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Gandhinagar Institute Of
Technology(012)
Active Learning Assignment
Subject:- Calculus (2110014)
Topic:- Continuity OF Function
Branch:- C. E.
Batch:-
Prepared by:-
Enrollment no:
Guided by:-
Introduction
• A function is said to be continuous at x=a if
there is no interruption in the graph of f(x) at a.
And its graph is unbroken at a, and there is no
hole, jump or gap in the graph.
Continuity
• A function is called continuous at c if the
following three conditions are met:
1. f(a,b) exists, i.e.,f(x,y) is defined at (a,b).
2. exists.
3. .
( , ) ( , )
lim ( , )
x y a b
f x y

( , ( , )
lim ( , ) ( , )
x y a b
f x y f a b


Example
Show that f(x,y)= 𝑥2
+ 2y is continuous at (1,2).
Solution
lim
𝑥,𝑦 →(1,2)
𝑓(𝑥, 𝑦)= lim
𝑥,𝑦 →(1,2)
(𝑥2
+ 2y ) = 12
+ 2(2) = 5
𝑓(1,2)=12
+ 2(2) = 5
lim
𝑥,𝑦 →(1,2)
𝑓(𝑥, 𝑦)= 𝑓(1,2)
Hence, f(x,y) is continuous at (1,2).
Example
Show that f(x,y) =
2𝑥𝑦
𝑥2+𝑦2 (x,y) ≠ (0,0)
= 0 (x,y) = (0,0)
is continuous at every point except at the origin.
Solution
lim
𝑥→0
lim
𝑦→0
𝑓 𝑥, 𝑦 = lim
𝑥→0
lim
𝑦→0
2𝑥𝑦
𝑥2+𝑦2
= lim
𝑥→0
0 = 0
lim
𝑥→0
lim
𝑦→0
𝑓 𝑥, 𝑦 = lim
𝑥→0
lim
𝑦→0
2𝑥𝑦
𝑥2+𝑦2
= lim
𝑥→0
0 = 0
Putting y = mx and taking limit x →0,
lim
𝑥→0
2𝑥(𝑚𝑥)
𝑥2+(𝑚𝑥)2
= lim
𝑦→0
2𝑚
1+𝑚2 =
2𝑚
1+𝑚2
Since the last limit depends on m and m is not fixed, the limit does not
exist.
Hence, f(x) is discontinuous at origin i.e., (0,0).
Let (x,y) = (a,b) ≠ (0,0) be an arbitrary point in xy-plane, where a
and b are real numbers.
lim
𝑥,𝑦 →(𝑎,𝑏)
𝑓(𝑥, 𝑦)= lim
𝑥,𝑦 →(𝑎,𝑏)
2𝑥𝑦
𝑥2+𝑦2
=
2𝑎𝑏
𝑎2+𝑏2
f(a,b)=
2𝑎𝑏
𝑎2+𝑏2
which is finite for real values of a and b.
lim
𝑥,𝑦 →(𝑎,𝑏)
𝑓 𝑥, 𝑦 = 𝑓(𝑥, 𝑦)
This shows that f(x,y) is continuous at (a,b).
Hence, f(x,y) is continuous at every point except the origin.
If f and g are functions, continuous at x = c
Then …
f(x) + g(x) is continuous
is continuous
is continuous
f(g(x)) is continuous
( ) ( )f x g x
( )
( )
f x
g x
Continuity Of Functions

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Continuity Of Functions

  • 1. Gandhinagar Institute Of Technology(012) Active Learning Assignment Subject:- Calculus (2110014) Topic:- Continuity OF Function Branch:- C. E. Batch:- Prepared by:- Enrollment no: Guided by:-
  • 2. Introduction • A function is said to be continuous at x=a if there is no interruption in the graph of f(x) at a. And its graph is unbroken at a, and there is no hole, jump or gap in the graph.
  • 3. Continuity • A function is called continuous at c if the following three conditions are met: 1. f(a,b) exists, i.e.,f(x,y) is defined at (a,b). 2. exists. 3. . ( , ) ( , ) lim ( , ) x y a b f x y  ( , ( , ) lim ( , ) ( , ) x y a b f x y f a b  
  • 4. Example Show that f(x,y)= 𝑥2 + 2y is continuous at (1,2). Solution lim 𝑥,𝑦 →(1,2) 𝑓(𝑥, 𝑦)= lim 𝑥,𝑦 →(1,2) (𝑥2 + 2y ) = 12 + 2(2) = 5 𝑓(1,2)=12 + 2(2) = 5 lim 𝑥,𝑦 →(1,2) 𝑓(𝑥, 𝑦)= 𝑓(1,2) Hence, f(x,y) is continuous at (1,2).
  • 5. Example Show that f(x,y) = 2𝑥𝑦 𝑥2+𝑦2 (x,y) ≠ (0,0) = 0 (x,y) = (0,0) is continuous at every point except at the origin. Solution lim 𝑥→0 lim 𝑦→0 𝑓 𝑥, 𝑦 = lim 𝑥→0 lim 𝑦→0 2𝑥𝑦 𝑥2+𝑦2 = lim 𝑥→0 0 = 0 lim 𝑥→0 lim 𝑦→0 𝑓 𝑥, 𝑦 = lim 𝑥→0 lim 𝑦→0 2𝑥𝑦 𝑥2+𝑦2 = lim 𝑥→0 0 = 0 Putting y = mx and taking limit x →0, lim 𝑥→0 2𝑥(𝑚𝑥) 𝑥2+(𝑚𝑥)2 = lim 𝑦→0 2𝑚 1+𝑚2 = 2𝑚 1+𝑚2
  • 6. Since the last limit depends on m and m is not fixed, the limit does not exist. Hence, f(x) is discontinuous at origin i.e., (0,0). Let (x,y) = (a,b) ≠ (0,0) be an arbitrary point in xy-plane, where a and b are real numbers. lim 𝑥,𝑦 →(𝑎,𝑏) 𝑓(𝑥, 𝑦)= lim 𝑥,𝑦 →(𝑎,𝑏) 2𝑥𝑦 𝑥2+𝑦2 = 2𝑎𝑏 𝑎2+𝑏2 f(a,b)= 2𝑎𝑏 𝑎2+𝑏2 which is finite for real values of a and b. lim 𝑥,𝑦 →(𝑎,𝑏) 𝑓 𝑥, 𝑦 = 𝑓(𝑥, 𝑦) This shows that f(x,y) is continuous at (a,b). Hence, f(x,y) is continuous at every point except the origin.
  • 7. If f and g are functions, continuous at x = c Then … f(x) + g(x) is continuous is continuous is continuous f(g(x)) is continuous ( ) ( )f x g x ( ) ( ) f x g x