moon Day Period = 29.53 solar days) (error 1%)
- Shortly
- 1 hour of Earth motion =29.3 hours of the moon motion
- The moon and Saturn use equal rates of time with Mercury
(B)
- 1 hour of Mercury motion = 2.078 hours of Earth motion
- and
- 1 hour of Mercury motion = 61.1 hours of Saturn motion
- Based on that
- 1 hour of Earth motion = (61.1 /2.078) = 29.4 hours of Saturn motion
- They are almost equal rates (29.3 and 29.4)
- Shortly
- 1 hour of Earth motion =29.4 hours of Saturn Motion

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Equation no. (3-4-a)
10747 days = 365.25 days x 29.4
- Where
- 10747 days = Saturn Orbital Period
- 365.25 days = Earth Orbital Period
- Now,
- The rate of time (1 hour of Earth motion =29.4 h of Saturn motion)be defined
based on each planet motion period for its orbital distance in comparison with
Mercury 671 hours –
- How the 2 planets orbital periods be defined based on this rate of time?
- I want to say that
- The rule I have created it, but why the planets data follows it?
- How this result be created?
- There's some fact behind this rule!
- For that we have to analyze each planet rate of time individually to discover how
these rates work…
- Because of that,
- We should use one new point for the planets motions rates of time analysis – we
should do that in the next point no. (4)

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4- The Solar Planets Rates Of Time Analysis
4-1 Preface
4-2 Venus Motion Rate of time
4-3 Earth Motion Rate of time
4-4 Mars Motion Rate of time
4-5 Jupiter Motion Rate of time
4-6 Saturn Motion Rate of time
4-7 Uranus Motion Rate of time
4-8 Neptune Motion Rate of time
4-9 Pluto Motion Rate of time
4-10 The General Discussion

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4-1 Preface
- In this point we use the rates of time which we calculated in the previous point to
see if the planets orbital periods be defined based on these rates of time as we have
seen the example in Saturn orbital period (10747 days) in the previous discussion.
- We use Mercury motion rates of time as a reference for the other solar planets
motions rates of time –
- The points provides the calculations for each planet with data analysis but the
general discussion be put in a separated point No. (4-10).
- Let's review Mercury Motion rates in following
MERCURY MOTION LIST
1 hour of Mercury motion = 1.279 h of Venus Motion
1 hour of Mercury motion = 2.078 h of Earth Motion
1 hour of Mercury motion = 3.91 h of Mars Motion
1 hour of Mercury motion = 24.6 h of Jupiter Motion
1 hour of Mercury motion = 61.1 h of Saturn Motion
1 hour of Mercury motion = 174.8 h of Uranus Motion
1 hour of Mercury motion = 344.6 h of Neptune Motion
1 hour of Mercury motion = 520.2 h of Pluto Motion
1 hour of Mercury motion = 60.8 h of The Earth Moon Motion
224.7 days (Venus orbital period) = 1.279 x 175.94 days (Mercury Day Period)
365.25 days (Earth orbital period) = 2.078 x 175.94 days (Mercury Day Period)
687 days (Mars orbital period) = 3.91 x 175.94 days (Mercury Day Period)
4331 days (Jupiter orbital period) = 24.6 x 175.94 days (Mercury Day Period)
10747 days (Saturn orbital period) = 61.1 x 175.94 days (Mercury Day Period)
30589 days (Uranus orbital period) = 174.8 x 175.94 days (Mercury Day Period)
59800 days (Neptune orbital period) = 344.6 x 175.94 days (Mercury Day Period)
90560 days (Pluto orbital period) = 520.2 x 175.94 days (Mercury Day Period)
Errors are 1.4% 1% with Neptune and Pluto respectively- no other error more than 1%

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4-2 Venus Motion Rate of time
I – Data
VENUS MOTION LIST
1 hour of Venus motion = (0.78) h of Mercury Motion
1 hour of Venus motion = 1.62 h of Earth Motion
1 hour of Venus motion = 3.057 h of Mars Motion
1 hour of Venus motion = 19.233 h of Jupiter Motion
1 hour of Venus motion = 47.8 h of Saturn Motion
1 hour of Venus motion = 136.7 h of Uranus Motion
1 hour of Venus motion = 269.4 h of Neptune Motion
1 hour of Venus motion = 406.7 h of Pluto Motion
1 hour of Venus motion = 47.54 h of The Moon Motion
II–Data Analysis
175.94 days (Mercury day period) = 0.78 x 224.7 days (Venus orbital period)
365.25 days (Earth orbital period) = 1.62 x 224.7 days (Venus orbital period)
687 days (Mars orbital period) = 3.057 x 224.7 days (Venus orbital period)
4331 days (Jupiter orbital period) = 19.2 x 224.7 days (Venus orbital period)
10747 days (Saturn orbital period) = 47.8 x 224.7 days (Venus orbital period)
30589 days (Uranus orbital period) = 136.7 x 224.7 days (Venus orbital period)
59800 days (Neptune orbital period) = 266.2 x 224.7 days (Venus orbital period)
90560 days (Pluto orbital period) = 403 x 224.7 days (Venus orbital period)
- There Are Errors (1%) Only With Neptune And Pluto Orbital Periods
- Shortly
- All planets orbital periods be created based on Venus orbital period (224.7 days)
by using the rate of time between Venus and these planets – no mistake in all data
more than 1% -
- The Data Proves That – The Rule Controls The Solar System

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4-3 Earth Motion Rate of time
I – Data
EARTH MOTION LIST
1 hour of Earth motion = (0.48) h of Mercury Motion
1 hour of Earth motion = (0.617) h of Venus Motion
1 hour of Earth motion = 1.88 h of Mars Motion
1 hour of Earth motion = 11.8 h of Jupiter Motion
1 hour of Earth motion = 29.4 h of Saturn Motion
1 hour of Earth motion = 84.1 h of Uranus Motion
1 hour of Earth motion = 165.8 h of Neptune Motion
1 hour of Earth motion = 250.4 h of Pluto Motion
1 hour of Earth motion = 29.3 h of The Moon Motion
II–Data Analysis
175.94 days (Mercury day period) = 0.48 x 365.25 days (Earth orbital period)
224.7 days (Venus orbital period) = 0.617 x 365.25 days (Earth orbital period)
687 days (Mars orbital period ) = 1.88 x 365.25 days (Earth orbital period)
4331 days (Jupiter orbital period) = 11.8 x 365.25 days (Earth orbital period)
10747 days (Saturn orbital period) = 29.4 x 365.25 days (Earth orbital period)
30589 days (Uranus orbital period) = 84.1 x 365.25 days (Earth orbital period)
59800 days (Neptune orbital period) = 163.8 x 365.25 days (Earth orbital period)
90560 days (Pluto orbital period) = 248 x 365.25 days (Earth orbital period)
- There Are Errors (1.2% and 1%) Only With Neptune And Pluto Orbital Periods
- Shortly
- All planets orbital periods be created based on Earth orbital period (365.25 days)
by using the rate of time between Earth and these planets – no mistake in all data
more than 1.2% -
The Data Proves That – The Rule Controls The Solar System

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4-4 Mars Motion Rate of time
I – Data
MARS MOTION LIST
1 hour of Mars motion = (0.255) h of Mercury Motion
1 hour of Mars motion = (0.327) h of Venus Motion
1 hour of Mars motion = (0.531) h of Earth Motion
1 hour of Mars motion = 6.3 h of Jupiter Motion
1 hour of Mars motion = 15.6 h of Saturn Motion
1 hour of Mars motion = 44.71 h of Uranus Motion
1 hour of Mars motion = 88.1 h of Neptune Motion
1 hour of Mars motion = 133 h of Pluto Motion
1 hour of Mars motion = 15.55 h of The Moon Motion
II–Data Analysis
175.94 days (Mercury day period) = 0.255 x 687 days (Mars Orbital Period)
224.7 days (Venus orbital period) = 0.327 x 687 days (Mars Orbital Period)
365.25 days (Earth orbital period = 0.531 x 687 days (Mars Orbital Period)
4331 days (Jupiter orbital period) = 6.3 x 687 days (Mars Orbital Period)
10747 days (Saturn orbital period) = 15.6 x 687 days (Mars Orbital Period)
30589 days (Uranus orbital period) = 44.7 x 687 days (Mars Orbital Period)
59800 days (Neptune orbital period) = 88.1 x 687 days (Mars Orbital Period)
90560 days (Pluto orbital period) = 133 x 687 days (Mars Orbital Period)
- There Are Errors (1.2% and 1%) Only With Neptune And Pluto Orbital Periods
- Shortly
- All planets orbital periods be created based on Mars orbital period (687 days) by
using the rate of time between Earth and these planets – no mistake in all data
more than 1.2%
The Data Proves That – The Rule Controls The Solar System

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4-5 Jupiter Motion Rate of time
I – Data
JUPITER MOTION LIST
1 hour of Jupiter motion = (0.040) h of Mercury Motion
1 hour of Jupiter motion = (0.0419) h of Venus Motion
1 hour of Jupiter motion = (0.084) h of Earth Motion
1 hour of Jupiter motion = (0.1589) h of Mars Motion
1 hour of Jupiter motion = 2.48 h of Saturn Motion
1 hour of Jupiter motion = 7.1 h of Uranus Motion
1 hour of Jupiter motion = 14 h of Neptune Motion
1 hour of Jupiter motion = 21.1 h of Pluto Motion
1 hour of Jupiter motion = 2.47 h of The Moon Motion
II–Data Analysis
175.94 days (Mercury day period) = 0.040 x 4331 days (Jupiter Orbital Period)
224.7 days (Venus orbital period) = 0.0419 x 4331 days (Jupiter Orbital Period)
365.25 days (Earth orbital period = 0.084 x 4331 days (Jupiter Orbital Period)
687 days (Mars orbital period) = 0.1589 x 4331 days (Jupiter Orbital Period)
10747 days (Saturn orbital period) = 2.48 x 4331 days (Jupiter Orbital Period)
30589 days (Uranus orbital period) = 7.1 x 4331 days (Jupiter Orbital Period)
59800 days (Neptune orbital period) = 14 x 4331 days (Jupiter Orbital Period)
90560 days (Pluto orbital period) = 21.1 x 4331 days (Jupiter Orbital Period)
- There Are Errors (1.4% and 1%) With Neptune And Pluto Periods respectively
- No other errors more than 1% in all data

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4-6 Saturn Motion Rate of time
I – Data
SATURN MOTION LIST
1 hour of Saturn motion = (0.016) h of Mercury Motion
1 hour of Saturn motion = (0.0209) h of Venus Motion
1 hour of Saturn motion = (0.0339) h of Earth Motion
1 hour of Saturn motion = (0.0639) h of Mars Motion
1 hour of Saturn motion = (0.403) h of Jupiter Motion
1 hour of Saturn motion = 2.857 h of Uranus Motion
1 hour of Saturn motion = 5.63 h of Neptune Motion
1 hour of Saturn motion = 8.5 h of Pluto Motion
1 hour of Saturn motion = 1 h of The Moon Motion
II–Data Analysis
175.94 days (Mercury day period) = 0.040 x 10747 days (Saturn Orbital Period)
224.7 days (Venus orbital period) = 0.0209 x 10747 days (Saturn Orbital Period)
365.25 days (Earth orbital period = 0.0339 x 10747 days (Saturn Orbital Period)
687 days (Mars orbital period) = 0.0639 x 10747 days (Saturn Orbital Period)
4331 days (Jupiter orbital period) = 0.403 x 10747 days (Saturn Orbital Period)
30589 days (Uranus orbital period) = 2.857 x 10747 days (Saturn Orbital Period)
59800 days (Neptune orbital period) = 5.63 x 10747 days (Saturn Orbital Period)
90560 days (Pluto orbital period) = 8.5 x 10747 days (Saturn Orbital Period)
- There Are Errors (1%) Only With Neptune And Pluto Orbital Periods
- Shortly
- All planets orbital periods be created based on Saturn orbital period (10747 days)
by using the rate of time between Venus and these planets – no mistake in all data
more than 1% -

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4-7 Uranus Motion Rate of time
I – Data
URANUS MOTION LIST
1 hour of Uranus motion = (0.0057) h of Mercury Motion
1 hour of Uranus motion = (0.0073) h of Venus Motion
1 hour of Uranus motion = (0.011) h of Earth Motion
1 hour of Uranus motion = (0.022) h of Mars Motion
1 hour of Uranus motion = (0.14) h of Jupiter Motion
1 hour of Uranus motion = (0.3499) h of Saturn Motion
1 hour of Uranus motion = 1.97 h of Neptune Motion
1 hour of Uranus motion = 2.97 h of Pluto Motion
1 hour of Uranus motion = (0.349) h of The Moon Motion
II–Data Analysis
175.94 days (Mercury day period) = 0.0057 x 30589 days ( Uranus Orbital Period)
224.7 days (Venus orbital period) = 0.0073 x 30589 days ( Uranus Orbital Period)
365.25 days (Earth orbital period = 0.011 x 30589 days ( Uranus Orbital Period)
687 days (Mars orbital period) = 0.022 x 30589 days ( Uranus Orbital Period)
4331 days (Jupiter orbital period) = 0.14 x 30589 days ( Uranus Orbital Period)
10747 days (Uranus orbital period) = 0.3499 x 30589 days (Saturn Orbital Period)
59800 days (Neptune orbital period) = 1.97 x 30589 days ( Uranus Orbital Period)
90560 days (Pluto orbital period) = 2.97 x 30589 days ( Uranus Orbital Period)
- No mistake in all data more than 1% -

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4-8 Neptune Motion Rate of time
I – Data
NEPTUNE MOTION LIST
1 hour of Neptune motion = (0.0029) h of Mercury Motion
1 hour of Neptune motion = (0.0037) h of Venus Motion
1 hour of Neptune motion = (0.006) h of Earth Motion
1 hour of Neptune motion = (0.011) h of Mars Motion
1 hour of Neptune motion = (0.0713) h of Jupiter Motion
1 hour of Neptune motion = (0.177) h of Saturn Motion
1 hour of Neptune motion = (0.507) h of Uranus Motion
1 hour of Neptune motion = 1.509 h of Pluto Motion
1 hour of Neptune motion = (0.1773) h of The Moon Motion
II–Data Analysis
175.94 days (Mercury day period) = 0.0029 x 59800 days (Neptune Orbital Period)
224.7 days (Venus orbital period) = 0.0037 x 59800 days (Neptune Orbital Period)
365.25 days (Earth orbital period = 0.006 x 59800 days (Neptune Orbital Period)
687 days (Mars orbital period) = 0.011 x 59800 days (Neptune Orbital Period)
4331 days (Jupiter orbital period) = 0.0713 x 59800 days (Neptune Orbital Period)
10747 days (Saturn orbital period) = 0.177 x 59800 days (Neptune Orbital Period)
30589 days (Uranus orbital period) = 0.507 x 59800 days (Neptune Orbital Period)
90560 days (Pluto orbital period) = 1.509 x 59800 days (Neptune Orbital Period)
- Neptune orbital period creates error 1.3% with all data except Pluto and Uranus

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4-9 Pluto Motion Rate of time
I – Data
PLUTO MOTION LIST
1 hour of Pluto motion = (0.00192) h of Mercury Motion
1 hour of Pluto motion = (0.00245) h of Venus Motion
1 hour of Pluto motion = (0.00399) h of Earth Motion
1 hour of Pluto motion = (0.0075) h of Mars Motion
1 hour of Pluto motion = (0.0472) h of Jupiter Motion
1 hour of Pluto motion = (0.1174) h of Saturn Motion
1 hour of Pluto motion = (0.336) h of Uranus Motion
1 hour of Pluto motion = (0.662) h of Neptune Motion
1 hour of Pluto motion = (0.11743) h of The Moon Motion
II–Data Analysis
175.94 days (Mercury day period) = 0.00192 x 90560 days (Pluto Orbital Period)
224.7 days (Venus orbital period) = 0.00245 x 90560 days (Pluto Orbital Period)
365.25 days (Earth orbital period = 0.00399 x 90560 days (Pluto Orbital Period)
687 days (Mars orbital period) = 0.0075 x 90560 days (Pluto Orbital Period)
4331 days (Jupiter orbital period) = 0.0472 x 90560 days (Pluto Orbital Period)
10747 days (Saturn orbital period) = 0.1174 x 90560 days (Pluto Orbital Period)
30589 days (Uranus orbital period) = 0.336 x 90560 days (Pluto Orbital Period)
59800 days (Neptune orbital period) = 0.662 x 90560 days (Pluto Orbital Period)
- Pluto orbital period creates error 1% with all data.

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4-10 The General Discussion
- The data is clear,
- Shortly
- All planets orbital periods are rated with one another by the rates of time we have
calculated based on the rule –let's remember it in following –
- The Rule
- The period which a planet needs to move a distance equal this planet orbital
distance – this period should be in comparison with the period 671 hours of
Mercury Motion. and by this comparison this planet rate of time be defined and by
that we can know the rates of time among the planets motions.
- This is the rule which we have used and by it we have defined all planets motions
rates of time and we have discovered that all plants orbital periods be rated with
each planet motion rate of time
- We simply catch the machine motor clearly
- Now
- We can claim that, The solar system is one machine and no separated planets
moving in independent motions –it's Not true – The Solar Group is a machine of
Gears each planet moves as one Gear in this machine – because of that – all plants
orbital periods be rated perfectly with one another by the rates of time we have
defined
- Notice
- Mercury itself moves a distance = 2 x Mercury orbital distance during the period
671 hours – but the rule tells any other planet moves a distance = this planet orbital
distance only…
- We have 2 positive results be produced by this data analysis:
- (1st
Result) The Solar Planets Motions Use Different Rates Of Time
- (2nd
Result) The Solar Planets Move As Gears IN One Machine

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- Clearly, No any Independent Motion be found in The Solar System.
- The previous data analysis gives us a powerful argument against the concept
(Planet Motion Independency Concept)
- The data gives us a force to disprove Newton Theory of the sun mass gravity and
the planet motion independency concept which is inherited from it.
- The data clearly tells that, the solar group moves by a different description from
what Newton had told us – simply the facts disproves his theory
- What's The Solar Group?
- The Solar Group is similar to a machine of gears each planet is a gear in it, or
- The Solar Group is similar to one building and each planet is a part of this same
building, or
- The Solar Group is similar to puppets theater, all puppets are connected together
by one force and causes their motions, or
- The Solar Group is similar a canal water moves through the canal and causes the
rotation of 9 waterwheels. The Motion Direction of The waterwheels is different
from the water motion direction but no waterwheel can rotate without the water
motion, or
- The solar planets are similar to train carriages, they move together one unified
general motion, or
- The solar planets be similar to knots on one robe or similar to points on the same
one trajectory of energy –
- The solar planets motions be similar to chess board pieces motions, each motion
depend on the other planets motions and be done by geometrical calculations.
- I want to say
- The previous data analysis gives us clearly another vision around the solar system.
- The point is that, The solar planets are NOT rigid separated bodies from one
another, as Newton told us. The data shows clearly that, The planets are parts in
one machine and their motions be done depending on one another.

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More Discussion
The previous rates of time are the basic rates of time among the solar planets. But
there are rates be produced as parts of these rates which be used by planets motions
data. let's use 2 examples for short discussion.
Example No. (1)
1 hour of Earth motion be = 29.4 hours of Saturn motion
But
The working rate of Data between Earth and Saturn is 9.5, where
29.4 = π x 9.36 (with 9.5 error 1.5%)
Data
(i)
Saturn moves daily 838080 km = the Earth moon displacement 88000 km x 9.5
(ii)
Saturn diameter 120536 km = Earth diameter 12756 km x 9.5
(iii)
Saturn orbital distance 1433.5 mkm = Earth orbital distance 149.6 mkm x 9.5
(iv)
Earth axial tilt 23.4 deg = Saturn orbital inclination 2.5 deg x 9.5 (error 1.7%)
(v)
Saturn Orbital Period 10747 days = 365.25 days x 29.53 days
The data shows that,
The working rate is 9.5 which is produced based on 29.4,
That tells not only the direct rates of time be used between the planets motions data
but also these rates produce others effect on these planets motions data

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Example No. (2)
1 hour of Pluto motion = 0.11743 hours of The Earth moon motion
Means
8.5 hours of the moon motion = 1 hour of Pluto Motion
But
The working rate between Pluto and the moon is (4.61), where
8.5 = 2 x 4.25, and
4.61 = 1.0725 x 4.25 (error 1%)
We know that, the rate (1.0725) effects on 40% of all distances in the solar system
and effect on many other data, so we don't search behind it here to know why it's used
with the moon data.
Shortly
Based on this calculation, the rate (8.5) produces the rate (4.61)
Where
(1)
406000 km (Pluto motion distance during a solar day) = 4.61 x 88000 km
(88000 km = the moon daily displacement)
(2)
708.7 h (The moon day period) = 4.61 x 153.3 h (Pluto Day Period)
Notice
The rate (4.61) is some very great one in the solar system, we should discuss it later
again but to show its massive power may take a look on the next data.

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More Data
778.6 mkm (Jupiter Orbital Distance) = 4.61 x 170 mkm
550.7mkm (Jupiter Mars Distance) = 4.61 x 119.7 mkm
2094 mkm (Jupiter Uranus Distance) = 4.61 x 2 x 227.9 mkm
2872.5 mkm (Uranus Orbital Distance) = 4.61 x 629 mkm
3033.5 mkm (Uranus Pluto Distance) =4.61 x 654.9 mkm
5127 mkm (Jupiter Pluto Distance) = 4.61 x 2 x 550.7 mkm
5906 mkm (Pluto Orbital Distance) =4.61 x 1284 mkm
1375.6 mkm (Mercury Saturn Distance) =4.61 x 2 x 149.6 mkm
3062 mkm (Saturn Neptune Distance) =4.61 x 671 mkm
4345.5 mkm (Earth Neptune Distance) =4.61 x 940 mkm
4267.2 mkm (Mars Neptune Distance) =4.61 x 929 mkm
Where
170 mkm = Mercury Mars Distance
119.7 mkm = Venus Mars Distance
227.9 mkm = Mars Orbital Distance
629 mkm = Jupiter Earth Distance 654.9 mkm = Jupiter Saturn Distance
550.7 mkm = Jupiter Mars Distance 1284 mkm = Earth Saturn Distance
149.6 mkm = Earth Orbital Distance 671 mkm = Jupiter Venus Distance
940 mkm = Earth Orbital Circumference
929 mkm = Earth Jupiter Distance when the 2 planets be on the sun 2 sides
(Max error 1%)
Notice
The previous distances are (22 distances) where all distances in the solar system are
(45 distances) –means these distances be around 50% of all distances in the solar
system and be controlled by this rate (4.61)
More discussion about the planets motions rates of time should be done in Part (II) in
this paper.

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5- Planets Unified General Motion
5-1 The Planets Unified General Motion Description
5-2 The Solar Planets Motions Are Complementary One Another
5-3 The Solar Planets Move An Unified Motion (A Team Motion)

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5-1 The Planets Unified General Motion Description
- I claim that (The Planets Motions Create One Unified General Motion)
- This claim tells the planets motions be similar to Train Carriages Motion
- Also It tells the planets motions be similar to Chess Pieces Motions
- The idea discovers One Law controls the solar system motion and data.
- The planets unified general motion forces each planet motion to be complementary
with other planets motions to perform The Unified General Motion. as a result,
The Planet motion be An Obligatory Motion.
- The Solar Planet creates its data to be in consistency with its motion.
- The planet can't change its motion, but can change its data to be in consistency
with its motion. And the planet data be created in consistency with its motion.
- Because the planet motion be complementary with other planets motions.
- The planet data be created complementary with other planets data
- Based On This Vision
- The solar planets data be created complementary to other planets data and based
on that the planets data be created depends on One Geometrical Design.
- And
- The Planets Creation And Motions Data Be Controlled By One Equation Only

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- Please remember
- The Solar Group is similar to a machine of gears each planet is a gear in it, or
- The Solar Group is similar to one building and each planet is a part of this same
building, or
- The Solar Group is similar to puppets theater, all puppets are connected together
by one force and causes their motions, or
- The Solar Group is similar a canal water moves through the canal and causes the
rotation of 9 waterwheels. The Motion Direction of The waterwheels is different
from the water motion direction but no waterwheel can rotate without the water
motion, or
- The solar planets are similar to train carriages, they move together one unified
general motion, or
- The solar planets be similar to knots on one robe or similar to points on the same
one trajectory of energy –
- The solar planets motions be similar to chess board pieces motions, each motion
depend on the other planets motions and be done by geometrical calculations.
- Notice
- The planets motions data analysis in this point aims to prove this feature which is
(The Solar Planets Motions Be Integrated Into One Unified General Motion)
- Let's do that in the next points(5-2 and 5-3)

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5-2 The Solar Planets Motions Are Complementary One Another
I-Data
(The Interaction between Mercury, Mars and Jupiter)
(No. 1) (Mercury and Mars Motions)
- Mercury moves during its day period (4222.6 h.) a distance = 720.7 mkm
- Mars moves during (2802 hours) a distance = 243 mkm
- Mercury moves during (1407.6 hours) a distance = 243 mkm (error 1%)
- Mars moves during 346.6 d. a distance =720.7 mkm (Mercury Jupiter Dis.)
- Mercury moves during 346.6 d. a distance =1419 mkm (with 1433 error 1%)
- Mars moves during 687 d. a distance = 1433 mkm (Mars orbit. Circum)
- Mercury moves during 687 d. a distance =2815mkm (Mercury Uranus Dis.)
- Mars moves during 4331d. a distance = 9010mkm (Saturn orbit. Circum)
- Mercury moves during 4331d. a distance = 2815 mkm x 2π
- Mars moves during 224.7 d. a distance = π x 149.6 mkm (Earth orb. Dis)
- Mercury moves during 224.7 d. a distance = 920 mkm (with 928 error 1%)
- Mars moves during 365.25 d. a distance = π x 243 mkm (0.5%)
- Mercury moves during 365.25 d. a distance = 2 x 748 mkm
- Mars moves during 5040s. a distance= 121464 km= Saturn Diameter (+1%)
- Mercury moves during 5040s. a distance= 238896 km= 2 Saturn Diameters (-1%)
Where
1407.6 h = Mercury Rotation Period 2802 h = Venus Day Period
346.6 days = the nodal year 224.7 days = Venus orbital period
687 days = Mars Orbital Period
4331 days = Jupiter orbital period = 2π x 687 days

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(No. 2) (Mars And Jupiter Motions)
- Mars moves during 636.7 days a distance =1325 mkm= (Venus Saturn Dis.)
- Jupiter moves during 636.7 days a distance =720.7 mkm
- Mars moves during 687 d. a distance= 1433 mkm= Mars Orbital Circumference
- Jupiter moves during 687 d. a distance= 778.6 mkm= Jupiter Orbital Distance
- Mars moves during 4331d. a distance= 9010 mkm= Saturn orbital circumference
- Jupiter moves during 4331 d. a distance= 4900 mkm= Jupiter Orbital Circum.
- Mars moves during 778.6 d. a distance = 1622 mkm = Uranus Neptune Dis.
- Jupiter moves during 778.6 d a distance= 881 mkm =58 days x 15.19 mkm.
- ( 15.19 mkm = the 9 solar planets motions distances total per a solar day).
- Notice
- 2.082 mkm / day x 778.6 days = 1622 mkm = 1.1318 mkm /day x 1433 days

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(No. 3) (Mercury And Jupiter Motions)
- Mercury moves during 687 d. a distance= 2815 mkm= Mercury Uranus Distance
- Mercury moves during 1433 d. a distance =5848 mkm= Mercury Pluto Dis.
- Jupiter moves during 1433 d a distance =1622 mkm=Uranus Neptune Dis.
- Mercury moves during 4331d. a distance= 2815 mkm x 2π
- Mercury moves during 4222.6 h a distance = 720.7 mkm
- Jupiter moves during 4222.6 h a distance = 200 mkm = 629 mkm/π
- Mercury moves during 550.7 d a distance = π x 720.7 mkm (0.4%)
- Jupiter moves during 550.7 d a distance = 629 mkm (error 1%)
Please Remember,
Data Group No. (1)
- Mars moves during 687 d. a distance= 1433 mkm= Mars Orbital Circumference
- Mars moves during 4331d. a distance= 9010 mkm= Saturn orbital circumference
- Mars moves during 4331 x π d a distance= 28255 mkm= Neptune orbital circumference
Data Group No. (2)
- Mercury moves during 687 d. a distance= 2815 mkm= Mercury Uranus Distance
- Mercury moves during 4331d. a distance= 2815 mkm x 2π
Data Group No. (3)

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II-Discussion
- The planets move defined distances in defined periods of time.
- The Defined Distance means a distance is known in the solar system, as to be any
planet orbital distance or a distance between any 2 planets.
- The Defined Periods Of Time means a period of any planet cycle, as 365.25 days
(Earth orbital period) or any planet orbital period. Or any planet rotation period or
any planet day period. All these periods are defined periods of time
- The argument tells that
- If the solar planets move their motions independently from one another, based on
that, the planets motions during defined periods of time should pass (random)
distances. Because these Planets are independent in their motion from one
another. (For example) Mercury motion depends on its orbital period (88 days) and
doesn't interest neither for Mars orbital period (687 days) nor for Jupiter orbital
period (4331 days) and by that, Mercury during these periods (687 days and 4331
days) should move some random distances (not defined in the solar system
distances).
- The data disproves Planet Motion Independency Concept. because the (3)
planets move defined distances in defined periods of time. These planets motions
aren't independent from one another. These motions are done based on One
Geometrical Design. And these motions be are similar to Chess Board Pieces
Motions. Each Motion is calculated geometrically and be obligatory.
- Notice
- Jupiter orbital distance analysis can support the discussion of this point greatly, we
discuss it in a separated point no. (6)

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5-3 The Solar Planets Move An Unified Motion (A Team Motion)
- Let's Summarize The Proof Idea In Following:
- This proof depends on 2 planets motion cycles are discovered later. Which are
(planet 8 days cycles) and (planet 6 days cycles). We study one Cycle only in this
paper because both cycles provide the same argument.
- The Cycle Shows That Different Planets Motions Be Used In The Same One
Cycle To Create One Final Result.
- Means,
- Many planets move relative one another to create one result.
- For Example
- Jupiter moves a distance (A) and Uranus moves a distance (B).
- The different distance between (A) and (B) = Jupiter Diameter
- Now
- The machine uses this behavior frequently, and (the different distance = Jupiter
Diameter) be created frequently while the cycle uses its different periods (8 days,
16 days, 24 days….etc).
- Based on that,
- We can't consider these planets motions are independent from one another because
the different distance be defined by the 2 planets motions. we have to consider
these planets motions as a team motion. They move relative to one another which
proves The Unified General Motion Concept.
- Based on that,
- (Planet 8 and 6 Days Cycle) disproves Planet Independent Motion Concept.
- In following we study Planet 8 Days Cycle

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(Planet 8 Days Cycle)
(I)
- Jupiter (13.1 km/s) moves during its day period (9.9 h) a distance = 466884 km
- But
- 466884 km = 449197 km (Jupiter Circumference) + 17687 km
- Where
- (8 x 17687 km = 141496 km (Jupiter Diameter) (error 1%)
- Based on that, we have concluded that, Jupiter has a cycle of 8 days
- Jupiter (13.1 km/s) moves during 8 Jupiter days (79.2 h) a distance = 3735072 km
- (3735072 km= 8 Jupiter circumferences + 141496 km (Jupiter diameter) (1%)
(II)
- The distance 3735072 km be passed also by Saturn and Neptune with a rate 80%
depends on one another as following:
- Saturn (9.7 km/s) moves during 10 Saturn days (107 h) a distance = 3736440 km
- (10 Saturn Circumferences = 3786750 km, the difference =50310 km = Uranus
Diameter error 1.5%)
- Neptune (5.4 km/s) moves during 12 Neptune days (193.2 h) a distance = 3755808
km
- (24 Neptune Circumferences = 3734323 km, the difference =21485 km = Mars
Circumference (error 0.6 %))
(III)
- Uranus (6.8 km/s) moves during Pluto day period (153.3 h) a distance = 3752784
km
- The distance 3752784 km = Jupiter motion distance during 8 days + 17687 km
- And because
- 17687 km x (8) = 141496 km (Jupiter Diameter) (error 1%)
- That tells another Cycle is found between Uranus and Jupiter based on 8 Pluto
days

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- That means, the distance be passed by Uranus during 8 Pluto days equal the
distance be passed by Jupiter during 64 Jupiter days and equal the distance be
passed by Saturn during 80 Saturn days and equal the distance be passed by
Neptune during 100 Neptune days
Let's see that in following
(1)
Jupiter (13.1 km/s) moves during (64 Jupiter days) a distance =29880756 km
(2)
Saturn (9.7 km/s) moves during (80 Saturn days) a distance =29891520 km
(3)
Neptune (5.4 km/s) moves during (100 Neptune days) a distance =31298400 km
(4)
Uranus (6.8 km/s) moves during (8 Pluto days) a distance =30022272 km
Comments
- Uranus motion distance (30022272 km) – Jupiter motion distance (29880756 km)
= 141496 km (Jupiter Diameter)
- The differences between these distances are less than 1 % (generally) and based on
that we can't consider they are different distances but we have to consider they are
equal distances.
- Although still there are small differences which are found for geometrical reasons
for example the difference between Jupiter and Saturn motions distances =
29880756 km – 29891520 km = 10921 = the moon circumference
- The data shows Planets Motions Dependency, because the different distances are
defined geometrically and that means these aren't 2 different distances of 2 plants
independent motions. On the contrary, the 2 distances are planned geometrically
and the 2 planets are 2 players to perform one different distance.

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The Discussion
- Let's discuss the previous data
(A)
- The outer planets are 5 planets, they consist 2 teams,
- The first team is consisted of Jupiter, Saturn and Neptune, these 3 planets move
based on a cycle (8 days cycle) depends on Jupiter motion with the rate 80%,
- That means
- The distance be passed by Jupiter in 8 Jupiter days be equal the distance be passed
by Saturn in 10 Saturn days and equal the distance be passed by Neptune during 12
Neptune Days
- The (small) difference between these 3 distances have geometrical necessities, as
we have seen in the difference between Jupiter and Saturn motions distances which
= 10921 km = The Earth Moon Circumference
- The moon circumference itself tells that it's a cycle because if it's not a cycle we
would find a part of the moon circumference
(B)
- The second team is Uranus and Pluto….
- Uranus uses Pluto day period (153.3 hours), and by that, Uranus (6.8 km/s) moves
during Pluto day period (153.3 hours) a distance = 3752784 km
- Because
- 3752784 km = Jupiter motion distance during 8 Jupiter days +17687 km
- Because of this data, we have concluded that, these motions depends on (8 days
Cycle), because
- Uranus needs to move during a period (= 8 Pluto days) to cause this value (17687
km) be = (141496 km (Jupiter Diameter) (1%)
- Because of Jupiter diameter we conclude that Uranus has a cycle of (8 Pluto days)
- Based on that

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- Uranus motion distance during 8 Pluto days = Jupiter motion distance during 64
Jupiter days = Saturn motion distance during 80 Saturn days = Neptune motion
distance during 100 Neptune days.
- How (Planet 8 Days Cycle) Can Prove The Unified Motion?
- Because
- Many planets motions be done to produce One Result
- This result be the different distance 141496 km (Jupiter Diameter) (1%)
- If we deal with planets independent motions this different distance can't be created
regularly and the Cycle can't be defined.
- Because (Planet 8 days Cycle) be defined, that means, the different distance
141496 km (Jupiter Diameter) be defined regularly which can be done only if
we deal with a team motion and NOT Planets independent Motions.
- Why does Uranus depend on Pluto Day Period?(additional question)
- Pluto day period is so long (153.3 h) in comparison with the outer planets days
periods. We suppose that, Uranus Motion effect on Pluto motion causes Pluto day
extension. We know Uranus did this effect because Pluto orbital inclination = 17.2
deg but Uranus day period =17.2 hours, even if we can't catch the mechanism of
this process yet, but the data shows that's Uranus effect on Pluto motion.
A Conclusion
Planet 8 Days Cycle disproves The Planet Independent Motion Concept,
On The Contrary, The Planets Move As A Team. (A Unified General
Motion)

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6- Jupiter orbital Circumference Analysis
6-1 Preface
6-2 Jupiter orbital Circumference Analysis

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6-1 Preface
- We analyze Jupiter orbital circumference (4900 mkm) here ,
- because
- it's very rich circumference in its discussion and we need to avoid the confusion
with the other parts of Jupiter motion data discussion
- for that reason we discuss this circumference here to provide the data analysis as
clear as possible
- we need Jupiter orbital circumference analysis in our discussion for Jupiter motion
data.

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6-2 Jupiter orbital Circumference Analysis
I –Data
(6-2-a)
4900 mkm = 1.16 mkm x 4224 = 1.1318 mkm x 4331 days
(6-2-b)
4900 mkm = 10921 km x 449197 km
And
9010 mkm = 10921 km x 2 x 413600 km
(6-2-c)
(708.7 h /10.7 h) = (655.7 h/ 9.9h) = 66.2
(6-2-d)
(9010 mkm /1433 mkm) = (4331 days /687 days) = 2π
(6-2-e)
(24.6 h/9.9h) = (24.1/9.7) =(10747 days /4331 days) = 2.48
But
(24.6/24.1) = (9.9/9.7) = (9.7/9.5)
(6-2-f)
0.3mkm/sec x 16333 sec =4900 mkm
But
27.78 km/sec x 16333 sec =449197 km (error 1%)
(6-2-g)
(37100 mkm - 4900 mkm) x 2π =28255 mkm +2 x86400 mkm
(6-2-h)
4900 mkm = 360 mkm +680 mkm +940 mkm +1433 mkm +1433 mkm
(6-2-i)
(90560 /88000) =(24.7/24) = (9.9/9.5) = ( 51118/49528) =(5040/4900)

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II-Discussion
- Where
- 4900 mkm =Jupiter Orbital Circumference
- 4222.6 hours = Mercury Day Period
- 1.16 mkm =Jupiter Motion Distance during 24.6h (Mars Rotation Period)
- 1.1318 mkm = Jupiter Motion Distance during 24 h ( a solar day)
- 4331 days = Jupiter orbital Period
- This equation cornerstone is the number (4224) because it's so near to (4222.6) =
Mercury day period.
- Mercury Day period = 4222.6 hours if (24.6 hours) of Jupiter Motion = 1 hour of
Mercury Motion- the periods (4331 days) and (4222.6 hours) will be equal
- Then
- The difference between (4224) and (4222.6) we can deal it later
- Now, the idea is that,
- Jupiter orbital circumference (4900 mkm) is designed based on the distance (1.16
mkm). So the distance (4900mkm) is designed to be 4224 distances each distance
=1.16 mkm.
- Jupiter (13.1 km/s) moves during 24.6 h (Mars rotation period) =1.16 mkm
- Means,
- The distance is designed based on 2 periods (4222.6 h and 24.6h) but the design
takes into consideration Jupiter velocity – means
- By using Jupiter motion and based on Jupiter velocity, the distance 1.16 mkm will
be passed on (24.6 h) and by that the circumference 4900 mkm will be = 4224parts
each part =1.16 mkm, means
- We have 3 players (Jupiter velocity, Mars rotation period, Mercury day period)
- Based on these 3 players Jupiter orbital circumference be design!

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Equation no. (6-2-a) (continued)
- The difference between 24 h and 24.6 h is (2.5%), and that causes the difference
between (1.16 mkm) and (1.1318 mkm) to be (2.5%) (= 28160 km)
- We realize now how this data be created, let's summarize it again in following:
- Jupiter velocity (13.1 km/s) be used by Mars rotation period (24.6 h) to pass a
distance = 1.16 mkm and Jupiter orbital circumference be design as a function in
the distance 1.16 mkm by the rate (4224) which is (Mercury Day Period 4222.6h)
- Means, Jupiter motion depends on 2 cycles (24.6 h and 4222.6 h)
- But
- Jupiter moves during 687 days a distance = 778.6 mkm = Jupiter orbital distance,
where 687 days = Mars Orbital Period
- That add one more player to the picture – because – We know– Jupiter motion
depends on 2 cycles (24.6h and 4222.6h) but now a third cycle be used also! Why?
- 687 days x 24 h = 24.6 h x 671 but (4222.6 h = 2π x 671)
- That means, some interaction is found inside Mars cycles periods found by some
effect of Mercury motion on Mars Cycles, this effect causes the period (687 days)
be dependent on the same 2 periods (24.6 h and 4222.6 h)
- Because of that Jupiter uses Mars Cycles Periods as its own periods!
- Please Note
- The data is created based on a geometrical system which we try to discover, But,
because we still don't know this geometrical system I try to arrange the data in best
from to discover it – for that reason I depend on the data arrangement – and
because of that – I add the data step be step to show clearly their effects – when we
discover the geometrical system behind this data – in this case- we will not be so
careful with data because we know the rule behind but now we don't this rule and
we should keep our eyes on the data arrangement because by the correct
arrangement the geometrical rule will be discovered.

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Equation no. (6-2-b)
4900 mkm = 10921 km x 449197 km
And
9010 mkm = 10921 km x 2 x 413600 km
- Where
- 4099 mkm = Jupiter Orbital Circumference
- 9010 mkm = Saturn Orbital Circumference
- 10921 km = The Moon Circumference
- 449197 km = Jupiter Circumference
- 413600km = the moon supposed apogee radius!!
- (Notice the moon daily displacement =88000 km and during 29.53 days the total
distance = 2.598693 mkm = 2π x 413600km, means if the total distance (2.598
mkm) be the moon orbital apogee circumference (as should be) the apogee radius
should be (413600 km) –but the apogee real radius is 406000 km – for that I call
the radius 413600km (the supposed apogee radius)
- Equation no. (6-2-b) tries to show that, Jupiter and Saturn orbital circumferences
be defined as functions in the moon circumference – that creates more complexity
for our discussion – because –Jupiter orbital circumference is already effected and
designed based on 2 cycles (24.6 h and 4222.6 h) and now the moon circumference
is effected also which creates more difficulties for out discussion
- Equation no. (6-2-b) tries to show that, Jupiter and Saturn orbital circumferences
are designed taken into consideration the moon circumference – that because – the
2 planets effect greatly on the moon motion -
- I want to say
- Jupiter orbital circumference be created effected by 2 forces (at least), the first
force is the 2 cycles periods effect (24.6 h and 4222.6 h) and the second force is
the moon circumference

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- I add the connection with the moon circumference here to show that Saturn motion
effects on Jupiter orbital circumference design and creation – after we discuss this
point we should return again to Jupiter orbital circumference analysis to see how
it's designed –
Equation no. (6-2-c)
(708.7 h /10.7 h) = (655.7 h/ 9.9h) = 66.2
- Where
- 10.7 h = Saturn Day Period
- 9.9 h = Jupiter Day Period
- 708.7 h = The Moon Day Period
- 655.7 h = The Moon Rotation Period
-
- This equation is the cornerstone in the relationship between the moon on one side
and Jupiter and Saturn on the other side.
- This equation is a treasure – it has no error – means its error = (ZERO)
- Means,
- These 4 numbers are created together in one process!
- This equation is a proof for an interaction found among Jupiter, Saturn and the
moon.
- We should know, these values aren't some empty number be created by some
chance – these 4 numbers be created based on the planets motions –where the
planets motions mentioned to create these 4 numbers –
- shortly
- Jupiter and Saturn days periods are created based on the moon cycles periods, but
not as individual values or independent values, instead, in one process, the 4
periods be created- the next equation can help our investigation

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Equation no. (6-2-d)
(9010 mkm /1433 mkm) = (4331 days /687 days) = 2π
- Where
- 9010 mkm = Saturn Orbital Circumference
- 1433mkm = Mars Orbital Circumference
- 687 days = Mars Orbital Period
- 4331 days = Jupiter Orbital Period
- Equation (6-2-d) shows, Mars orbital period and circumference be created based
on Jupiter and Saturn orbital period and circumference by the same rate (2π)
- This equation is provided to show that, Jupiter motion uses mars rotation period
(not by chance) but based on a geometrical necessity
- I want to say
- The planets are similar to gears in one machine of gears, but, the planets in fact
aren't gears, and we don't know how to attribute (the motion transportation) for
planets motions. because we can't attribute any mechanical features for the Space
between the planets and no direct touch causes the motion transportation from a
planet to another – but the data shows that-any planet motion can't be considered
as independent or individual motion –for that reason we analyze the planets
motions data to discover how the motions data be transported or be taken into
consideration in comparison with other planets data
- Simply
- If Jupiter day period =9.9 and 655.7 h /9.9 h = 66.2, why Saturn should interest?
Why 66.2 = 708.7 h /10.7? how this data transportation is done?
- The question is found with our point discussion start because
- Jupiter orbital circumference be design based on the distance (1.16 mkm) which be
passed during (24.6 h) and the design produces 4224 (where 4222.6 h = Mercury
day period) – the data tells clearly that – they are created based on each other – and
how planet motion data can effect on another planet motion data?

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Equation no. (6-2-e)
(24.6 h/9.9h) = (24.1/9.7) =(10747 days /4331 days) = 2.48
But
(24.6/24.1) = (9.9/9.7) = (9.7/9.5)
- Where
- 24.6 h = Mars Rotation Period
- 24.1 km /s = Mars velocity
- 9.7 km /s = Saturn velocity
- 2.5 degrees = Saturn Orbital Inclination
- Equation no. (6-2-e) shows that many data of Jupiter and Saturn be created in
proportionality with one another –
- I use this equation to show my deep effect be occurred between planets motion..
- The equation itself is straight for example
- (24.6 h/9.9h) = (24.1/9.7), these 2 parts are straight because the equation divides
period on period (24.6 h/9.9) and velocity on velocity (24.1/9.7)
- But
- We can create some exchange by the geometrical rules, and based on that
- (24.6/24.1) = (9.9/9.7), this equality is correct geometrically, but it's not straight,
because, it divides (period) on (velocity) to be = (period) on (velocity)
- For that we will forget the units of numbers and use them arithmetically
- Based on that
- (24.6/24.1) = (9.9/9.7) = (9.7/9.5), And So,
- (9.7)2
= 9.9 x 9.5
- This is the equation I mean to use – this is a very important one –let's explain why

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- Saturn (9.7 km/s) moves during its day period (10.7 h) a distance = 373644 km
which differs from Saturn Circumference (378675km) with (1.3%)
- This data creates some idea tells, The Planet Moves During Its Day Period A
Distance = Its Circumference
- I don't know what result can be produced if the planet does this motion – but
- Jupiter moves during its day period a distance = 104% its circumference
- Means, there's a difference =4%
- That can kill the concluded rule simply
- Jupiter during 9.5 hours moves a distance = its circumference, the problem is that,
Jupiter day period =9.9 hours, this difference causes the error (4%) between Jupiter
motion distance during its day period and Jupiter circumference
- But we know that
- The difference 4% between Jupiter motions distance and its circumference causes
to create planet 8 days cycle.
- Shortly
- (9.7)2
= 9.9 x 9.5
- Where
- 9.7 km/sec = Saturn velocity
- 9.5 h = the period during Jupiter moves a distance = its Circumference
- I try to show that, Jupiter doesn't move during its day period a distance = its
circumference because of a geometrical necessity
- I hope the data does the task well
- We have many clear proves that, Jupiter motion through its orbital circumference
depends on other planets motions and cycles periods.

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Equation no. (6-2-f)
0.3 mkm/sec x 16333 sec =4900 mkm
But
27.78 km/sec x 16333 sec =449197 km (Jupiter Circumference) (error 1%)
- Where
- 0.3 mkm/sec = Light Known Velocity
- 27.78 km /sec = The Moon Velocity
- Equation no. (6-2-f) tells that, the period the light uses to pass Jupiter orbital
circumference =the period the moon uses to pass a distance =Jupiter circumference
- This equation importance is found because the light uses the same period of time
- I try to show that,
- The Data Is Created Based On A Complex Geometrical Machine
- Please remember
- Jupiter (13.1 km/sec) moves during 10921 seconds a distance = 142984 km =
Jupiter diameter.
- And
- 4900 mkm (Jupiter orbital circumference) = 449197 km x 10921 km
- Where
- 449197 km = Jupiter Circumference
- 10921 km = the moon Circumference
- There's a very complex interaction is found between Jupiter, Mars, Saturn the
moon and Mercury… these planets motions data be used frequently with Jupiter
motion data -
- Shortly
- There's a complex machine behind Jupiter orbital circumference design

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Equation no. (6-2-g)
(37100 mkm -4900 mkm) x 2π =28255 mkm +2 x 86400 mkm = 2 x 1.16 mkm/sec
x 86400 seconds
Where
- 37100 mkm =Pluto Orbital Circumference
- 28255 mkm =Neptune Orbital Circumference
- 680 mkm =Venus Orbital Circumference
- (28255 mkm – 680 mkm) x 2π = 86400 mkm
- Equation no. (6-2-g) is the solar system main equation because it shows the energy
distribution trough the solar system – we have to discuss this equation in details in
our discussion for light motion accompanying planet motion –
- The point we need to discuss here is the distances distribution based on Jupiter
orbital circumference.
- The distance between Jupiter and Pluto by some geometrical method defines the
distance between Neptune and Venus –also we can use Earth orbital circumference
in place of Venus' because the error in both equations be only 1%
- We don't explain the equation third part (1.16 mkm/sec x 86400 sec) because it
depends on light motion hypothesis – we discuss it in light motion accompanying
planet motion (Point no.11)
- The difficulties be more clear now, let's try to explain as possible in following:
- The Planet Motion be done based on integration of other planets motions – means-
No Independent Motion be done in the solar system
- Because of that –
- Planets Motions data be transported among the planets and be used by each other –
for that reason we have seen that Jupiter uses Mars rotation period (24.6h) to move
a distance =1.16mkm based on which Jupiter orbital circumference be design taken
into consideration Mercury day period (4222.6 h).

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- Shortly
- Planets Motions Data be Transported from planet to another
- Neither Newton theory nor our geometry book has a method to explain how the
data be transported from one planet to another – as a result – the explanation be
usually (pure coincidence of numbers) which kills our chance for understanding
and remove the priceless data
- On the other side the planets aren't gears and the motion transportation, or energy
transportation which causes the data transportation is a process not defined yet and
we can't catch its features spite the deep analysis
- Based on this situation,
- I have tried to divide my work into 2 different tasks
- The first task to prove that, the planets motions can't be created independently –
Simply Planet Motion Independency Concept is Mistaken (Newton Theory is
wrong) – and to prove this idea – I have arranged the planets data in best form to
prove that- the motions can't be done independently
- The previous data is example….
- Although I have no explanation how this data be created but the data prove clearly
that no motion can be done independently
- The second task is to try to explain how the planets motions be done depending on
one another – and this point is discussed in the paper theory of (light motion
accompanying planet motion) (Point no.11)
- As a result we conclude, for now, that Jupiter orbital circumference is designed
based on a geometrical design takes into consideration the other planets motions
data.

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Equation no. (6-2-h)
4900 mkm = 360 mkm +680 mkm +940 mkm +1433 mkm +1433 mkm (error 1%)
- Where
- 360 mkm = Mercury Orbital Circumference
- 680 mkm = Venus Orbital Circumference
- 940 mkm = Earth Orbital Circumference
- 1433 mkm = Mars Orbital Circumference
- Why (1433 mkm) is used 2 times? (my answer is)
- The data considers the moon orbital circumference around the sun = 1433 mkm=
Mars orbital circumference –
- Why? I don't know
- Can this data be invented one? let's see the following data:
(1)
- Mercury moves during its day period a distance = Mercury Jupiter distance
(2)
- Venus moves during its orbital period a distance = Venus Jupiter distance (1.2%)
- (because Venus orbital circumference = Venus Jupiter distance wit error 1.2%)
(3)
- Earth moves during its orbital period a distance = Earth Jupiter distance (1.2%)
- (because Earth orbital circumference = Earth Jupiter distance wit error 1.2%)
- (notice in this case should Earth and Jupiter be on 2differnt sides from the sun)
- Means,
- The 3 planets define their orbital circumferences to be equal or rated to their
distances to Jupiter – this data should be added to the previous and think about
them together – some specific relationship be found between the 3 inner planets
and Jupiter motions data

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II-Discussion (continued)
- In following we need analyze Jupiter data in more deep analysis – the point I that,
we can't catch the idea behind – the data is so rich but the understanding is limited
- Let's try again in following
Jupiter motion in 24 h in 24.6 h A distance
778.6 mkm 687 671 671 mkm = Jupiter Venus distance
720.7 mkm 637 621 629 mkm == Jupiter Earth distance
671 mkm 593 580
629 mkm 555.7 542 550.7 mkm = Jupiter Mars Distance
4900 mkm 4331 4224 4224 mkm =2π x 671 mkm
2094 mkm 2094 mkm = (1.16)2
x 778.6 x 2
- Distances
- 778.6 mkm = Jupiter Orbital Distance
- 720.7 mkm = Jupiter Mercury Distance
- 671 mkm = Jupiter Venus Distance
- 629 mkm = Jupiter Earth Distance
- 550.7 mkm = Jupiter Mars Distance
- 2094 mkm = Jupiter Uranus Distance
- Periods
- 4331 days =Jupiter Orbital Period
- I try to show that, Jupiter motion isn't explained by out analysis of data – it still
have great secrets need to be discovered –
- Jupiter motion data shows that, planet motion depends on a very complex machine
which uses different cycles periods in one motion and can used distances values as
periods of time.

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- Notice
- 413600 km=9.7 km/sec x 42640 seconds
- But
- 30589 days x 24 h = 17.2 h (Uranus day period) x 42682
- This data tells
- 1 second of Saturn motion = 17.2 hours of Uranus motion!
Equation no. (6-2-i)
(90560 /88000) =(24.7/24) = (9.9/9.5) = ( 51118/49528) =(5040/4900)
- 90560 days = Pluto Orbital Period
- 88000 km = The moon daily displacement
- 24.7 hours = Mars Day Period
- 24 hours = Earth Day Period
- 9.9 hours =Jupiter Day Period
- 51118 km = Uranus Diameter
- 49528 km = Neptune Diameter

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7- Jupiter Motion Analysis
7-1 Preface
7-2 Jupiter Orbital Period Analysis
7-3 Jupiter Orbital Circumference More Discussion
7-4 Mars Rotation Period Analysis

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7-1 Preface
- We analyze Jupiter motion in comparison with Mercury and Mars motions
- Because
- 4331 days (Jupiter orbital period) = 687 days (Mars orbital period) x 2π
- And
- 4331 days (Jupiter orbital period) = 175.94 days (Mercury Day Period) x 24.6
- (24.6 h =Mars Rotation Period)
- This data shows puzzles in the 3 planets motions because they creates some
equality between their periods of time
- The only explanation depend on the planets using of different rates of time
- Let's analyze Jupiter orbital period in the next point.

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7-2 Jupiter Orbital Period Analysis
I- Data
(7-2-a)
4331 days = 2π x 687 days = 175.94 days x 24.6
(7-2-b)
671 hours (of Mercury) =687 days (of Jupiter) =109 days (of Mars) =1705 days
(Saturn) = 859 hours (Venus)
But
687 days (Mars Orbital Period) x 24 = 24.6 h (Mars Rotation Period) x 671
(7-2-c)
10747 days x 24 h = 24.6 hours x 10485
but
4331 days x 24 h = 9.9 hours x 10499
(7-2-d)
4331 days =224.7 days x 19.27
(7-2-e)
(10747 /4331) =(24.6/9.9) = (24.1/9.7) = (17.4/7) =2.48

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II- Discussion
- In this point we analyze Jupiter orbital period to know why it's created in
proportionality with Mercury and Mars Cycles Periods
- I suppose that, the equality of cycles creates equality of the motion rates of time –
means, where
- 4331 days = 2π x 687 days = 175.94 days x 24.6 - And
- 4331 days = Jupiter Orbital Period 687 days = Mars Orbital Period
- 175.94 days = Mercury Day Period
- We know that
- 1h of Mercury motion = 24.6 h of Jupiter motion =3.91 h of Mars motion
- Let's discuss the data in folloiwng
Equation No. (7-2-a)
4331 days = 2π x 687 days = 175.94 days x 24.6
- Where
- 4331 solar days = Jupiter Orbital Period
- 687 solar days = Mars Orbital Period
- 175.94 solar days = Mercury Day Period
- 24.6 hours = Mars Rotation Period
- Equation no. (7-2-a) is the main point equation, it gives an interesting suggestion
- It tells
- 1 h of Mercury motion = 3.91 h of Mars Motion = 24.6 h of Jupiter Motion
- And
- 1 h of Mars Motion = 2π h of Jupiter Motion
- The equation provides the rates of time between the 3 planets motions.

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Equation No. (7-2-b)
671 hours (of Mercury) =687 days (of Jupiter) =109 days (of Mars)
- Equation no. (7-2-a) tells that, 1 day of Mercury Motion = 24.6 days of Jupiter
Motion = 3.91 days of Mars Motion
- And
- 1 day of Mars motion be = 2π days of Jupiter Motion.
- Equation (7-2-b) uses these same rates
- 671 hours of Mercury motion = 671 h x 24.6 (= 687 solar days) of Jupiter motion
= 671 h x 3.91 (= 109.3 solar days) of Mars Motion
- Now we have 3 periods of time depend on the suggested rates of time we have
discussed in the previous equation
- Now, How To Prove These Periods Are Equal? let's see the planets motions
distances during these periods
- Mercury moves during (671 h) a distance = 2 x 57.2 mkm ( = Mercury orbital
distance - error 1%)
- Jupiter moves during (687 days) a distance =778.6 mkm ( = Jupiter orbital
distance)
- Mars moves during (109.3 days) a distance =227.9 mkm ( = Mars orbital
distance)
- Means,
- The planets during these periods move distances equal their orbital distances but
Mercury moves a double value of its orbital distance
- We use this result as a rule for now and later we should see if it's working rule
- But
- Why these planets move during these periods of time distances equal their orbital
distances?! And the most important why Mercury moves a double value?!
- The data tells,

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- Some fact be found behind the suggested motions rates of time. Because the
planets move during these periods distances equal orbital distance, in this case we
consider Mercury is exceptional and we should later ask why it moves double
value of its orbital distance?
- Now we test our rule which tells
- The period be used by a planet motion to pass distance = its orbital distance, this
period can be compared with 671 hours of Mercury motion to define the rate of
time between Mercury and this planet motions –
- Let's use it in the next equation…
Equation No. (7-2-c)
10747 days x 24 h = 24.6 hours x 10485
but
4331 days x 24 h = 9.9 hours x 10499
- Where
- 9.9 hours = Jupiter Rotation Period
- The values (10499 and 10485 are equal because the difference is 0.1%)
- Equation no. (7-2-c) tells that
- (10747 days /4331days) = (24.6 h /9.9 h) =2.48
- And for that, Saturn orbital period (10747 days) = (10485 rotation period)
- And
- Jupiter orbital period (4331 days) = (10499 Jupiter days periods)
- Can 1 hour of Jupiter motion =2.48 hours of Saturn motion? Can this rate of
time be a real one?
- 1 hour of Mercury Motion = 24.6 hour of Jupiter Motion

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- Based on the previous conclusion
- 1 hour of Mercury Motion = 61 hours of Jupiter Motion
- Based on that
- 61 hours of Saturn motion = 1 hour of Mercury Motion
- 2.48 hours Saturn motion = 1 hour of Jupiter Motion
- 15.6 hours Saturn motion = 1 hour of Mars Motion
- Let's return to equation no. (7-2-b)
671 hours (of Mercury) =687 days (of Jupiter) =109 days (of Mars) = 1705.5 days
(Saturn)
- We know that
- Mercury moves during (671 h) a distance = 2 x 57.2 mkm ( = Mercury orbital
distance - error 1%)
- Jupiter moves during (687 days) a distance =778.6 mkm ( = Jupiter orbital
distance)
- Mars moves during (109.3 days) a distance =227.9 mkm ( = Mars orbital
distance)
- And Now
- Saturn moves during (1705.5 days) a distance =1430 mkm (= Saturn orbital
distance)
- And Also
- Venus moves during (859 hours) a distance =108.2 mkm (= Venus Orbital
Distance)
- Notice
- 3.1 deg (Jupiter Axial Tilt) x 0.8 =2.48 deg (Saturn Orbital Inclination)
- 0.8 deg = Uranus Orbital Inclination
- Notice
- 1440 minutes = 61 x 23.6

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II- Discussion (continued)
- We here don't discuss Planets Motions Rates Of Time, Because this subject is
discussed deeply in Points no. (3 and 4 ) in this current paper.
- We here analyze Planets Motions Features, and through our analysis Planets
Motions Rates of time be referred and discussed briefly. For that reason we don't
try to prove the rates of time using – because we here refers to a short reference for
this using –
- Notice (2)
- The solar planets motions using of different rates of time makes the solar system to
work as a clock – means,
- Each planet provide its motion rate of time and the planets rates of time be unified
in one general rate by that, the solar system be similar to a great clock – because
the solar system uses energy of a motion for 1 second – and by this energy the
solar system produces another motion for 1 solar day –
- Let's write this idea in more clear words -
- The solar system uses energy of light motion for a period 1second and by this
energy the solar system produces a planet motion for 1soalr day – this is the basic
job of the solar system motion – but
- Light motion effect on planet motion is a subject will be discussed in part no. (II)
of this paper. I don't want to discuss this idea in any discussion before part (II)
because the paper provides data analysis and the data analysis shows facts has no
doubt – I don't want to write any of my ideas here which can create some doubt
against the data analysis – for that reason I keep the explanation to be written in
Part (II) of this paper –
- But
- The solar system uses of different rates of time basically to use 1 second of light
motion energy to produce by it a planet motion for 1 solar day.

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4331 days =224.7 days x 19.27
- Where
- 1 hour of Mercury motion = 1.279 hours of Venus motion
- 1 hour of Venus motion = 3.057 hours of Mars motion
- And
- 224.7 days (Venus orbital period) x 3.057 = 687 days (Mars orbital period)
- Equation no. (7-2-d) shows that, the rate of time between Mercury and Venus
motions (1.279) is the correct rate –and that supports the rule which be used to
define this rate –
- The data simply supports the discussion and shows that it moves in the right way –

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(10747 /4331) =(24.6/9.9) = (24.1/9.7) = (17.4/7) =2.48
- Where
- 9.9 hours = Jupiter Rotation Period
- 24.1 km/s = Mars Velocity
- 9.7 km/s = Saturn Velocity
- 17.4 deg = The Inner Planets Orbital Inclinations Total
- 7 deg = Mercury Orbital Inclination
- This equation should be discussed later in this paper deeply as possible –
- But
- This equation be added here to show that,
- Saturn rate of time we have concluded, which is (1h or Mercury Motion =61 of
Saturn Motion) and (1h of Jupiter Motion =2.48 h of Saturn Motion)
- These rates are effective deeply on the planets motions data –as seen in the
equation – the shows that one connection connects Jupiter, Saturn and Mars
Motion – that may help to explain our old data which is
- 331 days (Jupiter Orbital Period) =2π x 687 days (Mars Orbital Period)
- 1433mkm (Saturn Orbital Distance) =2πx 227.9 mkm (Mars Orbital Distance)
- This data should be put beside equation no (7-2-c) which can tell clearly that one
connection be found behind all this data. for that we should discuss this equation
later deeply
- Notice
- (17.4 mkm / 7mkm) = 2.5
- Light known velocity (0.3 mkm/sec) x 23.4 s = 7 mkm
- Light known velocity (0.3 mkm/sec) x 57.9 seconds = 17.37 mkm

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7-3 Jupiter Orbital Circumference More Discussion
I-Data
(7-3-a)
1.16 mkm =13.1 km/sec x 24.6 h x 3600 sec.
(7-3-b)
4900 mkm = 1.16 x 4224
(7-3-c)
4900 mkm = 199.2 mkm x 24.6
(7-3-d)
4900 mkm = 0.406 mkm x 12104 = 0.384 mkm x 12756
(7-3-e)
Jupiter moves 778.6 mkm in (687 solar days) or (671 mars oration period)
And
Jupiter moves 671 mkm in (592 solar days) or (580 mars oration period)
And
Jupiter moves 629 mkm in (555.7 solar days) or (542 mars oration period)

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II- Discussion
- The data tells us some interesting puzzled story, let's explain it in following:
- Jupiter (13.1 km/s) moves during 24.6h (Mars rotation period) a distance 1.16
mkm - But
- Jupiter orbital circumference (4900 mkm) be designed geometrically base on this
distance 1.16 mkm and by that 4900 mkm =1.16 mkm x 4224
- Where , 4222.6 hours = Mercury Day Period, So If
- 4224 be equal 4222.6,
- In this case
- Jupiter orbital circumference be created based on a geometrical design takes into
consideration these 2 cycles periods (24.6 h and 4222.6 h)
- I created no data here, I just arrange it… Planets data be created (almost) based on
this arrangement. That means, the circumference (4900 mkm) in fact be created
based on these 2 cycles periods
- Please Note
- Even if there's an explanation for this data- we should not discuss it here – because
we have a discovery we should know it it's a real one because
- 4900 mkm = Jupiter orbital circumference, and HWY this distance be created
depends on the 2 cycles periods
- I wish I do my job correctly… the data is made of pure gold and I'm afraid that I'm
stupid and covers the data brightness
- The distance 4900 mkm be created in proportionality with the 2 cycles (24.6 h and
4222.6 h) BUT, BY Using Jupiter Motion Velocity
- The using of the cycles (24.6 h and 4222.6 h) in Jupiter orbital circumference
design isn't so strange using of data made far from Jupiter motion and the numbers
be found here by chance. The cycles (24.6 h and 4222.6 h) takes Jupiter velocity in
consideration.
- The paper dedicated a point to analyze Jupiter orbital circumference (point no.6)

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Equation (7-3-a)
1.16 mkm =13.1 km/sec x 24.6 h x 3600 sec.
Equation (7-3-b)
4900 mkm = 1.16 x 4224
- These 2 equations tell the story. Equation no (7-3-a) shows that Jupiter motion
distance 1.16 mkm in 24.6 h (mars rotation period).
- Equation no (7-3-b) shows that Jupiter orbital circumference (4900 mkm) be
designed based 1.16 mkm and 4224 (where 4222.6h = Mercury day period)
Equation (7-3-c)
4900 mkm = 199.2 mkm x 24.6
- 199.2 mkm = Jupiter motion distance during Mercury day period (4222.6h)
- 24.6 h = Mars Rotation Period
- This equation we discuss with the distance 720.7 mkm analysis –
- The point is that
- Mars rotation period be analyzed in the next point because of its so effective role
in motions data – we try to know why the number (24.6) be used so frequently
with Jupiter motion
- In the next point (No. 8) we analyze Mercury Motion during its day period –
because the period 4222.6h is the second period on which Jupiter orbital
circumference depends- So with Mercury Motion analysis we discuss the edistance
199.2.

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Equation (7-3-d)
4900 mkm = 0.406 mkm x 12104 = 0.384 mkm x 12756
- Where
- 0.406 mkm = Earth moon Distance At Apogee Radius
- 0.384 mkm = The Earth Moon Orbital Distance.
- 12014 km = Venus Diameter
- 12756 km = Earth Diameter
- Equation no.(7-3-d) shows that, Jupiter orbital circumference effect on the
distances between the moon and Earth by the proportionality to Earth and Venus
diameters –
- This idea should be a correct one – because we have seen frequently that – Planet
orbital distance is defined almost as a function in its diameter – by that to define
the distance between the moon and Earth based on Venus and Earth diameters it's
logical idea –
- Notice
- 4900 mkm = The Sun Diameter x The Moon Diameter (error 1%)
- The data tries to show that Jupiter orbital circumference be designed geometrically
as we should discuss later.

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7-4 Mars Rotation Period Analysis
I- Data
(7-4- a)
Mars moves during (84 solar days) a distance = 174.9 mkm
But
174.9 solar days = 4197.8 hours (this period is less than 4222.6 h with 24.8 h)
(7-4- b)
Mars moves during (4222.6 h) a distance = 366.3 mkm = π x 116.6 mkm
(7-4- c)
Mars moves during (366.3 solar days) a distance = 763.4 mkm = π x 243 mkm
(760 s x 0.3 mkm/sec = 227.9 mkm = Mars Orbital Period)
(7-4- d)
Mercury moves during (4222.6 h) a distance = 720.7 mkm = Mars Motion Distance
During (346.1 solar days)
(7-4- e)
(672 mkm/ 84 mkm) = 196.8 seconds /24.6 seconds
(7-4- f)
720.7 mkm = 4.095 mkm/day x 175.94 day = 4.197 mkm x 171.7
(7-4- g)
654.9 x 24 h =24.6h x 639
Notice
Mars moves during (329.9 solar days) a distance = 687 mkm
Mercury moves during (84 solar days) a distance = 344 mkm
and
4222.6 = 193 x 21.8
2550973 km = 116750 km x 21.8
344 = 4.095 x 84 = 3.91 x 88

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II- Discussion
- In this point we try to know why mars rotation period (24.6 h) is used frequently in
Jupiter and Mercury motions data
- Because of that, we try with this period (24.6 h) by different analysis forms of data
- The point is that
- Mercury and Mars Motions have some (specific) harmony and because of that
their motions causes some (similar effect) or (proportional effect)
- Many examples can show that, let's discuss one in following:
- During 5040 seconds
- Mercury (47.4 km/s) moves a distance = 2 x Saturn diameter (error -1%)
- Mars (24.1 km/s) moves a distance = Saturn diameter (error +1%)
- Another example
- Mercury during its rotation period (1407.6 h) moves a distance = 243mkm (1%)
- Mars during Venus day period (2802 h) moves a distance = 243 mkm
- Venus Day Period = 2 x Mercury Rotation Period (error 0.4%)
- Mars rotation period (24.6 h) effect on Jupiter and mercury cycles periods isn't a
unique effect but there are many other similar effects can be discovered where
these effects together tell that a geometrical mechanism be found behind this data
creation and specifically there's a geometrical mechanism behind Mars rotation
period creation.

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But
174.9 solar days = 4197.8 hours (this period is less than 4222.6 h with 24.8 h)
- Equation no. (7-4-a) tells, Mars during 84 days moves a distance = 174.9 mkm
- Mercury day period =175.94 solar day, if 1 solar day = 1 mkm, that will result the
following…
- The distance 174.9 mkm will be equivalent to 174.9 solar days = 4197.8 h
- Mercury day period = 4222.6 hours
- The difference 4222.6 hours – 4197.8 hours = 24.8 hours
- This period (24.8 h) is different from Mars rotation period (24.6 h) with (0.8%)
- For now we consider both values are equal,
- Equation no. (7-4-a) tries to find a deep connection between Mercury Day Period
and Mars Rotation Period …we do that because of the equation in the previous
discussion which told (4331 days = 2π x 687 days = 175.94 days x 24.6). we try
to know why Mars rotation period (24.6 h) be used so frequently with Mercury
Day Period and Jupiter Motion Data.
- Based on this equation
- Mars rotation period (may be) created as a function in Mercury Day Period
- The point is that,
- The relationship between Mercury and Mars isn't clear
- The relationship between Jupiter and Mercury be so clear
- But
- Mars is a puzzled point…
- Equation no. (7-4-a) tells us that, There's some reason for a relationship between
Mercury Day Period and Mars Rotation Period regardless Jupiter Motion!

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Equations No. (a, b and c) Respectively
And
Mars moves during (175.94 days) a distance = 366.3 mkm = π x 116.75 mkm
And
Mars moves during (366.3 solar days) a distance = 763.4 mkm = π x 243 mkm
- Where
- 116.75 days = Venus Day Period
- 243 days = Venus Rotation Period
- We have a series of motions depend on one another and passed distances (all of
them) be used as periods of time based on the same rate (1mkm = 1 solar day)
- The fighting is useless
- The opponent will tell that (the data be created based on pure coincidence) and I
will say (NO there's a geometrical reason behind) but he has no proof for his (pure
coincidence claim) and I don't know the geometrical reason based on which the
data be created….
- And
- Because no help is available, the rich data will be removed without explanation
because of the weak knowledge.
- This data is created based on a geometrical reason… we have examples, let's
provide some of them in following
Example
- Mercury moves during its rotation period (1407.6 h) a distance = 243 mkm (1%)
- Venus moves during its day period (2802 h) x 2 a distance = 706 mkm
- Mars moves during Venus Day8 Period (2802 h) a distance = 243 mkm
- Where
- 243 days = Venus Rotation Period 706 days = π x 224.7 days (= Venus Orbital Period)

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- The planets move distances and used them as periods of time
- This fact is proved frequently spite we can't catch how that's happened
- Many questions are left behind
- For example
- If Mars moves during (116.75 solar days) another distance (in place of 243 mkm
move 260 mkm)
- In this case Venus rotation period will be changed into 260 mkm or still be 243
mkm?
- I want to say
- The solar system is a machine of gears. Its motion depends on the gears motion but
the geometrical rules which controls this motion are unknown and because of that
we see the data but don't understand.

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Equation No. (7-4-e)
(672 mkm/ 84 mkm) = (196.8 seconds /24.6 seconds) = 8
- Where
- 671 mkm = Venus Jupiter Distance
- 84 mkm = Mars Original Orbital Distance
- During 196.5 (Mars rotation periods) Jupiter moves a distance =227.9 mkm =
Mars Orbital Distance.
- Notice. Mars migration theory tells that Mars original orbital distance was 84 mkm
and had migrated to it current one 227.9 mkm.
- Equation no.(7-4-e) tells that,
- Mars rotation period 24.6 h (may be) created because of Mars orbital distance
(227.9 mkm)
- Means
- Mars had migrated from its original orbital distance (84 mkm) to its current one
(227.9 mkm), and the migration process almost needed Mars rotation period to be
=24.6 hours. I mean some geometrical reason behind forced to create Mars rotation
period to be =24.6 hours!
- But
- The basic value in the Equation is the value (671)
- Because 671 h (of Mercury motion) = 687 solar days (of Jupiter motion) = 109
solar days (of Mars motion)…
- And
- During 671 h Mercury moves 2 x 57.2 mkm (Mercury orbital distance 57.9 mkm)
(1%)
- During 687 days Jupiter moves 778.6 mkm = Jupiter orbital distance
- During 109 days Mars moves 227.9 mkm = Mars orbital distance

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Equation No. (7-4-f)
720.7 mkm = 4.095 mkm/day x 175.94 day = 4.197 mkm x 171.7
- Where
- 720.7 mkm = Mercury Jupiter Distance
- 4.095 mkm /day = Mercury Velocity Per A Solar Day
- 4.197 mkm = Mercury Motion Distance during (24.6 hours)
- 170 mkm = Mercury Mars Distance (error 1% with 171.7)
- The interesting information is that,
- Mercury Day period (175.9) is used in part 1 of the equation but in place of it the
distance between Mars and Mercury be used (170) in the equation part 2
- We know that the distances be used as periods of time so, if Mercury day period
175.94 solar day be used as 175.94 mkm that will be understandable
- But
- It's interesting to use the distance between Mars And Mercury (170 mkm) in place
of Mercury Day Period
- The point is that, Mercury uses of Mars rotation periods changed the distance from
4.095 mkm to 4.197 mkm and that changed the period 175.94 to 171.7
- But
- What does that mean?
- Let's write some concluded answer in following
- We know, Mars was the second planet after Mercury with original orbital distance
(=84 mkm) and had migrated to its current orbital distance (227.9 mkm) with a
distance 170 mkm from Mercury.
- The equation tells us, Mars had migrated from its original position but Mercury
controlled this migration and didn't permit for Mars to be at a distance more far
than 170 mkm from Mercury

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- Means,
- Mercury controlled Mars Migration process and didn't let the distance with Mars to
be more than 170 mkm.
- This motion and distance depend on Mercury Day Period
- Notice
- The equation tells the distance (170 mkm = Mercury Mars Distance) depends on
the distance (720.7 mkm = Mercury Jupiter Distance)
- More data can support our analysis

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MORE DATA
(1)
- (Mercury day period 4222.6 h / Mars rotation period 24.6 h) =171.7
- (Mercury rotation period 1407.6 h / Mars rotation period 24.6 h) =57.27
- Where
- 171.7 mkm is different from Mercury Mars Distance (170 mkm) with 1%
- 57.2 mkm is different from Mercury Orbital Distance (57.9 mkm) with 1%
(2)
- Light known velocity (0.3mkm/s) moves during 193 sec a distance 57.9 mkm
- Light supposed velocity (1.16 mkm/s) moves during 196.5 sec a distance 227.9
mkm
- Where 196.5 sec is different from 193 sc with 2%
- 57.9 mkm = Mercury Orbital Distance
- 227.9 mkm = Mars Orbital Distance
- Notice
- (Mars Mass / Mercury Mass) = 0.514
- And
- 360 degrees /687 days = 0.524
- The difference between (0.514) and (0.524) is around 2%
- But, If we accept these values are equal (for now)
- That may tell how Mercury control Mars motion because the rate 0.524 expresses
Mars Motion Daily and that define Mars daily motion distance and if Mars Cycles
periods be interacted with Mercury cycles periods that define obligatory Mars
orbital distance. And by that Mercury define the point to which Mars could
migrate and couldn't move beyond it.

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MORE DISCUSSION
- The previous data tries to show that, a deep connection is found between Mercury
an Mars motions – this connection effect is seen on Jupiter motion by the equation
(4331 days =2π x 687 days =175.94 days x 24.6), but
- This connection is found between Mercury and Mars motions originally, even this
connection controlled Mars Migration process…
- I hope I do my job correctly,
- Because
- The puzzle be raised because of this equation (4331 days =2π x 687 days =175.94
days x 24.6) and we have tries to explain why these cycles periods are rated with
each other…
- But now
- We have more tenths of data shows more connections between the 2 same planets,
I claim there's a geometrical reason behind and the (pure coincidences of numbers)
is a wrong claim if any one try to raise because we have tenths of directed data
which express of the 2 planets motions. And
- If I can't catch the geometrical reason of mechanism behind this data creation that
shouldn't effect negatively of this data force.
- Mars rotation period isn't the only piece of data effective strongly on the 3 planets
motions but there are many other basic players of data and all of them tells loudly
that the data be created based on geometrical mechanism and these planets motions
be done depends on one another and in proportionality with one and other and that
means, if any planet of these 3 planets be absent the other planets will change their
motion or even suffer from more great damage – we here don't deal with separated
moving rigid bodies – we deal with one building and each planet is a part of this
same building – it's one machine of gears and any gear stops will effects greatly on
all other gears motions.

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Equation No. (7-4-g)
654.9 x 24 h =24.6 h x 639
- Where
- 654.9 mkm = Jupiter Saturn Distance
- 639 mkm = (629 mkm /929mkm) x 940 mkm
- 24.6 h =Mars Rotation Period
- But
- Jupiter moves during 639 days a distance 723.25 mkm (= 720.7 mkm)
- Saturn moves during 654.9 days a distance 550.7 mkm (= Mars orbital distance)
- The equation basic value is 639 days or (639 mkm) because Jupiter moves during
this period (639 days) distance = 723 mkm where Mercury moves during its day
period a distance =720.7 mkm = Mercury Jupiter distance
- The equation tells that, the periods (654.9 and 639) are rated based on Mars
rotation period – but the period 639 days has a value because of the distance 720.7
mkm – means we can't see why this equation is important unless w understand
why Jupiter needs the period 639 days? And Jupiter needs it to pass a distance
=720.7 mkm
- Shortly
- We need to discuss Mercury motion for the distance 720.7 mkm for better
understanding– we Discuss Mercury Motion in the next point (no. 8)
- Notice
- (629 mkm /929mkm) x 940 mkm
- 629 mkm= Earth Jupiter Distance
- 929 mkm= Earth Jupiter Distance (when the 2 planets be on the sun 2 sides)
- That tells the distance 639 mkm is created based on Earth Jupiter Distance

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8- Mercury Motion Distance During Its Day Period
8-1 Preface
8-2 Why Mercury Jupiter Distance =720.7 mkm?
8-3 Pluto Motion For A Distance =720.7 mkm
8-4 Jupiter Motion In A Comparison With Light Motion

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8-1 Preface
- Mercury moves during its day period a distance =720.7 mkm
- In this point we choose 3 planets motions for the distance 720.7 mkm – these
planets are Mercury, Jupiter and Pluto
- Mercury moves 720.7 mkm in a period =4222.6 h = Mercury day period
- Jupiter moves 720.7 mkm in a period = 637 solar days = 622 Mars rotation periods
- Pluto moves 720.7 mkm in a period = 1775 solar days
- The data discussion will show the importance of these planets motions
- But
- Matter is created out of light, as a result the solar planets move accompanying with
light motion –
- When we discuss the light motion effect on planets motions we will discover that
the light beam started from Mercury to Jupiter and then to Pluto –
- Means,
- I have choose these 3 planets because of the light motion effect on them, but here
we don't discuss the light motion and I try to show that the planets motions data be
created depends on one another by analysis this and without any outer idea -
- Shortly
- The 3 planets motions choice will be more clear with light motion discussion – but
here we try to show that – the planets motions data be created dependently on one
another.

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8-2 Why Mercury Jupiter Distance =720.7 mkm?
I - Data
(8-2-a)
Mercury moves during its day period (4222.6 h) a distance =720.7 mkm
(8-2-b)
Mercury day period =2 Mercury orbital period = 3 Mercury rotation period
(8-2-c)
Jupiter moves during Mercury day period (4222.6 h) a distance =199.2 mkm
(8-2-d)
(240 mkm/158 mkm) =(88 days /58.65 days) (error 1.2%)
II – Discussion
(240 mkm/158 mkm) =(88 days /58.65 days) (error 1.2%)
- Where
- 240 mkm = Mercury Motion Distance during its rotation period (1407.6 hours)
- 158 mkm = π x 50.3 mkm (Mercury Venus Distance)
- 88 days = Mercury Orbital Period
- 58.65 days = Mercury Rotation Period
- Let's remember the question?
- Why Mercury Jupiter Distance =720.7 mkm? We have 2 reasons …. one reason is
related to Mercury Motion and the other is related to Jupiter motion.

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- (1st
Point Mercury Motion)
- Mercury Day period 4222.6 hours = 2 x Mercury orbital period 2112 hours, and
- Mercury Day period 4222.6 hours = 3 x Mercury rotation period 1407.6 hours…
- And
(I)
- Mercury moves during its rotation period a distance = 240 mkm (which is related
to Mercury Venus Distance) with the rate (1.5= Mercury orbital period / Mercury
rotation period).
- Means, Mercury Motion distance during its rotation period is related to Mercury
Venus Distance (it's related to Venus Basically because 243 days = Venus rotation
period)
(II)
- Mercury moves during its orbital period a distance = 360 mkm (Mercury orbital
circumference). (means this motion is related to Mercury Position)
(III)
- Mercury moves during its day period a distance = 720.7 mkm= Mercury Jupiter
distance
- By that
- Mercury has 3 cycles
- By its rotation period creates a connection with Venus (the most inner planet to it)
- By its orbital period does its revolution around the sun
- By its day period creates a connection with Jupiter (the nearest outer planet to it)
- There's some geometrical design on which Mercury moves
- And if this idea is a correct one, we can conclude simply that, Mercury has to
move a distance = 720.7 mkm= Mercury Jupiter distance by using on of its cycles
periods (and of course no better choice than Mercury Day Period)
- Geometrically, if Mercury connects with Venus by its motion during rotation
period, So mercury should connect with Jupiter with its day period.

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- If this description is a correct one, the question should be (why mercury day be
=4222.6 h) and this question we discuss in Jupiter orbital circumference analysis.
- Notice
- Mercury Venus distance is multiplied by (π) and then the rate (1.5)… while
Mercury Jupiter distance (720.7) be used directly… that because Mercury day
period is a period = (1 period) but mercury orbital period (0.5 period) and Mercury
rotation period be (1/3 Period). That means, the fractions be found with (orbital
and rotation periods) while day period uses the integer number… So the rates of
periods be seen in the distances.

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- (2nd
Point Jupiter Motion)
- Mercury Jupiter Distance =720.7 mkm = Mercury Motion distance during Mercury
day period (4222.6 h).
- But
- Jupiter moves during Mercury day period (4222.6 h) a distance = 199.2 mkm
- Because
- 720.7 mkm is Mercury Jupiter Distance, both planets may interest for this same
distance and we have seen that Mercury moves during its day period 720.7 mkm
and the question – Why Jupiter doesn't take the distance 720.7 mkm into account
in its motion?
- In fact Jupiter motion takes into consideration the distance 720.7 mkm,
- But the geometrical mechanism is hard for me to catch, let's refer to its data in
following:
- Jupiter moves during Mercury day period (4222.6 h) a distance = 199.2 mkm
- But
- 199.2 mkm x π = 629 mkm (Earth Jupiter Distance)
- And
- (629 mkm /929 mkm) = (637 mkm/ 940 mkm)
- Where
- 629 mkm = Earth Jupiter Distance
- 929 mkm = Earth Jupiter Distance when the 2 planets be on the sun 2 sides
- 940 mkm = Earth Orbital Circumference.
- 637 mkm = The Required Distance
- Jupiter moves during 637 days a distance = 720.7 mkm
- Based on that, Jupiter motion for 199.2 mkm causes its motion for 720.7 mkm,
means, some connection is found between the 2 motions
- Notice, this explanation can be more clear when we compare Jupiter motion with
light motion –we do that in point no. (4-4) for better explanation for this motion.

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8-3 Pluto Motion For A Distance =720.7 mkm
I- Data
(8-3-a)
0.3 mkm/sec x 5906 seconds = 1775 mkm
(8-3-b)
0.406 mkm /day x 1775 days = 720.7 mkm
(8-3-c)
2.574 mkm /day x 687 days = 1775 mkm (error 0.3%)
(8-3-d)
0.406 mkm /day x 4331 days = 1775 mkm (error 1%)
(8-3-e)
90560 days x 2 = 1775 days x 101
But
37100 mkm x 2 = 720.7mkm x 103
(8-3-f)
0.3 mkm/sec x 2390 second = 717 mkm (error 0.5%)
(8-3-g)
(1775/346.6) =(24.1/4.7) = 5.14
(8-3-h)
30589 days = 1775 days x 17.2
(8-3-i)
(929 km/542 mkm) = (3030 mkm/1775 mkm)

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II- Discussion
0.3 mkm/sec x 5906 seconds = 1775 mkm
0.406 mkm /day x 1775 days = 720.7 mkm
2.574 mkm /day x 687 days = 1775 mkm (error 0.3%)
0.406 mkm /day x 4331 days = 1775 mkm (error 1%)
- Where
- 0.3 mkm/sec = light known velocity
- 5906 mkm = Pluto Orbital Distance
- 0.406 mkm/day = Pluto Velocity Per A Solar Day
- 2.574 mkm/day = Earth Velocity Per A Solar Day
- We discuss these 4 equations together, Because one idea be seen in them, let's
write this idea directly in following…
- 1 hour of Mars Motion = 2π hours of Jupiter Motion
- And
- 1 hour of Earth Motion = 2π hours of Pluto Motion
- These rules we have discussed before deeply and frequently
- The question is (How The Rate 2π Be Transported?)
- The period 1775 days (or the distance 1775 mkm) is the method to do that,

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- Earth moves during (687 days Mars orbital period) a distance = 1775 mkm =
Pluto Motion distance during (4331 days = Jupiter orbital period)
- By this equality of distances, the rate of time (2π) be transported from (Jupiter and
Mars motions) to (Earth and Pluto motions)
- The value (1775) tells us this information clearly, let's with it in following:
- Our interest point is the distance 720.7 mkm and we ask about (how many day
Pluto needs to pass 720.7 mkm? The answer is 1775 solar days)
- But
- The value 1775 mkm be passed by 3 motions
- Light (0.3 mkm/sec) motion during 5906 seconds
- Earth (2.574 mkm/day) motion during (687 days)
- Pluto (0.406 mkm/day) motion during (4331 days)
- We know that
- Light motion = (2π) Planet motion (will be discussed in Part no. II)
- If we use this rule, so
- 5906 mkm = (2π) x 940 mkm or 5906 seconds = (2π) x 940 seconds
- Where
- Shortly
- The value 1775 shows a comparison between light and planet motions – we will
discuss this idea clearly in the next point (8-4)

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90560 days x 2 = 1775 days x 101
But
37100 mkm x 2 = 720.7mkm x 103
- Where
- 37100 mkm = Pluto Orbital Circumference
- The rates 101 and 103 are different with 2% (we should later explain the
geometrical rule of the error 2%)
- For now we consider the 2 rates (101 and 103) are equal
- Equation (8-3-e) tells that, while Pluto orbital circumference be created as a
function in the distance (720.7 mkm) (Mercury Jupiter Distance), also Pluto orbital
period be created as a function in the period 1775 days which Pluto needs to pass
the distance (720.7 mkm).
0.3 mkm/sec x 2390 second = 717 mkm (with 720.7 mkm error 0.5%)
- Where
- 2390 km =Pluto diameter
(1775/346.6) =(24.1/4.7) = 5.14
- Where
- 346.6 days = The Nodal Year
- 24.1 km/s = Mars velocity
- 4.7 km/s = Pluto velocity

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30589 days = 1775 days x 17.2
- Where
- 30589 days = Uranus Orbital Period
- 17.2 hours = Uranus Day Period
- 1774 days = our point of discussion
Equation no. (8-3-i)
(929 km/542 mkm) = (3030 mkm/1775 mkm)
- Where
- 929 mkm = Earth Jupiter Distance when the 2planets be on 2 different sides
from the sun
- 3030 mkm = Uranus Pluto Distance
- Notice
- 346.6 seconds x 0.3 mkm/sec = 104 mkm
- 346.6 seconds x 1.16 mkm/sec = 2 x 201 mkm
- 346.6 days x 4.095 mkm /day = 1419 mkm
- Notice
- The basic idea behind this data may be as following:
- Pluto Orbital Distance (5906 mkm) be defined based on Mercury Jupiter Distance.
- That means, the light motion created Pluto orbital circumference by using Mercury
Jupiter distance as a measurement - But
- We know that, the light used the distance 100733mkm as a measurement
- That means,
- The distance 100733 mkm should be created as a function in the distance 720.7
mkm (means the 2 distances should be connected geometrically)
- 100733 mkm = 720.7 mkm x 139.8
- Pluto moves during 346.6 days a distance = 140.7 mkm
- That tells the nodal year (346.6 days) plays an important role here but what's it?

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- Notice
- Why The Error 2% Doesn't Effect Negatively On The Discussion?
- as we have seen before
- Earth moves during its day period a distance = 2.574 mkm (100%)
- Pluto moves during its day period a distance = 2.593 mkm (101%)
- The moon displacements total during (29.53 days) = 2.598 mkm (102%)
- The moon apogee orbital circumference = 2.550 mkm (99%)
- The previous data is an example for this system which is used frequently in
different planets motions data
- I want to say that
- For some geometrical necessities, the solar system geometrical design created
categories of data on 3 levels each one is different with 1%
- I don't know why
- But the error 1% I have found regularly and in order case – so this order of data is
an example of many similar orders – let's provide another one in following
- 17.4 degrees = the inner planets orbital inclinations total
- 17.2 degrees = Pluto orbital inclination (error 1% )
- And
- 23.6 degrees = the outer planets orbital inclinations total
- 23.4 degrees = Earth Axial Tilt
- The error 1% or 2% be found for geometrical necessity – so when we find it we
should not remove the data for that
- But, notice
- I mean the rates 1 % or 2% ONLY but NOT 1.4%, 1.5%, 1.6% or 1.7%.......etc
- All these rates are errors in measurements. The geometrical design aim only 1% or
2%.

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8-4 Jupiter Motion In Comparison With Light Motion
I - DATA
(8-4-a)
4222.6 = 2π x 671
But
0.3 mkm /sec x 671 s = 201 mkm (light moves during 671s a distance 201 mkm)
13.1 km/s x 4222.6 h x 3600 s = 199.2 mkm (Jupiter moves 199.2 mkm)
(8-4-b)
4900 mkm = 0.3 mkm/sec x 16333 seconds
(8-4-c)
4900 mkm = 1.16 mkm/sec x 4224 seconds
(8-4-d)
4900 mkm = 199.2 mkm x 24.6
(8-4-e)
24.6 = (1.16/0.3) x 2π (error 1.2%)
(8-4-f)
(10747 x 24)/24.6 = 10485 = (4331 x 24)/ 9.9 h
(8-4-g)
(10747 /4331) =(24.6/9.9) = (24.1/9.7) = (17.4/7) =2.48

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II – Discussion
4222.6 h = 2π x 671 h
- Where
- 4222.6 h = Mercury Day Period
- 671 mkm =Venus Jupiter Distance
- But
- Light known velocity (0.3 mkm /s) during 671 s moves a distance (201 mkm)
- Jupiter (13.1 km /s) during 4222.6 h a distance (199.2 mkm) (error 1%)
- Where 4222.6 hours =Mercury Day Period
- The equation tells, Jupiter moves during Mercury day period (4222.6 h) a distance
= 199.2mkm = light motion distance during 671 seconds (671= 4222.6 /2π)
- We should notice that
- We deal with strict geometrical design, and no mistake is allowable
- Light known velocity (0.3mkm/sec) moves during 671 seconds a distance 201
mkm. We consider that light motion is the master one here
- Light motion effects on planet motion with the rate (2π) and both motions pass
equal distances based on this rate
- But
- 1 second of light motion = (2π) hours of Jupiter motion
- This is the rule we should keep in mind
- 1 second of light motion = 1 hour of planet motion but with the rate (2π) between
the passed distances. Means if the distances be equal so 1second be = (2π) hours
and if 1second be = 1hour the passed distance will not be equal but rated with this
rate (2π).
- Notice
- The rate (2π) rule we discuss in part (II) of this paper, but the rule 1 second = 1
hour isn't the general one, because the general one is 1 second = 1 day, but Jupiter

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here uses a part of this rate and we try to analyze its motion to see the depth behind
this rate.
- The conclusion is
- 1 second of light motion = (2π) hours of Jupiter motion
- We should see that as clear as possible
- Light does the motion at first, that means, we don't deal here with (720.7 mkm) but
we deal with light motion for a distance (201 mkm)
- This distance (201) will give a birth for planets motions distance (720.7 mkm) but
the distance (201 mkm) is the original one.
- Light And Jupiter Move Equal Distances
4900 mkm = 199.2 mkm x 24.6
- Where
- 199.2 mkm = Jupiter motion distance during Mercury day period (4222.6 h)
- How to understand this hard equation (3-2-d)? we have to analyze more deep Mars
rotation period, let's try to do that in following
- 24.6 = (1.16/0.3) x 2π (error 1.2%)
- Where
- 1.16 mkm/sec = light supposed velocity
- 0.3 mkm/sec = light known velocity
- Equation no. (8-4-e) tells a great information that, Mars rotation period is a point
inside which light supposed velocity (1.16 mkm/sec) interacted or cohered with
light known velocity (0.3mkm/ec)!
- We can't accept such great conclusion based on one simple equation, we have to
go to mars and examine if its motion be related in this same conclusion

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- MORE DATA
(1)
- (300000 km /24.1 km) = (120536 km/9.7 km)
- Light known velocity (0.3 mkm/sec) / Mars velocity 24.1 km/sec = Saturn
diameter 120536 km / Saturn velocity for 1 second.
(2)
- 1160000 km = 24.1 km/sec x 48133 seconds
- Saturn (9.7km/s) moves during 48133 seconds a distance = 466556 km= Jupiter
motion distance during Jupiter day period = Neptune motion distance during a
solar day.
- But
- Saturn (9.7km/s) moves 300000 km during a period 30589 seconds (error 1%)
(30589 days = Uranus Orbital Period)
- Saturn (9.7km/s) moves 1160000 km during a period 120536 seconds (error 0.8%)
(120536 km = Saturn diameter)
- But
- (120536 /30589) = 3.94 but (1h of Mercury motion =3.91 h of Mars Motion)
- How to understand this data?
- The interaction between light known velocity (0.3 mkm/s) and light supposed
velocity (1.16 mkm/sec) be done in Saturn motion, and Saturn transports its
motion to Mars where the interaction between the 2 light beams velocities be seen
in Mars rotation period – that explains why Mars rotation period is so important as
such.
(10747 x 24)/24.6 = 10485 = (4331 x 24)/ 9.9 h
(10747 /4331) =(24.6/9.9) = (24.1/9.7) = (17.4/7) =2.48

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- 9.9 hours = Jupiter Day Period
- 24.1 km/s = Mars Velocity
- 9.7 km/s = Saturn Velocity
- 17.4 deg = the inner planets orbital inclinations total
- 7 deg = Mercury orbital inclination.
Additional Equation no. (1)
10 x 10747 days x 24 h = 10.7 h x 2 x 120536 = 2579280 hours - Let's remember
- (1)
- Saturn (0.838 mkm /daily) moves during 120536 days a distance =100733mkm =
the distance be passed by light supposed velocity (1.16 mkm/s) during one solar
day (where 120536 km = Saturn Diameter)
- (2)
- The moon (2.4 mkm/ daily) moves during 10747 days a distance =25920mkm =
light known velocity (0.3 mkm/s) motion distance during a solar day. And
Additional Equation no. (2)
- 1433.5 mkm (Saturn Orbital Distance) = 17.75 mkm x (511.1 /2π)
- 17.75 mkm= the planets motions distances total per a solar day (this total contains
the moon velocity per a solar day 2.57 mkm = Earth velocity because they aren't
separated from one another)
- 511 deg = The Planets Axial Tilts Total

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9- The Solar System Historical Development
9-1 Preface
9-2 Mars Migration Theory
9-3 Pluto Migration Theory
9-4 Planets Migration Theories Proves

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9-1 Preface
- The solar system geometrical design is effected by three basic factors, let's
summarize them in following:
- (1) Planets Motions Dependency On One Another
- (2) The Historical Events Effect On Planets Motions
- (3) Light Motion Effect On Planet Motion
- Shortly
- Matter is created out of light and the matter isn't separated from its parent light but
moves with it in one unified motion by using different rates of time
- This is the solar system case. The solar system is created out of one light beam and
the planets move with this light beam in one unified motion by using different
rates of time – this idea be explained in details in Part (II) of this paper with its
proves discussion.
- The planets behave as rigid bodies and not as light beam. Although the matter be
created out of light beam- the rigid bodies behavior still be distinguish from light
motion - here – our difficulties are to discover how the matter be created out of
light beam and how this light motion effect on the matter motion.
- But
- Through the solar system history, basic changes are done for the planets positions,
and these changes also effect on the planets current motions. As a result, the
planets motions description be some (very) complex process
- Because
- We at first need to explain how the matter be created out of light and how the
created matter moves by effect of light motion – then we should describe how the
planets matters effect on one another and how the motion be done based on these
effect- and at end – we have to discover the changes happened through the solar
system history and how these changes effect on the planets current motions –
- I wish the respectful reader doesn't find the process so complex,

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- Newton Theory gives us a clear and simple idea, but it's just an imaginary and
unreal idea – the complex description for the solar planets motions is some logical
process for its accurate fabrication and long age –for example – a human his age
100 years goes to a doctor for diagnosis – the diagnosis should be some complex
because of the age and its accurate creation –
- We all hope for simple ideas to explain the machine –but the facts force us for
what's real and prevents us from the imaginary ideas – for that reason we should
thank Newton because his simple idea gives us the chance to love the physics –
and by that we bear the complex ideas now….
- Based on this vision we have to discover some basic changes occurred in the solar
system history -
- There are 2 basic events occurred in the solar system history
- (1st
Event) Mars Migration
- Mars original orbital distance was 84 mkm and had migrated to its current one
227.9 mkm.
- Pluto Migration
- Pluto Was The Mercury Moon And Had Migrated With Mars Migration
- (2nd
Event) The Sun Creation
- The Earth Moon Be Created As A Result For Mars Migration
- Saturn is the last planet be created in the solar system (be crated after the Earth
Moon Creation)
- The Sun Be Created After Saturn Creation
- The Sun Age simply disproves Newton Theory of The Sun Mass Gravity. Because
The Sun Is Created After All Planets Creation And Motions.
- In this point we try to prove the 2 historical events

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9-2 Mars Migration Theory
- Mars was the next planet after Mercury with original orbital distance =84 mkm
and Mars had migrated into Mars current orbital distance (227.9 mkm)
- Through Mars Displacement from (84 mkm) to (227.9 mkm), Mars had collided
with Venus (at first) and then with Earth (at second) and then reach to its current
orbital distance point (227.9 mkm).
- Mars had moved from (84 mkm) to (227.9 mkm) in a direct displacement – and
had pushed with it all collisions debris in its direction
- From these collisions debris the Earth could create its own moon and also Mars
moons are created from them and the rest debris be attracted by Jupiter Gravity
and Created The Asteroid Belt.
- Means,
- Mars Migration Theory is in full harmony with (Giant- Impact Hypothesis), but
- Mars itself had collided with Earth and caused the moon creation and not the
ancient planet (theia) as supposed by the Giant-impact hypothesis.
- The point is that, the planets order (Mercury – Venus –Earth) shows that Mars was
the second planet after Mercury – and Mars had migrated from (84 mkm) to (227.9
mkm) –through this displacement – Mars has collided with Venus and Earth–
- Mars collisions with Earth and Venus left many proves behind which prove that
Mars did these collisions and not the planet (theia).
- Mars Migration theory answers many of the Giant-impact hypothesis questions.
- Let's do that in following
(1st
Question)
- Why has Venus no a moon? spite it suffered from a similar collision as Earth?
- Mars had moved its displacement from (84 mkm) to (227.9 mkm), and through
this displacement Mars pushed all debris with it in its motion direction and
because of that, Venus had found no debris around, And couldn't create its own
moon because of that.

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- But the debris lost some of their motion momentum at Earth position and Earth
gravity is more strong than Venus, by that Earth could attract some debris by
which Earth created its moon.
(2nd
Question)
- What's The Lunar Magma Ocean (LMO) Origin?– It's Venus
- Because
- The Earth moon rocks are created from the 3 planets debris (Mars- Venus – Earth)
and for that the moon has a Magma Ocean (LMO).
(3rd
Question)
- Why The Iron Oxide (Feo) of the Moon= (13%)?
- Because The rate (13%) is a middle rate between Mars rate (18%) and the
terrestrial mantle (8%).
Notice no.(1)
- Mars Moons Creation is a good proof for Mars Migration Theory.
- The collisions debris lost the great part of their momentum when reach to Mars
orbital distance point (227.9 mkm), because of that, Mars with its small mass could
attracted 2 moons, because the debris is too much around it and can attract them
easily.
- But Venus great gravity couldn't create even one moon because no debris be found
around it
Notice no.(2)
- The asteroid belt is one more proof for Mars Migration
- The collisions debris which were pushed with Mars motion to its current orbital
distance point (227.9 mkm) couldn't all be attracted by Mars gravity because of its
small mass, Mars had attracted only its 2 small moons
- But
- Jupiter great gravity attracted the rest debris and they created the asteroid belt.
- The whole trajectory is filled with references of the event and shows that it's a fact.

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Notice no.(3)
- Mars diameter before Migration was 7070 km and be 6792 mkm after migration as
a result for the collisions Venus and Earth
- We know that because
- The equation (7070 km x 1092
= 84 mkm), where 84 mkm=Mars original orbital
distance.
- The equation (d = r x 1092
) is the equation controls planet orbital distance based on
its diameter. The equation be used by Mercury, Earth and Saturn but the planets
migration effects negatively on the other planets using of it.
- From this analysis we conclude, Mars Diameter be decreased with 4.1%
- Additional Data
- Mercury Orbital Distance 57.9 mkm = Mercury Diameter 4879 km x 1092
- Earth orbital distance 149.6 mkm = Earth diameter 12756 km x 1092
- Saturn orbital distance 1433.5 mkm =Saturn diameter 120536 km x 1092
Notice no.(4)
- If Mars Mass be decreased as a result for the collisions with 8%, in this case
- Mercury mass (0.33) and its orbital distance (57.9 mkm) be in proportionality with
Mars mass (0.688) and Mars original orbital distance (84 mkm) based on Newton
gravitation Equation – this same proportionality be working also with the current
data of Jupiter and Saturn.

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9-3 Pluto Migration Theory
- Pluto Was The Mercury Moon
- One great force stroke Mercury, Pluto and Mars, with order
- Means,
- Mercury had received the most strong stroke directly, Mercury couldn't escape
from its fate. But Mercury axial tilt was (One Degree) and after the stroke be (0.01
Degree or even Zero)!
- The third stroke be received by Mars by which Mars had Migrated
- The second stroke be received by Pluto, which caused Pluto to be flying along the
solar system and reach to the end point of the solar system.
- The solar system end point with distance (5906 mkm) is a defined geometrically.
- Before Pluto migration –
- Neptune orbital distance was 5906 mkm
- Means,
- Neptune was in the position in which Pluto now be found. The distance 5906 mkm
was Neptune original orbital distance
- Pluto had flying along the solar system distance and reach to Neptune position, and
had collided with Neptune, pushed it out of its orbit and then put it out of (Pluto
Influence area) – That's why Pluto Neptune Distance = Pluto eccentricity Distance
Result No. 1
Mercury Pluto Distance = 5848 mkm = 101 x Mercury orbital distance 57.9 mkm
- This data is so important because the solar system distances be designed in
proportionality with it. based on that the rate (101) is one geometrical pillar in the
solar system design.
Result No. 2
Neptune Be Out Of The Network
- We will study that, the solar system distances be created in a network form in point
no. (12), with many proves we discuss this point…
- But

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- How the distances be created in a network form? We should answer this question
in details in that point no.(12) – but let's summarize the idea in following:
- Matter is created out of light and the planets be created of one light beam- light
motion creates the distances through which the planets move – by that –
- The Solar System Distances Be Similar To Railways
- And, the planets be similar to trains
- That shows why the planets motions be obligatory motions that because light
provides the required energy for distances creation and forces the planets to move
through these distances by this energy.
- Now, we have very (unclear) event – because –
- Pluto had pushed Neptune and put it Out Of The Railways
- That means, Neptune has no orbit and no definition of motion – and because of
that Neptune needed energy to build its orbit!
- Frankly
- I don't understand correctly the meaning of the network or how Neptune be out of
the network- because no space (I know) out of the network and I can't define any
point out of the network
- But
- This idea I have built on 2 data which are
- (1) Neptune Pluto Distance = Pluto Eccentricity Distance =1411 mkm
- (2) Neptune has seized 14% of Jupiter energy to create its orbital circumference
28255 mkm and this lost energy is registered clearly in the solar planets distances
as we will discuss in Part no.(II) of this paper.
- These 2 data pushed me to conclude that, Neptune had no orbit and had to create
one for which Neptune seized the energy, Now this result must be done by the
collision between Neptune and Pluto.
Result No. 3
- Pluto and Neptune collisions caused to create Pluto moons and the Kuiper belt.

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9-4 Planets Migration Theories Proves
(Point No. 1) (Mars Migration Proves)
Mars Migration proves depends on the interaction of motion between Mercury and
Mars supposing that Mars was Mercury neighbor.
I- Data
(9-4-a)
(Mars Mass / Mercury Mass) = (6792 km/4879 km)2
(9-4-b)
(687 days /175.94 days) = (227.9 mkm /57.9 mkm)
(9-4-c)
7 degrees = 5.1 degrees + 1.9 degrees
II- Discussion
(Mars Mass / Mercury Mass) = (6792 km/4879 km)2
= 0.524
- Where
- 6792 km = Mars diameter
- 4879 km = Mercury diameter
- Equation no. (1) tells that, Mercury And Mars Masses And Diameters Are Rated
With Each Other.
Notice
- Mars motion daily =0.524 degrees
(687 days /175.94 days) = (227.9 mkm /57.9 mkm)
- Where
- 175.94 days = Mercury Day Period
- 227.9 mkm = Mars Current orbital distance
- 57.9 mkm = Mercury Current orbital distance

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- More data is rated between Mars and Mercury
- We should notice that, the data proportionality is done mostly between the
neighbor planets… for example
- Mars orbital period (687 days) = the moon orbital period (27.3 days) x 25.2
- Where 25.2 deg = Mars Axial Tilt. Also
- 25.2 deg = 1.9 deg x 13.17 deg
- Where, 13.17 deg = The Moon Daily Degrees
- And 1.9 deg = Mars orbital inclination
Equation No. (9-4-c)
7 degrees = 5.1 degrees + 1.9 degrees
- Where
- 7 deg = Mercury orbital inclination
- 5.1 deg = The moon orbital inclination
- 1.9 deg = Mars orbital inclination
- Mercury motion data shows a strong proportionality with Mars motion data which
gives reference that Mars once was a neighbor to Mercury.
-

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(Point No. 2) (Pluto Migration Proves)
Pluto Migration proves depends on the fact that Pluto was the Mercury moon and by
that Pluto be longed to the inner planets.
I- Data
(9-4-d)
Pluto is a planet belonged to the inner planet (small mass and long day period)
(9-4-e)
The rate (101) controls the solar system basic data
(Mercury Pluto Distance/ Mercury orbital distance) = 101
II- Discussion
- In Part no.(II) there are many other proves supports Pluto Migration Theory and
proves that Pluto be belonged to Mercury in its original case
- Notice
- 17.4 deg = 7 deg (Mercury orbital inclination) x 2.5 deg (Saturn orbital inclination)
- 17.4 deg = 5.1 deg (the moon orbital inclination) x 3.4 deg (Venus orbital
inclination)
- 17.2 deg = Pluto orbital inclination (error 1%)
- Notice
- Pluto Migration explains why bode law couldn’t predict Neptune Orbital Distance
– Because Neptune orbital distance be created as additional trajectory in the solar
system distances network – means- the equations be built on the original design
couldn't predict Neptune orbital distance because this distance be defined after The
Planets Migration.

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10- The Sun Age Description
10-1 The Sun Circles The Earth
10-2 The Rate (1.0725)
10-3 The Sun Diameter Analysis
10-4 The Sun Rays Analysis

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10-1 The Sun Circles The Earth
- The sun gives one face always to the Earth during the motion. although Earth
revolves around the sun a complete revolution, we always see the same face of the
sun, that tells the sun rotates with us giving The Earth The Same face always
- Can this motion refer to the Sun dependency on the period (365.25 days = Earth
orbital period)?
- Can that lead us to conclude, the sun be created after the Earth and because of that,
The Sun motion takes into consideration the period 365.25 days?
- Also
- The Sun Behavior is similar perfectly to the moon behavior, both give the same
face to the Earth during the motion.
- Why we accept that the moon be created after The Earth Creation but The Sun be
Created Before The Earth Creation? if the 2 behaviors are similar it may prove
both (the sun and the moon) be created after The Earth Creation.

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10-2 The Rate (1.0725)
I- Data
(A)
(1)
= Mercury Jupiter Distance x 2
(2)
Earth Neptune Distance = Mercury Saturn Circumference (error 0.5%)
(3)
Jupiter Venus Distance = Venus Orbital Circumference (error 1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (error 1.2%)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (error 0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (error 0.8%)

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(B)
More Data
Why These Distances Are NOT Equal?
1. 0725
.
1
mkm
2.41
nce
Circumfere
Orbital
Moon
mkm
2.58
Motion
Daily
Earth
=
2. 1.0725
km)
(378500
radius
Eclipse
Solar
Total
km)
(406000
radius
orbital
Apogee
=
3. 0725
.
1
distance
Mercury
Jupiter
mkm
720.3
Distance
Orbital
Juppiter
mkm
6
.
778
= (Error 0.7%)
4. 1.0725
Distance
Venus
Jupiter
mkm
670
distance
Mercury
Jupiter
mkm
720.3
=
5. 1.0725
Distance
Earth
Jupiter
mkm
629
Distance
Venus
Jupiter
mkm
670
= (Error 0.6%)
6. 1.0725
mkm)
(1325.3
Distance
Venus
Sarurn
mkm)
(1433.5
Distance
Orbital
Saturn
= (Error 0.8%)
7. 1.0725
mkm)
(1205.6
Distance
Mars
Sarurn
mkm)
(1284
Distance
Earth
Saturn
= (Error 0.7%)
8. 1.0725
mkm)
(2644
Distance
Mars
Uranus
mkm)
(2872.5
Distance
Orbital
Uranus
= (Error 0.7%)
9. 1.0725
mkm)
(4495.1
Distance
Orbital
Neptune
mkm)
(4846
= (Error 0.5 %)
(10)
Notice
4846 mkm =the inner planets orbital circumferences total. it will be discussed with Jupiter
orbital circumference analysis
0725
.
1
T.
Axail
Earth
23.4
T.
Axail
Mars
25.2
T.
Axail
Mars
25.2
T.
Axail
Satrun
26.7
Tilt
Axail
Satrun
26.7
Tilt
Axail
Neptune
28.3
=
=
=

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II – Discussion
- We have discussed The previous data before
- 50% of all distances in the solar system be equal one another, and
- 40% of all distances in the solar system be rated one another with the same rate
(1.0725)
- We answered why 50% of distances are equal and 40% are rated
- Let's ask
-
- How this data can prove that (the sun I created after all planets creation and
motion)? let's answer in following
- Let's consider this question in following:
o The usual case is the equal distances as the data in Point no. (A), That
means, these rated distances were equal distances one another before and all
of them be effected by the rate 1.0725,
o Means,
o We have some historical order here, which is
o The distances were equal, but
o Some change caused these equal distances to be rated with (1.0725)
o And, 1.0725 = (100/100) + (7.25/100)
o We can conclude that,
o The distances were equal till The Sun Creation, and after the sun creation,
the sun obliquity on ecliptic (7.25 deg) caused the equal distances to be
rated with one another by the same one rate (1.0725).
o Means, the rate 1.0725 proves that, The Sun Is Created After All Solar
Planets Creation.
o One more feature supports this powerful argument, that

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o The same rate (1.0725) is used for different distances. Because the sun
effects on all solar planets. That shows the rate (1.0725) must be related to
the sun because it's the same one rate. If this rate be belonged to any planet,
it will not effect on different distances equally because the sun only effects
on the planets equally. That shows the rate 1.0725 is belonged to the sun effect.

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10-3 The Sun Diameter Analysis
I-Data
1- Diameters
- (6792 km Mars Diameter) / (4879 km Mercury Diameter) =1.392
- (4879 km Mercury Diameter) / (3475 km the moon Diameter) =1.392 (1%)
- (71492 km Jupiter Radius) / (51118 km Uranus Diameter) =1.392
2- Distances
- (57.9 mkm Mercury orbital distance) /(41.4 mkm Venus Earth distance)=1.392
- (108.2 mkm Venus orbital distance) /(78.3 mkm Earth Mars distance)=1.392
- (149.6 mkm Earth orbital distance) /(108.2 mkm Venus orbital distance)=1.392
- (4267 mkm Mars Neptune distance) /(3061 mkm Saturn Neptune distance)=1.392
- (778.6 mkm Jupiter orbital distance) /(550.7 mkm Mars Jupiter distance)=1.392
- (550.7 mkm Mars Jupiter distance x 2) /(778.6 mkm Jupiter orbital distance) =1.392
- (5127 mkm Pluto Jupiter distance) /(3716 mkm Jupiter Neptune distance) =1.392
(error 1%)
- (5906 mkm Pluto orbital distance) /(4267 mkm Mars Neptune distance) =1.392
- (2872.5 mkm Uranus orbital distance) /(2094 mkm Jupiter Uranus distance) =1.392
3- Periods
- (243 days Venus Rotation Period) /(175.94 days Mercury day period) =1.392
- 2.5 deg (Saturn orbital inclination) /1.8 deg (Neptune orbital inclination) =1.392
- 1.8 deg (Neptune orbital inclination) / 1.3 deg (Jupiter orbital inclination) =1.392
- 5.1 deg (The moon orbital inclination) / 3.66 =1.392
4- The Sun Diameter
- 1.392 mkm (The Sun Diameter) = Venus Diameter 12104 km x 115.2
- 1.392 mkm (The Sun Diameter) = Mars Diameter 6792 km x 205.2
- 1.392 mkm (The Sun Diameter) = Neptune Diameter 49528 km x 28.3

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II- Discussion
- The data groups no. (1,2 and 3) show that,
- The rate 1.392 is used frequently among planets different data.
- Why? because
- The solar system is similar to one machine of gears and each planet is one gear in
it. because the machine moves one unified motion, the gears data should be in
proportionality with one another.
- Similar to that, the planets creation and motion data be created in proportionality
with one another. we will prove that in details in thus paper discussion.
- Based on this vision the solar planets data be created depends on one geometrical
design.
- The Sun Diameter Be defined geometrically before the sun creation.
- Because
- The machine depends on one geometrical design and each part should be created
in harmony with this geometrical design otherwise the machine can't work.
- We should notice that, the rate 1.392 is defined with the solar system creation
geometrically, Before the sun creation and also before the planets migration.
- This definition is done geometrically, so, the value (1.392) in the data is very
ancient. But the sun diameter (1.392 mkm) be created later.
- Let's discuss the data no. (4)

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Group Data No. (4)
- The sun diameter 1.392 mkm = Venus diameter 12104 km x 115.2 = Mars
diameter 6792 km x 205.2, But
- 25.2 + 90 = 115.2 and 115.2 +90 =205.2 where (25.2 degrees = Mars Axial Tilt)
And
- The sun diameter 1.392 mkm = Neptune diameter 49528 km x 28.3
- And 28.3 degrees = Neptune Axial Tilt
Discussion
- The data shows that, Venus, Mars and Neptune diameters are rated with the sun
diameter based on Mars axial tilt and Neptune axial tilt, Means,
- We have 3 planets diameters are rated with 2 planets axial tilts based on the sun
diameter.
- More logical that, the sun diameter is created after the 3 planets diameters,
depending on their values, causing planets axial tilts be created in proportionality.
- The opposite choice can't be working. Because if the sun be created at first and all
planets later, that creates a rule for the sun effect on the planets axial tilts, by that
we have to find (not) 3 planets only their axial tilts be rated based on the sun
diameter proportionality with their diameters, but found all planets behave by this
same rule because the sun has equal effect on all of them.
- The first option is more logical, that the sun is created after the planets creation and
the sun depended on 3 planets (specifically) for its diameter creation. by that the
data be more understandable
- Shortly
- The sun diameter analysis gives support for the claim (the sun is created after all
planets creation and motion).
Notice (1)
- In kepler third law in which (D3
= P2
x constant), the constant used for the solar
planets orbital distance and periods should be = 25

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10-4 The Sun Rays Analysis
- Let's Summarize The Sun Rays Creation Idea In Following:
(Point No. A)
o The Solar Planets Move One Unified General Motion. This Idea we discuss
and prove clearly in this paper.
o The planets unified general motion causes to unify the planets velocities in
one unifies velocity = the planets velocities total.
o The 9 planets velocities total =176 km/sec,
o But
o The Earth moon is a player and its velocity should be added, where the
moon velocity be considered = Earth velocity because they aren't separated
from one another through their motions.
o The 10 planets velocities total be 176 +29.8 =205.8 km/s
o Based on this velocity (205.8 km/s) the sun rays be created
(Point No. B)
o 10921 km (The Moon Circumference) x 86400 Seconds = 940 mkm
o This Equation tells. If Earth revolves around the sun a complete revolution
(=940 mkm = Earth Orbital Circumference) in one solar day only (86400
sec), in this case, the moon circumference (10921 km) will be equal the
Earth motion distance during 1 second.
o But, because
o Earth revolves around the sun in one year (=365.25 days), so this equation
may refer to a rate of time is used by The Sun herself.
o Let's use this idea as a hypothesis. where
o 1 Day Of The Sun Motion = 365.25 Days Of Earth Motion
o We suppose that's The Sun Rate Of Time

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(Point No. C)
o The velocity (205.8 km/s) passes during a solar day (86400 s) a distance
=17.75 mkm
o 1 day of Earth motion = 237 seconds of the sun motion.
(This value depends on our hypothesis)
o Now
o The distance =17.75 mkm and the time =237 seconds what's the velocity?
o 75000 km/s = (a quarter Light Velocity) = 0.25 C
o But
o Earth has a cycle of 4 years (1461 days = 365 +365 +365 +366)
o Based on one year, the velocity be (0.25 C)
o And
o Based on the cycle (4 years), the velocity (0.25C) became (C light velocity)
o Based on this explanation the sun rays be created.
(Point No. D)
o There's one more method to create the sun rays
o 0.25 C x 4 C = C2
o Where
o The velocity 0.25 C is produced already in the previous discussion
o We need only the value (4C) to perform this equation
o Jupiter motion enjoys by light motion supposed velocity (1.16 mkm/s) this
value is very near to our required value (4C)
o Light supposed velocity travels for 1 second and passed 1.16 mkm
o And
o Earth rotates around its axis one per solar day and move a distance = its
circumference =40080 km in a solar day
o If 1 solar day of Earth motion be = 1 second of light supposed velocity
motion.

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o Based on that, the distances can be added
o 1.16 mkm + 40080 km = 1.2 million km = 4C
o By that the equation works
o 0.25 C x 4 C = C2
o That explains why, Jupiter and The Moon data are the 2 basic players in the
sun data definition. Because the sun creation depends on Earth and Jupiter
motion. in addition to Uranus motion which is seen in the Earth moon
motion.
o The data explains how the sun rays be created
(Point No. E)
o The rate of time (1 solar day of planet motion = 1 second of light motion) is
the original rate of time in the solar system. We should refer to that in the
planets unified general motion discussion.
o The idea is that, the light motion for 1 second provides the required energy
for a planet to move one solar day, because the light motion depends on the
solar day as we have discussed. By that the planets divides this great rate of
time (1 sec = 86400 sec) on their motions to work as a great clock and
produce this rate by their Unified General Motion.
o The basic part (1 sec =365.25 sec) be between the Earth and the Sun motion.
(Point No. F)
o Because the solar system be created out of a light beam its velocity 1.16
mkm/sec
o And the sun light velocity 0.3 mkm/sec
o That proves the light (0.3 mkm/sec)be created as a product from the original
one 1.16 mkm/sec
o And that proves
o The sun is created after all solar planets creation and motion.

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Extensive Discussion
- Why Does The Previous Investigation Prove The Claim?
- The claim tells that,
- The Sun Is The Solar System Last Created Piece. And that means, the sun is
created after All Planets Creation And Motion.
- If this fact can be proved, it will disprove Newton Theory of The Sun Mass
Gravity decisively.
- How to prove that the sun is created after all planets creation and motion?
- In addition to the historical proves there's one basic proof which is
- The sun rays velocity be = 300000 km
- While
- The solar planets matters and distances be created out of light beam its velocity
=1.16 mkm/sec.
- As a result, I have analyzed the planets data to prove that, this data be created
based on a light beam its velocity =1.16 mkm/sec
- After this analysis, we have to describe how the sun rays be created and the
previous data provides this description.
- Now
- Why Does This Analysis Provide A Sufficient Proof?
- The proof sufficiency depends on the arguments and discussions logic
- The discussions used hundreds of the planets data and put them in some form to
prove some idea. I can create the idea but can't create the data. that means if the
data be in harmony with the idea that supports the proof sufficiency.
- We have used hundreds of data in different discussion, if the discussion logic be
straight and the data be in harmony with it that proves the claim clearly
- The point is that, we searched for the rules based on which this data be created. so
as much as the used data be in harmony with these rules that prove these rules
sufficiency.

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- For example
- I claim (1 day of the sun motion = 1 year of Earth motion). this idea we have
accepted as a hypothesis and used it based on that
- But
- This idea is created because of the moon circumference equation (10921 km x
86400 seconds =940 mkm). Means, we have some data refer to this hypothesis.
- So we have used this idea as a hypothesis.
- We have found that, the data be in harmony and produce a velocity = (0.25 C)
- This velocity be created as a result for the hypothesis we suggested because of the
moon circumference
- But
- Earth Cycle (4 years) can change this velocity (0.25C) into ( 300000 km/s)
- I try to show that, w don't create the data
- We Rearrange The Data In New Positions Relative To One Another
- This is the basic method of the proof.
- Then we find that
- Jupiter (again) provides us a chance to create the value (C2
) (which can be a
source of the sun rays energy)
- So we used the velocity 1.16 mkm/s which we have learnt from Jupiter motion
data and added it to earth circumference to produce the required value (4C)
Notice
The planets unified general motion supports the proof with powerful arguments which
makes the proof more understandable and trustee.

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Paper Part No. (II)
The Solar System Creation Theory

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11- The Solar System Creation Theory
11-1 Preface
11-2 The Solar System Creation Theory
11-3 The Inner Planets Motions Reason
11-4 Light Beam (1.16 mkm/sec) Proves Discussion
11-5 Saturn Motion More Analysis
11-6 Equal Distances Method

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11-1 Preface
- There's a light beam its velocity =1.16 million km per second
- The solar planets matters and distances are created of Energy provided by this light
beam whose velocity (1.16 mkm/sec) (The Theory hypothesis)
- Shortly
- The solar planets are created and moving based on one light beam its velocity is
1.16 million km per second
- Means,
- The light beam whose velocity 1.16 mkm/sec is The Real Motor found behind the
solar planets motions.
- In following I provide my theory for the solar system creation and motion. and I
provide many explanations for this theory
- But
- The theory is NOT the objective of this point discussion –
- We discuss this point to prove that (a light beam its velvety 1.16 mkm/sec be
found in the solar system motion and caused its creation)
- This point discussion interests basically for the light beam its velocity =1.16
mkm/sec
- I want to say
- Through the paper discussions I have provided data disproved Newton theory and
created astonishments and surprises for the respectful readers because they show
un-expectable using of data –
- Through the whole paper discussions, we have moved from planet data to another
trying to understand how this data be created – and left hundreds of questions
behind because no answers we could reach for our questions…
- Then

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- The light beam velocity 1.16 mkm/sec be supposed and then hundreds of data be
understandable –
- A great light came through our cave darkness and then we have one chance to
leave it ….
- A light beam its velocity 1.16 mkm/sec is found under the solar planets matters
and distances creation – this light beam is the responsible for the planets motions
and the distances creation and distribution – it's the main force behind and controls
every thing and saves the solar group
- I want to say
- I provide a good theory about the solar system creation and good explanations for
different features of planets motions- but –this is a cover –
- I make a cover for the existence proves discussion of the light beam velocity (1.16
mkm/sec).
- So,
- We keep our eyes on the data discussions because we –here – reread the same data
once again and will discover that the planets motions data be created as a result of
the light supposed velocity (1.16 mkm/sec) effect on these planets motions.

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11-2 The Solar System Creation Theory
(I)
- Matter is Created out of light beam, and the born matter isn't separated from its
light parent but moves with it one unified motion by using different rates of time
between the matter and light.
- The matter is created of energy and the space is created of energy and by that, the
matter is created in motion.
(II)
- The solar planets and their distances are created from one light beam its velocity
=1.16 mkm/sec (The Theory Hypothesis)
- The energy of the light supposed velocity (1.16 mkm/sec) be used for the solar
system creation and by that this light beam motion features be registered in the
planets matters and their distances.
- The planets move in comparison with their parent light beam in one unified
general motion. by using different rates of time
- The basic rate of time is (1 Second Of Light Motion = 1 Day Of Planet Motion)
- Or
- (Energy of light motion for 1 second be used to move a planet for 1 solar day)
- This great rate be divided among the planets motions (as we have discussed in
planets motions use different rates of time – Point no.6 )
(III)
- Based on this vision
- The Solar System Be Similar To A Great Clock.
- The Clock input is an energy of light motion for 1 second and the clock output is
an energy enough for a planet motion for 1 solar day –
- The rates of time be used by the planets to create One Unified General Rate Of
Time.

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(IV)
- The solar planets be similar to points on the same one trajectory of energy – or
they are knots on the same rope –
- Also
- The solar planets be similar to gears in one machine of gears – or the planets be
similar to puppets on a puppets theater –
- The rope can show the best similarity for the solar planets – the matter and apace
be created of light beam energy – and by that – the light creates planet matter and
its distance by light energy – by that – light created planet matter and its distance
to be in proportionality with other planets data because all of them be created out
of the same one energy.
- The creation process of planet matter and distance isn't discovered yet but the light
motion supposed velocity (1.16 mkm/sec) be registered in the planets motions data
and by that we discovered that these planets be created by this light beam energy.
(V)
- Because all planets be created of one light beam, the planets move with this light
beam and by that we conclude simply a light beam motion be in accompanying
with planets motions –
- Light motion be accompanying with one motion– because of that
- The solar planets motions be integrated into One Unified General Motion.
- The solar planets move one unified general motion – This motion be similar to
Train Carriages Motion – they all move together one unified general motion– spite
the planets velocities are different from one another – but as a machine of Gears –
the gears move by different velocities but create one unified general motion.
(VI)
- A river water motion can be very good example for our explanation ….

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- Imagine 9 waterwheels be built on one canal, so the 9 waterwheels rotate because
of the water motion (the water motion here is similar to the light motion and the
waterwheels are similar to the planets)
- This example is a great help for our explanation – the water motion direction is
different from the waterwheels rotation direction but no waterwheel can rotate
without water motion – also – the waterwheel motions effect one another because
they effect on the water amount for one another – that perfectly shows how the
solar system works
(VII)
- Now we have one more great help,
- The solar planets move One Unified General Motion because the light beam deal
with the unified motion of the planets
- The planets unified motion forces each planet to move a complementary motion
which can be integrated with one another to create the planets unified general
motion.
- Now each planet motion became (some how) obligatory motion because it should
be integrated with other planets motions to create the unified general motion.
- By that the planets motions be obligatory motions
- Planet data should be in harmony with this planet motion –the motion is obligatory
to be complementary with other planets motions – based on that – the planets
motions data should be complementary data with one another.
- Based on this vision
- There's one law controls all planets motions data –that because – the data should
be created in harmony with their motions and the motions must be complementary
to create one unified general motion.
- By that, the light beam motion controls the solar planets motions and their data –
shortly we have One Law controls all data.

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(VIII)
- Light supposed velocity (1.16mkm/sec) starts its journey from Mercury to Jupiter
directly and then Jupiter Energy is sent to Pluto directly (1st
trajectory)
- There's one more trajectory of light supposed velocity (1.16 mkm/s) motion starts
from Mercury also to Pluto directly – light supposed velocity by this motion
caused to create Mercury Day period (4222.6 h) – as we will discus that deeply
later -
- These 2 trajectories are light motions, but
- We analyze in comparison Mercury Motion following the light motion, and also
we analyze Saturn motion in parallel.
(IX)
- Jupiter motion distance during Mars rotation period (24.6 hours) be = 1.16 mkm
and this is the reason of the important of Jupiter motion and Mars rotation period –
light supposed velocity moves for 1 second a distance = 1.16 mkm and that creates
the comparison of data with Jupiter motion.
(X)
- Light known velocity (0.3 mkm/sec) is found in the solar system and behaves as
the light supposed velocity effects on the planets motions data.
- But
- Light known velocity (0.3mkm/sec) is almost created later – because the sun is
created after all planets motions –and by that – the light known velocity (0.3
mkm/sec) be created almost as a side product from the original one the light
supposed velocity (1.16mkm/sec)
(XI)
- Spite the previous ideas – Jupiter motion data shows light supposed velocity (1.16
mkm/sec) effects more greatly than any other planet. This fact isn't solved yet –
Jupiter (all) distances be created based on the light supposed velocity (1.16

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mkm/sec) – and this feature isn't seen in any other planet – nor even Mercury –
let's provide Jupiter list here before out discussion to be a reference
- (1.16 mkm/sec) x 671 seconds = 778.6 mkm (Jupiter Orbital Distance)
- (1.16 mkm/sec) x 629 seconds = 720.7 mkm (Jupiter Mercury Distance)
- (1.16 mkm/sec) x 580 seconds = 671 mkm (Jupiter Venus Distance)
- (1.16 mkm/sec) x 500 seconds = 580 mkm
- (1.16 mkm/sec) x 542 seconds = 629 mkm (Jupiter Earth Distance)
- (1.16 mkm/sec) x 940 seconds = 2 x 550.7 mkm (Jupiter Mars Distance) (1%)
- (1.16 mkm/sec)2
x 2 x 778.6 seconds = 2094 mkm (Jupiter Uranus Distance)
- (1.16 mkm/sec) x 3717 seconds = 4331 mkm
- (1.16 mkm/sec) x 5127 seconds = 5906 mkm (error 0.7%)
- (1.16 mkm/sec) x 2644.5 mkm = 3033.5 mkm (Uranus Pluto Distance)
(error 1%)
- Where
- 940 mkm = Earth orbital circumference
- 3717 mkm = Jupiter Neptune Distance
- 2644 mkm = Mars Uranus Distance
- The distances be used as periods of time to pass other distances – by this system
the distances be created in a network form -
- The distances rate is (1 mkm = 1 second) (this rate is used for light motion)
- And
- (1 mkm =1 solar day) this rate is the rate used by planets motions.
- Some very strange notice that Jupiter all distanced depend on (1.16 mkm/s)we
should analyze that as possible in this point discussion

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11-3 The Inner Planets Motions Reason
I- Data
(11-3-a)
Earth Mass = The Masses total of (Mercury + Venus + Mars)
(11-3-b)
Earth Circumference = The 5 inner planets diameters total
(Means the diameters total of (Mercury + Venus + The Moon + Earth + Mars))
(11-3-c)
2 x Earth Circumferences = 2 Mars Circumferences + Venus Circumference
(11-3-d)
Earth Circumference = The moon freedom space of motion
II- Discussion
- The double production experiment tells us
- From Gamma ray one electron and one positron can be created, 2 particles equal in
mass and opposite in charge.
- Equation no. (11-3-a) tells, Earth Mass = The 3 Inner Planets Masses Total (error
1%)
- Can we imagine that, a great gamma ray be used to create the inner planets.
- Earth is (The Great Electron) (means, Earth atom has a positive nucleus and
negative charges revolve around)
- The 3 Inner Planets Consist Together (The Great Positron) (means, the inner
planets Mercury – Venus – Mars, Their atoms have negative nucleus and
positive charges move around)
- If these hypotheses be working, the inner planets can create One Electric Field to
cause their motions around the sun.
- The error (1%) refers to a part of mass be consumed to create the required energy
for these planets motions through their orbits.

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- By that the error (1%) is found for a physical necessity and not be found as an
error in measurements.
- The previous description provides a suitable base to create an eclectic field
- The electric field is better for the planets motions than the sun gravity force.
- Newton has no one proof for the sun mass gravity force but the electric field
theory depends on the masses equality fact.
- The next discussion can support the electric field theory.
Earth Circumference = The 5 inner planets diameters total
(Means the diameters total of (Mercury + Venus + The Moon + Earth + Mars))
2 x Earth Circumferences = 2 Mars Circumferences + Venus Circumference
- For what we search? For Electric Charges
- If we can prove that, some electric charge be found in the inner planets. That can
support this idea greatly
- Why these 2 equations refer to charges in the inner planets data?
- Because of Gauss Law!
- Gauss law tells, The Charges Be On The Outer Surface, that means, the outer
surface can be effected Geometrically by electric charges. Because more wide
outer surface receives more charges. That tells The Charge Electric Field Effect on
the matter dimensions must be A Geometrical Effect
- I want to say
- If some planet be charged its outer surface formation and dimensions should be
effected Geometrically because of the electric charge.
- Means, the geometrical effects should be used as a proof for charges existence.

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- The previous 2 equations no. (b and c) can support this idea because the inner
planets circumferences and diameters be created in proportionality which can refer
to geometrical effects be produced by electric charges on their creation.
Earth Circumference = The moon freedom space of motion
- The moon orbital Perigee radius =363000 km
- The moon orbital apogee radius =406000 km
- The difference 43000 km
- But the space without the moon diameter =43000 km- 3475 km = 39500km= Earth
Circumference (error 1.3%)
- This data is used for the same argument, A geometrical effect be found on the
surface distances which can be used as a reference for an electric field effects on
the matter dimensions
- Notice
- 43000 km (the distance from perigee to apogee) x 3475 km (the moon diameter)
=149.6 mkm (Earth Orbital Distance). I try to show that, geometrical features are
found behind the dimensions and distances definition in the inner planets. And
these geometrical features supports the electric field effect claim.
- Notice
- If the planets move as chess board pieces - The electric field is the best method
can provide this type of motion (Chess Board Motion)
- That supports the claim, (The Inner Planets Motions Depend On Electric Field)

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A Comment
- The inner planets electric field idea tries to create a physical machine causes the
planets motions.
- I want to say,
- The solar system creation theory supposes that the light motions causes the solar
planets motions- and the data supports this description but
- We have no a real machine causes planets motions depend on light motion.
- For that
- I provide this idea as an example of such machine
- I don't confirm that, the inner planets motions depend on electric field – but I prove
an example of planets motions be caused by light motion- if this is the method
used by the inner planets so the theory is correct otherwise this example works as
an example for similar machines may work by more correct ideas than this –
- Shortly
- The machine aims to use light motion to cause planet motion.

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11-4 Light Beam (1.16 mkm/sec) Proves Discussion
I - Data
(11-4-a)
1.16 mkm/s x 86400 s = 100733 mkm
And
0.3 mkm/s x 86400 s = 25920 mkm
(11-4-b)
1.16 mkm/s x 500 s = 580 mkm
1.16 mkm/s x 580 s = 671 mkm (Venus Jupiter Distance)
1.16 mkm/s x 671 s = 778.6 mkm (Jupiter Orbital Distance)
1.16 mkm/s x 629 s = 720.7 mkm (error 1%) (Mercury Jupiter Distance)
1.16 mkm/s x 5127 s = 5906 mkm (error 0.7%) (Pluto Orbital Distance)
(11-4-c)
1.16 mkm/s x 4224 seconds = 4900 mkm
(11-4-d)
1.16 mkm per second x 2 x 86400 seconds =2 x 100733 mkm = (37100 mkm – 4900
mkm) x 2π = 28255 mkm + 2 x 86400 mkm
(11-4-e)
1.16 mkm/s x 5040 seconds = 5848 mkm (Mercury Pluto Distance)
And
5848 mkm (Mercury Pluto Distance) – 4900 mkm = 948 mkm
(11-4-f)
1.16 mkm/s x 4900 seconds = 5678.1 mkm (Mars Pluto Distance)
And
1.16 mkm/s x 5687.1 seconds = 6585.4 mkm
(11-4-g)
193 seconds x 0.3mkm/sec = 57.9 mkm (Mercury Orbital Distance)
196.5 seconds x 1.16 mkm/sec = 227.9 mkm (Mars Orbital Distance)
(11-4-h)
5040 sec = 88 sec x 57.27 (this data answers why Mercury day = double its period)

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II- Discussion
1.16 mkm/s x 86400 s = 100733 mkm
And
0.3 mkm/s x 86400 s = 25920 mkm
- Light known velocity (0.3 mkm/s) travels during a solar day (86400 s) a distance =
25920 mkm.
- Because it's a light motion we see this value (25920 mkm) as a period of time
(25920 years = the Precession Cycle)
- Also
- The distance 25920 mkm be = The Planets Motions Distances Total During A
Period =1461 days (where 1461 days =365 +365 +365 +366)
- Because the period 1461 days is (Earth Cycle) we consider that the distance 25920
mkm be mentioned by planets motions total
- Notice, the distances total added the Earth moon motion distance to the 9 planets
motions distance to create the total per a solar day (17.75 mkm) where the moon
motion daily distance be considered = Earth motion daily distance because they
aren't separated from one another through their motions.
- The light supposed velocity (1.16 mkm/s) travels during a solar day (86400 s) a
distance = 100733 mkm = The 9 Planets Orbital Circumferences Total
- Equation no. (11-4-a) tries to prove, Light Motion Uses The Solar Day Period
As Its Basic Period Of Motion.
- Light known velocity and light supposed velocity both use the solar day as the
basic period of time. Because of that, both light beams passes essential distances in
the solar system geometry.
- The next discussions will prove that these distances (25920 mkm and 100733
mkm) are essential distances in the solar system geometry.

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- Notice
- The rule tells
- (Light Motion For 1 Second = Planet Motion For 1 Solar Day)
- This rule which is a supposed one and we should prove it through the paper
discussions…
- This rule tells that,
- The light motion depends on the solar day as a period of time as similar to its
dependency on the second as a period of time.
- That means,
- These 2 periods of time (the second and the solar day) are the 2 basic columns for
light and planet motions accompaniment.
- And by that, light motion doesn't use the solar day as similar to any other planet
day period. On the contrary, the solar day is the basic period of time for light
motion (For both velocities, the known and supposed).

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1.16 mkm/s x 500 s = 580 mkm
1.16 mkm/s x 580 s = 671 mkm (Venus Jupiter Distance)
1.16 mkm/s x 671 s = 778.6 mkm (Jupiter Orbital Distance)
1.16 mkm/s x 629 s = 720.7 mkm (error 1%) (Mercury Jupiter Distance)
1.16 mkm/s x 5127 s = 5906 mkm (error 0.7%) (Pluto Orbital Distance)
- The data is apart of Jupiter series we have seen, and the data shows specific feature
which is:
- The light supposed velocity (1.16 mkm/s) uses the distances values as a periods of
time by the rate (1 mkm = 1 second).
- Based on that, the distances be created depends on one another and no distance be
created independent from the other distances. means, the distances be created in a
network form of distances and not as independent distances from one another.
- The data shows how the solar system distances be created in a network form
- In details
- Light supposed velocity (1.16 mkm/s) uses the period (500 sec) to pass a distance
580 mkm, and
- Light supposed velocity (1.16 mkm/s) uses the distance (580 mkm) as a period of
time (580 sec) to pass a distance 671 mkm (= Venus Jupiter Distance), and
time (671 sec) to pass a distance 778.6 mkm (=Jupiter Orbital Distance), and
time (629 sec) to pass a distance 720.7 mkm (=Jupiter Mercury Distance), …etc
- We have discussed this data before but now we have another reading for this same
data
- Notice (The Distances Network Theory Be Discussed In Point No.12)

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The Motion 1st
Trajectory
- The Trajectory Summary
- Light supposed velocity (1.16 mkm/s) travels starting from Mercury to Jupiter,
creating Jupiter orbital circumference
- And, then
- Light supposed velocity (1.16 mkm/s) travels from Jupiter to Pluto (Directly) and
doesn't touch any other planet in the way.
- The motion trajectory is built on 2 basic equations and many other additional data.
because
- Mercury Motion uses light supposed velocity (1.16 mkm/s) because of that,
different data of Mercury motion be created based on this light supposed velocity
(1.16 mkm/s) energy
- Shortly
The motion 1st
trajectory is defined based on Equation no. (11-4-c) and (11-4-d) as
basic equations. And through discussion many other data be added
Notice
Equation no. (11-4-d) is the solar system geometry main equation and it's the paper
main one we discuss it along the paper,

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1.16 mkm/s x 4224 seconds = 4900 mkm
- Where
- Equation no. (11-4-c) tells, the light supposed velocity (1.16 mkm/s) travels during
4224 seconds a distance = 4900 mkm = Jupiter Orbital Circumference.
- Now, let's suppose 1 second of light motion = 1 hour of Mercury Motion
- based on that, 4224 seconds be equivalent to 4224 hours (but 4222.6 hours =
Mercury Day Period).
- Equation no. (11-4-c) provides 3 branches of data! let's summarize them:
- (1st
Branch) Light supposed velocity (1.16 mkm/s) moves in (4224 s) a distance
=4900 mkm but Mercury moves during (4222.6 h) a distance = 720.7 mkm
(=Mercury Jupiter Distance) and we suppose that 1 second of light motion = 1
hour of Mercury Motion. Because of that we need to find some connection
between 4900 mkm and 720.7 mkm to create a comparison between light motion
and planet motion.
- The comparison is complex because, I suppose the rate (2π) distinguish between
light and planet motions. By that, if light moves 4900 mkm, a planet motion
should be 778.6 mkm but Mercury motion distance only be 720.7 mkm, where,
- 778.6 mkm (Jupiter orbital distance) =1.0725 x 720.7 mkm (Mercury Jupiter
Distance)
- The rate (1.0725) creates a negative effect on the rule of the value (2π). although
the rate (1.0725) be used between 40% of all distances in the solar system. But
because it be found here creates more complexity for the discussion and causes
some negative effect for the comparison between light and planet motions. because
always in other data we have found that the value (2π) distinguish clearly between
light and planet motions but in our equation the rate (1.0725) causes some
difficulty for this comparison vision.

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- (2nd
Branch) Mercury Day Period Creation.
- We have supposed that, 1 second of light motion be equivalent to 1 hour of
Mercury Motion. that means the period (4224 s ) be equivalent to (4224 h) and
Mercury Day Period = (4222.6 hours).
- This supposition suggests that, Light supposed velocity (1.16 mkm/) motion causes
to create Mercury Day Period be (= 4222.6 hours).
- The data is accurate and clear
- NOW
- The data tells that…
- Mercury is the source of the light supposed velocity (1.16 mkm/s)
- The light supposed velocity (1.16 mkm/s) started from Mercury and sent to Jupiter,
creating the distance (4900 mkm = Jupiter Orbital Circumference).
- This motion depends on Mercury Day Period.
- As a result, Mercury Day Period (422.6h) be defined by light supposed velocity
(1.16 mkm/s) motion effect on Mercury Motion.
- i.e.
- Mercury Day Period = 4222.6 hours And
- 4900 mkm= 1.16 mkm/s x 4224 seconds
- We suppose that, 1 hour of Mercury Motion = 1 second of light motion… means
- The difference (4224 -4222.6 = 1.4) is created by the light supposed velocity (1.16
mkm/s) motion effect. that means,
- The light motion effected on Mercury Motion and caused Mercury day period to
be 4222.6 hours and less than 4224 hours with 1.4 hour = 5040 seconds
- Why??
- Because
- Light supposed velocity (1.16 mkm/s) travels during (5040 s) a distance =5848
mkm = Mercury Pluto Distance

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- The light supposed velocity (1.16 mkm/s) created a connection between Mercury
and Pluto motions by creating the period 5040 seconds as a difference between
Mercury Day period (4222.6 h) and 176 solar days (=4224 hours).
- We can't discover the geometrical machine behind this data. But the data clearly
shows that, the light supposed velocity (1.16 mkm/s) travels during 5040 seconds a
distance = 5848 mkm.
- We have 3 information we got based on this analysis which are:
- (1st
) Mercury Is The Origin Point Of The Light Supposed Velocity (1.16 mkm/s)
- (2nd
) light supposed velocity (1.16 mkm/s) motion created Jupiter orbital
circumference 4900 mkm.
- (3rd
) Mercury Day Period be (4222.6 h) and less than (4224 h) with (5040 s)
because of light supposed velocity (1.16 mkm/s) effect on Mercury motion, to
create a connection between Mercury and Pluto motions.
- A Question
- The accompaniment of The Light supposed velocity and Mercury Motions caused
Mercury day Period to be (4222.6 hours)
- Is There any Proof for this conclusion? Let's see it in following …

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Mercury Motion Data
- 5040 seconds = 84 minutes
- Mercury (4.095 mkm/ daily) moves during 84 solar days a distance = 344 mkm
- And
- Mercury (4.095 mkm/ daily) moves during 346.6 solar days a distance = 1419.5 mkm
- And
- Mercury (4.095 mkm/ daily) moves during 1419.5 solar days a distance = 5813 mkm
- (the difference between 5813 mkm and 5848 mkm is 0.6%)
- The mechanisms is complex, but the data shows Mercury motion follows light
motion. Also Mercury uses light motion strategy. By that it moves a distance and
use it as a period of time to pass another distance. Nothing is clear in this process –
but we have 2 things (the period 5040 seconds which is related to Mercury day
period and the distance 5848 mkm = Mercury Pluto Distance) these 2 values are
used by light supposed velocity motion now be used by Mercury Motion.
- For that reason I suppose Mercury follows light motion
- PLEASE NOTE
- Based on what this paper discussions be created?
- I Depend On The Planets Data Arrangement
- This is the main force behind the paper arguments. For example, I claim there's a
light beam its velocity =1.16 mkm/sec, I have no empirical proves for this light
beam existence –so – based on what – such heavy claim can be raised? Based on
the planets motions data arrangement and order -
- We have seen that all Jupiter distances be rated with (1.16 mkm/sec), So the
hypothesis tells (A light beam its velocity 1.16 mkm/sec be found in the solar
system) is an intelligent answer for all Jupiter distances –
- And here, we have many data of Mercury Motions be arranged logically based on
the velocity (1.16 mkm/sec). By arrangement all this data beside each other we
catch one clear idea about how the solar system works

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The Conclusions
- The data tells,
- Mercury is the origin point of the light supposed velocity (1.16 mkm/s) motion.
that means, the light starts its motion from Mercury point. (A Conclusion No. 1)
- The light supposed velocity (1.16 mkm/s) passes the distance (4900 mkm = Jupiter
orbital circumference) in a period (4224 seconds). By that the light connects
between Mercury motion and Jupiter motion. (A Conclusion No. 2)
- Mercury Day Period be less than (4224 hours) by 5040 seconds because light
supposed velocity (1.16 mkm/s) travels during 5040s a distance = (5848 mkm) =
(Mercury Pluto Distance)
- Light supposed velocity (1.16 mkm/s) uses (5040s) to pass the distance (5848
mkm) and create a connection between Mercury motion and Pluto motion. (A
Conclusion No. 3)
- Notice
- 5848 mkm (Mercury Pluto Distance) –4900 mkm (Jupiter orbital circumference) =
946.5 mkm
- Where
- 940 mkm = Earth Orbital Circumference (error 0.7%)
- The value (946.5 mkm) is very important we will discuss in 2nd
Trajectory of
motion because it's related to Saturn motion data.
- Jupiter orbital circumference be analyzed in point no. (6) to show how rich
distance it's, and here we try to see the reason behind this distance richness.

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Mercury Motion Data Analysis (Continued)
- The previous data analysis concluded that, Mercury is the source of light supposed
velocity (1.16 mkm/s).
- So, let's ask,
- Is Mercury Motion data in harmony with light supposed velocity (1.16 mkm/s)?
(I)
- Light suppose velocity (1.16 mkm/s) needs only 50 seconds to pass Mercury
orbital distance (57.9 mkm).
- Can this (50 s) be a data belonged to Mercury Motion?
- Mercury (47.4 km/s) moves during 50.3 s a distance = 2390 km (Pluto diameter)
- Mercury (47.4 km/s) moves during 50.3 m x 60 s a distance = 142984 km (Jupiter
diameter)
- Mercury Venus Distance = 50.3 mkm ( 1mkm = 1 second)
- Mercury Neptune Distance (4437 mkm) = 50.3 mkm x 88
- (Mercury Orbital Period =88 days)
- Mercury Pluto Distance (5848 mkm) = 50.3 mkm x 116.2
- (57.9 mkm Mercury orbital distance x2 = 115.8 mkm)
- The data shows that, the period 50.3 seconds is a value be used frequently by
Mercury motion data. and mercury moves during (50.3 s) a distance = Pluto
diameter and moves during (50.3 m) a distance = Jupiter diameter, showing that
the 2 planets are the same planets mentioned by the 1st
trajectory motion.
- The basic difficulty is that, the light motion creates geometrical effects which we
can't discover because we don’t know neither their rule nor their effects. We have
only some data be transported from a point to another and that creates difficulties
for the analysis process.

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(II)
- Mercury Orbital Distance =57.9 mkm
- Mercury rotation period =58.65 solar days.
- The rate (1 mkm = 1 day) be used frequently in different motions data.
- The 2 values (57.9 mkm and 58.65 mkm) have an error (1%)
- Means, the 2 values (57.9 mkm and 58.66 days) can be created by the light
supposed velocity (1.16 mkm/s) motion during 50 seconds
- I try to show that, Mercury motion different data be in proportionality with light
supposed velocity (1.16 mkm/s) motion. which proves that Mercury is the origin
point of the light supposed velocity (1.16 mkm/s) motion.
- Because not only the period (5040 mkm) can be used or the period 4222.6 h
(which us equivalent to 4224 s) but also the period (50s)
- Notice
- 153.3 hours = Pluto day period
- 151.7 hours = 0.99 x 153.3 h (Pluto day period)
- But
- 176 mkm = 1.16 mkm/s x 151.7 seconds
- Where
- Mercury Day period =175.94 solar days
(If 1 day = 1 mkm, So 175.94 days be = 175.94 mkm)

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- (3rd
Branch) Saturn Motion Effect.
- Saturn (0.838 mkm / daily) moves during = 5848 days, a distance = 4900 mkm
- This data shows Saturn motion effect on Mercury motion data
- And
- We have to discuss Saturn data in a separated point because Saturn creates one
more reading for Mercury Motion Data
- We discuss Saturn motion data in point no. (11-5)

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1.16 mkm per second x 2 x 86400 seconds =2 x 100733 mkm = (37100 mkm –
4900 mkm) x 2π = 28255 mkm + 2 x 86400 mkm = 202318 mkm (error 1%)
- Where
- 100733 mkm = The 9 Solar Planets Orbital Circumferences Total
- 28255 mkm = Neptune orbital Circumference
- Equation no. (11-4-d) is the paper basic equation. Because it explains The Basic
Energy Trajectory Through The Solar System…
- First, We remember that we have discussed this equation before but here we
discuss it through another approach which shows a different reading for the data
- Also we notice that,
- The equation uses the rate (2) because of Neptune orbital circumference. Where
the equation 3 parts can be used without the rate (2), But the last part (28255 mkm
+ 2 x 86400 mkm) needs the rate (2) because of Neptune orbital circumference
(28255 mkm). That explains why the equation uses the rate (2).
- Now let's divide the equation into 4 Parts.
(Part No. 1)
- 1.16 mkm per second x 2 x 86400 seconds = 2 x 100733 mkm
- Part no. (1) tells us a known information which is
- Light supposed velocity (1.16 mkm/s) travels during one solar day (86400s) a
distance = 100733 mkm = The 9 Solar Planets Orbital Circumferences Total
- The rate (2) is used for Neptune Orbital Circumference.
- This part of equation tells that, light motion depends on the solar day period. This
idea we have discussed in equation no. (1) of this discussion.
- Also we know that

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- Light known velocity (0.3 mkm/s) travels during (86400 s) a distance = 25920
mkm
- Where
- 25920 mkm = 17.75 mkm x 1461 days
- 17.75 mkm = the planets distances total during a solar day in addition to the Earth
moon motion distance during a solar day, and
- 1461 days = Earth Cycle (365 +365 +365 +366)
- The data tries to prove that, the light motion depends on the solar day period.
- Notice
- (25920 mkm x 2) =37100 mkm x 1.392
- Where
- The sun diameter =1.392 mkm
- The data uses the rate (2) because this rate be used in equation no. (4) which
expresses the solar system basic energy trajectory.
- That means the value (25920 mkm x 2) refers to the total energy according to light
known velocity (0.3 mkm/s) range of motion.
- The data tells the value (25920 mkm x 2) expresses really the total energy because
37100 km (Pluto orbital circumference) is the greatest orbit
- That means, when the total energy be expresses by the value (2 x 100733 mkm)
this energy be transported to the light known velocity based on the same rate
because it's one machine.
- The data proves the energy unification through the solar system spite of using 2
different velocities of light.

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(Part No. 3)
- 2 x 100733 mkm = (37100 mkm – 4900 mkm) x 2π =
- This part is very important because
- The data shows the energy motion (or light motion) started from 4900 mkm
- That means,
- To create Pluto orbital circumference 37100 mkm, the light starts from the point
4900 mkm and measures a distance = 100733 mkm by geometrical calculations.
- We have 3 points here
- The start point which is (4900 mkm =Jupiter orbital circumference)
- The direction of motion (toward Pluto)
- The measurement unit is 100733 mkm (defined by light supposed velocity motion
during a solar day)
- The data tells, Pluto orbital circumference is created depending on (4900 mkm )
Jupiter orbital circumference by using the light motion.
- We remember
- The distance 4900 mkm be passed by light supposed velocity (1.16 mkm/s)
depends on the period (4224 s) which is defined in comparison with Mercury day
Period (4222.6 hours)
- As A Result, we conclude that,
- Light supposed velocity (1.16 mkm/s) starts from Mercury to Jupiter and continues
from Jupiter to Pluto. that shows one clear trajectory of motion from Mercury to
Jupiter to Pluto.
- That means, the motion from Mercury to Jupiter considers Mercury is the head of
the inner planets and by that the connection between Mercury and Jupiter express
the connection between Jupiter and all inner planets.
- And
- The connection between Jupiter and Pluto doesn't contain any other planet. It’s one
directed motion from Jupiter to Pluto immediately

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- Shortly
- Jupiter and Pluto orbital circumferences be created by light supposed velocity
(1.16 mkm/s) motion depends on Mercury motion data by creating different steps
of motions to connect between Mercury and Pluto
- This data confirms that the distances be created based on network form and
according to one geometrical design.
Notice
- (2π) This rate distinguish between light motion and planet motion as we have
discussed before.
- The rate (2π) distinguishes here clearly between the planet and light motions.
where the difference (37100 mkm – 4900 mkm) refer to the planets motions where
the value 2 x 100733 mkm refers to the light motion and the rate (2π) distinguish
between the 2 motions.
- Venus equation which we will study with the part no. (4) of this equation uses also
the rate (2π) between the energy source and the planet received energy. we should
refer to this meaning in its discussion.
- And
- The data gives a new meaning for the rate (2π).
- It's the rate between light motion and planet motion or
- It's the rate between the giver energy motion and the receiver energy motion
- That tells Mars energy be provided by Jupiter motion and Pluto energy be
provided by Earth motion.

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(Part No. 4)
- 2 x 100733 mkm = 28255 mkm + 2 x 86400 mkm
- The total energy be reflected from Pluto to Neptune. The distances behave
perfectly as light beams.
- Neptune had seized 14% of the total energy and the rest of energy be reflected
toward the inner planets into 2 trajectories of energy each has (86400 mkm)
- We suppose that (Distance = Energy)
- The energy be sent from Neptune to Venus and Earth, let's see their equations in
following
- 2 x 86400 mkm = (28255 mkm – 680 mkm) x 2π (Venus Equation)
- Where
- 28255 mkm = Neptune Orbital Circumference
- 680 mkm = Venus Orbital Circumference
- Earth equation is perfectly similar to Venus equation where between both the error
is less than 1%
- Also we see the rate (2π) which distinguish between light and planet motion as we
have seen in our equation no. (11-4-c)
- (or it distinguish between the source of energy and the planet received energy).
- Part (4) of the equation tells that, Neptune had seized 14% of the total energy and
the rest of energy is sent to Venus and Earth into equal trajectories of energy each
has (86400 mkm).
- That means, the inner planets energy be received from Neptune. And because of
that, the inner planets distance be controlled by Neptune orbital distance (4495.1
mkm) as the data shows that clearly.
- 4495.1 mkm (Neptune orbital distance) = 78.3 mkm x 57.9 mkm
- = 108.2 mkm x 41.4 mkm
- = (149.6 mkm x 120 mkm)/4

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- Where
- 108.2 mkm = Venus Orbital Distance
- 149.6 mkm = Earth Orbital Distance 41.4 mkm = Earth Venus Distance
- 78.3 mkm = Earth Mars Distance 120 mkm = Venus Mars Distance
- Notice
- Because the distance=energy and the inner planets receive their energy by Neptune
for that reason, Neptune orbital distance control all most distances among the inner
planets.
- Now let's ask
- Why Neptune had seized 14% of the total energy but Pluto seized nothing?
- Because
- Mars Migration Theory tells us…
- Pluto was The Mercury Moon and had migrated with Mars Migration.
- Neptune, in that time, was occupied the point (5906 mkm = Pluto current orbital
distance). And
- Pluto be migrated and thrown to the end of the solar group, flying along way and
had collided with Neptune at the point (5906 mkm).
- Pluto had pushed Neptune and put it out of Pluto (influence area!), for that reason
Pluto eccentricity distance = 1410 mkm= Pluto Neptune Distance
- The collision between Pluto and Neptune produced Pluto moons and the Kuiper
belt.
- Neptune be forced to be more near to the sun with orbital distance =4495.1 mkm
and without orbit.
- Neptune be out of the distances network (the railways) generally and needed
energy to built its orbit
- That explains why Bode Law Couldn't predict Neptune orbital distance, because
it's created (additionally) on the original geometrical design to repair the planets

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migration negative effects on the solar system motion. means, it's a distance not
designed geometrically with the original design. So the equations depend on the
original design couldn't predict Neptune orbital distance.
- Mars Migration Theory Is Discussed in Point No.(9)
Notice
- 202318 mkm = (449197 km)2
- Where
- 449197 km =Jupiter Circumference
- Accurately
- (202318 mkm) / (449197 km)2
= (361/360)
- What's (361 degrees)?
- The cycle is 360 degrees but the Earth moon orbital regresses 19 degrees per year
and during 19 years moves Metonic Cycle (19 years) (=361 degrees).
- The moon orbit regression effects on many of the planets motions data and
because of that the usual rate (360) be changed into (361).

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The Motion 1st
Trajectory (A Summary)
- Mercury is the origin point of this motion trajectory
- The energy be transported from Mercury to Jupiter by the light supposed velocity
(1.16 mkm/s) motion and by this energy Jupiter orbital circumference be created
- The energy be transported from Jupiter to Pluto by the light supposed velocity
(1.16 mkm/s)
- The energy be reflected from Pluto to Neptune and
- The energy be reflected from Neptune to the inner planets
- The Motion 1st
Trajectory Shows the energy trajectory from Mercury to
Jupiter to Pluto, which creates the solar system basic energy trajectory.

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The Motion 2nd
Trajectory
- Light supposed velocity (1.16 mkm/s) travels starting from Mercury to Pluto
directly
- In this trajectory of motion the light doesn’t use a central point as did with Jupiter
orbital circumference. Instead the light travels from Mercury to Pluto directly.
- As a result, this Trajectory of motion be formed based on the following data,
- Light supposed velocity (1.16 mkm/s) travels during (5040 seconds) a distance =
(5848 mkm= Mercury Pluto Distance)
-
- This trajectory of motion we have studied deeply. Because the period (5040 s) is
distinguish Mercury day period as we have discussed.
- But this trajectory of motion still have more important data
- This trajectory of motion uses one equation only which is no. (11-4-e), let's discuss
it in following…

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5848 mkm (Mercury Pluto Distance) – 4900 mkm = 948 mkm
And
5848 mkm (Mercury Pluto Distance) =5040 seconds x 1.16mkm/sec
- Where
- 5848 mkm = Mercury Pluto Distance
- 948 mkm = Earth orbital circumference (940 mkm) error (1%)
- Equation no. (11-4-e) shows Earth orbital circumference be taken into account
with the light supposed velocity motion for the 2 distances (5848 mkm and 4900
mkm)
- But
- Why the distance (948 mkm) be important here?
- The Earth moon daily displacement (=88000 km), and if the moon passes Earth
orbital circumference by using its displacement (88000 km), the moon needs a
period =10747 days to pass a distance = (945.5 mkm)
- Where 10747 days = Saturn Orbital Period
- The important information isn't (Saturn orbital period) but its (Saturn data),
because Saturn data be used frequently in the motions trajectories data between
Mercury and Pluto, for light and planet trajectories of motions.
- i.e.
- Through different data analysis we reach to Saturn data. this time we found (10747
days = Saturn orbital period), and in previous discussion we have found 3 data be
related Saturn motion defined by the light and mercury motions by using the
period (5040 seconds) which are:
o Saturn moves during (5848 days) a distance = 4900 mkm
o Mercury moves during (5040 seconds) a distance = 2 x Saturn diameters

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o Mercury moves during 1433.5 days a distance = 5870 mkm = Pluto orbital
distance (old definition) or near to (5848 mkm = Mercury Pluto Distance)
Where (1433.5mkm = Saturn Orbital Distance)
- Why (5848 mkm) – (4900 mkm) = 948 mkm (Earth Orbital Circumference)?
(error 1%)
- It's A Geometrical Distribution For Distances,
- But not only,
- Because this distribution contains data (10747 days) be used by Saturn and the
Earth moon motions…
- This data we should discuss with Saturn motion data because Saturn motion is
related to the light known velocity (0.3mkm/s) motion.
- The period 10747 days also be used by the moon to pass a distance = the distance
be passed by light known velocity motion during a solar day.

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The Motion 3rd
Trajectory
- Light supposed velocity (1.16 mkm/s) uses 2 different trajectories of motions (no.
1 and no. 2) to pass a distance =5848 mkm (Mercury Pluto Distance)
- And these motions be done by light velocity
- The first trajectory, the light travels from Mercury to Jupiter and then to Pluto
- The second trajectory, the light travels from Mercury to Pluto Directly
- The third trajectory expresses a motion from Mercury to Pluto (5848 mkm) but by
using mercury motion (Mercury velocity per a solar day =4.095 mkm)
- We have seen this data before, let's remember them:
o Mercury moves during 84 days a distance = 344 mkm
o Mercury moves during 346.6 days a distance = 1419 mkm
o Mercury moves during 1433.5 days a distance = 5848 mkm
o Where
o 5848 mkm = (Mercury Pluto distance)
o 1433.5 mkm = Saturn orbital distance
o 346.6 days = the nodal year.
- This trajectory of motion refers (frequently) to Saturn motion data among mercury
motion data. we don't know why that's happening…
- We can conclude that, the planet (Mercury) follows the light motion but with
different rate of time.
- Because this behavior is described by the matter creation theory. Where the theory
tells, the matter is born out of light but the born matter doesn't separate from its
light parent. On the contrary, they move together in one unified motion but by
using different rates of time.
- That's happening here. Mercury moves with light suppose velocity (1.16 mkm/s)
by using a different rate of time. (Saturn motion is discussed in 11-5)

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1.16 mkm/s x 4900 seconds = 5678.1 mkm (Mars Pluto Distance)
And
- Where
- Light supposed velocity (1.16 mkm/sec) travels during 4900 seconds a distance =
5678.1 mkm (Mars Pluto Distance).
- We remember that,
- The light supposed velocity (1.16 mkm/sec) depends on the period (4224 sec) to
pass the distance 4900 mkm.
- And depends on the period (5040 second to pass) the distance 5848 mkm (Mercury
Pluto distance)
- And we have asked why light supposed velocity (1.16 mkm/sec) created 2
trajectories between Mercury and Pluto positions? Or in more clear words why
light supposed velocity creates Jupiter orbital circumference (4900 mkm)by using
(4224 seconds)?
- Equation no. (11-4-f) gives an answer.
- Because light supposed velocity creates a connection between Mars and Pluto
positions with Mercury.
- Mars migration theory tells, Pluto was the Mercury moon and Mars was the next
planet to Mercury. And the 2 planets were migrated from their original positions.
- Light supposed velocity (1.16 mkm/sec) creates a connection between Mercury
and Pluto through the period 5040 second and another connection between Pluto
and Mars through the distance (4900 mkm)

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- Notice
- Light supposed velocity (1.16 mkm/sec) travels during 5687.1 seconds a distance
= 6585.4 mkm
- By the rate (1 mkm = 1 day) this distance 6858.4 mkm be = 6858.4 solar days
- Where (Saros Cycle =6858.4 solar days)
- Please remember
- Light known velocity (0.3 mkm/sec) moves during a solar day (86400 s) a distance
=25920 mkm,
- Where we see this distance (25920 mkm) as a period of time (25920 years = The
Procession Cycle)
- I try to show that, the period of Sarod Cycle (6585.39 days) is similar to the period
(25920 years), both be created by light motion behavior, which proves it's usual a
behavior in the solar system
- But that creates one more connection between Mars motion and the Earth moon
motion because Saros is a cycle produced by the moon motion effect.

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193 seconds x 0.3 mkm/sec = 57.9 mkm (Mercury Orbital Distance)
196.5 seconds x 1.16 mkm/sec = 227.9 mkm (Mars Orbital Distance)
- Equation no.(11-4-g) tries to explain why Mercury and Mars Motions have
interaction as we have proved in Jupiter Motion Analysis
- The reason is that, the 2 planets orbital periods are defined based on equal periods
approximately (193 seconds and 196.5 seconds the difference 2%), by using the 2
light velocities
- That shows the period (193 sec or 196.5 sec) are the reason of the 2 planets
motions integration or interaction
- But
- As we have seen Jupiter motion also be integrated with Mercury and Mars motions
- Can this period (196.5 sec) effect on Jupiter motion also?
- Yes
- 8 Jupiter days = 8 x 9.9 x 3600 = 285120 seconds = π x 90756.5 seconds
- Pluto orbital period =90560 days
- 90756.5 seconds - 90560 seconds = 196.5 seconds
- Where
- Light motion uses any period (of 1 solar day) as (1 second)

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The Motion Trajectories Summary
- As we have discussed in the previous analysis,
- There are 3 motions started from Mercury moving toward Pluto, and these motions
are:
o Light supposed velocity (1.16 mkm/) motion during (5040 s) to pass (5848
mkm = Mercury Pluto Distance)
o Light motion from Mercury to Jupiter by using (4224s)
o 1.16 mkm/s x4224 seconds =4900 mkm (= Jupiter orbital circumference),
where Mercury uses Jupiter orbital circumference as its central point to
connect with Pluto.
o Mercury Motion depends on (5040) to pass in three steps toward Pluto by
the data
o 4.095 mkm x 84 days =344 mkm
o 4.095 mkm x 346.6 days =1419 mkm
o 4.095 mkm x 1433.5 days =5870 mkm (very near to 5848 mkm)
o Notice
o Light supposed velocity (1.16 mkm/s) motion depends on the rate (2π R) but
Planet motion depends on (R). So if Mercury want to connects with Jupiter,
light motion doesn't use the distance (778.6 mkm Jupiter orbital distance)
but use (4900 mkm =Jupiter orbital circumference)
o 778.6 mkm =1.0725 x 720.7 mkm (Mercury Jupiter Distance)

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5040 sec = 88 sec x 57.27
5040 seconds are required for Mercury Day Period to be 176 solar days
88 days = Mercury Orbital Period
57.27 =Mercury Rotation Period / Mars Rotation Period
Let's remember our question
Why Mercury Day Period = 2 Mercury Orbital Periods?
4331 solar days = 24.6 hours x 175.94 = 687 solar days x 2π
Where
- 4331 days = Jupiter Orbital Period, and 175.94 days = Mercury Day Period, and
- 687 days = Mars Orbital Period , and 24.6 hours = Mars Rotation Period
- Based on this data we have concluded the following rates of time
- And
- 671 hours of Mercury Motion = 687 days of Jupiter motion = 109 days of
Mars motion
- The we have discovered that,
- During 671 hours Mercury moves a distance 57.2 mkm= 2 x Mercury Orbital
Distance (error 1%)
- And
- During 687 days Jupiter moves a distance 778.6 mkm = Jupiter Orbital
Distance
1 hour of Mercury Motion = 24.6 hours of Jupiter Motion
And
1 hour of Mercury Motion = 3.9 hours of Mars Motion
And
1 hour of Mars Motion = 2π hours of Jupiter Motion

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- And
- During 109 days Mars moves a distance 227.9 mkm = Mars Orbital Distance
- The question was
- Why Mercury moves distance = (2 x Mercury Orbital Distance), But Mars And
Jupiter Move Distances Only Equal Each Planet Orbital Distance?
- Then
- We have found, 5040 s are required for Mercury day to be =176 solar days
- And
- During 5040 seconds Mercury (47.4 km/s) moves a distance = 2 x 119448 km =
Saturn diameter (= 120536 km) (error -1%)
- But
- During 5040 seconds Mars (24.1 km/s) moves a distance =121464 km = Saturn
diameter (= 120536 km) (error +1%)
- This data gives one more reference that, the (one value for Mars) produces (2
values for Mercury)!
- We have a reason to find the rate (2) in data and because Mercury day = (2)
Mercury orbital period –some interesting feeling pushed to dig under this data may
we find answer why Mercury Day Period = 2 Mercury Orbital Period
- Let's return to the equation

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(Equation no. (11-4-h) (continued)
5040 sec = 88 sec x 57.27
- Light motion for 1 second causes a planet motion for 1 solar day,
- Because of this rule we couldn't discuss this equation in Jupiter Motion analysis
- Light moves 88 seconds and caused Mercury to move 88 solar day
- That means, this equation is Mercury orbital revolution equation… because of that
the rate (57.2) be produced, where 57.9 mkm =Mercury orbital distance (error 1%)
- Let's remember this data
- Mercury rotation period 1407.6 h / Mars rotation period 24.6 h = 57.2
- And
- Mercury day period 4222.6 h / Mars rotation period 24.6 h = 171.7
- Both values (57.2 and 171.7) are Mercury distances with the same error (1%)
- (57.9 mkm= Mercury orbital distance, and 170 mkm = Mercury Mars Distance)
- How Mercury orbital period 88 days can produce Mercury day period?
- 57.2 =2 x 28.6 (Neptune axial tilt =28.3 degrees error 1%)
- It's Neptune effect on Mercury Motion
- Why Neptune?? Because
- Neptune Orbital Distance 4495.1 mkm = π x Saturn Orbital Distance 1433.5 mkm
- Notice
- Neptune orbital period 59800 days = Mercury day period 175.94 days x 339
- But
- Venus rotation period 5832.5 hours = Uranus rotation period x 339
- It's the machine by which the rate (5.1) be transported, let's remember it here
o Venus Velocity = Uranus Velocity x 5.1
o Mars Velocity = Pluto Velocity x 5.1
o The Moon Velocity = Neptune Velocity x 5.1
- The machine by which the rate (2π) be transported and used as the time rate
between Mars And Jupiter.

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- And be used again as the time rate Between Earth And Pluto Motions.
- That tells why
- Mercury moves during its rotation period a distance 243mkm (error 1%) and
- Mars moves during Venus day period a distance 243mkm (error 1%)

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-
The General Discussion
- I have tried to arrange the data in best form to show that, the data be created based
on a geometrical design for a light beam motion by which the solar planets and
their distances be created.
- The Theory hypothesis gives a chance for better explanation….
- The hypothesis tells a light beam its velocity (1.16 mkm/sec) caused the solar
system creation and motion, and by effect of the light motion the distances be
created in a network form.
- The hypothesis shows itself so complex because we need to prove (at first) that
there's a light beam its velocity =1.16 mkm/s
- By the planets motions data arrangement I have tried to show that the planets
motions data be created depends on a light beam its velocity =1.16 mkm/s and if
this light beam isn't found there's no chance to create the solar planets motions data
and their distances as their values. This discussion is done in so deep details where
Jupiter motion data and its distances with other planets, this all data will be simply
removed if there's no light beam its velocity =1.16 mkm/s.
- The data still have more support for the hypothesis but needs at first to discover
the geometrical design based on which the planets motions data be created.
- Although, this try is a strong one, but many basic questions are still left behind, we
have to face them as a part of our effort searching for the truth
- (A Question) what's the relationship between Planet motion distance and a
distance be found between 2 planets? If these 2 distances be equal why does this
give any geometrical meaning?
- For example
- Light supposed velocity (1.16 mkm/s) travels during 5040 seconds a distance =
5848 mkm = Mercury Pluto Distance
- What's the relationship between the distance be passed by light motion (5848
mkm) and Mercury Pluto Distance (5848 mkm)?

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- If these 2 distances are equal why this is important?
- My answer for this question is a simple one ( I Don't Know How The Machine
Works).
- For example
- Earth moves during a solar day (24 h) a distance = 2574720 km
- Pluto moves during its day period (153.3 h) a distance = 2593836 km
- The moon displacements total during (29.53 days) = 2598693 km
- These 3 distances are equal with max error only (1%)
- Can these equal distances effect on any planet motion data? yes
- As we discuss in (The Planets Motions Depend On Different Rates Of Time)
the three planets motion data be created in full proportionality with one another.
can this data be in proportionality because of the distances equality or the distances
equality be a result of the data proportionality, I can't give a decision.
- The fact is that, the planets data be in proportionality and the distances are equal.
- To prove this point of view let's bring the data here for better understanding…
- More Data
Group no. (1) (Pluto And Earth Rate Of Time)
- (Earth velocity / Pluto velocity) = (Pluto Day period/ earth day period) = 6.37 (0.8%)
- Pluto orbital distance 5906 mkm = Earth orbital circumference 940 mkm x 2π
- Pluto orbital period 90560 days = Earth Cycle (1461 days) x 2π3
Group no. (2) (Pluto And The moon Rate Of Time)
(1)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
(2)
Tan (12.2) x 708.7 hours = 153.3 hours
(3)
Tan (13.17) x 655.7 hours = 153.3 hours

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- Where
- 406000 km = Pluto Motion Distance during a solar day
- 88000 km = The moon displacement daily
- 708.7 hours = The Moon Day Period
- 153.3 hours = Pluto Day Period
- And
- The angle 12.2 degrees = 13.177 deg – 0.98562 deg
- 13.177 degrees = The Moon Motion Degrees Per A Solar Day
- 0.98562 degrees = The Earth Motion Degrees Per A Solar Day
- And
- 655.7 hours = The Moon Rotation Period.
- 153.3 hours = Also (153.3-) Pluto Rotation Period
- The data confirms the point of view, the equal distances effects on the planets
motion data be caused it to be in proportionality with one another. why or how?
We still search for the machine geometrical details.
- The discussion is limited and can't receives its power, as a creature crippled and
can't walk! Why? because we don't know the used geometrical rules based on
which the solar system be created and moving.
- For example
- The equal distances (as we have seen in Earth, its moon and Pluto data) is a
method used widely in the solar system. That means, all planets use this method.
All planets create equal distances with one another and based on these equal
distances the planets motions data be in proportionality with one another.
- Let's use one more example:
- Mercury moves during its rotation period (58.65 days) a distance = 243 mkm(1%)
- Mars moves during Venus day period ( 116.75 days) a distance = 243 mkm

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- These are the equal distances, where is the proportionality of data?
- (Mercury Day Period/ Venus Day Period) =(Mercury orbital period/ Mercury
rotation period)
- The data shows that, Venus Day period be created in proportionality with Mercury
cycles periods. Can that be a result for the equal distances?
- The equal distances is a method used thousands of times in the solar system, where
many planets motions distances be passed in defined periods of time be equal one
another. we don't know what effect be done from this distances equality and by
that a great part of the machine be out of our sight…
- Shortly,
- We have to depend on some conclusions (and even guess) to conclude how the
solar group be created and moving
- The other option is the imaginary ideas. As Newton idea of the sun mass gravity,
where he imagined that the sun is the planets motions reason while the fact is that
the sun is created after all planets creation and motion. and in fact the sun rays be
created by using the planets motions energies total. means, based on the planets
motions the sun be created, and that tells the planets can be found without the sun
but the sun can't be found without the planets. Newton idea is mistaken.
- Our situation is not so better. The point is that, the geometrical rules book is inside
the light nature, and we can't catch how the geometrical effects be done but we can
discover them in every where.
- Let's summarize the machine basic difficulties
o Planet moves side by side with a light motion by that the planet motion
refers to light motion features but we can't catch the velocity which creates
these features
o The equal distances method is the method caused the planets motions. this
method works geometrically.

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o That means, this method works as a waterwheel or as a lever. A tool works
by a geometrical rule and effect. But we don't understand what benefit be
produced by the equality of distances. This equality causes the planets
motions but how?
o We notice also that,
Jupiter motion depends on light supposed velocity (1.16 mkm/s) and
all distances around Jupiter be defined based on this velocity (1.16
mkm/) but
Saturn motion depends on the light (0.3 mkm/s) where different data
belong to Saturn depends on light known velocity.
The Earth moon motion be in proportionality with both light beam
velocities! The data confirms this meaning
10921 km x 27.3 days =300000 km (error 0.5%) the equation tells if
the moon rotates around its axis one time per solar day as Earth does,
the moon would pass by its circumference during 27.32 days (the
moon orbital period) a distance =300000 km = light known velocity
(0.3 mkm/s) motion distance during 1 second.
43000 km x 27.3 days =1160000 km (error 1.3%) the equation tells if
the moon is a point without circumference and moves from perigee
point to apogee point in a solar day and in the next day moves from
apogee to perigee … during the moon orbital period (27.3 days)the
moon would move a distance =1.16 mkm
Notice (43000 km = the distance between perigee and apogee points)
10921 km x 86400s =940 mkm, the equation tells if Earth revolves
around the sun a complete revolution (940 mkm) in one solar day
only (86400 s), the moon circumference (10921 km) will equal a
distance of Earth motion during 1 second period of time. (notice, the
geometrical design can create the effect without planet real motion)

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11-5 Saturn Motion More Analysis
I- Data
(11-5- a)
10747 days x 10x 24 h = 10.7 h x 2 x 120536
(11-5- b)
120536 days x 0.838 mkm /day = 100733 mkm = 1.16 mkm/sec x 86400 sec.
(11-5- c)
5848 days x 0.838 mkm /day = 4900 mkm (Jupiter orbital circumference)
(11-5- d)
929 days x 0.838 mkm /day = 778.6 mkm (Jupiter orbital distance)
(11-5- e)
1106 days x 0.838 mkm /day = 929 mkm
(11-5- f)
(2 x 120536 km)/ (2390 km) = 101 = (5848 mkm /57.9 mkm)
(11-5- g)
5848 mkm- 4900 mkm = 946.6 mkm
(11-5- i)
(300000 km/120536 km) = (24.1/9.7) = (10747/4331)
(11-5- j)
25920 mkm= 0.838 mkm/day x 30589 days = 2.4 mkm x 10747 days
(11-5- k)
(2 x 120536/24.1) = (300000 /29.8)
(11-5- l)
9.7 km/s x 30589 sec =300000 km
And
9.7 km/s x 120536 sec =1160000 km (error0.8%)
(11-5- m)
2.082 mkm x 778.6 days = 1622 mkm = 1.1318 mkm x 1433 days

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II- Discussion
Equation no. (11-5- a)
10747 days x 10x 24 h = 10.7 h x 2 x 120536
- Where
- 120536 km = Saturn Diameter
- 10.7 hours = Saturn Day period
Equation no. (11-5- b)
- Where
- 0.838 mkm/day = Saturn Velocity per a solar day
- 100733 mkm = The Solar Planets Orbital Circumferences Total
Equation no. (11-5- c)
- Where
- 5848 mkm =Mercury Pluto distance (be used as period 5848 days)
Equation no. (11-5- d)
- Where
- 929 mkm = Earth Jupiter distance when the 2 Planets be in the sun 2 sides

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Equation no. (11-5- e)
1106 days x 0.838 mkm /day = 929 mkm
- Where
- 1106 mkm = the distance Venus passes in 365.25 days
Equation no. (11-5- f)
(2 x 120536 km)/ (2390 km) = 101 = (5848 mkm /57.9 mkm)
- Where
- 2390 km = Pluto Diameter
Equation no. (11-5- g)
5848 mkm- 4900 mkm = 946.6 mkm
- Where
- 4900 mkm = Jupiter orbital circumference
Equation no. (11-5- i)
(300000 km/120536 km) = (24.1/9.7) = (10747/4331)
- Where
- 300000 km = light known velocity motion for 1 second
- 24.1 km/sec = Mars velocity
- 10747 days = Saturn orbital period
- 4331 days = Jupiter orbital period

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Equation no. (11-5- j)
25920 mkm= 0.838 mkm/day x 30589 days = 2.4 mkm x 10747 days
- Where
- 30589 days =Uranus Orbital Period
- 10747 days = Saturn orbital period
- 2.4 mkm/day = The moon Velocity per a solar day
Equation no. (11-5- k)
(2 x 120536/24.1) = (300000 /29.8)
- Where
- 24.1 km/sec = Mars velocity
- 29.8 km/sec = Earth velocity
Equation no. (11-5- l)
9.7 km/s x 30589 sec =300000 km
And
9.7 km/s x 120536 sec =1160000 km (error0.8%)
- Where
- 30589 days =Uranus Orbital Period
Equation no. (11-5- m)
2.082 mkm x 778.6 days = 1622 mkm = 1.1318 mkm x 1433 days
- Where
- 2.082 mkm/day = Mars Velocity per a solar day
- 778.6 mkm = Jupiter orbital distance (be used as a period)

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- 1.1318 mkm/day = Jupiter Velocity per a solar day
- 1433 mkm = Saturn orbital distance (be used as a period)
Equation no. (11-5- n)
Mercury moves during (5040 sec) a distance = 2 Saturn diameter (error -1%)
Mars moves during (5040 sec) a distance = Saturn diameter (error +1%)
II- Discussion (continued)
- There are 3 reasons for Saturn motion data importance which are
(I)
- Saturn diameter be used in double value, let's see that in following:
(a)
Mercury moves during (5040 sec) a distance = 2 Saturn diameter (error -1%)
Mars moves during (5040 sec) a distance = Saturn diameter (error +1%)
(b)
Pluto (4.7 km/sec) move during (51118 sec) a distance = 120536 km x2
(c)
Pluto (4.7 km/sec) move during (2 x 120536sec) a distance = 1.1318 mkm = Jupiter
motion distance per a solar day
That tells a geometrical mechanism controls Saturn motion and data
And
(2 x 120536 km)/ (2390 km) = 101 = (5848 mkm /57.9 mkm)
- Where
- 2390 km = Pluto Diameter

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(II)
Saturn motion be effective as light motion. fro example
Equation no. (11-5- b)
- Where
- 100733 mkm = The Solar Planets Orbital Circumferences Total
Equation no. (11-5- c)
- Where
- 5848 mkm =Mercury Pluto distance (be used as period 5848 days)
Equation no. (11-5- d)
- Where
Equation no. (11-5- e)
1106 days x 0.838 mkm /day = 929 mkm
- Where
- 1106 mkm = the distance Venus passes in 365.25 days
-

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- All these values are light motion values, for example
- Saturn moves during 120536 days a distance = light supposed velocity motion
distance during a solar day =100733 mkm= the 9 planets orbital circumference
total.
- That tells Saturn motion effects greatly on the solar system because the interaction
with light motion.
(III)
- Saturn data has a relationship with light motion wit both velocities (1.16 mkm/sec
and 0.3 mkm/sec). for example
- Saturn (9.7 km/sec) moves during 30589 seconds a distance 300000 km
- Also
- The moon (27.78 km/sec) moves during 10747 seconds a distance 300000 km
- And
- (300000 km / 24.1) = (120536 km/9.7)
- The relationship with light motion causes great effect of Saturn motion on the solar
system geometry –

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11-6 Equal Distances Method
- The Equal distances Method is A Feature be discovered in the solar system motion
- 2 Planets move equal distances in defined periods of time. And as a result this 2
planets data be in proportionality with one another.
- This feature be analyzed as deep as possible to know why it's used and what
geometrical effect it creates. Let's explain that by using examples in following:
Example No. (1) (Earth and Pluto Data)
(A)
- Earth moves during its day period a distance = Pluto motion distance during its day
period = the Earth moon displacements total during its day period (error 1%).
(B)
- (Earth velocity / Pluto velocity) = (Pluto Day period/ Earth day period) = 6.37 (0.8%)
(C)
- (Pluto motion distance daily406000 km/ the moon displacement daily88000 km)=4.61
- (The Moon Day Period 708.7 h / Pluto Day Period 153.3 h) = 4.61
- Tan (12.2) x 708.7 h (The Moon Day Period) = 153.3 hours (Pluto Day Period)
- Tan (13.17) x 655.7 h (The Moon rotation Period) = 153.3 hours (Pluto Day Period)
- (Where 13.17 deg = the moon daily motion degrees, and 12.2 deg =13.17 deg – 0.9856
deg Earth motion daily degrees)
- We have discussed this data before.
- The proportionality of data may be created by the equal distances of motions or by
the rate of time. Or may both be created based on each other.
- The fact is that,
- The 2 planets move equal distances in defined periods of time and their data be
created in proportionality with one another.

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- Let's analyze the previous example as possible:
o Equal Distances Be Passed By Earth And Pluto Motions,
o We should pay attention for the equal distances nature, because the distances
are equal. But these distances are not random distances. On the contrary,
these are mentioned distances because the planets pass these distances
during their days periods.
o It's necessary to put this data in front of our eyes (always). Because the
equal distances aren't any random equal distances but distances be passed
during defined periods of time and by that these distances be mentioned to
be equal.
o Defined period of time means a period be defined by a planet motion. as a
planet orbital period or day period or rotation period …etc
o Shortly a period depends on a planet motion
Example No. (2) (Mercury and Mars Data)
- Mercury moves during its rotation period a distance =243 mkm (error 1%)
- Mars moves during Venus day period a distance =243 mkm
- We have 2 equal distances! Where's the data proportionality?
- (Mercury Day Period)/ (Venus Day Period) = (Mercury Orbital Period / Mercury
Rotation Period)
- That tells, Venus day period is created as a function in Mercury cycles periods.
Can Mars motion for the distance 243 mkm be the reason of this proportionality?
Notice
243 solar days = Venus Rotation Period (if 1 mkm = 1 solar day), so this distance
(243 mkm) may refer to Venus Rotation Period
On the other side
Venus moves during (365.25 days) a distance = 1106 mkm =2π x 175.94 mkm
175.94 solar days = Mercury Day period (means, 1 mkm = 1 solar day is a rate
known by Venus and Mercury).

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The Equal Distances Using Range
- Why Do We Study The Equal Distances Method?
- Because
- This Method is almost the planets motions method. That means the solar planets
don't move by the sun mass gravity but move by the equal distances method (or at
least the outer planets move by the equal distances method).
- That means,
- The solar system motion depends on the equal distances method greatly.
- Why Do We Need to Know That? Even If Be A Fact
- Because
- This explains the heavy using of the equal distances methods in the solar system
motion. and by that we explain the following facts:
o 50% Of All Distances In The Solar System Be Equal One Another
o And
o 40% of all distances in the solar system be rated one another with the same
one rate (1.0725)
o This data be in appendix no. 1 of this paper
- Notice
- We have discussed this data before but the data of (50% of all distances are equal)
and (40% of all distances are rated) be put in the appendix no. 1 to be used as
reference

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Let's summarize the equal distances using range in following:
(1)
50% of all distances in the solar system are equal one another
and
40% all distances in the solar system are rated with the same rate (1.0725)
(2)
Planet 8 days Cycle depends on the equal distances using
We have discussed Planet 8 days Cycle in The planets Unified General Motion
(3)
Different examples we have discussed as Earth and Pluto equal distances
And also Mercury and Mars equal distances
(4)
Planet diameter or circumference using as a period of time depends on equal distances
let's provide some examples in following:
o Jupiter (13.1 km/s) moves during 10921 second a distance =142984 km =
Jupiter diameter.
o Uranus (6.8 km/s) moves during 7510 second a distance =51118 km =
Uranus diameter.
o Pluto (4.7 km/s) moves during 10921 second a distance =51118 km =
Uranus diameter.
o Pluto (4.7 km/s) moves during 51118 seconds a distance =2 x 120536 km =
Saturn Diameter.
o Pluto (4.7 km/s) moves during 2 x 120536 seconds a distance =1.1318 mkm
= Jupiter motion distance during a soar day.
o Where
o 10921 km = The Earth Moon Circumference
o 7510 km = Pluto Circumference

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The Equal Distances Using Reason
- I provide here an explanation why the equal distances method be used
- I want to say,
- This explanation (whether be correct or incorrect) can't effect on the fact that (the
Equal distances is the reason of the solar planets motions) because this fact
depends on The Equal Distances Method Wide Range Of Using.
- So, let's ask
- Why Be The Equal Distances Used As The Method Of The Planets Motions?
- Because
- This is the method be used between light motion and planet motion. and between 2
planets motions.
- That means,
- If a light beam energy be used to cause a planet motion, this energy be used
through the equal distances method
- And
- If a planet motion energy be used to cause another planet motion, this energy be
used through the equal distances method
- It's the same one method by which the motion be transported from a light beam to
a planet or from a planet to a planet. One method be used for 2 jobs
- As a result, we find distances be passed by light motion and be passed (again) by
planets motions.
- That means, because The Matter Is Created Out Of Light
- The Solar Planets motions depend on the equal distances method

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Example
- Light known velocity (0.3 mkm/s) travels during a solar day (86400 seconds) a
distance= 25920 mkm
- But
- All planets motions distances per a solar day (=17.75 mkm) x 1461 days = 25920
mkm
- If the period of time is not the cycle (1461 days), this equation would have no any
value. But because the period of time is a cycle (1461 days =365 +365 +365 +366)
defined by Earth motion. that tells the distance 25920 mkm be passed by 2 players.
(A light beam and all planets motions total).
- To prove this is a light motion. we see the value 25920 mkm as a period of time
which is (the precession cycle 25920 years)
- Also
- The moon (2.4 mkm/ daily) moves during 10747 days a distance =25920 mkm
- The data tries to show that, the equal distances be use by light and planet motions
or by planet and planet motions.
- That makes this method so useful and suitable for the solar planets motions

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12-The Solar System Distances Be Created In A Network Form
12-1 Preface
12-2 The Continuum effect Through the Solar System Distances
12-3 The Solar System Distances Distribution
12-4 The Solar System Distances Dependency On One Another

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12-1 Preface
- The Solar Planets data analysis shows that, The Planets Distances Be Created In A
Network Form.
- Means,
- The solar system distances are considered as one geometrical design or one
geometrical system. There's no one distance defined as independent distance or
created out of this one geometrical design.
- Let's suppose, this geometrical design be a square. So all dimensions in this
square be defined geometrically based on this square angles and data. means no
one dimension can be created independently from this square data because all of
them are parts in the same one geometrical design.
- Suppose we have a triangle its 2 angles are (60 degrees and 80 degrees) what's the
third one? (40 degrees). Can this angle be any thing else than (40 degrees)? NO it's
obligatory value defined by the geometrical basic rules
- Similar to that,
- The Solar System Distances Be Created Based On One Geometrical Design.
- But
- By using this vision we will have surprises. Because this vision tells (for example)
Venus Jupiter Distance be= 671 mkm Because Earth Jupiter distance = 629 mkm
- That creates another vision
- While we consider Venus is a planet and Earth is another planet and they move
independently from one another. We are astonished now with this fact that, their
distances to Jupiter be defined based on one another! How? And Why?
- How (Because The Solar System Distances Be Created In A Network Form)
- Why (this answer was discussed in Mercury Motion Analysis)
- The fact is proved strongly that
- The Solar System Distances Be Created in A Network

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- There Are Many Basic Proves For This Fact which are:
- (1) The Continuum effect Through the Solar System Distances
- (2) The Solar System Distances Distribution
- (3) The Solar System Distances Dependency On One Another
- Let's discuss these proves in their details in following
- Notice
- The idea tells that,
- By energy the distances be created in a network form
- means
- The Distances Be Similar To The Railways And The Planets Be Similar To The
Trains Move On The Railways.
- The important point is that, the distance be created by energy and because of that
it's a defined trajectory of motion. that makes the planet moves in some obligatory
motion because the energy created the distances.
- Means, the distances aren’t common space but defined distances be built for
specific reason. Based on that (Distance = Energy)
- And
- The created distance defined a trajectory of motion
- As a result
- The solar system distances be as a map created by energy

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12-2 The Continuum effect Through the Solar System Distances
Point No. (I)
The Continuum Effect Description
I- Data
(1)
50% of all distances in the solar system be equal one another
(2)
40% of all distances in the solar system be rated one another
Let's provide this data in details in following:
Data Group No. (A)
(1)
= Mercury Jupiter Distance x 2
(2)
Earth Neptune Distance = Mercury Saturn Circumference (0.5%)
(3)
Jupiter Venus Distance = Venus Orbital Circumference (1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (1.2%)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (0.8%)
(These Equal Distances Be Around 50% Of All Distances In The Solar System)

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Data Group No. (B)
Why These Distances Are NOT Equal?
10. 0725
.
1
mkm
2.41
nce
Circumfere
Orbital
Moon
mkm
2.58
Motion
Daily
Earth
=
11. 1.0725
km)
(378500
radius
Eclipse
Solar
Total
km)
(406000
radius
orbital
Apogee
=
12. 0725
.
1
distance
Mercury
Jupiter
mkm
720.3
Distance
Orbital
Juppiter
mkm
6
.
778
= (Error 0.7%)
13. 1.0725
Distance
Venus
Jupiter
mkm
670
distance
Mercury
Jupiter
mkm
720.3
=
14. 1.0725
Distance
Earth
Jupiter
mkm
629
Distance
Venus
Jupiter
mkm
670
= (0.6%)
15. 1.0725
mkm)
(1325.3
Distance
Venus
Sarurn
mkm)
(1433.5
Distance
Orbital
Saturn
= (0.8%)
16. 1.0725
mkm)
(1205.6
Distance
Mars
Sarurn
mkm)
(1284
Distance
Earth
Saturn
= (0.7%)
17. 1.0725
mkm)
(2644
Distance
Mars
Uranus
mkm)
(2872.5
Distance
Orbital
Uranus
= (0.7%)
18. 1.0725
mkm)
(4495.1
Distance
Orbital
Neptune
mkm)
(4864
= (0.5 %)
(These Rated Distances Be Around 40% Of All Distances In The Solar System)
Additional Data
(10)
0725
.
1
T.
Axail
Earth
23.4
T.
Axail
Mars
25.2
T.
Axail
Mars
25.2
T.
Axail
Satrun
26.7
Tilt
Axail
Satrun
26.7
Tilt
Axail
Neptune
28.3
=
=
=

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II- Discussion
- Let's suppose that,
- The solar planet moves independently from all other planets motions depending on
the sun mass gravity, in this case how these equal distances (50%) and the rated
distances (40%) be created?
- No logic can imagine a different reason for each 2 equal distances? We conclude
logically that (One Reason Caused These Distances To Be Equal)
- Based on that, we don't deal with independent distances instead we deal with one
machine be created by all distances integration. and As A Result, ONE REASON
effects on (the machine) caused (all distances to be effected by this one reason)
- I want to say,
- These 2 groups of data disproves Planet Motion Independency Concept.
- There's no way to create the equal and rated distances in huge percentage if the
planets motions be independent from one another.
- But
- Why These Distances Are Equal?
- The answer is somehow complex and be more clear in our discussion for the equal
distances method… but here let's provide a short answer in following:
- The solar planets don't move by the sun mass gravity. But they move by equal
distances method (or at least the outer planets move by this method)
- The equal distances method is a method be used by many planets. Let's explain
how this method be used…. 2 Planets move equal distances in defined periods of
time (as example, Earth moves during its day period a distance =2.574mkm and
Pluto moves during its day period a distance = 2.598 mkm, these 2 distances are
different with 1% only and by that they can be considered equal distances. As a
result for these 2 motions equal distances Earth and Pluto motions data be in
proportionality with one another)

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- This feature be used hundreds of time by the solar planets, I guessed that, because
this method is used hundreds or even thousands of times in the solar system, this
method causes the planets motions (but I don't know how yet). The idea is that,
this method (the equal distances) works by a geometrical rule, as a waterwheel or a
lever, these methods work by geometrical rules. Similar to that the equal distances
method caused the planets motions
- As a result for using the equal distances method, 50% of all distances in the solar
system be created equal one another and also 40% of all distances be rated with
one another by the same one rate (1.0725)
- But , Please note
- The 50% equal distances be created because the solar system uses the equal
distances method as I have explained it before.
- But
- Why Does The Rate (1.0725) effect On 40% Of All Distances?
- The rate (1.0725) effect on (40% distances) is a proof for a continuous effect
through the distances. There's Some Effect Like A Continuum effects on the
solar system distances!
- How that can be done if the planets move independently from one another? and
- If the distances be created independently from one another how one effect can be
continuous through (40%) of all distances?
- I try to prove, the distances are created in a network or by one geometrical design.
- means,
- the distances be created together in one geometrical system as one machine
because of that one effect can continue through (40%) of all distances
- the explanation of using this rate (1.0725) isn't our question…. Our basic notice is
that this effect has a continuous task through the solar system distances which
can't be done except if these distances be created based on one geometrical system
or in one Network

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- I wish the argument is powerful and proved strongly
- The data gives us a chance to show that, the planet motion can't be independent
from other planets motions. we here don't deal with independent data but with one
system of data.
- Notice
- The Continuum Effect Through The Solar System Is A Powerful Proof For The
Planets Creation And Motion Depend On A Light Beam
- Because
- The Continuous Motion And Effect Is A Feature Of Light Motion – and by
that – the solar planets can't be described as separated rigid bodies.
- Based on that,
- The solar system distances as a network should be used as a proof for the solar
planets creation out of light.

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12-3 The Solar System Distances Distribution
(1st
Point) The Idea Explanation
- There are 2 basic features we should discuss about the solar planet motion, thee 2
features are:
- (1) The Planets Motions Use Different Rates Of Time
- (2) The Planets Motions Use The Distances As Periods Of Time
- These 2 features we have discussed before in this paper discussion
- I need here just to explain how these features be used to test their effects on the
distances distribution
- There are different rates of time be used by the solar planets example:
- 1 hour of Mercury motion = 24.6 hours of Jupiter Motion
- And
- We have seen the rate (4.61) be the working rate between Pluto and the Earth
moon motions.
- Because the distances be used as periods of time and vice versa, the causes the rate
of time to be used as rates among the distances – as we have seen that the rate
(4.61) controls 50% of all distances in the solar system.
- Let's remember this rate in following
- 1 hour of Pluto motion =8.5 hours of the moon motion
- 8.5 =2 x 4.25 but (4.61 = 1.0725 x 4.25) (error 1%)
- By that the rate (4.61) be produced based on the rate of time (8.5) between Pluto
and the moon motion. and for geometrical reason this rate is the working one – for
that,
- Pluto move during a solar day 406000 km = 4.61 x (88000 km)
- (The moon displacement per a solar day =88000 km),
- and
- 708.7 hours (The Moon Day Period) = 4.61 x 153.3 hours (Pluto Day Period)

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- Now this rate (4.61) we see in Pluto and the moon motion data, but because it
works as a rate of time, it effects great on the distances distribution, let's remember
its data in following…
(2nd
Point) The Rate (4.61) Effect On The Distances Distribution
I- Data
778.6 mkm (Jupiter Orbital Distance) = 4.61 x 170 mkm
550.7mkm (Jupiter Mars Distance) = 4.61 x 119.7 mkm
2094 mkm (Jupiter Uranus Distance) = 4.61 x 2 x 227.9 mkm
2872.5 mkm (Uranus Orbital Distance) = 4.61 x 629 mkm
3033.5 mkm (Uranus Pluto Distance) =4.61 x 654.9 mkm
5127 mkm (Jupiter Pluto Distance) = 4.61 x 2 x 550.7 mkm
5906 mkm (Pluto Orbital Distance) =4.61 x 1284 mkm
1375.6 mkm (Mercury Saturn Distance) =4.61 x 2 x 149.6 mkm
3062 mkm (Saturn Neptune Distance) =4.61 x 671 mkm
4345.5 mkm (Earth Neptune Distance) =4.61 x 940 mkm
4267.2 mkm (Mars Neptune Distance) =4.61 x 929 mkm
Where
170 mkm = Mercury Mars Distance
119.7 mkm = Venus Mars Distance
227.9 mkm = Mars Orbital Distance
629 mkm = Jupiter Earth Distance
654.9 mkm = Jupiter Saturn Distance
550.7 mkm = Jupiter Mars Distance
1284 mkm = Earth Saturn Distance
149.6 mkm = Earth Orbital Distance
671 mkm = Jupiter Venus Distance
929 mkm = Earth Jupiter Distance when the 2 planets be on the sun 2 sides
940 mkm = Earth Orbital Circumference (Max error 1%)

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II- Discussion
- The solar system orbital and internal distances total be (45 distances)
- The previous data shows that (22 distances) are rated with the rate (4.61)
- Means
- 50% of all distances in the solar system be rated with one another based on this
same rate (4.61).
- The data proves the distances distribution depends on the planets motions rates
time.
- The data proves, The Solar System Distances Be Created As A Network.
- Notice
- More discussion about the planets motions rates of time we should do in the next
point (no.13)

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(3rd
Point) The Distances Distribution Proof.
I - Data
Equation no. (A)
1.16 mkm per second x (2) x 86400 seconds =(2) x 100733 mkm = (37100 mkm –
4900 mkm) x 2π = 28255 mkm + (2) x 86400 mkm
- Where
- 100733 mkm = The 9 Planets Orbital Circumferences Total
- This equation is the paper main equation and we have discussed it deeply before
(Equation no. 11-4-d)
- The equation shows that, the solar system distances be distributed based on
geometrical design.

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12-4 The Solar System Distances Dependency On One Another
I-Data
(1)
1.16 x 580 mkm = 671 mkm (Venus Jupiter Distance)
1.16 x 671 mkm = 778.6 mkm (Jupiter Orbital Distance)
1.16 x 629 mkm = 720.7 mkm (error 1%) (Mercury Jupiter Distance)
1.16 x 542 mkm = 629 mkm (Earth Jupiter Distance)
1.16 x 5127 mkm = 5906 mkm (error 0.7%) (Pluto Orbital Distance)
(2)
1.16 x 778.6 mkm x 2 = 1806 mkm
1.16 x 1806 mkm = 2094 mkm (Jupiter Uranus Distance)
1.16 x 2094 mkm = 2 x 1205 mkm (error 0.8%) (Mars Saturn Distance)
(3)
(1.16)2
x 170 mkm = 227.9 mkm (error 0.4%) (Mars Orbital Distance)
Where 170 mkm = Mercury mars Distance
(5)
1.16 x 1980 mkm = 2296.8 mkm
1.16 x 2296.8 mkm = 2644.6 mkm (error 0.7%) (Mars Uranus Distance)
1.16 x 2644.5 mkm = 3033.5 mkm (error 1%) (Uranus Pluto Distance)
We have discussed this data before, let's summarize its idea

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II-Discussion
We have discussed this data before, let's summarize its idea
- The previous distances are example for similar huge number of distances which
depend on the rate (1.16)
- We should analyze this rate (1.16) later
- But
- We need here to see how the distances be distributed base don this rate (1.16)
- The next data can help our analysis greatly
More Data
- 778.6 mkm (Jupiter Orbital Distance) = 1.0725 x 720.7 mkm (error 1%)
- 720.7 mkm (Jupiter Mercury Distance) = 1.0725 x 671 mkm
- 671 mkm (Jupiter Venus Distance) = 1.0725 x 629 mkm
- 629 mkm (Jupiter Earth Distance) = 1.0725 x 580 mkm (error 1%)
- This data also proves, these distances be created based on a geometrical design.
Because the same distances be rated on (1.0725 and 1.16).
- Please remember 1.16 =(1.077)2
The analysis shows that the solar system distances can't be created interpedently from
one another but created in a network form. And because of that the distances be
distributed based on a geometrical design and as a result the distances be rated with
the rates (1.16) and (1.0725)

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13- The Planets Motions Rates Of Time (More Discussion)
13-1 Preface
13-2 Mercury Pluto Motions Rate of Time
13-3 Mercury Saturn Motions Rate of Time
13-4 Earth, its moon And Pluto Motions Rates Of Time
13-5 Earth And Saturn Motions Rates Of Time

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13-1 Preface
- We have discussed the planets motions rates of time
- But
- As we have seen before, there are other rates be produced and used frequently
more than the original rates of time
- For example
- 1 hour of Earth motion = 29.4 hours of Saturn motion.
- But the rate be used between Saturn and Earth motions data is (9.5)
- Where
- 29.4 = π x 9.36 (and 9.36 has error with 9.5 equal 1.5%)
- Means,
- The rate of time is (29.4) and we tested it and proves it's the correct rate of time
between the 2 planets motions. but the planets motions data use the rate 9.5 instead
that because more geometrical effects be practiced on the rate (29.4), and these
geometrical effect force to use 9.5 in place of 29.4
- Also
- We have seen that (4.61) is the rate between Pluto and the moon motions data
where the rate of time is (1 hour of Pluto motion = 8.5 hours of the moon motion)
but 8.5 = 2 x 4.25 and 4.61 = 1.0725 x 4.25 (error 1%)
- I want to say
- The rate 8.5 is the rate of time between Pluto and the moon but the rate 4.61 is
used frequently more than the original rate that because other geometrical effects
be practiced on the original rate (8.5) to produce the other one (4.61) and
- Similar to that there are more rates of time be used between the planets
- For example we know that
- 1 hour of Mercury motion = 520.2 hours of Pluto motion
- But the working rate between them is (9.18)
- In this point we take a look on the working rates among the planets

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13-2 Mercury Pluto Motions Rate of Time
I- Data
(13-2-a)
1407.6 hours =153.3 hours x 9.18
(13-2-b)
90560 days = 4222.6 hours x 2.33 x 9.18 (error 2%)
(13-2-c)
(2 x 153.3 h x 3600 s) /5040 s =23.9 x 9.18
(13-2-d)
4222.6 h = 153.3 h x 27.5 (where 27.5 = 3 x 9.18)

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II- Discussion
- Let's summarize the idea in following:
- Mercury and Pluto Motions rate of time is (9.18), this rate is the rate between
Mercury rotation period and Pluto day period
- This rule is different from the rule which we have suggested, but that causes no
negative effect on the discussion – that because the rate (9.18) is found in Mercury
and Pluto motions data frequently and through many ways we can discover it –
that means- the rule which we have suggested is a method to discover among many
similar methods – this is one of them -
- The discussion will show that, the rate (9.18) is effective greatly on both planets
motions data but why?
- I want to say
- It's a rate of time! One hour of Mercury motion = (9.18) hours of Pluto motion
- Why this rate (9.18) controls so many other data? if the clock moves (9.18) hours
on Pluto why Mercury interests? What effect be done on Mercury motion?!
- But
- The fact is that, Mercury (motion) be effected with the rate (9.18) of Pluto motion!
- Let's see the data discussion to prove this point of view

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Equation (13-2-a)
1407.6 hours =153.3 hours x 9.18
- Where
- 1407.6 hours = Mercury Rotation Period
- 153.3 days = Pluto Day Period.
- (9.18) = The rate of time between Mercury and Pluto motions.
- As we have discussed the rate (9.18) is the rate between Mercury rotation period
and Pluto day period
- As a result
- 1 hour of Mercury Motion = (9.18) hours of Pluto Motion.
- Notice
- Pluto rotation period = (-153.3 hours), so
- The rate (9.18) can be between the 2 planets rotations periods
- But, can we discover the direction of this rate (9.18)?
Equation (13-2-b)
90560 days = 4222.6 hours x 9.18 x 2.33 (error 2%)
- Where
- 4222.6 hours = Mercury day period
- 2.33 = ??
- Mercury velocity (47.4 km/s) = 10.08 x Pluto velocity (4.7km/s). if the planets
rates of time depend on their velocities. That means 1 hour of Mercury motion
should be = 10.08 hours of Pluto motion. and in this case 24 hours of Pluto motion
= 2.37 hours of Mercury Motion.
- The value 2.33 = (2.37) (error 1.6%)
- Why the rate 2.37 (or 2.33) be used??

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- Because the equation uses (Pluto orbital period 90560 solar days) in comparison
with 4222.6 hours (Mercury day period). The equation proves strongly that the
rate (9.18) is The 2 Planets Motions Rate Of Time.
Equation (13-2-c)
(2 x 153.3 h x 3600 s) /5040 s =23.9 x 9.18
- Where
- 5040 seconds are required for Mercury day period to be 176 solar days
- 153.3 h = Pluto Day Period.
- 23.9 = (112.2km/s) / (4.7 km/ sec), where
- 112.2 km/sec = the velocities total of (Mercury + Venus + Earth)
- The data supposes that, the 3 planets velocities total be used as one velocity in
comparison with Pluto velocity (4.7 km/s), based on these velocities one hour of
the motion of this velocity (112.2km/s) will be equivalent to 23.9 hours of Pluto
motion.
- This equation also proves that the rate of time between Mercury and Pluto is (9.18)
- The data proves that, 1 hour or Mercury motion = (9.18) of Pluto motion.
Equation (13-2-d)
4222.6 h = 153.3 h x 27.5 (where 27.5 = 3 x 9.18)
- Where
- 27.3 days = The moon orbital period
- Where the moon orbital period be connected with Mercury and Pluto motions
strongly and that tells the rate (9.18) be used (the relationship with the moon be
explain later more clear)

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13-3 Mercury Saturn Motions Rate of Time
I- Data
(13-3-a)
1 hour of Mercury Motion = 61 hours of Saturn motion
(13-3-b)
1 hour of Jupiter Motion = 2.48 hours of Saturn motion
(13-3-c)
61 = (9.18) x 6.64
II- Discussion
(I)
- 1 hour of Mercury Motion =61 hours of Saturn Motion
- Based on the rule 1705 solar days (of Saturn motion) = 671 hours of (Mercury
Motion). and by that (1 hour of Mercury Motion = 61 hours of Saturn Motion)
- In fact this rate is correct
- Saturn moves during (1705.5 days) a distance =1430 mkm (= Saturn orbital
distance)
(II)
- 1 hour of Mercury Motion = 24.6 hours of Jupiter Motion
- And
- 1 hour of Jupiter Motion = 2.48 hours of Saturn Motion
- Based on that 1 hour of Mercury Motion = 61 hours of Saturn Motion
- Based on the previous data we have 2 proves for the rate (1 hour of Saturn motion
= 61 hours of Mercury Motion)
- We know that 1 hour of Mercury Motion = (9.18) hours of Pluto Motion, So

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61 = (9.18) x 6.64
- Where
- (61) is the rate between Mercury and Saturn Motions
- (9.18) is the rate between Mercury and Pluto Motions
- Based on that
- (6.64) should be the rate between Pluto and Saturn motion
- That means
- 1 hour of Pluto motion = 6.64 hours of Saturn motion
- Let's try test this rate of time in following
- 120536 second = 6.64 x 18153 seconds
- But
- 18153 seconds = 5.04 hours (with 5.1 error 1%)
- (Please remember)
- Mars velocity = Pluto velocity x 5.1
- Venus velocity = Uranus velocity x 5.1
- The moon velocity =Neptune velocity x 5.1
- Notice
- 90560 days = Pluto orbital period, but
- 90560 seconds = 25.15 hours (but (5.04 hours)2
= 25.4 hours (error 1%)
- The value 5.04 is related to Pluto motion strongly
- Notice
- 18142 seconds = 5.04 hours
- 30589 seconds x 2 = 12104 x 5.05
- 10747 days x 24 h = 10.7 h x 2 x 12053
- 1433 mkm = (12053 km x π)2
- From the previous data we conclude the following
- 120536 seconds of Saturn motion be =5.04 hours of Pluto motion

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- But
- 1 hour of Pluto = 4.61 hours of the moon motion
- Based on that,
- 5.04 hours of Pluto motion =23.23 hours of the moon motion (where 23.45
degrees = Earth Axial Tilt) (error 1%)
- Notice
- 1 hour of Jupiter motion = 2.48 hours of Saturn motion
- 1557.2 hours of Saturn motion = 629 hours of Jupiter motion
A QUESTION
Why the rate (5.1) be between Mars and Pluto velocities, why not use any of
Saturn motion data instead of Mars data? the next equation can help our answer
10747 days x 24 h = 24.6 hours x 10485
but
4331 days x 24 h = 9.9 hours x 10499
We have discussed this equation before.

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13-4 Earth, Its Moon And Pluto Motions Rates Of Time
I- Data
Group no. (1)
(A)
- Earth (29.8 km/s) moves during a solar day (24 h) a distance = 2574720 km
- Pluto (4.7 km/s) moves during its day (153.3) a distance = 2593836 km
- The moon displacements total during (29.53 days) = 2598693 km
- Pluto and the moon motion distances be equal but they are different from Earth
motion distance with (1%).
(B)
(C)
- 1 hour of Earth motion= 29.53 hours of the moon motion (explained in discussion)
Group no. (2)
(13-4-a)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
(13-4-b)
Tan (12.2) x 708.7 hours = 153.3 hours
(13-4-c)
Tan (13.17) x 655.7 hours = 153.3 hours
(13-4-d)
2 x 153.3 h = 4.61 x 66.5 But
(708.7 h /10.7 h) = (655.7 h /9.9 h) =66.23 (error 0.4%).
(13-4-e)
413600 km cos (10.96 deg) = 406000 km
(13-4-f)
(10.96 deg /1.7 deg) = (153.3 h /24 h) (error 1%)

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II- Discussion
- The data group no. (A) provides one more feature related to the planet motion rate
of time – Earth, its moon and Pluto move equal distances (Max error 1%) during
their days periods
- How the motions of the 3 planets effect on their rates of time? I can't explain, the
fact is that, the planets move equal distances during their days periods as a result
their motions be rated based on defined rates of time and these rates are used in the
3 planets motions data
- Now Earth and Pluto motions depends on the rate of time 6.38, means (1 hour of
Earth motion = 6.38 hours of Pluto motion) that is equivalent the rate of time
between Jupiter and Mars where (1hour of Mars Motion = 6.3 hours of Jupiter
motion)
- But
- While Jupiter orbital period 4331 days = 2π x 687 days Mars orbital period
- But
- Pluto orbital period 90560 days = 2π3
x 1461 days Earth Cycle (365 +365 +365
366 = 1461 days)
- Also
- Earth data depends on the rate 6.38 in proportionality with Pluto data
- By that
- The point is that
- It's impossible that, the distances be equal and the motions data depend on the
same rate of time –means – this data be created based on one geometrical system.
means the data be created based on a system of data.

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Pluto And The Moon Motions Rate Of Time
- 1 hour of Pluto motion = 4.61 hours of the moon motion
- And
- 1 hour of Earth motion = 29.53 hours of the moon motion
- Simply
- 29.53 hours =6.38 hours x 4.61 hours
- The data discussion can show that these rates control the planets motions data
Discussion (continued)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
- Where
- 406000 km = Pluto motion distance per a solar day
- 88000 km = The moon displacement per a solar day
- 708.7 hours = The Moon Day Period
- 1 hour of Pluto motion = 4.61 hours of the moon motion.
- The motions distances per a solar day be rated with their days periods,
- Both data be rated by the rate (4.61)
- Suppose 1 hour of Pluto motion = 4.61 hours of the moon motion – why the 2
distances be equal?
- Let's remember
- 671 h of Mercury motion =687 days of Jupiter motion = 109.3 days of Mars
motion =1705 days of Saturn motion and the 4 planets move distances during their
motions =Each planet orbital distance (but Mercury is exceptional and move a
distance = double its orbital distance with error 1%)
- Here
- The distances be equal the planets motions per a solar day (and not plant orbital
distances!) why?

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- The noticeable point is that,
- Pluto motion distance per a solar day =406000 km =the distance between the moon
and Earth at apogee radius (the most far point from the Earth the moon can reach)
- Again, the data shows that, it's created based on a geometrical system.
- But the geometrical system is so hard to be caught…
- Let's discuss the next equation
Tan (12.2) x 708.7 hours = 153.3 hours – where
- The angle 12.2 degrees = 13.177 deg – 0.98562 deg
- 0.98562 degrees = The Earth Motion Degrees Per A Solar Day
- Equation no. (13-4-b) shows that the moon and Pluto days periods are created
based on each other geometrically. The fact can't be denied. Pluto day period
(153.3 h) is created as a function in the moon day period (708.7 h).
Tan (13.17) x 655.7 hours = 153.3 hours where
- 655.7 hours = The Moon Rotation Period.
- 153.3 hours = Pluto Day Period and (153.3- ) = Pluto Rotation Period
- Equation no. (13-4-c) shows, Pluto rotation period is created depending on the
moon rotation period based on the angle (13.177 deg).
- The data of the 3 equations are strong and prove the idea clearly, because it's A
Directed Data. Means, this data be created based on geometrical mechanism be
found between Pluto and the moon motions. For that reason, the equations use (all)
data of the 2 planets. That shows the data is directed and can't be created by any
random process. It's data be created based on geometrical reasons and rules.
- The proportionality in data between Earth and its moon on one side and Pluto on
the other side shows that a geometrical mechanism must be found behind them.

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(708.7 h /10.7 h) = (655.7 h /9.9 h) =66.23
And
2 x 153.3 h = 4.61 x 66.5 But (error 0.4%).
And
153.3 h = 2.34 x 65.5 (error 1%)
- 708.7 hours = The moon Day period
- 655.7 hours = The Moon Rotation Period
- 10.7 hours = Saturn Day Period
- 9.9 hours = Jupiter Day Period

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413600 km cos (10.96 deg) = 406000 km
- Where
- 406000 km = Pluto Motion Distance During A Solar Day
- Equation no. (13-4-e) shows that, the motions interaction between the moon and
Pluto is a deep interaction. And effects on the planet motion basic data. Because
- The moon displacements total during 29.53 days =2598693 km = 2π x 413600 km
- The distance (413600 km) should be the moon apogee orbital radius if the moon
apogee orbital circumference = the moon displacements total during 29.53 days.
- This is the fact which should be performed
- But
- The moon apogee orbital circumference be (2550973 km) less than the moon
displacements total during (29.53 days) with 2%. This fact arises the question
Why? the moon apogee circumference should be 2598693 km (surely). But for
some geometrical miracle this distance became =2550973 km!
- The radius 413600 km be changed into 406000 km and this change be done based
on the equation no. (13-4-f). The angle (10.96) caused this change. We have
discussed this angle before deeply because it's the main angle in the moon orbit
geometrical structure. The angle (10.96 deg) causes the radius 413600 km to be
406000 km – why? (we will answer later)?
(10.96 deg /1.7 deg) = (153.3 h /24 h) (error 1%)
- The angle 10.96 deg be created based on the rate between Pluto Day Period
(153.3h) and Earth Day Period (24 h). this rate be used between the angle (10.96)
which causes to decrease the radius from 413600 km to 406000 km, and the angle
1.7 deg which is the moon daily motion angle in the moon orbital equation (θ1= θ0
+ 1.7 deg). (The moon orbital equation be discussed in appendix No.1)

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Notice (1)
- The moon displacements total 2598693 km should be the moon apogee orbital
circumference, by that, the moon apogee orbital radius should be =413600 km
- But
- It's not true, the moon apogee orbital radius =406000 km
- Why? because of the angle (10.96 degrees)
- Let's remember this angle in following:
o The moon orbital perigee radius =363000 km
o The moon orbital apogee radius = 406000 km
o If we draw these 2 radiuses in 2 circles as in the figure
o The tangent DB = 181843 km, also
o The perigee orbital circumference = 2.28 mkm
o (181843 km /2.28 mkm) = 0.08
o 137 degrees x 0.08 = (10.96 degrees)
o As we remember that 137 degrees = 95.1 deg x 1.44 deg where
o 95.1 deg =90 deg + 5.1 deg (the moon orbital inclination)
o 1.44 deg = the moon orbit regression degrees per month.
o We have supposed that the angle 137 degrees is created based on the moon
orbital inclination (degrees) and the moon orbit regression angle monthly.
And this angle (137 deg) is the basic angle in the moon orbital geometrical
structure (hypothesis).
o The calculations of the tangent DB = 181843 km aimed to explain one basic
idea which is, the moon orbit is built geometrically to create the rate (0.08)
by which the moon orbital inclination and regression will create the angle
(10.96 deg).
o Let's explain that more clearly

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o The moon orbit inclination and regression controls the moon orbital motion.
this is a hypothesis. Now, the moon orbital motion creates the moon orbit
based on a geometrical design, the moon orbital motion uses the moon orbit
geometrical design to create the angle (10.96 deg) from the basic one (137
deg). by that the original angle is (137 deg) which is created by the moon
inclination and regression unification, and the born angle is (10.96 deg)
which is the motor of the machine.
o What we need to refer to is that, the moon orbit geometrical design is used
in this process. That's why the distance 413600 be decreased and became
406000 km. By that, the main player is the angle (10.96 deg).
- This explanation answers the question,
- Why Pluto Motion Distance During A Solar Day = The Moon Apogee Orbital
Radius=406000 km?

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Notice (2)
- The previous data still have another reading let's summarize it in following:
o Pluto day period is a very long day period in comparison with the outer
planets days periods, Why?
o We notice also that, Pluto Moves During Its Day Period A Distance =
Earth Motion Distance During Earth Day Period. That means, Pluto Day
Period be extending to perform this requirement.
o i.e.
o Pluto Day Period be extending to be 153.3 h to enable Pluto to move a
distance = Earth motion distance during Earth day period.
o Because of that,
o Pluto day period (and rotation period) be created as functions in the Earth
moon day and rotation periods as we have seen in the data discussion.
o i.e.
o The interaction between Pluto motion on one side with the Earth and its
moon motions on the other side caused the following results:
o (1st
Result) the moon apogee orbital radius be decreased from 413600 km to
be 406000 km
o (2nd
Result) Pluto Day Period be extending to be =153.3 days.
Notice (3)
- Uranus effect is the main force behind the changes for the 2 planets data.
- Uranus effect on Pluto is proved by Planet 8 days Cycle where Uranus uses Pluto
day period in its motion.
- Uranus effect on the moon is proved by the fact, Uranus orbital circumference =
19.2 Earth orbital circumference. The moon moves a cycle called Metonic cycle
and extends for 19 years. Metonic Cycle is caused almost by Uranus effect on the
moon motion.

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13-5 Earth And Saturn Motions Rates Of Time
I - Data
(i)
Saturn moves daily 838080 km = the Earth moon displacement 88000 km x 9.5
(ii)
Saturn diameter 120536 km = Earth diameter 12756 km x 9.5
(iii)
Saturn orbital distance 1433.5 mkm = Earth orbital distance 149.6 mkm x 9.5
(iv)
Earth axial tilt 23.4 deg = Saturn orbital inclination 2.5 deg x 9.5 (error 1.7%)
(v)
Saturn Orbital Period 10747 days = 365.25 days x 29.53 days
- Notice (1)
- 3.1 deg x 0.8 =2.5 deg
- Where
- 3.1 deg = Jupiter Axial Tilt
- 2.5 deg = Saturn Orbital Inclination
- 0.8 deg = Uranus Orbital Inclination
- But
- 1.44 deg = the moon orbit regression per month = 0.8 x 1.8 deg
- 1.8 deg = Neptune Orbital Inclination
- Notice (2)
- The moon daily displacement 88000
- If the moon passes earth orbital circumference (940 mkm) by using its
displacement per a solar day, the moon would need 10747 days (error 0.6%)
- Notice (3)
- The moon motion daily (2.4 mkm) during 10747 days passes 25920 mkm =Light
Motion Distance During A Solar Day

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Appendix No. (1)
The Moon Orbital Motion Equation
I- Why Does The Moon Use Pythagorean Triangle In Its Motion?
- Let's summarize this question answer in following:
o The moon uses Pythagorean triangle basically to decrease its displacement
daily through its orbit
o The moon daily displacement = 88000 km and the moon has to move this
distance every day without any decreasing (later we will know why!)
o But
o If the moon moves by this displacement as its orbital displacement the moon
would revolve around Earth through its apogee orbit only (r=0.406 mkm)
o For that reason
o The moon creates an angle between its motion direction and its orbit
horizontal level to create a displacement through its orbit less than (88000
km)
o As a result of this technique, the moon can revolve around Earth through
more near orbits than apogee orbit (r=0.406 mkm)
o Simply, because the moon uses this technique the moon can revolve around
Earth through perigee orbit (r=0.363 mkm)
o Let's explain this intelligent technique with some details to show the useful
result of using Pythagorean triangle by the moon orbital motion….

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II- How Does The Moon Use Pythagorean Triangle In Its Motion?
- The moon moves daily (88000 km) on the right triangle hypotenuse (AC), but the
moon creates an angle (θ) between its motion direction and its orbit horizontal
level, by that the real displacement through the moon orbit will be (L= 88000 km
cos (θ)), and by that, spite the moon moves 88000 km, but the real orbital
horizontal displacement be less than (88000 km) and this is the objective for which
the moon uses Pythagorean triangle –
As an example,
- If (θ) =28.63 degrees, the real displacement (L== 88000 km cos (θ)) = 77237 km,
So, if the moon real displacement daily be (77237 km), during 29.53 days the
moon will pass a distance = 2.28 million km and this will be the moon orbital
circumference, where 2.28 mkm = 2π x (0.363 mkm)
- The Moon Orbital Perigee Radius =0.363 mkm
- That means, the moon by a real displacement =77237 km can move around Earth
through the perigee orbit (radius =0.363 mkm), this is the useful result the moon
performs by using Pythagorean triangle,
- Now let's suppose the moon doesn't use Pythagorean triangle, what would happen?
- The moon daily displacement = 88000 km, during 29.53 days the moon moves a
distance = 2.598 mkm where 2.598 mkm = 2π x (0.413 mkm)
- The Moon Orbital Apogee Radius =0.406 mkm
- So the moon will move along month revolving around Earth through its apogee
orbit (or even far from apogee orbit) because the total distance can't be passed
through any more near orbit around Earth…
- The data shows how Pythagorean triangle is so useful for the moon orbital motion.

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The Angle θ
- The angle (θ) should get our attention for its specific effect…let's summarize the
idea in following
o The angle (θ) changes the real displacement (L = 88000 cos (θ)), through the
moon orbit..
o We know that, when the real displacement (L) be shorter the moon can
move through near orbits to Earth and by that the moon can be near or at
Perigee radius (0.363 mkm)
o When the real displacement (L) be greater the moon has to move through
orbits far from Earth and by that the moon can be near or at apogee orbit
(r=0.406 mkm)
o That means, the angle (θ) changes the real displacement (L) and also
changes the distance between the moon to perigee or to apogee, shortly, the
angle (θ) defines the moon position (as a ship) between 2 river banks….
- The angle (θ) defines the moon orbital motion basic features and we have to
discuss is deeply with the moon orbital motion equation (θ1= θ0 + 1.7 degrees),
but before we need to analyze the moon orbital motion
Notice
o We know that (363000)2
+ (86000)2
= (373000)2
o In Pythagoras triangle with dimensions (363000 km, 373000km, 86000 km),
what's the angle (θ)? The angle (θ) = 13.33 degrees
o Also (396800)2
+ (86000)2
= (406000)2
the angle (θ) = 12.229 degrees
o I have used (363000 km and 406000 km) because they are the perigee and
apogee radiuses between which the moon moves.
o The difference between angles = 1.1 degrees
i.e.,
The angle (1.1 deg.) controls the moon motion from perigee to apogee, we will need
this notice later in our discussion

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III- The Moon Orbital Motion
- The moon moves per a solar day a motion typical to the Earth motion to avoid the
separation from Earth through their motions, based on this rule, the moon moves
per a solar day 2.573 million km with an angle declines on the horizontal level
0.98562 degrees as typical to Earth motion
- If there's no Lorentz Length Contraction Phenomenon effect on the moon motion,
the moon motion trajectory would to be a parallel line to Earth Motion Trajectory,
But Lorentz Length Contraction effects on the moon motion daily distance (2.573
mkm) with a rate 1.0725 and causes this distance to be contracted (2.399 mkm)
- The moon difficulties are started here, because the difference between both
distances (0.17 mkm) will cause the moon to be separated from Earth motion
inevitably
- We should notice that, these motions are done far from our observation, means, we
see nothing of this motion distance, because the moon moves on the Earth orbital
circumference revolving around the sun, but, even if we can't observe this motion
distance the motion is still fact and proved by its power, because the Earth moves
per a solar day 2.573 mkm and if the moon doesn't move this same distance every
solar day that necessities the moon to be separated from the Earth through their
motions course – based on that- the facts prove this motion regardless our
observation ability for it.
- Now the moon has an additional distance to be passed (0.17 mkm) and the moon
has to pass this distance on the same solar day to avoid the separation from the
Earth during their motions.
- Because of that, the moon moves its daily displacement (88000 km) depends on
Earth gravity force (by which we see the moon in the Earth sky), but the different
distance (0.17 mkm) to be covered still needs the moon to move one more
displacement (= 88000 km)

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- The previous explanation tells that, the moon has to move 2 displacements each =
88000 km, while we see one displacement only because it's done through the
moon orbital motion around Earth but the other displacement should be done also
because this total distance (0.17 mkm) is required to cover the different distance
and create the total (2.573 mkm) which saves the moon and Earth motions
accompanying.
- Now we have 2 basic information about the moon orbital motion
o (1st
information) the moon uses Pythagorean triangle in its orbital motion
o (2nd
information) the moon has to move 2 displacements each =88000 km
and their total distance =0.17 mkm which is a required distance necessary to
cover the difference between the moon and Earth motions distances.
- This explanation helps us to understand why the moon uses Pythagorean triangle
in its motion, because the moon can't decrease its daily displacement (88000 km)
because the moon needs this distance to cover the different distance between its
contracted motion distance (2.399 mkm) and Earth motion distance (2.573 mkm),
So the moon needs to move this displacement perfectly, but if it's used as a
displacement through the moon orbit, the moon would be always a prisoner in the
apogee orbit (r=0.406 mkm) as we have discussed before, because of that, the
moon creates Pythagorean triangle technique by which the moon moves actually
88000 km daily but the real displacement through the moon orbit became less (L =
88000 Cos θ) and by that the moon can achieve 2 objectives, First to pass the
required distance (88000 km) and Second to move in near orbits to Earth, that
shows the intelligent moon motion technique…
- (Notice, Lorentz Length Contraction Effect Discussion is in Appendix No. 1)

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The Moon Orbital Motion Needs One More Orbit
- The previous explanation tells that, the moon moves 2 displacements each =88000
km, we see one of these 2 displacements but where's the other displacement?!
- We know that, the moon original motion (2.573 mkm) which is contracted to be
(2.399 mkm) isn't seen by us because the moon moves this distance revolving with
Earth around the sun along the Earth Orbital Circumference
- We may accept that, the 2nd
displacement the moon does on this same trajectory
and isn't seen by us.
- So,
- There must be one more orbit for the moon to move through this 2nd
displacement.
means,
- There's 2nd
Orbit For The Moon Motion
- But
- How can we discover this second orbit if we can't observe the 2nd
displacement
motion?
- We can discover this 2nd
orbit by the moon orbit data analysis. So we should
depend on the moon orbital triangle data analysis to define this 2nd
orbit position.
- For that we have to discuss the moon 2nd
orbit in our deep analysis of The Moon
Orbital Triangle Geometrical Structure.

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IV- The Moon Orbital Motion Equation
A- The Equation Concept
B- The Equation Test and Accuracy
A- The Equation Concept
The Moon Orbital Motion Equation
(θ1= θ0 + 1.7 degrees)
- The moon orbital motion equation is created depending on the concept we have
discussed, which is (the moon uses Pythagorean triangle in its orbital motion)
- The moon uses Pythagorean triangle and by this intelligent technique the moon be
under control of the angle (θ) change
- The angle (θ) defines almost all the moon motion features.…
- The moon uses this technique, aiming to create a real displacement shorter than its
actual displacement (88000 km) based on the equation (L =88000 cos (θ)) and by
that while the moon moves a displacement =88000 km but the real displacement
(L) through its orbit be shorter than 88000 km and by that the moon can revolve
around Earth through more near orbits than its apogee orbit (r=0.406 mkm).
- The moon orbital motion equation depends on this concept and, the equation
uses (the constant) 1.7 degrees as the moon daily motion degrees, and the equation
uses the previous day angle (θ0) to produce the today angle (θ1)
- We have 3 questions in this equation study which are:
o How does this equation work?
o Is this equation trustee and correct?
o Why does the equation use the angle 1.7 degrees for the moon daily motion?
Let's try to answer….

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How to use this equation?
- Perigee Radius =0.363 mkm, so Its Orbital Circumference =2.28 mkm
- Suppose the moon will revolve around Earth through perigee orbit only during
29.53 days, so
- (2.28 mkm /29.53 days) = 77237 km
- This is (the real displacement = L = 88000 km Cos θ = 77237 km),
- What's the angle θ value? the angle θ = 28.63 degrees
- Suppose the moon stand on this point yesterday with the angle (θ) =28.63 degrees,
where the moon will move today?
- From Perigee (the most near point to Earth) the moon will move in Ascending
motion because it moves from perigee (0.363 mkm) to apogee (0.406 mkm)
- In Ascending motion we use (-1.7 degrees) because the angle (θ) is decreased
where the real displacement (L) is increased, So let's do that in following
o (θ1= θ0 - 1.7 degrees)
o (θ1= 28.63 degrees - 1.7 degrees) = 26.93 degrees
o L = 88000 Cos (26.93 degrees) = 78454 km
o During 29.53 days so (78454 km x 29.53 days = 2.316 mkm)
o 2.316 mkm = 2π x 368722 km
That means
o The moon was (before motion) on Perigee radius (r=0.363 mkm) and starts
its motion displacement 88000 km. For day motion the equation uses 1.7
degrees, that means, the moon on perigee uses Pythagorean triangle with
angle (28.63 degrees) and during one solar day the moon uses - 1.7 degrees
and by that the angle will be (26.93 degrees)…... The angle 1.7 degrees
expresses The Moon Daily Motion
o By using Pythagorean triangle its angle (θ) = 26.93 deg, the displacement
(88000 km) will create a real displacement through the moon orbit = 78454
km and the moon will finish its motion today at a distance 368722 km

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means the moon is far from perigee radius with (368722 km-363000 km
=5722 km )
o So, the moon after 1 day motion will be at the point 368722 km and will
have the Pythagorean triangle its angle 26.93 degrees.
The Descending Motion
o When the moon moves from apogee (0.406 mkm) to perigee (0.363 mkm),
so the angle (1.7 degrees) will be positive (+1.7 degrees) because the angle
(θ) is increased and the real displacement (L = 88000 Cos (θ)) be shorter.
So
o If the moon in apogee radius (r=0.406 mkm), what's the angle (θ)?
o The apogee orbital circumference = 0.406 mkm x2π =2.55 mkm = 29.53
days x 86400 km, the angle (θ) = 10.96 degrees (=11 deg approx.)
o The moon moves from apogee to perigee (descending motion)
o (θ1= θ0 + 1.7 degrees) means (θ1= 11 degrees + 1.7 degrees) = 12.7 deg.
o L = 88000 Cos (12.7 degrees) = 85847 km
o During 29.53 days so (85847 km x 29.53 days = 2.535 mkm)
o 2.535 mkm = 2π x 403467 km
So
o After one day the moon will be on 403467 km far from apogee (406000 km)
with 2540 km
Now let's see this equation test and efficiency in following

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B- The Equation Test and Accuracy
- I have tested the Equation with real data for 2 months June 2020 and October 2020
- The results are very good and I provide the results here for better vision
concerning the equation efficiency
1st
Test June 2020
Day Registered Data The Results (1.7) Difference
6-6-2020 369418 km
7-6-2020 373729 km 374772.5 - 1044
8-6-2020 378917 km 378821.5 96
9-6-2020 384534 km 383667.7 867
10-6-2020 390096 km 388890 1206
11-6-2020 395156 km 394000 1156
12-6-2020 399345 km 398604.2 741
13-6-2020 402395 km 402361.3 34
14-6-2020 404153 km 405052.8 -900
15-6-2020 404574 km ---- ---
16-6-2020 403718 km 401848.5 1870
17-6-2020 401733 km 400876.1 857
18-6-2020 398840 km 398640.7 200
19-6-2020 395303 km 395417.4 115
20-6-2020 391409 km 391521.2 -113
21-6-2020 387432 km 387273.4 159
22-6-2020 383607 km 382968.4 639
23-6-2020 380110 km 378852 1258
24-6-2020 377044 km 375107 1937
25-6-2020 374451 km 371836.5 2615
26-6-2020 372338 km 369077 3262
27-6-2020 370703 km 366855.6 3847
[

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The 1st
Test Results Analysis:
- The Total Results Are 20 Values
(1st
Category)
o 15 values, defines the moon position in range 1300 km (Error 3%)
(2nd
Category)
o 2 values, defines the moon position in range 1300-2000 km (Error 4.6 %)
(3rd
Category)
o 3 values, defines the moon position in range 2000-3500 km (Error 8 %)
- The Results Explanation
- The distance from perigee to apogee =43000 km…
o 1st
Category of results defines the moon position in error range (1300 km) =
error (3%), that means, (15 values of 20) defines the moon position with
error (3%) only (Small Error Range)
o 2nd
Category of results defines the moon position in error range from (1300
km to 2000 km) = error (4.5%), that means (2 values of 20) defines the
moon position with error (4.5%) (Average Error Range)
o 3rd
km to 3500 km) = error (8%), that means (3 values of 20) defines the moon
position with error (8%) (Great Error Range)
- The Equation Accuracy
o The previous explanation shows that, the equation has a good range of
accuracy and its error is in the acceptable error range
The Conclusion
The Equation Is correct and trustee
And
It's a useful tool to define the moon position daily

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2nd
Test October 2020
Day Registered Data Results (1.7) Difference
5-10-2020 405,690 km --- ---
6-10-2020 404,171 km 403125.3 km 1046 km
7-10-2020 401,649 km 401390 km 259 km
8-10-2020 398,073 km 398545.6 Km - 473 km
9-10-2020 393,464 km 394568.8 km -1105 km
10-10-2020 387,944 km 389510 km -1567 km
11-10-2020 381,763 km 383520 km -1758 km
12-10-2020 375,302 km 376875.3km -1574 km
13-10-2020 369,063 km 369981km -919 km
14-10-2020 363,617 km 363363.4km 254 km
15-10-2020 359,530 km 357612 km 1918 km
16-10-2020 357,269 km 353307 km 3962 km
17-10-2020 357,105 km ---- --
18-10-2020 359,048 km --- --
19-10-2020 362,851 km 364979.7 km - 2129 km
20-10-2020 368,058 km 368579.3 km -522 km
21-10-2020 374,101 km 373492.4 km 609 km
22-10-2020 380,412 km 379168.3 Km 1244 Km
23-10-2020 386,497 km 385059.3Km 1438 km
24-10-2020 391,989 km 390694.3 km 1295 km
25-10-2020 396,659 km 395729.5 km 930 km
26-10-2020 400,395 km 399958.7 km 437 km
27-10-2020 403,181 km 403299 km 112 km
28-10-2020 405,059 km 405738.5 km -680 km
29-10-2020 406,104 km 407359.4 km -1256 km
[

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The Test Results Analysis:
- The Total Results Are 22 Values
(1st
Category)
o 15 values, defines the moon position in range 1300 km (Error 3%)
(2nd
Category)
o 5 values, defines the moon position in range 1300-2000 km (Error 4.6 %)
(3rd
Category)
o 2 values, defines the moon position in range 2000-3500 km (Error 8 %)
- The Results Explanation
- The distance from perigee to apogee =43000 km…
o 1st
Category of results defines the moon position in error range (1300 km) =
error (3%), that means, (15 values of 22) defines the moon position with
error (3%) only (Small Error Range)
o 2nd
km to 2000 km) = error (4.5%), that means (5 values of 22) defines the
moon position with error (4.5%) (Average Error Range)
o 3rd
km to 3500 km) = error (8%), that means (2 values of 22) defines the moon
position with error (8%) (Great Error Range)
- The Equation Accuracy
o The previous explanation shows that, the equation has a good range of
accuracy and its error is in the acceptable error range
The Conclusion
The Equation Is correct and trustee
And
It's a useful tool to define the moon position daily

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The Value 1.7 degrees
- The 3rd
question was, why the equation uses 1.7 degrees?
Because
1.7 degrees = 0.98562 degrees + 0.712 degrees
Where
- 0.98562 degrees = Earth motion daily degrees, and it equals the moon daily
motion degrees because the moon has to move an equal distance to Earth motion
daily distance to save their motions accompanying
- This question and the angle 0.712 degrees is discussed in my previous paper.

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The Moon Motion Difficulties
- There are 2 basic difficulties are observed in the moon orbital motions, let's refer
to them in following:
o (1st
Difficulty) The moon moves per day different distances from perigee to
apogee…..
o We know the moon moves from perigee to apogee (go and back) during
Anomalistic month (27.55 solar days)
o (43000 km x 2) / 27.55 days = 3122 km
o The moon doesn't use this rate (3122 km) in its motion, instead the moon
can move (6000 km) on one day only and on another day may move only
2500 km (or even less)!
o The moon orbital equation tries to solve this difficulty by using the rate 1.7
degrees in the equation (θ1 = θ0 + 1.7 degrees), the value 1.7 degrees is a
great number and enables the moon to move around (5000 km) per solar day
and by that if the moon moves per solar day 4000 km the different distance
will be 1000 km and if the moon moves 6000 km the different will be
– 1000 km, it’s the same difference, and by that, the error be minimized as
possible enabling the equation to be more efficient..
o (2nd
Difficulty) The moon stays in perigee and apogee points long time….
o That means, while the moon be on perigee or apogee, the moon doesn't use
the equation and doesn't change its distance to perigee or apogee for long
days…we may notice that in the equation tests, when the moon reach to
perigee or apogee the equation stops its work and stays 2 or 3 days to return
to its work… because the moon consumes long time to leave the points
(perigee and apogee)…

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References and Biography
(Preprint No. 1) Mars Migration Theory
https://www.academia.edu/49051037/_Preprint_No_1_Mars_Migration_Theory
(Preprint No. 2) The Moon Orbital Motion Equation
https://www.academia.edu/49051029/_Preprint_No_2_The_Moon_Orbital_Motion_Equation
The Solar Planets Motions Description (Revised)
https://www.academia.edu/49464125/The_Solar_Planets_Motions_Description_Revised_
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944p=15209
Mr. Gerges Francis Tawdrous +201022532292
Physics Department- Physics Mathematics Faculty
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
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Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
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Planet Motion Features Disproves Newton Theory (Revised)

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