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What is the runtime complexity of Adam's famous string splitter code? Hint: Make sure to look
into the source code for string.find() in the C++ std library. I’ve included that code (downloaded
from GNU). static vector ring text string delimiter vector ring pieces int location text, (delimiter);
inte start 0; //while we find something interesting while location string DRos)f build substring
string piece text substr (start location start); (piece start location 1 //find again location ext find
deli miter start); string piece text substr (start location start); pieseswRush bask (piece return
pieces;
Solution
Assumption is we have text length as N and we have N-1 delimeters in that text.
text.find() -->Takes O(n) time in the worst case to find the delimeter.
vectorpieces; -->O(1)
int location = text.find();delimeter-->At max O(n)
while(location!=string.pos()){ . -> Runs N times
string piece = text.substr(start,location-start); -->At max takes O(N) [Copying that many
characters]*N times for while loop
start = location+1; -->O(1)
location = text.find(delimeter,start);-->At Max O(N) * N times for while loop
So While loop will run N time as we have N-1 delmieters and each time finding substr() and
find() on an average will take O(n). So overall time complexity is O(N2)
}
Thanks, let me know if there is any concern.

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What is the runtime complexity of Adams famous string splitter cod.pdf

  • 1. What is the runtime complexity of Adam's famous string splitter code? Hint: Make sure to look into the source code for string.find() in the C++ std library. I’ve included that code (downloaded from GNU). static vector ring text string delimiter vector ring pieces int location text, (delimiter); inte start 0; //while we find something interesting while location string DRos)f build substring string piece text substr (start location start); (piece start location 1 //find again location ext find deli miter start); string piece text substr (start location start); pieseswRush bask (piece return pieces; Solution Assumption is we have text length as N and we have N-1 delimeters in that text. text.find() -->Takes O(n) time in the worst case to find the delimeter. vectorpieces; -->O(1) int location = text.find();delimeter-->At max O(n) while(location!=string.pos()){ . -> Runs N times string piece = text.substr(start,location-start); -->At max takes O(N) [Copying that many characters]*N times for while loop start = location+1; -->O(1) location = text.find(delimeter,start);-->At Max O(N) * N times for while loop So While loop will run N time as we have N-1 delmieters and each time finding substr() and find() on an average will take O(n). So overall time complexity is O(N2) } Thanks, let me know if there is any concern.