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UNSTEADY FLOWING ORIFICE (Physical Application) Differential Equations Group 6 Presentation By: Genesis Bernaldez Marfel Obciana Teto Estelito
(a) In  hydraulics , it has been shown that the discharge  Q  or rate of change of the volume   of a liquid through a small opening  or  orifice  located in a tank and under a head  h  is given by the formula,
Where:  C   – is the dimensionless constant known  as the      “ coefficient of discharge ” (C ≈ 0.60)   Ao  – is the area of the orifice  Q   –  is the discharge or flow  h   – is the  head  of liquid or the vertical distance from the orifice to    the liquid surface (m)   d(Vol)  – is the elemental volume taken at a distance of  h  above he    orifice    g   – is the acceleration of gravity
(b) If the outflow or discharge through the orifice is replaced by an equivalent inflow into the tank, the flow condition is said to be “ steady ”. However, if there is no inflow, the liquid surface drops and the flow through the orifice varies since  Q  = f(h). This flow condition is known as “ unsteady ”. The problem here is the determination of the time for the liquid surface to drop from one elevation to another elevation. See the Figure on the next slide.
 
(c) Writethe EQ from (a) in the form where the (-) sign implies that the volume    of the liquid in the tank decreases    with the time, t.
Integration from  to  gives where d(Vol) = A dh and A = f(h).
Finally, after an interchange of the limits, we get REMARK : It is also possible to attain unsteady  flow conditions if at time, t=0, there  is a constant inflow, Q 1  ≠ Qo. This  case, however, will not be treated  here.
EXAMPLE PROBLEM 1 A cylindrical tank 1.5m in diameter and 3m high stands with its axis vertical. The tank is full of water and has a 10cm diameter orifice (C = 0.60) located at the bottom. Determine the time required to empty the tank of its contents through the orifice.
 
NOTE:  In this problem the sectional area  A  of the tank at any elevation the water surface is constant. SOLUTION:
EXAMPLE PROBLEM 2 A tank is in the shape of a frustum of a pyramid having a square section. The upper base is 3m x 3m, and the lower base is 1.5m x 1.5m with a height of 3m. Determine the time required to lower down the water surface 2m through a 10cm by 10cm square orifice located at the bottom. Assume the tank to be initially full of water and use C = 0.60.
 
 
(b) Use EQ from (a), that is,

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Unsteady Flowing Orifice

  • 1. UNSTEADY FLOWING ORIFICE (Physical Application) Differential Equations Group 6 Presentation By: Genesis Bernaldez Marfel Obciana Teto Estelito
  • 2. (a) In hydraulics , it has been shown that the discharge Q or rate of change of the volume of a liquid through a small opening or orifice located in a tank and under a head h is given by the formula,
  • 3. Where: C – is the dimensionless constant known as the “ coefficient of discharge ” (C ≈ 0.60) Ao – is the area of the orifice Q – is the discharge or flow h – is the head of liquid or the vertical distance from the orifice to the liquid surface (m) d(Vol) – is the elemental volume taken at a distance of h above he orifice g – is the acceleration of gravity
  • 4. (b) If the outflow or discharge through the orifice is replaced by an equivalent inflow into the tank, the flow condition is said to be “ steady ”. However, if there is no inflow, the liquid surface drops and the flow through the orifice varies since Q = f(h). This flow condition is known as “ unsteady ”. The problem here is the determination of the time for the liquid surface to drop from one elevation to another elevation. See the Figure on the next slide.
  • 5.  
  • 6. (c) Writethe EQ from (a) in the form where the (-) sign implies that the volume of the liquid in the tank decreases with the time, t.
  • 7. Integration from to gives where d(Vol) = A dh and A = f(h).
  • 8. Finally, after an interchange of the limits, we get REMARK : It is also possible to attain unsteady flow conditions if at time, t=0, there is a constant inflow, Q 1 ≠ Qo. This case, however, will not be treated here.
  • 9. EXAMPLE PROBLEM 1 A cylindrical tank 1.5m in diameter and 3m high stands with its axis vertical. The tank is full of water and has a 10cm diameter orifice (C = 0.60) located at the bottom. Determine the time required to empty the tank of its contents through the orifice.
  • 10.  
  • 11. NOTE: In this problem the sectional area A of the tank at any elevation the water surface is constant. SOLUTION:
  • 12. EXAMPLE PROBLEM 2 A tank is in the shape of a frustum of a pyramid having a square section. The upper base is 3m x 3m, and the lower base is 1.5m x 1.5m with a height of 3m. Determine the time required to lower down the water surface 2m through a 10cm by 10cm square orifice located at the bottom. Assume the tank to be initially full of water and use C = 0.60.
  • 13.  
  • 14.  
  • 15. (b) Use EQ from (a), that is,