![15
Derivative as Velocity
compute the average velocities over shorter and shorter
time intervals [a, a + h].
instantaneous velocity = derivative of position](https://image.slidesharecdn.com/lecture7-derivatives-140922120616-phpapp01/85/Lecture-7-Derivatives-15-320.jpg)
Lecture 7 Derivatives
- 1. Derivatives 2.6 and Rates of Change
- 2. 2 Average Rate of Change Function notation
- 3. 3 Derivatives - Definition
- 4. 4 Derivative – Slope of Tan Line Tangent line is the limiting position of the secant line PQ as Q approaches P.
- 5. 5 Tangents slope of the secant line PQ: Then we let Q approach P along the curve C by letting x approach a.
- 6. 6 Slope of Tangents
- 7. Tangents If h = x – a, then x = a + h and so the slope of the secant line PQ is 7 Figure 3
- 8. 8 Tangents as x a, h 0 (because h = x – a)
- 9. Example 1 – Finding an Equation of a Tangent Find an equation of the tangent line to the parabola y = x2 at the point P(1, 1). Solution: 9
- 10. 10 Example 1 – Solution Using the point-slope form of the equation of a line, we find that an equation of the tangent line at (1, 1) is cont’d
- 11. 11 Derivative – Slope of Curve We sometimes refer to the slope of the tangent line to a curve at a point as the slope of the curve at the point. The idea is that if we zoom in far enough toward the point, the curve looks almost like a straight line. Figure 2 illustrates this procedure for the curve y = x2 in Example 1. Zooming in toward the point Figure 2 (1, 1) on the parabola y = x2
- 12. 12 Slope of a Curve - Example
- 13. 13 Velocities
- 14. 14 Velocities The average velocity over this time interval is which is the same as the slope of the secant line PQ in Figure 6. Figure 6
- 15. 15 Derivative as Velocity compute the average velocities over shorter and shorter time intervals [a, a + h]. instantaneous velocity = derivative of position
- 16. Example 3 – Velocity of a Falling Ball Suppose that a ball is dropped from the upper observation deck of the CN Tower, 450 m above the ground, using the equation of motion s = f (t) = 4.9t 16 2 What is the velocity of the ball after 5 seconds? Solution:
- 17. 17 Speed The speed of the particle is the absolute value of the velocity, that is, | f ¢(a) |.
- 18. 18 Speed - Example
- 19. Derivative as Instantaneous Rate of Change 19
- 20. Rates of Change This means that when the derivative is large (and therefore the curve is steep, as at the point P in Figure 9), the y-values change rapidly. When the derivative is small, the curve is relatively flat (as at point Q) and the y-values change slowly. 20 Figure 9 The y-values are changing rapidly at P and slowly at Q.
- 21. Example 6 – Derivative of a Cost Function A manufacturer produces bolts of a fabric with a fixed width. The cost of producing x yards of this fabric is C = f (x) dollars. (a) What is the meaning of the derivative f ¢(x)? What are its 21 units? (b) In practical terms, what does it mean to say that f ¢(1000) = 9? (c) Which do you think is greater, f ¢(50) or f ¢(500)? What about f ¢(5000)?
- 22. 22 Example 6(a) – Solution The derivative f ¢(x) is the instantaneous rate of change of C with respect to x; that is, f ¢(x) means the rate of change of the production cost with respect to the number of yards produced. Because the units for f ¢(x) are the same as the units for the difference quotient DC/Dx. Since DC is measured in dollars and Dx in yards, it follows that the units for f ¢(x) are dollars per yard.
- 23. Example 6(b) – Solution The statement that f ¢(1000) = 9 means that, after 1000 yards of fabric have been manufactured, the rate at which the production cost is increasing is $9/yard. (When x = 1000, C is increasing 9 times as fast as x.) cont’d Since Dx = 1 is small compared with x = 1000, we could use the approximation 23 and say that the cost of manufacturing the 1000th yard (or the 1001st) is about $9.
- 24. 24 Example 6(c) – Solution The rate at which the production cost is increasing (per yard) is probably lower when x = 500 than when x = 50 (the cost of making the 500th yard is less than the cost of the 50th yard) because of economies of scale. (The manufacturer makes more efficient use of the fixed costs of production.) So f ¢(50) > f ¢(500) cont’d
- 25. 25 Example 6(c) – Solution But, as production expands, the resulting large-scale operation might become inefficient and there might be overtime costs. Thus it is possible that the rate of increase of costs will eventually start to rise. So it may happen that f ¢(5000) > f ¢(500) cont’d