6.5.2 Example
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The document describes how to calculate the total current (Itotal) as the phasor sum of three currents (I1, I2, I3). It shows that I1 is 4A in phase with the voltage source. I2 is calculated to be 6.15A lagging the voltage by 75 degrees, by determining the impedance ZL of a circuit involving a resistor RL and inductor XL in series.
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6.5.2 Example
- 2. The total current Itotal is the phasor sum of I1, I2, and I3.
- 3. V I1 = R 240 I1 = =4A 60
- 4. Φ1 = 0⁰
- 5. V I2 = ZL
- 6. ZL = √RL² + XL²
- 7. RL = 2 π f L RL = 2 x π x 50 x 0.12 =37.699 (37.7) Ω RL = 37.7 Ω
- 8. ZL = √RL² + XL² ZL = √10² + 37.7² ZL = √100 + 1420 = 39 Ω ZL = 39 Ω
- 9. V I2 = ZL 240 I2 = = 6.15 A 39 I2 = 6.15 A
- 10. RL Cos Φ2 = ZL 10 Cos Φ2 = = 0.256 39 Φ2 = 75⁰ (lagging; that is I2 lags V by 75⁰)