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By: Lawrence P. Avillano, LPT
A z-score (aka, a standard score)
indicates how many Standard Deviation
an element or a score is from the mean
is from the mean. A z-score can be
calculated from the following formula
• It can be found using the formula z = (x – μ) / σ, : read z is
equal to the quotient between the difference of the raw
score and mean and the standard deviation.
Where:
• z - is the z - score
• x - is the raw score
• μ - is the (population) mean, but u can use x bar too
• .σ - is the standard deviation
• A z-score less than zero (0) represents an element
less than the mean.
• A z-score greater than 0 represents an element
greater than the mean.
• A z-score equal to 0 represents an element equal to
the mean.
• A z-score equal to 1 represents an element that is 1 standard
deviation greater than the mean; a z-score equal to 2, 2
standard deviations greater than the mean; etc.
• A z-score equal to -1 represents an element that is 1 standard
deviation less than the mean; a z-score equal to -2, 2 standard
deviations less than the mean; etc.
• If the number of elements in the set is large, about 68% of the
elements have a z-score between -1 and 1; about 95% have a z-
score between -2 and 2; and about 99% have a z-score between
-3 and 3.
In a 20 item test, the average score of the class is 16 and with 3.5
SD. Cherrie Pie scored 18.
z = (x – μ) / σ
z = (18– 16) /3.5
z = 2/3.5z = 0.57
That means that Cherrie Pie`s score is 0.57 (less than 1) standard
deviations above the mean.
Other than said above, we can use Cherri Pies`s z-score of .57 to
see how well she performed compared to other students or look at
her class standing.
• We may have to look through the z-table which can be found
here http://www.statisticshowto.com/tables/z-table/
• Now take 0.57
• y - is 0.5
• x - is 0.07
We would get the z-value of 0.2157
Understanding the Z- score (Application on evaluating a Learner`s performance)
• Multiply the z-value by 100: 0.2157*100 = 21.57
• It means that 21.57% of the class performed better than Cherrie
Pie
• Substract 21.57 from 100: 100-21.57 = 78.43
• It means that Cherrie Pie performed better than 78.43% of the
test class.
• That would help the teacher on making decisions with regards to
Cherri Pie`s performance.

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Understanding the Z- score (Application on evaluating a Learner`s performance)

  • 1. By: Lawrence P. Avillano, LPT
  • 2. A z-score (aka, a standard score) indicates how many Standard Deviation an element or a score is from the mean is from the mean. A z-score can be calculated from the following formula
  • 3. • It can be found using the formula z = (x – μ) / σ, : read z is equal to the quotient between the difference of the raw score and mean and the standard deviation. Where: • z - is the z - score • x - is the raw score • μ - is the (population) mean, but u can use x bar too • .σ - is the standard deviation
  • 4. • A z-score less than zero (0) represents an element less than the mean. • A z-score greater than 0 represents an element greater than the mean. • A z-score equal to 0 represents an element equal to the mean.
  • 5. • A z-score equal to 1 represents an element that is 1 standard deviation greater than the mean; a z-score equal to 2, 2 standard deviations greater than the mean; etc. • A z-score equal to -1 represents an element that is 1 standard deviation less than the mean; a z-score equal to -2, 2 standard deviations less than the mean; etc. • If the number of elements in the set is large, about 68% of the elements have a z-score between -1 and 1; about 95% have a z- score between -2 and 2; and about 99% have a z-score between -3 and 3.
  • 6. In a 20 item test, the average score of the class is 16 and with 3.5 SD. Cherrie Pie scored 18. z = (x – μ) / σ z = (18– 16) /3.5 z = 2/3.5z = 0.57 That means that Cherrie Pie`s score is 0.57 (less than 1) standard deviations above the mean.
  • 7. Other than said above, we can use Cherri Pies`s z-score of .57 to see how well she performed compared to other students or look at her class standing. • We may have to look through the z-table which can be found here http://www.statisticshowto.com/tables/z-table/ • Now take 0.57 • y - is 0.5 • x - is 0.07 We would get the z-value of 0.2157
  • 9. • Multiply the z-value by 100: 0.2157*100 = 21.57 • It means that 21.57% of the class performed better than Cherrie Pie • Substract 21.57 from 100: 100-21.57 = 78.43 • It means that Cherrie Pie performed better than 78.43% of the test class. • That would help the teacher on making decisions with regards to Cherri Pie`s performance.