Shown in the diagram is a simple biochemical pathway. The substrates.pdf
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The document discusses a biochemical pathway involving an orange mutant and a purple mutant, each affecting one gene. When crossed, the offspring (F1) are heterozygous and exhibit a normal phenotype due to complementary gene interaction, leading to a 9:7 phenotypic ratio in a dihybrid cross. Subsequent crosses of these offspring will also exhibit expected ratios and phenotypes linked to the normal interaction of alleles.
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Shown in the diagram is a simple biochemical pathway. The substrates.pdf
- 1. Shown in the diagram is a simple biochemical pathway. The substrates and product are illustrated in the color they produce. We have a pure-breeding orange mutant and a pure-breeding purple mutant, each affected at one gene in the pathway above (all other genes being wildtype). If we cross the orange and the purple mutants, what would we see in the offspring? Indicate any ratios expected, phenotypes observed and any phenomena exhibited If we cross those offspring, what do we expect to observe? Indicate any ratios expected, phenotypes observed and any phenomena exhibited Enzyme catalysis Enzyme catalysis Enzyme catalysis Enzyme catalysis Enzyme catalysis Solution Explanation :-If we cross pure breeding orange mutant with pure breeding purple mutant the F1 would be normal that would be heterozygous for orange and purple alleles due to complementary gene interaction. F1=AaBBCcDDEE. The biochemical pathway woyld be normal because normal orange/purple allele of one would complment each other. Normally complementary ratio is 9:7 for dihybrid cross.