Why Should We Refuse Newton Theory Of The Sun Gravity (Part No.2)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Why Should We Refuse Newton Theory Of The Sun Gravity (Part No.2)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –30th
November 2021
Abstract
Paper Question
Can Planet diameter be created depending on a period of time? And can it be used as
a period of time by the rate (1 km = 1 second)?
Paper question explanation
- One more time we have to ask
- Why Should We Refuse Newton Theory Of The Sun Gravity?
- What's the planet diameter according to Newton Vision?, But
- Jupiter diameter 142984 km can be = 4 Jupiter days periods total
- Saturn diameter 120536 km can be = (π x 10.7 h) (Saturn day period 10.7 h)
- The moon circumference can be = 1/8 of the solar day (if 1 km =1 sec)
- This data be considered as results of pure coincidences of numbers by Newton
vision but more data shows that – in fact – Planet diameter be created as a function
in some period of time and be used as a period of time – for example
- Venus (35 km/s) moves during 12104 s a distance = 421056 km = Uranus motion
distance during its day period (where 12104 km = Venus diameter) and
- Neptune (5.4 km/s) moves during 155597 s a distance = 838000 km = 7 Saturn
diameters = Saturn motion distance during a solar day
- Newton simply didn't see these motions because he supposed the planet diameter
is a piece of rock created by some random process

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- Newton theory of the sun gravity is mistaken because the theory components are
not defined – the planet diameter is an example
- I want to say
- The solar system is a complex network of motions – Newton theory sees only the
planets revolutions around the sun – and by that the basic part of motions be
hidden and not defined by the theory
- As a result
- The planets motions features be far from Newton Theory- basically for 3 reasons
which are
(1) The Motion Be Transported Among The Solar Planets
(2) The Solar System Distances Be Created Based On A Continuum –and not
as individual independent distances
(3) The planets motions effect mutually on one another and these effects can't
be attributed to the mass gravity forces
- To solve this dilemma there's one simple approach – by asking (how the matter is
created?)
- The matter is created out of light, but the matter doesn't separate its light parent but
move together one unified motion by using different rates of time –the basic rate of
time is that 1 second of light motion be equivalent to 1 solar day of Earth motion –
and by this same rate can the other planets days periods be dealt
- By that simply
- Light motion features be discovered frequently in planets motions – that's why
Newton theory is far from the planets motions features – because light motion
effects on planet motion and creates features – as a result – no way to explain the
solar planets motions without light motion reference because light motion is a part
of planet motion. The 3 provided features show light motion features effect on
planets motions.

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- The continuum effect specially is a clear light motion feature effects on planets
motions – where the solar system distances be created as one group of distances
based on one geometrical design – or as one network of distances –
- The motion transportation also is a clear feature of light motion effect on planet
motion
Paper objective
- The Paper Provides A New Discovered Rule Proves The Motion Be Transported
Among The Solar Planets.
(Please scan the figure (ORCID)

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Paper Contents
Subject Page No.
1- Introduction 6
2- Methodology 10
3- Saturn and Neptune Motions Analysis 12
3-1 Preface 13
3-2 Can Planet Diameter Depend On Its Day Period? 14
3-3 Saturn and Neptune Velocities Proportionality 23
3-4 Planet Orbital And Day Periods Proportionality 31
3-5 The Outer Planets Motions Distances During Their Days Periods 41
3-6 Mars Motion During Saturn Day Period 43
3-7 Planet Orbital Inclination Analysis 49
4- The Continuum Effect Proof 55
4-1 The Continuum Effect Proof 56
4-2 Saturn Motion Analysis 62
4-3 Planet Diameter Analysis 88
4-4 Why do the planets revolve around the sun if there's no sun gravity? 90
5- The Solar Planets Motions Use Different Rates Of Time 91
5-1 Preface 92
5-2 The Planets Motions Rates Of Time 94
6- The Solar Planets Rates Of Time Analysis 98
6-1 Preface 99
6-2 Venus Motion Rate of time 100
6-3 Earth Motion Rate of time 102
6-4 Mars Motion Rate of time 104
6-5 Jupiter Motion Rate of time 106
6-6 Saturn Motion Rate of time 108
6-7 Uranus Motion Rate of time 110
6-8 Neptune Motion Rate of time 112
6-9 Pluto Motion Rate of time 114
6-10 The Planets Orbital Distances Test 116
6-11 One Law Controls The Planets Orbital Periods And Distances 121
6-12 The General Discussion 122
7- The Planets Motions Rates Of Time Effect Analysis 125
7-1 Preface 126
7-2 Planets Motions Rates Of Time And Distances Data 127
7-3 The Data Equal Distances 131
7-4 The Data and the planets velocities. 139
7-5 The Data Distances And Rates Of Time Interaction 143
7-6 The Data General Discussion 153
7-7 Mars, Jupiter and Saturn Motions Analysis 155
7-8 Why Saturn And The Moon Use Equal Rates Of Time? 160
7-9 Why Mercury Use A Double Of Its Orbital Distance? 165

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7-10 The Rate (4.61) be used between Pluto and the moon motion 166
7-11 The Moon Orbital Motion Equation 170
8- Planets Unified General Motion 186
8-1 The Planets Unified General Motion Description 187
8-2 The Solar Planets Motions Are Complementary One Another 189
8-3 The Solar Planets Move An Unified Motion (A Team Motion) 193
9- Mars Migration Theory 198
9-1 Mars Migration Theory 199
9-2 Pluto Migration Theory 202
9-3 Planets Migration Theories Proves 204
9-4 Is There An Absent Planet In The Solar Group? 207
10- The Sun Age Description 210
10-1 Preface 211
10-2 The Sun Circles The Earth 212
10-3The Rate (1.0725) 213
10-4 The Sun Diameter Analysis 216
10.5 The Sun And Earth Motions Rate Of Time (1 day =365.25 days) 219
10-6 The Sun Rays Creation 227
11- Light Beam (1.16 mkm/sec) Proves 233
11-1 The solar system Creation Theory 234
11-2 Light Beam (1.16 mkm/sec) Proves Discussion 239
12-The Solar System Distances Be Created In A Network Form 276
12-1 Preface 277
12-2 The Continuum effect Through the Solar System Distances 279
12-3 The Solar System Distances Distribution 284
12-4 The Solar System Distances Dependency On One Another 288
Appendix No.1 The Solar System Equal Distances List 290
Claims Be Sent Against The Decision Of Nobel Prize For Physics 2021 292
References and Biography 297

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1-Introduction
- A new rule I have discovered in the planets motions-let's provide it in following:
- (Planet Diameter/R) = (Its Velocity/ Another Planet Velocity)
- (R = The Planet Rotation Periods Number In Its Orbital Period)
- Example no. (1)
- (49528 km /89143) = (5.4/ 9.7)
- Where
- 49528 km = Neptune Diameter
- 5.4 km/s = Neptune velocity
- 9.7 km/s = Saturn velocity
- 89143 = Neptune orbital period (59800 days) has 89143 Neptune days
- 16.1 hours = Neptune Day Period
- This rule be proved in Point no. (3-4) of this paper
- We need to pay attention for this rule because it connects 4 data of one planet
data with a velocity of another planet.
- By that, the solar planets motions be similar to one train carriages because all
planets be connected with one another – the rule simply shows a clear feature of a
motion transportation among the solar planets –
- This rule creates a wide proportionality among the planets motions data –and by
that the data dependency and proportionality be proved and clear –
- Clearly the rule disproves Newton theory of the sun mass gravity because no
planet moves by the mass gravity can produce this proportionality of data because
the masses rates show no proportionality –As a result we have a complete different
vision from that one Newton had told
- We have 3 positive results of this rule discovery which are

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- (1st
Result) The rule shows the origin of the planets motions data proportionality
and by that no more (pure coincidences) claim will be raised because the
proportionality be produced based on a geometrical rule.
- (2nd
Result) We can explain many of the planets motions data which we couldn't n
before explain it – let's use the same 2 planets for wide discussion
- Saturn (9.7 km/s) moves during (155597 seconds) distance = 4 x 378675 km
(Saturn Circumference)
- Neptune (5.4 km/s) moves during (155597 seconds) distance = 7 x 120536 km
(Saturn Diameter)
- We discuss these 2 planets motions data in details in the paper – here I try only to
show that many data we couldn't before explain it – we can now explain by this
new discovered rule –
- (3rd
Result) The solar planets motions should be similar to train carriages – the
motion be transported from a planet to another planet and this transportation of
motion be proved by the discovered rule and the proportional data –we have to
know how the motion be transported – but the rule proves that the motion be
transported regardless our knowledge by its method
- Now let's ask, why this rule be used by the planets data? what's the geometrical
objective of this transportation of motion?
- This question can be more clear with one more question, let's ask it
- (Why does the moon rotation period equal= the moon orbital period?), can this
equality create any effect on other planets motions?
- A third question may help us much better
- Why does the moon move Metonic Cycle (19 years) if Earth Cycle is 4 years only?
- I suppose that, the moon moves Metonic Cycle as a result of Uranus motion effect
on the moon motion

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- Because
- Uranus orbital distance 2872.5mkm =19 Earth orbital distance 149.6 mkm
- If Earth and Uranus velocities be equal, while Uranus revolves around the sun one
complete revolution, Earth would revolve 19 revolutions (19 years) –
- This proportionality of the periods cause my hypothesis that the moon moves
Metonic Cycle under Uranus motion effect on the moon motion – but how Uranus
can cause this effect on the moon?
- Because of the long distance from Uranus to the moon, we need to find the method
by which Uranus can effect on the moon motion..
- I suggest that, the moon orbital period =27.3 days = the moon rotation period
because of the result of the discovered rule on the moon –means – Uranus motion
effects on the planets to use this rule and transport Uranus motion effect from a
planet to another till reach to the moon –the rule depends on the difference
between the planet orbital period and its rotation period – where the basic factor is
the planet rotation periods numbers in its orbital period as we have seen before -
Neptune orbital period has 89143 Neptune rotation periods – the rule depend on
this factor basically – but in the moon case the moon orbital period = the moon
rotation period – that makes the rule is invalid for the moon – by that – we
conclude that the rule be created by Uranus effect to transport Uranus motion
effect to the moon motion through the planets motions. and this effect be seen as a
proportionality of the planets motions data
- Notice
- The planet orbital inclination be defined also based on the new discovered rule –
for example for our 2 friends Saturn and Neptune,
- Saturn velocity = 1.8 x Neptune velocity
- Neptune orbital inclination be =1.8 degrees as a result for the velocities
proportionality.

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- Let's take a look on the paper contents
- Saturn and Neptune motion analysis
(Be discussed in point no. 3 of this paper)
- The Continuum Effect Found In The Planets Motions Data
- The Solar Planets Motions Use Different Rates Of Time
(Be discussed in points no. 5-6-7 of this paper)
- The Planets Move One Unified Motion
- Mars Migration And The Sun Creation
(Be discussed in points no. 9 and 10 of this paper)
- A light beam its velocity 1.16 mkm/sec be found and effects on the solar
system motion.
- The Solar System distances be created in a network form as one group of distances

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2- Methodology
- I use the planets motions data analysis in comparison with the theories which try to
explain the planets motions-
- Shortly
- I suppose the planet motion data be similar to a creature genes and by analysis of
this data we should discover this planet motion features.
- Let's use one example to explain how this method works?
- Example No. 1
- 778.6 mkm = 1.0725 x 720.7 mkm (Mercury Jupiter Distance)
- 720.7 mkm = 1.0725 x 671 mkm (Venus Jupiter Distance)
- 671 mkm = 1.0725 x 629 mkm (Earth Jupiter Distance)
- 629 mkm = (1.0725)2
x 550.7 mkm (Mars Jupiter Distance)
- 550.7 mkm = (1.0725) x 511 mkm
- 4900 mkm = (1.0725) x 4495.1 mkm (Neptune Orbital Distance) (1.6%)
- 1375 mkm = (1.0725) x 1284 mkm (Earth Saturn Distance)
- The data shows that, the distances between Jupiter and the other planets be rated
by the same rate (1.0725). Why?
- The next question should be (How the space be created? we need to ask before if
the space be created or found without creation?)
- That's the useful result of the planet motion data analysis, it gives us new direction
of thinking. No one of us knows how the space be created. but no one will accept
that Jupiter (all) distances be rated by the same rate (1.0725) as a result for pure
coincidence of numbers – the simple conclusion is that – one geometrical reason
must be found behind.
- Then, New vision be seen in this data analysis because, the data shows that the
distances can't be created independently because they are related to one planet
(Jupiter) and depend on the same rate (1.0725) that tells one geometrical reason
caused to create this data.

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- We may conclude based on that, The distances be created in Some Network Form
- Means, no distance be created independently from the others on the contrary the
distances be created together in a network form and based on one geometrical
design. This is a different vision from Newton's theory.
- We should notice that, the previous data isn't exceptional example, on the contrary,
the rate (1.0725) controls 40% of all distances in the solar system. there must be a
geometrical reason for this using. (These distances list be inserted in appendix no.1
of this paper)
- I want to say
- The planets motions data analysis correct our understanding toward the solar
planets motions and save our understanding from the imaginary ideas –
- We discuss the solar system distances network theory in this paper in point no.
(12) in which we should prove that the distances can't be created individually or
independently, on the contrary, the distances be created together in a network form
and based on one geometrical design which makes the solar system as a chess
board - each piece moves in comparison with the others.
- Shortly
- The planets motions data analysis put the planets motions data in comparison with
the theories trying to explain how this data be created and to test the theory trying
to prove if it's sufficient and trustee.

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3- Saturn and Neptune Motions Analysis
3-1 Preface
3-2 Can Planet Diameter Depend On Its Day Period?
3-3 Saturn and Neptune Velocities Proportionality
3-4 Planet Orbital And Day Periods Proportionality
3-5 The Outer Planets Motions Distances During Their Days Periods
3-6 Mars Motion During Saturn Day Period
3-7 Planet Orbital Inclination Analysis

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3-1 Preface
(1)
- Saturn (9.7 km/s) moves during its day period (10.7 h) a distance = 373644 km =
Saturn Circumference (378675 km) (error 1.3%)
(2)
- Pluto (4.7 km/s) moves during its day period (153.3 h) a distance = 2.5938 m km =
Earth motion distance during its day period (24 h) (error 1%)
- Based on data no (1), we conclude that, Planet moves during its day period a
distance= this planet circumference
- Based on data no. (2), We conclude that, planet moves during its day period a
distance = a distance be passed by another planet in its own day period – but
(3)
- Neptune moves during its day period a distance =2 Neptune Circumferences
- The discussion analyzes Saturn and Neptune motions as example for the solar
planet motion details to discover its basic features -

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3-2 Can Planet Diameter Depend On Its Day Period?
I- Data
Group no. (I)
(1)
155597 sec = 4 x 10.7 hours x 3600 s (error 1%)
(2)
120536 sec = π x 10.7 hours x 3600 s (error 0.4 %)
(3)
(9.7 / 5.4) = 4π/7
(4)
155597 sec x 5.4 km/s = 840224 km = 2 x 420112 km = 7 x 120536 km = 373644 km
+ 466884 km
(5)
2 x 155597 sec x 9.7 km/s = 8 x 378675 km = 3.024 mkm =
(6)
49528 km = 9.7 x 5106 sec
Group no. (II)
(7)
142984 sec = 4 x 9.9 hours x 3600 s (error 361/360)
(8)
2x 160592 sec = 9 x 9.9 hours x 3600 s (error 361/360)
(9)
(120536 km /5.4 km) = (25920 mkm /1.16 mkm)

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II-Discussion
Equation no. (1)
155597 sec = 4 x 10.7 hours x 3600 s (error 1%)
Equation no. (2)
120536 sec = π x 10.7 hours x 3600 s (error 0.4 %)
Equation no. (3)
(9.7 / 5.4) = 4π/7
- Where
- 155597 km = Neptune Circumference
- 10.7 hours = Saturn Day Period
- 120536 km = Saturn Diameter
- 9.7 km/s = Saturn Velocity
- 5.4 km/s = Neptune Velocity
- The previous data shows that
- Neptune Circumference and Saturn diameter both can be considered as functions
in Saturn day period if 1 km be = 1 second - the data has error (1%) and (0.4%),
the functions depend on (4) for Neptune and (π) for Saturn and by that the rate
between both = (4/π)
- The 2 planets velocities rate be (4π/7), we see that the 2 rates are near
- We should ask why the 2 rates are near? Later we should discuss this question
- The point I need to discuss now immediately in the result of this proportionality,
because it has a massive effect on both planets motions – let's see the next
equations

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Equation no. (4)
+466884 km
Equation no. (5)
2 x 155597 sec x 9.7 km/s = 8 x 378675 km = 3.024 mkm
Equation no. (6)
49528 km = 9.7 x 5106 sec
- Shortly
- Neptune motion during (155597 s) passes a distance = 7 Saturn diameters
- Saturn motion during (155597 s) passes a distance = 4 Saturn Circumferences
- We notice that
- Neptune Circumference =4 Saturn days periods if 1 km = 1sec and
- Saturn Diameter =π x Saturn day period if 1 km = 1sec and
- I try to prove that a geometrical rule must be found behind this proportionality of
data, before any progress in the discussion we need to know why Saturn velocity
=9.7 km/s and Neptune velocity =5.4 km/s – because the rate between the 2
velocities is very near to the rate between Neptune circumference and Saturn
diameter – No hope to use (the pure coincidence of numbers) as a method of
Escape – because we have many different data be created depends on one another.
- Let's see equation no. (4) in following

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Equation no. (4)
+466884 km
- Where
- 838000 km = Saturn motion distance during a solar day
- 421056 km = Uranus motion distance during Uranus day period
- 120536 km= Saturn diameter
- 373644 km = Saturn motion distance during Saturn day period
- 466884 km = Neptune motion distance during a solar day
- 155597 km= Neptune Circumference
- Neptune (5.4 km/s) moves during 155597 sec a distance = 840224 km
- But, the distance 840224 km is so interesting one because
- (1)
- 840224 km = it equals Saturn motion distance during a solar day (838000 km)
- (840224 /838000) =(361/360)
- (2)
- 840224 km = 2 x Uranus motion distance during Uranus day period (17.2 h)
- 840224 km = 2 x 420112 km (Uranus motion distance =421056 km)
- (3)
- 840224 km =373644 km + 466884 km
- So
- Neptune motion during (155597 sec) moves distance = 7 Saturn diameters =
Saturn motion distance during a solar day = 2 Uranus motion distance during its
day period = the total of Neptune motion distance during a solar day plus Saturn
motion distance during Saturn day period
- It must be the greatest happy chance in the universe which produces so many
(correct) distances by one motion!

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Equation no. (5)
155597 sec x 9.7 km/s = 4 x 378675 km
- Saturn moves during 155597 sec a distance = 4 Saturn Circumferences
- Here
- Neptune motion and Saturn motion (during the same period of time 155597 sec)
pass distances = Saturn diameters and circumferences respectively! Why?
- But
- 2 values of 155597 sec makes a difference because
2x 155597 sec x 9.7 km/s = 8 x 378675 km = 3.024 mkm
- Saturn moves during (2 x 155597 sec) a distance = 8 Saturn circumferences
- And
- For one more happy chance the 8 Saturn circumferences total be = 3.024 mkm =
Venus motion distance during a solar day
- Why?
- I want to say
- Neptune and Saturn diameters rate in comparison their velocities rate effects
greatly on the planets motions data – it's incredible – we may understand that the 2
planets motions data be effected by this proportionality which we don't know how
to create or explain because – No one suggests any transportation of motion among
the solar planets –then if the rates be found by chance may they effect on the 2
planets motions data-but why and how they effect on other planets motions data?
what's the role of Uranus and Venus in this confusion?
- By the way
- 35 km/sec (Venus velocity) = 2x (9.7)2
x 5.4
- Means, Venus velocity is produced as a function in Saturn velocity (9.7 km/s) and
Neptune velocity (5.4 km/s)
- And

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- (35/6.8) = (24.1 /4.7) = (27.78 /5.4)
- Where
- 35 km/s = Venus Velocity
- 6.8 km/s = Uranus Velocity
- 24.1 km/s = Mars Velocity
- 4.7 km/s = Pluto Velocity
- 27.78 km/s = The Moon Velocity
- That makes Uranus velocity be rated with Venus velocity through this interesting
machine of velocities
- Notice
- Neptune moves during its day period a distance = 2 Neptune Circumferences = 2 x
155597 km
- This information is an important one because Neptune motion uses (usually) the
value (2 x 155597 km) as we have seen in equation no. (5)
- Also
- 2 x 155597= 311194 km =Jupiter diameter +Saturn diameter + Uranus diameter (1%)
- This data shows again Neptune motion uses the value (2 x 155597 km) better than
(155597 km) and that means the geometrical design uses this distance of motion be
passed by Neptune during its day period and not uses Neptune circumference.

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Equation no. (6)
49528 km = 9.7 x 5106 sec
- Equation no.(6) tells that, Saturn (9.7 km/s) moves during 5106 seconds a distance
= 49528 km (Neptune diameter) –
- but we know that –
- Mercury day period needs 5040 seconds to be 4224 hours
- 5106 seconds is different from 5040 seconds with (1.3%) - Means
- Saturn moves during (5040 seconds) a distance = Neptune diameter (error 1.3%)
- Mercury moves during (5040 seconds) a distance = 2 Saturn diameter (error -1%)
- Mars moves during (5040 seconds) a distance = Saturn diameter (error +1%)
Equation no. (7)
142984 sec = 4 x 9.9 hours x 3600 s (error 361/360)
- Where
- 142984 km =Jupiter diameter
- 9.9 hours = Jupiter day period
- Equation no.(7) tells simply that, Jupiter diameter can be equal 4 days of Jupiter
days if 1km= 1 second
- 4 Jupiter days = 142560 seconds
- And
- (142984 /142560) = (361/360)
- Now
- Jupiter is the 3rd
planet whose diameter can be used as a period of time because it
equals 4 Jupiter days periods (the 2 planets are Saturn and Neptune)
- Again
- We have to ask (Can Planet diameter depend on it day? Or on any period of time?)
Why the planet diameter be used as a period of time?!

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Equation no. (8)
2x 160592 sec = 9 x 9.9 hours x 3600 s (error 361/360)
- Where
- 160592 = Uranus Circumference
- 9.9 hours = Jupiter Day Period
- Equation no.(8) tells 2 Uranus circumferences can be = 9 Jupiter days if
- 1 km =1 second
- Shortly
- Saturn and Neptune diameters depend on Saturn Day Period
- And
- Jupiter And Uranus Diameters Depends One Jupiter Day Period
- We remember that
- 2 Jupiter circumferences – 2 Saturn circumferences = 1 Jupiter diameter (1.3%)
- This data tells that
- Saturn diameter be created as a function in Jupiter diameter and that connects the 4
planets data together
- Can Saturn day period (10.7 h) depend on Jupiter day period (9.9 h)?
- Notice
- Neptune diameter depends on 4 Saturn days periods
- Jupiter diameter depends on 4 Jupiter days periods
- Earth cycle is 4 years (365 +365 +365 +366 =1461 days)
- Can this (4 Periods) Cycle be a general cycle in the solar system?

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- The Discussion Summary
- Let's summarize the discussion idea in following:
- There are 2 reasons of proportionality between Saturn and Neptune motions data –
- (First) (Saturn velocity /Neptune velocity) = (4π /7)
- (second ) (Saturn diameter be produced by a motion during 155597 seconds
whether . .this motion be done by Saturn or by Neptune
- Here we have 2 reasons of proportionality, and no logic to suppose both of them
be created by chance -
- If the 2 planets diameters be created as function in Saturn day period (although we
don't know how that can be possible) – the question is still on table asks that why
the velocities are rated? It's incredible the 2 planets diameters are rated and also
their velocities – that makes the 2 planets motions data some how identical – for
example –
- Neptune orbital distance 4495.1 mkm = Saturn orbital distance 1433 mkm x π
- And
- Neptune orbital period 59800 d = Saturn orbital period 10747 d x (π)3/2
- The 2 planets motions data be some how identical because of this proportionality
where we have no explanation yet how or why this proportionality be found!
- Let's analyze the 2 planets velocities trying to find an explanation for the data

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3-3 Saturn and Neptune Velocities Proportionality
I- Data
(a)
(9.7/5.4) = (4π /7) =1.8 = (35/9.7x2)= (47.4/13.1 x2) = (89143/49528)
(b)
482144 = 5.4 x 89143 =9.7 x 49528 =4.7x2 x 51118 = 6.8 x 71492
(c)
2 x 24106 x 9.7 = 466884
(d)
(482144/466884)= (51118/49528)=(89143/86400)
(e)
10500 sec x 13.1 km/s = 9.7 km/s x 14178 sec
(f)
42683 sec x 6.8/ km/s = 290245 km = 27.78 km/s x 10500 sec = 24.1 km/s x 12044
sec = 4.7 km/s x 61920 sec
(g)
1.8 = (9.7/5.4)= (47.4/13.1 x2) = (35/9.7 x2) = (89143/49528) = (155597/86400)
=(840391/466884) =(120536/66965) =(2 x 378675/420750) = (42683/23713) =(2 x
366560 /406000) = (2.082/1.1318)
(h)
203.8 =9.7 x 6.7 π

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II-Discussion
Equation no. (a)
(9.7/5.4) = (4π /7) =1.8 = (35/9.7x2)= (47.4/13.1 x2) = (89143/49528)
- Where
- 9.7 km / sec = Saturn velocity
- 5.4 km / sec = Neptune velocity
- 35 km / sec = Venus velocity
- 47.4 km / sec = Mercury velocity
- 13.1 km / sec = Jupiter velocity
- 1.8 degrees = Neptune orbital inclination
- 49528 km = Neptune diameter
- Equation no. (a) shows an interesting meaning that
- The rate (4π /7) which we have found between Saturn and Neptune velocities used
also as a rate between many other planets – that makes this rate a famous rate –
- There are 3 additional planets use this rate (4π /7) for their velocities, Venus,
Mercury and Jupiter in addition to Saturn and Neptune
- The equation tells that the planets motions be done in comparison with one another
means
- The planets velocities be in proportionality with one another because there's a
geometrical reason requires this proportionality –that means- this proportionality
can't be done by any planet according to its data but done by the general design of
the solar system geometry and it defines the rates used by this proportionality
- For that we see the rates be repeated in using by different planets – but what's the
power which forces all planets to use specific rates?

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Equation no. (b)
482144 = 5.4 x 89143 =9.7 x 49528 =4.7x2 x 51118 = 6.8 x 71492
- Where
- 482144 km = 4 x 120536 km (Saturn Diameter)
- 4.7 km/s = Pluto velocity
- 6.8 km/s = Uranus velocity
- 51118 km = Uranus Diameter
- 71492 km= Jupiter radius
- All planets diameters and radiuses be used as periods of time based on the rate (1
km = 1 second) -
- All data error less than 1%
- Equation no. (b ) is discussed for the value (89143) let's define it in following:
- 59800 days = Neptune orbital period = 1435200 hours = 89143 Neptune days
- Where Neptune day = 16.1 hours
- Equation no. (b) uses the period (89143 Neptune days) as (89143 seconds)!!
- Where
- By 89143 seconds Neptune moves a distance = 482144= 4 Saturn Diameters
- This is one more proportionality between the same 2 planets motions!
- How the period 16.1 hours be = 1 second? and why it be in proportionality with
Saturn diameters?!!

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Equation no. (c)
2 x 24106 x 9.7 = 466884 km
- Where
- 466884 km = The distance be passed by Neptune during a solar day
- 24106 = ((10747 days x 24 h) / 10.7 h)
- 10747 days = Saturn Orbital Period
- Equation no.(c) is an identical to equation no. (b),
- Saturn orbital period = 10747 days = 257928 h = 24106 Saturn Days
- How Saturn day (10.7 hours) be used as (1 second)???
- Saturn moves during (2 x 24106 seconds) a distance = 466884 km = the distance
be passed by Neptune in a solar day (86400 seconds) =the distance be passed by
Jupiter in Jupiter day period (9.9h)
- No understanding can be seen yet
- Let's see the next equation
Equation no. (d)
(482144/466884)= (51118/49528)=(89143/86400)
- Where
- 482144 km = 4 x Saturn diameters
- 466884 km = The distance be passed by Neptune in a soar day
- 51118 km = Uranus diameter
- 86400 sec = The solar day
- The value 89143 = the number of Neptune days period in Neptune orbital period
but the data uses this value as a period = 89143 seconds – that tells each day of
Neptune day period (16.1 hours) be used as 1 second

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Equation no. (e)
10500 sec x 13.1 km/s = 9.7 km/s x 14178 sec = 137550 km
- Where
- 10500 = (4331 d x 24 h) /(9.9 h) (Jupiter orbital period has 10500 Jupiter days)
- 14178 = (90560 d x 24) /(153.3 h) (Pluto orbital period has 14178 Pluto days)
- 13.1 km/s = Jupiter velocity
- Each value (10500 and 14178) be used as periods of time by units of seconds
(10500 seconds and 14178 seconds)
- And by that simply (Jupiter day 9.9 hours be considered = 1 second and also Pluto
day 153.3 hours be considered = 1 second), this very strange using of data we have
to discuss trying to find an explanation for it.
- Notice
- The solar system creation theory tells that- the matter is created out of light but
doesn’t separate its light parent but move together by using different rates of time
–the rule tells that –
- 1 second of light motion be = 1 solar day of planet motion that means
- 1 second of light motion be = 24 hours of planet motion
- The period 24 hours is greater than all outer planets days periods except Pluto –
may this approach enable us to find some explanation how the planet motion use
the day period as 1 second only?!

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Equation no. (f)
42683 sec x 6.8/ km/s = 290245 km = 27.78 km/s x 10500 sec = 24.1 km/s x 12044
sec = 4.7 km/s x 61920 sec
- Where
- 42683 = (30589 d x 24 h) /(17.2 h) (Uranus orbital period has 42683 Uranus days)
- 10500 = (4331 d x 24 h) /(9.9 h) (Jupiter orbital period has 10500 Jupiter days)
- 27.78 km/s = the moon velocity
- 24.1 km/s = Mars velocity
- 61920 sec = Uranus Day Period
- 12044 sec = Venus diameter 12104 km (error 0.5%) (1 km=1sec)
- Equation no. (f) shows that Pluto uses Uranus day period to pass the distance
290245 km that shows a strong connection between both planets –
- The question is why the moon uses the period (10500 seconds)?
Because a deep connection b found between the moon and Jupiter –for example:
- 708.7 h (the moon day period) = 10.7 h (Saturn day period) x 66.2
- 655.7 h (the moon rotation period) = 9.9 h (Jupiter day period) x 66.2
- Notice
- Saturn orbital period has 10500 Mars rotation period
- Some very complex interaction must be found behind this data

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Equation no. (g)
1.8 = (9.7/5.4)= (47.4/13.1 x2) = (35/9.7 x2) = (89143/49528) = (155597/86400)
=(840391/466884) =(120536/66965) =(2 x 378675/420750) = (42683/23713) =(2 x
366560 /406000) = (2.082/1.1318)
notice (The part (2.082/1.1318) has error 2% - all other parts errors are 1% or less)
- 47.4 km/s = Mercury velocity
- 35 km/s = Venus velocity
- 89143 = Neptune days number in Neptune orbital period
- 49528 km = Neptune Diameter (be used as a period of time)
- 155597 km = Neptune Circumference (be used as a period of time)
- 86400 sec = the solar day
- 840391 km = 466884 km + 373507 km
- 466884 km = Neptune Motion Distance During A Solar Day
- 66965 =??
- 378675 km = Saturn Circumference
- 420750 km = Uranus motion distance during its day period (421056km)
- 42683 = Uranus days number in Uranus orbital period
- 23713 =??
- 366560 km = The Outer Planets Diameters Total
- 406000 km = Pluto Motion Distance During A Solar Day
- 1.1318 mkm = Jupiter Motion Distance Per A Solar Day
- 2.082 mkm = Mars Motion Distance Per A Solar Day
- This equation is provided to show that the rate (1.8) be used widely among
different data shows a wide proportionality be used among these values

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Equation no. (h)
203.8 =9.7 x 6.7 π
- 203.8 km/sec = The planets velocities total
- 9.7 km /sec = Saturn velocity
- 6.7 degrees = the moon axial tilt
- Equation no.(h) tries to show that, Saturn velocity is distinguished among the other
planets because it expresses the planets velocities total based on the rate of (6.7)
where the moon uses equal rates of time for Saturn motion rates of time and that
creates some integration in Saturn and the moon motion
- Let's summarize the point main question in following
- The Discussion Summary
- (1)
- By using the period (155597 sec) (where 155597 km = Neptune circumference),
using this period…
- The motion passes distances = Saturn Circumference or Diameters, when these
motions be done by Saturn and Neptune respectively
- (2)
- Neptune moves during (89143 s) a distance = 4 x 120536 km (4 Saturn diameters)
- (3)
- Saturn velocity / Neptune velocity = (4π/7) =1.8
- The question should be
- How a huge number of motions data can be created in proportionality with one
another? and what effect can be produced by this proportionality?
- Let's try to solve this question in the next point

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3-4 Planet Orbital And Day Periods Proportionality
I-Data
Group no.(I)
(1)
(89143 /49528) = (9.7/5.4)
(2)
(24106 /120536) = (9.7 /47.4) (error 2 %)
(3)
(14178/2390) = (27.78 /4.7)
(4)
(42683/51118) = (5.4/6.8) (error 5%)
(5)
(10500/142984) = (178.4/13.1) (error 4%)
(6)
(671/6792) = (48.2/4.7)
(7)
(366.7/12756) = 35
Group no.(II)
(8)
Saturn orbital period has 10500 Mars rotation period
(9)
10500 x 27.78 = 6.8 x 42682
(10)
10500 x 13.1 =137550 = 14178 x 9.7
(11)
3.024 mkm = 10500 x 288

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II-Discussion
Equation no. (1)
(89143 /49528) = (9.7/5.4)
- Where
- 89143 = Neptune Days Numbers In Neptune Orbital Period
- 9.7 km /s = Saturn velocity
- 5.4 km /s = Neptune velocity
- The previous equations provide one idea – let's discuss equation no (1) as example
for the others –
- Neptune has 89143 Neptune days (16.1 h) in its orbital period (59800 solar days)
- Now this number (89143) is rated with Neptune diameter and velocity in
proportional with Saturn velocity.
- The equation shows a direct rule – it connects Neptune orbital period, Neptune day
period, Neptune diameter and Neptune velocity with Saturn velocity – if this is a
rule be used by the other planets – that will create a strong connection between all
planets motions
- We need to think in equation no. (1) deeply– it's some very strange one – also- the
theoretical reason by which this data be created we don't discuss now because we
try to restore our realization from the confusion –
- It's incredible 4 data of one planet be rated in one data of another planet – simply
and clearly – we don't deal with separated rigid bodies move independently – on
the contrary – we deal with one machine and one trajectory of energy – each planet
be created based on the others data and because of that the data be created in deep
and great proportionality –
- We need to prove that this equation isn't created by chance and the suggested rule
by it is a real geometrical rule be used by the planets motions data

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- Notice
- The previous equation and its proportionality effect also on the planets motions
distances during a solar day – by that – Saturn motion distance during a solar day
(838000 km) be rated with Neptune Motion data and on the other side Neptune
motion distance during a solar day (466884 km) be rated with Saturn motion data –
the solar planets are not separated rigid bodies –it's one machine move together
one unified motion and this one motion be seen in the planets motions data
proportionality.
- But how the planets motions can create one unified motion? all tries to answer this
question should suggest a transportation of motion among the solar planets and
how that can be possible? We can't attribute mechanical features for the space
supposing that the space works as a conveyor of motion – can the space transports
the motion by some other method and not mechanical method?
- Let's move to the next equation for more discussion

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Equation no. (2)
(24106 /120536) = (9.7 /47.4) (error 2 %)
- Where
- 24106 = Saturn Days Numbers In Saturn Orbital Period
- 9.7 km /s = Saturn velocity
- 47.4 km /s = Mercury velocity
- Equation no.(2) is an identical to Equation no. (1), Saturn orbital period, Saturn
day period, Saturn diameter and Saturn velocity all be rated with Mercury velocity
– typically to the previous equation – just there's a flexibility to use the rates order,
- Equation no. (2) supports the same idea – that – the planets motions and creations
data be created depending in one another and by that all planets data be connected
together in one strong connection – Again no rigid bodies separated from one
another be found here – We deal with One Continuum and the continuum creates
the planets data depending on one another – completely – the data shows a
different vision from Newton Theory of the sun mass gravity – it's completely a
different universe –
- But
- Can this simple analysis tells the whole fact
- Why Saturn data be in proportionality with Mercury velocity (specifically)?
- And Why Saturn velocity be in proportionality with Neptune motion data?
- Notice
- Mercury day period needs 5040 seconds to be = 4224 hours
- Mercury (47.4km/s) moves during 5040 seconds a distance = 2 x 120536 km ( 2
Saturn diameters) (error 1%)
- Can this data also be produced by chance? The Newton simple idea of the sun
mass gravity hided a great machine for long time

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Equation no. (3)
(14178/2390) = (27.78 /4.7)
- Where
- 14178 = Pluto Days Numbers In Pluto Orbital Period
- 2390 km = Pluto Diameter
- 4.7 km /s = Pluto velocity
- 27.78 km /s = The Moon velocity
- Equation no. (3) is one more identical equation uses the same rule – where
- Pluto orbital period (90560 solar days) has 14178 Pluto days (153.3 h) – and
- Pluto orbital period, Pluto day period, Pluto diameter and Pluto velocity are rated
with the Earth moon velocity (27.78 km/s)
- We simply has a rule be used by the outer planets – at least –
- How a planet 4 data be connected and rated with another planet velocity? How that
can be possible?
- It's a happy situation that I have the chance to write the data before the respectful
readers to avoid all types of confusion – the data shows its power
- Notice
- The moon velocity =27.78 km/sec be proved in point no. (7-11) of this paper
- Notice
- Pluto needs 14547 days to pass a distance = 5906 mkm = Pluto orbital distance,
between 14547 and 14178 there's an error (2.5%)
- Can there be any relationship between these 2 numbers (14547 and 14178)?
- The point is – the value 14547 is different from 14178 with 2.5% and Pluto
motion distance during a solar day (406000 km) is related to the moon velocity
(27.78) because 406000 km = the moon Earth distance at the moon apogee radius!!

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Equation no. (4)
(42683/51118) = (5.4/6.8) (error 5%)
- Where
- 42683 = Uranus Days Numbers In Uranus Orbital Period
- 51118 km = Uranus Diameter
- 6.8 km /s = Uranus velocity
- 5.4 km /s = Neptune velocity
- Equation no. (3) is one more identical equation uses the same rule – its error is a
great one (5%)
- But the equation follows the rule perfectly –
- Why is the error so great (5%)?
- It's almost because of the moon motion effect on Uranus motion– let's remember
this idea in following…
- I suppose that the moon moves Metonic Cycle (19 years) because of Uranus
motion effect on the moon motion – my proof for this hypothesis is that – Uranus
orbital distance = 19 Earth orbital distances – means –if Earth and Uranus
velocities are equal – while Uranus revolves one revolution around the sun Earth
would revolve 19 revolutions (19 years)
- That creates a connection between Uranus and the moon that may effect on the
equation accuracy
- Specifically – the moon motion effect on Uranus diameter – that causes the great
error (5%) – the point is that-as we have seen – the planet diameter be created as a
function in its day period as we have seen in Jupiter, Saturn and Neptune diameters
- But, Uranus day period = 61920 seconds = 51118 seconds +10800 seconds
- 51118 km = Uranus diameter and 10800 km = The Moon Circumference (error 1%)
- Please notice, the connection is so complex because (light velocity / the moon
velocity) =10800 which pushed us to suppose the moon circumference be created
as a rate between its velocity and the light velocity

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Equation no. (5)
(10500/142984) = (178.4/13.1) (error 4%)
- Where
- 10500 = Jupiter Days Numbers In Jupiter Orbital Period
- 142984 km = Jupiter Diameter
- 13.1 km /s = Jupiter velocity
- 178.4 = (13.35)2
- Equation no. (5) uses Jupiter velocity in both sides and by that no outer velocity be
required!!
- It's some very strange using of data – Jupiter doesn't depend on any other planet
but on itself
- Now
- Let's test if the inner planets can follow this same rule

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Equation no. (6)
(671/6792) = (48.2/4.7)
- Where
- 6792 km = Mars Diameter
- 48.2 km/s = 2 x 24.1 km/s (Mars velocity)
- 671 = Mars orbital period (687 days) has (671 Mars rotation periods)
- 24.6 h = Mars rotation period
- Equation no.(6) is almost identical with the other equations and uses the same rule
- Mars diameter be rated with Mars rotation periods numbers found in Mars orbital
period an this rate be in proportionality with the rate between Mars and Pluto
velocities where Mars uses double value of its velocity –
- It's almost the same rule where Mars uses its rotation period in place of the planet
day period be used by the outer planets – we notice that – the outer planets days
periods be = their rotation periods –that means – all previous calculations may be
used for the planets rotations periods because they are equal their days in values
- By that Mars tells us the rule depend on the rotation period and not on the day
period – as we see
- Let's see the next equation for Earth motion data
Equation no. (7)
- (366.7/12756) = 35
- Where
- 12756 km = Earth Diameter
- 366.7 = Earth rotation periods number in Earth orbital period
- Just Earth velocity is absent from the equation – it's a great a change in the
equation why is it done?

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- The Discussion Conclusion
- We know that
- The Moon Orbital Period = 27.3 Days = The Moon Rotation Period
- Because of that we suppose the moon is the main point from which this rule be
started
- Venus and Mercury aren't effected by this rule because it started from the moon
toward the outer planets – the explains why the rule doesn't work for Earth motion
data suitably
- The rule started from the rate (1) because the moon orbital period = the moon
rotation period and the rule be used by all planets from Earth to Pluto creating the
rate between planet orbital period and its rotation period to create a configuration
of motion of all planets in proportionality with the moon motion data
- Even if this conclusion is so strange – this is the most near one to explain the data
- The point is that
- Metonic Cycle is a proof for Uranus motion effect on the moon motion and that
may cause to create a system of data to provide this effect through the planets
motions –by that the effect of Uranus motion reaches to the moon by help of the
other planets motions data proportionality to create the required environment for
this effect.

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Equation no. (8)
Saturn orbital period has 10500 Mars rotation period
Equation no. (9)
10500 x 27.78 = 6.8 x 42682
- Where
- 27.78 km/s = the moon velocity
- 6.8 km/s = The moon velocity
- 10500 = Jupiter has 10500 Jupiter days in its orbital period
- 10500 = Saturn has 10500 Mars rotation period in its orbital period
- 42682 = Uranus has 42682 Uranus days in its orbital period
Equation no. (10)
10500 x 13.1 =137550 = 14178 x 9.7
- Where
- 10500 = Jupiter has 10500 Jupiter days in its orbital period
- 14178 = Pluto has 10500 Pluto days in its orbital period
-
Equation no. (11)
3.024 mkm = 10500 x 288
- Where
- 10500 = Saturn has 10500 Mars rotation period in its orbital period
- 3.024 mkm = Venus motion distance during a solar day

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3-5 Outer Planets Motions Distances During Their Days Periods
I-Data
(1)
466884 km + 373644 km + 421056 km + 312984 km = 1574568 km
(1574568 km = 13.1 km/s x 120536 sec)
(2)
466884 km + 373644 km + 421056 km + 312984 km + 2593836 km = 4168404 km
(4168404 km = 35 km/s x 120536 sec (error 1%))
II-Discussion
Equation no. (1)
466884 km + 373644 km + 421056 km + 312984 km = 1574568 km
(1574568 km = 13.1 km/s x 120536 sec)
- Where
- 466884 km = Jupiter Motion Distance During Jupiter Day Period
- 373644 km = Saturn Motion Distance During Saturn Day Period
- 421056 km = Uranus Motion Distance During Uranus Day Period
- 312984 km = Neptune Motion Distance During Neptune Day Period
- 120536 km = Saturn diameter
- The 4 planets motions distances total be = 1574568 km
- Jupiter can pass this distance (1574568 km) in a period = 120536 sec
- that shows a massive effect of Saturn data on the outer planets motions – we still
need to discover this effect facts
- we notice also that, Uranus motion distance be greater than Saturn's – the correct
order is that (Jupiter – Uranus – Saturn – Neptune) –in fact the planet days periods
order should be (Jupiter – Saturn –Neptune – Uranus) this order refers to the
shortest day period (Jupiter) and the longest day period (Uranus) where this order
also arrange the planets masses in correct order from the greater mass to the
smaller one

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Equation no. (2)
466884 km + 373644 km + 421056 km + 312984 km + 2593836 km = 4168404 km
(4168404 km = 35 km/s x 120536 sec (error 1%))
- Where
- In this equation we add also Pluto motion distance during its day period to the
other 4 planets and the total be 4168404 km
- Venus (35 km/s) can pass this distance in a period = 120536 seconds (error 1%)
- We notice that
- In both calculations Saturn diameter 120536 km be used as a period of time
120536 sec –
- Why??
- Notice
- I use the minimum data error and Saturn diameter each time causes the less error
in data (max error in this data is 1%)

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3-6 Mars Motion During Saturn Day Period
I- Data
(a)
10.7 h x 3600 s x 24.1 km/s = 2 x 466884 km (error 0.5%)
(b)
(120536 km/9.7) = (300000 km /24.1)
(c)
24.1 km/sec x 49528 seconds = 4 x 300000 km
(d)
89143 seconds = 24.76 hours
(e)
(300000 km x 2 /6792) = (59800 /671) (error 0.8%)
(f)
(1160000 km /24.1 km) = (466884 km /9.7 km) = 48133

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II-Discussion
Equation no. (a)
10.7 h x 3600 s x 24.1 km/s = 2 x 466884 km
- Where
- 10.7 h = Saturn Day Period
- 466884 = the distance be passed by Neptune during a solar day
- Mars motion is the companion of Saturn motion – but where Saturn moves
distances equal its data, Mars moves distances related to light motion –let's try to
explain that in details in following:
-
- During 49528 seconds Saturn moves a distance =4 x 120536 km ( Saturn diameter)
- But
- During 49528 seconds Mars moves a distance = 4 x 300000 km
- Where 300000 km = Light Motion Distance During 1 Second
- That connects Saturn and Mars with Neptune –and as we have seen –Saturn and
Neptune Data be rated to one another clearly – that connects Mar also in this same
proportionality of data
- For that reason – as Equation no. (a) shows
- Mars moves during Saturn day period (10.7 h) a distance = 2 x 466884 km
(Neptune motion distance during a solar day)
- We notice also that, Jupiter moves during its day period equal distance 466884 km
and that creates a connection with Jupiter also –this connection be seen in Mars
motion data –
- for example
- Jupiter orbital period / Mars orbital period = 2π
- Saturn orbital distance / Mars orbital distance = 2π

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Equation no. (b)
(120536 km/9.7) = (300000 km /24.1)
- Where
- 300000 km = A distance be passed by light motion in 1 second
Equation no. (c)
24.1 km/sec x 49528 seconds = 4 x 300000 km
- Where
- 49528 km = Neptune diameter
- Equations no. (b) and (c) be understood clearly base on the previous explanation
Equation no. (d)
- Where
- 24.7 hours = Mars day period
- 89143 = The number of Neptune days be found in Neptune orbital period
- Means
- Neptune day period (16.1 h ) x 89143 = Neptune orbital period (59800) x 24 h
- We have used the value (89143) as a period = (89143 seconds) frequently in the
analysis of Saturn and Neptune motions data- here we discover that the period
89143 seconds is very near to 24.7 hours = Mars day period – that shows more
connections and proportionality between Neptune and Mars motions data
- Notice
- Mars orbital circumference =1433 mkm =Saturn orbital distance = Neptune orbital
distance 4495 mkm/π

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Equation no. (e)
(300000 km x 2 /6792) = (59800 /671)
- Where
- 6792 km = Mars diameter
- 59800 days = Neptune orbital period
- 671 = Mars orbital period (687 days) has 671 Mars rotation periods
- The proportionality of data between Mars and Neptune motions shows (frequently)
light motion distances that because Mars and Saturn motions rate depend on light
motion distance for Mars and depend on Saturn motion distance for Saturn
- This explanation tries to tell that – we have 2 trajectories of motion – one of them
be done by Mars and the motion distances (frequently) be rated to light motions
and the other be done by Saturn and the motion distance shows Saturn diameter or
its motion distance in solar day or in its day
- To explain that let's remember one data
- Light velocity (0.3 mkm/s) moves during a solar day (86400 sec) a distance=
25920 mkm
- But
- Saturn moves during 30589 days (Uranus orbital period) a distance = 25920 mkm
(error 1%)
- Also
- Light supposed velocity (1.16 mkm/s) moves during a solar day (86400 sec) a
distance= 100733 mkm =the solar planets orbital circumferences total
- But
- Saturn moves during 120536 days a distance = 100733 mkm
- Saturn motion distance per a solar day =0.838 mkm

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Equation no. (f)
(1160000 km /24.1 km) = (466884 km /9.7 km) =48133
- Where
- 466884 = the distance be passed by Neptune during a solar day
- 1160000 km = a distance be passed by Jupiter during Mars rotation period
- Equation no. (f) shows this meaning of the previous equation clearly
- 1.16 mkm = light supposed velocity motion distance during 1 second = Jupiter
motion distance during mars rotation period.
- During 48133 seconds Mars moves 1.16 mkm and
- During 48133 seconds Saturn moves 466884 km (= Neptune motion distance
during a solar day)
- That makes the proportionality between Saturn and Neptune motions data be found
for Mars motion data also but it found between Mars motion data and light motion
distance – by that Mars motion creates (frequently) distances be passed by light
motion in defined period of time – for that reason Mars motion be related
frequently to light motion
- For example
- 2 Saturn diameters= 120536 x 2= 241072 km and
- (241072 km /24.1 km) = (300000 km/ 29.8 km)
- Mars moves the distance 241072 km in a period = 10000 seconds and
- Earth moves in 10000 seconds a distance = 300000 km = light motion distance for
1 second.
- Shortly
- Mars motion shows that light motion is an effective player in the solar system
motion.

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Notice
- 48133 = 2 x 24106
- Where
- Saturn orbital period = 10747 days = 257928 hours = 24106 x 10.7 hours
- Means
- Saturn orbital period (10747 days) has a number 24106 of Saturn days periods
Notice
- 49528 km – (4x 12104km)=1112km
- Venus (35 km/s) moves during 1112 seconds a distance = 38920 km
- 38920 seconds = 10.8 hours
- Saturn moves during 10.8 hours a distance = its circumference
-
- This notice is added because
- Uranus diameter 51118 km= 4 x 12756 km Earth diameter
- And
- Neptune diameter 49528 km be used as 49528 second by Saturn motion to move a
distance = 4 Saturn diameters
- That pushes to conclude that there's some rate for (4 parts) in all data specially

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3-7 Planet Orbital Inclination Analysis
I- Data
(1)
47.4 /6.8 = 7
(2)
47.4 /24.1 = 1.9 (error 3.5 %)
(3)
24.1 /9.7 = 2.5
(4)
9.7 / 5.4 = 1.8
(5)
13.1 /9.7 = 1.3 (error 3.5 %)
(6)
5.4/6.8 = 0.8
(7)
82.3 /4.7 =17.2 (error 2%)
(8)
27.78 /5.4 = 5.1
(9)
35/3.4 =10.29

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Data Analysis
Equation no. (1)
47.4 /6.8 = 7
- Where
- 47.4 km /s = Mercury Velocity
- 6.8 km /s = Uranus Velocity
- 7 degrees = Mercury Mars orbital inclination
Equation no. (2)
47.4 /24.1 = 1.9 (error 3.5 %)
- Where
- 47.4 km /s = Mercury Velocity
- 24.1 km /s = Mars Velocity
- 1.9 degrees = Mars orbital inclination
Equation no. (3)
24.1 /9.7 = 2.5
- Where
- 24.1 km /s = Mars Velocity
- 9.7 km /s = Saturn Velocity
- 2.5 degrees = Saturn orbital inclination
Equation no. (4)
9.7 / 5.4 = 1.8
- Where
- 5.4 km /s = Neptune Velocity
- 1.8 degrees = Neptune orbital inclination
Equation no. (5)
13.1 /9.7 = 1.3 (error 3.5 %)
- Where

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- 13.1 km /s = Jupiter Velocity
- 1.3 degrees = Jupiter orbital inclination
Equation no. (6)
5.4/6.8 = 0.8
- Where
- 0.8 degrees = Uranus orbital inclination
Equation no. (7)
82.3 /4.7 =17.5
- Where
- 4.7 km /s = Pluto Velocity
- 82.3 km /s = 2π x 13.1 km/s (Jupiter Velocity)
- 17.2 degrees = Pluto orbital inclination (error 1.7%)
Equation no. (8)
27.78 /5.4 = 5.1
- Where
- 27.78 km /s = The moon Velocity
- 5.1 degrees = The moon orbital inclination
Equation no. (9)
35/3.4 =10.29
- Where
- 35 km /s = Venus Velocity
- 3.4 degrees = Venus Orbital Inclination

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II-Discussion
- The previous data shows that the planets orbital inclinations be defined as rates
between the planets velocities-the data simply be understood – but the point is that
to discover what planet plays the main role for another planet –for example –
Saturn is the main player effective on Neptune motion data because of that their
velocities rate causes to create Neptune orbital inclination (1.8 deg) –but on the
other side – Mars is a main player for Saturn motion – by that the rate between
Saturn and Mars velocities causes to create Saturn orbital inclination (2.5 deg)–
- And also
- Uranus is the effective player on Mercury motion for that the rate between their
velocities causes to create Mercury orbital inclination (7 deg)
- The data creates a map for the solar planets motions data distribution -
- Please note
- The data gives a simple vision for strong connection – for example – Uranus
effects on Mercury and causes its orbital inclination to b 7 degrees – what result of
this event? Uranus axial tilt = 97.8 degrees = 90 deg + 7.8 degrees where (7.8 deg
= 7 deg Mercury orbital inclination + 0.8 deg Uranus orbital inclination) that
means Uranus axial tilt is perpendicular on the inclination of Mercury and Uranus
orbital inclination –
- I want to say that, the simple facts be provided by the previous data covers strong
relationships effect on the planets motions and their data.
- Now the question is
- How to define Venus orbital inclination?

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- Venus Orbital Inclination Definition
- Equation no. (9)
- 35/3.4 =10.29
- Where
- 3.4 degrees = Venus Orbital Inclination
- Uranus velocity = 6.8km/sec
- Shortly
- (6.8 = 2 x 3.4 ), means
- Uranus effects on Venus motion causes Venus orbital inclination to be 3.4 deg,
- let's explain how that's happened in following:
- Venus velocity = Uranus velocity x 5.1 , and
- Mars velocity = Pluto velocity x 5.1 , and
- The moon velocity = Neptune velocity x 5.1
- By this (5.1) Neptune motion caused the moon orbital inclination to be =5.1
degrees –Venus orbital inclination should be =5.1 degrees also
- Because of 3 reasons
- (1) The 6 Planets Velocities Are Rated
- (2) The moon orbital inclination is near to Venus
- (3) Uranus motion effect on the moon, Venus and Pluto motions
- Shortly
- Venus orbital incaution be 3.4 deg because of Uranus effect on Venus motion –and
Venus orbital inclination should be 5.1 deg as a result –but because the moon
orbital inclination =5.1 deg and very near Venus – and because the moon orbital
motion equation uses the value (1.7 deg) for the moon motion daily, that causes
Venus orbital inclination to be 3.4 degrees (5.1 deg – 1.7 deg =)

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- We notice that Earth has no orbital inclination –
- The moon orbital motion equation be discussed in point no. (7-11) of this paper
- Notice
- Uranus is the main player behind the definition of Venus orbital incaution, that
because
- 180.8 degrees = 177.4 deg (Venus axial tilt) + 3.4 deg (Venus orbital inclination)
- Where
- 180.8 degrees = 180 degrees + 0.8 degrees (Uranus orbital inclination)

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4- The Continuum Effect Proof
4-1 The Continuum Effect Proof
4-2 Saturn Motion Analysis
4-3 Planet Diameter Analysis
4-4 Why do the planets revolve around the sun if there's no sun gravity?

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4-1 The Continuum Effect Proof
I - Data
(1) (Distances)
2 x 149.6 mkm (Earth orbital distance) = 119.7 mkm (Venus Mars distance) x 2.48
227.9 mkm (Mars orbital distance) =91.7 mkm (Mercury Earth Distance) x 2.48
2 x 680 mkm (Venus orbital Circumference) =550.7 mkm (Jupiter Mars distance) x 2.48
778.6 mkm (Jupiter orbital distance) = 2π x 550.7 mkm (Venus Mercury distance) x 2.48
720.7mkm (Mercury Jupiter distance)= π x 91.7 mkm (Mercury Earth Distance) x 2.48 (1%)
1375 mkm (Mercury Saturn distance) = 550.7 mkm (Venus Mercury distance) x 2.48
1325 mkm (Venus Saturn distance) = π x 170 mkm (Mercury Mars Distance) x 2.48
2815 mkm (Mercury Uranus distance) = π x 360 mkm (Mercury orb. Circumference) x 2.48
2764 mkm (Venus Uranus distance) = 2 x 550.7 (Jupiter Mars distance) x 2.48(1%)
4267 mkm (Mars Neptune distance) = π x 550.7 (Jupiter Mars distance) x 2.48
3030 mkm (Uranus Pluto distance) = 1205 (Mars Saturn distance) x 2.48 (1.4%)
5127 mkm (Jupiter Pluto distance) = π x 655 (Jupiter Saturn distance) x 2.48
5678 mkm (Mars Pluto distance) = π x 720.7 (Mercury Jupiter distance) x 2.48 (1%)
654.9 mkm (Jupiter Saturn distance) = 84 mkm (Mars Original Point) x 2.48 (1%)
Notice
The used distances more than 60% of all distances in the solar system.
(2) Diameters
12104 km (Venus diameter) = 4879 km (Mercury Diameter) x 2.48
2 x 49528 km (Neptune diameter) = 40080 km (Earth Circumference) x 2.48
120536 km (Saturn diameter) = 49528 km (Neptune diameter) x2.48 (2%)
142984 km (Jupiter diameter) = 57655 km x 2.48
(3) Periods
10747 days (Saturn orbital period) =4331 days (Jupiter orbital period) x 2.48
59800 days (Neptune orbital period) = 2 x 12057 x 2.48
(4) Degrees

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17.4 degrees = 7 degrees (Mercury orbital inclination) x 2.48
97.8 degrees (Uranus Axial Tilt) = 39.4 degrees x 2.48
174 degrees (Venus Data) = 28.3 deg Neptune axial tilt x (2.48)2
25.2 degrees (Mars Axial Tilt) = 2 x 5.1 deg (The moon orbital inclination) x 2.48
3.1degrees (Jupiter Axial Tilt) =1.25 degrees (1/Uranus orbital inclination) x 2.48
118.3 deg (=90 +28.3) = 2 x 23.8 deg x 2.48
23.4 deg = 9.42 x 2.48 But 9.42 = 2 x 1.9 deg x 2.48
26.7 (Saturn Axial Tilt) =10.76 x 2.48
Where
17.4 deg = The Inner Planets Orbital Inclinations Total
23.8 deg = The outer Planets Orbital Inclinations Total (23.6 deg) (error 1%)
39.4 = 4π2
1.9 deg = Mars Orbital Inclination.

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II – Discussion
- The Distances Data
- The solar system has 55 distances contains the solar planets orbital distances and
their internal distances. The data provided are 28 distances of this total which
equal more than (50%) of the solar system all distances.
- The data contradicts Newton theory in 2 basic points.
- (1st
Point) The data shows that no planet motion be independent because the
planets orbital and internal distances be created in some network form- we don't
deal here with separated distances, on the contrary- we deal with one network of
distances. The distances be created together based on one geometrical design
regardless the gravitation equation. Clearly Newton is mistaken
- (2nd
Point) The distances be rated with (2.48) where Saturn orbital inclination =2.5
degrees. The data shows that they are created to be in harmony with Saturn
motion. We here don't deal with equal planets in their motions. but we deal with a
geometrical design depends on main points. And this geometrical design depends
on Saturn motion and the data be created in harmony with Saturn motion data.
- I want to say
- We have another vision contradicts Newton theory of the sun mass gravity,
Newton is wrong, but, to prove this fact we have a hard task.
- The first observation is that, The solar system geometrical design is different from
what Newton tells because of 2 reasons, (1st
reason) is, The planet motion
Independency concept refutation and the (2nd
reason) is, the solar system design be
created for Saturn motion.
- Means,
- No planet motion be done independently and the planets motions be done to be in
proportionality with Saturn motion. that means, not only the planets motions be
done depending one another but also this dependency has a direction. It's directed
toward Saturn! why? The other data is found to support this same meaning –

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- The Continuum Effect
- The continuum effect is a clear meaning we can realize that from the data. the rate
(2.48) is used between 50% of all distances in the solar system, that shows the
meaning clearly
- The dependency meaning is understandable but why the rate (2.48) be used along
very many distances? Why not different rates be used? That because the reason
which creates this rate (2.48) continuous through the solar planets motions. the
meaning is something very interesting – it's the continuum – let's use an example
to explain this meaning…..
- In ancient time there was an illness called (Leprosy), it's very interesting illness
because it infects the human, and the cloths and also the buildings!!
- How can that be possible? I don't know,
- But it's one illness and infects different forms of matters…(I think the cancer is
similar because some glass also may suffer of cancer!)
- It's the continuum effect meaning
- The reason which creates the rate (2.48) effects on (50% of all distances in the
solar system) and no force prevents its effect, still this reason has more power to
effect on some planets orbital periods, diameters, axial tilts and orbital inclinations.
- Why do I suppose the matter be created out of light?
- The light creates the matter and space
- Simply this is the fact,
- The light can creates this continuum effect through matter different data. the light
can use the distances as periods of time and vice versa
- I suppose the matter and space are created out of light simply because the matter
motion features can be created only by light motion.
- The Continuum Effect is one real force against Newton theory of the sun mass
gravity – and we can simply say that Newton is mistaken because of The Solar
System Continuum Effect Of Data.

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- I hope to show how this argument is powerful and able to disprove Newton theory
and to do that let's refer to some other data….
- In our study we have seen more rates as (1.0725) and (4.61) and (31)
- The rate (1.0725) be used as a rate between 40% of all distances in the solar
system, a list for these distances be provided in appendix no. (1) of this current
paper
- And also the rate (4.61) be used as a rate between around 50% of all distances of
the solar system, and this rate we discuss deeply in point no. (7-10) with the rate of
time between Pluto and the moon motions.
- I try to show that, the using of rates between huge number of distances (or other
data) is a usual using of data in the solar system – this feature can be created only
if the data be created by a continuum effect- let's to explain the meaning in more
clear words in following
- If the planets motions be independent, no any rate can b used among huge number
of distances as we see – this using of the rates means we deal with planets move
depending on one another – and
- If this dependency is local – means- each planet depends on another planet but
without a series of dependency – the rate (2.48) will not be continuous so long –
but will be so limited in using -
- The rates continuous using tells that we deal with some textile. It's a network
designed basically for a purpose and moves from a point to another point trying to
create one trajectory of energy which we see as a rate be used between huge
number of distances (or other data).
- The Continuum Is A Light Motion Feature. By that, sometimes the continuous
effect has to be cut. In Fact the continuum isn't cut but it's hidden behind some data
not understandable by us. let's use one example
- 142984 km (Jupiter diameter) = 2.48 x 57655 km
- Now what's this value (57655 km)?? it's very near to 57960 seconds (error 0.5%)

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- Where
- 57960 seconds be = 16.1 hours = Neptune Day Period
- If 1 km = 1 second we may find the meaning behind this data!
- But
- What's the fact really? the fact is that
- 4 Jupiter days periods = 39.6 hours = 142560 seconds
- That means,
- Jupiter diameter be =142984 km because it expresses for 4 Jupiter days periods,
- Where (142984 /142560) =(361/360)
- And
- The previous data shows there's a proportionality with Neptune day period – that's
found because Jupiter moves during its day period a distance = 466884 km =
Neptune motion distance during a solar day.
- The difficulty was that to prove the relationship between Jupiter diameter 142984
km and Jupiter 4 days periods (142560 seconds) which is a very far meaning to us
and by that the continuum effect be hidden behind the un-understood data but not
be cut.
- The simple question should be why Jupiter diameter be in proportionality with 4
Jupiter days (specifically)? Why 4 days??
- My basic fight point is to prove The Continuum Effect
- The Discussion Conclusions
- There are 2 basic reasons disproving Newton theory of the sun gravity
- (1st
Reason) The solar planets motions data be transported among the planets
- (2nd
Reason) The solar planets motions data be created in a continuum feature.

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4-2 Saturn Motion Analysis
I- Data
(1)
(27.78/9.7) = (2x 9.7/6.8) = (2x6.8/4.7)= (2 x35/24.6)= (2 x24.6/17.2) = 1.16mkm
/0.406 mkm = (0.3 mkm /104895 km)
(2)
(35/6.8) = (24.1/4.7) = (27.78/5.4) = 5.14
(3)
1.16 mkm/ 13.1 km = 602208 km /6.8 =416232 km /4.7
(4)
24.1+25.2 = 24.6 + 24.7
(5)
300000 = 27.78 x 10800 = 13.1 x 22901 = 47.4 x 6330 = 9.7 x 30928
(6)
(1163352 /29.8) = (378675 /9.7) = (300000π / 24.1) = (210816/5.4) = (2x
470416/24.1)
(7)
(373644 /9.7) = (2 x 90560/4.7) = (2 x 464166 /24.1)
(8)
2 x 466884 = π x 297228 (1%)

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(9)
119590 x (9.7)2
=24.1 x 466884
(10)
(1.16 mkm /9.7 km) =119590 = 2x 2.48 ((10747 x 24)/10.7)
(11)
(1.16 mkm /35 km) = 33182= (10747 x 9.7)/ π
(12)
(24.6/17.2) = (9.72/6.8) but (9.72/9.7) =(361/360)
(13)
(142984/90560) =(4495.1/2872.5) = π/2
(14)
10747 x 24 h = 24.6 h x 10500
But
10500 x 9.9 h = 4331 days x 24
(15)
9.7 km/s x 2 x 155597 seconds = 8 x 378675 km

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II- Discussion
Equation no. (1)
(27.78/9.7) = (2x 9.7/6.8) = (2x6.8/4.7)= (2 x35/24.6)= (2 x24.6/17.2) = 1.16 mkm
/0.406 mkm = (0.3 mkm /104895 km)
- Where
- 27.78 km /s = The Moon Velocity
- 4.7 km /s = Pluto Velocity
- 24.6 hours = Mars Rotation Period
- 17.2 hours = Uranus Day Period
- 0.406 mkm = Pluto motion distance during a solar day
- 0.3 mkm = light known velocity (0.3 mkm/s)
- 1.16 mkm = Jupiter motion distance during 24.6 hours
(There's a light beam its velocity supposed to be 1.16 mkm/s)
- I have tried to write equation no. (1) to be in the best form but it still doesn't tell
the fact clearly – let's move with its step by step
- (1st
Point)
- We see 4 planets velocities are rated one another which are (the Earth moon,
Saturn, Uranus and Pluto), these 4 planets velocities are rated with one another –
we need to know why?
- But
- The equation doesn't tell the facts clearly – the fact is that:
- During Uranus day period (17.2 h) Saturn moves 600000 km

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- And
- During Mars rotation period (24.6 h) Uranus moves 600000 km
- And
- During 2 x 12430 seconds Mars moves 600000 km
- And
- During 35.5 hours Pluto moves 600000 km
- This fact has many points to notice
- First, the distances are equal
- Second, the distance 600000 km = light motion distance for 2 seconds
- Third, the periods are defined by the 4 planets and no information are needed!
- Based on that, Saturn motion uses Uranus day period and Uranus motion uses
Mars rotation period and Mars motion uses the period 12430 sec (this period is
defined by Saturn motion because during 12430 seconds Saturn moves a distance
= 120536 = Saturn diameter), and Pluto uses (35.5 hours) (And this period = 2
Uranus Days periods with error 3%)
- (Notice Venus needs 35.8 days to pass a distance = Venus orbital distance) (error
1%) ( if 1 hour be = 1 day that makes the 2 periods are equal)
- I want to say
- The 4 planets move equal distances in periods defined by themselves and no data
is needed and the equal distance = light motion distance for 2 second….
- No pure coincidence here be found – we have some very complex geometrical
machine – but how this data be created?
- Because all distances = light motion we can consider the light motion be a basic
player behind – but how?
- The first question we have left as (Why The Velocities Are Rated?)

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- (2nd
Point)
- The second point is the number (2) in the equation
- We see clearly that, this number is used for the moon velocity where the other
planets velocities can be rated simply without this (2) but the moon forces all
planets to use this (2) to create a general harmony for the equation
- The moon has this power because of the rate (1.16 mkm/0.406 mkm), where this
part of equation doesn't use the number (2), because of that, all planets have to use
the number (2) even if the moon velocity be not found
- We need to notice that the rate (1.16 mkm/0.406 mkm) = 2.86 controls many basic
data in the solar system – that makes this rate be so powerful – let's refer to some
of this data in following
- Additional Data
- The solar planets masses total x 2 = Jupiter mass x 2.86 (error 1.8%)
- The solar planets diameters total 406000 km = Jupiter diameter x 2.86 (0.7%)
- Jupiter diameter 142984 km = Neptune diameter 49528 km x 2.86 (1%)
- Mars diameter 6792 km = Pluto diameter 2390 km x 2.86
- 511.1 deg (all planets axial tilts total) = 180 x 2.86
- 278.4 deg (the outer planets axial tilts total) = 97.8 de (Uranus Axial Tilt) x 2.86
- 5.1 deg (the moon orbital inclination) = 1.8 deg (Neptune orbital inclination) x 2.86
-
- Many other basic data can be added to show the significance of this rate (2.86)
- What I'm trying to do is that, to prove the data be created based on a geometrical
system and trying to discover it – in fact – some great machine of geometry be
found behind but because many concepts be unknown we can't catch this machine
clearly as possible

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- (3rd
Point)
- (2 x 24.6 h/17.2 h) = (2.86)
- 24.6 hours =Mars Rotation Period
- 17.2 hours =Uranus Day Period
-
- This part of equation creates a proportionality between Mars rotation period (24.6
h) and Uranus day period (17.2 h),
- Why this proportionality is found? What's the relationship between Uranus and
Mars motions?. The data tells Uranus uses Saturn motion as a mediator to Mars
motion. Why Uranus motion should have a connection with Mars motion? what a
big deal behind?
- During Mars rotation period Jupiter moves 1.16 mkm and
- During Mars rotation period Uranus moves 2 x 300000 km
- Both Motions Are Light Motions Distances?
- Why Mars Rotation Period is important for many planets motions?
- My problem is that,
- I'm afraid to write more data to avoid the confusion but on the other side no
meaning can be concluded from the (short) data – let's look inside Uranus day
period
- 17.2 hours = 61920 seconds
- This powerful period how to understand? 61920 sec = 2 x 30589 s +742 sec
- 742 seconds = 1% of 61920 seconds
- Means
- Uranus orbital period 30589 days should be used in seconds units, then
- 2 x 30589 seconds = Uranus day period 61920 second with error (1%)
- Why?? But
- Light known velocity (0.3 mkm/sec) needs 4950 seconds to pass a distance = 1484
mkm = 2 x 742 mkm

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- If 1 second = 1 mkm that makes the distance 742 mkm be found in relationship
with 742 seconds – light motion be found behind Uranus motion to create Uranus
day period and orbital period in proportionality with one another based on light
motion.,
- Why this concussion is not an imaginary idea?! because
- Uranus needs 4900 solar days to move a distance =2872.5 mkm = Uranus orbital
distance – and we know that – 1 second of light motion = 1 day of planet motion.
- Now, this deep analysis doesn't tell why Uranus day period =17.2 hours, nor tells
why Uranus day period be in proportionality with Mars rotation period 24.6 hours?
- The data be created by unknown geometrical rules and we are watchers in some
Cinema –the nature creates its great tools and we don't understand what's happing
because of our less knowledge.
- Notice
- Uranus moves during 30589 hours a distance = 748.8 mkm wit error 1% with the
distance 742 mkm
- (4th
Point)
- The data forces for some modification let's see in following
- The distance 1200000 km
- Be passed by Mercury in a period =2 x 12658 seconds, and
- Be passed by Venus in a period = 9.52 hours, and
- Be passed by Earth in a period = 40269 seconds, and
- Be passed by The moon in a period = 43200 seconds, and
- Be passed by Mars in a period = 49793 seconds, and
- Be passed by Jupiter in a period = 91603 seconds, and
- Be passed by Saturn in a period = 2 x 61920 seconds, and
- Be passed by Uranus in a period = 2 x 24.6 hours, and
- Be passed by Neptune in a period =2 x 61.7 hours, and
- Be passed by Pluto in a period =71 hours

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- The period 40269 seconds be equal Earth circumference 40080 km (error 0.5%) if
1 km = 1 second– by that the distance be passed by Earth and the Earth
circumference be used as the period of time –
- The period 49793 seconds be equal Neptune diameter (49528 km) (error 0.5%) if 1
km = 1 sec. that shows why we need 1.2 mkm and not 600000 km because if we
use 600000 km mars will use a period =(24896 second) which can be equal
Neptune radius – but for diameter we need 1.2 mkm –
- That's happened with Earth circumference also – we need 1.2 mkm because we
can't divide Earth circumference into parts.
- The period 91603 seconds has an error (1%) with the period 90560 seconds (where
90560 days = Pluto orbital period)
- Here also we need the distance 1.2 mkm because Jupiter can't use part of Pluto
orbital period
- (Notice, we usually uses the periods in days, minutes or seconds. For example
Pluto moves during 90560 seconds a distance = 425632 km = Uranus motion
distance during its day period with error 1%)
- The motions of Saturn and Uranus use the periods in 2 cycles (2 Uranus days 17.2
hours) and (2 Mars rotation periods = 24.6 h), and it's possible to use the cycles in
any number but that the distance 1.2 mkm can create a general harmony of motion
for many planets.
- Notice
- The period Mercury needs to pass 1.2 mkm = 7 hours but
- 24 hours /7 hours =3.4 (can that have a relationship with Venus orbital inclination
3.4 degrees?)
- And
- The period Venus needs to pass 1.2 mkm = 9.52 hours but
- 24 hours /9.52 hours =2.55
- (The moon orbital inclination 5.1 degrees =2 x 2.55)

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Equation no. (2)
(35/6.8) = (24.1/4.7) = (27.78/5.4) = 5.14
- Where
- 35 km/s = Venus Velocity
- 6.8 km/s = Uranus Velocity
- 4.7 km/s = Pluto Velocity
- 27.78 km/s = The moon Velocity
- Simply Equation no. (2) is produced from equation no. (1)
- Equation no. (2) shows that one force effects on the 6 planets and cause their
velocities to be rated with (5.14)
- But, again
- The equation can't tell the facts clearly, Let's try to do that in following
o Uranus moves during its day period (17.2 h) a distance = 421056 km
o Venus moves during 12104 seconds a distance = 423640 km
o Pluto moves during 90560 seconds a distance = 425632 km
o Neptune moves during 155597 seconds a distance =2x 420111 km
o The moon moves during 15328 seconds a distance = 425807 km
o Mars moves during 17660 seconds a distance = 425632 km
o The max error among these distances be 1%
o Where
o 12104 km = Venus Diameter
o 155597km = Neptune Circumference
o 90560 days = Pluto Orbital Period
o 15328 km = Mercury Circumference
o 17660 km x8= 141555 km (Jupiter diameter error 1%)
- Shortly

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- All planets move equal distances to Uranus motion distance during its day period
by using their own data except the moon uses Mercury circumference as a period
of time and Mars uses (1/8) of Jupiter diameter as a period of time
- The point is that the distance 17660 km is the basic distance in Planet 8 Days
Cycle
- The data may tell, that Mars should have a relationship with Planet 8 days cycle
- I want to say
- The simple form of the equation tells nothing about its deep fact – let's try to
deepen this discussion as possible in following
Equation no. (2) (continued)
(35/6.8) = (24.1/4.7) = (27.78/5.4) = 5.14
- This simple form of Equation no. (2) tells noting about the facts because not only
the planets velocities are rated but also the periods of time are rated and the planets
diameters and circumferences be used as periods of time in proportionality to pass
the required distance –
- Again
- We are invited to this happy party, but we get nothing of it! we don't listen any
beautiful song and not watch any interesting film, we don't listen any told joke for
laughing – we are invited visitors but we stand behind the glass wall looking but
understand nothing! Why
- Because we don't know by what geometrical rules this data be created and why.
- Why the planets have to move equal distances? What the big benefit if the planets
do? Why the planets use different sources of data? some planets use their
diameters or circumferences as periods of time others use their orbital periods by
change the units from one day into one second – the whole machine works before
our eyes and the data move from point to another point along the discussion but we
understand and learn nothing because we don't know neither the geometrical rules

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based on which the machine works nor the geometrical design by which the
machine be designed– then simply one question can expose our weak situation –
Let's ask, Why does the planet move if there's no sun gravity? Or what positive
result be produced by the planet motion?
- Notice
- 8 days of Uranus days periods =137.6 hours
- 137.6 hours = 24.6 hours (Mar rotation period) x 5.6
- What's 5.6??
- 5.1 degrees = The Moon Orbital Inclination
- 0.5 degrees = The moon angular diameter
- 5.6 degrees = the moon orbital inclination be measure above the moon body
- Also
- 137.6 hours = 8.51 x 16.1 hours (Neptune Day Period)
- 1 hour of Saturn motion = 8.51 hours of Pluto motion
- 16.1 hours of Saturn motion = 137.6 hours of Pluto motion
- That means
- 1 Neptune day period (16.1 h) can produce 8 Uranus days period (137.6 h) by
using the rate of time between Saturn an Pluto (8.51) but how? by what
geometrical rule that can be done?

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Equation no. (3)
1.16 mkm/ 13.1 km = 602208 km /6.8 km=416232 km /4.7 km
- Equation no. (3) tells
- Jupiter (13.1 km/s) moves during Mars rotation period (24.6 hours) a distance =
1.16 mkm
- And
- Uranus (6.8 km/s) moves during Mars rotation period (24.6 hours) a distance = 2 x
300000 km
- And
- Pluto (4.7 km/s) moves during Mars rotation period (24.6 hours) a distance =
416232 km
- But
- Sin (12.19 deg) x 416232 km = 88000 km (The moon daily displacement)
- The angle 12.19 degrees = 13.177 deg – 0.98562 deg
- 13.177 deg = The moon motion degrees per a solar day
- 0.9856 deg = The Earth motion degrees per a solar day
- Means, the distance 416232 km is related to the moon daily displacement – We
know that Pluto motion has some effect on The moon daily displacement but why
Mars rotation period is so effective??
- Notice
- 49528 km (Neptune diameter) x π2
=488822 km = 5.4 km/s x 90522 sec.
- But
- (488822 km = 466884 km + 2 x 10921 km the moon circumference)
- 90560 days = Pluto Orbital Period
- Notice
- 27.78 km/s (the moon velocity) x 4331 sec = 120316 km (but 120536km = Saturn
diameter) where 4331 days = Jupiter orbital period

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Equation no. (4)
24.1+25.2 = 24.6 + 24.7 = 49.3
- Where
- 25.2 degrees = Mars Axial Tilt
- 24.7 hours = Mars Day Period
-
- I don't know how this equation can work!
- Just it's accurate equation, the numbers work accurately but the units cause a great
confusion
- It's Mars own data
- The simple conclusion is that, the planet data be created of periods of time –
means- the building unit is a period of time –
- No mass and no distance – the universe building unit is a period of time – that
makes all data be created from the same kitchen – and any data can be replaced in
place of any other data – the exchange be found simply because all components are
periods of time – whatsoever we see – all things are periods of time –
- For better explanation
- Imagine we see some distance, or we have some matter with mass, or we have 3
angles of triangle…etc all these components are (periods of time)
- It's the universe secret
- And
- What's our task now?
- We have to find the player-For Whom All Components Can Be Periods Of
Time? What's the player which can see (every thing) as periods of time?
- A Conclusion (The Universe Building Unit Is A Period Of Time)

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Equation no. (5)
300000 = 27.78 x 10800 = 13.1 x 22901 = 47.4 x 6330
- Where
- 300000 km/s = Light Velocity
- 27.78 km /s = The Moon Velocity
- 47.4 km = Mercury Velocity
- 10800 sec = (1/8) x 86400 seconds
- 10921 km = The moon circumference (error 1%)
- 142984 km = Jupiter diameter = 22901 km x 2π (error 0.6%)
- 6330 sec = where Earth radius =6378 km (error 0.7%)
- The Equation shows an important observation that,
- The moon and Jupiter diameters be created equal to their rates between light
velocity (0.3 mkm/s) and their velocities (27.78 km/s and 13.1 km/s)
- Mercury motion uses (6330 sec) which be related to (Earth radius) and we have
seen that the moon uses Mercury circumference to pass the distance 425807 km
(=Uranus motion distance during its day period)
- Some deep relationship must be found between the moon and Mercury motions.
- But
- The question still has no answer
- The moon and Jupiter diameters be created as rates between light velocity and
their velocities – can that be a general rule? because no other planet use this same
rule just Mercury and defines another planet radius (Earth) and not its own
- So,
- Can a proportionality be found between planet diameter and its velocity?

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- More Data
- 300000 km = 47.4 km /s (Mercury velocity) x 6330 seconds
- 300000 km = 35 km /s (Venus velocity) x 8571 seconds
- 300000 km = 29.8 km /s (Earth velocity) x 10067 seconds
- 300000 km = 27.78 km /s (The Moon velocity) x 10800 seconds
- 300000 km = 24.1 km /s (Mars velocity) x 12430 seconds
- 300000 km = 13.1 km /s (Jupiter velocity) x 22901 seconds
- 300000 km = 9.7 km /s (Saturn velocity) x 30928 seconds
- 300000 km = 6.8 km /s (Uranus velocity) x 44117 seconds
- 300000 km = 5.4 km /s (Neptune velocity) x 55556 seconds
- 300000 km = 4.7 km /s (Pluto velocity) x 63830 seconds
- Notice
- ( 300000 km /5.4 km) =55556 = π2
(155597 km/27.78) (error 0.5%)
- Where (155597 km = Neptune Circumference)
- This notice tries to show that, Neptune circumference be used also as a rate
between light and Neptune velocities –The difficulty is
- While the moon and Jupiter diameters show direct dependency on the planets
velocities rates with light velocity, we expect this rule to be used for all planets-
this is usual thinking that any acceptable equation or rule should be used for all
planets data – also kepler laws prove this fact- my point of view contradicts this
idea – the point is that – the solar planets aren't similar planets to one another in all
data- because they are integrated with one another – that makes some data be
similar and others be different – for that reason not all equations be used by some
planets should be used by the others – we learn that from the nature – even in the
creatures creation – male and female have similar parts and different parts – the
point is that – the solar system is an integrated machine its parts are integrated with
one another – by that we need different parts to create this integration. Means the
rule is correct but not always be used by direct relationships

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Equation no. (6)
(1163352 /29.8) = (378675 /9.7) = (300000π / 24.1) = (210816/5.4) = (2x 470416/24.1) =
39040 AND (1160000/1163352) = (360/361)
- Where
- 29.8 km/s = Earth Velocity
- 300000 km/s = light velocity
- Mars moves during 12430 sec (=39040 /π) a distance = 300000 km = light motion
distance during 1 second. based on that, Mars moves during 39040 seconds a
distance = 300000 km x π
- Earth moves during 39040 seconds a distance = 1163352 km
- Saturn moves during 39040 seconds a distance = 378675 km = Saturn
Circumference
- 155597 sec x 9.7 km/s = 4 x 378675 km (error 0.35%)
- Notice
- 155597 km (Neptune Circumference) = 4 x 38899 km
- We use the period (39040 seconds) frequently, so if 1 km = 1 sec, So
- 38899 km be =39040 sec (error 0.4%)
- That means,
- The period (39040 seconds) which we have used frequently is found based on
Neptune Circumference -
- As a result
- 2 x 155597 km (Neptune circumference) = 311193.6 km
- 24.1 km/s (Mars velocity) x 311193.6 seconds = 25 seconds x 0.3 mkm/sec
- (Mars axial tilt =25.2 degrees)

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- Notice
- Neptune moves during Neptune day period (16.1 h) a distance = 2 Neptune
Circumference
- Notice
- (1160000/1163352) = (360/361)
- Light velocity 1.16 mkm/s is rated to earth motion distance 1.163352 mkm by the
rate (361/360)
- Because
- The moon orbit regresses 19 degrees per year and during 19 years the total be 361
degrees, by that all data be configured based on this rate (361/360) showing the
moon orbit effect on the solar system motion data.

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Equation no. (7)
(373644 /9.7) = (2 x 90560/4.7) = (2 x 464166 /24.1)
- Where
- 9.7 km/sec = Saturn velocity
- 4.7 km/sec = Pluto velocity
- 24.1 km/sec = Mars velocity
- 373644km = The distance be passed by Saturn during its day period (10.7 h)
(Saturn day period 10.7 h = 38520 seconds)
- 90560 days =Pluto orbital period – in data it's used as a distance = 90560 km –
- The equation tells that Pluto moves a distance = (2x 90560 km) during the period
38520 seconds = 10.7 hours = (Saturn day period)
- 464166 km = this distance is very near to the distance (466884 km) (error 0.6%)
- The equation tells that, Mars moves during (10.7 hours) (Saturn day period) a
distance = 2 x 466884 km (error 0.6%)
- We know that, Jupiter moves during its day period a distance = 466884 km =
Neptune motion distance during a solar day
- I wish the data analysis does its task and causes to get the respectful readers
attention-because
- It's some very interesting feature that the data be so limited and we discover that
each planet uses the same data which be used by the other planets – even if the
geometrical explanation be still far to be discussed but the data disproves the
independent motions or random creation
- In fact the words can't tell the facts
- It's incredible to find the numbers are so limited and simply the same numbers be
used for all planets motions – where what's used as distances for one planet be
used again as periods for another one – and by that we discover at end Saturn
depends on the period 39040 sec to move a distance = its circumference where this

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period 39040 sec be = (25% of Neptune Circumference and each 1 km be = 1
second!)
- Notice
- During 10.7 hours (38520 seconds) (Saturn Day Period)
o Mercury (47.4 km/s) moves distance = 1825848 km
o Venus (35 km/s) moves distance = 1348200 km
o Earth (29.8 km/s) moves distance = 1147896 km
o The Moon (27.78 km/s) moves distance= 1070086 km
o Mars (24.1 km/s) moves distance = 928332 km = 2 x 464166 km
o Jupiter (13.1 km/s) moves distance = 504612 km
o Saturn (9.7 km/s) moves distance = 373644 km
o Uranus (6.8 km/s) moves distance = 261936 km
o Neptune (5.4 km/s) moves distance = 208008 km
o Pluto (4.7 km/s) moves distance =181044 km =2 x 90522 km
- We notice that,
- Earth moves during (38520 seconds) a distance = 1147896 km but Jupiter moves
during a solar day a distance =1131840 km (error 1.4%)
- Can These 2 Distances Be Equal? if we neglect the error (1.4%) and consider the
2 distances be equal, why they are equal??
- We notice also that
- Uranus moves during (38520 sec) a distance = 261936 km =the distance Mars
moves in 10921 seconds (error 0.5%) (where 10921km = the moon circumference)
- I try to show that
- We don't deal with independent points may some connections connect them by
chance – but we deal with one body- each part is connected with the other parts by
several connections – that means- any planet data analysis will show another
planet data behind it! but why Uranus and Mars here?

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Equation no. (8)
2 x 466884 = π x 297228 (1%)
- Where
- 297228 km = 300000 km (error 1%)
- 466884 km = the distance be passed by Jupiter in its day period (9.9 h) = the
distance be passed by Neptune in solar day
- We have discussed this distance in the previous equation,
- Equation no. (8) tells some very interesting information
- Light motion distance for 1 second 300000 km is a diameter for a circle its
circumference be = 942478 km = 2 x 466884 km
- Now, One more surprise!
- The distance which we have analyzed deeply before, which Jupiter passes it in its
day period (9.9 h) and Neptune passes it in a solar day (24 h), and Mars passes
double this distance in (10.7 h) = (Saturn day period)
- This distance be defined by light motion (Why??)
- The planets motions simply followed light motion
- Again we don't know the used geometrical rule!
- But the planets motions be done depending on light motion – the light motion is
the train engine and the planets are the train carriages
- Why this distance 466884 km be defined based on light motion?
- Can we remember this number 942478 km ??
- We have studied it in the moon orbital triangle where the triangle be consisted of
3 dimensions their measurements were (449197 km +373000 km +120536 km),
the triangle perimeter be = 942478 km!
- Notice
- The data tells that we Will Perform A Great Progress When We Discover The
Definition Of (π) And Its Effect On The Planets Motions.
- The value (π) has a great effect on the planet motion

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- For the moon orbital triangle and its discussion
- Please read my paper.
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
https://www.slideshare.net/Gergesfrancis/the-moon-orbital-motion-geometry-ii
- Notice
- (The Distance 466884 Km)
- 466884 km = 47.4 km /s (Mercury velocity) x 9850 s
- 466884 km = 35 km /s (Venus velocity) x 13339 s = 222.3 m
- 466884 km = 29.8 km /s (Earth velocity) x 15667 s = 261 m
- 466884 km = 27.78 km /s (The Moon velocity) x 16807 s = 4.66 h
- 466884 km = 24.1 km /s (Mars velocity) x 38520/2s
- 466884 km = 13.1 km /s (Jupiter velocity) x 9.9 hours
- 466884 km = 9.7 km /s (Saturn velocity) x 48133 s
- 466884 km = 6.8 km /s (Uranus velocity) x 68660 s
- 466884 km = 5.4 km /s (Neptune velocity) x 86400 s
- 466884 km = 4.7 km /s (Pluto velocity) x 99337 s
- Notice
- 68660 km = 2π x 10921 km (The Moon Circumference)
- 30589 days = 2 x 15295 (where 15328 km = Mercury Circumference)

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Equation no. (9)
119590 x (9.7)2
=24.1 x 466884
- Where
- 466884 km = our distance which is passed by Jupiter in Jupiter day period (9.9
h) and equal the distance be passed by Neptune in a solar day period and equal half
the distance passed by Mars during 10.7 h (Saturn day period)
- How This Equation Be Found?
- We have 2 values 119590 km (which = 120536 km Saturn diameter error 0.8%)
And
- 466884 km = 3 x 155597 km (Neptune Circumference)
- Also
- We have 9.7 km/s = Saturn velocity, where
- Saturn moves during 12430 seconds a distance = 120536 km = Saturn diameter
- 12430 km x π =39040 km
- And
- 39040 km x 4 = 155597 km = Neptune Circumference
- Shortly
- The distance 120536 km (Saturn diameter) be defined by Neptune circumference
- And
- The distance 466884 km = 3 x 155597 km (Neptune Circumference)
- Where
- (Mars velocity / Saturn velocity ) = 2.48
- And
- 1.16 mkm /466884 km = 2.48

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Equation no. (10)
(1.16 mkm /9.7 km) =119590 = 2x 2.48 ((10747 x 24)/10.7)
- Where
- 119560 km = Saturn diameter (120536 km error 0.8%)
- What's the surprise of this equation?
- (10747 days x 24 hours) /10.7 hours = 24105.4
- And
- 2 x 24105.4 = 48211
- But
- 48211 seconds x 9.7 km/s = 467647 km ( = 466884 km error 0.2%)
- We know that
- 1.16 mkm /466884 km =2.48
- These notices show how the Equation no. (10) be built, but more important, the
equation shows that Saturn orbital period (10747 days) and Saturn day period
(10.7 h) be created based on a geometrical rule takes into consideration the
distances 1.16 mkm and 466884 km.
- Time after time we see much better how the planets data be created- there's a
geometrical machine behind this data and they are created toward one direction.
The light motion almost uses the distance (466884 km) by different forms and
that's the reason for which we find this distance frequently in our data and to be
used as a reference behind – there's a geometrical rule for this using and when we
discover it all questions will be answered…

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Equation no. (11)
(1.16 mkm /35 km) = 33182= (10747 x 9.7)/ π
- Where
- The equation tells
- Venus (35 km/s) moves during 33182 seconds a distance = 1.16 mkm
- And
- Saturn (9.7 km/s) moves during 10747 seconds a distance =104246 km
- Where
- 104246 km = π x 33182 km
- Let's summarize this equation in best form
- Venus (35km/s) moves a distance = 1.16 mkm x π in a period = 104121 seconds
- Saturn (9.7 km/s) moves during 10747 seconds a distance = 104121 km
- Notice (104121 seconds = 1375 minutes = 29 hours
- The moon radius =1735 km
- And
- Saturn orbital period (10747 days) = 365.25 days x 29.4 (with 29 error 1.5%)
- By that
- Venus motion data be transported to Saturn motion data based on the Earth moon
data – that may explain – why Saturn and the moon uses equal rates of time –
Venus should be considered the mother of both.
- The equation still has more secrets
- (First) the distance 466884 km Venus passes in a period = (224.7 minutes) (1%)
(where 224.7 days = Venus orbital period)
- And
- (Second) the value 1735 minutes which cause the moon radius to be 1735 km

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Equation no. (12)
(24.6/17.2) = (9.72/6.8) but (9.72/9.7) =(361/360)
- Where
- 24.6 h = Mars Rotation Period
- 17.2 h = Uranus Day Period
- The data rated to the basic gear (361/360) which we have discussed before
- The gear (361/360) is found as a result for the moon orbit regression.
- Why the data be modified based on the rate (361) as a result for the moon orbit
regression? it's very hard question to answer – the simple question we also can't
solve! Let's ask it
- Why Does The Moon Orbit Regresses?
Equation no. (13)
(142984/90560) =(4495.1/2872.5) = π/2
- Where
- 142984 km = Jupiter diameter
- 90560 days = Pluto Orbital Period
- 4495.1 mkm = Neptune Orbital Distance
- 2872.5 mkm = Uranus Orbital Distance
- This equation tries to tell that, the value (π) is an independent player in the solar
system geometry. Here the value (π) isn't related to any planet motion but it's used
for the solar system general geometrical design –it's part of the motion reason of
the solar planets –

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Equation no. (14)
10747 x 24 h = 24.6 h x 10500
But
10500 x 9.9 h = 4331 days x 24 h
- Where
- 10747 days = Saturn orbital period
- 4331 days = Jupiter orbital period
- 9.9 hours = Jupiter Day Period
- 24 hours = the solar day
- We have 3 values of 10500 which are:
- Jupiter has 10500 Jupiter days (9.9 h) in its orbital period
- Saturn has 10500 Mars rotation periods (24.6 h) in its orbital period
- Neptune in 10500 solar days moves a distance =4900mkm = Jupiter orbital
circumference – these 3 values should be equal because Jupiter moves during its
day period a distance = 466884 km = Neptune motion distance during a solar day
Equation no. (15)
9.7 km/s x 2 x 155597 seconds = 8 x 378675 km
-
- This equation tells that –
- 155597 km= Neptune circumference, if this distance be used as a period of time,
Saturn (9.7 km/s) moves during it (155597 seconds) a distance = 8 Saturn
circumferences where 8 Saturn circumferences =3.024 mkm = Venus motion
distance per a solar day

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4-3 Planet Diameter Analysis
I- Data
Planet Diameter Divided by (π) Divided by (π2
)
4879 km 1553 km 494.4 km
12104 km 3852.8 km 1226.4 km
12756 km 4060.4 km 1292.5 km
3475 km 1106.2 km 352.1 km
6792 km 2162 km 688.2 km
142984 km 45513.2 km 14487.3 km
120536 km 38367.8 km 12213 km
51118 km 16271.4 km 5179.3 km
49528 km 15765.3 km 5018.3 km
2390 km 761 km 242.3 km
- Why do we analyze the planets diameters based on the rates (π) and (π2
)? Because
I try to show that the proportionality of data isn't some random process – it's not
true- the data mentioned the proportionality- this table tries to help our analysis but
before let's summarize the idea as clear as possible in following
- The Almighty Creator uses the numbers – here – there are no periods neither
distances – the basic using depends on the numbers – He creates a series of
numbers – when the series be completed He uses this series to create the periods
and the distances (and the planets diameters), here our difficulty be seen because
we distinguish between the period and the distance –the number doesn't –
- I want to say – in the kitchen – the number 86400 is a just number – for us it be
86400 seconds (a solar day) but the kitchen still can produce 86400 mkm or 86400
minutes or 86400 hours -
- The table shows that clearly

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- For example
- 3852.8 km can be used as 38520 seconds = Saturn day period
- 1106 km can be used as 1106 mkm the distance passed by Venus in 365.25 days
- 38367.8 km can be used Venus Circumference (error 1%)
- 761 km can be used as 760 seconds the period needs by light (0.3 mkm/s) to pass
227.9 mkm = Mars orbital distance
- 45513.2 can be used as 90560/2 where 90560 days = Pluto Orbital Period
- 1226.4 km can be used as 1226.4 hours =8 Pluto days periods total
- 688.2 km can be used as 687 days = Mars Orbital Period
- 242.3 km can be used as 243 days = Venus rotation period
- It's NOT random numbers found by chance – it's a series of numbers be used in
distances, periods, planets diameters ….etc
- By that it's some very strange situation that we don't understand how the solar
planets move till now because the machine is created by some defined system- and
the mathematical analysis can help greatly to discover the basic concept behind the
machine geometrical design.
- The fighting has no meaning – it's found just because of the wrong vision – as in
the big bang theory which was a wrong theory in concept – the mistake was just
clear that the theory supposed the universe be created by some random process and
no geometrical design be found before creation –the principle itself is mistaken
because the planets data show a system of data – disproving the random creation.

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4-4 Why do the planets revolve around the sun if there's no sun gravity?
- Let's provide one idea can solve this question in following:
- The solar system geometrical design forces the planets to revolve around the sun –
this process is done basically depends on Saturn motion – that shows the rate
(2.48) is found for a geometrical necessity
- Uranus almost has a vertical effect by which Uranus causes Saturn to do its job to
direct the planets revolving around the sun
- In this process Uranus depends on Venus, Earth and Pluto motions
- But basically
- The vertical and horizontal motions harmony depends on the harmony of Earth and
Venus Motions –
- In more clear words
- Venus Mass be = 80% of Earth Mass because of the effect of Uranus orbital
inclination (0.8 degrees) or Uranus inclination be created as a result for this rate of
masses.
- This idea can be more clear when we answer the following question
- Why Saturn orbital distance = Saturn Uranus distance? And more important we
should ask if the sun, Saturn and Uranus be on a straight line (180 degrees) or on
perpendicularity (90 degrees)?
- Please Notice
- 778.6 mkm (Jupiter orbital distance) = 3.024 mkm x 257.4 = 2.57 mkm x 302.5
- 100733 mkm = 149.6 mkm x 671 mkm = 108.2 mkm x 929 mkm Where
- 3.024 mkm = Venus motion distance during a solar day
- 2.574 mkm = Earth motion distance during a solar day
- 100733 mkm = the solar planets orbital circumferences total
- 149.6 mkm = Earth orbital distance 108.2 mkm = Venus orbital distance
- 671 mkm = Venus Jupiter distance
- 929 mkm = Earth Jupiter distance (Be on 2 different sides from the sun)

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5- The Solar Planets Motions Use Different Rates Of Time
5-1 Preface
5-2 The Planets Motions Rates Of Time

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5-1 Preface
(I)
- The solar planets motions rates of time depend on the planets required periods to
move distances = their orbital distances.
- For example Venus needs 35.8 solar days to pass a distance = 108.2 mkm = Venus
orbital distance.
- The planets motions rates of time be defined based on these periods by which the
planets need to move distances = their orbital distances
- Let's write a list of these periods in following:
- Mercury needs 14.13 Solar Days (27.9 Solar Days)
- Venus needs 35.8 Solar Days
- Earth needs 58.1 Solar Days
- The moon needs 1700 Solar Days
- Mars needs 109.4 Solar Days
- Jupiter needs 687 Solar Days
- Saturn needs 1710 Solar Days
- Uranus needs 4890 Solar Days
- Neptune needs 9635 Solar Days
- Pluto needs 14547 Solar Days
- The periods are understandable simply, for example
- Earth moves during (58.1 Solar Days) a distance = 149.6 mkm = Earth orbital
distance.
- We notice, The Earth moon needs 1700 days because the moon daily displacement
=88000 km and the distance from the Earth to the sun =149.6 mkm and because of
that the moon needs 1700 days. And we notice that Saturn needs 1710 solar days
which makes the moon and Saturn rates of time are equal approximately
- We notice also that, the moon apogee radius =406000 km and this distance needs
only 4.61 days to be passed by the moon daily displacement 88000km. by that the

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moon has 2 periods of time for its orbital distance, 4.61 days for the distance from
the moon to the Earth and 1700 days for the distance from the moon to the sun.
- The planets motions rates of time be defined based on these periods.
(II)
- The planets motions rates of time be the rate between any 2 periods, let's use
Mercury rates of time as example in following
- Notice for Mercury we 27.9 days and not 14.13 days, we should explain why in a
separated point of discussion in point no. (6-9) of this paper.
- Mercury Motions Rates Of Time
- (35.8 /27.9) = 1.279, means
- 1 hour of Mercury Motion = 1.279 hours of Venus Motion
- (58.1 /27.9) = 2.078, means
- 1 hour of Mercury Motion = 2.078 hours of Earth Motion
- (1700 /27.9) = 60.8, means
- 1 hour of Mercury Motion = 60.8 hours of The Moon Motion
- (109.4 /27.9) = 3.91, means
- 1 hour of Mercury Motion = 3.91 hours of Mars Motion
- 687 /27.9) = 24.6, means
- 1 hour of Mercury Motion = 24.6 hours of Jupiter Motion
- (1710 /27.9) = 61.1, means
- 1 hour of Mercury Motion = 3.91 hours of Saturn Motion
- (4890 /27.9) = 174.8, means
- 1 hour of Mercury Motion = 174.8 hours of Uranus Motion
- (9635 /27.9) = 344.8, means
- 1 hour of Mercury Motion = 344.8 hours of Neptune Motion
- (14547 /27.9) = 520.2, means
- 1 hour of Mercury Motion = 520.2 hours of Pluto Motion
- Let's test these rates in the next point…

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5-2 The Planets Motions Rates Of Time.
MERCURY MOTION RATES OF TIME LIST
1 hour of Mercury motion = 1.279 h of Venus Motion
1 hour of Mercury motion = 2.078 h of Earth Motion
1 hour of Mercury motion = 3.91 h of Mars Motion
1 hour of Mercury motion = 24.6 h of Jupiter Motion
1 hour of Mercury motion = 61.1 h of Saturn Motion
1 hour of Mercury motion = 174.8 h of Uranus Motion
1 hour of Mercury motion = 344.6 h of Neptune Motion
1 hour of Mercury motion = 520.2 h of Pluto Motion
1 hour of Mercury motion = 60.8 h of The Earth Moon Motion
- Notice
- The planets motions rates of time cause the planets revolutions around the sun to
be done in equal periods of time.
- That because
- If 1 day of Mercury motion = 61.1 days of Saturn motion, during Saturn orbital
period (10747 days) Mercury uses a period =175.94 = Mercury day period, that
makes all planets orbital periods are equal in proportionality with their motions
rates of time.
- Let's try to prove that in following…

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Mercury Rates Of Time Test
224.7 days (Venus orbital period) = 1.279 x 175.94 days (Mercury Day Period)
365.25 days (Earth orbital period) = 2.078 x 175.94 days (Mercury Day Period)
687 days (Mars orbital period) = 3.91 x 175.94 days (Mercury Day Period)
4331 days (Jupiter orbital period) = 24.6 x 175.94 days (Mercury Day Period)
10747 days (Saturn orbital period) = 61.1 x 175.94 days (Mercury Day Period)
30589 days (Uranus orbital period) = 174.8 x 175.94 days (Mercury Day Period)
59800 days (Neptune orbital period) = 344.6 x 175.94 days (Mercury Day Period)
90560 days (Pluto orbital period) = 520.2 x175.94 days (Mercury Day Period)
- The errors are 1.4% and 1% with Neptune and Pluto orbital periods respectively,
no other error more than 1%
- The data tells, Mercury rate of time defines all planets orbital periods based on
Mercury Day Period (175.94solar days).
- Now we notice that, Mercury use 27.9 days in place of 14.13 days and use its day
period (175.94 days) in place of its orbital period (88 days). Shortly Mercury uses
a double value of its data we should discover why in point no. (6-9) of this paper.
- The data shows that the periods of time are equal – for example – 1 Mercury day -
=2.078 days of Earth motion. by that 175.94 days of Mercury motion be = 365.25
days of Earth motion. that means 175.94 days be = 365.25 days. As a result all
planets revolve around the sun in equal periods of time depending on their motions
rates of time.
- The point is, All solar planets orbital periods are defined based on these rates of
time, similar to Mercury Data Using.
- We have to test all planets motions data to prove all planets follow this same using
of data and by that we obtain a rule control the data clearly. We test all planets in
the next point no. (5)
- Then we have to discuss the planet motions rates of time meaning and effect on the
planets motions.

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NOTICE
- While we analyze the planets motions rates of time using, I wish the vision be seen
clearly from out of the analysis process.
- The analysis process tries to prove that the planets motions data be created as
layers above one another. we here deal with some fruit as (one onion) it consists of
layers above one another.
- The planet motion creates these players one above another. while the outer vision
shows (one onion) may be so strong as a rigid body but in fact it consists of layers
one above another. so the analysis process moves from one layer to the next and
we should follow this process with attention to discover how the planet data be
created and how this planet motion be in harmony with its data.
NOTICE
- In the next point no. (5) We use Mercury as an example for all planets motions
data. The point no. (5) is a simple one because we test just the rates of time in it.
but
- There are 2 important data we should keep in mind.
- The first data is the planets orbital distances which are defined also based on the
planets motions rates of time and we prove that in point no. (4.5 and 6)
- The second data is the planets required periods to move their orbital distances,
these periods have a great significance …
- I want to say,
- The planets motions rates of time are rates defined based on the required periods,
but these rates of time control all planets motions data. I have to arrange the data in
best form for that the simple test I put in points no. (4, 5 and 6) as an approach, but
many other analysis we have to discuss in the paper rest points to explain the
major significance of the planets motions rates of time.
- The basic difficulty is the theoretical explanations, for example, when someone
asks how the planet low velocity motion can use different rate of time?

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- This question I can't answer simply… also
- Another question asks,
- Why Do The Planets Motions Use Different Rates Of Time?
- Also this question is hard to answer!
- It doesn't mean, it has no answer. It has an answer.. let's write it
- The planets motions use different rates of time to work as a great clock to create
one great rate of time (1 day of the sun motion = 365 days of Earth motion)
- This rate of time is required to be built because the sun rays energy be provided by
the planets motions energies accumulation. Means, the sun rays aren't produced by
any nuclear interactions inside the sun, on the contrary, the planets motions
energies be accumulated during one year (365 days) and the sun use it on one day
and by that the energy be enough for the sun rays creation.
- The answer is surprised and my be refused…
- That's why I don't answer the theoretical questions
- I want to put the data in front of the respectful readers. The planets motions data
isn't my opinion or theory, it's the planets motions data and we have to explain
how this data be created even if all my explanations be mistaken.
- I want to say
- The planets motions data contradicts Newton theory of the sun mass gravity and
the whole description of the solar system motion. this is the point we need to
prove.
- Newton theory which is lived for 400 years created its environment inside the
physics book, that's why the contradiction has a massive negative effect.
- It's not a small point in the physics book we should repair. It's a wide vision and
understanding concerning the solar system motion. the contradiction means we
should change a great part in the physics book.

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6- The Solar Planets Rates Of Time Analysis
6-1 Preface
6-2 Venus Motion Rate of time
6-3 Earth Motion Rate of time
6-4 Mars Motion Rate of time
6-5 Jupiter Motion Rate of time
6-6 Saturn Motion Rate of time
6-7 Uranus Motion Rate of time
6-8 Neptune Motion Rate of time
6-9 Pluto Motion Rate of time
6-10 The Planets Orbital Distances Test
6-11 One Law Controls The Planets Orbital Periods And Distances
6-12 The General Discussion

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6-1 Preface
- In this point we follow the example of Mercury motion. by that we define each
planet motion rates of time relative to the other planets and prove these rates of
time define all other planets orbital periods. (and also All Orbital Distances)
- There are 2 basic tasks we have to notice in our discussion which are:
- (1st
Task) The Comparison Of The Data With Newton Vision.
- We need to consider this comparison, because it's not enough to write a sentence
as this one (Newton Description Contradicts The Planets Motions Data), this
sentence is a fact but not enough. We have to see the planets data and to follow the
planets motions different forms to see how Newton description be so far from the
truth. We here don't deal with some wrong idea we need to disprove, but we deal
with a wrong vision and we need to rearrange the data in their correct positions to
see the real picture.
- If we do that, we will discover (for example) that, the sun is the last created piece
in the solar system, the sun be created after all planets creations and motions, that
shows clearly how Newton theory is mistaken because Newton saw what's result
as a reason and what's a reason he considered as a result, means, according to
Newton we have to see a reversed vision for the truth.
- (2nd
Task) The Observation Of The Data Values
- The values are our treasures we should analyze them to their depth. For example
the moon needs 1700 solar days to pass the distance 149.6 mkm = Earth orbital
distance by using its daily displacement 88000 km and Saturn needs 1710 solar
days to move a distance = 1433.5 mkm= Saturn orbital distance, we should know
why these 2 periods are equal and what effect be done as a result
- The data which we analyze here to prove the planets motions rates of time are
priceless data we should keep and follow them – because by the analysis we can
see the different layers of motions which create the planet and its motions data.
- Notice (The Data Be Discussed In Point 6-12)

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6-2 Venus Motion Rate Of Time
I – Data
VENUS MOTION LIST
1 hour of Venus motion = (0.78) h of Mercury Motion
1 hour of Venus motion = 1.62 h of Earth Motion
1 hour of Venus motion = 3.057 h of Mars Motion
1 hour of Venus motion = 19.233 h of Jupiter Motion
1 hour of Venus motion = 47.8 h of Saturn Motion
1 hour of Venus motion = 136.7 h of Uranus Motion
1 hour of Venus motion = 269.4 h of Neptune Motion
1 hour of Venus motion = 406.7 h of Pluto Motion
1 hour of Venus motion = 47.54 h of The Moon Motion
- In Following We Provide The Data Analysis

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II–Data Analysis
175.94 days (Mercury day period) = 0.78 x 224.7 days (Venus orbital period)
365.25 days (Earth orbital period) = 1.62 x 224.7 days (Venus orbital period)
687 days (Mars orbital period) = 3.057 x 224.7 days (Venus orbital period)
4331 days (Jupiter orbital period) = 19.2 x 224.7 days (Venus orbital period)
10747 days (Saturn orbital period) = 47.8 x 224.7 days (Venus orbital period)
30589 days (Uranus orbital period) = 136.7 x 224.7 days (Venus orbital period)
59800 days (Neptune orbital period) = 266.2 x 224.7 days (Venus orbital period)
90560 days (Pluto orbital period) = 403 x 224.7 days (Venus orbital period)
- There Are Errors (1%) Only With Neptune And Pluto Orbital Periods
- Shortly
- All planets orbital periods be created based on Venus orbital period (224.7 days)
by using the rates of time between Venus and these planets –
- No error in all data more than 1% -
- The Data Proves That – The Rate of Time Controls The Solar System motion

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6-3 Earth Motion Rate Of Time
I – Data
EARTH MOTION LIST
1 hour of Earth motion = (0.48) h of Mercury Motion
1 hour of Earth motion = (0.617) h of Venus Motion
1 hour of Earth motion = 1.88 h of Mars Motion
1 hour of Earth motion = 11.8 h of Jupiter Motion
1 hour of Earth motion = 29.4 h of Saturn Motion
1 hour of Earth motion = 84.1 h of Uranus Motion
1 hour of Earth motion = 165.8 h of Neptune Motion
1 hour of Earth motion = 250.4 h of Pluto Motion
1 hour of Earth motion = 29.3 h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.48 x 365.25 days (Earth orbital period)
224.7 days (Venus orbital period) = 0.617 x 365.25 days (Earth orbital period)
687 days (Mars orbital period ) = 1.88 x 365.25 days (Earth orbital period)
4331 days (Jupiter orbital period) = 11.8 x 365.25 days (Earth orbital period)
10747 days (Saturn orbital period) = 29.4 x 365.25 days (Earth orbital period)
30589 days (Uranus orbital period) = 84.1 x 365.25 days (Earth orbital period)
59800 days (Neptune orbital period) = 163.8 x 365.25 days (Earth orbital period)
90560 days (Pluto orbital period) = 248 x 365.25 days (Earth orbital period)
- Errors (1.2% and 1%) With Neptune And Pluto Orbital Periods Respectively
- Shortly
- All planets orbital periods be created based on Earth orbital period (365.25 days)
by using the rates of time between Earth and these planets –
- No other error in all data more than 1% -

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6-4 Mars Motion Rate Of Time
I – Data
MARS MOTION LIST
1 hour of Mars motion = (0.255) h of Mercury Motion
1 hour of Mars motion = (0.327) h of Venus Motion
1 hour of Mars motion = (0.531) h of Earth Motion
1 hour of Mars motion = 6.3 h of Jupiter Motion
1 hour of Mars motion = 15.6 h of Saturn Motion
1 hour of Mars motion = 44.71 h of Uranus Motion
1 hour of Mars motion = 88.1 h of Neptune Motion
1 hour of Mars motion = 133 h of Pluto Motion
1 hour of Mars motion = 15.55 h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.255 x 687 days (Mars Orbital Period)
224.7 days (Venus orbital period) = 0.327 x 687 days (Mars Orbital Period)
365.25 days (Earth orbital period = 0.531 x 687 days (Mars Orbital Period)
4331 days (Jupiter orbital period) = 6.3 x 687 days (Mars Orbital Period)
10747 days (Saturn orbital period) = 15.6 x 687 days (Mars Orbital Period)
30589 days (Uranus orbital period) = 44.7 x 687 days (Mars Orbital Period)
59800 days (Neptune orbital period) = 88.1 x 687 days (Mars Orbital Period)
90560 days (Pluto orbital period) = 133 x 687 days (Mars Orbital Period)
- Errors (1.2% and 1%) With Neptune And Pluto Orbital Periods Respectively
- Shortly
- All planets orbital periods be created based on Mars orbital period (687 days) by
using the rates of time between Mars and these planets

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6-5 Jupiter Motion Rate Of Time
I – Data
JUPITER MOTION LIST
1 hour of Jupiter motion = (0.040) h of Mercury Motion
1 hour of Jupiter motion = (0.0419) h of Venus Motion
1 hour of Jupiter motion = (0.084) h of Earth Motion
1 hour of Jupiter motion = (0.1589) h of Mars Motion
1 hour of Jupiter motion = 2.48 h of Saturn Motion
1 hour of Jupiter motion = 7.1 h of Uranus Motion
1 hour of Jupiter motion = 14 h of Neptune Motion
1 hour of Jupiter motion = 21.1 h of Pluto Motion
1 hour of Jupiter motion = 2.47 h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.040 x 4331 days (Jupiter Orbital Period)
224.7 days (Venus orbital period) = 0.0419 x 4331 days (Jupiter Orbital Period)
365.25 days (Earth orbital period = 0.084 x 4331 days (Jupiter Orbital Period)
687 days (Mars orbital period) = 0.1589 x 4331 days (Jupiter Orbital Period)
10747 days (Saturn orbital period) = 2.48 x 4331 days (Jupiter Orbital Period)
30589 days (Uranus orbital period) = 7.1 x 4331 days (Jupiter Orbital Period)
59800 days (Neptune orbital period) = 14 x 4331 days (Jupiter Orbital Period)
90560 days (Pluto orbital period) = 21.1 x 4331 days (Jupiter Orbital Period)
- Errors (1.4% and 1%) With Neptune And Pluto Periods respectively
- All planets orbital periods be created based on Jupiter orbital period (4331days)
by using the rates of time between Jupiter and these planets

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6-6 Saturn Motion Rate Of Time
I – Data
SATURN MOTION LIST
1 hour of Saturn motion = (0.016) h of Mercury Motion
1 hour of Saturn motion = (0.0209) h of Venus Motion
1 hour of Saturn motion = (0.0339) h of Earth Motion
1 hour of Saturn motion = (0.0639) h of Mars Motion
1 hour of Saturn motion = (0.403) h of Jupiter Motion
1 hour of Saturn motion = 2.857 h of Uranus Motion
1 hour of Saturn motion = 5.63 h of Neptune Motion
1 hour of Saturn motion = 8.5 h of Pluto Motion
1 hour of Saturn motion = 1 h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.040 x 10747 days (Saturn Orbital Period)
224.7 days (Venus orbital period) = 0.0209 x 10747 days (Saturn Orbital Period)
365.25 days (Earth orbital period = 0.0339 x 10747 days (Saturn Orbital Period)
687 days (Mars orbital period) = 0.0639 x 10747 days (Saturn Orbital Period)
4331 days (Jupiter orbital period) = 0.403 x 10747 days (Saturn Orbital Period)
30589 days (Uranus orbital period) = 2.857 x 10747 days (Saturn Orbital Period)
59800 days (Neptune orbital period) = 5.63 x 10747 days (Saturn Orbital Period)
90560 days (Pluto orbital period) = 8.5 x 10747 days (Saturn Orbital Period)
- Errors (1%) Only With Neptune And Pluto Orbital Periods
- Shortly
- All planets orbital periods be created based on Saturn orbital period (10747 days)
by using the rates of time between Saturn and these planets

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6-7 Uranus Motion Rate Of Time
I – Data
URANUS MOTION LIST
1 hour of Uranus motion = (0.0057) h of Mercury Motion
1 hour of Uranus motion = (0.0073) h of Venus Motion
1 hour of Uranus motion = (0.011) h of Earth Motion
1 hour of Uranus motion = (0.022) h of Mars Motion
1 hour of Uranus motion = (0.14) h of Jupiter Motion
1 hour of Uranus motion = (0.3499) h of Saturn Motion
1 hour of Uranus motion = 1.97 h of Neptune Motion
1 hour of Uranus motion = 2.97 h of Pluto Motion
1 hour of Uranus motion = (0.349) h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.0057 x 30589 days ( Uranus Orbital Period)
224.7 days (Venus orbital period) = 0.0073 x 30589 days ( Uranus Orbital Period)
365.25 days (Earth orbital period = 0.011 x 30589 days ( Uranus Orbital Period)
687 days (Mars orbital period) = 0.022 x 30589 days ( Uranus Orbital Period)
4331 days (Jupiter orbital period) = 0.14 x 30589 days ( Uranus Orbital Period)
10747 days (Saturn orbital period) = 0.3499 x 30589 days (Uranus Orbital Period)
59800 days (Neptune orbital period) = 1.97 x 30589 days ( Uranus Orbital Period)
90560 days (Pluto orbital period) = 2.97 x 30589 days ( Uranus Orbital Period)
- No Error In All Data More Than 1% -
- All planets orbital periods be created based on Uranus orbital period (30589 days)
by using the rates of time between Uranus and these planets

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6-8 Neptune Motion Rate Of Time
I – Data
NEPTUNE MOTION LIST
1 hour of Neptune motion = (0.0029) h of Mercury Motion
1 hour of Neptune motion = (0.0037) h of Venus Motion
1 hour of Neptune motion = (0.006) h of Earth Motion
1 hour of Neptune motion = (0.011) h of Mars Motion
1 hour of Neptune motion = (0.0713) h of Jupiter Motion
1 hour of Neptune motion = (0.177) h of Saturn Motion
1 hour of Neptune motion = (0.507) h of Uranus Motion
1 hour of Neptune motion = 1.509 h of Pluto Motion
1 hour of Neptune motion = (0.1773) h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.0029 x 59800 days (Neptune Orbital Period)
224.7 days (Venus orbital period) = 0.0037 x 59800 days (Neptune Orbital Period)
365.25 days (Earth orbital period = 0.006 x 59800 days (Neptune Orbital Period)
687 days (Mars orbital period) = 0.011 x 59800 days (Neptune Orbital Period)
4331 days (Jupiter orbital period) = 0.0713 x 59800 days (Neptune Orbital Period)
10747 days (Saturn orbital period) = 0.177 x 59800 days (Neptune Orbital Period)
30589 days (Uranus orbital period) = 0.507 x 59800 days (Neptune Orbital Period)
90560 days (Pluto orbital period) = 1.509 x 59800 days (Neptune Orbital Period)
- Neptune orbital period creates an error 1.3% with all data except Pluto and
Uranus
- All planets orbital periods be created based on Neptune orbital period (59800 days)
by using the rates of time between Neptune and these planets

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6-9 Pluto Motion Rate of time
I – Data
PLUTO MOTION LIST
1 hour of Pluto motion = (0.00192) h of Mercury Motion
1 hour of Pluto motion = (0.00245) h of Venus Motion
1 hour of Pluto motion = (0.00399) h of Earth Motion
1 hour of Pluto motion = (0.0075) h of Mars Motion
1 hour of Pluto motion = (0.0472) h of Jupiter Motion
1 hour of Pluto motion = (0.1174) h of Saturn Motion
1 hour of Pluto motion = (0.336) h of Uranus Motion
1 hour of Pluto motion = (0.662) h of Neptune Motion
1 hour of Pluto motion = (0.11743) h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.00192 x 90560 days (Pluto Orbital Period)
224.7 days (Venus orbital period) = 0.00245 x 90560 days (Pluto Orbital Period)
365.25 days (Earth orbital period = 0.00399 x 90560 days (Pluto Orbital Period)
687 days (Mars orbital period) = 0.0075 x 90560 days (Pluto Orbital Period)
4331 days (Jupiter orbital period) = 0.0472 x 90560 days (Pluto Orbital Period)
10747 days (Saturn orbital period) = 0.1174 x 90560 days (Pluto Orbital Period)
30589 days (Uranus orbital period) = 0.336 x 90560 days (Pluto Orbital Period)
59800 days (Neptune orbital period) = 0.662 x 90560 days (Pluto Orbital Period)
- Pluto orbital period creates error 1% with all data.
- No error In All Data More Than 1% -
- All planets orbital periods be created based on Pluto orbital period (90560 days)
by using the rates of time between Pluto and these planets –
The Data Proves That – The Rate of Time Controls The Solar System motion

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6-10 The Planets Orbital Distances Test
- Let's refer to what we will do here
- We remember here Mercury rates of time with the other planets
- Then
- We suppose that, Mercury moves during one solar day
- And
- We will find the other planets periods of time in comparison with this 1 solar day
of Mercury motion based on these planets rates of time with Mercury
- Then
- We will discover the distances the planets pass during these periods
- Then
- We will compare these distances with Mercury motion distance for 1 solar day
=4.095 mkm
- Based on this comparison, we should test if the planets orbital distances be defined
based on these planets rates of time,
- Let's Do That In Following…

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I- Data
Mercury Rates Of Time
1 hour of Mercury motion = 1.279 h of Venus Motion
1 hour of Mercury motion = 2.078 h of Earth Motion
1 hour of Mercury motion = 3.91 h of Mars Motion
1 hour of Mercury motion = 24.6 h of Jupiter Motion
1 hour of Mercury motion = 61.1 h of Saturn Motion
1 hour of Mercury motion = 174.8 h of Uranus Motion
1 hour of Mercury motion = 344.6 h of Neptune Motion
1 hour of Mercury motion = 520.2 h of Pluto Motion
1 hour of Mercury motion = 60.8 h of The Earth Moon Motion
The Motions Distances Based On Mercury Rates Of Time
(1)
Mercury (4.095 mkm / solar day) moves during 1 day a distance =4.095 mkm
(2)
Venus (3.024 mkm / solar day) moves during 1.279 days a distance =3.867 mkm
(3)
Earth (2.574 mkm / solar day) moves during 2.078 days a distance = 5.35 mkm
(4)
Mars (2.082 mkm / solar day) moves during 3.91 days a distance = 8.14 mkm
(5)
Jupiter (1.13184 mkm / solar day) moves during 24.6 days a distance = 27.8 mkm
(6)
Saturn (0.838 mkm / solar day) moves during 61.1 days a distance = 51.2 mkm
(7)
Uranus (0.5875 mkm / solar day) moves during 174.8 days a distance = 102.7 mkm
(8)
Neptune (0.4665 mkm / solar day) moves during 344.8 days a distance = 160.8 mkm
(9)
Pluto (0.406 mkm / solar day) moves during 520.2 days a distance = 211.2 mkm

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II- Data Analysis
No. (2)
(Venus motion distance=3.867 mkm) /(Mercury Motion Distance 4.095 mkm) =0.944
Where
(Venus orbital circumference =680 mkm) /(Mercury Distance 720.7 mkm) =0.944
No. (3)
(Earth motion distance=5.35 mkm) /(Mercury Motion Distance 4.095 mkm) =1.3
Where
(Earth orbital circumference =940 mkm) /(Mercury Distance 720.7 mkm) = 1.3
No. (4)
(Mars motion distance=8.14 mkm) /(Mercury Motion Distance 4.095 mkm) = 1.98
Where
(Mars orbital circumference =1433 mkm) /(Mercury Distance 720.7 mkm) = 1.98
No. (5)
(Jupiter motion distance=27.8 mkm) /(Mercury Motion Distance 4.095 mkm) = 6.8
Where
(Jupiter orbital circumference =4900 mkm) /(Mercury Distance 720.7 mkm) = 6.8
No. (6)
(Saturn motion distance=51.2 mkm) /(Mercury Motion Distance 4.095 mkm) = 12.5
Where
(Saturn orbital circumference =9010 mkm) /(Mercury Distance 720.7 mkm) = 12.5
No. (7)
(Uranus motion distance =102.7 mkm) /(Mercury Motion Distance 4.095 mkm) =25.1
Where (Uranus orbital circumference =18048 mkm) /(Mercury Distance 720.7 mkm) = 25.1
No. (8)
(Neptune motion distance =161 mkm) /(Mercury Motion Distance 4.095 mkm) =39.3
Where
(Neptune orbital circumference =28255 mkm) /(Mercury Distance 720.7 mkm) = 39.3
No. (9)
(Pluto motion distance =211.2 mkm) /(Mercury Motion Distance 4.095 mkm) =51.6
Where (Pluto orbital circumference =37100 mkm) /(Mercury Distance 720.7 mkm) = 51.6

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III- Discussion
(A)
- Let's summarize the idea in following:
- As we have seen the planets orbital periods and distances be defined clearly based
on the rates of time which we have calculated.
- And
- The rates of time be calculated based on the required periods for the planets to
move distances = their orbital distances, means
- The required periods should be considered as the cornerstone of the rates of time
definition and using.
- Shortly
- We conclude that, the planets orbital periods and distances be created as function
in these planets required periods to move their orbital distances, let's remember
these required periods in following
- Mercury needs 14.13 Solar Days (27.9 Solar Days)
- Venus needs 35.8 Solar Days
- Earth needs 58.1 Solar Days
- The moon needs 1700 Solar Days
- Mars needs 109.4 Solar Days
- Jupiter needs 687 Solar Days
- Saturn needs 1710 Solar Days
- Uranus needs 4890 Solar Days
- Neptune needs 9635 Solar Days
- Pluto needs 14547 Solar Days
(B)
- We notice that,
- The planet motion rates of time be defined also as the rates between this planet
orbital period and the other planets orbital periods.
- As we have noticed before

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- The planets orbital period defines planet orbital Circumference but
- The planets required period defines planet orbital Distance but
- Please review the discussion in point no. (3-6 The planets motions rates of time A
Summary)
(C)
- The next step is to create one equation express these required periods of time,
- Means, if we have one equation controls the planets required periods of time, that
will create one law controls all planets orbital periods and distances.
- Let's discover this one law in the next point (5-11)

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6-11 One Law Controls The Planets Orbital Periods And Distances
- Let's Summarize The One Law Idea In Following:
(A)
- The inner planets required periods total = 235.8 days
- The outer planets required periods total = 31469 days
- The solar planets required periods total = 31705 days
- Notice
- 31469 days = 133 x 235.8 days (error 0.4%)
(B)
- The inner planets orbital periods total = 1480 days
- The outer planets orbital periods total = 196027 days
- The solar planets orbital periods total = 197027 days
- The total 197027 days = 1480 days x 133
(C)
- The solar planets orbital distances total = 16030 mkm
- 16030 mkm = 53.99 x 2 x 149.6 mkm (Earth orbital distance) (error 1%)
- Where
- 53.99 mkm = the distance be passed by Pluto in 133 days
-
- Notice
- We have discussed this data in point no. (3-6) (The planets motions rates of time
A Summary)

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6-12 The General Discussion
- What conclusions we can reach through the previous data?
- The data tries to create an approach for the planets motions data analysis… we try
to know why or how this data be created by these values?
- One notice is, Saturn motion rate of time equal approximately the moon motion
rate of time. No any source in physics book tells this information or tells that the
Earth moon and Saturn have some interaction of motions. but the data shows that's
truth.
- The rate of time of Saturn and the moon motions be equal because their motions
creates this equality. For example the moon daily displacement 88000 km needs a
period 10747 days to pass a distance = 940 mkm (Earth orbital circumference),
where (10747 days = Saturn orbital period)
- I want to say
- The previous data analysis open the planets data and arrange it in some form to
facilitate the analysis process. We try to test Newton vision for the planet motion.
here we can't show the contradictions in each point spite they are found, but we
interest to see the planet motion depth as possible. It's not enough to say that
Newton was the bad person in our physics book, it's not our objective, we need to
know why Newton is mistaken?, why the planet motion in its depth be different
from the outer observation? Why the direct vision only without data analysis
deceives us?
- For the last question I have a very interesting answer let's write it in an example for
explanation in following:
- Example For Explanation
- The moon displacement per a solar day = 88000 km
- The moon day period =29.53 solar day
- By that, the distances total which be passed by the moon in its day period should
be =(88000 km x 29.53 days = 2598640 km = 2π x 413600 km)

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- Based on this data, The Moon Apogee Radius Should Be = 413600 km
- But it's not a fact
- The moon apogee radius = 406000 km
- Means,
- The moon can't be far from the Earth at a distance more than 406000 km, and the
moon never visit the point 413600 km
- This data shows clearly we can't understand the moon motion trajectory by the
observation only but we need to analyze the motion data to know what's going on.
- Again
- How the moon apogee radius be (406000 km)? while it should be (413600 km?)
- Notice
- There's one more feature should be referred as a result because the distance
(2598640 km) is so long the moon would have to revolve around Earth through its
(new) apogee orbit
- Shortly
- Based on this data, the moon would revolve around Earth along month through the
apogee orbit whose radius (r=413600 km) and would be prevented to revolve
around Earth through any more near orbits!
- The Fact Is That,
- The moon creates an angle (θ) between the moon displacement direction and the
moon orbit horizontal level, by that, while the moon moves daily 88000 km but
this distance doesn't be accounted for the moon orbit. The orbit considers another
displacement depend on the angle, let's call it (the real displacement L)
- (The Real Displacement) L = 88000 km cos (θ)
- As a result
- The real displacement be shorter than (88000 km) and the total displacements
during (29.53 days) be less than (2598640 km) and be = (2550973 km) (-2%)

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- By this intelligent technique, the genius moon can revolve around Earth through
more near orbits and avoid to visit the point 413600 km forever and makes its
apogee radius =406000 km
- I wish the example proves the idea clearly, that we can't understand the planets
motions by observation only, but it necessitates to use the planets motions data
analysis.
- I want to say
- The previous analysis is an approach, the rest paper points use this approach to
analyze different points of the planets motions data. because of that the paper will
discuss the equality of the rates of time between Saturn and the moon.
- Let's summarize what we try to do here
- I arrange the planets motions data to enable the analysis process to be done. In our
minds we compare between Newton vision of the solar system motion and the
planets motions data analysis. By that the contradictions will be seen along the
analysis process. After we finish we should suggest our description for the solar
system motion which be in harmony with the planets motions data analysis.

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7- The Planets Motions Rates Of Time Effect Analysis
7-1 Preface
7-2 Planets Motions Rates Of Time And Distances Data
7-3 The Data Equal Distances
7-4 The Data and the planets velocities.
7-5 The Data Distances And Rates Of Time Interaction
7-6 The Data General Discussion
7-7 Mars, Jupiter and Saturn Motions Analysis
7-8 Why Saturn And The Moon Use Equal Rates Of Time?
7-9 Why Mercury Use A Double Of Its Orbital Distance?
7-10 The Rate (4.61) be used between Pluto and the moon motion
7-11 The Moon Orbital Motion Equation

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7-1 Preface
In this point we provide analyze the motions rates of time and their distances –
In next point we provide a table for the data we analyze in this point.
Let's use some of this data as example to explain how the table data works
Planet Rate of time Relative to Motion Distance
Mercury 1 day 1.279 days Venus 3.867 mkm
2.078 days Earth 5.37 mkm
3.91 days Mars 8.14 mkm
Let's explain this part of the table
1 day of Mercury motion = 1.279 days of Venus motion and Venus moves during
1.279 days a distance = 3.867 mkm
1 day of Mercury motion = 2.078 days of Earth motion and Earth moves during
1 day of Mercury motion = 3.91 days of Mars motion and Mars moves during 3.91
days a distance = 8.14 mkm
By this way the table works

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7-2 Planets Motions Rates Of Time And Distances
I- Data
(This table w have discussed before in point no. (3-6), we use it here as a reference for
the point discussion)
Planet Rate of time Relative to Motion Distance
Mercury 1 day 1.279 days Venus 3.867 mkm
days The moon
24.6 days Jupiter 27.84 mkm
61.1 days Saturn 51.2 mkm
174.8 days Uranus 102.7 mkm
344.6 days Neptune 160.8 mkm
520.2 days Pluto 211.2 mkm
Venus 1 day 0.78 days Mercury 3.194 mkm
1 day Venus 3.024 mkm
The moon
47.8 days Saturn 40 mkm
Earth 1 day 0.481 days Mercury 1.97 mkm
0.617 days Venus 1.866 mkm

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1 day Earth 2.574 mkm
The moon
250 days Pluto 101.5 mkm
Mars 1 day 0.255 days Mercury 1.044 mkm
1 day Mars 2.082 mkm
The moon
133 days Pluto 53.99 mkm
Jupiter 1 day 0.0406 days Mercury 0.1664 mkm
0.0520 Venus 0.1572 mkm
0.08474 Earth 0.2181
0.1587 Mars 0.3304 mkm
The moon
1 day Jupiter 1.1318 mkm

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14 days Neptune 6.5318 mkm
Saturn 1 day 0.01639 days Mercury 0.0671 mkm
The moon
0.4032 days Jupiter 0.4563mkm
1 day Saturn 0.838 mkm
Uranus 1 day 0.00572 days Mercury 0.0234 mkm
0.0223 days Mars 0.04657 mkm
The moon
1 Uranus 0.5875 mkm
Neptune 1 day 0.0029 days Mercury 0.0118 mkm
0.0060 days Earth 0.01552

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0.1135 days Mars 0.02363 mkm
The moon
1 Neptune 0.46656 mkm
Pluto 1 day 0.00192 days Mercury 0.00 787mkm
0.00245 days Venus 0.007435 mkm
0.007518 days Mars 0.01565 mkm
The moon
0.04739 days Jupiter 0.05364mkm
1 Pluto 0.406 mkm

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7-3 The Data Equal Distances
I-Data
(1)
102.7 mkm =0.5875 mkm /day x174.8 days
102.4 mkm = 0.838 mkm /day x 61.1 days x 2
101.5 mkm = 0.406 mkm /day x 250 days
(2)
88000 km x 29.53 = 2.5986 mkm
And
Earth motion distance per a solar day =2.574mkm (error1%)
(3)
4.163 mkm = 2.57 mkm /day x 1.62 days
4.177 mkm = 0.5875 mkm /day x 7.11 days
(4)
88.1 x 0.4665 mkm x 2 =136.7 x 0.5875 mkm (2.3%)

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II- Discussion
Equation no. (1)
102.7 mkm =0.5875 mkm /day x174.8 days
102.4 mkm = 0.838 mkm /day x 61.1 days x 2
101.5 mkm = 0.406 mkm /day x 250 days
- Where
- 0.838 mkm = Saturn Velocity per a solar day
- 0.5875 mkm = Uranus Velocity per a solar day
- 0.406 mkm = Pluto Velocity per a solar day
- And
- 1 Day Of Mercury = 61.1 Days Of Saturn =174.8 Days Of Uranus
- 1 Day Of Earth =250 Days Of Pluto
- Equation no.(1) is clear, 1 day of Mercury = 61.1days of Saturn =174.8 days of
Uranus, and
- Saturn moves during 61.1 days (51.2 mkm) and Uranus moves during 174.8 days
(102.4 mkm) the 2 distances be equal when we use the double value of Saturn
motion.
- Let's summarize the basic points in following:
(1) Uranus Orbital Distance = 2 Saturn Orbital Distance because of that all
produced distances of the table shows this fact. Uranus Motion Distance be
(always) = 2 Saturn motion distance
(2) Mercury velocity = 2 Mars velocity (error 1.7 %), because of that all produced
distances of the table shows this fact. Mercury Motion Distance be (always) = 2
Mars motion distance (error 1.7%)
(3) The table shows interesting feature and shows the rate (2) be used frequently
among many different of table data. we have to notice that the data considers
planet velocity effect= planet orbital distance effect which we need to analyze
in the general discussion.

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- Now the equality between Uranus motion distance (102.7 mkm) and double Saturn
motion distance (2 x 51.2 mkm) is a basic feature of the table but why these 2
distances = Pluto motion distance during 250 days (101.5 mkm) (error 1%)?
- Why these 3 distances are equal?
- Why any 2 distances be equal in the solar system? what's the result of this equality
of distances?
Equation no. (2)
88000 km x 29.53 = 2.5986 mkm
And
Earth motion distance per a solar day =2.574mkm (error1%)
- We understand this data clearly,
- The Earth velocity per a solar day = 2.574 mkm
- The moon displacement total during 29.53 days = 2.598 mkm
- The difference (1%) we consider the 2 distances are equal and the difference be
(1%) be found for a geometrical necessity… but
- Why these 2 distances are equal?
- What effect be done on Earth motion or the moon motion as a result for this
quality of distances?
- Notice
- The equal distances is a very important feature in the solar planets motions, we
have to know why these distances be equal because huge number of data be
created as a result for the planets distances equality – the point is that – the
equality of distances which effects greatly on the planets motions and data uses
some unknown method for us. by the equality of distances effects on the planets
motions and data but we can't catch this effect because we didn't discover the
method by which this equality effects on the planets motion. let's us one example
for better explanation.

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- Example no. (1)
- Earth moves during the solar day (24 hours) a distance = 2.574 mkm
- The moon displacements total during 29.53 days =2.598 mkm
- Pluto moves during its day period (153.3 hours) a distance = 2.593 mkm
- This equation of distances between the 3 planets produced a deep proportionality
between these planets motions data… let's refer to some of them in following
(I)
- (Earth velocity / Pluto velocity) = (Pluto Day period/ earth day period) = 6.37 (0.8%)
- Pluto orbital distance 5906 mkm = Earth orbital circumference 940 mkm x 2π
- Pluto orbital period 90560 days = Earth Cycle (1461 days) x 2π3
(II)
(a)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
(b)
Tan (12.2) x 708.7 hours = 153.3 hours
(c)
Tan (13.17) x 655.7 hours = 153.3 hours
(d)
2 x 153.3 h = 4.61 x 66.5 But
(708.7 h /10.7 h) = (655.7 h /9.9 h) =66.23 (error 0.4%).
(e)
413600 km cos (10.96 deg) = 406000 km
(f)
(10.96 deg /1.7 deg) = (153.3 h /24 h) (error 1%)
Notice
4.7 km/sec x 88000 seconds = 413600 km

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Equation no. (3)
4.163 mkm = 2.57 mkm /day x 1.62 days
4.177 mkm = 0.5875 mkm /day x 7.11 days
- 1 day of Venus motion = 1.62 days of Earth motion, Earth moves during this
period (1.62 days) a distance = 4.163 mkm
- 1 day of Jupiter motion = 7.11 days of Uranus motion, Uranus moves during this
- The 2 distances are equal approximately (error around 0.3%)
- Why the 2 distances are equal?
Equation no. (4)
88.1 x 0.4665 mkm x 2 =136.7 x 0.5875 mkm (2.3%)
- 1 day of Venus motion = 136.7 days of Uranus motion, Uranus moves during this
- 1 day of Mars motion = 88.1 days of Neptune motion, Neptune moves during this
period (88.1 days) a distance = 41.1 mkm for that reason the rate (2) is used and
then the value (41.1 be 82.2 which is different from 80.3 with 2%)
- Again
- Why the distances are equal?
- I wish our try to analyze the planets motions data be seen as clear as possible… the
classical vision which tells the planets move independent motions be refuted
frequently by different data of planets motions. we here depend on the suggested
vision which tells the planets motions be done by planets motions dependency on
one another. that tells the equality of distances can't be created by any random
process. The equality of distance be done by geometrical necessity which is used
by planets motions. that means, if these distances aren't equal the planets motion
necessitate to change as a result….
- The difficulty is, we can't catch the distances equality effect on planets motions.
As a result we can't understand what would happen if these distances aren't equal

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- Here, in more clear light
- We can see the mistake of Newton theory of the sun mass gravity. The basic
difficulty is, Newton supposed that the planets motions be independent from one
another. by that all previous data should be created by some random process and
pure coincidences of numbers. The sun mass gravity isn't a theory we need to
remove from the physic book. It's the parent of the big bang theory – the sun mass
gravity is a result of the wrong in vision and wrong in the thinking direction and
description. The basic illness behind is the hypothesis that the solar system be
create out of any mentioned geometrical design.
- The basic description told that, the planets be created by some random process and
without any geometrical design found before this creation.
- That's why we fight against Newton so strongly
- It's not the wrong idea of the sun as a reason for the planets motion while in fact
the sun be created after all planets creation and motions –This is not the point we
fight Newton for – the point is that – Newton supposed the whole machine be
created by some random process without a geometrical design found before – that's
the main point-
- On The Contrary
- There Is A Geometrical Design Found Before Any Planet Creation.
- The planet data be created based on some map be defined before this planet
creation. here is the point-
- The next question is
- Who created this design which is found behind the planets creation?
- The light beam
- For that reason we fight against Newton, Because
- While the universe is create basically out of light and the matter be created as a
form of light (coherence) or (interference) by that there are 2 different universes
around us, the light motion network universe and the matter motion universe

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- The planets be as ships sail over sea,
- The ships are the planets and the sea is the light motion network – by that – light
motion (continuously) effect on the planets motions. That's why our equations be
created depending on geometrical necessities even if we don't know these
necessities because the light motion creates these geometrical necessities and
create the planets motions data.
- Newton simply remove the other universe and told us that the universe is these
planets matters and distances where they define their motions by their-selves but
when we analyze the data always found that a strange players are found an effect
on the planets motions data – as a result the idea told by Newton contradicts
(frequently) the planets data.
- Now Newton idea is similar to some claim tells the animal is a body only, and in
this case I can't distinguish between a living animal and a dead one
- The point is that, the random creation and motion independency removes the other
universe which is found behind and so we still imprisoned behind the sun mass
gravity concept trying to understand how this concept causes the planets motions
while the data (frequently and always) be in contradictions.
- Let's remember these contradictions in following
- First,
- Newton told the planet orbital distance be defined by the gravitation equation, but
The planets order disproves the gravitation equation frequently, for explanation
(the planets initial conditions claim) be invented and so the contradiction be
covered – But- no support from the planets order for the gravitation equation – and
why it's acceptable
- Second
- Newton told the planet velocity be defined based on the masses gravity force, but
(Venus velocity/ Uranus velocity) = (Mars velocity/ Pluto velocity) = (the
velocity/ Neptune velocity)

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- This proportionality of velocities isn't supported by masses rates and by that the
definition of velocity violate the law and concept which Newton defined!
- Again planets data against Newton
- One more problem in Newton theory of the sun mass gravity that, the theory
doesn't tray to explain how the planets data be created? and of course Newton
supposed that the planets use the same rate of time –
- I want to say
- Newton theory be so far from the truth of the planets creations and motions – the
basic point is that – Newton depended on the outer observation as a basic reference
and didn't use any analysis of the planets motion – this point essentially is the big
bang mistake which is found in Newton theory – because any planets data analysis
can simply disprove the big bang theory, because the big bang concept tells the
solar group be created by some random process and without any geometrical
design be found before the planets creation – this is perfectly the point by which
Newton theory of the sun mass gravity be refuted – because the solar group is built
based on a geometrical design be found before any planet creation – the
geometrical design be created by light motion which is found before any planet
creation and motion– the light is found before the matter -

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7-4 The Data and the planets velocities.
- In the table there are 3 important values which are (2.078 – 3.057 – 2.48)
- Where
- 1 day of Mercury =2.078 days of Earth
- But
- 2.082 mkm per solar day = Mars velocity
- And
- 1 day of Venus =3.057 days of Mars
- But
- 3.024 mkm per solar day = Venus velocity (difference with 1%)
- And
- 1 day of Jupiter = 2.48 days of Saturn
- But
- (2.574 mkm (Earth velocity daily) + 2.4 mkm (the moon velocity daily)) /2 = 2.48
mkm per a solar day
- Means 2.48 mkm daily is the average velocity for Earth and the moon motions
- By that we have 3 velocities which be used as rates of time these velocities are:
- (1) Venus velocity per a solar day 3.024 mkm
- (2) The velocity 2.48 mkm per a solar day (the average of Earth and the moon)
- (3) Mars velocity per a solar day 2.082 mkm
- And Mercury velocity = 2 Mars velocity (error 1.7%) and the rate (2) be used
frequently in the table data.
- That means,
- The inner planets velocities be produced among the rates of time
- First
- Let's test what would happen if the rate of time be equal a planet velocity – let's
test that with Mars in following…
-

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(1) Mars Velocity = Mercury Earth Rate Of Time
Mars velocity 2.082 Earth Rate Mercury Rate
2.082 x 1/2.082 (Mercury) = 1
2.082 x 1/1.62 (Venus) =1.279
2.082 x 1.88 (Mars) =3.91
2.082 x 11.8 (Jupiter) 24.6
2.082 x 29.4 (Saturn) 61.1
2.082 x 84.1 (Uranus) 174.8
2.082 x 165.8 (Neptune) 344.6
2.082 x 250 (Pluto) 520.2
- The data shows the idea clearly
- Earth column shows the rates of time between the Earth and the other planets
- Mercury column shows the rates of time between Mercury and the other planets
- 2.078 is the rate between earth and Mercury (means 1 h Mercury =2.078 h Earth)
- 2.082 mkm = Mars Velocity Per A Solar Day
- By that simply
- Earth column be used as periods of time and Mercury columns be used as
distances passed by Mars during these periods of time
- The same result will be told with the 2 other velocities (3.024 mkm Venus velocity
per a solar day and 2.48 mkm the average velocity of Earth and the moon per a
solar day)
- Let's see their tables in following

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(2) Venus velocity 3.024 =Venus Mars Rate Of Time (3.057) (error 1%)
Venus velocity 3.024 Mars Rate Venus Rate
3.024 x 0.255 (Mercury) = 0.77
3.024 x 0.327 (Venus) = 1
3.024 x 0.531 (Earth) = 1.62
3.024 x 6.3 (Jupiter) = 19.2
3.024 x 15.6 (Saturn) = 47.8
3.024 x 44.7 (Uranus) = 136.7
3.024 x 88.1 (Neptune) = 269.7
3.024 x 133 (Pluto) = 406.7
Max error 1%
(3) The Average Velocity 2.48 = Jupiter Saturn Rate Of Time
The average Venus 2.48 mkm Saturn Rate Jupiter Rate
2.48 x 0.0163 (Mercury) = 1/24.6
2.48 x 1/47.8 (Venus) = 1/19.2
2.48 x 1/ 29.4 (Earth) = 1/11.8
2.48 x 1/15.6 (Mars) = 1/6.3
2.48 x 1/2.48 (Jupiter) = 1
2.48 x 2.857 (Uranus) = 7.1
2.48 x 5.63 (Neptune) = 14
2.48 x 8.51 (Pluto) = 21.1
Max error 1%
- The data shows simply
- One column works as periods of time and the other column work as distances
- The idea is clear – but we don't know why the inner planets velocities only be
found among the planets motions rates of time? Why not the outer planets?!

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- Comments And Questions
- The inner planets velocities are found among the motions rates of time, and that
may cause the planets velocities proportionality – as we have seen before – let's
remember this data in following:
- (1)
- (Venus Velocity / Uranus Velocity) = (Mars Velocity / Pluto Velocity) = (the
moon velocity/ Neptune)
- (2)
- (Mercury velocity / Venus Velocity) = (Jupiter Velocity/ Saturn Velocity)
- (3)
- (Earth velocity /Mars velocity) = (Uranus Velocity / Neptune Velocity) (error 2%)
- This proportionality of planets velocities must be created by using the planets
motions rates of time because the inner planets velocities be used as rates of time
of the planets motions.
- That means, the planets velocities be in proportionality based on interaction of
motions done by the planets motions rates of time – that tells how the machine
transports the data through the planets
- The data be transported (as the velocities proportionality rates) be done by using
the planets motions rates of time -
- But
- We still need to answer the question – how the planets motions rates of time
effect on the planets motions. where the motions rates of time be transported
among the planets and transport the motions data with it. but how this
transportation process is done? This question should be answered when clearly we
know how the planets motion –while no sun gravity is used and the hypothesis
tells that the matter is created out of light and by that the matter is created basically
in motion - the transportation process should be done by the light beam from
which the planets be created.

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7-5 The Data Distances And Rates Of Time Interaction
- This point deals with the table distances produced with planets motions, where
these distances equal rates of time – for example
- 1 day of Venus motion =3.057 days of Mars motion and Mars moves during these
- 1day of mars motion =6.3 days of Jupiter motion
- If
- 1 mkm = 1 day
- The distance 6.3 mkm =6.3 days
- We analyze this data by this method to show that some continuum be found
through this data – we should discuss that after the data provision – but let's
summarize the idea in following….
- Some continuous effect be found through the planets motions data -
- This effect uses periods of time and distances through different planets – by that
the planet itself be As A Point On A Straight Line – the planet here isn't the
player but be the board on which the player writes – again – the planet in this case
be as a hole but the player be as a digger – now this player may be the planet
motion or other planets motions or light motion found behind the board.
- That's what I try to tell
- The data be created by some powerful hand moves through the planets, the planet
here be as a gear be assembled in some greater machine. The planet has to move
because the machine pushes it. and by the planet motion the machine data be seen
in this planet motion.
- Let's see the data in following

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I- Data
(A)
- 1 day of Venus = 3.057 days of Mars and mars moves during (3.057 days) a
distance =6.3 mkm (1 day of mars =6.3 days of Jupiter)
(B)
- 2 days of Venus = 2 x 269.7 days of Neptune and Neptune moves during (2 x
269.7 days) a distance = 250 mkm (1 day of Earth =250 days of Pluto)
(C)
- 1 day of Venus = 406.7 days of Pluto and Pluto moves during (406.7 days) a
distance = 165.1 mkm (1 day of Earth =165.1 days of Neptune)
(D)
- 1 day of Earth = 0.481 day of Mercury and Mercury moves during (0.481 days) a
distance = 1.97 mkm (1 day of Uranus =1.97 days of Neptune)
(E)
- 1 day of Earth = 0.671 day of Venus and Venus moves during (0.671 days) a
distance = 1.88 mkm (1 day of Earth =1.88 days of Mars) (error 0.8%)
(F)
- 1 day of Earth = 1.88 days of Mars and Mars moves during (1.88 days) a distance
= 3.91 mkm (1 day of Mercury =3.91 days of Mars)
(G)
- 1 day of Earth = 29.4 days of Saturn and Saturn moves during (29.4 days) a
distance = 24.6 mkm (1 day of Mercury =24.6 days of Jupiter)
(H)
- 1 day of Mars = 6.3 days of Jupiter and Jupiter moves during (6.3 days) a
distance = 7.11 mkm (1 day of Jupiter =7.11 days of Uranus)

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(I)
- 1 day of Jupiter = 2.48 days of Saturn and Saturn moves during (2.48 days) a
distance = 2.078 mkm (1 day of Mercury =2.078 days of Earth) –also (2.082mkm
per solar day = Mars velocity)
(J)
- 1 day of Jupiter = 21.1 days of Pluto and Pluto moves during (21.1 days) a
distance = 8.56 mkm (1 day of Saturn =8.51 days of Pluto) (error 0.7%)
(K)
- 1 day of Saturn = 2.857 days of Uranus and Uranus moves during (2.857 days) a
distance = 1.52 mkm (1 day of Neptune =1.509 days of Pluto) (error 0.7%)
II- Discussion
- We notice that, the most distances which can be used as rates of time be found in
Earth and Venus data, then there are some few rates in Mars, Jupiter and Saturn,
then no more planets distances can be used as rates of time
- How Does This Machine Work?
- Why the planets motions produce distances can be used as rates of time? Is this
feature found only in this table which I have created? of course not, it's feature of
the planets motions – for example
- Mercury moves during its rotation period (1407.6 h) a distance =243 mkm (1%)
- And
- Mars moves during Venus day period (2802 h) a distance =243 mkm
- Where 243 solar days = Venus rotation period
- One more example
- Venus moves during 365.25days a distance = 2π x 175.94 mkm where (Mercury
day period =175.94 solar days)
- The pure coincidence of numbers claim is useless and gave nothing, let's analyze
some of this data in following:

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(1st
Point)
I-Data
(1)
1 day of Earth motion = 29.4 days of Saturn motion, and Saturn moves during 29.4
days a distance = 24.6 mkm
(2)
Jupiter moves during 29.4 days distance = 33.3 mkm
(3)
0.838 mkm x 33.3 days =1.1318 mkm x 24.6 days = 27.9 mkm =47.4 x 0.5875
And
(24.6 mkm/0.838 mkm/day) = (33.3 mkm /1.1318 mkm/day)
(4)
Mercury moves during 27.9 days a distance = 2 x 57.2 mkm (mercury orbital distance
57.9 mkm error 1%)
(5)
1 day of Mercury motion = 24.6 days of Jupiter motion
(Notice No.1 47.4 km/s x 6.8 h x 3600 s = 1.16 mkm)
(Notice No.2 175.94 days =6 days x 29.33 mercury moves during 6 day 24.6 mkm)
(Notice No.3 33.48 hours = 120536 seconds, but 120536 km =Saturn diameter)
(6)
(29.4/27.9) =(12756 km/ 12104 km)

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II-Discussion
- Let's summarize the previous data in some understandable form
- 1 Day of Earth motion be = 29.4 days of Saturn motion, and Saturn moves during
this period 29.4 days a distance = (24.6 mkm)
- 24.6 mkm of Saturn be used as 24.6 solar days by Jupiter, a planet motion distance
be used as a period of time by another planet.
- Jupiter moves during (24.6 days) a distance = 27.9 mkm
- 27.9 mkm of Jupiter motion be used by Mercury as a period of time and be used as
(27.9 days)
- Mercury moves during (27.9 days) a distance = 2 x 57.2 mkm (mercury orbital
distance = 57.9 mkm error 1%).
- Where
- 1 day of Mercury motion = (24.6 days) of Jupiter motion
- And
- 1 day of Jupiter motion = (2.48 days) of Saturn motion.
- Shortly
- We have some transportation of data from Saturn to Jupiter to Mercury…
- We can explain the previous data only by transportation of data because no
random process can produce this data…
- The data is more complex. And I can't extend the discussion greatly because I'm
afraid from the confusion… but
- We should see that, Uranus moves this distance (24.6 mkm) in 47.4 days where
47.4 km/sec = Mercury velocity… the notice is that, (Mercury moves during 6.8
hours a distance =1.16 mkm where 6.8 km/sec = Uranus velocity).
- Let's write the analysis of the distance (24.6 mkm) in following

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- (24.6 mkm) = 4.095 mkm x 6 days
= 3.027 mkm x 8.13 days
= 2.574 mkm x 9.55 days
= 2.4 mkm x 10.25 days
= 1.1318 mkm x 21.7 days
= 0.838 mkm x 29.35 days
= 0.5875 mkm x 41.8 days
= 0.46656 mkm x 52.7 days
= 0.406 mkm x 60.6 days
- Now let's see the second point in following…

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(2nd
Point)
I-Data
(1)
1 day of Jupiter motion =21.1 days of Pluto motion, but Pluto moves during 21.1 days
a distance = 8.51 mkm
(2)
1 day of Saturn motion = 1 day of the moon motion = 8.51 days of Pluto motion.
II-Discussion
- If 1 mkm be = 1 day, so
- 1 day of Saturn motion = 8.51 days of Pluto motion and 1 day of Jupiter motion
causes to be equal 8.51 days of Pluto motion.
- 1 day of Jupiter motion = 2.48 days of Saturn motion
- But here we see that 1 day of Jupiter =8.51 days of Pluto and 1 day of Saturn
=8.51 days of Pluto.
- That means,
- 1 day of Saturn motion should be = 1 day of Jupiter motion relative to Pluto
- As a result
- The rate 2.48 between Jupiter and Saturn be transported to Pluto motion data and
because of that 90560 days (Pluto orbital period) = 2.48 x 37100 days (where
37100 mkm = Pluto orbital circumference)
- I try to prove, different data shows the transportation of data among the planets.
- Notice
- The rate 2.48 be transported from Pluto data to Earth data because of that (365.25
days /149.6 mkm) = 2.48 (error 1.5%), we should know how this rate be
transported to the Earth later.

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(3rd
Point)
I-Data
(1)
Saturn moves during 8.51 days a distance = 7.13 mkm
(1 day of Jupiter motion =7.11 days of Uranus motion) and
(2)
Pluto moves during 7.11 days a distance = 2.895 mkm
(1 day of Uranus motion =2.96 days of Pluto motion) (with 2.895 the error =2%)
II-Discussion
- The data tries to show that, the planets motions rates of time creates some series in
data. and by that planets data be created based on other planets data in some series.
- Here we have no pulses of data but we have some direction and the data be
transported or produced based on this direction.
- I wish the data proves the idea clearly
- We are very far from Newton theory of the sun mass gravity, the planets aren't
some rigid bodies separated from one another and found by some random process.
The planets are building be created based on one another and by participation of all
members according to their motion and energy.
- The mistake isn't just one point but the mistake is a general direction. Newton had
lost into the imagination and created and idea completely different from how the
machine works. By this imagination the splendid geometrical design of the solar
system be covered

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(4th
Point)
I-Data
(1)
24.6 mkm = 2.57 mkm (Earth motion daily) x 9.55 days
(1.1318 mkm x 8.51 days = 9.6 mkm)
(2)
24.6 mkm = 1.1318 mkm (Jupiter motion daily) x 21.7 days
(21.9 mkm = 8.51 days 2.57 mkm)
(3)
2.57 mkm x 9.55 = 1.1318 mkm x 21.7 days = 29.4 days x 0.838 mkm
(0.838 mkm Saturn Motion Distance During A Solar Day)
Notice 8.51 mkm = 88000 km x 96.7 (the moon axial tilt 6.7 deg +90 deg =96.7 deg)
II-Discussion
- The previous data be provided for 2 reasons let's summarize them in following:
- (1st
Reason)
- The data shows a system of data. we deal with the same numbers which are used
tenths of time. This behavior is the geometrical rule behavior and no pure
coincidences or any random process can produce this data.
- Shortly, we deal with a geometrical machine which produces the data.
- (2nd
Reason)
- I have provided the data may someone can discover the geometrical rule based on
which this data is created. Let's try with it as we can in following
- (1)
- We have 2 basic players which are Jupiter and Saturn, the data uses their motions
with Earth and Mercury (Point no. 1) and with Pluto (Point no.2)
- The same 2 players Jupiter and Saturn … this is the first observation
- The second observation be that, the used rule almost the same, because Saturn
moves a distance =24.6 mkm and Jupiter uses a period =24.6 days (in point no. 1)
and

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- In Point no. (2)
- Pluto moves the distance (8.51 mkm) based on it rate of time with Jupiter and 1
day of Saturn motion be = 8.51 days of Pluto. here the motion be done by Pluto in
compassion with Jupiter and Saturn data
- From that we understand
- Jupiter and Saturn motions do some specific job for Earth and Mercury on one side
and for Pluto on the other side.
- Now
- We should notice that, the connection between Earth and Mercury depend on the
value (24.6 mkm or day or hours)
- That may tell us, Jupiter and Saturn tried to connect Mercury and Earth with Mars
because the basic used value is (24.6 hours =Mars rotation period)
- Now we can reach to some conclusion
- The 2 planets (Mars and Pluto) had migrated from their original orbital distances
to the current one. The solar system distances be created as a network, we can
imagine these distances be created as a chess board. The migration of the 2 planets
caused confusion for the distances distribution and by that the planets motions
tried to repair the negative effects of the 2 planets migration. After Saturn creation,
the repair process be started, where Saturn and Jupiter tried to connect the solar
system together as a unified unit. By that Jupiter and Saturn motions connect
between Mercury and Earth on one side with Mars and with Pluto on the other
side. That may explain the previous data.
- But
- There's something important in this vision,
The value 24.6 mkm or days or hours is a cornerstone in the solar group repair
process. This value in inherited from Mercury because this value Mercury defined
before the planets migration. Mercury insist to use this value (24.6) because by that
the repair process will be built based on the solar system original geometrical design.

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7-6 The Data General Discussion
- About What This Table Data Analysis Argue?
- We have 2 clear visions
- Newton Theory Of The Sun Mass Gravity And Its Description For The Planets
Motions – which considers the planet motion be independent from all other planets
and the planets move by the sun mass gravity – and this motion be done even if
one planet only be found in the solar group.
- The paper suggested vision tells that, the solar group is one machine, and each
planet is part of this machine by that each planet motion and data be created
depending on the other planets motions and data
- We analyze the planets data in some form to create confidence in the suggested
vision against Newton theory
- Our suggested vision has an advantage over Newton theory because we try to
explain how the planets motions data be created –
- For example
- Newton would tell that, the table data be created by pure coincidence of numbers,
but we see clearly that the table data be created based on a system of data. We
didn't find any feature of random process as a reason behind this data. for example
we have the rate (2) be found frequently in data but we don't find any other rates
repeated frequently as this rate, and the fact tells that Uranus orbital distance =2
Saturn orbital distance and mercury velocity = 2 Mars velocity (error 1.7%) by that
there's some logical conclusion to find the rate (2) in the table data and not any
other rate – that shows we don't deal with some random process but we deal with
directed data.
- By that, the table data provides a description for one feature of the solar planet
motion features –here we have some advantage against Newton.
- Now, we have to ask

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- Did we understand this table data?
- For example
- Pluto moves during 15.6 days a distance =6.3 mkm where
- 1 day of Mars = 15.6 days of Saturn and
- 1day of Mars = 6.3 days of Jupiter and
- How can we explain this data?
- Why Pluto velocity be created as a rate between Jupiter, Saturn and mars data?
- Let's ask one more question
- Why the inner planets velocities only be found in the planets motions rates of
time?
- I suppose that the inner planets be created with charges by that the Earth is the
great electron and the rest inner planets together be the great positron – I suggest
this hypothesis because Earth mass alone = the rest inner planets masses total,
(error 1%)
- and
- The electron and positron are 2 particle equal in mass
- This idea tries to attribute some different charges for the inner planets, and because
the charges are different the inner planets create an electric field for their motions.
- The accurate motion of planets can depend on electric filed in place of the sun
mass gravity and also the electric field idea be more suitable for the planets
motions more than the sun gravity force –
- Also I suppose the outer planets motions depend on the inner planets motions,
means the motion be transported from the inner planets to the outer planets.
- This description be discussed in more details in (the Cycle 2737 years analysis)
point no. (8)

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7-7 Mars, Jupiter And Saturn Motions Analysis
I - Data
(1)
- 1 hour of Mars Motion = 6.3 hours of Jupiter Motion = 15.56 hours of Saturn
Motion = 44.6 hours of Uranus Motion = 88 hours of Neptune motion = 132.7
hours of Pluto motion
(2)
- 4331 days (Jupiter Orbital Period) =2π x 687 days (Mars Orbital Period)
- 1433 mkm (Saturn Orbital Distance) =2π x227.9 mkm (Mars Orbital Distance)
- 10747 days (Jupiter Orbital Period) =2.5 x 4331 mkm (Jupiter Orbital Period)
- 24.1 km/s (Mars Velocity) =2.5 x 9.7 km/s (Saturn Velocity)
- 24.6 h (Mars rotation period) =2.5 x 9.9 h (Jupiter Day Period)
- ((10747 days x 24 h) /24.6 h) = ((4331 days x 24 h) /9.9h) = 10485
- 3.1 deg (Jupiter Axial Tilt) x 2 = (2.5 deg = Saturn orbital inclination)2

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II –Discussion
Equation no. (1)
- 1 hour of Mars Motion = 6.3 hours of Jupiter Motion = 15.56 hours of Saturn
Motion = 44.6 hours of Uranus Motion = 88 hours of Neptune motion = 132.7
hours of Pluto motion
- i.e.
- 1 Solar Day of Mars Motion = 6.3 Solar Days of Jupiter Motion = 15.56 Solar
Days of Saturn Motion = 44.6 Solar Days of Uranus Motion = 88 Solar Days
of Neptune motion = 132.7 Solar Days of Pluto motion.
- Let's define the distances which these planets pass during these periods of time
- Mars (2.08 mkm per solar day) moves during 1 solar day a distance = 2.082 mkm
- Jupiter (1.1318 mkm per day) moves during 6.3 solar days a distance = 7.13 mkm
- Saturn (0.838 mkm per day) moves during 15.56 solar days a distance =13.1 mkm
- Uranus (0.5875 mkm per day) moves during 44.6 days a distance=26.22 mkm
- Neptune (0.466560 mkm per day) moves during 88 days a distance = 41.05 mkm
- Pluto (0.406 mkm per day) moves during 132.7 solar days a distance =53.88 mkm
- Based on that
- Mars during (1 solar day) moves 2.082 mkm
- Jupiter during (6.3 solar day) moves 7.13 mkm
- Saturn during (15.5 solar day) moves 13.1 mkm
- Uranus during (44.6 solar day) moves 26.22 mkm
- Neptune during (88 solar day) moves 41.05 mkm
- Pluto during (132.7 solar day) moves 53.88 mkm

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Data Analysis
(1)
- Saturn motion distance = 13.1 mkm = Mars Motion Distance 2.08 mkm x 2π
- This data explains why
- Saturn orbital circumference 9007 mkm = Mars orbital circumference 1433
mkm x 2π
(2)
- Uranus motion distance = 26.22 mkm = Saturn Motion Distance 13.1 mkm x 2
- Uranus orbital circumference 18048 mkm = Saturn orbital circumference
9007 mkm x 2
(3)
- Neptune motion distance =41.05 mkm =Saturn Motion Distance 13.1 mkm x π
- Neptune orbital circumference 28255 mkm = Saturn orbital circumference
9007 mkm x π
(4)
- Pluto motion distance =53.9 mkm =Saturn Motion Distance 13.1 mkm x 4.11
- Pluto orbital circumference 37100 mkm = Saturn orbital circumference 9007
mkm x 4.11
(5)
- Pluto motion distance =53.9 mkm =Uranus Motion Distance 26.22 mkm x 2.06
- Pluto orbital circumference 37100 mkm= Uranus orbital circumference 18048
mkm x 2.06

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Discussion (Continued)
- Now we know that,
- Saturn moves a distance =13.1 mkm = 2π x Mars Distance 2.082 mkm
- Simply that rate (2π) is created here because of the motions rates of time among
the planets.
- We have explained one data
- Based on that, the rate (2π) isn't be created by any pure coincidence of numbers
but because,
- 1 day of Mars motion = 6.3 days of Jupiter motion = 15.56 days of Saturn motion
- These rates of time effect on the planets motions distances
- The period 15.56 days enables Saturn to move 13.1 mkm = (2π) x Mars Motion
Distance per a solar day (2.082 mkm).
- By that we explain clearly how these planets data be created.
- The result is important because, it tells we can explain all planets motions data
origin.
- Now
- We explained why Saturn orbital distance = (2π) Mars orbital distance
- Let’s try with another data
- Why Mars Velocity =(2.5) Saturn Velocity?
- Let's analyze the data no (4 and 5) to explain this one
(5)
- Pluto orbital circumference 37100 mkm= Uranus orbital circumference 18048
mkm x 2.06 = Saturn orbital circumference 9007 mkm x 4.1
- Pluto is a common point between the 2 planets (Saturn and Uranus), and the rates
are (4.1 and 2.06), but we know that, Mercury motion distance per a solar day
=4.095 mkm and Mars motion distance per a solar day =2.08 mkm (error 1%)
- The rates can be used as these planets velocities…

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- That tells Mercury Velocity = 2 x Mars velocity (approximately), because Uranus
orbital distance = 2 x Saturn orbital distance – that connects the solar system and
makes it as one machine.
- But
- Even if we accept that, the velocities are Mars and Mercury, where we search for
Mars and Saturn velocities rate,
- BUT
- Mercury velocity 47.4 km/s x 2 = (Saturn velocity 9.7 km/s)2
- That makes Saturn velocity as a function in Mercury velocity, the point is we have
seen this type of equation before let's remember it
- 3.1 deg (Jupiter Axial Tilt) x 2 = (2.5 deg = Saturn orbital inclination)2
- I want to say,
- It's a geometrical method used by Saturn with Jupiter and with Mercury
- Please Notice
- By discovery of the planets motions rates of time we enable to explain the rate
(2π) between Saturn and Mars orbital distances. And now we have a trustee
method to explain this rate (2π).
- But, there are many other geometrical methods needed to be discovered to explain
the other data because of that the form (Data)2
is a form we need to discover its
geometrical mechanism. But the data isn't created by pure coincidence of numbers
on the contrary base on a geometrical mechanism need to be discovered.
- Notice
- The planet motion has its own effect on its data for example (26.7 =2.5 x10.7)
(where 10.7 h = Saturn day period, 2.5 deg = Saturn orbital inclination, 26.7 deg =
Saturn Axial Tilt) There's a geometrical machine behind this data but we still need
to analyze Saturn motion data in more deep analysis.
- Also 687 days (Mars Orbital Period) + 2 x 3.1 = 2 x 346.6 days (the nodal year)
(where 3.1 deg = Jupiter Axial Tilt)

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7-8 Why Saturn And The Moon Use Equal Rates Of Time?
I-Data
(1)
- The moon needs accurately 1700 solar days to pass a distance = 149.6 mkm =
(Earth orbital distance) by using its daily displacement 88000 km
And
- Saturn needs accurately 1710.457 solar days to pass a distance = 1433.5 mkm =
Saturn orbital distance
- The difference between the 2 periods (1700 days and 1710.457 days = 251 hours)
(2)
(3)
4.095 mkm (Mercury velocity per solar day) x 1433.5 days = 5848 mkm
0.838 mkm (Saturn velocity per solar day) x 6939.75 days = 5848 mkm
1.16 mkm/sec x 5040 seconds = 5848 mkm (Mercury Pluto Distance)
(4)
(4900 days /1710 days) = (153.3 hours / 53.9 hours) = (1.16 mkm /0.406 mkm)
(5)
317050 days = 37100 days x 8.5
(6)
31705 solar days = 109.4 solar days x 133 x 2.18

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II-Discussion
Equation No. (1)
- The moon needs accurately 1700 solar days to pass a distance = 149.6 mkm =
Earth orbital distance
And
- Saturn needs accurately 1710.457 solar days to pass a distance = 1433.5 mkm =
Saturn orbital distance
- The difference between the 2 periods (1700 days and 171.457 days = 251 hours)
- The planets rates of time depends on the required periods to move their orbital
distances, and Saturn required period is 1710.457 solar days but the moon required
period is 1700 solar days – That causes their rates of time to be almost equal, for
example 1 hour of Earth motion be = 29.4 hours of the moon motion = 29.3 hours
of Saturn motion. almost they are equal
- We have to ask why?
- Let's summarize the idea in following:
(I)
- Uranus Orbital Distance =19.2 Earth Orbital Distance,
- This data means, if Uranus and Earth velocities are equal, During Uranus revolves
around the sun one revolution, Earth revolves around the sun 19 revolutions (19
years)
- And
- The Earth moon moves a cycle called Metonic Cycle continues for 19 years. we
know that Earth Cycle is 4 years (365 +365 +365 +366 days =1461 days) for that
we have asked frequently, why the moon moves Metonic Cycle?
- A suggested answer tell
- The Moon Moves Metonic Cycle By An Effect Of Uranus Motion
- And

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- We know that the moon and Saturn be created after Mars and Pluto migration,
(II)
- The idea is that, Uranus Motion effects on Saturn and the moon and by this effect,
Uranus caused the 2 planets periods to be (1700 days and 1710.5 days) (the
difference between them be 251 hours).
- Why? because
- Mars moves during 25.1 hours a desistance = 2.18 mkm
- This we have seen in the equation no. (6)
Equation No. (6)
- Where
- Mars needs 109.4 days to pass a distance =227.9 mkm = Mars orbital distance
- 1 Mars motion solar day =133 solar days Pluto motion
- This equation we have discussed before,
- but for revision
- This equation needs the distance 2.18 mkm to define the periods 31705 days which
is the total required periods of the solar planets. Mars moves 2.18 mkm in a period
25.1 hours and the difference between the 2 planets (251 hours) be found to
support Mars motion.
- The number 251 hours is so effective because
- (1)
- If 1 hour = 1 month based on that 251 hours will be =251 months but Metonic
Cycle is (254 months) (error 1%)
- (2)
- 25.1 hours = 90560 seconds where Pluto orbital period =90560 days
- (3)
- 251 hours = 25.1 hours x 10 but

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- 10747 days (Saturn Orbital Period) x 24 h x 10 = 10.7 h x 2 x 120536
- (where 10.7 h = Saturn day period and 120536 km = Saturn diameter)
- I try to show that, the data is integrated in harmony with one another, we don't
know the geometrical mechanism but the data shows interesting integration ability
- Shortly
- Uranus caused the 2 planets periods to be rated with the difference 251 hours
(error 0.5%) and by that Uranus effect on the planets motions caused their required
periods to be equal approximately
Equation No. (3)
4.095 mkm (Mercury velocity per solar day) x 1433.5 days = 5848 mkm
0.838 mkm (Saturn velocity per solar day) x 6939.75 days = 5848 mkm
1.16 mkm/sec x 5040 seconds = 5848 mkm (Mercury Pluto Distance)
- The idea tells, Uranus effect on the 2 planets be done through Metonic Cycle,
Equation no. (3) gives one proof for this claim, because
- Saturn (0.838 mkm per a solar day) moves a distance =5848 mkm during (6939.75
solar days = Metonic Cycle)
- The distance 5848 mkm = (Mercury Pluto Distance) is the basic Distance in the
solar system design and based on it many important data be created.
- The point is that, Mercury moves the distance 5848 mkm by using a period
=1433.5 days where 1433.5 mkm = Saturn Orbital Distance
- And Saturn moves equal distance (848 mkm) during Metonic Cycle, and Saturn
moves during (5848 days) a distance =4900 mkm= Jupiter orbital circumference,
that shows Saturn motion harmony in data.
- The data shows a deep connection between Mercury and Saturn motions.

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Equation No. (5)
317050 days = 37100 days x 8.5 (where 3710 mkm =Pluto orbital circumference)
But
Equation no. (6)
31705 solar days = The planets required periods total
Equation no. (6) be discussed before
Equation No. (4)
(4900 days /1710 days) = (153.3 hours / 53.9 hours) = (1.16 mkm /0.406 mkm) =
(30589 days/10747 days) - Where
- 4900 Days Uranus Needs To Move Its Orbital Distance
- 1710.5 Days Saturn Needs To Move Its Orbital Distance
- 153.3 hours = Pluto Day Period
- 53.9 hours = the outer planets days periods total
- 1.16 mkm = Jupiter motion distance during mars rotation period
- 0.406 mkm = Pluto velocity Per A Solar Day.
- 30589 days = Uranus Orbital Period
- This equation tries to prove that Pluto day period (153.3 h) effects on the 4 outer
planets days total (53.9 hours).
- Notice
- The sun is the last created piece in the solar system and is created after all planets
creations and motions

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7-9 Why Mercury Use A Double Of Its Orbital Distance?
- In our discussion we have seen that, Mercury used its double values usually
- Because of that,
- Mercury required period is 27.9 solar days and Mercury moves during this period a
distance = 2 x 57.2 mkm (Mercury Orbital Distance)
- Mercury uses its day period (175.94 solar days) and not its orbital period (88 solar
days)
- Also Mercury uses the distance 720.7 mkm in place of its orbital circumference
360 mkm
- Shortly
- Mercury uses double of its data values
- Why?
- If we use Mercury values as all other planets, means if we use (88 days, 360 mkm
and 14.4 solar days as required period), no change will be done for the rates of
time system, the system will work normally
- But
- Mercury motion depends on the distance 720.7 mkm
- Mercury moves during its day period 720.7 mkm and
- 720.7 mkm =Mercury Jupiter Distance
- These facts make this distance 720.7 mkm is the basic distance in Mercury motion.
Mercury all other data be created based on thi0s distance 720.7 mkm
- Why?
- A deep interaction is found between Mercury and Jupiter based on this distance
720.7 mkm –
- In more clear words –
- The distances network (and system) between Jupiter and the inner planets depends
on this distance 720.7 mkm – we have discuss that in point no. (3-9) (Jupiter
orbital circumference analysis)

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7-10 The Rate (4.61) be used between Pluto and the moon motion
- The rate (4.61) is the main rate between the moon and Pluto motion
- To show this fact as clear as possible 3 groups of Data we have to see
- Let's provide the first group in following
- I- Data
Group No (I)
- Earth (29.8 km/s) moves during a solar day (24 h) a distance = 2574720 km
- Pluto (4.7 km/s) moves during its day (153.3) a distance = 2593836 km
- The moon displacements total during (29.53 days) = 2598693 km
- Pluto and the moon motion distances be equal but they are different from Earth
motion distance with (1%).
Group No (II)
(1)
406000 km (Pluto motion distance during a solar day) = 4.61 x 88000 km
(88000 km = the moon daily displacement)
(2)
708.7 h (The moon day period) = 4.61 x 153.3 h (Pluto Day Period)
(3)
Tan (12.2) x 708.7 hours = 153.3 hours
(4)
Tan (13.17) x 655.7 hours = 153.3 hours
(5)
(10.96 deg /1.7 deg) = (153.3 h /24 h) (error 1%)
- Notice
- 13.177 degrees = the moon daily motion degrees
- 12.19 degrees = 13.177 degrees – 0.9856 degrees (Earth motion daily degrees)
For revision
(708.7 h /10.7 h) = (655.7 h /9.9h) = 66.23 = (132.47/2)

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II- Discussion
Equation no. (2)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
- Where
- 406000 km = Pluto motion distance per a solar day
- 88000 km = The moon displacement per a solar day
- 708.7 hours = The Moon Day Period
Equation no. (3)
Tan (12.2) x 708.7 hours = 153.3 hours – where
- 13.177 degrees = The Moon Motion Degrees Per A Solar Day
- 0.98562 degrees = The Earth Motion Degrees Per A Solar Day
- The Equation shows that the moon and Pluto days periods are created based on
each other geometrically. The fact can't be denied. Pluto day period (153.3 h) is
created as a function in the moon day period (708.7 h).
Equation no. (4)
Tan (13.17) x 655.7 hours = 153.3 hours where
- 655.7 hours = The Moon Rotation Period.
- 153.3 hours = Pluto Day Period and (153.3- ) = Pluto Rotation Period
- The Equation shows, Pluto rotation period is created depending on the moon
rotation period based on the angle (13.177 deg).
- The proportionality in data between Earth and its moon on one side and Pluto on
the other side shows that a geometrical mechanism must be found behind them.

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- More Data
Group No (III)
778.6 mkm (Jupiter Orbital Distance) = 4.61 x 170 mkm
550.7mkm (Jupiter Mars Distance) = 4.61 x 119.7 mkm
2094 mkm (Jupiter Uranus Distance) = 4.61 x 2 x 227.9 mkm
2872.5 mkm (Uranus Orbital Distance) = 4.61 x 629 mkm
3033.5 mkm (Uranus Pluto Distance) =4.61 x 654.9 mkm
5127 mkm (Jupiter Pluto Distance) = 4.61 x 2 x 550.7 mkm
5906 mkm (Pluto Orbital Distance) =4.61 x 1284 mkm
1375.6 mkm (Mercury Saturn Distance) =4.61 x 2 x 149.6 mkm
3062 mkm (Saturn Neptune Distance) =4.61 x 671 mkm
4345.5 mkm (Earth Neptune Distance) =4.61 x 940 mkm
4267.2 mkm (Mars Neptune Distance) =4.61 x 929 mkm
Where
170 mkm = Mercury Mars Distance
119.7 mkm = Venus Mars Distance
227.9 mkm = Mars Orbital Distance
629 mkm = Jupiter Earth Distance 654.9 mkm = Jupiter Saturn Distance
550.7 mkm = Jupiter Mars Distance 1284 mkm = Earth Saturn Distance
149.6 mkm = Earth Orbital Distance 671 mkm = Jupiter Venus Distance
940 mkm = Earth Orbital Circumference
929 mkm = Earth Jupiter Distance when the 2 planets be on the sun 2 sides
(Max error 1%)
Notice
The previous distances are (22 distances) where all distances in the solar system are
(45 distances) –means these distances be around 50% of all distances in the solar
system and be controlled by this rate (4.61)

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II- Discussion (Continued)
- Let's summarize this discussion
(I)
- How the rate 4.61be found?
- Pluto orbital distance 5906 mkm = Earth orbital distance 5906 mkm x 39.4
- But
- 1 solar day of the moon motion be =8.51 days of Pluto motion
- 39.4 = 8.51 x 4.61
- That means, the rate (4.61) is the complementary one with the rate of time
(II)
- Why this rate (4.61) controls more than 50% of the solar system distances?
- Because of the equation importance we brought it for revision here
For revision
(708.7 h /10.7 h) = (655.7 h /9.9h) = 66.23 = (132.47/2)
- Where
- 708.7h = the moon day period
- 655.7h = the moon rotation period
- 10.7 h = Saturn Day Period
- 9.9 h = Jupiter Day Period
- The equation is so accurate,
- The rate 66.2 = 132.4/2
- 1 solar day of Mars motion =133 solar days of Pluto motion
- But
- The outer planets required periods total =133 The inner planets required periods
total, as we have seen before
- That makes the rate (133) is a basic one and by that the rate (4.61) is a basic one
also.

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7-11 The Moon Orbital Motion Equation
- Let's explain why we discuss the moon orbital equation in this point…
- The moon needs 1700 solar days to pass a distance = 149.6 mkm=Earth orbital
distance by using its daily displacement 88000 km
- If 1000 km = 1 degree, so 1700 days will be 1.7 degrees
- In fact the moon orbital equation uses the angle 1.7 deg as the moon motion angle
per a solar day
- Because of that, the angle 1.7 degrees found its source 1700 solar days.
- But
- Can 1000 km= 1 day or 1 degree?
- If that's happened so, the moon daily displacement 88000km will be equal 88 days
= Mercury orbital period
- And
- In many other situations we found that it's useful to use the rate 1000 km = 1 day
=1 degree and because of that we study the moon orbital equation to show how the
angle 1.7 degrees be used by the moon motion.
- Let's summarize the moon orbital motion equation in following

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I- Why Does The Moon Use Pythagorean Triangle In Its Motion?
- Let's summarize this question answer in following:
o The moon uses Pythagorean triangle basically to decrease its displacement
daily through its orbit
o The moon daily displacement = 88000 km and the moon has to move this
distance every day without any decreasing (later we will know why!)
o But
o If the moon moves by this displacement as its orbital displacement the moon
would revolve around Earth through its apogee orbit only (r=0.406 mkm)
o For that reason
o The moon creates an angle between its motion direction and its orbit
horizontal level to create a displacement through its orbit less than (88000
km)
o As a result of this technique, the moon can revolve around Earth through
more near orbits than apogee orbit (r=0.406 mkm)
o Simply, because the moon uses this technique the moon can revolve around
Earth through perigee orbit (r=0.363 mkm)
o Let's explain this intelligent technique with some details to show the useful
result of using Pythagorean triangle by the moon orbital motion….

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II- How Does The Moon Use Pythagorean Triangle In Its Motion?
- The moon moves daily (88000 km) on the right triangle hypotenuse (AC), but the
moon creates an angle (θ) between its motion direction and its orbit horizontal
level, by that the real displacement through the moon orbit will be (L= 88000 km
cos (θ)), and by that, spite the moon moves 88000 km, but the real orbital
horizontal displacement be less than (88000 km) and this is the objective for which
the moon uses Pythagorean triangle –
As an example,
- If (θ) =28.63 degrees, the real displacement (L== 88000 km cos (θ)) = 77237 km,
So, if the moon real displacement daily be (77237 km), during 29.53 days the
moon will pass a distance = 2.28 million km and this will be the moon orbital
circumference, where 2.28 mkm = 2π x (0.363 mkm)
- The Moon Orbital Perigee Radius =0.363 mkm
- That means, the moon by a real displacement =77237 km can move around Earth
through the perigee orbit (radius =0.363 mkm), this is the useful result the moon
performs by using Pythagorean triangle,
- Now let's suppose the moon doesn't use Pythagorean triangle, what would happen?
- The moon daily displacement = 88000 km, during 29.53 days the moon moves a
distance = 2.598 mkm where 2.598 mkm = 2π x (0.413 mkm)
- The Moon Orbital Apogee Radius =0.406 mkm
- So the moon will move along month revolving around Earth through its apogee
orbit (or even far from apogee orbit) because the total distance can't be passed
through any more near orbit around Earth…
- The data shows how Pythagorean triangle is so useful for the moon orbital motion.

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The Angle θ
- The angle (θ) should get our attention for its specific effect…let's summarize the
idea in following
o The angle (θ) changes the real displacement (L = 88000 cos (θ)), through the
moon orbit..
o We know that, when the real displacement (L) be shorter the moon can
move through near orbits to Earth and by that the moon can be near or at
Perigee radius (0.363 mkm)
o When the real displacement (L) be greater the moon has to move through
orbits far from Earth and by that the moon can be near or at apogee orbit
(r=0.406 mkm)
o That means, the angle (θ) changes the real displacement (L) and also
changes the distance between the moon to perigee or to apogee, shortly, the
angle (θ) defines the moon position (as a ship) between 2 river banks….
- The angle (θ) defines the moon orbital motion basic features and we have to
discuss is deeply with the moon orbital motion equation (θ1= θ0 + 1.7 degrees),
but before we need to analyze the moon orbital motion
Notice
o We know that (363000)2
+ (86000)2
= (373000)2
o In Pythagoras triangle with dimensions (363000 km, 373000km, 86000 km),
what's the angle (θ)? The angle (θ) = 13.33 degrees
o Also (396800)2
+ (86000)2
= (406000)2
the angle (θ) = 12.229 degrees
o I have used (363000 km and 406000 km) because they are the perigee and
apogee radiuses between which the moon moves.
o The difference between angles = 1.1 degrees
i.e.,
The angle (1.1 deg.) controls the moon motion from perigee to apogee, we will need
this notice later in our discussion

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III- The Moon Orbital Motion
- The moon moves per a solar day a motion typical to the Earth motion to avoid the
separation from Earth through their motions, based on this rule, the moon moves
per a solar day 2.573 million km with an angle declines on the horizontal level
0.98562 degrees as typical to Earth motion
- If there's no Lorentz Length Contraction Phenomenon effect on the moon motion,
the moon motion trajectory would to be a parallel line to Earth Motion Trajectory,
But Lorentz Length Contraction effects on the moon motion daily distance (2.573
mkm) with a rate 1.0725 and causes this distance to be contracted (2.399 mkm)
- The moon difficulties are started here, because the difference between both
distances (0.17 mkm) will cause the moon to be separated from Earth motion
inevitably
- We should notice that, these motions are done far from our observation, means, we
see nothing of this motion distance, because the moon moves on the Earth orbital
circumference revolving around the sun, but, even if we can't observe this motion
distance the motion is still fact and proved by its power, because the Earth moves
per a solar day 2.573 mkm and if the moon doesn't move this same distance every
solar day that necessities the moon to be separated from the Earth through their
motions course – based on that- the facts prove this motion regardless our
observation ability for it.
- Now the moon has an additional distance to be passed (0.17 mkm) and the moon
has to pass this distance on the same solar day to avoid the separation from the
Earth during their motions.
- Because of that, the moon moves its daily displacement (88000 km) depends on
Earth gravity force (by which we see the moon in the Earth sky), but the different
distance (0.17 mkm) to be covered still needs the moon to move one more
displacement (= 88000 km)

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- The previous explanation tells that, the moon has to move 2 displacements each =
88000 km, while we see one displacement only because it's done through the
moon orbital motion around Earth but the other displacement should be done also
because this total distance (0.17 mkm) is required to cover the different distance
and create the total (2.573 mkm) which saves the moon and Earth motions
accompanying.
- Now we have 2 basic information about the moon orbital motion
o (1st
information) the moon uses Pythagorean triangle in its orbital motion
o (2nd
information) the moon has to move 2 displacements each =88000 km
and their total distance =0.17 mkm which is a required distance necessary to
cover the difference between the moon and Earth motions distances.
- This explanation helps us to understand why the moon uses Pythagorean triangle
in its motion, because the moon can't decrease its daily displacement (88000 km)
because the moon needs this distance to cover the different distance between its
contracted motion distance (2.399 mkm) and Earth motion distance (2.573 mkm),
So the moon needs to move this displacement perfectly, but if it's used as a
displacement through the moon orbit, the moon would be always a prisoner in the
apogee orbit (r=0.406 mkm) as we have discussed before, because of that, the
moon creates Pythagorean triangle technique by which the moon moves actually
88000 km daily but the real displacement through the moon orbit became less (L =
88000 Cos θ) and by that the moon can achieve 2 objectives, First to pass the
required distance (88000 km) and Second to move in near orbits to Earth, that
shows the intelligent moon motion technique…
- (Notice, Lorentz Length Contraction Effect Discussion is in Appendix No. 1)

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The Moon Orbital Motion Needs One More Orbit
- The previous explanation tells that, the moon moves 2 displacements each =88000
km, we see one of these 2 displacements but where's the other displacement?!
- We know that, the moon original motion (2.573 mkm) which is contracted to be
(2.399 mkm) isn't seen by us because the moon moves this distance revolving with
Earth around the sun along the Earth Orbital Circumference
- We may accept that, the 2nd
displacement the moon does on this same trajectory
and isn't seen by us.
- So,
- There must be one more orbit for the moon to move through this 2nd
displacement.
means,
- There's 2nd
Orbit For The Moon Motion
- But
- How can we discover this second orbit if we can't observe the 2nd
displacement
motion?
- We can discover this 2nd
orbit by the moon orbit data analysis. So we should
depend on the moon orbital triangle data analysis to define this 2nd
orbit position.
- For that we have to discuss the moon 2nd
orbit in our deep analysis of The Moon
Orbital Triangle Geometrical Structure.

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IV- The Moon Orbital Motion Equation
A- The Equation Concept
B- The Equation Test and Accuracy
A- The Equation Concept
The Moon Orbital Motion Equation
(θ1= θ0 + 1.7 degrees)
- The moon orbital motion equation is created depending on the concept we have
discussed, which is (the moon uses Pythagorean triangle in its orbital motion)
- The moon uses Pythagorean triangle and by this intelligent technique the moon be
under control of the angle (θ) change
- The angle (θ) defines almost all the moon motion features.…
- The moon uses this technique, aiming to create a real displacement shorter than its
actual displacement (88000 km) based on the equation (L =88000 cos (θ)) and by
that while the moon moves a displacement =88000 km but the real displacement
(L) through its orbit be shorter than 88000 km and by that the moon can revolve
around Earth through more near orbits than its apogee orbit (r=0.406 mkm).
- The moon orbital motion equation depends on this concept and, the equation
uses (the constant) 1.7 degrees as the moon daily motion degrees, and the equation
uses the previous day angle (θ0) to produce the today angle (θ1)
- We have 3 questions in this equation study which are:
o How does this equation work?
o Is this equation trustee and correct?
o Why does the equation use the angle 1.7 degrees for the moon daily motion?
Let's try to answer….

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How to use this equation?
- Perigee Radius =0.363 mkm, so Its Orbital Circumference =2.28 mkm
- Suppose the moon will revolve around Earth through perigee orbit only during
29.53 days, so
- (2.28 mkm /29.53 days) = 77237 km
- This is (the real displacement = L = 88000 km Cos θ = 77237 km),
- What's the angle θ value? the angle θ = 28.63 degrees
- Suppose the moon stand on this point yesterday with the angle (θ) =28.63 degrees,
where the moon will move today?
- From Perigee (the most near point to Earth) the moon will move in Ascending
motion because it moves from perigee (0.363 mkm) to apogee (0.406 mkm)
- In Ascending motion we use (-1.7 degrees) because the angle (θ) is decreased
where the real displacement (L) is increased, So let's do that in following
o (θ1= θ0 - 1.7 degrees)
o (θ1= 28.63 degrees - 1.7 degrees) = 26.93 degrees
o L = 88000 Cos (26.93 degrees) = 78454 km
o During 29.53 days so (78454 km x 29.53 days = 2.316 mkm)
o 2.316 mkm = 2π x 368722 km
That means
o The moon was (before motion) on Perigee radius (r=0.363 mkm) and starts
its motion displacement 88000 km. For day motion the equation uses 1.7
degrees, that means, the moon on perigee uses Pythagorean triangle with
angle (28.63 degrees) and during one solar day the moon uses - 1.7 degrees
and by that the angle will be (26.93 degrees)…... The angle 1.7 degrees
expresses The Moon Daily Motion
o By using Pythagorean triangle its angle (θ) = 26.93 deg, the displacement
(88000 km) will create a real displacement through the moon orbit = 78454
km and the moon will finish its motion today at a distance 368722 km

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means the moon is far from perigee radius with (368722 km-363000 km
=5722 km )
o So, the moon after 1 day motion will be at the point 368722 km and will
have the Pythagorean triangle its angle 26.93 degrees.
The Descending Motion
o When the moon moves from apogee (0.406 mkm) to perigee (0.363 mkm),
so the angle (1.7 degrees) will be positive (+1.7 degrees) because the angle
(θ) is increased and the real displacement (L = 88000 Cos (θ)) be shorter.
So
o If the moon in apogee radius (r=0.406 mkm), what's the angle (θ)?
o The apogee orbital circumference = 0.406 mkm x2π =2.55 mkm = 29.53
days x 86400 km, the angle (θ) = 10.96 degrees (=11 deg approx.)
o The moon moves from apogee to perigee (descending motion)
o (θ1= θ0 + 1.7 degrees) means (θ1= 11 degrees + 1.7 degrees) = 12.7 deg.
o L = 88000 Cos (12.7 degrees) = 85847 km
o During 29.53 days so (85847 km x 29.53 days = 2.535 mkm)
o 2.535 mkm = 2π x 403467 km
So
o After one day the moon will be on 403467 km far from apogee (406000 km)
with 2540 km
Now let's see this equation test and efficiency in following

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B- The Equation Test and Accuracy
- I have tested the Equation with real data for 2 months June 2020 and October 2020
- The results are very good and I provide the results here for better vision
concerning the equation efficiency
1st
Test June 2020
Day Registered Data The Results (1.7) Difference
6-6-2020 369418 km
7-6-2020 373729 km 374772.5 - 1044
8-6-2020 378917 km 378821.5 96
9-6-2020 384534 km 383667.7 867
10-6-2020 390096 km 388890 1206
11-6-2020 395156 km 394000 1156
12-6-2020 399345 km 398604.2 741
13-6-2020 402395 km 402361.3 34
14-6-2020 404153 km 405052.8 -900
15-6-2020 404574 km ---- ---
16-6-2020 403718 km 401848.5 1870
17-6-2020 401733 km 400876.1 857
18-6-2020 398840 km 398640.7 200
19-6-2020 395303 km 395417.4 115
20-6-2020 391409 km 391521.2 -113
21-6-2020 387432 km 387273.4 159
22-6-2020 383607 km 382968.4 639
23-6-2020 380110 km 378852 1258
24-6-2020 377044 km 375107 1937
25-6-2020 374451 km 371836.5 2615
26-6-2020 372338 km 369077 3262
27-6-2020 370703 km 366855.6 3847
[

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The 1st
Test Results Analysis:
- The Total Results Are 20 Values
(1st
Category)
o 15 values, defines the moon position in range 1300 km (Error 3%)
(2nd
Category)
o 2 values, defines the moon position in range 1300-2000 km (Error 4.6 %)
(3rd
Category)
o 3 values, defines the moon position in range 2000-3500 km (Error 8 %)
- The Results Explanation
- The distance from perigee to apogee =43000 km…
o 1st
Category of results defines the moon position in error range (1300 km) =
error (3%), that means, (15 values of 20) defines the moon position with
error (3%) only (Small Error Range)
o 2nd
Category of results defines the moon position in error range from (1300
km to 2000 km) = error (4.5%), that means (2 values of 20) defines the
moon position with error (4.5%) (Average Error Range)
o 3rd
km to 3500 km) = error (8%), that means (3 values of 20) defines the moon
position with error (8%) (Great Error Range)
- The Equation Accuracy
o The previous explanation shows that, the equation has a good range of
accuracy and its error is in the acceptable error range
The Conclusion
The Equation Is correct and trustee
And
It's a useful tool to define the moon position daily

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2nd
Test October 2020
Day Registered Data Results (1.7) Difference
5-10-2020 405,690 km --- ---
6-10-2020 404,171 km 403125.3 km 1046 km
7-10-2020 401,649 km 401390 km 259 km
8-10-2020 398,073 km 398545.6 Km - 473 km
9-10-2020 393,464 km 394568.8 km -1105 km
10-10-2020 387,944 km 389510 km -1567 km
11-10-2020 381,763 km 383520 km -1758 km
12-10-2020 375,302 km 376875.3km -1574 km
13-10-2020 369,063 km 369981km -919 km
14-10-2020 363,617 km 363363.4km 254 km
15-10-2020 359,530 km 357612 km 1918 km
16-10-2020 357,269 km 353307 km 3962 km
17-10-2020 357,105 km ---- --
18-10-2020 359,048 km --- --
19-10-2020 362,851 km 364979.7 km - 2129 km
20-10-2020 368,058 km 368579.3 km -522 km
21-10-2020 374,101 km 373492.4 km 609 km
22-10-2020 380,412 km 379168.3 Km 1244 Km
23-10-2020 386,497 km 385059.3Km 1438 km
24-10-2020 391,989 km 390694.3 km 1295 km
25-10-2020 396,659 km 395729.5 km 930 km
26-10-2020 400,395 km 399958.7 km 437 km
27-10-2020 403,181 km 403299 km 112 km
28-10-2020 405,059 km 405738.5 km -680 km
29-10-2020 406,104 km 407359.4 km -1256 km
[

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The Test Results Analysis:
- The Total Results Are 22 Values
(1st
Category)
o 15 values, defines the moon position in range 1300 km (Error 3%)
(2nd
Category)
o 5 values, defines the moon position in range 1300-2000 km (Error 4.6 %)
(3rd
Category)
o 2 values, defines the moon position in range 2000-3500 km (Error 8 %)
- The Results Explanation
- The distance from perigee to apogee =43000 km…
o 1st
Category of results defines the moon position in error range (1300 km) =
error (3%), that means, (15 values of 22) defines the moon position with
error (3%) only (Small Error Range)
o 2nd
km to 2000 km) = error (4.5%), that means (5 values of 22) defines the
moon position with error (4.5%) (Average Error Range)
o 3rd
km to 3500 km) = error (8%), that means (2 values of 22) defines the moon
position with error (8%) (Great Error Range)
- The Equation Accuracy
o The previous explanation shows that, the equation has a good range of
accuracy and its error is in the acceptable error range
The Conclusion
The Equation Is correct and trustee
And
It's a useful tool to define the moon position daily

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The Value 1.7 degrees
- The 3rd
question was, why the equation uses 1.7 degrees?
Because
1.7 degrees = 0.98562 degrees + 0.712 degrees
Where
- 0.98562 degrees = Earth motion daily degrees, and it equals the moon daily
motion degrees because the moon has to move an equal distance to Earth motion
daily distance to save their motions accompanying
- This question and the angle 0.712 degrees is discussed in my previous paper.

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The Moon Motion Difficulties
- There are 2 basic difficulties are observed in the moon orbital motions, let's refer
to them in following:
o (1st
Difficulty) The moon moves per day different distances from perigee to
apogee…..
o We know the moon moves from perigee to apogee (go and back) during
Anomalistic month (27.55 solar days)
o (43000 km x 2) / 27.55 days = 3122 km
o The moon doesn't use this rate (3122 km) in its motion, instead the moon
can move (6000 km) on one day only and on another day may move only
2500 km (or even less)!
o The moon orbital equation tries to solve this difficulty by using the rate 1.7
degrees in the equation (θ1 = θ0 + 1.7 degrees), the value 1.7 degrees is a
great number and enables the moon to move around (5000 km) per solar day
and by that if the moon moves per solar day 4000 km the different distance
will be 1000 km and if the moon moves 6000 km the different will be
– 1000 km, it’s the same difference, and by that, the error be minimized as
possible enabling the equation to be more efficient..
o (2nd
Difficulty) The moon stays in perigee and apogee points long time….
o That means, while the moon be on perigee or apogee, the moon doesn't use
the equation and doesn't change its distance to perigee or apogee for long
days…we may notice that in the equation tests, when the moon reach to
perigee or apogee the equation stops its work and stays 2 or 3 days to return
to its work… because the moon consumes long time to leave the points
(perigee and apogee)…

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8- Planets Unified General Motion
8-1 The Planets Unified General Motion Description
8-2 The Solar Planets Motions Are Complementary One Another
8-3 The Solar Planets Move An Unified Motion (A Team Motion)

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8-1 The Planets Unified General Motion Description
- I claim that (The Planets Motions Create One Unified General Motion)
- This claim tells the planets motions be similar to Train Carriages Motion
- Also It tells the planets motions be similar to Chess Pieces Motions
- The idea discovers One Law controls the solar system motion and data.
- The planets unified general motion forces each planet motion to be complementary
with other planets motions to perform The Unified General Motion. as a result,
The Planet motion be An Obligatory Motion.
- The Solar Planet creates its data to be in consistency with its motion.
- The planet can't change its motion, but can change its data to be in consistency
with its motion. And the planet data be created in consistency with its motion.
- Because the planet motion be complementary with other planets motions.
- The planet data be created complementary with other planets data
- Based On This Vision
- The solar planets data be created complementary to other planets data and based
on that the planets data be created depends on One Geometrical Design.
- And
- The Planets Creation And Motions Data Be Controlled By One Equation Only

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- Please remember
- The Solar Group is similar to a machine of gears each planet is a gear in it, or
- The Solar Group is similar to one building and each planet is a part of this same
building, or
- The Solar Group is similar to puppets theater, all puppets are connected together
by one force and causes their motions, or
- The Solar Group is similar a canal water moves through the canal and causes the
rotation of 9 waterwheels. The Motion Direction of The waterwheels is different
from the water motion direction but no waterwheel can rotate without the water
motion, or
- The solar planets are similar to train carriages, they move together one unified
general motion, or
- The solar planets be similar to knots on one robe or similar to points on the same
one trajectory of energy –
- The solar planets motions be similar to chess board pieces motions, each motion
depend on the other planets motions and be done by geometrical calculations.
- Notice
- The planets motions data analysis in this point aims to prove this feature which is
(The Solar Planets Motions Be Integrated Into One Unified General Motion)
- Let's do that in the next points(5-2 and 5-3)

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8-2 The Solar Planets Motions Are Complementary One Another
I-Data
(The Interaction between Mercury, Mars and Jupiter)
(No. 1) (Mercury and Mars Motions)
- Mercury moves during its day period (4222.6 h.) a distance = 720.7 mkm
- Mars moves during (2802 hours) a distance = 243 mkm
- Mercury moves during (1407.6 hours) a distance = 243 mkm (error 1%)
- Mars moves during 346.6 d. a distance =720.7 mkm (Mercury Jupiter Dis.)
- Mercury moves during 346.6 d. a distance =1419 mkm (with 1433 error 1%)
- Mars moves during 687 d. a distance = 1433 mkm (Mars orbit. Circum)
- Mercury moves during 687 d. a distance =2815mkm (Mercury Uranus Dis.)
- Mars moves during 4331d. a distance = 9010mkm (Saturn orbit. Circum)
- Mercury moves during 4331d. a distance = 2815 mkm x 2π
- Mars moves during 224.7 d. a distance = π x 149.6 mkm (Earth orb. Dis)
- Mercury moves during 224.7 d. a distance = 920 mkm (with 928 error 1%)
- Mars moves during 365.25 d. a distance = π x 243 mkm (0.5%)
- Mercury moves during 365.25 d. a distance = 2 x 748 mkm
- Mars moves during 5040s. a distance= 121464 km= Saturn Diameter (+1%)
- Mercury moves during 5040s. a distance= 238896 km= 2 Saturn Diameters (-1%)
Where
1407.6 h = Mercury Rotation Period 2802 h = Venus Day Period
346.6 days = the nodal year 224.7 days = Venus orbital period
687 days = Mars Orbital Period
4331 days = Jupiter orbital period = 2π x 687 days

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(No. 2) (Mars And Jupiter Motions)
- Mars moves during 636.7 days a distance =1325 mkm= (Venus Saturn Dis.)
- Jupiter moves during 636.7 days a distance =720.7 mkm
- Mars moves during 687 d. a distance= 1433 mkm= Mars Orbital Circumference
- Jupiter moves during 687 d. a distance= 778.6 mkm= Jupiter Orbital Distance
- Mars moves during 4331d. a distance= 9010 mkm= Saturn orbital circumference
- Jupiter moves during 4331 d. a distance= 4900 mkm= Jupiter Orbital Circum.
- Mars moves during 778.6 d. a distance = 1622 mkm = Uranus Neptune Dis.
- Jupiter moves during 778.6 d a distance= 881 mkm =58 days x 15.19 mkm.
- ( 15.19 mkm = the 9 solar planets motions distances total per a solar day).
- Notice
- 2.082 mkm / day x 778.6 days = 1622 mkm = 1.1318 mkm /day x 1433 days

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(No. 3) (Mercury And Jupiter Motions)
- Mercury moves during 687 d. a distance= 2815 mkm= Mercury Uranus Distance
- Mercury moves during 1433 d. a distance =5848 mkm= Mercury Pluto Dis.
- Jupiter moves during 1433 d a distance =1622 mkm=Uranus Neptune Dis.
- Mercury moves during 4331d. a distance= 2815 mkm x 2π
- Mercury moves during 4222.6 h a distance = 720.7 mkm
- Jupiter moves during 4222.6 h a distance = 200 mkm = 629 mkm/π
- Mercury moves during 550.7 d a distance = π x 720.7 mkm (0.4%)
- Jupiter moves during 550.7 d a distance = 629 mkm (error 1%)
Please Remember,
Data Group No. (1)
- Mars moves during 687 d. a distance= 1433 mkm= Mars Orbital Circumference
- Mars moves during 4331d. a distance= 9010 mkm= Saturn orbital circumference
- Mars moves during 4331 x π d a distance= 28255 mkm= Neptune orbital circumference
Data Group No. (2)
- Mercury moves during 687 d. a distance= 2815 mkm= Mercury Uranus Distance
- Mercury moves during 4331d. a distance= 2815 mkm x 2π
Data Group No. (3)

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II-Discussion
- The planets move defined distances in defined periods of time.
- The Defined Distance means a distance is known in the solar system, as to be any
planet orbital distance or a distance between any 2 planets.
- The Defined Periods Of Time means a period of any planet cycle, as 365.25 days
(Earth orbital period) or any planet orbital period. Or any planet rotation period or
any planet day period. All these periods are defined periods of time
- The argument tells that
- If the solar planets move their motions independently from one another, based on
that, the planets motions during defined periods of time should pass (random)
distances. Because these Planets are independent in their motion from one
another. (For example) Mercury motion depends on its orbital period (88 days) and
doesn't interest neither for Mars orbital period (687 days) nor for Jupiter orbital
period (4331 days) and by that, Mercury during these periods (687 days and 4331
days) should move some random distances (not defined in the solar system
distances).
- The data disproves Planet Motion Independency Concept. because the (3)
planets move defined distances in defined periods of time. These planets motions
aren't independent from one another. These motions are done based on One
Geometrical Design. And these motions be are similar to Chess Board Pieces
Motions. Each Motion is calculated geometrically and be obligatory.
- Notice
- Jupiter orbital distance analysis can support the discussion of this point greatly, we
discuss it in a separated point No. (9)

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8-3 The Solar Planets Move An Unified Motion (A Team Motion)
- Let's Summarize The Proof Idea In Following:
- This proof depends on 2 planets motion cycles are discovered later. Which are
(planet 8 days cycles) and (planet 6 days cycles). We study one Cycle only in this
paper because both cycles provide the same argument.
- The Cycle Shows That Different Planets Motions Be Used In The Same One
Cycle To Create One Final Result.
- Means,
- Many planets move relative one another to create one result.
- For Example
- Jupiter moves a distance (A) and Uranus moves a distance (B).
- The different distance between (A) and (B) = Jupiter Diameter
- Now
- The machine uses this behavior frequently, and (the different distance = Jupiter
Diameter) be created frequently while the cycle uses its different periods (8 days,
16 days, 24 days….etc).
- Based on that,
- We can't consider these planets motions are independent from one another because
the different distance be defined by the 2 planets motions. we have to consider
these planets motions as a team motion. They move relative to one another which
proves The Unified General Motion Concept.
- Based on that,
- (Planet 8 and 6 Days Cycle) disproves Planet Independent Motion Concept.
- In following we study Planet 8 Days Cycle

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(Planet 8 Days Cycle)
(I)
- Jupiter (13.1 km/s) moves during its day period (9.9 h) a distance = 466884 km
- But
- 466884 km = 449197 km (Jupiter Circumference) + 17687 km
- Where
- (8 x 17687 km = 141496 km (Jupiter Diameter) (error 1%)
- Based on that, we have concluded that, Jupiter has a cycle of 8 days
- Jupiter (13.1 km/s) moves during 8 Jupiter days (79.2 h) a distance = 3735072 km
- (3735072 km= 8 Jupiter circumferences + 141496 km (Jupiter diameter) (1%)
(II)
- The distance 3735072 km be passed also by Saturn and Neptune with a rate 80%
depends on one another as following:
- Saturn (9.7 km/s) moves during 10 Saturn days (107 h) a distance = 3736440 km
- (10 Saturn Circumferences = 3786750 km, the difference =50310 km = Uranus
Diameter error 1.5%)
- Neptune (5.4 km/s) moves during 12 Neptune days (193.2 h) a distance = 3755808
km
- (24 Neptune Circumferences = 3734323 km, the difference =21485 km = Mars
Circumference (error 0.6 %))
(III)
- Uranus (6.8 km/s) moves during Pluto day period (153.3 h) a distance = 3752784
km
- The distance 3752784 km = Jupiter motion distance during 8 days + 17687 km
- And because
- 17687 km x (8) = 141496 km (Jupiter Diameter) (error 1%)
- That tells another Cycle is found between Uranus and Jupiter based on 8 Pluto
days

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- That means, the distance be passed by Uranus during 8 Pluto days equal the
distance be passed by Jupiter during 64 Jupiter days and equal the distance be
passed by Saturn during 80 Saturn days and equal the distance be passed by
Neptune during 100 Neptune days
Let's see that in following
(1)
Jupiter (13.1 km/s) moves during (64 Jupiter days) a distance =29880756 km
(2)
Saturn (9.7 km/s) moves during (80 Saturn days) a distance =29891520 km
(3)
Neptune (5.4 km/s) moves during (100 Neptune days) a distance =31298400 km
(4)
Uranus (6.8 km/s) moves during (8 Pluto days) a distance =30022272 km
Comments
- Uranus motion distance (30022272 km) – Jupiter motion distance (29880756 km)
= 141496 km (Jupiter Diameter)
- The differences between these distances are less than 1 % (generally) and based on
that we can't consider they are different distances but we have to consider they are
equal distances.
- Although still there are small differences which are found for geometrical reasons
for example the difference between Jupiter and Saturn motions distances =
29880756 km – 29891520 km = 10921 = the moon circumference
- The data shows Planets Motions Dependency, because the different distances are
defined geometrically and that means these aren't 2 different distances of 2 plants
independent motions. On the contrary, the 2 distances are planned geometrically
and the 2 planets are 2 players to perform one different distance.

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The Discussion
- Let's discuss the previous data
(A)
- The outer planets are 5 planets, they consist 2 teams,
- The first team is consisted of Jupiter, Saturn and Neptune, these 3 planets move
based on a cycle (8 days cycle) depends on Jupiter motion with the rate 80%,
- That means
- The distance be passed by Jupiter in 8 Jupiter days be equal the distance be passed
by Saturn in 10 Saturn days and equal the distance be passed by Neptune during 12
Neptune Days
- The (small) difference between these 3 distances have geometrical necessities, as
we have seen in the difference between Jupiter and Saturn motions distances which
= 10921 km = The Earth Moon Circumference
- The moon circumference itself tells that it's a cycle because if it's not a cycle we
would find a part of the moon circumference
(B)
- The second team is Uranus and Pluto….
- Uranus uses Pluto day period (153.3 hours), and by that, Uranus (6.8 km/s) moves
during Pluto day period (153.3 hours) a distance = 3752784 km
- Because
- 3752784 km = Jupiter motion distance during 8 Jupiter days +17687 km
- Because of this data, we have concluded that, these motions depends on (8 days
Cycle), because
- Uranus needs to move during a period (= 8 Pluto days) to cause this value (17687
km) be = (141496 km (Jupiter Diameter) (1%)
- Because of Jupiter diameter we conclude that Uranus has a cycle of (8 Pluto days)
- Based on that

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- Uranus motion distance during 8 Pluto days = Jupiter motion distance during 64
Jupiter days = Saturn motion distance during 80 Saturn days = Neptune motion
distance during 100 Neptune days.
- How (Planet 8 Days Cycle) Can Prove The Unified Motion?
- Because
- Many planets motions be done to produce One Result
- This result be the different distance 141496 km (Jupiter Diameter) (1%)
- If we deal with planets independent motions this different distance can't be created
regularly and the Cycle can't be defined.
- Because (Planet 8 days Cycle) be defined, that means, the different distance
141496 km (Jupiter Diameter) be defined regularly which can be done only if
we deal with a team motion and NOT Planets independent Motions.
- Why does Uranus depend on Pluto Day Period?(additional question)
- Pluto day period is so long (153.3 h) in comparison with the outer planets days
periods. We suppose that, Uranus Motion effect on Pluto motion causes Pluto day
extension. We know Uranus did this effect because Pluto orbital inclination = 17.2
deg but Uranus day period =17.2 hours, even if we can't catch the mechanism of
this process yet, but the data shows that's Uranus effect on Pluto motion.
A Conclusion
Planet 8 Days Cycle disproves The Planet Independent Motion Concept,
On The Contrary, The Planets Move As A Team. (A Unified General
Motion)

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9- Mars Migration Theory
9-1 Mars Migration Theory
9-2 Pluto Migration Theory
9-3 Planets Migration Theories Proves
9-4 Is There An Absent Planet In The Solar Group?

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9-1 Mars Migration Theory
- Mars was the next planet after Mercury with original orbital distance =84 mkm
and Mars had migrated into Mars current orbital distance (227.9 mkm)
- Through Mars Displacement from (84 mkm) to (227.9 mkm), Mars had collided
with Venus (at first) and then with Earth (at second) and then reach to its current
orbital distance point (227.9 mkm).
- Mars had moved from (84 mkm) to (227.9 mkm) in a direct displacement – and
had pushed with it all collisions debris in its direction
- From these collisions debris the Earth could create its own moon and also Mars
moons are created from them and the rest debris be attracted by Jupiter Gravity
and Created The Asteroid Belt.
- Means,
- Mars Migration Theory is in full harmony with (Giant- Impact Hypothesis), but
- Mars itself had collided with Earth and caused the moon creation and not the
ancient planet (theia) as supposed by the Giant-impact hypothesis.
- The point is that, the planets order (Mercury – Venus –Earth) shows that Mars was
the second planet after Mercury – and Mars had migrated from (84 mkm) to (227.9
mkm) –through this displacement – Mars has collided with Venus and Earth–
- Mars collisions with Earth and Venus left many proves behind which prove that
Mars did these collisions and not the planet (theia).
- Mars Migration theory answers many of the Giant-impact hypothesis questions.
- Let's do that in following
(1st
Question)
- Why has Venus no a moon? spite it suffered from a similar collision as Earth?
- Mars had moved its displacement from (84 mkm) to (227.9 mkm), and through
this displacement Mars pushed all debris with it in its motion direction and
because of that, Venus had found no debris around, And couldn't create its own
moon because of that.

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- But the debris lost some of their motion momentum at Earth position and Earth
gravity is more strong than Venus, by that Earth could attract some debris by
which Earth created its moon.
(2nd
Question)
- What's The Lunar Magma Ocean (LMO) Origin?– It's Venus
- Because
- The Earth moon rocks are created from the 3 planets debris (Mars- Venus – Earth)
and for that the moon has a Magma Ocean (LMO).
(3rd
Question)
- Why The Iron Oxide (Feo) of the Moon= (13%)?
- Because The rate (13%) is a middle rate between Mars rate (18%) and the
terrestrial mantle (8%).
Notice no.(1)
- Mars Moons Creation is a good proof for Mars Migration Theory.
- The collisions debris lost the great part of their momentum when reach to Mars
orbital distance point (227.9 mkm), because of that, Mars with its small mass could
attracted 2 moons, because the debris is too much around it and can attract them
easily.
- But Venus great gravity couldn't create even one moon because no debris be found
around it
Notice no.(2)
- The asteroid belt is one more proof for Mars Migration
- The collisions debris which were pushed with Mars motion to its current orbital
distance point (227.9 mkm) couldn't all be attracted by Mars gravity because of its
small mass, Mars had attracted only its 2 small moons
- But
- Jupiter great gravity attracted the rest debris and they created the asteroid belt.
- The whole trajectory is filled with references of the event and shows that it's a fact.

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Notice no.(3)
- Mars diameter before Migration was 7070 km and be 6792 mkm after migration as
a result for the collisions Venus and Earth
- We know that because
- The equation (7070 km x 1092
= 84 mkm), where 84 mkm=Mars original orbital
distance.
- The equation (d = r x 1092
) is the equation controls planet orbital distance based on
its diameter. The equation be used by Mercury, Earth and Saturn but the planets
migration effects negatively on the other planets using of it.
- From this analysis we conclude, Mars Diameter be decreased with 4.1%
- Additional Data
- Mercury Orbital Distance 57.9 mkm = Mercury Diameter 4879 km x 1092
- Earth orbital distance 149.6 mkm = Earth diameter 12756 km x 1092
- Saturn orbital distance 1433.5 mkm =Saturn diameter 120536 km x 1092
Notice no.(4)
- If Mars Mass be decreased as a result for the collisions with 8%, in this case
- Mercury mass (0.33) and its orbital distance (57.9 mkm) be in proportionality with
Mars mass (0.688) and Mars original orbital distance (84 mkm) based on Newton
gravitation Equation – this same proportionality be working also with the current
data of Jupiter and Saturn.

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9-2 Pluto Migration Theory
- Pluto Was The Mercury Moon
- One great force stroke Mercury, Pluto and Mars, with order
- Means,
- Mercury had received the most strong stroke directly, Mercury couldn't escape
from its fate. But Mercury axial tilt was (One Degree) and after the stroke be (0.01
Degree or even Zero)!
- The third stroke be received by Mars by which Mars had Migrated
- The second stroke be received by Pluto, which caused Pluto to be flying along the
solar system and reach to the end point of the solar system.
- The solar system end point with distance (5906 mkm) is a defined geometrically.
- Before Pluto migration –
- Neptune orbital distance was 5906 mkm
- Means,
- Neptune was in the position in which Pluto now be found. The distance 5906 mkm
was Neptune original orbital distance
- Pluto had flying along the solar system distance and reach to Neptune position, and
had collided with Neptune, pushed it out of its orbit and then put it out of (Pluto
Influence area) – That's why Pluto Neptune Distance = Pluto eccentricity Distance
Result No. 1
Mercury Pluto Distance = 5848 mkm = 101 x Mercury orbital distance 57.9 mkm
- This data is so important because the solar system distances be designed in
proportionality with it. based on that the rate (101) is one geometrical pillar in the
solar system design.
Result No. 2
Neptune Be Out Of The Network
- We will study that, the solar system distances be created in a network form in point
no. (12), with many proves we discuss this point…
- But

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- How the distances be created in a network form? We should answer this question
in details in that point no.(12) – but let's summarize the idea in following:
- Matter is created out of light and the planets be created of one light beam- light
motion creates the distances through which the planets move – by that –
- The Solar System Distances Be Similar To Railways
- And, the planets be similar to trains
- That shows why the planets motions be obligatory motions that because light
provides the required energy for distances creation and forces the planets to move
through these distances by this energy.
- Now, we have very (unclear) event – because –
- Pluto had pushed Neptune and put it Out Of The Railways
- That means, Neptune has no orbit and no definition of motion – and because of
that Neptune needed energy to build its orbit!
- Frankly
- I don't understand correctly the meaning of the network or how Neptune be out of
the network- because no space (I know) out of the network and I can't define any
point out of the network
- But
- This idea I have built on 2 data which are
- (1) Neptune Pluto Distance = Pluto Eccentricity Distance =1411 mkm
- (2) Neptune has seized 14% of Jupiter energy to create its orbital circumference
28255 mkm and this lost energy is registered clearly in the solar planets distances
as we have discussed in point no. (3) (Neptune and Jupiter Motions Analysis)
- These 2 data pushed me to conclude that, Neptune had no orbit and had to create
one for which Neptune seized the energy, Now this result must be done by the
collision between Neptune and Pluto.
Result No. 3
- Pluto and Neptune collisions caused to create Pluto moons and the Kuiper belt.

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9-3 Planets Migration Theories Proves
(Point No. 1) (Mars Migration Proves)
Mars Migration proves depends on the interaction of motion between Mercury and
Mars supposing that Mars was Mercury neighbor.
I- Data
(a)
(Mars Mass / Mercury Mass) = (6792 km/4879 km)2
(b)
(687 days /175.94 days) = (227.9 mkm /57.9 mkm)
(c)
7 degrees = 5.1 degrees + 1.9 degrees
II- Discussion
Equation No. (a)
(Mars Mass / Mercury Mass) = (6792 km/4879 km)2
= 0.524
- Where
- 6792 km = Mars diameter
- 4879 km = Mercury diameter
- Equation no. (a) tells that, Mercury And Mars Masses And Diameters Are Rated
With Each Other.
Notice
- Mars motion daily =0.524 degrees
Equation No. (b)
(687 days /175.94 days) = (227.9 mkm /57.9 mkm)
- Where
- 687 days = Mars Orbital Period
- 175.94 days = Mercury Day Period
- 227.9 mkm = Mars Current orbital distance
- 57.9 mkm = Mercury Current orbital distance

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- More data is rated between Mars and Mercury
- We should notice that, the data proportionality is done mostly between the
neighbor planets… for example
- Mars orbital period (687 days) = the moon orbital period (27.3 days) x 25.2
- Where 25.2 deg = Mars Axial Tilt. Also
- 25.2 deg = 1.9 deg x 13.17 deg
- Where, 13.17 deg = The Moon Daily Degrees
- And 1.9 deg = Mars orbital inclination
Equation No. (c)
7 degrees = 5.1 degrees + 1.9 degrees
- Where
- 7 deg = Mercury orbital inclination
- 5.1 deg = The moon orbital inclination
- 1.9 deg = Mars orbital inclination
- Mercury motion data shows a strong proportionality with Mars motion data which
gives reference that Mars once was a neighbor to Mercury.

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(Point No. 2) (Pluto Migration Proves)
Pluto Migration proves depends on the fact that Pluto was the Mercury moon and by
that Pluto be longed to the inner planets.
I- Data
(d)
Pluto is a planet belonged to the inner planet (small mass and long day period)
(e)
The rate (101) controls the solar system basic data
(Mercury Pluto Distance/ Mercury orbital distance) = 101
II- Discussion
- In Part no.(II) there are many other proves supports Pluto Migration Theory and
proves that Pluto be belonged to Mercury in its original case
- Notice
- 17.4 deg = 7 deg (Mercury orbital inclination) x 2.5 deg (Saturn orbital inclination)
- 17.4 deg = 5.1 deg (the moon orbital inclination) x 3.4 deg (Venus orbital
inclination)
- 17.2 deg = Pluto orbital inclination (error 1%)
- Notice
- Pluto Migration explains why bode law couldn’t predict Neptune Orbital Distance
– Because Neptune orbital distance be created as additional trajectory in the solar
system distances network – means- the equations be built on the original design
couldn't predict Neptune orbital distance because this distance be defined after The
Planets Migration.

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9-4 Is There An Absent Planet In The Solar Group?
- The planets motions data analysis tells that, one more planet should be absent from
the solar group
- This planet orbital distance was almost 71 mkm and its diameter was 6020 km =
Venus radius (0.5%)
- And its orbital period almost be 121 days and velocity 3.7 mkm per solar day –
these period and velocity values be calculated as a average based on the planets
required periods of time to pass distance = theory orbital distances
- There are 3 proves for this planet existence in the history which are
- (1) Mars and Pluto migration because the collision between Mars and this planet
caused reactions of these planets and by that the force pushed the 2 planets (mars
and Pluto)to migrate from their original orbital distances.
- (2) Mercury axial tilt was 1 degree and after this planet destruction be 0.01 deg,
that tells some change is found in Mercury motion forever.
- (3) many data of this planet be similar to Venus data which may show that Venus
may be created after this planet creation.
MORE DETAILS
- This planet was between Mercury and Mars ancient point (84 mkm) (in this
distance Mars require period to pass its orbital distance may be =24.6 days)
- Mars almost had collided with this planet and caused to destroy this planet.
- This is the catastrophe be occurred for the solar group before Mars migration,
- The reaction force of this collision had pushed Mars to migrate from its original
orbital distance (84 mkm) to its current one (227.9 mkm)
- The collision be done almost because of Mars eccentricity, but
- Mars couldn't destroy that planet if the collision depended on the eccentricity only,
Mars had depended on one more force which caused the collision to be so strong
and the other planet be destroyed in it.
- This force be found by an effect of Neptune.

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- Neptune was the planet behind Jupiter directly and occupied (2872.5 mkm) and
Uranus occupied in that time the point 5906 mkm which is the last point in the
solar system
- Neptune was very near to Jupiter- But Neptune effect in this collision still need to
be analyzed.
- The point is that, Mercury moves during 6 days a distance =24.6 mkm
- Mercury orbital inclination be 7 degree but Mercury axial tilt was 1 degree and by
that (7 degree – 1 degree) = 6 degrees = 6 days
- After Mars migration Mercury axial tilt be = 0.01 deg or even Zero.
- That means, the distance 24.6 mkm from which the period 24.6 days or 24.6 hours
(Mars rotation period) be created.
- I want to say,
- This period (24.6 hours) is produced based on the situation before migration. That
tells why this period is so important in the solar system motion data as we have
seen – because the new changes be built on the ancient geometrical design and
Mercury created this period 24.6 days or hours to be the connection point between
the repair process for the solar group and the ancient geometrical design.
- Notice
- The previous description tells that, the solar planets order was done similar to the
interference of young experiment of light coherence (double slits experiment)
- The planets were perfectly arranged as the fringes,
- Jupiter was the greatest fringe and found in the middle, and then
- The planets on its left be ordered as following (Earth – Venus – Mars – Mercury),
and we know that Pluto was the mercury moon, by that the planets order moves
gradually from the greater to the smaller perfectly as the interference fringes
- And the planets on Jupiter right side be in Order Neptune and Uranus
- Where Saturn wasn't created yet and Neptune was more near to Jupiter that Uranus
which occupied the point 5906 mkm

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- That tries to tell, the matter is a form of light coherence
- The Absent Planet Data
- Planet Orbital Distance = 71.5 mkm
- Planet diameter = 6020 km
- Planet Orbital Circumference = 449.4 mkm =2 x 224.7 mkm
- (7510 km /6020 km) = (6020 km /4879 km)
- Velocity =3.7 mkm per a solar day
- Orbital period = 121 solar days

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10- The Sun Age Description
10-1 Preface
10-2 The Sun Circles The Earth
10-3The Rate (1.0725)
10-4 The Sun Diameter Analysis
10.5 The Sun And Earth Motions Rate Of Time (1 day =365.25 days)
10-6 The Sun Rays Creation

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10-1 Preface
- The sun gives 2 reasons disproving Newton Theory of the sun mass gravity, which
are
- (1st
Reason) The sun is created after all planets creation and motion. that disproves
Decisively Newton Theory Of The Sun Mass Gravity
- (2nd
Reason) the sun light velocity =300000 km
- But
- The solar planets and their distances be created out of one light bam its velocity
=1.16 million km per second (as we prove in point no.11)
- That tells the light known velocity (.3 mkm/s) is created as a product from the
original light beam whose velocity 1.16 mkm/s
- That proves the sun is created after all solar planets creation and motions.
- The fact is that, the sun rays is created from the planets motion energies total as we
should prove in this point. This fact disproves Newton theory decisively
- The sun rays creation depend on the Sun And Earth motions rate of time which is
(1 day of the sun motion= 365.25 days of the Earth motion)
- The historical order can help our analysis.
o After Mars and Pluto migration, Saturn be created
o For that reason the period 10747 days is used by the moon and Saturn
motions (will be discussed in our analysis). (Notice Saturn is the last crated
planet)
o The sun is created after Saturn creation and depends on the period 365.25
days which be inherited in Saturn orbital period (10747 days).

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10-2 The Sun Circles The Earth
- The sun gives one face always to the Earth during the motion. although Earth
revolves around the sun a complete revolution, we always see the same face of the
sun, that tells the sun rotates with us giving The Earth The Same face always
- Can this motion refer to the Sun dependency on the period (365.25 days = Earth
orbital period)?
- Can that lead us to conclude, the sun be created after the Earth and because of that,
The Sun motion takes into consideration the period 365.25 days?
- Also
- The Sun Behavior is similar perfectly to the moon behavior, both give the same
face to the Earth during the motion.
- Why we accept that the moon be created after The Earth Creation but The Sun be
Created Before The Earth Creation? if the 2 behaviors are similar it may prove
both (the sun and the moon) be created after The Earth Creation.

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10-3 The Rate (1.0725)
I- Data
(A)
Why These Distances Are Equal?
(1)
Saturn Orbital Distance = Saturn Uranus Distance
= Mars Orbital Circumference
= Pluto Neptune Distance (error 1.5%)
= Pluto eccentricity Distance (error 1.5%)
= Neptune Orbital Distance/π
= Uranus Orbital Distance /2
= Mercury Jupiter Distance x 2
(2)
Mercury Neptune Distance = Saturn Pluto Distance
Jupiter Pluto Distance = Uranus Neptune Circumference
Earth Neptune Distance = Mercury Saturn Circumference (error 0.5%)
(3)
Jupiter Mercury Distance = 2 Mercury Orbital Circumference
Jupiter Venus Distance = Venus Orbital Circumference (error 1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (error 1.2%)
(Earth and Jupiter at 2 different sides from the sun)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (error 0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (error 0.8%)
Pluto Orbital Distance = Earth Orbital Circumference x 2π

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(B)
More Data
Why These Distances Are NOT Equal?
1. 0725
.
1
mkm
2.41
nce
Circumfere
Orbital
Moon
mkm
2.58
Motion
Daily
Earth
=
2. 1.0725
km)
(378500
radius
Eclipse
Solar
Total
km)
(406000
radius
orbital
Apogee
=
3. 0725
.
1
distance
Mercury
Jupiter
mkm
720.3
Distance
Orbital
Juppiter
mkm
6
.
778
= (Error 0.7%)
4. 1.0725
Distance
Venus
Jupiter
mkm
670
distance
Mercury
Jupiter
mkm
720.3
=
5. 1.0725
Distance
Earth
Jupiter
mkm
629
Distance
Venus
Jupiter
mkm
670
= (Error 0.6%)
6. 1.0725
mkm)
(1325.3
Distance
Venus
Sarurn
mkm)
(1433.5
Distance
Orbital
Saturn
= (Error 0.8%)
7. 1.0725
mkm)
(1205.6
Distance
Mars
Sarurn
mkm)
(1284
Distance
Earth
Saturn
= (Error 0.7%)
8. 1.0725
mkm)
(2644
Distance
Mars
Uranus
mkm)
(2872.5
Distance
Orbital
Uranus
= (Error 0.7%)
9. 1.0725
mkm)
(4495.1
Distance
Orbital
Neptune
mkm)
(4846
= (Error 0.5 %)
(10)
Notice
4846 mkm =the inner planets orbital circumferences total. it will be discussed with Jupiter
orbital circumference analysis
0725
.
1
T.
Axail
Earth
23.4
T.
Axail
Mars
25.2
T.
Axail
Mars
25.2
T.
Axail
Satrun
26.7
Tilt
Axail
Satrun
26.7
Tilt
Axail
Neptune
28.3
=
=
=

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II – Discussion
- We have discussed The previous data before
- 50% of all distances in the solar system be equal one another, and
- 40% of all distances in the solar system be rated one another with the same rate
(1.0725)
- Let's ask
- How this data can prove that (the sun is created after all planets creation and
motion)? let's answer in following
o The usual case is the equal distances as the data in Point no. (A), That
means, these rated distances were equal distances one another before and all
of them be effected by the rate 1.0725,
o Means,
o We have some historical order here, which is
o The distances were equal, but
o Some change caused these equal distances to be rated with (1.0725)
o And, 1.0725 = (100/100) + (7.25/100)
o We can conclude that,
o The distances were equal till The Sun Creation, and after the sun creation,
the sun obliquity on ecliptic (7.25 deg) caused the equal distances to be
rated with one another by the same one rate (1.0725).
o Means, the rate 1.0725 proves that, The Sun Is Created After All Solar
Planets Creation.
o One more feature supports this powerful argument, that
o The same rate (1.0725) is used for different distances. Because the sun
effects on all solar planets. That shows the rate (1.0725) must be related to
the sun because it's the same one rate. If this rate be belonged to any planet,
it will not effect on different distances equally because the sun only effects
on the planets equally. That shows the rate 1.0725 is belonged to the sun effect.

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10-4 The Sun Diameter Analysis
I-Data
1- Diameters
- (6792 km Mars Diameter) / (4879 km Mercury Diameter) =1.392
- (4879 km Mercury Diameter) / (3475 km the moon Diameter) =1.392 (1%)
- (71492 km Jupiter Radius) / (51118 km Uranus Diameter) =1.392
2- Distances
- (57.9 mkm Mercury orbital distance) /(41.4 mkm Venus Earth distance)=1.392
- (108.2 mkm Venus orbital distance) /(78.3 mkm Earth Mars distance)=1.392
- (149.6 mkm Earth orbital distance) /(108.2 mkm Venus orbital distance)=1.392
- (4267 mkm Mars Neptune distance) /(3061 mkm Saturn Neptune distance)=1.392
- (778.6 mkm Jupiter orbital distance) /(550.7 mkm Mars Jupiter distance)=1.392
- (550.7 mkm Mars Jupiter distance x 2) /(778.6 mkm Jupiter orbital distance) =1.392
- (5127 mkm Pluto Jupiter distance) /(3716 mkm Jupiter Neptune distance) =1.392
(error 1%)
- (5906 mkm Pluto orbital distance) /(4267 mkm Mars Neptune distance) =1.392
- (2872.5 mkm Uranus orbital distance) /(2094 mkm Jupiter Uranus distance) =1.392
3- Periods
- (243 days Venus Rotation Period) /(175.94 days Mercury day period) =1.392
- 2.5 deg (Saturn orbital inclination) /1.8 deg (Neptune orbital inclination) =1.392
- 1.8 deg (Neptune orbital inclination) / 1.3 deg (Jupiter orbital inclination) =1.392
- 5.1 deg (The moon orbital inclination) / 3.66 =1.392
4- The Sun Diameter
- 1.392 mkm (The Sun Diameter) = Venus Diameter 12104 km x 115.2
- 1.392 mkm (The Sun Diameter) = Mars Diameter 6792 km x 205.2
- 1.392 mkm (The Sun Diameter) = Neptune Diameter 49528 km x 28.3

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II- Discussion
- The data groups no. (1,2 and 3) show that,
- The rate 1.392 is used frequently among planets different data.
- Why? because
- The solar system is similar to one machine of gears and each planet is one gear in
it. because the machine moves one unified motion, the gears data should be in
proportionality with one another.
- Similar to that, the planets creation and motion data be created in proportionality
with one another. we will prove that in details in thus paper discussion.
- Based on this vision the solar planets data be created depends on one geometrical
design.
- The Sun Diameter Be defined geometrically before the sun creation.
- Because
- The machine depends on one geometrical design and each part should be created
in harmony with this geometrical design otherwise the machine can't work.
- We should notice that, the rate 1.392 is defined with the solar system creation
geometrically, Before the sun creation and also before the planets migration.
- This definition is done geometrically, so, the value (1.392) in the data is very
ancient. But the sun diameter (1.392 mkm) be created later.
- Let's discuss the data no. (4)

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Group Data No. (4)
- The sun diameter 1.392 mkm = Venus diameter 12104 km x 115.2 = Mars
diameter 6792 km x 205.2, But
- 25.2 + 90 = 115.2 and 115.2 +90 =205.2 where (25.2 degrees = Mars Axial Tilt)
And
- The sun diameter 1.392 mkm = Neptune diameter 49528 km x 28.3
- And 28.3 degrees = Neptune Axial Tilt
Discussion
- The data shows that, Venus, Mars and Neptune diameters are rated with the sun
diameter based on Mars axial tilt and Neptune axial tilt, Means,
- We have 3 planets diameters are rated with 2 planets axial tilts based on the sun
diameter.
- More logical that, the sun diameter is created after the 3 planets diameters,
depending on their values, causing planets axial tilts be created in proportionality.
- The opposite choice can't be working. Because if the sun be created at first and all
planets later, that creates a rule for the sun effect on the planets axial tilts, by that
we have to find (not) 3 planets only their axial tilts be rated based on the sun
diameter proportionality with their diameters, but found all planets behave by this
same rule because the sun has equal effect on all of them.
- The first option is more logical, that the sun is created after the planets creation and
the sun depended on 3 planets (specifically) for its diameter creation. by that the
data be more understandable
- Shortly
- The sun diameter analysis gives support for the claim (the sun is created after all
planets creation and motion).
Notice (1)
- In kepler third law in which (D3
= P2
x constant), the constant used for the solar
planets orbital distance and periods should be = 25

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10.5 The Sun And Earth Motion Rates Of Time
- One solar day of the sun motion = 365.25 solar days of Earth motion.
- This rate we have concluded because of the moon circumference, let's try to
explain that in following
o 10921 km (The Moon Circumference) x 86400 Seconds = 940 mkm
o This Equation tells. If Earth revolves around the sun a complete revolution
(=940 mkm = Earth Orbital Circumference) in one solar day only (86400
sec), in this case, the moon circumference (10921 km) will be equal the
Earth motion distance during 1 second.
o But, because
o Earth revolves around the sun in one year (=365.25 days), so this equation
may refer to a rate of time is used by The Sun herself.
o This is a conclusion needs a proof
o The conclusion tells
o 1 Day Of The Sun Motion = 365.25 Days Of Earth Motion
o Let's try to know how this rate be created in following

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(Point no. I) (Saturn Orbital Period)
I- Data
(1)
10747 days = 29.4 x 365.25 days
(2)
25920 mkm = 4.37 x 5906 =2.4 x 10747 = 0.838 x 30589
(3)
10 x 10747 days x 24 h = 10.7 h x 2 x 120536
(4)
4.7 km /s x 120536 seconds x 2 = 1.13184 mkm
II- Discussion
- Please note, this discussion depends on the discussions in points (5-7) and (5-8) of
this current paper.
- Now
- Let's suppose, 1 day of the sun motion =365.25 days of Earth motion.
- We here try to prove it and to know why Earth orbital period =365.25 days.
- Let's summarize the idea in following
o Earth orbital period 365.25 days and the rate of time (1 day =365.25 days)
depends on Saturn orbital period (10747 days) which depends on a machine
uses Saturn, Pluto, Uranus and the moon motions
o Means
o These 4 planets motions be interacted one another and caused to create Earth
orbital period 365.25 days in proportionally period 10747 days
o Let's move step by step with this machine:
o Equation no. (1), 10747 days (Saturn orbital period) = 29.4 x 365.25 days.
o The rate (29.4) between Earth and Saturn orbital periods we know from our
discussion for the planets motions rates of time.

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o But
o 29.53 days = the Earth moon day period.
o That makes Saturn orbital period is especial one for the Earth motion.
o Also
o The moon daily displacement (88000 km) needs (10747 days) to pass a
distance =940 mkm (Earth orbital circumference) (error 0.6%)
o This data creates a special connection between Saturn and Earth motions,
especially Saturn and Earth orbital periods.
o Many other data shows the proportionality between earth and Saturn, for
example
o (Saturn orbital distance /Saturn diameter) = (Earth orbital distance /Earth
diameter).
o (Saturn diameter)/ (Earth diameter) =(earth axial tilt) / (Saturn orbital
inclination).
o I try to show that many data of the 2 planets be in proportionality
o Equation no.(2) 25920 mkm = 4.37 x 5906 =2.4 x 10747 = 0.838 x 30589
o Where
o 4.37 mkm = the sun circumference
o 5906 mkm = Pluto orbital distance
o 10747 days = Saturn orbital period
o 30589 days = Uranus orbital period
o 2.4 mkm/day = the moon motion distance per a solar day
o 0.838 mkm/day = Saturn motion distance per a solar day
o Please remember
o Light known velocity (0.3 mkm/s) moves during a solar day (86400 sec) a
distance =25920 mkm.
o Equation no. (2) tries to show that, the connection of motions data which be
found between the Earth and its moon with Saturn this same connection is

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extending to contain Uranus motion in relationship with Saturn. By that
Saturn be the point between Uranus and Earth.
o I still try to support the connection be discovered by the data between Earth,
moon, Saturn and Uranus.
o Then
o The Part (25920 mkm = 5906 mkm x 4.37 mkm)
o This part tells the connection reach Pluto and based on these distance 25920
mkm the sun circumference be defined based on 5906 mkm = Pluto orbital
distance.
o Notice / 25920 mkm =940 mkm (Earth orbital circumference) x 27.5
- Please note, what do we try to do here is to show the connection of these planets
motions. I claim that the machine which created the orbital period (365.25 days)
and the rate of time ( 1=365.25) this machine depends on Saturn orbital periods
(10747 days) and this data tries to show, many data be created in proportionality
because of this machine.
- The previous data shows the connection between Saturn and Earth motion.
- Equation no. (3) (10 x 10747 days x 24 h = 10.7 h x 2 x 120536)
- Where
- 10.7 h = Saturn Day
- What does this equation tell?
- It tells, If Saturn diameter (120536 km) be used as a period of time (120536 hours)
in this case there's one equation controls the 3 periods of Saturn (10747 days, 10.7
hours and 120536 hours), that means these periods are connected together as one
period be used in different forms based on the situation.
- Why do we need this conclusion?

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- Because
- Saturn is connected with the Earth, its moon and Uranus by its orbital period
(10747 days) and connected with Pluto by its diameter value (120536 km) and I try
to show these connections are one connection. This connection is similar to a
straight line on which there are many points. Let's see equation no. (4)
- Equation (4), 4.7 km /s x 120536 seconds x 2 = 1.13184 mkm
- Where
- 120536 km = Saturn diameter (be used as a period (120536 seconds))
- 1.1318 mkm = Jupiter motion distance for a solar day
- We know that, the previous data is directed data and can't be created by any pure
coincidence, because
- Pluto (4.7 km/s) moves during 51118 seconds a distance =2 x 120536 km
- (51118 km = Uranus Diameter)
- Notice
- It's very hard to explain how the planet diameter or circumference be used as a
period of time, but it's one feature found frequently and we have no method to
refuse it, the example can help our discussion…
- Jupiter (13.1 km/sec) moves during 10921 seconds a distance = 142984 km =
Jupiter diameter. (10921 km = the moon Circumference)
- Uranus (6.8 km/sec) moves during 7510 seconds a distance = 51118 km = Uranus
diameter. (7510km = Pluto Circumference)
- Venus (35 km/sec) moves during 12104 seconds a distance = 421056 km = Uranus
motion distance during its day period. (12104 km = Venus Diameter)
- These are examples added to Pluto

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- The conclusion
- Saturn motion connects with Earth, its moon and Uranus motions through Saturn
orbital period (10747 days) and with Pluto motion through Saturn diameter
(120536 km).
- Where the periods (10747 days, 10.7 hours and 120536 hours) are connected
together by one equation and based on that the 5 planets motions be connected
together.
- Let's remember what we try to do?
- I try to prove that, Earth orbital period (365.25 days) be created depending on
Saturn orbital period by interaction of the 5 planets motions.
- Notice
- Saturn is the last planet created and be created after the Earth moon creation or in
the same time. By that the period 365.25 day (Earth orbital period) be found and
used before Saturn creation.
- But the point is that, the period 10747 days is defined before Saturn creation.
- Shortly
- Earth orbital period (365.25 days) is the most ancient period and these 5 planets
motions depend on it. but because Saturn is the connection point we have to put its
orbital period in the focus. So we understand that, Saturn orbital period (10747
days) is the motor but Earth orbital period (365.25 days) is the original period.

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(Point no. III) (Metonic Cycle)
- The Earth moon moves a cycle be called Metonic cycle continues for 19 years
(6939.75 solar days)
- And
- Uranus orbital distance =19.2 x Earth orbital distance,
- means, if the velocities are equal, in this case, while Uranus revolves around the
sun one revolution, Earth would revolve 19 revolution (19 years)
- based on this data I have concluded that the moon move Metonic cycle under
effect of Uranus motion. but the geometrical machine isn't clear because the
velocities aren't equal.
- I want to say that,
- The moon moves Metonic cycle under Uranus motion effect, and this effect is
transported by Saturn motion through Saturn orbital period.
- To prove that,
- The moon displacements total during Metonic cycle = 610 mkm
- Saturn moves during Metonic cycle a distance =5848 mkm = Mercury Pluto
Distance
- 9007 mkm (Saturn orbital circumference) /(610 mkm) = (51118 km/3475 km) =
(86.8/5.97) =(97.8 deg /6.7 deg) = (11.8/0.8) =
- 51118 km = Uranus diameter
- 3475 km = The moon diameter
- 86.8 x 1024
kg = Uranus mass
- 5.97 x 1024
kg = Earth mass
- 97.8 deg = Uranus Axial Tilt
- 6.7 deg = the moon Axial Tilt
- 11.8 deg = 5.1 deg (the moon orbital inclination) +6.7 deg
- 0.8 deg = Uranus Orbital Inclination

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- The data tries to show that, a great machine is found behind and caused many
different data to be rated by the same rate.
- The data tries to prove that, Uranus effect on the moon motion be done through
Saturn.
- Please remember that, Uranus caused the moon required period to be 1700 days
and Saturn required period is 1710.4 days with difference 251 hours which causes
the 2 planets use equal rates of time approximately (please review point no. 5-5)
- Shortly
- Metonic Cycle shows Uranus effect on Saturn and the moon motions, or shows
Saturn is the connection – point between Uranus and the moon.
(Point no. III) (Saturn and Pluto motions rate of time).
- Here we follow the rate (2.48) to show this rate transportation among the planets
(Saturn, Pluto and Earth)
- Pleas review in details the point no. (5-6) (Saturn and Pluto rate of time)
- The point shows in details that, the rate (2.48) is transported from Saturn to Pluto
an then to Earth.
- (for Earth data, 365.25 days = 2.48 x 149.6) where 365.25 days Earth orbital
period and 149.6 mkm + Earth orbital distance.
- The conclusion
- The rate (1=365) is created by an effect of the 4 planets motions interaction
- In more accurate words…
- Earth orbital period (365.25 days) is ancient period and
- The rate of time (1: 365.25) is the rate between the sun and Earth motions. and this
rate is created depend on Earth orbital period (365.25days), by using the 5 planets
motions interaction.
- Let's summarize how the sun rays be created in the next point.

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10-6The Sun Rays Creation
- Let's Summarize The Sun Rays Creation Idea In Following:
(Point No. A)
o The Solar Planets Move One Unified General Motion. This Idea we discuss
and prove clearly in this paper.
o The planets unified general motion causes to unify the planets velocities in
one unifies velocity = the planets velocities total.
o The 9 planets velocities total =176 km/sec,
o But
o The Earth moon is a player and its velocity should be added, where the
moon velocity be considered = Earth velocity because they aren't separated
from one another through their motions.
o The 10 planets velocities total be 176 +29.8 =205.8 km/s
o Based on this velocity (205.8 km/s) the sun rays be created
(Point No. B)
o The rate of time (1 day of the sun motion =365.25 of Earth motion)
o This rate of time we have discussed, and it depends on the 5 planets motions
interaction
o Notice the moon is a basic player as we see in the data, let's remember the
following equation
o 10921 km (The Moon Circumference) x 86400 Seconds = 940 mkm
o This Equation tells. If Earth revolves around the sun a complete revolution
(=940 mkm = Earth Orbital Circumference) in one solar day only (86400
sec), in this case, the moon circumference (10921 km) will be equal the
Earth motion distance during 1 second.

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o But, because
o Earth revolves around the sun in one year (=365.25 days), so this equation
may refer to a rate of time is used by The Sun herself.
o Let's use this idea as a hypothesis. where
o 1 Day Of The Sun Motion = 365.25 Days Of Earth Motion
o We suppose that's The Sun Rate Of Time
(Point No. C)
o The velocity (205.8 km/s) passes during a solar day (86400 s) a distance
=17.75 mkm
o 1 day of Earth motion = 237 seconds of the sun motion.
(This value depends on our hypothesis)
o Now
o The distance =17.75 mkm and the time =237 seconds what's the velocity?
o 75000 km/s = (a quarter Light Velocity) = 0.25 C
o But
o Earth has a cycle of 4 years (1461 days = 365 +365 +365 +366)
o Based on one year, the velocity be (0.25 C)
o And
o Based on the cycle (4 years), the velocity (0.25C) became (C light velocity)
o Based on this explanation the sun rays be created.
(Point No. D)
o There's one more method to create the sun rays
o 0.25 C x 4 C = C2
o Where
o The velocity 0.25 C is produced already in the previous discussion
o We need only the value (4C) to perform this equation

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o Jupiter motion enjoys by light motion supposed velocity (1.16 mkm/s) this
value is very near to our required value (4C)
o Light supposed velocity travels for 1 second and passed 1.16 mkm
o And
o Earth rotates around its axis one per solar day and move a distance = its
circumference =40080 km in a solar day
o If 1 solar day of Earth motion be = 1 second of light supposed velocity
motion.
o Based on that, the distances can be added
o 1.16 mkm + 40080 km = 1.2 million km = 4C
o By that the equation works
o 0.25 C x 4 C = C2
o That explains why Jupiter and The Moon data are the 2 basic players in the
sun data definition. Because the sun creation depends on Earth and Jupiter
motion. in addition to Uranus motion which is seen in the Earth moon
motion.
o The data explains how the sun rays be created
(Point No. E)
o The rate of time (1 solar day of planet motion = 1 second of light motion) is
the original rate of time in the solar system. We should refer to that in the
planets unified general motion discussion.
o The idea is that, the light motion for 1 second provides the required energy
for a planet to move one solar day, because the light motion depends on the
solar day as we have discussed. By that the planets divides this great rate of
time (1 sec = 86400 sec) on their motions to work as a great clock and
produce this rate by their Unified General Motion.
o The basic part (1 sec =365.25 sec) be between the Earth and the Sun motion.

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Extensive Discussion
- Why Does The Previous Investigation Prove The Claim?
- The claim tells that,
- The Sun Is The Solar System Last Created Piece. And that means, the sun is
created after All Planets Creation And Motion.
- If this fact can be proved, it will disprove Newton Theory of The Sun Mass
Gravity decisively.
- How to prove that the sun is created after all planets creation and motion?
- In addition to the historical proves there's one basic proof which is
- The sun rays velocity be = 300000 km
- While
- The solar planets matters and distances be created out of light beam its velocity
=1.16 mkm/sec.
- As a result, I have analyzed the planets data to prove that, this data be created
based on a light beam its velocity =1.16 mkm/sec
- After this analysis, we have to describe how the sun rays be created and the
previous data provides this description.
- Now
- Why Does This Analysis Provide A Sufficient Proof?
- The proof sufficiency depends on the arguments and discussions logic
- The discussions used hundreds of the planets data and put them in some form to
prove some idea. I can create the idea but can't create the data. that means if the
data be in harmony with the idea that supports the proof sufficiency.
- We have used hundreds of data in different discussion, if the discussion logic be
straight and the data be in harmony with it that proves the claim clearly
- The point is that, we searched for the rules based on which this data be created. so
as much as the used data be in harmony with these rules that prove these rules
sufficiency.

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- For example
- I claim (1 day of the sun motion = 1 year of Earth motion). this idea we have
accepted as a hypothesis and used it based on that
- But
- This idea is created because of the moon circumference equation (10921 km x
86400 seconds =940 mkm). Means, we have some data refer to this hypothesis.
- So we have used this idea as a hypothesis.
- We have found that, the data be in harmony and produce a velocity = (0.25 C)
- This velocity be created as a result for the hypothesis we suggested because of the
moon circumference
- But
- Earth Cycle (4 years) can change this velocity (0.25C) into ( 300000 km/s)
- I try to show that, w don't create the data
- We Rearrange The Data In New Positions Relative To One Another
- This is the basic method of the proof.
- Then we find that
- Jupiter (again) provides us a chance to create the value (C2
) (which can be a
source of the sun rays energy)
- So we used the velocity 1.16 mkm/s which we have learnt from Jupiter motion
data and added it to earth circumference to produce the required value (4C)

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- Notice
(A)
- The inner planets required periods total = 235.8 days
- The outer planets required periods total = 31469 days
- The solar planets required periods total = 31705 days
- 31469 days = 133 x 235.8 days (error 0.4%)
(B)
- The inner planets orbital periods total = 1480 days
- The outer planets orbital periods total = 196027 days
- The solar planets orbital periods total = 197027 days
- The total 197027 days = 1480 days x 133
(C)
- The solar planets orbital distances total = 16030 mkm
- 16030 mkm = 53.99 x 2 x 149.6 mkm (Earth orbital distance) (error 1%)
- Where
- 53.99 mkm = the distance be passed by Pluto in 133 days
- The data shows that the planets data system depends on the rate133 which is the
rate of time between Mars and Pluto, the 2 migrants planets.
- The geometrical system depends on these 2 planets rate of time because they had
migrated and it's necessary to depend on their motions to repair the negative results
of their migration –
- But in this process the system uses 149.6 mkm Earth orbital distance to prove that
Earth is a distinguish planet in the solar system and to prove that the sun circles
Earth based on a geometrical necessity defined by the geometrical design.

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11- Light Beam (1.16 mkm/sec) Proves
11-1The solar system Creation Theory
11-2 Light Beam (1.16 mkm/sec) Proves Discussion

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11-1The solar system Creation Theory
(I)
- Matter is Created out of light beam, and the born matter isn't separated from its
light parent but moves with it one unified motion by using different rates of time
between the matter and light.
- The matter is created of energy and the space is created of energy and by that, the
matter is created in motion.
(II)
- The solar planets and their distances are created from one light beam its velocity
=1.16 mkm/sec (The Theory Hypothesis)
- The energy of the light supposed velocity (1.16 mkm/sec) be used for the solar
system creation and by that this light beam motion features be registered in the
planets matters and their distances.
- The planets move in comparison with their parent light beam in one unified
general motion. by using different rates of time
- The basic rate of time is (1 Second Of Light Motion = 1 Day Of Planet Motion)
- Or
- (Energy of light motion for 1 second be used to move a planet for 1 solar day)
- This great rate be divided among the planets motions
(III)
- Based on this vision
- The Solar System Be Similar To A Great Clock.
- The Clock input is an energy of light motion for 1 second and the clock output is
an energy enough for a planet motion for 1 solar day –
- The rates of time be used by the planets to create One Unified General Rate Of
Time.

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(IV)
- The solar planets be similar to points on the same one trajectory of energy – or
they are knots on the same rope –
- Also
- The solar planets be similar to gears in one machine of gears – or the planets be
similar to puppets on a puppets theater –
- The rope can show the best similarity for the solar planets – the matter and apace
be created of light beam energy – and by that – the light creates planet matter and
its distance by light energy – by that – light created planet matter and its distance
to be in proportionality with other planets data because all of them be created out
of the same one energy.
- The creation process of planet matter and distance isn't discovered yet but the light
motion supposed velocity (1.16 mkm/sec) be registered in the planets motions data
and by that we discovered that these planets be created by this light beam energy.
(V)
- Because all planets be created of one light beam, the planets move with this light
beam and by that we conclude simply a light beam motion be in accompanying
with planets motions –
- Light motion be accompanying with one motion– because of that
- The solar planets motions be integrated into One Unified General Motion.
- The solar planets move one unified general motion – This motion be similar to
Train Carriages Motion – they all move together one unified general motion– spite
the planets velocities are different from one another – but as a machine of Gears –
the gears move by different velocities but create one unified general motion.
(VI)
- A river water motion can be very good example for our explanation ….

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- Imagine 9 waterwheels be built on one canal, so the 9 waterwheels rotate because
of the water motion (the water motion here is similar to the light motion and the
waterwheels are similar to the planets)
- This example is a great help for our explanation – the water motion direction is
perpendicular on the waterwheels rotation direction but no waterwheel can rotate
without water motion – also – the waterwheel motions effect one another because
they effect on the water amount for one another – that perfectly shows how the
solar system works
(VII)
- Now we have one more great help,
- The solar planets move One Unified General Motion because the light beam deal
with the unified motion of the planets
- The planets unified motion forces each planet to move a complementary motion
which can be integrated with one another to create the planets unified general
motion.
- Now each planet motion became (some how) obligatory motion because it should
be integrated with other planets motions to create the unified general motion.
- By that the planets motions be obligatory motions
- Planet data should be in harmony with this planet motion –the motion is obligatory
to be complementary with other planets motions – based on that – the planets
motions data should be complementary data with one another.
- Based on this vision
- There's one law controls all planets motions data –that because – the data should
be created in harmony with their motions and the motions must be complementary
to create one unified general motion.
- By that, the light beam motion controls the solar planets motions and their data –
shortly we have One Law controls all data.
(VIII)

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- Light supposed velocity (1.16mkm/sec) starts its journey from Mercury to Jupiter
directly and then Jupiter Energy is sent to Pluto directly (1st
trajectory)
- There's one more trajectory of light supposed velocity (1.16 mkm/s) motion starts
from Mercury also to Pluto directly – light supposed velocity by this motion
caused to create Mercury Day period (4222.6 h) –
- These 2 trajectories are light motions, but
- We analyze in comparison Mercury Motion following the light motion, and also
we analyze Saturn motion in parallel.
(IX)
- Jupiter motion distance during Mars rotation period (24.6 hours) be = 1.16 mkm
and this is the reason of the importance of Jupiter motion and Mars rotation period
– light supposed velocity moves for 1 second a distance = 1.16 mkm and that
creates the comparison of data with Jupiter motion.
(X)
- Light known velocity (0.3 mkm/sec) is found in the solar system and behaves as
the light supposed velocity effects on the planets motions data.
- But
- Light known velocity (0.3mkm/sec) is almost created later – because the sun is
created after all planets motions –and by that – the light known velocity (0.3
mkm/sec) be created almost as a side product from the original one the light
supposed velocity (1.16mkm/sec)
(XI)
- Spite the previous ideas – Jupiter motion data shows light supposed velocity (1.16
mkm/sec) effects more greatly than any other planet. This fact isn't solved yet –
Jupiter (all) distances be created based on the light supposed velocity (1.16
mkm/sec) – and this feature isn't seen in any other planet – nor even Mercury –
let's provide Jupiter list here to be a reference
- (1.16 mkm/sec) x 671 seconds = 778.6 mkm (Jupiter Orbital Distance)

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- (1.16 mkm/sec) x 629 seconds = 720.7 mkm (Jupiter Mercury Distance)
- (1.16 mkm/sec) x 580 seconds = 671 mkm (Jupiter Venus Distance)
- (1.16 mkm/sec) x 500 seconds = 580 mkm
- (1.16 mkm/sec) x 542 seconds = 629 mkm (Jupiter Earth Distance)
- (1.16 mkm/sec) x 940 seconds = 2 x 550.7 mkm (Jupiter Mars Distance) (1%)
- (1.16 mkm/sec)2
x 2 x 778.6 seconds = 2094 mkm (Jupiter Uranus Distance)
- (1.16 mkm/sec) x 3717 seconds = 4331 mkm
- (1.16 mkm/sec) x 5127 seconds = 5906 mkm (error 0.7%)
- (1.16 mkm/sec) x 2644.5 mkm = 3033.5 mkm (Uranus Pluto Distance)
(error 1%)
- Where
- 940 mkm = Earth orbital circumference
- 3717 mkm = Jupiter Neptune Distance
- 5906 mkm = Pluto Orbital Distance
- 2644 mkm = Mars Uranus Distance
- 4331 days = Jupiter Orbital Period
- The distances be used as periods of time to pass other distances – by this system
the distances be created in a network form -
- The distances rate is (1 mkm = 1 second) (this rate is used for light motion)
- And
- (1 mkm =1 solar day) this rate is the rate used by planets motions.
- Some very strange notice that Jupiter all distanced depend on (1.16 mkm/s)
- Notice
- Saturn motion data be in harmony with light known velocity 300000 km/s and this
is a distinguish feature for Saturn motion.

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11-2 Light Beam (1.16 mkm/sec) Proves Discussion
I - Data
(11-2-a)
1.16 mkm/s x 86400 s = 100733 mkm
And
0.3 mkm/s x 86400 s = 25920 mkm
(11-2-b)
1.16 mkm/s x 500 s = 580 mkm
1.16 mkm/s x 580 s = 671 mkm (Venus Jupiter Distance)
1.16 mkm/s x 671 s = 778.6 mkm (Jupiter Orbital Distance)
1.16 mkm/s x 629 s = 720.7 mkm (error 1%) (Mercury Jupiter Distance)
1.16 mkm/s x 5127 s = 5906 mkm (error 0.7%) (Pluto Orbital Distance)
(11-2-c)
1.16 mkm/s x 4224 seconds = 4900 mkm
(11-2-d)
1.16 mkm per second x 2 x 86400 seconds =2 x 100733 mkm = (37100 mkm – 4900
mkm) x 2π = 28255 mkm + 2 x 86400 mkm
(11-2-e)
1.16 mkm/s x 5040 seconds = 5848 mkm (Mercury Pluto Distance)
And
5848 mkm (Mercury Pluto Distance) – 4900 mkm = 948 mkm
(11-2-f)
1.16 mkm/s x 4900 seconds = 5678.1 mkm (Mars Pluto Distance)
And
1.16 mkm/s x 5687.1 seconds = 6585.4 mkm
(11-2-g)
193 seconds x 0.3mkm/sec = 57.9 mkm (Mercury Orbital Distance)
196.5 seconds x 1.16 mkm/sec = 227.9 mkm (Mars Orbital Distance)
(11-2-h)
5040 sec = 88 sec x 57.27 (this data answers why Mercury day = double its period)

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II- Discussion
Equation no. (11-2-a)
1.16 mkm/s x 86400 s = 100733 mkm
And
0.3 mkm/s x 86400 s = 25920 mkm
- Light known velocity (0.3 mkm/s) travels during a solar day (86400 s) a distance =
25920 mkm.
- Because it's a light motion we see this value (25920 mkm) as a period of time
(25920 years = the Precession Cycle)
- Also
- The distance 25920 mkm be = The Planets Motions Distances Total During A
Period =1461 days (where 1461 days =365 +365 +365 +366)
- Because the period 1461 days is (Earth Cycle) we consider that the distance 25920
mkm be mentioned by planets motions total
- Notice, the distances total added the Earth moon motion distance to the 9 planets
motions distance to create the total per a solar day (17.75 mkm) where the moon
motion daily distance be considered = Earth motion daily distance because they
aren't separated from one another through their motions.
- The light supposed velocity (1.16 mkm/s) travels during a solar day (86400 s) a
distance = 100733 mkm = The 9 Planets Orbital Circumferences Total
- Equation no. (11-2-a) tries to prove, Light Motion Uses The Solar Day Period
As Its Basic Period Of Motion.
- Light known velocity and light supposed velocity both use the solar day as the
basic period of time. Because of that, both light beams passes essential distances in
the solar system geometry.
- The next discussions will prove that these distances (25920 mkm and 100733
mkm) are essential distances in the solar system geometry.

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- Notice
- The rule tells
- (Light Motion For 1 Second = Planet Motion For 1 Solar Day)
- This rule which is a supposed one and we should prove it through the paper
discussions…
- This rule tells that,
- The light motion depends on the solar day as a period of time as similar to its
dependency on the second as a period of time.
- That means,
- These 2 periods of time (the second and the solar day) are the 2 basic columns for
light and planet motions accompaniment.
- And by that, light motion doesn't use the solar day as similar to any other planet
day period. On the contrary, the solar day is the basic period of time for light
motion (For both velocities, the known and supposed).

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Equation no. (11-2-b)
1.16 mkm/s x 500 s = 580 mkm
1.16 mkm/s x 580 s = 671 mkm (Venus Jupiter Distance)
1.16 mkm/s x 671 s = 778.6 mkm (Jupiter Orbital Distance)
1.16 mkm/s x 629 s = 720.7 mkm (error 1%) (Mercury Jupiter Distance)
1.16 mkm/s x 5127 s = 5906 mkm (error 0.7%) (Pluto Orbital Distance)
- The data is apart of Jupiter series we have seen, and the data shows specific feature
which is:
- The light supposed velocity (1.16 mkm/s) uses the distances values as a periods of
time by the rate (1 mkm = 1 second).
- Based on that, the distances be created depends on one another and no distance be
created independent from the other distances. means, the distances be created in a
network form of distances and not as independent distances from one another.
- The data shows how the solar system distances be created in a network form
- In details
- Light supposed velocity (1.16 mkm/s) uses the period (500 sec) to pass a distance
580 mkm, and
- Light supposed velocity (1.16 mkm/s) uses the distance (580 mkm) as a period of
time (580 sec) to pass a distance 671 mkm (= Venus Jupiter Distance), and
time (671 sec) to pass a distance 778.6 mkm (=Jupiter Orbital Distance), and
time (629 sec) to pass a distance 720.7 mkm (=Jupiter Mercury Distance), …etc
- We have discussed this data before but now we have another reading for this same
data
- Notice (The Distances Network Theory Be Discussed In Point No.12)

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The Motion 1st
Trajectory
- The Trajectory Summary
- Light supposed velocity (1.16 mkm/s) travels starting from Mercury to Jupiter,
creating Jupiter orbital circumference
- And, then
- Light supposed velocity (1.16 mkm/s) travels from Jupiter to Pluto (Directly) and
doesn't touch any other planet in the way.
- The motion trajectory is built on 2 basic equations and many other additional data.
because
- Mercury Motion uses light supposed velocity (1.16 mkm/s) because of that,
different data of Mercury motion be created based on this light supposed velocity
(1.16 mkm/s) energy
- Shortly
The motion 1st
trajectory is defined based on Equation no. (11-2-c) and (11-2-d) as
basic equations. And through discussion many other data be added
Notice
Equation no. (11-2-d) is the solar system geometry main equation and it's the paper
main one we discuss it along the paper,

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Equation no. (11-2-c)
1.16 mkm/s x 4224 seconds = 4900 mkm
- Where
- 4900 mkm = Jupiter Orbital Circumference
- Equation no. (11-2-c) tells, the light supposed velocity (1.16 mkm/s) travels during
4224 seconds a distance = 4900 mkm = Jupiter Orbital Circumference.
- Now, let's suppose 1 second of light motion = 1 hour of Mercury Motion
- based on that, 4224 seconds be equivalent to 4224 hours (but 4222.6 hours =
Mercury Day Period).
- Equation no. (11-2-c) provides 3 branches of data! let's summarize them:
- (1st
Branch) Light supposed velocity (1.16 mkm/s) moves in (4224 s) a distance
=4900 mkm but Mercury moves during (4222.6 h) a distance = 720.7 mkm
(=Mercury Jupiter Distance) and we suppose that 1 second of light motion = 1
hour of Mercury Motion. Because of that we need to find some connection
between 4900 mkm and 720.7 mkm to create a comparison between light motion
and planet motion.
- The comparison is complex because, I suppose the rate (2π) distinguish between
light and planet motions. By that, if light moves 4900 mkm, a planet motion
should be 778.6 mkm but Mercury motion distance only be 720.7 mkm, where,
- 778.6 mkm (Jupiter orbital distance) =1.0725 x 720.7 mkm (Mercury Jupiter
Distance)
- The rate (1.0725) creates a negative effect on the rule of the value (2π). although
the rate (1.0725) be used between 40% of all distances in the solar system. But
because it be found here creates more complexity for the discussion and causes
some negative effect for the comparison between light and planet motions. because
always in other data we have found that the value (2π) distinguish clearly between
light and planet motions but in our equation the rate (1.0725) causes some
difficulty for this comparison vision.

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- (2nd
Branch) Mercury Day Period Creation.
- We have supposed that, 1 second of light motion be equivalent to 1 hour of
Mercury Motion. that means the period (4224 s ) be equivalent to (4224 h) and
Mercury Day Period = (4222.6 hours).
- This supposition suggests that, Light supposed velocity (1.16 mkm/) motion causes
to create Mercury Day Period be (= 4222.6 hours).
- The data is accurate and clear
- NOW
- The data tells that…
- Mercury is the source of the light supposed velocity (1.16 mkm/s)
- The light supposed velocity (1.16 mkm/s) started from Mercury and sent to Jupiter,
creating the distance (4900 mkm = Jupiter Orbital Circumference).
- This motion depends on Mercury Day Period.
- As a result, Mercury Day Period (422.6h) be defined by light supposed velocity
(1.16 mkm/s) motion effect on Mercury Motion.
- i.e.
- Mercury Day Period = 4222.6 hours And
- 4900 mkm= 1.16 mkm/s x 4224 seconds
- We suppose that, 1 hour of Mercury Motion = 1 second of light motion… means
- The difference (4224 -4222.6 = 1.4) is created by the light supposed velocity (1.16
mkm/s) motion effect. that means,
- The light motion effected on Mercury Motion and caused Mercury day period to
be 4222.6 hours and less than 4224 hours with 1.4 hour = 5040 seconds
- Why??
- Because
- Light supposed velocity (1.16 mkm/s) travels during (5040 s) a distance =5848
mkm = Mercury Pluto Distance

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- The light supposed velocity (1.16 mkm/s) created a connection between Mercury
and Pluto motions by creating the period 5040 seconds as a difference between
Mercury Day period (4222.6 h) and 176 solar days (=4224 hours).
- We can't discover the geometrical machine behind this data. But the data clearly
shows that, the light supposed velocity (1.16 mkm/s) travels during 5040 seconds a
distance = 5848 mkm.
- We have 3 information we got based on this analysis which are:
- (1st
) Mercury Is The Origin Point Of The Light Supposed Velocity (1.16 mkm/s)
- (2nd
) light supposed velocity (1.16 mkm/s) motion created Jupiter orbital
circumference 4900 mkm.
- (3rd
) Mercury Day Period be (4222.6 h) and less than (4224 h) with (5040 s)
because of light supposed velocity (1.16 mkm/s) effect on Mercury motion, to
create a connection between Mercury and Pluto motions.
- A Question
- The accompaniment of The Light supposed velocity and Mercury Motions caused
Mercury day Period to be (4222.6 hours)
- Is There any Proof for this conclusion? Let's see it in following …

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Mercury Motion Data
- 5040 seconds = 84 minutes
- Mercury (4.095 mkm/ daily) moves during 84 solar days a distance = 344 mkm
- And
- Mercury (4.095 mkm/ daily) moves during 346.6 solar days a distance = 1419.5 mkm
- And
- Mercury (4.095 mkm/ daily) moves during 1419.5 solar days a distance = 5813 mkm
- (the difference between 5813 mkm and 5848 mkm is 0.6%)
- The mechanisms is complex, but the data shows Mercury motion follows light
motion. Also Mercury uses light motion strategy. By that it moves a distance and
use it as a period of time to pass another distance. Nothing is clear in this process –
but we have 2 things (the period 5040 seconds which is related to Mercury day
period and the distance 5848 mkm = Mercury Pluto Distance) these 2 values are
used by light supposed velocity motion now be used by Mercury Motion.
- For that reason I suppose Mercury follows light motion
- PLEASE NOTE
- Based on what this paper discussions be created?
- I Depend On The Planets Data Arrangement
- This is the main force behind the paper arguments. For example, I claim there's a
light beam its velocity =1.16 mkm/sec, I have no empirical proves for this light
beam existence –so – based on what – such heavy claim can be raised? Based on
the planets motions data arrangement and order -
- We have seen that all Jupiter distances be rated with (1.16 mkm/sec), So the
hypothesis tells (A light beam its velocity 1.16 mkm/sec be found in the solar
system) is an intelligent answer for all Jupiter distances –
- And here, we have many data of Mercury Motions be arranged logically based on
the velocity (1.16 mkm/sec). By arrangement all this data beside each other we
catch one clear idea about how the solar system works

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The Conclusions
- The data tells,
- Mercury is the origin point of the light supposed velocity (1.16 mkm/s) motion.
that means, the light starts its motion from Mercury point. (A Conclusion No. 1)
- The light supposed velocity (1.16 mkm/s) passes the distance (4900 mkm = Jupiter
orbital circumference) in a period (4224 seconds). By that the light connects
between Mercury motion and Jupiter motion. (A Conclusion No. 2)
- Mercury Day Period be less than (4224 hours) by 5040 seconds because light
supposed velocity (1.16 mkm/s) travels during 5040s a distance = (5848 mkm) =
(Mercury Pluto Distance)
- Light supposed velocity (1.16 mkm/s) uses (5040s) to pass the distance (5848
mkm) and create a connection between Mercury motion and Pluto motion. (A
Conclusion No. 3)
- Notice
- 5848 mkm (Mercury Pluto Distance) –4900 mkm (Jupiter orbital circumference) =
946.5 mkm
- Where
- 940 mkm = Earth Orbital Circumference (error 0.7%)
- The value (946.5 mkm) is very important we will discuss in 2nd
Trajectory of
motion because it's related to Saturn motion data.

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Mercury Motion Data Analysis (Continued)
- The previous data analysis concluded that, Mercury is the source of light supposed
velocity (1.16 mkm/s).
- So, let's ask,
- Is Mercury Motion data in harmony with light supposed velocity (1.16 mkm/s)?
(I)
- Light suppose velocity (1.16 mkm/s) needs only 50 seconds to pass Mercury
orbital distance (57.9 mkm).
- Can this (50 s) be a data belonged to Mercury Motion?
- Mercury (47.4 km/s) moves during 50.3 s a distance = 2390 km (Pluto diameter)
- Mercury (47.4 km/s) moves during 50.3 m x 60 s a distance = 142984 km (Jupiter
diameter)
- Mercury Venus Distance = 50.3 mkm ( 1mkm = 1 second)
- Mercury Neptune Distance (4437 mkm) = 50.3 mkm x 88
- (Mercury Orbital Period =88 days)
- Mercury Pluto Distance (5848 mkm) = 50.3 mkm x 116.2
- (57.9 mkm Mercury orbital distance x2 = 115.8 mkm)
- The data shows that, the period 50.3 seconds is a value be used frequently by
Mercury motion data. and mercury moves during (50.3 s) a distance = Pluto
diameter and moves during (50.3 m) a distance = Jupiter diameter, showing that
the 2 planets are the same planets mentioned by the 1st
trajectory motion.
- The basic difficulty is that, the light motion creates geometrical effects which we
can't discover because we don’t know neither their rule nor their effects. We have
only some data be transported from a point to another and that creates difficulties
for the analysis process.

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(II)
- Mercury Orbital Distance =57.9 mkm
- Mercury rotation period =58.65 solar days.
- The rate (1 mkm = 1 day) be used frequently in different motions data.
- The 2 values (57.9 mkm and 58.65 mkm) have an error (1%)
- Means, the 2 values (57.9 mkm and 58.66 days) can be created by the light
supposed velocity (1.16 mkm/s) motion during 50 seconds
- I try to show that, Mercury motion different data be in proportionality with light
supposed velocity (1.16 mkm/s) motion. which proves that Mercury is the origin
point of the light supposed velocity (1.16 mkm/s) motion.
- Because not only the period (5040 mkm) can be used or the period 4222.6 h
(which us equivalent to 4224 s) but also the period (50s)
- Notice
- 153.3 hours = Pluto day period
- 151.7 hours = 0.99 x 153.3 h (Pluto day period)
- But
- 176 mkm = 1.16 mkm/s x 151.7 seconds
- Where
- Mercury Day period =175.94 solar days
(If 1 day = 1 mkm, So 175.94 days be = 175.94 mkm)

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- (3rd
Branch) Saturn Motion Effect.
- Saturn (0.838 mkm / daily) moves during = 5848 days, a distance = 4900 mkm
- This data shows Saturn motion effect on Mercury motion data
- And
- We have to discuss Saturn data in a separated point because Saturn creates one
more reading for Mercury Motion Data

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Equation no. (11-2-d)
1.16 mkm per second x 2 x 86400 seconds =2 x 100733 mkm = (37100 mkm –
4900 mkm) x 2π = 28255 mkm + 2 x 86400 mkm = 202318 mkm (error 1%)
- Where
- 37100 mkm = Pluto Orbital Circumference
- 100733 mkm = The 9 Solar Planets Orbital Circumferences Total
- 28255 mkm = Neptune orbital Circumference
- Equation no. (11-2-d) is the paper basic equation. Because it explains The Basic
Energy Trajectory Through The Solar System…
- First, We remember that we have discussed this equation before but here we
discuss it through another approach which shows a different reading for the data
- Also we notice that,
- The equation uses the rate (2) because of Neptune orbital circumference. Where
the equation 3 parts can be used without the rate (2), But the last part (28255 mkm
+ 2 x 86400 mkm) needs the rate (2) because of Neptune orbital circumference
(28255 mkm). That explains why the equation uses the rate (2).
- Now let's divide the equation into 4 Parts.
(Part No. 1)
- 1.16 mkm per second x 2 x 86400 seconds = 2 x 100733 mkm
- Part no. (1) tells us a known information which is
- Light supposed velocity (1.16 mkm/s) travels during one solar day (86400s) a
distance = 100733 mkm = The 9 Solar Planets Orbital Circumferences Total
- The rate (2) is used for Neptune Orbital Circumference.
- This part of equation tells that, light motion depends on the solar day period. This
idea we have discussed in equation no. (1) of this discussion.
- Also we know that

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- Light known velocity (0.3 mkm/s) travels during (86400 s) a distance = 25920
mkm
- Where
- 25920 mkm = 17.75 mkm x 1461 days
- 17.75 mkm = the planets distances total during a solar day in addition to the Earth
moon motion distance during a solar day, and
- 1461 days = Earth Cycle (365 +365 +365 +366)
- The data tries to prove that, the light motion depends on the solar day period.
- Notice
- (25920 mkm x 2) =37100 mkm x 1.392
- Where
- The sun diameter =1.392 mkm
- The data uses the rate (2) because this rate be used in equation no. (11-2-d) which
expresses the solar system basic energy trajectory.
- That means the value (25920 mkm x 2) refers to the total energy according to light
known velocity (0.3 mkm/s) range of motion.
- The data tells the value (25920 mkm x 2) expresses really the total energy because
37100 km (Pluto orbital circumference) is the greatest orbit
- That means, when the total energy be expresses by the value (2 x 100733 mkm)
this energy be transported to the light known velocity based on the same rate
because it's one machine.
- The data proves the energy unification through the solar system spite of using 2
different velocities of light.

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(Part No. 3)
- 2 x 100733 mkm = (37100 mkm – 4900 mkm) x 2π =
- This part is very important because
- The data shows the energy motion (or light motion) started from 4900 mkm
- That means,
- To create Pluto orbital circumference 37100 mkm, the light starts from the point
4900 mkm and measures a distance = 100733 mkm by geometrical calculations.
- We have 3 points here
- The start point which is (4900 mkm =Jupiter orbital circumference)
- The direction of motion (toward Pluto)
- The measurement unit is 100733 mkm (defined by light supposed velocity motion
during a solar day)
- The data tells, Pluto orbital circumference is created depending on (4900 mkm )
Jupiter orbital circumference by using the light motion.
- We remember
- The distance 4900 mkm be passed by light supposed velocity (1.16 mkm/s)
depends on the period (4224 s) which is defined in comparison with Mercury day
Period (4222.6 hours)
- As A Result, we conclude that,
- Light supposed velocity (1.16 mkm/s) starts from Mercury to Jupiter and continues
from Jupiter to Pluto. that shows one clear trajectory of motion from Mercury to
Jupiter to Pluto.
- That means, the motion from Mercury to Jupiter considers Mercury is the head of
the inner planets and by that the connection between Mercury and Jupiter express
the connection between Jupiter and all inner planets.
- And
- The connection between Jupiter and Pluto doesn't contain any other planet. It’s one
directed motion from Jupiter to Pluto immediately

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- Shortly
- Jupiter and Pluto orbital circumferences be created by light supposed velocity
(1.16 mkm/s) motion depends on Mercury motion data by creating different steps
of motions to connect between Mercury and Pluto
- This data confirms that the distances be created based on network form and
according to one geometrical design.
Notice
- (2π) This rate distinguish between light motion and planet motion as we have
discussed before.
- The rate (2π) distinguishes here clearly between the planet and light motions.
where the difference (37100 mkm – 4900 mkm) refer to the planets motions where
the value 2 x 100733 mkm refers to the light motion and the rate (2π) distinguish
between the 2 motions.
- Venus equation which we will study with the part no. (4) of this equation uses also
the rate (2π) between the energy source and the planet received energy. we should
refer to this meaning in its discussion.
- And
- The data gives a new meaning for the rate (2π).
- It's the rate between light motion and planet motion or
- It's the rate between the giver energy motion and the receiver energy motion
- That tells Mars energy be provided by Jupiter motion and Pluto energy be
provided by Earth motion.

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(Part No. 4)
- 2 x 100733 mkm = 28255 mkm + 2 x 86400 mkm
- The total energy be reflected from Pluto to Neptune. The distances behave
perfectly as light beams.
- Neptune had seized 14% of the total energy and the rest of energy be reflected
toward the inner planets into 2 trajectories of energy each has (86400 mkm)
- We suppose that (Distance = Energy)
- The energy be sent from Neptune to Venus and Earth, let's see their equations in
following
- 2 x 86400 mkm = (28255 mkm – 680 mkm) x 2π (Venus Equation)
- Where
- 28255 mkm = Neptune Orbital Circumference
- 680 mkm = Venus Orbital Circumference
- Earth equation is perfectly similar to Venus equation where between both the error
is less than 1%
- Also we see the rate (2π) which distinguish between light and planet motion as we
have seen in our equation no. (11-2-c)
- (or it distinguish between the source of energy and the planet received energy).
- Part (4) of the equation tells that, Neptune had seized 14% of the total energy and
the rest of energy is sent to Venus and Earth into equal trajectories of energy each
has (86400 mkm).
- That means, the inner planets energy be received from Neptune. And because of
that, the inner planets distance be controlled by Neptune orbital distance (4495.1
mkm) as the data shows that clearly.
- 4495.1 mkm (Neptune orbital distance) = 78.3 mkm x 57.9 mkm
- = 108.2 mkm x 41.4 mkm
- = (149.6 mkm x 120 mkm)/4

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- Where
- 57.9 mkm = Mercury Orbital Distance
- 108.2 mkm = Venus Orbital Distance
- 149.6 mkm = Earth Orbital Distance 41.4 mkm = Earth Venus Distance
- 78.3 mkm = Earth Mars Distance 120 mkm = Venus Mars Distance
- Notice
- Because the distance=energy and the inner planets receive their energy by Neptune
for that reason, Neptune orbital distance control all most distances among the inner
planets.
- Now let's ask
- Why Neptune had seized 14% of the total energy but Pluto seized nothing?
- Because
- Mars Migration Theory tells us…
- Pluto was The Mercury Moon and had migrated with Mars Migration.
- Neptune, in that time, was occupied the point (5906 mkm = Pluto current orbital
distance). And
- Pluto be migrated and thrown to the end of the solar group, flying along way and
had collided with Neptune at the point (5906 mkm).
- Pluto had pushed Neptune and put it out of Pluto (influence area!), for that reason
Pluto eccentricity distance = 1410 mkm= Pluto Neptune Distance
- The collision between Pluto and Neptune produced Pluto moons and the Kuiper
belt.
- Neptune be forced to be more near to the sun with orbital distance =4495.1 mkm
and without orbit.
- Neptune be out of the distances network (the railways) generally and needed
energy to built its orbit
- That explains why Bode Law Couldn't predict Neptune orbital distance, because
it's created (additionally) on the original geometrical design to repair the planets

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migration negative effects on the solar system motion. means, it's a distance not
designed geometrically with the original design. So the equations depend on the
original design couldn't predict Neptune orbital distance.
Notice
- 202318 mkm = (449197 km)2
= 1.16 km/s x 2 x 86400 sec
- Where
- 449197 km =Jupiter Circumference
- Accurately
- (202318 mkm) / (449197 km)2
= (361/360)
- What's (361 degrees)?
- The cycle is 360 degrees but the Earth moon orbital regresses 19 degrees per year
and during 19 years moves Metonic Cycle (19 years) (=361 degrees).
- The moon orbit regression effects on many of the planets motions data and
because of that the usual rate (360) be changed into (361).

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The Motion 1st
Trajectory (A Summary)
- Mercury is the origin point of this motion trajectory
- The energy be transported from Mercury to Jupiter by the light supposed velocity
(1.16 mkm/s) motion and by this energy Jupiter orbital circumference be created
- The energy be transported from Jupiter to Pluto by the light supposed velocity
(1.16 mkm/s)
- The energy be reflected from Pluto to Neptune and
- The energy be reflected from Neptune to the inner planets
- The Motion 1st
Trajectory Shows the energy trajectory from Mercury to
Jupiter to Pluto, which creates the solar system basic energy trajectory.

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The Motion 2nd
Trajectory
- Light supposed velocity (1.16 mkm/s) travels starting from Mercury to Pluto
directly
- In this trajectory of motion the light doesn’t use a central point as did with Jupiter
orbital circumference. Instead the light travels from Mercury to Pluto directly.
- As a result, this Trajectory of motion be formed based on the following data,
- Light supposed velocity (1.16 mkm/s) travels during (5040 seconds) a distance =
(5848 mkm= Mercury Pluto Distance)
-
- This trajectory of motion we have studied deeply. Because the period (5040 s) is
distinguish Mercury day period as we have discussed.
- But this trajectory of motion still have more important data
- This trajectory of motion uses one equation only which is no. (11-2-e), let's discuss
it in following…

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Equation no. (11-2-e)
5848 mkm (Mercury Pluto Distance) – 4900 mkm = 948 mkm
And
5848 mkm (Mercury Pluto Distance) =5040 seconds x 1.16mkm/sec
- Where
- 5848 mkm = Mercury Pluto Distance
- 948 mkm = Earth orbital circumference (940 mkm) error (1%)
- Equation no. (11-4-e) shows Earth orbital circumference be taken into account
with the light supposed velocity motion for the 2 distances (5848 mkm and 4900
mkm)
- But
- Why the distance (948 mkm) be important here?
- The Earth moon daily displacement (=88000 km), and if the moon passes Earth
orbital circumference by using its displacement (88000 km), the moon needs a
period =10747 days to pass a distance = (945.5 mkm)
- Where 10747 days = Saturn Orbital Period
- The important information isn't (Saturn orbital period) but its (Saturn data),
because Saturn data be used frequently in the motions trajectories data between
Mercury and Pluto, for light and planet trajectories of motions.
- i.e.
- Through different data analysis we reach to Saturn data. this time we found (10747
days = Saturn orbital period), and in previous discussion we have found 3 data be
related Saturn motion defined by the light and mercury motions by using the
period (5040 seconds) which are:
o Saturn moves during (5848 days) a distance = 4900 mkm
o Mercury moves during (5040 seconds) a distance = 2 x Saturn diameters

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o Mercury moves during 1433.5 days a distance = 5870 mkm = Pluto orbital
distance (old definition) or near to (5848 mkm = Mercury Pluto Distance)
Where (1433.5mkm = Saturn Orbital Distance)
- Why (5848 mkm) – (4900 mkm) = 948 mkm (Earth Orbital Circumference)?
(error 1%)
- It's A Geometrical Distribution For Distances,
- But not only,
- Because this distribution contains data (10747 days) be used by Saturn and the
Earth moon motions…
- This data we should discuss with Saturn motion data because Saturn motion is
related to the light known velocity (0.3mkm/s) motion.
- The period 10747 days also be used by the moon to pass a distance = the distance
be passed by light known velocity motion during a solar day.

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The Motion 3rd
Trajectory
- Light supposed velocity (1.16 mkm/s) uses 2 different trajectories of motions (no.
1 and no. 2) to pass a distance =5848 mkm (Mercury Pluto Distance)
- And these motions be done by light velocity
- The first trajectory, the light travels from Mercury to Jupiter and then to Pluto
- The second trajectory, the light travels from Mercury to Pluto Directly
- The third trajectory expresses a motion from Mercury to Pluto (5848 mkm) but by
using mercury motion (Mercury velocity per a solar day =4.095 mkm)
- We have seen this data before, let's remember them:
o Mercury moves during 84 days a distance = 344 mkm
o Mercury moves during 346.6 days a distance = 1419 mkm
o Mercury moves during 1433.5 days a distance = 5848 mkm
o Where
o 5848 mkm = (Mercury Pluto distance)
o 1433.5 mkm = Saturn orbital distance
o 346.6 days = the nodal year.
- This trajectory of motion refers (frequently) to Saturn motion data among mercury
motion data. we don't know why that's happening…
- We can conclude that, the planet (Mercury) follows the light motion but with
different rate of time.
- Because this behavior is described by the matter creation theory. Where the theory
tells, the matter is born out of light but the born matter doesn't separate from its
light parent. On the contrary, they move together in one unified motion but by
using different rates of time.
- That's happening here. Mercury moves with light suppose velocity (1.16 mkm/s)
by using a different rate of time.

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Equation no. (11-2-f)
1.16 mkm/s x 4900 seconds = 5678.1 mkm (Mars Pluto Distance)
And
- Where
- 4900 mkm =Jupiter Orbital Circumference
- Light supposed velocity (1.16 mkm/sec) travels during 4900 seconds a distance =
5678.1 mkm (Mars Pluto Distance).
- We remember that,
- The light supposed velocity (1.16 mkm/sec) depends on the period (4224 sec) to
pass the distance 4900 mkm.
- And depends on the period (5040 second to pass) the distance 5848 mkm (Mercury
Pluto distance)
- And we have asked why light supposed velocity (1.16 mkm/sec) created 2
trajectories between Mercury and Pluto positions? Or in more clear words why
light supposed velocity creates Jupiter orbital circumference (4900 mkm)by using
(4224 seconds)?
- Equation no. (11-2-f) gives an answer.
- Because light supposed velocity creates a connection between Mars and Pluto
positions with Mercury.
- Mars migration theory tells, Pluto was the Mercury moon and Mars was the next
planet to Mercury. And the 2 planets were migrated from their original positions.
- Light supposed velocity (1.16 mkm/sec) creates a connection between Mercury
and Pluto through the period 5040 second and another connection between Pluto
and Mars through the distance (4900 mkm)

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- Notice
- Light supposed velocity (1.16 mkm/sec) travels during 5687.1 seconds a distance
= 6585.4 mkm
- By the rate (1 mkm = 1 day) this distance 6858.4 mkm be = 6858.4 solar days
- Where (Saros Cycle =6858.4 solar days)
- Please remember
- Light known velocity (0.3 mkm/sec) moves during a solar day (86400 s) a distance
=25920 mkm,
- Where we see this distance (25920 mkm) as a period of time (25920 years = The
Procession Cycle)
- I try to show that, the period of Saros Cycle (6585.39 days) is similar to the period
(25920 years), both be created by light motion behavior, which proves it's usual a
behavior in the solar system
- But that creates one more connection between Mars motion and the Earth moon
motion because Saros is a cycle produced by the moon motion effect.

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Equation no. (11-2-g)
193 seconds x 0.3 mkm/sec = 57.9 mkm (Mercury Orbital Distance)
196.5 seconds x 1.16 mkm/sec = 227.9 mkm (Mars Orbital Distance)
- Equation no.(11-2-g) tries to explain why Mercury and Mars Motions have
interaction as we have proved in Jupiter Motion Analysis
- The reason is that, the 2 planets orbital periods are defined based on equal periods
approximately (193 seconds and 196.5 seconds the difference 2%), by using the 2
light velocities
- That shows the period (193 sec or 196.5 sec) are the reason of the 2 planets
motions integration or interaction
- But
- As we have seen Jupiter motion also be integrated with Mercury and Mars motions
- Can this period (196.5 sec) effect on Jupiter motion also?
- Yes
- 8 Jupiter days = 8 x 9.9 x 3600 = 285120 seconds = π x 90756.5 seconds
- Pluto orbital period =90560 days
- 90756.5 seconds - 90560 seconds = 196.5 seconds
- Where
- Light motion uses any period (of 1 solar day) as (1 second)

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The Motion Trajectories Summary
- As we have discussed in the previous analysis,
- There are 3 motions started from Mercury moving toward Pluto, and these motions
are:
o Light supposed velocity (1.16 mkm/) motion during (5040 s) to pass (5848
mkm = Mercury Pluto Distance)
o Light motion from Mercury to Jupiter by using (4224s)
o 1.16 mkm/s x4224 seconds =4900 mkm (= Jupiter orbital circumference),
where Mercury uses Jupiter orbital circumference as its central point to
connect with Pluto.
o Mercury Motion depends on (5040) to pass in three steps toward Pluto by
the data
o 4.095 mkm x 84 days =344 mkm
o 4.095 mkm x 346.6 days =1419 mkm
o 4.095 mkm x 1433.5 days =5870 mkm (very near to 5848 mkm)
o Notice
o Light supposed velocity (1.16 mkm/s) motion depends on the rate (2π R) but
Planet motion depends on (R). So if Mercury want to connects with Jupiter,
light motion doesn't use the distance (778.6 mkm Jupiter orbital distance)
but use (4900 mkm =Jupiter orbital circumference)
o 778.6 mkm =1.0725 x 720.7 mkm (Mercury Jupiter Distance)

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Equation no. (11-2-h)
5040 sec = 88 sec x 57.27
5040 seconds are required for Mercury Day Period to be 176 solar days
88 days = Mercury Orbital Period
57.27 =Mercury Rotation Period / Mars Rotation Period
Let's remember our question
Why Mercury Day Period = 2 Mercury Orbital Periods?
4331 solar days = 24.6 hours x 175.94 = 687 solar days x 2π
Where
- 4331 days = Jupiter Orbital Period, and 175.94 days = Mercury Day Period, and
- 687 days = Mars Orbital Period , and 24.6 hours = Mars Rotation Period
- Based on this data we have concluded the following rates of time
- And
- 671 hours of Mercury Motion = 687 days of Jupiter motion = 109 days of
Mars motion
- The we have discovered that,
- During 671 hours Mercury moves a distance 57.2 mkm= 2 x Mercury Orbital
Distance (error 1%)
- And
- During 687 days Jupiter moves a distance 778.6 mkm = Jupiter Orbital
Distance
1 hour of Mercury Motion = 24.6 hours of Jupiter Motion
And
1 hour of Mercury Motion = 3.9 hours of Mars Motion
And
1 hour of Mars Motion = 2π= 6.3 hours of Jupiter Motion

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- And
- During 109 days Mars moves a distance 227.9 mkm = Mars Orbital Distance
- The question was
- Why Mercury moves distance = (2 x Mercury Orbital Distance), But Mars And
Jupiter Move Distances Only Equal Each Planet Orbital Distance?
- Then
- We have found, 5040 s are required for Mercury day to be =176 solar days
- And
- During 5040 seconds Mercury (47.4 km/s) moves a distance = 2 x 119448 km =
Saturn diameter (= 120536 km) (error -1%)
- But
- During 5040 seconds Mars (24.1 km/s) moves a distance =121464 km = Saturn
diameter (= 120536 km) (error +1%)
- This data gives one more reference that, the (one value for Mars) produces (2
values for Mercury)!
- We have a reason to find the rate (2) in data and because Mercury day = (2)
Mercury orbital period –some interesting feeling pushed to dig under this data may
we find answer why Mercury Day Period = 2 Mercury Orbital Period
- Let's return to the equation

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(Equation no. (11-2-h) (continued)
5040 sec = 88 sec x 57.27
- Light motion for 1 second causes a planet motion for 1 solar day,
- Because of this rule we couldn't discuss this equation in Jupiter Motion analysis
- Light moves 88 seconds and caused Mercury to move 88 solar day
- That means, this equation is Mercury orbital revolution equation… because of that
the rate (57.2) be produced, where 57.9 mkm =Mercury orbital distance (error 1%)
- Let's remember this data
- Mercury rotation period 1407.6 h / Mars rotation period 24.6 h = 57.2
- And
- Mercury day period 4222.6 h / Mars rotation period 24.6 h = 171.7
- Both values (57.2 and 171.7) are Mercury distances with the same error (1%)
- (57.9 mkm= Mercury orbital distance, and 170 mkm = Mercury Mars Distance)
- How Mercury orbital period 88 days can produce Mercury day period?
- 57.2 =2 x 28.6 (Neptune axial tilt =28.3 degrees error 1%)
- It's Neptune effect on Mercury Motion
- Why Neptune?? Because
- Neptune Orbital Distance 4495.1 mkm = π x Saturn Orbital Distance 1433.5 mkm
- Notice
- Neptune orbital period 59800 days = Mercury day period 175.94 days x 339
- But, Venus rotation period 5832.5 hours = Uranus rotation period x 339
- It's the machine by which the rate (5.1) be transported, let's remember it here
o Venus Velocity = Uranus Velocity x 5.1
o Mars Velocity = Pluto Velocity x 5.1
o The Moon Velocity = Neptune Velocity x 5.1
- That tells why
- Mercury moves during its rotation period a distance 243mkm (error 1%) and
- Mars moves during Venus day period a distance 243mkm (error 1%)
-

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The General Discussion
- I have tried to arrange the data in best form to show that, the data be created based
on a geometrical design for a light beam motion by which the solar planets and
their distances be created.
- The Theory hypothesis gives a chance for better explanation….
- The hypothesis tells a light beam its velocity (1.16 mkm/sec) caused the solar
system creation and motion, and by effect of the light motion the distances be
created in a network form.
- The hypothesis shows itself so complex because we need to prove (at first) that
there's a light beam its velocity =1.16 mkm/s
- By the planets motions data arrangement I have tried to show that the planets
motions data be created depends on a light beam its velocity =1.16 mkm/s and if
this light beam isn't found there's no chance to create the solar planets motions data
and their distances as their values. This discussion is done in so deep details where
Jupiter motion data and its distances with other planets, this all data will be simply
removed if there's no light beam its velocity =1.16 mkm/s.
- The data still have more support for the hypothesis but needs at first to discover
the geometrical design based on which the planets motions data be created.
- Although, this try is a strong one, but many basic questions are still left behind, we
have to face them as a part of our effort searching for the truth
- (A Question) what's the relationship between Planet motion distance and a
distance be found between 2 planets? If these 2 distances be equal why does this
give any geometrical meaning?
- For example
- Light supposed velocity (1.16 mkm/s) travels during 5040 seconds a distance =
5848 mkm = Mercury Pluto Distance
- What's the relationship between the distance be passed by light motion (5848
mkm) and Mercury Pluto Distance (5848 mkm)?

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- If these 2 distances are equal why this is important?
- My answer for this question is a simple one ( I Don't Know How The Machine
Works).
- For example
- Earth moves during a solar day (24 h) a distance = 2574720 km
- Pluto moves during its day period (153.3 h) a distance = 2593836 km
- The moon displacements total during (29.53 days) = 2598693 km
- These 3 distances are equal with max error only (1%)
- Can these equal distances effect on any planet motion data? yes
- As we discuss in (The Planets Motions Depend On Different Rates Of Time)
the three planets motion data be created in full proportionality with one another.
can this data be in proportionality because of the distances equality or the distances
equality be a result of the data proportionality, I can't give a decision.
- The fact is that, the planets data be in proportionality and the distances are equal.
- To prove this point of view let's bring the data here for better understanding…
- More Data
Group no. (1) (Pluto And Earth Rate Of Time)
- (Earth velocity / Pluto velocity) = (Pluto Day period/ earth day period) = 6.37 (0.8%)
- Pluto orbital distance 5906 mkm = Earth orbital circumference 940 mkm x 2π
- Pluto orbital period 90560 days = Earth Cycle (1461 days) x 2π3
Group no. (2) (Pluto And The moon Rate Of Time)
(1)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
(2)
Tan (12.2) x 708.7 hours = 153.3 hours
(3)
Tan (13.17) x 655.7 hours = 153.3 hours

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- Where
- 406000 km = Pluto Motion Distance during a solar day
- 88000 km = The moon displacement daily
- 708.7 hours = The Moon Day Period
- And
- 0.98562 degrees = The Earth Motion Degrees Per A Solar Day
- And
- 655.7 hours = The Moon Rotation Period.
- 153.3 hours = Also (153.3-) Pluto Rotation Period
- The data confirms the point of view, the equal distances effects on the planets
motion data be caused it to be in proportionality with one another. why or how?
We still search for the machine geometrical details.
- The discussion is limited and can't receives its power, as a creature crippled and
can't walk! Why? because we don't know the used geometrical rules based on
which the solar system be created and moving.
- For example
- The equal distances (as we have seen in Earth, its moon and Pluto data) is a
method used widely in the solar system. That means, all planets use this method.
All planets create equal distances with one another and based on these equal
distances the planets motions data be in proportionality with one another.
- Let's use one more example:
- Mercury moves during its rotation period (58.65 days) a distance = 243 mkm(1%)
- Mars moves during Venus day period ( 116.75 days) a distance = 243 mkm

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- These are the equal distances, where is the proportionality of data?
- (Mercury Day Period/ Venus Day Period) =(Mercury orbital period/ Mercury
rotation period)
- The data shows that, Venus Day period be created in proportionality with Mercury
cycles periods. Can that be a result for the equal distances?
- The equal distances is a method used thousands of times in the solar system, where
many planets motions distances be passed in defined periods of time be equal one
another. we don't know what effect be done from this distances equality and by
that a great part of the machine be out of our sight…
- Shortly,
- We have to depend on some conclusions (and even guess) to conclude how the
solar group be created and moving
- The other option is the imaginary ideas. As Newton idea of the sun mass gravity,
where he imagined that the sun is the planets motions reason while the fact is that
the sun is created after all planets creation and motion. and in fact the sun rays be
created by using the planets motions energies total. means, based on the planets
motions the sun be created, and that tells the planets can be found without the sun
but the sun can't be found without the planets. Newton idea is mistaken.
- Our situation is not so better. The point is that, the geometrical rules book is inside
the light nature, and we can't catch how the geometrical effects be done but we can
discover them in every where.
- Let's summarize the machine basic difficulties
o Planet moves side by side with a light motion by that the planet motion
refers to light motion features but we can't catch the velocity which creates
these features
o The equal distances method is the method caused the planets motions. this
method works geometrically.

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o That means, this method works as a waterwheel or as a lever. A tool works
by a geometrical rule and effect. But we don't understand what benefit be
produced by the equality of distances. This equality causes the planets
motions but how?
o We notice also that,
Jupiter motion depends on light supposed velocity (1.16 mkm/s) and
all distances around Jupiter be defined based on this velocity (1.16
mkm/) but
Saturn motion depends on the light (0.3 mkm/s) where different data
belong to Saturn depends on light known velocity.
The Earth moon motion be in proportionality with both light beam
velocities! The data confirms this meaning
10921 km x 27.3 days =300000 km (error 0.5%) the equation tells if
the moon rotates around its axis one time per solar day as Earth does,
the moon would pass by its circumference during 27.32 days (the
moon orbital period) a distance =300000 km = light known velocity
(0.3 mkm/s) motion distance during 1 second.
43000 km x 27.3 days =1160000 km (error 1.3%) the equation tells if
the moon is a point without circumference and moves from perigee
point to apogee point in a solar day and in the next day moves from
apogee to perigee … during the moon orbital period (27.3 days)the
moon would move a distance =1.16 mkm
Notice (43000 km = the distance between perigee and apogee points)
10921 km x 86400s =940 mkm, the equation tells if Earth revolves
around the sun a complete revolution (940 mkm) in one solar day
only (86400 s), the moon circumference (10921 km) will equal a
distance of Earth motion during 1 second period of time. (notice, the
geometrical design can create the effect without planet real motion)

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12-The Solar System Distances Be Created In A Network Form
12-1 Preface
12-2 The Continuum effect Through the Solar System Distances
12-3 The Solar System Distances Distribution
12-4 The Solar System Distances Dependency On One Another

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12-1 Preface
- The Solar Planets data analysis shows that, The Planets Distances Be Created In A
Network Form.
- Means,
- The solar system distances are considered as one geometrical design or one
geometrical system. There's no one distance defined as independent distance or
created out of this one geometrical design.
- Let's suppose, this geometrical design be a square. So all dimensions in this
square be defined geometrically based on this square angles and data. means no
one dimension can be created independently from this square data because all of
them are parts in the same one geometrical design.
- Suppose we have a triangle its 2 angles are (60 degrees and 80 degrees) what's the
third one? (40 degrees). Can this angle be any thing else than (40 degrees)? NO it's
obligatory value defined by the geometrical basic rules
- Similar to that,
- The Solar System Distances Be Created Based On One Geometrical Design.
- But
- By using this vision we will have surprises. Because this vision tells (for example)
Venus Jupiter Distance be= 671 mkm Because Earth Jupiter distance = 629 mkm
- That creates another vision
- While we consider Venus is a planet and Earth is another planet and they move
independently from one another. We are astonished now with this fact that, their
distances to Jupiter be defined based on one another! How? And Why?
- How (Because The Solar System Distances Be Created In A Network Form)
- Why (this answer was discussed in Mercury Motion Analysis)
- The fact is proved strongly that
- The Solar System Distances Be Created in A Network

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- There Are Many Basic Proves For This Fact which are:
- (1) The Continuum effect Through the Solar System Distances
- (2) The Solar System Distances Distribution
- (3) The Solar System Distances Dependency On One Another
- Let's discuss these proves in their details in following
- Notice
- The idea tells that,
- By energy the distances be created in a network form
- means
- The Distances Be Similar To The Railways And The Planets Be Similar To The
Trains Move On The Railways.
- The important point is that, the distance be created by energy and because of that
it's a defined trajectory of motion. that makes the planet moves in some obligatory
motion because the energy created the distances.
- Means, the distances aren’t common space but defined distances be built for
specific reason. Based on that (Distance = Energy)
- And
- The created distance defined a trajectory of motion
- As a result
- The solar system distances be as a map created by energy

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12-2 The Continuum effect Through the Solar System Distances
Point No. (I)
The Continuum Effect Description
I- Data
(1)
50% of all distances in the solar system be equal one another
(2)
40% of all distances in the solar system be rated one another
Let's provide this data in details in following:
Data Group No. (A)
(1)
(2)
Mercury Neptune Distance = Saturn Pluto Distance
Earth Neptune Distance = Mercury Saturn Circumference (0.5%)
(3)
Jupiter Venus Distance = Venus Orbital Circumference (1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (1.2%)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (0.8%)
(These Equal Distances Be Around 50% Of All Distances In The Solar System)

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Data Group No. (B)
10. 0725
.
1
mkm
2.41
nce
Circumfere
Orbital
Moon
mkm
2.58
Motion
Daily
Earth
=
11. 1.0725
km)
(378500
radius
Eclipse
Solar
Total
km)
(406000
radius
orbital
Apogee
=
12. 0725
.
1
distance
Mercury
Jupiter
mkm
720.3
Distance
Orbital
Juppiter
mkm
6
.
778
= (Error 0.7%)
13. 1.0725
Distance
Venus
Jupiter
mkm
670
distance
Mercury
Jupiter
mkm
720.3
=
14. 1.0725
Distance
Earth
Jupiter
mkm
629
Distance
Venus
Jupiter
mkm
670
= (0.6%)
15. 1.0725
mkm)
(1325.3
Distance
Venus
Sarurn
mkm)
(1433.5
Distance
Orbital
Saturn
= (0.8%)
16. 1.0725
mkm)
(1205.6
Distance
Mars
Sarurn
mkm)
(1284
Distance
Earth
Saturn
= (0.7%)
17. 1.0725
mkm)
(2644
Distance
Mars
Uranus
mkm)
(2872.5
Distance
Orbital
Uranus
= (0.7%)
18. 1.0725
mkm)
(4495.1
Distance
Orbital
Neptune
mkm)
(4864
= (0.5 %)
(These Rated Distances Be Around 40% Of All Distances In The Solar System)
Additional Data
(10)
0725
.
1
T.
Axail
Earth
23.4
T.
Axail
Mars
25.2
T.
Axail
Mars
25.2
T.
Axail
Satrun
26.7
Tilt
Axail
Satrun
26.7
Tilt
Axail
Neptune
28.3
=
=
=

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II- Discussion
- Let's suppose that,
- The solar planet moves independently from all other planets motions depending on
the sun mass gravity, in this case how these equal distances (50%) and the rated
distances (40%) be created?
- No logic can imagine a different reason for each 2 equal distances? We conclude
logically that (One Reason Caused These Distances To Be Equal)
- Based on that, we don't deal with independent distances instead we deal with one
machine be created by all distances integration. and As A Result, ONE REASON
effects on (the machine) caused (all distances to be effected by this one reason)
- I want to say,
- These 2 groups of data disproves Planet Motion Independency Concept.
- There's no way to create the equal and rated distances in huge percentage if the
planets motions be independent from one another.
- But
- Why These Distances Are Equal?
- The answer is somehow complex….. let's provide a short answer in following:
- The solar planets don't move by the sun mass gravity. But they move by equal
distances method (or at least the outer planets move by this method)
- The equal distances method is a method be used by many planets. Let's explain
how this method be used…. 2 Planets move equal distances in defined periods of
time (as example, Earth moves during its day period a distance =2.574mkm and
Pluto moves during its day period a distance = 2.598 mkm, these 2 distances are
different with 1% only and by that they can be considered equal distances. As a
result for these 2 motions equal distances Earth and Pluto motions data be in
proportionality with one another)

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- This feature be used hundreds of time by the solar planets, I guessed that, because
this method is used hundreds or even thousands of times in the solar system, this
method causes the planets motions (but I don't know how yet). The idea is that,
this method (the equal distances) works by a geometrical rule, as a waterwheel or a
lever, these methods work by geometrical rules. Similar to that the equal distances
method caused the planets motions
- As a result for using the equal distances method, 50% of all distances in the solar
system be created equal one another and also 40% of all distances be rated with
one another by the same one rate (1.0725)
- But , Please note
- The 50% equal distances be created because the solar system uses the equal
distances method as I have explained it before.
- But
- Why Does The Rate (1.0725) effect On 40% Of All Distances?
- The rate (1.0725) effect on (40% distances) is a proof for a continuous effect
through the distances. There's Some Effect Like A Continuum effects on the
solar system distances!
- How that can be done if the planets move independently from one another? and
- If the distances be created independently from one another how one effect can be
continuous through (40%) of all distances?
- I try to prove, the distances are created in a network or by one geometrical design.
- means,
- the distances be created together in one geometrical system as one machine
because of that one effect can continue through (40%) of all distances
- the explanation of using this rate (1.0725) isn't our question…. Our basic notice is
that this effect has a continuous task through the solar system distances which
can't be done except if these distances be created based on one geometrical system
or in one Network

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- I wish the argument is powerful and proved strongly
- The data gives us a chance to show that, the planet motion can't be independent
from other planets motions. we here don't deal with independent data but with one
system of data.
- Notice
- The Continuum Effect Through The Solar System Is A Powerful Proof For The
Planets Creation And Motion Depend On A Light Beam
- Because
- The Continuous Motion And Effect Is A Feature Of Light Motion – and by
that – the solar planets can't be described as separated rigid bodies.
- Based on that,
- The solar system distances as a network should be used as a proof for the solar
planets creation out of light.

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12-3 The Solar System Distances Distribution
(1st
Point) The Idea Explanation
- There are 2 basic features we should discuss about the solar planet motion, thee 2
features are:
- (1) The Planets Motions Use Different Rates Of Time
- (2) The Planets Motions Use The Distances As Periods Of Time
- These 2 features we have discussed before in this paper discussion
- I need here just to explain how these features be used to test their effects on the
distances distribution
- There are different rates of time be used by the solar planets example:
- 1 hour of Mercury motion = 24.6 hours of Jupiter Motion
- And
- We have seen the rate (4.61) be the working rate between Pluto and the Earth
moon motions.
- Because the distances be used as periods of time and vice versa, the causes the rate
of time to be used as rates among the distances – as we have seen that the rate
(4.61) controls 50% of all distances in the solar system.
- Let's remember this rate in following
- 1 hour of Pluto motion =8.5 hours of the moon motion
- 8.5 =2 x 4.25 but (4.61 = 1.0725 x 4.25) (error 1%)
- By that the rate (4.61) be produced based on the rate of time (8.5) between Pluto
and the moon motion. and for geometrical reason this rate is the working one – for
that,
- Pluto move during a solar day 406000 km = 4.61 x (88000 km)
- (The moon displacement per a solar day =88000 km),
- and
- 708.7 hours (The Moon Day Period) = 4.61 x 153.3 hours (Pluto Day Period)

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- Now this rate (4.61) we see in Pluto and the moon motion data, but because it
works as a rate of time, it effects great on the distances distribution, let's remember
its data in following…
(2nd
Point) The Rate (4.61) Effect On The Distances Distribution
I- Data
778.6 mkm (Jupiter Orbital Distance) = 4.61 x 170 mkm
550.7mkm (Jupiter Mars Distance) = 4.61 x 119.7 mkm
2094 mkm (Jupiter Uranus Distance) = 4.61 x 2 x 227.9 mkm
2872.5 mkm (Uranus Orbital Distance) = 4.61 x 629 mkm
3033.5 mkm (Uranus Pluto Distance) =4.61 x 654.9 mkm
5127 mkm (Jupiter Pluto Distance) = 4.61 x 2 x 550.7 mkm
5906 mkm (Pluto Orbital Distance) =4.61 x 1284 mkm
1375.6 mkm (Mercury Saturn Distance) =4.61 x 2 x 149.6 mkm
3062 mkm (Saturn Neptune Distance) =4.61 x 671 mkm
4345.5 mkm (Earth Neptune Distance) =4.61 x 940 mkm
4267.2 mkm (Mars Neptune Distance) =4.61 x 929 mkm
Where
170 mkm = Mercury Mars Distance
119.7 mkm = Venus Mars Distance
227.9 mkm = Mars Orbital Distance
629 mkm = Jupiter Earth Distance
654.9 mkm = Jupiter Saturn Distance
550.7 mkm = Jupiter Mars Distance
1284 mkm = Earth Saturn Distance
149.6 mkm = Earth Orbital Distance
671 mkm = Jupiter Venus Distance
929 mkm = Earth Jupiter Distance when the 2 planets be on the sun 2 sides
940 mkm = Earth Orbital Circumference (Max error 1%)

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II- Discussion
- The solar system orbital and internal distances total be (45 distances)
- The previous data shows that (22 distances) are rated with the rate (4.61)
- Means
- 50% of all distances in the solar system be rated with one another based on this
same rate (4.61).
- The data proves the distances distribution depends on the planets motions rates
time.
- The data proves, The Solar System Distances Be Created As A Network.

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(3rd
Point) The Distances Distribution Proof.
I - Data
Equation no. (A)
1.16 mkm per second x (2) x 86400 seconds =(2) x 100733 mkm = (37100 mkm –
4900 mkm) x 2π = 28255 mkm + (2) x 86400 mkm
- Where
- 100733 mkm = The 9 Planets Orbital Circumferences Total
- This equation is the paper main equation and we have discussed it deeply before
(Equation no. 11-2-d)
- The equation shows that, the solar system distances be distributed based on
geometrical design.

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12-4 The Solar System Distances Dependency On One Another
I-Data
(1)
1.16 x 580 mkm = 671 mkm (Venus Jupiter Distance)
1.16 x 671 mkm = 778.6 mkm (Jupiter Orbital Distance)
1.16 x 629 mkm = 720.7 mkm (error 1%) (Mercury Jupiter Distance)
1.16 x 542 mkm = 629 mkm (Earth Jupiter Distance)
1.16 x 5127 mkm = 5906 mkm (error 0.7%) (Pluto Orbital Distance)
(2)
1.16 x 778.6 mkm x 2 = 1806 mkm
1.16 x 1806 mkm = 2094 mkm (Jupiter Uranus Distance)
1.16 x 2094 mkm = 2 x 1205 mkm (error 0.8%) (Mars Saturn Distance)
(3)
(1.16)2
x 170 mkm = 227.9 mkm (error 0.4%) (Mars Orbital Distance)
Where 170 mkm = Mercury mars Distance
(5)
1.16 x 1980 mkm = 2296.8 mkm
1.16 x 2296.8 mkm = 2644.6 mkm (error 0.7%) (Mars Uranus Distance)
1.16 x 2644.5 mkm = 3033.5 mkm (error 1%) (Uranus Pluto Distance)
We have discussed this data before, let's summarize its idea

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II-Discussion
We have discussed this data before, let's summarize its idea
- The previous distances are example for similar huge number of distances which
depend on the rate (1.16)
- We should analyze this rate (1.16) later
- But
- We need here to see how the distances be distributed base don this rate (1.16)
- The next data can help our analysis greatly
More Data
- 778.6 mkm (Jupiter Orbital Distance) = 1.0725 x 720.7 mkm (error 1%)
- 720.7 mkm (Jupiter Mercury Distance) = 1.0725 x 671 mkm
- 671 mkm (Jupiter Venus Distance) = 1.0725 x 629 mkm
- 629 mkm (Jupiter Earth Distance) = 1.0725 x 580 mkm (error 1%)
- This data also proves, these distances be created based on a geometrical design.
Because the same distances be rated on (1.0725 and 1.16).
- Please remember 1.16 =(1.077)2
The analysis shows that the solar system distances can't be created interpedently from
one another but created in a network form. And because of that the distances be
distributed based on a geometrical design and as a result the distances be rated with
the rates (1.16) and (1.0725)

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Appendix no. (1)
The Solar System Equal Distances List
(A)
(1)
(2)
Neptune Orbital Distance = Saturn Pluto Distance
Earth Neptune Distance = Mercury Saturn Circumference (0.5%)
(3)
Jupiter Venus Distance = Venus Orbital Circumference (1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (1.2%)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (0.8%)
II- Discussion (A)
The previous distances form around 50% of all distances found in the solar system
(All orbital and internal distances)… Why These Distances Are Equal One Other?
We may notice that – the distances equality can be produced more easily by light
motion than the rigid body motion - for example – when we push a ball toward a wall
the ball after collision with the wall will return a distance (NOT) equal the original
one - because the collision causes to decrease the ball motion momentum – but the
light can be reflected at equal distances easily – means – equal distances can be
produced by light motion more easy than the Rigid Body Motion.

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(B)
19. 0725
.
1
mkm
2.41
nce
Circumfere
Orbital
Moon
mkm
2.58
Motion
Daily
Earth
=
20. 1.0725
km)
(378500
radius
Eclipse
Solar
Total
km)
(406000
radius
orbital
Apogee
=
21. 0725
.
1
distance
Mercury
Jupiter
mkm
720.3
Distance
Orbital
Juppiter
mkm
6
.
778
= (Error 0.7%)
22. 1.0725
Distance
Venus
Jupiter
mkm
670
distance
Mercury
Jupiter
mkm
720.3
=
23. 1.0725
Distance
Earth
Jupiter
mkm
629
Distance
Venus
Jupiter
mkm
670
= (0.6%)
24. 1.0725
mkm)
(1325.3
Distance
Venus
Sarurn
mkm)
(1433.5
Distance
Orbital
Saturn
= (0.8%)
25. 1.0725
mkm)
(1205.6
Distance
Mars
Sarurn
mkm)
(1284
Distance
Earth
Saturn
= (0.7%)
26. 1.0725
mkm)
(2644
Distance
Mars
Uranus
mkm)
(2872.5
Distance
Orbital
Uranus
= (0.7%)
27. 1.0725
mkm)
(4495.1
Distance
Orbital
Neptune
mkm)
(4864
= (0.5 %)
(10)
Discussion (B)
The same rate (1.0725) is used for all equations (around 18 distances = 40% of all
solar system distances) – why?
Suppose the equal distances are produced by light reflection and that cause these
distances to be equal – as I have supposed in the previous point (A).
Now suppose– part of these equal distances – is passed through another frame relative
to us – so this part of distances will suffer from Lorentz Length Contraction Effect
which is seen in the rate 1.0725
(Another frame can be found in the solar system because we deal with light motion) –
This explanation can answer why some distances are equal and others are rated with
the same rate (1.0725) – it's simply a feature of light motion.
0725
.
1
T.
Axail
Earth
23.4
T.
Axail
Mars
25.2
T.
Axail
Mars
25.2
T.
Axail
Satrun
26.7
Tilt
Axail
Satrun
26.7
Tilt
Axail
Neptune
28.3
=
=
=

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Claims Be Sent Against
The Decision Of Nobel Prize For Physics 2021

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The Honorable
United Nations Secretary-General António Guterres
On Tuesday 5th
October 2021 (4:30 pm - Cairo - Egypt)
Gerges Francis Tawdrous
47 years- Egyptian – Coptic
A Former Student – Peoples' Friendship Of Russia – Faculty Of Physics And Math –
physics department (2010-2013)
+201022532292
The Subject
- I send to your Excellency to claim against Nobel Prize Decision For Physics
2021
- Because
- I have published more than (500 papers) during 8 years (2013-2021) disproving
theories in the physics book and the decision ignored my work
- There's an important reason to send my claim to your Excellency specially
- Because
- I have written in my papers a refutation against basic theories in the physics
book, Specially Against Newton Theory Of The Sun Mass Gravity.
- There are 2 basic points I send to your Excellency for them which Are:
- (1st
Point)
- In physics usually we depend on the empirical results – but in the solar system
study we have no empirical results and because of that – many theories are built
on pure imagination- as a result the big bang theory be refuted recently and now
I disprove Newton theory of the sun mass gravity –
- My research depend on the planets motions data analysis and by that I provide a
method to test the theory –
- I want to say, the planets motions data using should open a new page in the
astrophysics research history because no longer we depend on the imagination
but we depend on the planets motions data analysis
- For that reason, my research provides a new vision for the solar system depend
on facts which is the planets motions data and doesn't depend on imagination as
Newton theory of the sun mass gravity
-
- The decision of Nobel prize physics 2021 doesn't see my work at all- while I
claim for basic mistakes in the physics book, someone should interest if they
want to correct the book- the point is that the book has lies and the decision
support these lies against the facts which are proved-
- That's why I send my claim to your Excellency because the decision result is to
misleading the whole humanity into lies in place of facts.

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- (2nd
Point)
- The big bang theory I have refuted since years
- During long period of time I have written many papers against this theory, But
All physicists supported this theory and claimed it's a fact – and I have tried
hardily to prove that this theory is mistaken – I did that by using planet data
analysis
- And after years, I have discovered some written book told the big bang theory
is refuted since 10 years!
- In that time I couldn't tell, it's me who refuted the theory (and some one may
stole my work). but in fact my work be lost in vain!
- I mean,
- They can do similar action with Newton theory of the sun mass gravity. I have
written more than 10 papers against this theory (Each paper more than 100
pages)- and then they ignore my work and will put any name on my work and
steal it
Please Help
Thanks Deeply from my heart bottom
Best Greetings
Gerges Francis Tawdrous +201022532292
Physics Department- Physics Mathematics Faculty
E-mail mrwaheid@gmail.com
Twitter https://twitter.com/GergesTawdrous1
Facebook https://www.facebook.com/gergis.tawadrous/
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Researchgate https://www.researchgate.net/profile/Gerges-Tawdrous
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJhl=en
box https://app.box.com/s/47fwd0gshir636xt0i3wpso8lvvl8vnv
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous
Slideshare https://www.slideshare.net/Gergesfrancis
Address /11 Mohamed Rageb st- Madenet El Saada – EL Materiya District – Cairo –
Egypt

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The Honourable
The Rector of
The Peoples' Friendship University Of Russia
On Tuesday 5th
October 2021 (4:30 pm - Cairo - Egypt)
Gerges Francis Tawdrous
47 years- Egyptian – Coptic
A Former Student – Peoples' Friendship Of Russia – Faculty Of Physics And Math –
physics department (2010-2013)
+201022532292
The Subject
- I send to your Excellency to claim against Nobel Prize Decision For Physics
2021
- Because
- I have published more than (500 papers) during 8 years (2013-2021) disproving
theories in the physics book and the decision ignored my work
- There's an important reason to send my claim to your Excellency specially
- Because
- I have written in my papers a refutation against basic theories in the physics
book, Specially Against Newton Theory Of The Sun Mass Gravity.
- There are 3 basic points I send to your Excellency for them which Are:
- (1st
Point)
- I'm a former student in the peoples' friendship university of Russia – and
- I couldn't return to Moscow to complete my study and had to stay in Egypt
since (2013 till now)
- I have consumed the period of time in study the solar system. and I have written
many hundreds papers about this subject
- (2nd
Point)
- In physics usually we depend on the empirical results – but in the solar system
study we have no empirical results and because of that – many theories are built
on pure imagination- as a result the big bang theory be refuted recently and now
I disprove Newton theory of the sun mass gravity –
- My research depend on the planets motions data analysis and by that I provide a
method to test the theory –
- I want to say, the planets motions data using should open a new page in the
astrophysics research history because no longer we depend on the imagination
but we depend on the planets motions data analysis
- For that reason, my research provides a new vision for the solar system depend
on facts which is the planets motions data and doesn't depend on imagination as
Newton theory of the sun mass gravity
-

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- The decision of Nobel prize physics 2021 doesn't see my work at all- while I
claim for basic mistakes in the physics book, someone should interest if they
want to correct the book- the point is that the book has lies and the decision
support these lies against the facts which are proved-
- That's why I send my claim to your Excellency because the decision result is to
misleading the whole humanity into lies in place of facts.
- (3rd
Point)
- The big bang theory I have refuted since years
- During long period of time I have written many papers against this theory, But
All physicists supported this theory and claimed it's a fact – and I have tried
hardily to prove that this theory is mistaken – I did that by using planet data
analysis
- And after years, I have discovered some written book told the big bang theory
is refuted since 10 years!
- In that time I couldn't tell, it's me who refuted the theory (and some one may
stole my work). but in fact my work be lost in vain!
- I mean,
- They can do similar action with Newton theory of the sun mass gravity. I have
written more than 10 papers against this theory (Each paper more than 100
pages)- and then they ignore my work and will put any name on my work and
steal it
Please Help
Thanks Deeply from my heart bottom
Best Greetings
Gerges Francis Tawdrous +201022532292
Address /11 Mohamed Rageb st- Madenet El Saada – EL Materiya District – Cairo –
Egypt

I do this research
2nd
297
References and Biography
Neptune Motion Analysis Disproves Newton Theory
https://www.academia.edu/59889782/Neptune_Motion_Analysis_Disproves_Newton_Theory
(Preprint No. 1) Mars Migration Theory
https://www.academia.edu/49051037/_Preprint_No_1_Mars_Migration_Theory
(Preprint No. 2) The Moon Orbital Motion Equation
https://www.academia.edu/49051029/_Preprint_No_2_The_Moon_Orbital_Motion_Equation
The Solar Planets Motions Description (Revised)
https://www.academia.edu/49464125/The_Solar_Planets_Motions_Description_Revised_
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944p=15209
Mr. Gerges Francis Tawdrous +201022532292
Please scan the figure (ORCID)

Why Should We Refuse Newton Theory Of The Sun Gravity (Part No.2)

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