Definition of space

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Definition of Space
By Gerges Francis Twadrous
2nd
course student – Physics Department - Physics & Math Faculty –
Peoples' Friendship University – Moscow – Russia -2010-2013
TEL +201022532292 georgytawdrous@yandex.ru / mrwaheid@gmail.com
The Assumption Of S. Virgin Mary -Written in Cairo – Egypt – 12th
October 2018
Abstract
The Space is Energy
This fact can be proved directly by Earth Jupiter Distance Analysis (627 million km)
That means the matter and distance are created from Energy regardless their different
forms (The sun rays is different from the oil but both are energy)
This fact supports the main idea in my research that:
The solar group is a trajectory of Energy and each planet is a point on this trajectory.
This paper aims to support my claim against Nobel Prize Board Decision –
in Physics -2018?
I provided the claim reason in my previous paper
Kepler 3rd
Law Explanation (a Claim Against Nobel Prize Board Decision in Physics 2018)
http://vixra.org/abs/1810.0053
Gerges Francis Tawdrous
TEL +201022532292
E-mail georgytawdrous@yandex.ru mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com/gergis.tawadrous
Academia https://rudn.academia.edu/GergesTawadrous
All my papers
http://vixra.org/author/gerges_francis_tawdrous

I do this research
2nd
2
1- Introduction
All my ideas and suggested theories depend on solar planets data analysis..
For example,
When we found that "d" (Mercury orbital distance) = "r" (Mercury diameter) x 1092
, and
found that Earth and Saturn follow this same Equation perfectly
(please review this Equation in "kepler 3rd
law Explanation" http://vixra.org/abs/1810.0053)
The previous data pushed me to expect that, there's a relationship between the planet
diameter and his orbital distance…. based on this expectation the following questions were
produced…
Is there a real relationship between the planet diameter and his orbital distance? How this
relationship can be created? And why some solar planets follow the Equation and other
planets don't?
The total solar eclipse phenomena supports the claim that, there's a relationship between the
planet diameter and his orbital distance…we can find this support when we answer our old
question… why we see the sun disc = the moon disc? Because (Sun diameter / Moon
diameter) = (Earth orbital distance /Earth moon distance)… why the diameters rate = the
distances rate? The usual answer was "by pure coincidence" in this case nothing can be
learnt ….!
But if the diameters rate = the distances rate because of a geometrical reason that will push
us to conclude that the planet matter and orbital distance must be created together as a
complementary to each other…
Theoretically how it's possible to find a relationship between the planet diameter and his
orbital distance?
Or to answer the direct questions … How the matter is created? What's the space?
We know the matter is Energy (E= mc2
), so if the matter and distance are created together as
a complementary to each other..
That means the Space also is Energy…
Let's describe that in details…
The matter is created in motion and for that the matter needs a space to move in…
That means each part of matter is connected with a part of space and the general space is
produced by summation of all these parts…
Shortly, I claim that the planet matter and orbital distance both are created from the same
energy regardless their difference in forms.
Now the solar group description will be different… because the distances between the
planets no longer be a space separates the planets from each other but becomes an Energy
trajectory…. And we know the planet matter is Energy also.. that provides 2 results:
1- The Planet mass is NOT independent but dependent on other planets data
2- The solar group is one Trajectory of Energy and each planet is a point on it.
 The previous conclusions explain the reason of the solar group motions harmony…

I do this research
2nd
3
Let's explain the result No. 2
 The solar group is created from one Energy. This energy creates the planet matter
and his orbital distance as a complementary to each other. That means the planet data
is created to be suitable for the planet motion which guarantees the solar group
motions general harmony.
 So the solar group is similar to a great river has many canals where these canals
created soils on their banks. So the river, canals and soils all of them are created from
the same water (matter and space are created from the same energy) which
guarantees the motions general harmony.
 Also the solar group is similar to one machine or body and each planet is a member
in this body, where all members are connected together by the same blood (the same
energy)…. That makes the distances between the planets as trajectories of Energy
and the planets as a store points of Energy which makes the solar group as one body.
Let's discuss the result No. 1
one of the classical mechanics pillars is the mass definition, where the mass independency is
a doubtless fact! Now how we can explain this result that the mass is dependent on other
planets data?
In my previous paper "Solar Planet Gravity Equation" http://vixra.org/abs/1808.0012
I provided an Equation defines the planet gravity based on his diameter and mass rates with
the Earth… I have showed that the sun herself follows this same equation which supports
my claim that the solar group is one machine or one body, each planet is a member in it.
In fact this description "the solar group is one body" shows a great importance for the
planets integration and cooperation.
But if this description is correct, the planet mass can't be independent from the planets other
data to support the solar planets motions general harmony.
This paper tries to prove 2 claims
1- The space is Energy
2- The planet mass is NOT independent but dependent on other planets data.
The Study Main Objective
This paper supports the main idea that the solar group is one Trajectory of Energy, and each
planet is a point on this trajectory (or one body and each planet is a member in this body)
(For the question, why some planet follow the Equation d = r*1092
but others don't? that because of
Mars Immigration … review Mars Immigration Proves (Revised) http://vixra.org/abs/1807.0268)
2- Methodology
I use the same method in all my researches, The Planet Data Analysis…
Let's explain the idea here again
In Pythagoras triangle we found that a2
+ b2
= c2
, this rule we can conclude from the triangle
data if its dimensions are 3, 4 and 5… so the data may show the geometrical rules….similar
to that, I use the solar planets data analysis to conclude the main geometrical rules which
explain the solar planets origin and motion…

I do this research
2nd
4
3- Earth Jupiter Distance 627 mkm
Data
Group No. I
Equation No. 1
The period 6939.75 seconds x c2
= 627 million km
Equation No. 2
The Value 6939.75 = 2666.7 x 2.6
Equation No. 3
940 mkm = 361 degrees x 2.6
Equation No. 4
1/2.6 mkm = 0.384 mkm
Group No. II
Equation No. 5
1898 x 0.33 = 627
Additional Equation No. c
102 x 5.97 = 609 (this value = 627 with error 2.8%)
Group No. III
Equation 7
d- 1898 km x 627km = 1.19 mkm
Equation 8
2666.7 x 1024
kg (solar group total Masses) = 2466.7 (rate 13.4) + 200 (rate 1)
DistanceJupiterEarthmkm627
DistanceanusJupiter Urmkm2088
MassSaturnkg10568
MassJupiterkg101898
24
24




I do this research
2nd
5
3-1 The Discussion of Data Group No. I
In my try to understand the solar group geometry I found that, our Geometry Science is
insufficient to explain the solar group geometry where many new rules we need to learn to
see much better the picture…
Let's discuss one example in following..
We know the E=mc2
… where m = mass and E= Energy
Let's see our Equation …
Equation No.1
The period 6939.75 seconds x c2
= 627 million km …
How to understand this equation?
The light with c velocity (0.3 mkm/sec) needs 6939.75 seconds to cover a distance = 2088
mkm (Jupiter Uranus Distance)….
The light with c velocity also needs 2088 seconds to cover a distance = 627 mkm (Earth
Jupiter Distance)
So, if we suppose that the value 2088 mkm works as 2088 seconds for some geometrical
reason, that makes Equation No.1 consistent
But what does Equation No.1 tells us?
mc2
=E…! 6939.7 seconds is a period and NOT mass where 627 mkm is a distance and NOT
Energy (my hypothesis is ……. Distance = Energy)
How can we understand this Equation?
Let's see Equation No.2
Equation No.2
6939.75 = 2666.7 x 2.6
Let's define the previous values
- 6939.75 seconds are needed for light (c velocity) to cover Jupiter Uranus Distance
2088 mkm, and also 6939.75 days is Metonic Cycle…
- 2666.7 x 1024
kg = the Solar Planets Masses Total
Note Please
In all Masses Equations the factor 1024
is the main problem, till now I didn't solve it. so I
have to ignore it in my discussion till we reach to the general accurate description…
What does Equation No.2 tell us?
The Solar Planets Total Masses 2666.7 x 1024
kg can be seen as Metonic Cycle Period (or
light travel period ) Based On The Rate 2.6
The Masses total is seen as a period of time…. This idea isn't very strange because we know
mass = Energy and distance = Energy where I claimed that the time and distance values can
be equivalent in some solar planets data (this equivalence I claimed is found because of
high velocity motion – please review the time definition http://vixra.org/abs/1805.0523)
Shortly
The solar group is created from one energy, where the mass and distance both are created
from the same energy. So the energy is seen by us as masses or as distances but we know
that the time and distance values sometimes can be equivalent… that's why the Masses can
be seen as a period of time…
The masses value is seen as a period of time based on this rate 2.6 and what's this rate?

I do this research
2nd
6
3-2 The Rate 2.6
I- Data …..Equation 3 and 4
3- 940 mkm = 361 degrees x 2.6 mkm
4- 1/2.6 mkm = 0.384 mkm ……Please Note also the following
a- 180 degrees = 177.4 degrees (Venus axial tilt) +2.6 degrees
b- 2.58 mkm (Earth daily velocity) x 6939.75 days (Metonic Cycle Period) = 18000
mkm (Uranus orbital Circumference)
II- Discussion
2.6 isn't just a number
This value defines Earth and moon interactive motions ..
Venus axial tilt needs 2.6 degrees to be 180 degrees …
And we know that …..1 degree = 1 mkm
So 2.6 degrees = 2.6 mkm ……….But
1/2.6 mkm = 0.384 mkm (Earth Moon distance in average orbit radius)
That tells us the moon defines his position from Earth based on the value 2.6 mkm
Equation No. 3
940 mkm (Earth orbital Circumference) = 361 degrees x 2.6 mkm
Equation No. 3 tells us that, if Earth revolution around the sun is divided by 361 degrees,
each 1 degree will equal 2.6 mkm … now we can see that the rate 2.6 expresses a
relationship between Earth and Venus, by this relationship the Moon is created (with
Support from Uranus!)…. That supports my claim "the moon belongs to Venus and Earth".
(For example the moon orbit regress 19 degrees yearly.. but 19 degrees = 2π *3.02 degrees,
where Venus daily motion =3.02 mkm)
Any way Equation No.3 tells us one more important information that, the Earth revolution
total degrees aren't 360 degrees but 361 degrees and why?
Because 19 degrees (the moon orbit regresses yearly) x 19 sidereal years = 361 degrees
(total degrees of Metonic Cycle)…
That means Earth rotates Metonic Cycle with her moon but this Cycle isn't seen in Earth
motion (unknown reason till now) but the Cycle is seen in the moon motion…!
Equation No. b
2.58 mkm (Earth daily velocity) x 6939.75 days (Metonic Cycle Period) = 18000 mkm
(Uranus orbital Circumference)
Shortly Earth moves during Metonic Cycle a distance = Uranus Orbital Circumference… in
my previous paper "Does The Moon move by Gravity?" http://vixra.org/abs/1810.0089 I
explained the strong relationship between the Moon and Uranus which tells us that Earth
rotates in fact Metonic Cycle.
The conclusion
Metonic Cycle effects on more than one planet motion (Moon, Earth and others), that
because… Metonic Cycle Period (in days) is born from the light travel period (in seconds)
from Jupiter to Uranus, and this period is the energy which causes Metonic Cycle from
which The solar planets Masses total is found depending on Earth-moon interactive motions
(the rate 2.6) …
Shortly…. E=mc2
this equation control our Equation 6939.75 seconds x c2
= 627 mkm
Where …6939.75 seconds expresses the solar planets total Masses
627 mkm expresses the resulted energy (distance = energy)

I do this research
2nd
7
3-3 The Discussion of Data Group No. II
5- 1898 x 0.33 = 627
Also
c- 102 x 5.97 = 609 ( =627 with error 2.8%)
In my paper (solar Group Geometry Part I http://vixra.org/abs/1509.0126)
I have discussed the following fact:
Earth mass = 4 planets total masses (Mercury + Venus +Moon +Mars)
(in fact 4 planet masses = 99% of Earth Mass)
And I have asked why…? We may remember Anderson experiment which produced
electron and positron from Gamma rays (1.2 mev) (2 particles equal in mass and different in
charge)
Let's imagine that the 5 inner planets are produced from great Gamma rays, which produced
one great electron (Earth) and one great positron (Mercury+ Venus+ Moon + Mars)
What does mean the great electron?
Earth atom has a positive nucleus and negative charges move around
But what does mean the great positron?
The 4 inner planets atoms have a negative nucleus and positive charges move around…
Now the attraction between the 5 inner planets depend on the charges attraction and not on
the gravity…
Based on this old description let's try to understand the previous equations…
Equation No. 5
1898 x 1024
kg (Jupiter Mass) x 0.33 x 1024
kg (Mercury Mass)= 627 x 1048
kg
I ignore the factor 1024
…! And then the Equation will be
1898 x (Jupiter Mass) x 0.33 (Mercury Mass)= 627 (Earth Jupiter distance =627 mkm)
M1 x M2 = E
We know if electron collide with positron the result will be Energy….!
We have 2 masses collide with each other and the result is the same distance 627 mkm
I understand that the factor 1024
effects greatly in the equation explanation, but we may
consider that as units configuration.. for example 627 is million km and not km… that
means the factor 1024
may be consumed in unit configuration process.
So equation no.5 tells us that 2 solar planets masses collision produced this distance 627
mkm which we should consider as Energy…
I wish the reader sees that we use 2 physical equations (E=mc2
and E= m1m2) and we reach
to the same distance 627 mkm … I see some support for my claim spite of its difficulty..
Equation No. c
102 * 1024
kg (Neptune Mass) x 5.97 * 1024
kg (Earth Mass) = 609 ( =627 with error 2.8%)
Spite of the great error…
I see the same distance is produced…
I wish the reader sees with me that the planet data gives us one clear direction.
Yes I don't know the geometrical structure which is behind all this data but I can see easily
that this data is produced related to each other and not independent which supports the main
idea that the solar group is one trajectory of Energy…

I do this research
2nd
8
3-3 The Discussion of Data Group No. III
Equation No. 7
d- 1898 km x 627km = 1.19 mkm
Equation No. 8
2666.7 x 1024
kg (solar group total Masses) = 2466.7 (rate 13.4) + 200 (rate 1)
Equation No. 7
We have studied the distance 2088 mkm (Jupiter Uranus Distance) frequently, and we
know that this distance is Metonic Cycle energy source where the light with c velocity
needs 6939.75 seconds to pass from Jupiter to Uranus…
And we have studied in Equation no.1 (627 mkm = 2088 seconds x c velocity), that means
both distances are important and related to each other strongly
But
What does Equation No. 7 tell us?
Equation 7 tells us that, Jupiter mass/ Saturn Mass = distance 2088 / distance 627… but we
know that the distances 2088 and 627 are related to each other…
Does that mean Jupiter Mass and Saturn Mass are related to each other?
Let's see Equation No. 8
Equation No. 8
2666.7 x 1024
kg (Solar Planets Total Masses) = 2466.7 (rate 13.4) + 200 (rate 1)
2666.7 x 1024
kg = (Solar Planets Total Masses)
2466.7 x 1024
kg = Jupiter Mass + Saturn Mass (rate 13.4)
200 x 1024
kg = rest planets masses total (rate 1)
What does that mean?
The solar planets masses total 2666.7 is divided into 2 parts by rate 13.4 to 1
The rate 13.4 produced the value (2466.7 x 1024
kg = Jupiter Mass + Saturn Mass)
and the rate 1 produced (200 x 1024
kg = the rest planets masses total)
Why this rate 13.4 is important?
Please review my paper Solar Group is one machine http://vixra.org/abs/1808.0081
Where I classified the solar planets data into 5 rates which are (1.392/1.9/3.66/13.4/179.56)
(A, A2
, A3
, A4
, A5
)
Which means, the masses are divided according to other data division rate…
Which proves that the mass isn't independent from the other planets data
To see the masses division more clear we need to discuss the solar planets masses
distribution, let's do it in following…..
MassSaturnkg10568
MassJupiterkg101898
24
24



MassSaturnkg10568
MassJupiterkg101898
24
24




I do this research
2nd
9
4- Solar Group Masses Distribution
I- Data
 Solar Planets Masses Total = 2666.7 x 1024
kg
 This masses total is divided into 2 parts with rate 1: (3.66)2
= 200 :2467
 2467 *1024
kg = Saturn Mass +Jupiter Mass
 The rest planets mass = 200 *1024
kg
 The rest planets mass = 200 *1024
kg is divided into 2 parts with rate 1: 1 (100 *1024
kg
Neptune Mass + 100 *1024
kg the rest planets masses total) (error 2%)
 100 *1024
kg (the rest planets masses) is divided into 88 100 *1024
kg Uranus Mass
+12*1024
kg the rest planetsa masses total (error 1.4%)
 12*1024
kg (The rest planets masses total) is divided into 2 parts with rate 1: 1 (6*1024
kg
Earth Mass) + 6*1024
kg (Total masses of Mercury + Venus+ Moon +Mars)
The rate 1:1
In Anderson experiment to produce electron and positron from Gamma rays (1.2 Mev) the
products were electron and positron whose masses are equal
i.e. The results rate was 1:1 …… So,
The value 200 is divided into 1:1 to produce Neptune Mass and the rest planets masses
(error 2%) …. Also
the value 12 is divided into 1: 1 to produce Earth mass and the 4 inner planets masses total
As we have discussed before, I noticed that Earth mass = 4 inner planet masses total and
suggested that Earth is the great electron and the 4 planets together are the great positron..
That means the rate 1:1 may produce electron and positron and that may be occurred also
with Neptune….
I want to say there's a resemblance in Mass distribution with Earth and Neptune… as we
have seen…
Let's see the following Equation
- Earth Circumference = 5 inner planets diameters total (with Earth) (no error)
- 2 x Neptune Circumference = 4 outer planets diameters total (without Neptune)
(error 1.8%)
I wish we see clearly the resemblances between Earth and Neptune in Mass and diameters..
This resemblance is found because
Earth Neptune distance x 2π2
= 86400 mkm (the soalr group main energy)..Iwish it's clear
that this data is produced based on a geometrical strcture which gurantees the motion
general harmony…
For more clear discussion please review
Solar Group Geometrical Structure

I do this research
2nd
10
More Relationships
1st-
MassMercury
MassVenus
MassEarth
MassUranus

2nd- 1
totalmassesplanetsrest
MassNeptune
TotalMassesPlanets4
MassEarth

3rd-
MassPluto
MassNeptune
MassMoon
MassSatrun
 (No Error)
4th-
MassMars
MassNeptune2
MassEarth
MassJupiter
 (No Error)
5th-
MassVenus
MassUranus
MassMercury
MassEarth
 (Error 1.5%)
6th-
MassMercury
MassSatrun
2
MassSatrun
MassSunThe
 (Error 1.6%)
7th-
MassMercury
MassNeptune
MassEarth
MassJupiter
 (Error 2.8%)
8th-
MassMoon
MassMars
TotalMassesPlanetsInner
MassNeptune
 (Error 2.4%)
9th-
MassMars
MassSatrun
MassPLuto
TotalMassesPlanetsInner
 (Error 2.4%)
10th-
MassPluto
MassMercury
MassNeptune
TotalMassesPlanetsOuter
 (Error 2.5%)
The Discussion
I try to prove clearly that, the planet mass isn't independent from other planets masses and
data…
In fact it's impossible to be independent from other planets data because the planets motions
general harmony is performed by general harmony of the solar planets data….
If this harmony isn't performed, there's no way to produce the solar planets motions general
harmony…

I do this research
2nd
11
5- The Energy E= 627 mkm
I- Data
9- E= 627 = 227.9 mkm x 2 x 1.3756 mkm (= 99% of the sun diameter 1.392 mkm)
10- Lunar umbra length = the sun diameter
Equation No.9
E= 627 mkm= 227.9 mkm x 2 x 1.3756 mkm (= 99% of the sun diameter 1.392 mkm)
Where
227.9 mkm = Mars orbital distance
1.392 mkm = the sun diameter
What does Equation No.9 tell us?
The sun diameter is created based on the distance 627 mkm (Earth Jupiter Distance) by
using Mars orbital distance 227.9 mkm… why?
I don't know…. But we know that Mars axial tilt 25.2 degrees is the constant in kepler 3rd
law table… let's remember it here again …
If we use Kepler 3rd
Law for the solar group data, we will find the following table
P2
* 25 = d3
(Kepler 3rd
Law)
- P : The Planet orbital period
- d : The Planet orbital distance
- 25.2 degrees : Mars Axial Tilt
The results are shown in the following table
Table No.1
Planet P2
* 25 = d3
Error
Mercury (88)2
*25 (57.9)3
0.2%
Venus (224.7)2
*25 (108.2)3
0.3%
Earth (366)2
*25 (149.6)3
0
Mars (687)2
*25 (227.9)3
0.3%
Jupiter (4331)2
*25 (778.6)3
1.4%
Saturn (10474)2
*25 (1433.5)3
1%
Uranus (30589)2
*25 (2872.5)3
1.3%
Neptune (59800)2
*25 (4495.1)3
1.5%
Pluto (90588)2
*25 (5870)3
1.4%
Comment:
The previous table I used many time in my papers, I have no explanation why Mars Axial
Tilt is the constant in Kepler 3rd
Law..
Some people told me I use wrong units to reach this result! I use million km for distance and
day for periods.. why these are wrong units?!
For Mars full discussion please read
Solar Planets Order disproves the Gravity Theory http://vixra.org/abs/1801.0114
Mars axial tilt is the constant in the table, and Mars data importance can be more clear by
revision of my paper
Kepler 3rd Law Explanation (a Claim Against Nobel Prize Board Decision in Physics 2018)

I do this research
2nd
12
Equation No. 10
Lunar umbra length = The Sun Diameter
Lunar umbra is found in the distance between Earth and Mars…
Let's summarize the whole idea in following
The distance 627 mkm (Earth Jupiter distance) is produced as Energy from many different
equations…
The sun diameter is created based on this distance 627 mkm
Earth, Mars, Jupiter and Uranus with the moon are the main players in the sun production
process
That's why each planet has specific relationship with the sun
 The sun diameter = Jupiter diameter xπ2
(error 1.4%)
 The sun circles Earth to complete the cycle in 365.25 days (Earth orbital period)
 63.7 degrees (sun declination) = 25.2 degrees Mars axial tilt x 2.5 degrees (Saturn orbital
inclination) (note Mars orbital circumference = Saturn orbital distance)
 Lunar Umbra length = The Sun diameter (the umbra locates between Mars and Earth)
Author Other Papers
Does The Moon move by Gravity?
Kepler 3rd Law Explanation (a Claim Against Nobel Prize Board Decision in Physics 2018)
Metonic and Saros Cycles Harmony Reason
The Solar Group Main Equation (Part 2)
The Solar Group Main Equation
The Solar Group Main Energy
Gerges Francis Tawdrous +201022532292
E-mail georgytawdrous@yandex.ru
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com/gergis.tawadrous
Academia https://rudn.academia.edu/GergesTawadrous
All papers https://www.slideshare.net/search/slideshow?searchfrom=header&q=gerges+francis+papers+

Definition of space

More Related Content

What's hot (20)

Similar to Definition of space (20)

More from Gerges francis (20)

Recently uploaded (20)

Definition of space