Chapter 8: Functions of several variables
Nguyen Thu Huong
Faculty of Mathematics and Informatics
Hanoi University of Science and Technology
December 15, 2024
Functions of several variables
Content
8. Functions of several variables
8.4 Higher order partial derivatives
8.5 Tangent planes and approximations
8.6 Total differentials
Content
8. Functions of several variables
8.4 Higher order partial derivatives
8.5 Tangent planes and approximations
8.6 Total differentials
Functions of several variables
Definition
Second order partial derivatives of f (x, y) are:
f 00
xx =
∂2f
∂x2
=
∂
∂x
∂f
∂x

f 00
yy =
∂2f
∂y2
=
∂
∂y
∂f
∂y

f 00
xy =
∂2f
∂y∂x
=
∂
∂y
∂f
∂x

f 00
yx =
∂2f
∂x∂y
=
∂
∂x
∂f
∂y

.
Functions of several variables
Example
1 Compute all the second order partial derivatives of the
function z = arctan(x2y).
2 Given z = y cos
y
x
. Compute z00
xy and z00
yx .
3 Given the function f (x, y) =



xy
x2 − y2
x2 + y2
if (x, y) 6= (0, 0),
0 if (x, y) = (0, 0).
Compute f 00
xy (0, 0) and f 00
yx (0, 0).
Functions of several variables
Schwarz theorem
Theorem
Assume that z = f (x, y) has partial derivatives f 00
xy và f 00
yx near
M0(x0, y0) which are continuous at M0. Then,
f 00
xy (M0) = f 00
yx (M0).
Question: higher derivatives of functions of two variables? Schwarz
theorem? higher derivatives of functions of three or more variables?
Content
8. Functions of several variables
8.4 Higher order partial derivatives
8.5 Tangent planes and approximations
8.6 Total differentials
Functions of several variables
Consider a surface S : z = f (x, y), where f has continuous first
partial derivatives. P(x0, y0, z0) ∈ S.
Let C1, C2 be two curves obtained by intersecting the planes y = y0
and x = x0 with S at P. Let T1 and T2 be the tangent lines to C1
and C2 at P. The plane contains T1 and T2 is called the tangent
plane to the surface S at P.
Functions of several variables
C1 :
(
y = y0
z = f (x, y0)
⇒ T1 :
(
y = y0
z − z0 = f 0
x (x0, y0)(x − x0).
A directional vector of the tangent plane −
→
u1 = (1; 0; f 0
x (P)).
Similarly, −
→
u2 = (0; 1; f 0
y (P)). Hence, a normal vector is
−
→
n = −
→
u1 × −
→
u2 = (−f 0
x (P); −f 0
y (P); 1).
Functions of several variables
Tangent plane equation
An equation of the tangent plane to the surface S : z = f (x, y) at
the point P(x0, y0, z0) is
z − z0 = f 0
x (P)(x − x0) + f 0
y (P)(y − y0)
Example
Write an equation of the tangent plane at M(1; 1, ; 3) of the
surface z = x2y + 2xy2.
Functions of several variables
Linear approximation
Suppose that the first order partial derivative of f are continuous.
Then for (x, y) close to (x0, y0), we have the linear approximation
f (x, y) ≈ f (x0, y0) + f 0
x (x0, y0)(x − x0) + f 0
y (x0, y0)(y − y0).
Example
f (x, y) = x3 − 2xy2. Approximate f (2.01; 1.98).
Example
Approximate A = 3
p
1, 022 + 1, 983 − 1;
B = ln( 3
√
1, 02 + 4
√
0, 98 − 1).
Content
8. Functions of several variables
8.4 Higher order partial derivatives
8.5 Tangent planes and approximations
8.6 Total differentials
Functions of several variables
Total differentials
Definition
Given f (x, y): D ⊂ R2 → R, M0(x0, y0) ∈ D.If we can express
∆f = f (x0+∆x, y0+∆y)−f (x0, y0) = A∆x+B∆y+ε1∆x+ε2∆y,
where the constants A, B depend only on x0, y0, and
ε1 → 0, ε2 → 0 as ∆x, ∆y → 0, we say that f (x, y) is
differentiable at M0.
df (x0, y0) = A∆x + B∆y: the total diffenrential of f at M0.
f is said to be differentiable on D if f is differentiable at all
M0 ∈ D.
Example
Is the function z = 2x − y2 differentiable at (1, 0)?
Functions of several variables
Properties
If f is differentiable at M0 then f is continuous at M0.
Indeed, let ∆x, ∆y → 0, then
∆f = A∆x + B∆y + ε1∆x + ε2∆y → 0.
∆y = 0,
f (x0 + ∆x, y0) − f (x0, y0)
∆x
= A + ε1.
Passing to the limit as ∆x → 0: A = f 0
x (x0, y0).
Similarly, B = f 0
y (x0, y0). df = f 0
x ∆x + f 0
y ∆y.
If f is differentiable at M0 then f has partial derivatives at
M0. However, the converse is not necessary true.
Take f (x, y) = x, then df = ∆x = dx.
Similarly, ∆y = dy, df = f 0
x dx + f 0
y dy
Functions of several variables
Example
Is f (x, y) =



xy
x2 + y2
if (x, y) 6= (0, 0),
0 if (x, y) = (0, 0),
differentiable at (0, 0)?
f is not differentiable at (0, 0) although f 0
x (0, 0) = f 0
y (0, 0) = 0.
Functions of several variables
Theorem (Sufficient condition for differentiability)
If f 0
x (x, y), f 0
y (x, y) exist in B(M0, ε) and are continuous at M0.
Then, f (x, y) is differentiable at M0 and
df (M0) = f 0
x (M0)dx + f 0
y (M0)dy.
Functions of several variables
Example
Compute the total differential of the following functions
a) z =
1
2
(x2
+ y2
) b) z = xy
c) z = arctan xy d) u =
z
p
x2 + y2
, du(1, 2, 3).
Recall: linear approximation
∆f = f (x0+∆x, y0+∆y)−f (x0, y0) ≈ f 0
x (x0, y0)∆x + f 0
y (x0, y0)∆y
| {z }
df (x0,y0)
Homework: Textbook page 116: Ex. 3c, 4, 5,7.

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13.Partial_derivative_total_differential.pdf

  • 1. Chapter 8: Functions of several variables Nguyen Thu Huong Faculty of Mathematics and Informatics Hanoi University of Science and Technology December 15, 2024
  • 2. Functions of several variables Content 8. Functions of several variables 8.4 Higher order partial derivatives 8.5 Tangent planes and approximations 8.6 Total differentials
  • 3. Content 8. Functions of several variables 8.4 Higher order partial derivatives 8.5 Tangent planes and approximations 8.6 Total differentials
  • 4. Functions of several variables Definition Second order partial derivatives of f (x, y) are: f 00 xx = ∂2f ∂x2 = ∂ ∂x ∂f ∂x f 00 yy = ∂2f ∂y2 = ∂ ∂y ∂f ∂y f 00 xy = ∂2f ∂y∂x = ∂ ∂y ∂f ∂x f 00 yx = ∂2f ∂x∂y = ∂ ∂x ∂f ∂y .
  • 5. Functions of several variables Example 1 Compute all the second order partial derivatives of the function z = arctan(x2y). 2 Given z = y cos y x . Compute z00 xy and z00 yx . 3 Given the function f (x, y) =    xy x2 − y2 x2 + y2 if (x, y) 6= (0, 0), 0 if (x, y) = (0, 0). Compute f 00 xy (0, 0) and f 00 yx (0, 0).
  • 6. Functions of several variables Schwarz theorem Theorem Assume that z = f (x, y) has partial derivatives f 00 xy và f 00 yx near M0(x0, y0) which are continuous at M0. Then, f 00 xy (M0) = f 00 yx (M0). Question: higher derivatives of functions of two variables? Schwarz theorem? higher derivatives of functions of three or more variables?
  • 7. Content 8. Functions of several variables 8.4 Higher order partial derivatives 8.5 Tangent planes and approximations 8.6 Total differentials
  • 8. Functions of several variables Consider a surface S : z = f (x, y), where f has continuous first partial derivatives. P(x0, y0, z0) ∈ S. Let C1, C2 be two curves obtained by intersecting the planes y = y0 and x = x0 with S at P. Let T1 and T2 be the tangent lines to C1 and C2 at P. The plane contains T1 and T2 is called the tangent plane to the surface S at P.
  • 9. Functions of several variables C1 : ( y = y0 z = f (x, y0) ⇒ T1 : ( y = y0 z − z0 = f 0 x (x0, y0)(x − x0). A directional vector of the tangent plane − → u1 = (1; 0; f 0 x (P)). Similarly, − → u2 = (0; 1; f 0 y (P)). Hence, a normal vector is − → n = − → u1 × − → u2 = (−f 0 x (P); −f 0 y (P); 1).
  • 10. Functions of several variables Tangent plane equation An equation of the tangent plane to the surface S : z = f (x, y) at the point P(x0, y0, z0) is z − z0 = f 0 x (P)(x − x0) + f 0 y (P)(y − y0) Example Write an equation of the tangent plane at M(1; 1, ; 3) of the surface z = x2y + 2xy2.
  • 11. Functions of several variables Linear approximation Suppose that the first order partial derivative of f are continuous. Then for (x, y) close to (x0, y0), we have the linear approximation f (x, y) ≈ f (x0, y0) + f 0 x (x0, y0)(x − x0) + f 0 y (x0, y0)(y − y0). Example f (x, y) = x3 − 2xy2. Approximate f (2.01; 1.98). Example Approximate A = 3 p 1, 022 + 1, 983 − 1; B = ln( 3 √ 1, 02 + 4 √ 0, 98 − 1).
  • 12. Content 8. Functions of several variables 8.4 Higher order partial derivatives 8.5 Tangent planes and approximations 8.6 Total differentials
  • 13. Functions of several variables Total differentials Definition Given f (x, y): D ⊂ R2 → R, M0(x0, y0) ∈ D.If we can express ∆f = f (x0+∆x, y0+∆y)−f (x0, y0) = A∆x+B∆y+ε1∆x+ε2∆y, where the constants A, B depend only on x0, y0, and ε1 → 0, ε2 → 0 as ∆x, ∆y → 0, we say that f (x, y) is differentiable at M0. df (x0, y0) = A∆x + B∆y: the total diffenrential of f at M0. f is said to be differentiable on D if f is differentiable at all M0 ∈ D. Example Is the function z = 2x − y2 differentiable at (1, 0)?
  • 14. Functions of several variables Properties If f is differentiable at M0 then f is continuous at M0. Indeed, let ∆x, ∆y → 0, then ∆f = A∆x + B∆y + ε1∆x + ε2∆y → 0. ∆y = 0, f (x0 + ∆x, y0) − f (x0, y0) ∆x = A + ε1. Passing to the limit as ∆x → 0: A = f 0 x (x0, y0). Similarly, B = f 0 y (x0, y0). df = f 0 x ∆x + f 0 y ∆y. If f is differentiable at M0 then f has partial derivatives at M0. However, the converse is not necessary true. Take f (x, y) = x, then df = ∆x = dx. Similarly, ∆y = dy, df = f 0 x dx + f 0 y dy
  • 15. Functions of several variables Example Is f (x, y) =    xy x2 + y2 if (x, y) 6= (0, 0), 0 if (x, y) = (0, 0), differentiable at (0, 0)? f is not differentiable at (0, 0) although f 0 x (0, 0) = f 0 y (0, 0) = 0.
  • 16. Functions of several variables Theorem (Sufficient condition for differentiability) If f 0 x (x, y), f 0 y (x, y) exist in B(M0, ε) and are continuous at M0. Then, f (x, y) is differentiable at M0 and df (M0) = f 0 x (M0)dx + f 0 y (M0)dy.
  • 17. Functions of several variables Example Compute the total differential of the following functions a) z = 1 2 (x2 + y2 ) b) z = xy c) z = arctan xy d) u = z p x2 + y2 , du(1, 2, 3). Recall: linear approximation ∆f = f (x0+∆x, y0+∆y)−f (x0, y0) ≈ f 0 x (x0, y0)∆x + f 0 y (x0, y0)∆y | {z } df (x0,y0) Homework: Textbook page 116: Ex. 3c, 4, 5,7.