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International Journal of Trend in Scientific Research and Development (IJTSRD)
Volume: 3 | Issue: 4 | May-Jun 2019 Available Online: www.ijtsrd.com e-ISSN: 2456 - 6470
@ IJTSRD | Unique Paper ID – IJTSRD25192 | Volume – 3 | Issue – 4 | May-Jun 2019 Page: 1657
Existence of Extremal Solutions of
Second Order Initial Value Problems
A. Sreenivas
Department of Mathematics, Mahatma Gandhi University, Nalgonda, Telangana, India
How to cite this paper: A. Sreenivas
"Existence of Extremal Solutions of
Second Order Initial Value Problems"
Published in International Journal of
Trend in Scientific Research and
Development
(ijtsrd), ISSN: 2456-
6470, Volume-3 |
Issue-4, June 2019,
pp.1657-1659, URL:
https://www.ijtsrd.c
om/papers/ijtsrd25
192.pdf
Copyright © 2019 by author(s) and
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Scientific Research and Development
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Attribution License (CC BY 4.0)
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by/4.0)
ABSTRACT
In this paper existence of extremal solutions of second order initial value
problems with discontinuous right hand side is obtained under certain
monotonicity conditions and without assumingtheexistenceofupperandlower
solutions. Two basic differential inequalities correspondingtotheseinitialvalue
problems are obtained in the form of extremal solutions. And also we prove
uniqueness of solutions of given initial value problems under certainconditions.
Keywords: Completelattice,Tarskifixed pointtheorem, isotoneincreasing,minimal
and maximal solutions.
1. INTRODUCTION
In [1], B C Dhage ,G P Patil established the existence of extremal solutions of the
nonlinear two point boundary value problems and in [2] , B C Dhage established
the existence of weak maximal and minimal solutions of the nonlinear two point
boundary value problems with discontinuousfunctionsontherighthand side.We
use the mechanism of [1]and [2] ,to develop the results for second order initial
value problems.
2. Second order initial value problems
Let R denote the real line and R+
, the set of all non negativerealnumbers.Suppose
I1= [0, A] is a closed and bounded interval in R. In this paper we shall establishthe
existence of maximal and minimal solutions for the second order initial value
problems of the type
x11 = f(t,x,x1) a.a. t∈I1 = [0,A], A>o with x(0)=a, x1(0)=b (2.1)
where f : I1xRxR →Risafunctionand
2
1 11
2
,
dx d x
x x
dt dt
= = .
By a solution x of the IVP (2.1), we mean a function x : I1 →R
whose first derivative exists and is absolutely continuouson
I1, satisfying (2.1).
Integrating (2.1), we find that
1 1
0
( ) ( , ( ), ( ))
t
x t b f s x s x s ds= + ∫ and
1
0
( ) ( , ) ( , ( ), ( ))
t
x t a bt k t s f s x s x s ds= + + ∫ (2.2)
where the kernel k(t,s)=t-s and
1( , ) ( , ) {( , ):0 }k t s C I wherein t s s t A∈ Ω Ω = ≤ ≤ ≤ .
To prove the main existence result we need the following
preliminaries.
Let C(I1,R) denote the space of continuous real valued
functions on I1, AC(I1,R) the space of all absolutely
continuous functions on I1 , M(I1,R ) the space of all
measurable real valued functions on I1 and B(I1,R), thespace
of all bounded real valued functions on I1 . By BM(I1,R),we
mean the space of bounded and measurable real valued
functions on I1, where I1 is given interval . We define an
order relation ≤ in BM(I1,R) by x,y∈BM(I1,R), then x ≤y if
and only if x(t) ≤y(t) and
1 1
( ) ( )x t y t≤ for all t∈ I1.
A set S in BM(I1, R) is a complete lattice w.r.t ≤ if supremum
and infimum of every sub set of S exists in S.
Definition 2.1 A mapping T: BM(I1,R) → BM(I1,R) is said to
be isotone increasing
if x,y ∈BM(I1,R) with x ≤y implies Tx ≤Ty.
The following fixed point theorem due to Tarski [7] will be
used in proving the existence of extremalsolutionsof second
order initial value problems.
Theorem 2.2 Let E be a nonempty set and let 1T : E →E be a
mapping such that
(i) (E, ≤ ) is a complete lattice
(ii) 1T is isotone increasing and
(iii) F= {u∈E / 1T u=u}.
Then F is non empty ( , )and F ≤ is a complete lattice.
To prove a result on existence define a norm on BM(I1, R) by
( )1
1
1
sup
( ) ( )x x t x t
t I
= +
∈
for 1( , )x BM I R∈ .
IJTSRD25192
International Journal of Trend in Scientific Research and Development (IJTSRD) @ www.ijtsrd.com eISSN: 2456-6470
@ IJTSRD | Unique Paper ID – IJTSRD25192 | Volume – 3 | Issue – 4 | May-Jun 2019 Page: 1658
Then clearly BM(I1,R) is a Banach space with the above
norm. We shall now prove the existence of maximal and
minimal solutions for the IVP (2.1). For this we need the
following assumptions:
(f1): f is bounded on I1xRxR by k3 , k3 >0.
(f2) : f (t,ϕ (t),ϕ 1(t) ) is Lebesgue measurable for Lebesgue
measurable functions ϕ ,ϕ 1 on I1, and
(f3) : f (t,x,x1) is nondecreasing in both x and x1 in R for a.a.
t∈I1.
Theorem 2.3 Assume that the hypotheses (f1-f3) hold. Then
the IVP (2.1) has maximal and minimal solutions on I1.
Proof . Define a sub set S of the Banach space BM(I1,R) by
1 31
{ ( , ): *}S x BM I R x k= ∈ ≤ (2.3)
where k3* =Max
2
3 3 3( , )
2
A
a b A k b k A k+ + + + .
Clearly S is closed, convex and boundedsubsetoftheBanach
space BM(I1,R) and hence by definition (S, ≤) is a complete
lattice. We define an operator
T : S →BM(I1,R) by
1
0
( ) ( ) ( , ( ), ( ))
t
T x t a bt t s f s x s x s ds= + + −∫ , t∈I1. (2.4)
Then
T
1 1
0
( ) ( , ( ), ( ))
t
x t b f s x s x s ds= + ∫ , t∈I1
Obviously (Tx) and (Tx1) are continuous on I1 and hence
measurable on I1 . We now show that T maps S into itself .Let
x∈Sbe an arbitrary point , then
1
0
2
3
( ) ( ) ( , ( ), ( ))
2
t
T x t a b t t s f s x s x s ds
t
a b t k
≤ + + −
≤ + +
∫
And
1 1
0
( ) ( , ( ), ( ))
t
T x t b f s x s x s ds≤ + ∫
3b k t≤ +
Therefore
( )1
1
1
2
3 3
1
2
3 3 3
sup
( ) ( )
sup
2
*
2
T x T x t T x t
t I
t
a b t k b k t
t I
A
a b A k b k A k
= +
∈
 
≤ + + + + 
∈  
 
≤ + + + + ≤ 
 
This shows that Tmaps S into itself. Let x, y be suchthat x ≤y,
then by (f3) we get
1
0
1
1
0
( ) ( ) ( , ( ), ( ))
( ) ( , ( ), ( )) ( )
t
t
T x t a bt t s f s x s x s ds
a bt t s f s y s y s ds T y t t I
= + + −
≤ + + − = ∀ ∈
∫
∫
and
1 1
0
1 1
1
0
( ) ( , ( ), ( ))
( , ( ), ( )) ( ) , .
t
t
T x t b f s x s x s ds
b f s y s y s ds T y t t I
= +
≤ + = ∈
∫
∫
This shows that T is isotone increasing on S.
In view of Theorem 2.2, it follows that the operator equation
Tx = x has solutions and that the set of all solutions is a
complete lattice, implying that the set of all solutionsof (2.1)
is a complete lattice. Consequently theIVP(2.1)hasmaximal
and minimal solutions in S.
Finally in view of the definition of the operator T ,it follows
that these extremal solutions are in C(I1,R) ⊂ AC(I1,R). This
completes the proof.
We shall now show that the maximal and minimal solutions
of the IVP (2.1) serve as the bounds for the solutions of the
differential inequalities related to the IVP (2.1).
Theorem 2.4 Assume that all the conditions of Theorem2.3
are satisfied. Suppose that there exists a function u∈S,
where S is as defined in the proof of Theorem 2.3 satisfying
11 1
( , , )u f t u u≤ a.a. t∈I1 with u(0 ) = a ,
1
(0)u b= . (2.5)
Then there exists a maximal solution Mx of the IVP (2.1)
such that
1( ) ( ) ,Mu t x t t I≤ ∈ .
Proof. Let p = Sup S. Clearly the element p exists, since S is a
complete lattice. Consider the lattice interval [u, p] in S
where u is a solution of (2.5) .We notice that [u, p] is
obviously a complete lattice.
It can be shown as in the proof of Theorem 2.3 that T : [u, p]
→ S is isotone increasing on [u,p] . We show that T maps
[u, p] into itself. For this it suffices toshowthatu ≤Txforany
x∈S with u ≤x. Now from the inequality(2.5),itfollowsthat
1 1
0
( ) ( , ( ), ( ))
t
u t b f s u s u s ds≤ + ∫
1 1
1
0
( , ( ), ( )) ( ) ,
t
b f s x s x s ds T x t t I≤ + = ∈∫ And
1
0
( ) ( ) ( , ( ), ( ))
t
u t a bt t s f s u s u s ds≤ + + −∫
1
0
( ) ( , ( ), ( ))
t
a bt t s f s x s x s ds≤ + + −∫ = Tx(t) for all t∈I1.
This shows that T maps [u, p] into itself. Applying the
Theorem 2.2, we conclude that there is a maximal
International Journal of Trend in Scientific Research and Development (IJTSRD) @ www.ijtsrd.com eISSN: 2456-6470
@ IJTSRD | Unique Paper ID – IJTSRD25192 | Volume – 3 | Issue – 4 | May-Jun 2019 Page: 1659
solution Mx of the integral equation (2.2) and consequently
of the IVP (2.1) in [u, p].
Therefore
)()( txtu M≤ for t∈I1.
This completes the proof.
Theorem 2.5 Suppose that all theconditionsof Theorem 2.3
hold, and assume that there is a function v∈S, where S is as
defined in the proof of Theorem 2.3, such that
11 1
( , , )v f t v v≥ a.a. t ∈I1 with v (0 ) = a ,
1
(0)v b= .
Then there is a minimal solution xm of the IVP (2.1) such that
xm(t) ≤ v(t) , for t∈I1 .
The proof is similar to that of Theorem 2.4 and we omit the
details We shall now provetheuniquenessof solutionsofthe
IVP (2.1).
Theorem 2.6 In addition tothehypothesisofTheorem 2.3,if
the function
1
( , , )f t x x on I1 x R x R satisfies the condition
that
1 1
1 1
1 1
( , , ) ( , , ) ,
x yx y
f t x x f t y y M Min
A x y A x y
 −−
 − ≤
 + − + − 
(2.6)
for some M>0. Then the IVP (2.1) has unique solution
defined on I1 .
Proof . Let BM(I1, R) denote the space of all bounded and
measurable functions defined on I1 .Define a norm on BM(I1,
R) by
2
1
sup
( )Lt
x e x t
t I
−
=
∈
, for x∈ BM (I1, R)
where L is a fixed positive constantsuch that 2
1
M
L
< .Notice
that BM(I1, R) is a Banach space with the norm 2
. . DefineT:
BM(I1,R) → BM(I1,R) by (2.4).
Let ( ), ( )m Mx t x t be minimal and maximal solutions of the
IVP (2.1 ) respectively. Then we have
(T Mx )(t) - (T mx )(t) =
1 1
0
( ) ( , ( ), ( )) ( , ( ), ( ))
t
M M m mt s f s x s x s f s x s x s ds − − ∫ .
Using (2.6) we see that
( )( ) ( )( )M mT x t T x t−
0
( ) ( )
( )
( ) ( )
t
M m
M m
x s x s
M t s ds
A x s x s
 −
≤ −   + − 
∫
That is
( ) 3 2
1 0
sup
( ) ( )( ) ( )
t
Ls
M m M mT x t T x t M x x t s e ds
t I
− ≤ − −
∈ ∫
22
Lt
M m
e
M x x
L
≤ − .
This implies that
22 2M m M m
M
T x T x x x
L
− ≤ − .
Since 2
1
M
L
< , the mapping T is a contrition .Applying the
contraction mapping principle, we concludethatthereexists
a unique fixed point x∈ BM(I1,R) such that
(Tx)(t) =
1
1
0
( ) ( ) ( , ( ), ( ))
t
x t a bt t s f s x s x s ds t I= + + − ∀ ∈∫ .
This completes the proof.
Acknowledgements: I am thankfultoPro.K.Narsimhareddy
for his able guidance. Also thankful to Professor KhajaAlthaf
Hussain Vice Chancellor of Mahatma Gandhi University,
Nalgonda to provide facilities in the tenure of which this
paper was prepared.
References
[1] B.C. Dhage and G.P. Patil “ On differential inequalities
for discontinuous non-linear twopointboundaryvalue
problems” Differential equations and dynamical
systems, volume 6, Number 4, October 1998, pp. 405 –
412.
[2] B.C.Dhage , “On weak Differential Inequalities for
nonlinear discontinuous boundary valueproblemsand
Applications’’. Differential equations and dynamical
systems, volume 7, number 1, January 1999, pp.39-47.
[3] K. Narshmha Reddy and A.Sreenivas “On Integral
Inequities in n – Independent Variables”, Bull .Cal
.Math. Soc ., 101 (1) (2009), 63-70 .
[4] G. Birkhoff , “Lattice theory ’’ , Amer .Math. Soc.
Coll.publ. Vol.25, NewYork, 1979.
[5] S.G. Deo, V.Lakshmikantham, V.Raghavendra, “Text
book of Ordinary Differential Equations” second
edition.
[6] B.C.Dhage “ Existence theory for nonlinear functional
boundary value Problems’’. Electronic Journal of
Qualitative theoryofDifferentialEquations,2004,No1,
1-15.
[7] A. Tarski , “A lattice theoreticalfixed pointtheorem and
its application, pacific . J. Math., 5(1955), 285 – 310.

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Existence of Extremal Solutions of Second Order Initial Value Problems

  • 1. International Journal of Trend in Scientific Research and Development (IJTSRD) Volume: 3 | Issue: 4 | May-Jun 2019 Available Online: www.ijtsrd.com e-ISSN: 2456 - 6470 @ IJTSRD | Unique Paper ID – IJTSRD25192 | Volume – 3 | Issue – 4 | May-Jun 2019 Page: 1657 Existence of Extremal Solutions of Second Order Initial Value Problems A. Sreenivas Department of Mathematics, Mahatma Gandhi University, Nalgonda, Telangana, India How to cite this paper: A. Sreenivas "Existence of Extremal Solutions of Second Order Initial Value Problems" Published in International Journal of Trend in Scientific Research and Development (ijtsrd), ISSN: 2456- 6470, Volume-3 | Issue-4, June 2019, pp.1657-1659, URL: https://www.ijtsrd.c om/papers/ijtsrd25 192.pdf Copyright © 2019 by author(s) and International Journal of Trend in Scientific Research and Development Journal. This is an Open Access article distributed under the terms of the Creative Commons Attribution License (CC BY 4.0) (http://creativecommons.org/licenses/ by/4.0) ABSTRACT In this paper existence of extremal solutions of second order initial value problems with discontinuous right hand side is obtained under certain monotonicity conditions and without assumingtheexistenceofupperandlower solutions. Two basic differential inequalities correspondingtotheseinitialvalue problems are obtained in the form of extremal solutions. And also we prove uniqueness of solutions of given initial value problems under certainconditions. Keywords: Completelattice,Tarskifixed pointtheorem, isotoneincreasing,minimal and maximal solutions. 1. INTRODUCTION In [1], B C Dhage ,G P Patil established the existence of extremal solutions of the nonlinear two point boundary value problems and in [2] , B C Dhage established the existence of weak maximal and minimal solutions of the nonlinear two point boundary value problems with discontinuousfunctionsontherighthand side.We use the mechanism of [1]and [2] ,to develop the results for second order initial value problems. 2. Second order initial value problems Let R denote the real line and R+ , the set of all non negativerealnumbers.Suppose I1= [0, A] is a closed and bounded interval in R. In this paper we shall establishthe existence of maximal and minimal solutions for the second order initial value problems of the type x11 = f(t,x,x1) a.a. t∈I1 = [0,A], A>o with x(0)=a, x1(0)=b (2.1) where f : I1xRxR →Risafunctionand 2 1 11 2 , dx d x x x dt dt = = . By a solution x of the IVP (2.1), we mean a function x : I1 →R whose first derivative exists and is absolutely continuouson I1, satisfying (2.1). Integrating (2.1), we find that 1 1 0 ( ) ( , ( ), ( )) t x t b f s x s x s ds= + ∫ and 1 0 ( ) ( , ) ( , ( ), ( )) t x t a bt k t s f s x s x s ds= + + ∫ (2.2) where the kernel k(t,s)=t-s and 1( , ) ( , ) {( , ):0 }k t s C I wherein t s s t A∈ Ω Ω = ≤ ≤ ≤ . To prove the main existence result we need the following preliminaries. Let C(I1,R) denote the space of continuous real valued functions on I1, AC(I1,R) the space of all absolutely continuous functions on I1 , M(I1,R ) the space of all measurable real valued functions on I1 and B(I1,R), thespace of all bounded real valued functions on I1 . By BM(I1,R),we mean the space of bounded and measurable real valued functions on I1, where I1 is given interval . We define an order relation ≤ in BM(I1,R) by x,y∈BM(I1,R), then x ≤y if and only if x(t) ≤y(t) and 1 1 ( ) ( )x t y t≤ for all t∈ I1. A set S in BM(I1, R) is a complete lattice w.r.t ≤ if supremum and infimum of every sub set of S exists in S. Definition 2.1 A mapping T: BM(I1,R) → BM(I1,R) is said to be isotone increasing if x,y ∈BM(I1,R) with x ≤y implies Tx ≤Ty. The following fixed point theorem due to Tarski [7] will be used in proving the existence of extremalsolutionsof second order initial value problems. Theorem 2.2 Let E be a nonempty set and let 1T : E →E be a mapping such that (i) (E, ≤ ) is a complete lattice (ii) 1T is isotone increasing and (iii) F= {u∈E / 1T u=u}. Then F is non empty ( , )and F ≤ is a complete lattice. To prove a result on existence define a norm on BM(I1, R) by ( )1 1 1 sup ( ) ( )x x t x t t I = + ∈ for 1( , )x BM I R∈ . IJTSRD25192
  • 2. International Journal of Trend in Scientific Research and Development (IJTSRD) @ www.ijtsrd.com eISSN: 2456-6470 @ IJTSRD | Unique Paper ID – IJTSRD25192 | Volume – 3 | Issue – 4 | May-Jun 2019 Page: 1658 Then clearly BM(I1,R) is a Banach space with the above norm. We shall now prove the existence of maximal and minimal solutions for the IVP (2.1). For this we need the following assumptions: (f1): f is bounded on I1xRxR by k3 , k3 >0. (f2) : f (t,ϕ (t),ϕ 1(t) ) is Lebesgue measurable for Lebesgue measurable functions ϕ ,ϕ 1 on I1, and (f3) : f (t,x,x1) is nondecreasing in both x and x1 in R for a.a. t∈I1. Theorem 2.3 Assume that the hypotheses (f1-f3) hold. Then the IVP (2.1) has maximal and minimal solutions on I1. Proof . Define a sub set S of the Banach space BM(I1,R) by 1 31 { ( , ): *}S x BM I R x k= ∈ ≤ (2.3) where k3* =Max 2 3 3 3( , ) 2 A a b A k b k A k+ + + + . Clearly S is closed, convex and boundedsubsetoftheBanach space BM(I1,R) and hence by definition (S, ≤) is a complete lattice. We define an operator T : S →BM(I1,R) by 1 0 ( ) ( ) ( , ( ), ( )) t T x t a bt t s f s x s x s ds= + + −∫ , t∈I1. (2.4) Then T 1 1 0 ( ) ( , ( ), ( )) t x t b f s x s x s ds= + ∫ , t∈I1 Obviously (Tx) and (Tx1) are continuous on I1 and hence measurable on I1 . We now show that T maps S into itself .Let x∈Sbe an arbitrary point , then 1 0 2 3 ( ) ( ) ( , ( ), ( )) 2 t T x t a b t t s f s x s x s ds t a b t k ≤ + + − ≤ + + ∫ And 1 1 0 ( ) ( , ( ), ( )) t T x t b f s x s x s ds≤ + ∫ 3b k t≤ + Therefore ( )1 1 1 2 3 3 1 2 3 3 3 sup ( ) ( ) sup 2 * 2 T x T x t T x t t I t a b t k b k t t I A a b A k b k A k = + ∈   ≤ + + + +  ∈     ≤ + + + + ≤    This shows that Tmaps S into itself. Let x, y be suchthat x ≤y, then by (f3) we get 1 0 1 1 0 ( ) ( ) ( , ( ), ( )) ( ) ( , ( ), ( )) ( ) t t T x t a bt t s f s x s x s ds a bt t s f s y s y s ds T y t t I = + + − ≤ + + − = ∀ ∈ ∫ ∫ and 1 1 0 1 1 1 0 ( ) ( , ( ), ( )) ( , ( ), ( )) ( ) , . t t T x t b f s x s x s ds b f s y s y s ds T y t t I = + ≤ + = ∈ ∫ ∫ This shows that T is isotone increasing on S. In view of Theorem 2.2, it follows that the operator equation Tx = x has solutions and that the set of all solutions is a complete lattice, implying that the set of all solutionsof (2.1) is a complete lattice. Consequently theIVP(2.1)hasmaximal and minimal solutions in S. Finally in view of the definition of the operator T ,it follows that these extremal solutions are in C(I1,R) ⊂ AC(I1,R). This completes the proof. We shall now show that the maximal and minimal solutions of the IVP (2.1) serve as the bounds for the solutions of the differential inequalities related to the IVP (2.1). Theorem 2.4 Assume that all the conditions of Theorem2.3 are satisfied. Suppose that there exists a function u∈S, where S is as defined in the proof of Theorem 2.3 satisfying 11 1 ( , , )u f t u u≤ a.a. t∈I1 with u(0 ) = a , 1 (0)u b= . (2.5) Then there exists a maximal solution Mx of the IVP (2.1) such that 1( ) ( ) ,Mu t x t t I≤ ∈ . Proof. Let p = Sup S. Clearly the element p exists, since S is a complete lattice. Consider the lattice interval [u, p] in S where u is a solution of (2.5) .We notice that [u, p] is obviously a complete lattice. It can be shown as in the proof of Theorem 2.3 that T : [u, p] → S is isotone increasing on [u,p] . We show that T maps [u, p] into itself. For this it suffices toshowthatu ≤Txforany x∈S with u ≤x. Now from the inequality(2.5),itfollowsthat 1 1 0 ( ) ( , ( ), ( )) t u t b f s u s u s ds≤ + ∫ 1 1 1 0 ( , ( ), ( )) ( ) , t b f s x s x s ds T x t t I≤ + = ∈∫ And 1 0 ( ) ( ) ( , ( ), ( )) t u t a bt t s f s u s u s ds≤ + + −∫ 1 0 ( ) ( , ( ), ( )) t a bt t s f s x s x s ds≤ + + −∫ = Tx(t) for all t∈I1. This shows that T maps [u, p] into itself. Applying the Theorem 2.2, we conclude that there is a maximal
  • 3. International Journal of Trend in Scientific Research and Development (IJTSRD) @ www.ijtsrd.com eISSN: 2456-6470 @ IJTSRD | Unique Paper ID – IJTSRD25192 | Volume – 3 | Issue – 4 | May-Jun 2019 Page: 1659 solution Mx of the integral equation (2.2) and consequently of the IVP (2.1) in [u, p]. Therefore )()( txtu M≤ for t∈I1. This completes the proof. Theorem 2.5 Suppose that all theconditionsof Theorem 2.3 hold, and assume that there is a function v∈S, where S is as defined in the proof of Theorem 2.3, such that 11 1 ( , , )v f t v v≥ a.a. t ∈I1 with v (0 ) = a , 1 (0)v b= . Then there is a minimal solution xm of the IVP (2.1) such that xm(t) ≤ v(t) , for t∈I1 . The proof is similar to that of Theorem 2.4 and we omit the details We shall now provetheuniquenessof solutionsofthe IVP (2.1). Theorem 2.6 In addition tothehypothesisofTheorem 2.3,if the function 1 ( , , )f t x x on I1 x R x R satisfies the condition that 1 1 1 1 1 1 ( , , ) ( , , ) , x yx y f t x x f t y y M Min A x y A x y  −−  − ≤  + − + −  (2.6) for some M>0. Then the IVP (2.1) has unique solution defined on I1 . Proof . Let BM(I1, R) denote the space of all bounded and measurable functions defined on I1 .Define a norm on BM(I1, R) by 2 1 sup ( )Lt x e x t t I − = ∈ , for x∈ BM (I1, R) where L is a fixed positive constantsuch that 2 1 M L < .Notice that BM(I1, R) is a Banach space with the norm 2 . . DefineT: BM(I1,R) → BM(I1,R) by (2.4). Let ( ), ( )m Mx t x t be minimal and maximal solutions of the IVP (2.1 ) respectively. Then we have (T Mx )(t) - (T mx )(t) = 1 1 0 ( ) ( , ( ), ( )) ( , ( ), ( )) t M M m mt s f s x s x s f s x s x s ds − − ∫ . Using (2.6) we see that ( )( ) ( )( )M mT x t T x t− 0 ( ) ( ) ( ) ( ) ( ) t M m M m x s x s M t s ds A x s x s  − ≤ −   + −  ∫ That is ( ) 3 2 1 0 sup ( ) ( )( ) ( ) t Ls M m M mT x t T x t M x x t s e ds t I − ≤ − − ∈ ∫ 22 Lt M m e M x x L ≤ − . This implies that 22 2M m M m M T x T x x x L − ≤ − . Since 2 1 M L < , the mapping T is a contrition .Applying the contraction mapping principle, we concludethatthereexists a unique fixed point x∈ BM(I1,R) such that (Tx)(t) = 1 1 0 ( ) ( ) ( , ( ), ( )) t x t a bt t s f s x s x s ds t I= + + − ∀ ∈∫ . This completes the proof. Acknowledgements: I am thankfultoPro.K.Narsimhareddy for his able guidance. Also thankful to Professor KhajaAlthaf Hussain Vice Chancellor of Mahatma Gandhi University, Nalgonda to provide facilities in the tenure of which this paper was prepared. References [1] B.C. Dhage and G.P. Patil “ On differential inequalities for discontinuous non-linear twopointboundaryvalue problems” Differential equations and dynamical systems, volume 6, Number 4, October 1998, pp. 405 – 412. [2] B.C.Dhage , “On weak Differential Inequalities for nonlinear discontinuous boundary valueproblemsand Applications’’. Differential equations and dynamical systems, volume 7, number 1, January 1999, pp.39-47. [3] K. Narshmha Reddy and A.Sreenivas “On Integral Inequities in n – Independent Variables”, Bull .Cal .Math. Soc ., 101 (1) (2009), 63-70 . [4] G. Birkhoff , “Lattice theory ’’ , Amer .Math. Soc. Coll.publ. Vol.25, NewYork, 1979. [5] S.G. Deo, V.Lakshmikantham, V.Raghavendra, “Text book of Ordinary Differential Equations” second edition. [6] B.C.Dhage “ Existence theory for nonlinear functional boundary value Problems’’. Electronic Journal of Qualitative theoryofDifferentialEquations,2004,No1, 1-15. [7] A. Tarski , “A lattice theoreticalfixed pointtheorem and its application, pacific . J. Math., 5(1955), 285 – 310.