Traffic light setting

Intelligent Urban Traffic Control System
(KKKA 6424)

Assignment no .1
Traffic Light Setting

Supervisor
Prof. Dr. Riza Atiq Abdullah OK Rehmat

Prepared by: Rasha salah ahmed P64799
Sarah hazim P65407

Fig (1) (The Study area)
Location of intersections

First Intersection

Phase Traffic volume Actual saturation saturation Y= Green (Y / ∑y)
left straight right flow flow per flow flow/sat time split *Ge
(pcu/hr) lane (pcu/hr) uration
(pcu/hr) flow Y / ∑y
1 111 88 199 1800 3600 0.1 0.33 8
2 95 201 296 1800 3600 0.1 0.33 8
3 85 100 185 1800 3600 0.1 0.33 8

∑y=0.3 ∑=24

1. L (lost time) =3× (3+2) =15 sec
(1.5 𝐿 +5 1.5 15 +5
2. Co= = = 39.28 take Co=40 sec
1−∑𝑌 1−0.3
3. Effective green time (Ge) =Co-L =40-15=25 sec

(Multiply this value in green time split to get the final column).

4. Total green time=24sec
5. Cycle time =green time + lost time
=24+15=39sec

Second intersection

Phase Traffic volume Actual saturation saturation Y= Green (Y / ∑y)
left straight right flow flow per flow flow/sat time split *Ge
(pcu/hr) lane (pcu/hr) uration
(pcu/hr) flow Y / ∑y
1 80 328 184 592 1800 3600 0.16 0.31 16
2 84 140 98 322 1800 3600 0.1 0.19 10
3 148 252 160 560 1800 3600 0.16 0.31 16
4 64 92 120 276 1800 3600 0.1 0.19 10
∑y=0.52 ∑=52

1. L (lost time) =4× (3+2) =20 sec
(1.5 𝐿 +5 1.5 20 +5
2. Co= = =72.9 take Co=73 sec
1−∑𝑌 1−0.52



4. Total green time=52 sec
5. Cycle time =green time + lost time
=52+20=72 sec

Third intersection

Phase Traffic volume Actual saturation saturation Y= Green (Y /
left straight right flow flow per flow flow/sat time ∑y)
(pcu/hr) lane (pcu/hr) uration split *Ge
(pcu/hr) flow
Y / ∑y
1 151 215 99 465 1800 3600 0.13 0.217 15
2 90 198 75 363 1800 3600 0.1 0.167 11
3 88 119 90 297 1800 3600 0.1 0.167 11
4 356 501 113 970 1800 3600 0.27 0.45 31
∑y=0.6 ∑=68

1. L (lost time) =4× (3+2) =20 sec
(1.5 𝐿 +5 1.5 20 +5
2. Co= = =87.5 take Co=88 sec
1−∑𝑌 1−0.6



4. Total green time=68 sec
5.
Cycle time =green time + lost time
=68+20=88 sec.
 To determine (offset time) T ideal from inter1 to 2:
𝐿
T ideal= − 𝑄 × ℎ + 𝑙𝑜𝑠𝑠 𝑡𝑖𝑚𝑒 Where:
𝑆

L=450m

S=10m/sec

Q=14 cars
h=2sec
Loss time=2 sec. T ideal=15 sec.
 To determine (offset time) T ideal from inter 2 to 3:

L=650m

S=10m/sec

Q=12 cars

h=2 sec

Loss time=2 sec T ideal=39 sec

We choose the maximum value of C₀ = 88 and make recalculation for the green time, and
the new results in the table below:

Co=88 Ge=Co-L=88-20=68 sec

phase Intersection 1 Intersection 2 Intersection 3
Green Time = (Y/∑ Green Time = (Y/∑ Green Time = (Y/∑
Y)*Ge Y)*Ge Y)*Ge
Q1 23 21 15
Q2 23 13 11
Q3 22 21 11
Q4 13 31
∑=68 ∑=68 ∑=68
So the new diagram will be like the following:

Traffic light setting

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