Surface areas and volumes ppt
- 3. First, what is surface area and volume?
- 4. The surface area of a solid object is the total area of the object's faces and curved surfaces.
- 5. Volume is the space that a substance or shape occupies or contains.
- 6. NOW LETS LOOK INTO SOME 3-D SHAPES AND THEIR SURFACE AREAS AND VOLUMES
- 7. A cube is a three dimensional figure, with six sides- all Sides in shape of Square. Length of side is denoted by the letter ‘l’’. l
- 8. Lateral surface area refers to the area of only the walls ( it does not include the area of the floor and roof). Formula :- 4 l² Derivation :- Since all the sides of cube are in the shape of square. area of the square= l² no. of sides=4 area = 4l²
- 9. 1. Find the lateral surface area of the cube with side of 15cm. Sol.- We are given- l = 15cm lateral surface area = 4l² = 4(15 cm)² = 4* 225cm² = 900cm²
- 10. Formula :- 6l² Derivation :- Since all the faces of a cube are squares , Area of square = l² No. of square = 6 Area of 6 square = Total surface area of cube = 6l² Therefore , total surface area of the cube is 6l² .
- 11. 1. Find the total surface area of the cube with side of 7.2cm. Sol. - We are given, l = 7.2cm Total surface area = 6l² = 6(7.2cm)² = 6*51.84 cm² = 311.04 cm²
- 12. Volume of the cube refers to the space inside the six walls. Formula :- l * l * l = l³ Unit :- unit³
- 13. 1. Three equal cubes are placed Side by side in a row. Find the volume of the new figure formed, Also find its ratio in respect to the single cube. Sol.- Let ‘a’ be the edge of each cube. Volume of the single cube = a³ Sum of the volume of three cubes = 3*a³ = 3a³ Ratio of the volume of two figures = Volume of the cube / Volume of the new figure = a³ / 3a³ = 1:3 a a a a
- 14. Cuboid is a three dimensional figure, with six sides and all sides of equal length. In Cuboid opposite rectangles are equal. It’s three dimensions are :- 1.Length(l) 2. Breadth (b) 3. Height (h) l b h
- 15. Lateral surface area of the cuboid refer to the area of the four walls of it. Formula :- 2(l+b) h Derivation :- Area of rectangle1 = l*h Area of rectangle2 = b*h Area of rectangle3 = l*h Area of rectangle 4 = b*h Total area =2lh+2bh = 2(l+b) h l b h
- 16. Formula :- 2(lb + bh + hl ) Derivation :- Area of rectangle 1 (= lh) + Area of rectangle 2 (=lb )+ Area of rectangle 3 (=lh ) + Area of rectangle 4 (=lb ) + Area of rectangle 5 (=bh ) + Area of rectangle 6 (= bh ) = 2(l*b ) + 2 ( b*h ) + 2 (l*h ) = 2 ( lb + bh + hl )
- 17. 1. A wall of length 10m was to be built across an open ground. the height of wall is 4m and thickness of the wall is 24cm. If this wall is to be built up with bricks whose dimensions are 24cm * 12cm * 8cm, how many bricks would be required ? Sol. – We are given, Length = 10m = 1000cm Breadth = 24cm Height = 4m = 400cm So, volume of wall = length * breadth * height= 1000* 24* 400cm³ Now, each brick is a cuboid with length=24cm, breadth=12cm, height= 8cm Volume of each brick = l*b*h = 24 *12 * 8 cm³ So, no. of brick require = volume of the wall/ Volume of each brick = 1000* 24 * 400/ 24 * 12 *8 = 4166.6 So, the wall requires 4167 bricks.
- 18. A right circular cylinder is a solid generated by the revolution of a rectangle about one of its side. It is a folded rectangle with both circular ends. h r
- 19. Curved surface area of the cylinder :- = Area of the rectangular sheet = length * breadth = perimeter of the base of the cylinder* h = 2πr * h = 2πrh
- 20. 1. Shubhi had to make a model of a cylindrical kaleidoscope for her project. She wanted to use chart paper to use chart paper to make the curved surface of it. What would be the area of chart paper required by her, if she wanted to make a kaleidoscope of length-25cm with a 3.5cm radius ? Sol. – Radius of the base of the cylindrical kaleidoscope (r) = 3.5cm Height (length) of kaleidoscope (h) = 25cm Area of paper required = curved surface area of kaleidoscope = 2πrh = 2*22/7*3.5*25 cm² = 550 cm²
- 21. Total surface area of a cylinder : = area of the rectangular sheet + 2 (area of the circular regions ) = perimeter of the base of cylinder* h + 2 (area of circular base ) = 2πrh + 2πr² = 2 πr ( r + h) h r
- 22. 1. A barrel is to be painted from inside and outside. It has no lid .The radius of its base and height is 1.5m and 2m respective. Find the expenditure of painting at the rate of Rs. 8 per square meter. Sol. – Given, r= 1.5m , h = 2m Base area of barrel = πr² Base area to be painted (inside and outside ) = 2 πr² =2 * 3.14 * (1.5 )² cm² = 2* 3.14 * 2.25 = 14.13cm² Curved surface area of barrel = 2 πrh Area to be painted = 2 * 2 πrh = 4 * 3.14 *1.5 *2 cm² = 12 * 3.14cm² = 37.68 cm² Total area to be painted = ( 37.68 + 14.13 ) cm² = 51.81 cm² Expenditure on painting = Rs. 8 * 51.81 = Rs. 414.48
- 23. Volume of a cylinder can be built up using circles Of same size. So, the volume of cylinder can be obtained as :- base area * height = area of circular base * height = πr²h r
- 24. 1. A measuring jar of one liter for measuring milk is of right circular cylinder shape. If the radius of the base is 5cm , find the height of the jar. Sol. – Radius of the cylindrical jar = 5cm Let ‘h’ be its height Volume = πr²h Volume = 1 liter = 1000cm³ Πr²h = 1000 H = 1000/πr² H = 1000 *7 / 22*5*5 cm = 1000*7 / 22*25 cm = 140 / 11 cm = 12.73 cm Height of the jar is 12.73 cm .
- 25. If a right angled triangle is revolved about one of its sides containing a right angle, the solid Thus formed is called a right circular cone. The point V is the vertex of cone. The length OV=h, height of the cone The base of a cone is a circle with O as center and OA as radius. The length VA = l , is the slant height of the cone. V l h O r A
- 26. It is the area of the curved part of the cone. (Excluding the circular base ) Formula :- 1/2* perimeter of the base* slant height = ½ * 2πr * l = πr l l r
- 27. 2.How many meters of cloth 5m wide will be required to make a conical tent , the radius of whose base is 7m and whose height is 24m ? Sol. – Radius of base = 7m Vertical height , ‘h’ = 24m Slant height ‘l’ = √ h² + r² = √(24)² + (7)² =√576 + 49 = √625 = 25 m Curved surface area = πrl = 22/7 *7*25 m² = 550 m² Width of cloth = 5m Length required to make conical tent = 550/5 m = 110m
- 28. Total surface area of the cone :- =Curved surface area of cone + circular base ( Red coloured area + green coloured area ) =πrl + πr² =πr ( l + r ) hh h l r
- 29. 1. Total surface area of a cone is 770cm². If the slant height of cone is 4 times the radius of its base , then find the diameters of the base. Sol. – Total surface area of cone = 770 cm² = πr (r + l ) = 770 = l = 4 * radius = 4r = πr (r + 4r ) = 770 = 5πr ² = 770 = r² = 770 *7 / 5 *22 = 7 * 7 = r = 7cm Therefore, diameter of the base of the cone is 14cm.
- 30. Formula :- 1/3 πr²h Derivation :- If a cylinder and cone of sane base Radius and height are taken , and if cone is put Under the cylinder then it will occupy only One –third part of it . Therefore, volume of cone is 1/3 of the volume of Cylinder. = 1/3πr²h hh 1 2 3 h l rr
- 31. The set of all points in space equidistant from a fixed point, is called a sphere . The fixed point is called the center of the sphere. A line segment passing through the center of the sphere with its end points on the sphere is called a diameter of the sphere. r
- 32. Surface area of the sphere :- =4πr² r
- 33. Volume of the sphere :- =4/3πR³
- 34. 1. How many spherical bullets can be made out of lead whose edge measures 44cm, each bullet being 4cm in diameter. Sol. – Let the total no. of bullets be x Radius of spherical bullet = 4/2 cm = 2cm Volume of a spherical bullet = 4/3 π * (2)³ cm³ =(4/3 *22/7 *8 ) cm³ Volume of solid cube = (44)³ cm³ Number of spherical bullets recast = volume of cube = 44*44*44*3*7 volume of one bullet 4 *22*8 = 33*77 = 2541
- 35. A plane passing through the centre of a sphere divides the sphere into two equal parts . Each part is known as hemisphere. r
- 36. Formula : - 2πr² Derivation :- Since, hemisphere is half of sphere- Therefore, Surface area of sphere = 4πr² Half of it = 2πr² r
- 37. Total surface area of hemisphere: = Curved surface area + circular base = 2πr² + πr² = 3πr²
- 38. VOLUME OF HEMISPHERE: Volume of hemisphere = 1/2 * volume of sphere = 1/2 * 4/3*Пr³ =2/3 πr³
- 39. THANK YOU