How the Solar Group is Created? (Discussion No. 1)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
How the Solar Group is Created? (Discussion No. 1)
By Gerges Francis Twadrous
2nd
Course Student – Physics Department - Physics & Math Faculty –
Peoples' Friendship University – Moscow – Russia -2010-2013
TEL +201022532292 mrwaheid@gmail.com / georgytawdrous@yandex.ru
The Assumption Of S. Virgin Mary -Written in Cairo – Egypt – 3rd
April 2019
Abstract
This Paper provides our first try to answer the question…
How The Solar Group Is Created?
Here we'll try to prove The Following Arguments:
1- The Solar Group is One Geometrical Structure or one building and each planet
is a part of this same geometrical structure (building)- i.e. Each planet data is
created to be suitable for the required task of this planet in the whole building and
No solar planet can be found or move independently
a. Also the solar group can be similar to one body, and each planet is a member
in this same body. All solar planets and their orbital distances are created by
the same energy (by the same blood all body members are created)
b. OR, The solar group be similar to one machine each planet is a gear in this
same machine… so the machine job depends on the gears different tasks..
and that means the cooperation and integration between the solar
planets data is the main base on which the solar group is created and move.
c. Also, The solar group can be similar to a great river has many canals and
these canals created soils on their banks. The river, canals and their soils all
of them are created from the same water (the same energy)
The previous claim and conclusion is discussed in this paper strongly and the paper
provides curial proves to show this fact as clear as the sun herself.
2- Saturn is The Most Important Planet in the solar group and he connects the
group together where without Saturn the solar group can't be found or move.
3- Mars current existence and motion depends on Earth Moon Orbit.
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
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All my papers http://vixra.org/author/gerges_francis_tawdrousBest

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1- Introduction
The solar group is one machine, or one geometrical structure…etc
I have tried to prove this fact frequently before but the proves always were
insufficient to enable this conclusion to be acceptable…! Why?
I wish to explain the basic difficulty in following….
I use The Solar Planet Data Analysis,
For example, when we ask "How The Planet Diameter Is Created?" I analyze the
solar planets diameters values to see the geometrical concept behind their creation.
As in Pythagoras rule… (a2
= b2
+c2
)… now if we have a triangle its dimension = 3,4
and 5 meters by this triangle dimensions analysis we can reach to Pythagoras rule…
That's the same when I analyze the solar planets diameters data, I may reach to the
geometrical concept behind their creations…. Let's test this method in following:
Equation No.1
The Solar Planets Diameters Total = 2 Jupiter Diameters + 1 Saturn Diameter
Equation No.2
The Solar Planets Diameters Total = Earth Moon Distance At Apogee Point
Let's analyze Equation No. 1
- Solar planets diameter total equal 2 Jupiter diameters plus 1 Saturn diameter…
what conclusion we may reach here? Jupiter and Saturn are the main columns
in the solar group geometry…. Is it correct? Almost yes … but we need to see
as deeply as possible… the next question is ………. Is there a relationship
between Jupiter and Saturn diameters? Of course Yes
Equation No.3
2 Saturn Circumferences = 2 Jupiter Circumference – 1 Jupiter Diameter
Equation No.4
Saturn Circumference = Earth Moon Distance At Total Solar Eclipse.
The Discussion:-
I have provided a few data trying to explain that the solar planets diameters are
created by a geometrical rule depending on Saturn diameter! Is it a sufficient proof?
Of course Not…. and why I can't provide the sufficient one?
Actually It's a real complex process!
The data analysis is boring process and the reader will give up soon…
But when I provide the conclusion without data analysis… the conclusion will be
seen as an imaginary idea has no roots…!
So we need to analyze the data as deeply as possible and in the same time we need to
provide the clear idea gradually to be completed with the data analysis …. It's not
easy process but we have chance this time to do that because we have many strong
points in a series… so we'll start directly to analyze the Saturn and Jupiter diameters
in following point to prove our main claim which is
The Solar Group is One Geometrical Structure

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2-Saturn Diameter Analysis
2-1 Preface
2-2 Saturn Diameter Analysis
2-3 Saturn Orbital Inclination and Axial Tilt
2-4 Mars Motion
2-1 Preface
Why Saturn diameter is so important one? Who claims this idea and based on what?
In fact there are at 4 approaches to reach to this conclusion… let's refer to them:
1- The Solar Planets Diameters Total (we have referred to it in the Introduction)
2- The Earth Moon Data (we have referred to it in the Introduction)
3- Mercury Data
4- Saturn Orbital Distance
Let's remember Mercury Day data in following:
Mercury Day = 176 Solar Days but minus only 5040 seconds…
The value 5040 seconds is defined clearly by Mercury day and solar day period…
Now let's see the puzzle again…
a- Mercury by his actual velocity moves during 5040 seconds a distance = 2 Saturn
diameters
b- Mars by his actual velocity moves during 5040 seconds a distance = 1 Saturn
diameter
c- Saturn by his actual velocity moves during 5040 seconds a distance = 1 Neptune
diameter
d- Pluto by his actual velocity moves during 5040 seconds a distance = Pluto
diameter x π2
The distinguished data should be (a and b) because Saturn diameter is found in them
– as we expect- but in fact all data are puzzled- for example Neptune orbital distance
= Saturn orbital distance x π…. I can't explain the geometrical reason behind but I
can see there's a real connection here…about Pluto equation (d).. we will discuss it
basically in this paper… where the argument here in fact concerning the relationship
between Saturn and Pluto!
Let's provide more data in following……
Saturn Orbital Distance:
Table No.1 Saturn Orbital Distance
- If Saturn Orbital Distance = 1 So
- Mars Orbital Circumference = 1
- Saturn Uranus Distance = 1
- Pluto Eccentricity Distance = 1
- Uranus Orbital Distance = 2
- Neptune Orbital Distance = Π
- Mercury Jupiter Distance = 1/2
Why These Values Are Equal? I see it's illogical to ignore the planet data claiming
any data is found by pure coincidence without any geometrical or physical reason!

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The Moon Orbit Triangle
The moon orbit data analysis provides absolute strong claims here
Let's suppose C is Earth
- AB = 120536 km = (=Saturn diameter)
- CB = 449000km = (=Jupiter Circumference)
- AC =373000 km =(=Saturn Circumference)= 373000 km = (Earth Moon
Distance when the moon at solar eclipse radius)
Details of CB
- CD= 363000 km =(Earth Moon Distance when the moon at perigee point)
- CF= 406000 km =(Earth Moon Distance when the moon at apogee point)
- DF=FB=43000 km (distance between perigee and apogee)
- AD is Perpendicular on the base CB where AD = DB = 86000 km
- EF=GD =43000 km (DFEG is a square its dimension =43000km)
- EF is perpendicular on the base, so the angle (BEF)= 45 degrees.
More Data:
I- Solar Planets Diameters Total = 2 Jupiter diameters + 1 Saturn diameter
II- Jupiter Diameter = 2 Jupiter Circumference – 2 Saturn Circumference
III-
VI- CD =363000 km = Perigee radius = outer planets diameters total
- Saturn diameter = Venus diameter x π2
- The sun diameter = Jupiter diameter x π2
- (Earth diameter/ Moon diameter) = (Sun diameter/ Saturn Circumference)
(Group No. 4)
During A Period = 5040 seconds
a- Mercury moves a distance = 2 Saturn diameter (Error 1%)
b- Mars moves a distance = 1 Saturn diameter (Less than 1%)
c- Saturn moves a distance = Neptune diameter (Error 1.2%)
d- Pluto moves a distance = Pluto circumference x π (Less than 1%)
e- Saturn Orbital Distance = (Saturn diameter)2
/π2
(Error 2.6 %)
There's more data to support this same claim (Saturn Diameter is the most important
one in the solar group), but we'll discuss it with our arguments
For more data please review
Does Earth Velocity Causes The Eclipse Phenomena? (T.S. Eclipse III)
http://vixra.org/abs/1903.0489
12
2
km120536diameterSaturn
km142984diameterJupiter
−
=
π
π

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2-2 Saturn Diameter Analysis
We have provided many data in previous sub-point (2-1)... how to understand it?
I have one approach to do that ... let's start immediately (with Equation No.3 found in
the introduction)
Equation No.3
2 Saturn Circumferences = 2 Jupiter Circumference – 1 Jupiter Diameter
That tells us
Equation No.5
We can see that Saturn and Jupiter are functions in each other… but to create both of
them the rate (2π) is necessary to be found….! Why?
The following data will give us a key to answer this question but later we will have
serious fighting to define one traditional expression in our new vision …. We need to
define "The Unit"…. Let's firstly to provide the data….
Solar Planets Velocities
Planet Velocity daily x another planet Velocity daily = 2π mkm2
• 4.095 mkm (Mercury Velocity daily) x 1.535 mkm (Ceres Velocity daily) = 2π mkm2
• 3.02 mkm (Venus Velocity daily) x 2.08 mkm (Mars Velocity daily) =2π mkm2
• 2.58 mkm (Earth Velocity daily) x 2.41 mkm (Moon Velocity daily) =2π mkm2
So the rate (2π) which is found by Saturn and Jupiter diameters creation, is transported
into the solar planets velocities… (please remember that solar planets diameters total = 2
Jupiter diameters + 1 Saturn diameter )
Here we need to redefine "the Unit"… but before, we need to ask why this rate (2π) is so
important and based on it the planets diameters and velocities are created?
Because the solar group needs to have a connection with Pluto otherwise Pluto
will be lost and separated from the solar group!! How that can be possible?
Equation No.5
Pluto orbital period = (2π)3
Earth orbital period
Specially 90588 days = (2π)3
1461 days
(1461 days = 365+365+365+366) = Earth Cycle
Equation No. 5 tells us why Pluto still connected with the solar group…to understand
much better let's tell the whole story in following:
(Please Note That, the rate (2π) connects the planet diameter with the planet
velocity, that tells us how the matter is created..! the matter is c created based on the
motion and without motion the matter will be perished).
2
DiameterJupiter
-DiameterJupiterDiameterSaturn
π
=

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I- Pluto Story
We know This Story… let's summarize it shortly:-
- The ancient solar planets were 7 planets which are in order (Mercury – Pluto-
Mars- Earth – Jupiter- Uranus – Neptune)
But
- Mars had immigrated from his original point at distance 84 mkm from the sun
to dwell in his new point at distance 227.9 mkm from the sun….
- Mars immigration caused Pluto also to immigrate – but very far- so Pluto
occupies the last point in the solar group.
After Mars Immigration
- Saturn, Venus and the Earth Moon are created
- Saturn specifically works to connect the solar group again and to deal the
disturbance which is caused by Mars immigration…
- Saturn basically tries strongly to keep Pluto in the solar group
- We need to remember that the matter is found based on the motion and that
means the planets diameters were not fixed but changed with their motions
changes to be suitable for the general cooperation and integration between the
solar planets each other. But that doesn't mean the planets diameters were
created after Mars immigration but the planets diameters have modifications after
Mars immigration in configuration with other factors effected on the planet creation
and motion..
- There are other modifications were happened in the solar group… which we can't
discuss because we have no strong proves for them…
- This story still is confused and not clear… but the following discussion will support
this vision strongly
To review some more data please read
Mars Immigration Proves (Revised)
Pluto was "The Mercury Moon"

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II- The Unit Definition
How (2π)–as a rate between Saturn and Jupiter diameters- can be transported as (2π mkm2
)?
How this 2 values can be equal…
To answer we have to point to discuss here (1) the planet velocity (2) the unit meaning
(1) The Planets Velocities
- Data
f- A==== 17.1
VelocityPluto
VelocityNeptune
VelocityMars
VelocityMoon
VelocityEarth
VelocityVenus
(Max error 1.8%)
g- 2
355.1
VelocityJupiter
VelocityCeres
VelocityCeres
VelocityMars
VelocityVenus
VelocityMercury
A==== (Max error less 1%)
h- B=== 239.1
VelocityMars
VelocityEarth
VelocityNeptune
VelocityUranus
(Max error 1.6 %)
i- 2
4263.1
VelocityUranus
VelocitySaturn
B== (Max error1.8 %)
j- (B/A) = (B2
/A2
) = 1.0725 (Max error1.3%)
Discussion
The previous data simply tells that the planet velocity is found by a geometrical reason and
not but the gravity effect as the current theory tells us…!
Simply the current definition of velocity is unreal….
(2) The Unit Meaning – Data
Table No.2 (the table uses 1433.5 days and not 1433.5 mkm) error
-1433.5 days x Mercury velocity daily 4.095 mkm = 5870 mkm Pluto Orbital Distance No Error
-1433.5 days x Venus velocity daily 3.02 mkm =4329 mkm Venus Neptune Distance 0
-1433.5 days x Earth velocity daily 2.58 mkm = 3699 mkm Jupiter Neptune Distance 0
-1433.5 days x Mars velocity daily 2.082 mkm = 2984.5 mkm Uranus Pluto Distance 0
-1433.5 days x Jupiter velocity daily 1.1318 mkm =1622.4 mkm Uranus Neptune Distance 0
-1433.5 days x Saturn velocity daily 0.838 mkm =1201 mkm Mars Saturn Distance 0.3%
-1433.5 days x Uranus velocity daily 0.5875 mkm =842 mkm
-1433.5 days x Neptune velocity daily 0.4665 mkm =670 mkm Venus Jupiter Distance 0
-1433.5 days x Pluto velocity daily 0.406 mkm =582 mkm Mercury Earth distance*2Π 1%
- Discussion
In the previous table we use 1433.5 days (we know that Saturn orbital distance =1433.5
mkm)… the table simply uses the value of distance as time value – and during this period
all solar planets (except Uranus) produces a real distances.. I can't consider that's happened
by pure coincidences but I consider that's happened as a part of the solar group geometrical
structure – and that means- the value which we see as a distance value can work in another
place (or another frame) as a time value… this idea we have discussed deeply in my
previous paper …. The Time Definition http://vixra.org/abs/1805.0523
So
The Unit Definition Is Found Based On The Observer Situation
That's why the 2 values can be equal ….!

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2-3 Saturn Orbital Inclination And Axial Tilt
2-3-1 Saturn Axial Tilt
In my previous paper I have claimed that
There Are Relativistic Effects In The Solar Group
And I have claimed that, the rate 1.0725 is found by lorentz length contraction effect
So, based on the previous hypothesis let's try to understand the previous equation …
28.3 degrees (Neptune axial tilt) is the main value which is contracted by lorentz
length contraction effect (by the 1.0725) to produce 26.7 deg (Saturn axial tilt) which
also is contracted again to produce 25.2 deg. (Mars axial tilt) and then contracted
again to produce 23.4 deg. (Earth axial tilt) so these 4 values are equal (or in fact
there are only one value) but the difference is found by relativistic effects
2-3-2 Saturn orbital inclination =2.5 degrees
The previous data shows clearly the strong relationship between Saturn and Venus
Now, we know that Venus axial tilt = 177.4 degrees….
Venus axial tilt 177.4 degrees + Saturn orbital inclination 2.5 degrees = 179.9 degrees
The solar group depends on this value 179.9 degrees to perform the planets motions
general harmony…. This claim needs to be clear as possible
Let's see the following data…
- 179.9 x 7 (Mercury orbital inclination = 7 degrees) = 1259.3 degrees
- 1259 x 0.406 mkm daily (Pluto velocity) =511.1 mkm (511.1 degrees = solar
planets axailt tilts total) (please remember 1 degree = 1 mkm because mercury
orbital circumference =360 mkm =360 degrees)
Please Note/
The Value 0.406 mkm/day is a very important value we have discussed hardly in
myprevious paper
The Solar Day Production http://vixra.org/abs/1812.0426
and also
Earth Circumference http://vixra.org/abs/1812.0434
Let's suppose that, the claim is correct, the rate (2π) is found to connect Pluto….
If Pluto and Mars have immigrated together why and how that can be possible that
the rate (2π) connects Pluto only without Mars?
0725.1
tiltaxailSatrun26.7
tiltaxailNeptune28.3
tiltaxailMars25.2
tiltaxailSatrun26.7
tiltaxailEarth23.4
tiltaxailMars25.2
===

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2-4 Mars Motion
Let's try to answer the previous question ….Shortly
Mars Exists Because he Receives his Required Energy From The Moon Orbit
Let's summarize that in following
- The Rate (2π) connects Mars with Saturn because Mars orbital circumference =
Saturn orbital distance= 1433.5 mkm … that means the same rate (2π) connects
Mars with Saturn as similar as Pluto…
Note Please
- 2 Saturn diameters x 5040 = 1206 mkm (Mars Saturn Distance)
Remember
- Mercury needs 5040 seconds to make his day = 176 solar days but mercury
moves during 5040 seconds a distance = 2 Saturn diameters (where in this
same period Mars moves a distance = 1 Saturn diameter).
Does (2π) effects on Mars in more ways?
- 6792 km (Mars Diameter) x (2π) = 42693 km (the distance between perigee and
apogee Earth moon orbit = 43000 km) and that connects Mars with the moon by
more connections..
The question is
Why Mars takes his energy from the Moon orbit?
Let's summarize the whole story in following:
- The solar group energy original is Jupiter energy – Jupiter sent this energy in light
beams form toward Pluto – where Neptune reflected this energy toward the inner
planets in 2 trajectories with equal energy
- 1st
Trajectory is sent to Mercury alone
- 2nd
Trajectory is sent to Earth and Venus (both together work to create the moon orbit
with effect of Uranus through Saturn cooperation)
- So No Energy is sent to Mars… Basically because he immigrated from his original
position at distance 84 mkm from the sun to his new point at distance 227.9mkm
from the sun… for that reason Mars has no share of Energy sent to Earth and
Venus… that's why Mars lives through The Moon orbit help- as we should prove
with Pluto and Neptune velocities discussion …..
Let's do that immediately…

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3-Neptune and Pluto Velocities
3-1 Pluto and Neptune velocities
3-2 Pluto Venus relationship
3-3 Mercury Jupiter Distance
3-1 Pluto and Neptune Velocities
I- Data
1- Neptune Velocity Daily = (1 / Mars Velocity Daily)
0.4665 mkm daily = 1/2.082 mkm daily
2- Pluto Velocity Daily = (1 / The Moon Velocity Daily)
0.406 mkm daily = 1/2.41 mkm daily
II- Discussion
- I wish we see that, the previous equations deal only with the 2 immigrants planets
only… that tells us there's something common between them (where the current
theory will find no relationship between Pluto and Mars because epf the great
distance between both)
Why the moon velocity = 2.41 mkm daily? The answer is in my previous paper
Does Mars Fit his Position Is The Solar Group? Why Not?!
but here we need to understand what's the geometrical benefit which is performed form the
previous equalities….
- Mars Velocity Daily x Neptune Velocity Daily = 1 million km 2
- This 1 million km2
we know perfectly….let's remember it in following
(2nd
Rule) Moon Orbital Circumference at Rn= (1/Rn+1)
I-Data
km)million(InRRadiusOrbitalMoon
1
km)millionIn(RatnceCircumfereOrbitalMoon
n
n =
- R1 = 363000 km (Perigee Radius) = 0.363 mkm Circumference= 2.281 mkm
- R2 = 377000 km (Total Solar Radius) = 0.377 mkm Circumference= 2.41 mkm
- R3 = 384000 km (Moon Orbital Radius) = 0.384 mkm Circumference= 2.58 mkm
- R4 = 406000 km (Apogee Radius) = 0.406 mkm Circumference= 2.754 mkm
From the previous data we can conclude that, the rule is true
(1/0.363 mkm) (Earth Moon distance at Perigee point) =2.754 mkm
(1/0.377 mkm) (Earth Moon distance at solar eclipse point) =2.63 mkm
(1/0.384 mkm) (Earth Moon distance at average point) =2.58 mkm
(1/0.406 mkm) (Earth Moon distance at apogee point) =2.41 mkm
II- Discussion
The previous data tells us that, the rule is performed correctly…
Specially the values 0.384 mkm and 0.406 mkm which show the rule perfectly….

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(1/0.384 mkm) =2.58 mkm = 0.406 mkm x 2π
(1/0.406 mkm) =2.41 mkm = 0.384 mkm x 2π
The other values are working also in the moon orbit but we need to extend our
discussion to see that in better vision….we should do that in next points…
But here we have only one question ….which is:
Why moon orbital circumference multiplies with moon orbital radius = 1mkm2
?
Because
1million km2
is the defined energy from which the moon orbital different radiuses are
created.. it's similar to Neptune orbital distance… let's remember it here…
Neptune Orbital Distance = 4495.1 mkm =
= 50.3mkm (Mercury Venues distance) x 91.9 mkm (Mercury Earth distance)
=108.2 mkm (Venus orbital distance) x 41.4mkm (Venus Earth distance)
= 57.9 mkm (Mercury orbital distance) x 78.3 mkm (Earth Mars Distance)
We have noticed that before and asked why any 2 inner distances multiplies produce
the same value (Neptune orbital distance 4495.1mkm)?
The answer was because
i. The distance is Energy
ii. Neptune orbital distance is the energy source from which the inner planets
created their orbital and internal distances…
For more details please review
Solar Group Geometrical Structure
The question is the same….
Why multiplication of the moon orbital circumference with the moon orbital radius =
1million km2
?
Because this 1 million km2
is the source of Energy from which
the moon orbital different radiuses are created..
In which direction this 1 mkm2
is found?
xyz coordinates may help us to answer this question…the moon
orbital radius is perpendicular on the moon orbital circumference tangent.. so let's
suppose the radius is x and circumference tangent is y so… x y = 1 mkm ….why?
Because it's this "Z axis"
That means 1 million km2
is perpendicular on the xy plain….what does that mean?
The moon orbit source of Energy is perpendicular on the moon orbit plain? Why?
Because this is the sent energy from Uranus to the moon by which the moon built his
orbit and does his motion… Uranus is perpendicular on the moon orbit that's why the
source of Energy is perpendicular on the moon orbit…
Let's remember this idea here..

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Light (with c velocity) travels from Uranus to Jupiter in 6939.75 seconds, this motion
produces the moon required Energy to rotates Metonic Cycle, so the energy is sent
from Uranus to Jupiter to the moon orbit (Perpendicular on the orbit plain) to acause
the moon motion based on the light motion but with different rate of time… so 1
seond in light motion will be 1 day in the moon motion which produces Metonic
Cycle 6939.75 days…
So Metonic Cycle is done because the moon orbit is built to perofm it, that'w why the
moon orbit regresses 19 degrees yearly.
The Conclusion:
The Moon Orbital Diameter =1 mkm works In 3 Directions As xyz Coordinates..
Note please: from long time I have suggested that, the moon orbital diameter =1 mkm
and not = 0.812 mkm …. This conclusion I have reach from the following equation:
108.2mkm (Venus orbital distance) x 0.384mkm (Moon orbital distance) = 41.4mkm2
41.4mkm = Venus Earth distance, but 41.4 mkm2
is an Area? How to solve that?
If the moon orbital diameter = 1 million km, in this case I can claim that Venus Earth
distance is 41.4 mkm in length and 1 million km breadth which makes it an area
Let's Return To Our Question
Why Mars Velocity Daily x Neptune Velocity Daily= 1mkm2
Because Neptune Energy is sent to Mars according through this vertical 1 million km2
The Pluto energy also is sent by this same method… which tells us about the great
importance of Pluto- Earth relationship… because from this relationship Pluto gets his
required energy to still in the solar group (spite of his very far position from the sun)
Please I recommend the reader to read this paper, it helps perfectly to see much better
The Moon Orbit Analysis
or
https://www.academia.edu/37856075/The_Moon_Orbit_Analysis

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3-2 Pluto Venus Relationship
I- Data
I. Pluto orbital inclination =17.2 degrees and the inner solar planets orbital inclinations
total = 17.4 degrees (99%)
II. (Venus diameter / Pluto diameter) = (Pluto orbital inclination / Venus orbital
inclination) = 5.1 (the moon orbital inclination = 5.1 degrees)
III. Venus Diameter x 1092
= 144 mkm = Mars Displacement = Pluto diameter x Saturn
radius
Note Please (Planet diameter x 1092
= the planet orbital distance is the rule which we have
discussed before hardly.. Please review …
Solar Planet Diameter Creation Rule
That tells us, Venus performs a specific role in Mars immigration effects treatment, and that
explains strongly the relationship between Venus and Saturn…
II- Discussion
I wish to provide all data to help the picture to be as clear as possible…!
But how can I do that?… for example
- Uranus Pluto Distance = Neptune Diameter x Saturn Radius
- Neptune orbital distance = Saturn Circumference x Venus diameter = Saturn
orbital distance x π
I wish we see clearly… there are many data supports the same claim…. That Saturn,
Neptune and Venus try to connect Pluto with the solar group…
Pluto main connection is with Earth – and this connection is found through the moon orbit
which is created by Saturn cooperation… that explains our old question ..
Why Saturn circumference = Earth Moon distance at the total solar eclipse
More Important Data and Argument
6585.39 degrees = 23.65 degrees x 278.4 degrees (1st
Point)
= 28.3 degrees x 232.7 degrees (2nd
point)
Let's explain the previous numbers…
6585.36 days = Saros Cycle and if 1 day = 1 degree the number will be 6585.39 degrees (1
day = 1 degrees because the moon orbit regresses yearly 19 degrees which regresses the
calendar with 19 days)
23.65 degrees = outer planets orbital inclinations total
28.3 degrees = Neptune axial tilt
232.7 degrees = Inner Planets Axial Tilts Total
278.4 degrees = Outer Planets Axial Tilts Total
I wish for all of us that we deal With One Machine …. Simply the vision which deals with
each planet as independent unit is a wring vision clearly and strongly…. The data tells with
very load voice… we are one team … one body … one machine … no one of us is
independent neither in origin nor in motion

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3-3 Mercury Jupiter Distance
I- Data
(1)
- Mercury Jupiter distance = 720.7 mkm
- Mercury orbital Circumference = 360 mkm (Mercury orbital period =88 days)
But
- Mercury Day = 2 Mercury Orbital Periods Approximately (176 days)
- i.e. Mercury moves during his day period a distance = 720.7 mkm
- Remember Mercury day needs 5040 seconds to be 176 solar days
(2)
- Jupiter Diameter 142984 km x 5040 = 720.7 mkm (Mercury Jupiter distance)
- (Remember 2 Saturn diameters x 5040 = 1206 mkm (Mars Saturn distance)
(3)
- Mercury diameter 4897 km x 1 million km= 4897 mkm (Jupiter orbital
circumference)
(4)
4900 mkm (Jupiter Orbital Circumference)
= The Sun Diameter x The Moon Diameter
= Jupiter Circumference x The Moon Circumference
= Mercury diameter x Jupiter diameter x Mercury Orbital Inclination
Let's write these relationships in more clear form
1 million km= Jupiter diameter 142984 km x Mercury orbital inclination 7deg.
=(Jupiter Orbital Circumference 4900 mkm/ Mercury diameter 4900km)
Also 1/7 = θ = 1/(Mercury orbital inclination) is the angle in the sun defined by Sun,
Earth and moon positions….
θ
The 2 near circles are Earth and Moon where the far one is the sun, angle θ= 0.142984
It's hard to explain all that, let's see more data about this angle
II- Discussion
I wish I did my task suitably and explained somehow that the solar group is not at any
cases separated planets from each other… the solar group is one body and one
machine and one geometrical structure where each planet is a gear in this machine
and a member in this body and a part of the same geometrical structure… a new
vision toward the solar group we need to adopt to understand and see much better
how the solar group is created and works
DistanceMoon
Distance
sin
Earth
OrbitalEarth
=θ

I do this research
2nd
15
Gerges Francis Twadrous Curriculum Vitae
or
https://www.academia.edu/38285624/Gerges_Francis_Tawdrous_Curriculum_Vitae_.doc
or
https://www.slideshare.net/Gergesfrancis/gerges-francis-tawdrous-curriculum-vitae
Author Other Papers
No Random Process Causes The Solar Group Creation (No Big Bang)
Does Mars Fit his Position Is The Solar Group? Why Not?!
There Are Relativistic Effects In The Solar Group
The Sun Gravity Concept is Unreal (Proves)
Does Earth Velocity Causes The Eclipse Phenomena? (T.S. Eclipse III)
Why We See the Sun Disc = the Moon Disc? (T.S. Eclipse II)
Total Solar Eclipse Analysis (Part I)
Why The Solar Planet Motion Trajectory is An Ellipse?(revised)
Solar Planet Data Geometrical Concepts disproves the Current Theory
Life Is Found On Earth Only (Claim)
Is the 2737 Phenomenon a Real One?
The Moon Orbit Triangle
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Twitter https://twitter.com/TawdrousF
Facebook https://www.facebook.com/gergis.tawadrous
Academia https://rudn.academia.edu/GergesTawadrous
All my papers http://vixra.org/author/gerges_francis_tawdrousBest

How the Solar Group is Created? (Discussion No. 1)

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