SlideShare a Scribd company logo
How To Do KS2 Maths SATs
Type Questions
(Paper A – Calculator Not
Allowed)
Division 1: Finding a
Missing Number Using
Division
For more maths help & free games related to
this, visit: www.makemymathsbetter.com
In a SAT paper you might be asked to find a missing number
in a sum by using division.
In a SAT paper you might be asked to find a missing number
in a sum by using division.
For example: write the missing number to make this
calculation correct.

12 x

= 1452
In a SAT paper you might be asked to find a missing number
in a sum by using division.
For example: write the missing number to make this
calculation correct.

12 x

= 1452

To find the answer, you need to divide the number on the right
hand side of the equation
In a SAT paper you might be asked to find a missing number
in a sum by using division.
For example: write the missing number to make this
calculation correct.

12 x

= 1452

To find the answer, you need to divide the number on the right
hand side of the equation (1452)
In a SAT paper you might be asked to find a missing number
in a sum by using division.
For example: write the missing number to make this
calculation correct.

12 x

= 1452

To find the answer, you need to divide the number on the right
hand side of the equation (1452) by the number on the left
hand side
In a SAT paper you might be asked to find a missing number
in a sum by using division.
For example: write the missing number to make this
calculation correct.

12 x

= 1452

To find the answer, you need to divide the number on the right
hand side of the equation (1452) by the number on the left
hand side (12).
In a SAT paper you might be asked to find a missing number
in a sum by using division.
For example: write the missing number to make this
calculation correct.

12 x

= 1452

To find the answer, you need to divide the number on the right
hand side of the equation (1452) by the number on the left
hand side (12).
1452 divided by 12 = 121
In a SAT paper you might be asked to find a missing number
in a sum by using division.
For example: write the missing number to make this
calculation correct.

12 x

= 1452

To find the answer, you need to divide the number on the right
hand side of the equation (1452) by the number on the left
hand side (12).
1452 divided by 12 = 121

Therefore:

12 x 121 = 1452
A similar example is: write in the missing number.

4x

= 200

(2007 Paper A)

Again, to find the answer, you need to divide the number on
the right hand side of the equation (200) by the number on
the left hand side (4).
200 divided by 4 = 50

Therefore:

4x

50

= 200
A similar example is: write in the missing number.

4x

= 240

Again, to find the answer, you need to divide the number on
the right hand side of the equation (200) by the number on
the left hand side (4).
200 divided by 4 = 50

Therefore:

4x

50

= 200
A similar example is: write in the missing number.

4x

= 240

Again, to find the answer, you need to divide the number on
the right hand side of the equation (200) by the number on
the left hand side (4).
200 divided by 4 = 50

Therefore:

4x

50

= 200
A similar example is: write in the missing number.

4x

= 240

Again, to find the answer, you need to divide the number on
the right hand side of the equation (240) by the number on
the left hand side (4).
200 divided by 4 = 50

Therefore:

4x

50

= 200
A similar example is: write in the missing number.

4x

= 240

Again, to find the answer, you need to divide the number on
the right hand side of the equation (240) by the number on
the left hand side (4).
200 divided by 4 = 50

Therefore:

4x

50

= 200
A similar example is: write in the missing number.

4x

= 240

Again, to find the answer, you need to divide the number on
the right hand side of the equation (240) by the number on
the left hand side (4).
200 divided by 4 = 50

Therefore:

4x

50

= 200
A similar example is: write in the missing number.

4x

= 240

Again, to find the answer, you need to divide the number on
the right hand side of the equation (240) by the number on
the left hand side (4).
240 divided by 4 = 50

Therefore:

4x

50

= 200
A similar example is: write in the missing number.

4x

= 240

Again, to find the answer, you need to divide the number on
the right hand side of the equation (240) by the number on
the left hand side (4).
240 divided by 4 = 60

Therefore:

4x

50

= 200
A similar example is: write in the missing number.

4x

= 240

Again, to find the answer, you need to divide the number on
the right hand side of the equation (240) by the number on
the left hand side (4).
240 divided by 4 = 60

Therefore:

4x

60

= 240
Now try some by yourself. Calculate the missing numbers in
these equations. Click to see if you are correct:
Now try some by yourself. Calculate the missing numbers in
these equations. Click to see if you are correct:

a)

6x

= 420
Now try some by yourself. Calculate the missing numbers in
these equations. Click to see if you are correct:

a)

6 x 70 = 420
70
Now try some by yourself. Calculate the missing numbers in
these equations. Click to see if you are correct:

a)

6 x 70 = 420
70

b)

x 7 = 630
Now try some by yourself. Calculate the missing numbers in
these equations. Click to see if you are correct:

a)

6 x 70 = 420
70

b)

90 x 7 = 630
70
Now try some by yourself. Calculate the missing numbers in
these equations. Click to see if you are correct:

a)

6 x 70 = 420
70

b)

90 x 7 = 630
70

c)

9x

= 720
Now try some by yourself. Calculate the missing numbers in
these equations. Click to see if you are correct:

a)

6 x 70 = 420
70

b)

90 x 7 = 630
70

c)

9 x 80 = 720
70
Now try some by yourself. Calculate the missing numbers in
these equations. Click to see if you are correct:

a)

6 x 70 = 420
70

b)

90 x 7 = 630
70

c)

9 x 80 = 720
70

d)

x 12 = 1452
Now try some by yourself. Calculate the missing numbers in
these equations. Click to see if you are correct:

a)

6 x 70 = 420
70

b)

90 x 7 = 630
70

c)

9 x 80 = 720
70

d)

1217 x 12 = 1452
0
Now try some by yourself. Calculate the missing numbers in
these equations. Click to see if you are correct:

a)

6 x 70 = 420
70

b)

90 x 7 = 630
70

c)

9 x 80 = 720
70

d)

1217 x 12 = 1452
0

e)

x 17 = 7752
Now try some by yourself. Calculate the missing numbers in
these equations. Click to see if you are correct:

a)

6 x 70 = 420
70

b)

90 x 7 = 630
70

c)

9 x 80 = 720
70

d)

1217 x 12 = 1452
0

e)

4567 x 17 = 7752
0
Now try some by yourself. Calculate the missing numbers in
these equations. Click to see if you are correct:

a)

6 x 70 = 420
70

b)

90 x 7 = 630
70

c)

9 x 80 = 720
70

d)

1217 x 12 = 1452
0

e)

4567 x 17 = 7752
0

f)

26 x

= 19578
Now try some by yourself. Calculate the missing numbers in
these equations. Click to see if you are correct:

a)

6 x 70 = 420
70

b)

90 x 7 = 630
70

c)

9 x 80 = 720
70

d)

1217 x 12 = 1452
0

e)

4567 x 17 = 7752
0

f)

26 x 7537 = 19578
0
That’s it for now......
For more help with your maths, try
my book:
mastering multiplication tables
on amazon.com

5

More Related Content

PPT
PDF
2nd grade mastery_assessments-small
PPT
Top Drawer Teachers: Splitting arrays into known parts
DOCX
0010 chapter iii
PDF
CPSC 125 Ch 3 Sec 4 6
ODP
Permutations and combinations
PPTX
2 addition and subtraction of signed numbers 125s
2nd grade mastery_assessments-small
Top Drawer Teachers: Splitting arrays into known parts
0010 chapter iii
CPSC 125 Ch 3 Sec 4 6
Permutations and combinations
2 addition and subtraction of signed numbers 125s

What's hot (18)

PDF
QL-8Z65MgMR
PPT
Variables On Both Sides
PPTX
Fundamental counting principle powerpoint
PPTX
2.4 prime numbers and factors w
PDF
U11007410 statistics 111
PPT
Top Drawer Teachers: Splitting Arrays into Known Parts
PDF
Pre-Cal 40S Slides April 18, 2007
PDF
Union and intersection of events (math 10)
PPTX
Kungfu math p4 slide5 (multiples)
PPTX
Fundamental Counting Principle
PPTX
Factorials permutations and_combinations_using_excel
PDF
Counting techniques
PPT
Countingprinciple
PPT
Aii12 permutations combinations
PPTX
Imaginary numbers
PPTX
Imaginary numbers
PPT
Probabilty1
PPTX
CABT Math 8 - Fundamental Principle of Counting
QL-8Z65MgMR
Variables On Both Sides
Fundamental counting principle powerpoint
2.4 prime numbers and factors w
U11007410 statistics 111
Top Drawer Teachers: Splitting Arrays into Known Parts
Pre-Cal 40S Slides April 18, 2007
Union and intersection of events (math 10)
Kungfu math p4 slide5 (multiples)
Fundamental Counting Principle
Factorials permutations and_combinations_using_excel
Counting techniques
Countingprinciple
Aii12 permutations combinations
Imaginary numbers
Imaginary numbers
Probabilty1
CABT Math 8 - Fundamental Principle of Counting
Ad

Similar to How To Do KS2 Maths SATs Paper A Division Questions (Part 1) (20)

PPTX
Multiples and factors,what you need to learn
PPTX
Factorial Notations.pptx
DOCX
Yahooanswr how to gain points
PPT
Percentages
PPT
Percentages
PPT
Percentages
PPT
Chapter2 Jeopardy R
PPT
G7 Math Q1-Week 7-Roots-and-Irrational-Numbers.ppt
PPTX
Multiply-and-Disvide-Integers---COT.pptx
PDF
Gcse revision cards checked 190415
DOCX
Yahooanswr how
PPTX
Preparing for KS3- Probability, Formulae and Equations, Ratio and Proportion,...
PPT
Hierarchical graphic organizer
PPT
Hierarchical graphic organizer
DOC
Kahn Help on ACT Math 1
DOC
Kahn Help for ACT Math III
PPTX
November 6th, 2014
PPTX
Additive inverse zero pairs absolute value
PDF
Math for 800 03 real numbers
Multiples and factors,what you need to learn
Factorial Notations.pptx
Yahooanswr how to gain points
Percentages
Percentages
Percentages
Chapter2 Jeopardy R
G7 Math Q1-Week 7-Roots-and-Irrational-Numbers.ppt
Multiply-and-Disvide-Integers---COT.pptx
Gcse revision cards checked 190415
Yahooanswr how
Preparing for KS3- Probability, Formulae and Equations, Ratio and Proportion,...
Hierarchical graphic organizer
Hierarchical graphic organizer
Kahn Help on ACT Math 1
Kahn Help for ACT Math III
November 6th, 2014
Additive inverse zero pairs absolute value
Math for 800 03 real numbers
Ad

More from Chris James (20)

PPTX
How To Do KS2 Maths SATs A Subtraction Questions (Part 2)
PPT
How To Do KS2 Maths SATs A Subtraction Questions
PPTX
How To Do KS2 Maths A SATs Addition Questions (Part 1)
PPT
How To Do KS2 Mental Maths Paper SATs Negative Number Questions
PPT
How To Do KS2 Maths A SATs Negative Number Questions
PPT
Multiplying 3 Digit Numbers by 1 Digit Numbers Using The Grid Method
PPT
How To Do KS2 Maths B SATs Money Questions (Part 1)
PPT
How To Do KS2 Maths SATs Paper B Fractions Questions (Part 2)
PPTX
How To Do KS2 Maths SATs Paper B Fractions Questions (Part 3)
PPT
How To Do KS2 Maths SATs Paper B Fractions Questions (Part 1)
PPT
How To Do KS2 Maths SATs Paper B Percentage Questions (Part 2)
PPT
How To Do KS2 Maths SATs Paper B Percentage Questions (Part 1)
PPT
How To Do KS2 Maths SATs Paper A Percentage Questions (Part 1)
PPTX
How To Do KS2 Maths SATs Paper A Multiplication Questions (Part 2)
PPTX
How To Do KS2 Maths SATs Paper A Multiplication Questions (Part 1)
PPT
How To Do KS2 Maths SATs Paper A Division Questions (Part 2)
PPTX
Adding Decimals
PPTX
Multiplying Decimals (3 Digit by 1 Digit)
PPTX
Short Division Of Decimals
PPTX
Addition Using The Column Method
How To Do KS2 Maths SATs A Subtraction Questions (Part 2)
How To Do KS2 Maths SATs A Subtraction Questions
How To Do KS2 Maths A SATs Addition Questions (Part 1)
How To Do KS2 Mental Maths Paper SATs Negative Number Questions
How To Do KS2 Maths A SATs Negative Number Questions
Multiplying 3 Digit Numbers by 1 Digit Numbers Using The Grid Method
How To Do KS2 Maths B SATs Money Questions (Part 1)
How To Do KS2 Maths SATs Paper B Fractions Questions (Part 2)
How To Do KS2 Maths SATs Paper B Fractions Questions (Part 3)
How To Do KS2 Maths SATs Paper B Fractions Questions (Part 1)
How To Do KS2 Maths SATs Paper B Percentage Questions (Part 2)
How To Do KS2 Maths SATs Paper B Percentage Questions (Part 1)
How To Do KS2 Maths SATs Paper A Percentage Questions (Part 1)
How To Do KS2 Maths SATs Paper A Multiplication Questions (Part 2)
How To Do KS2 Maths SATs Paper A Multiplication Questions (Part 1)
How To Do KS2 Maths SATs Paper A Division Questions (Part 2)
Adding Decimals
Multiplying Decimals (3 Digit by 1 Digit)
Short Division Of Decimals
Addition Using The Column Method

Recently uploaded (20)

PDF
Mobile App Security Testing_ A Comprehensive Guide.pdf
PDF
Building Integrated photovoltaic BIPV_UPV.pdf
PDF
Reach Out and Touch Someone: Haptics and Empathic Computing
PDF
7 ChatGPT Prompts to Help You Define Your Ideal Customer Profile.pdf
PDF
Diabetes mellitus diagnosis method based random forest with bat algorithm
PPTX
Spectroscopy.pptx food analysis technology
PPTX
sap open course for s4hana steps from ECC to s4
PDF
Machine learning based COVID-19 study performance prediction
PDF
Unlocking AI with Model Context Protocol (MCP)
PDF
Agricultural_Statistics_at_a_Glance_2022_0.pdf
PDF
Peak of Data & AI Encore- AI for Metadata and Smarter Workflows
PDF
Approach and Philosophy of On baking technology
PDF
Architecting across the Boundaries of two Complex Domains - Healthcare & Tech...
PDF
Chapter 3 Spatial Domain Image Processing.pdf
PPTX
Digital-Transformation-Roadmap-for-Companies.pptx
PDF
Build a system with the filesystem maintained by OSTree @ COSCUP 2025
PDF
Review of recent advances in non-invasive hemoglobin estimation
PPTX
VMware vSphere Foundation How to Sell Presentation-Ver1.4-2-14-2024.pptx
PDF
Encapsulation theory and applications.pdf
DOCX
The AUB Centre for AI in Media Proposal.docx
Mobile App Security Testing_ A Comprehensive Guide.pdf
Building Integrated photovoltaic BIPV_UPV.pdf
Reach Out and Touch Someone: Haptics and Empathic Computing
7 ChatGPT Prompts to Help You Define Your Ideal Customer Profile.pdf
Diabetes mellitus diagnosis method based random forest with bat algorithm
Spectroscopy.pptx food analysis technology
sap open course for s4hana steps from ECC to s4
Machine learning based COVID-19 study performance prediction
Unlocking AI with Model Context Protocol (MCP)
Agricultural_Statistics_at_a_Glance_2022_0.pdf
Peak of Data & AI Encore- AI for Metadata and Smarter Workflows
Approach and Philosophy of On baking technology
Architecting across the Boundaries of two Complex Domains - Healthcare & Tech...
Chapter 3 Spatial Domain Image Processing.pdf
Digital-Transformation-Roadmap-for-Companies.pptx
Build a system with the filesystem maintained by OSTree @ COSCUP 2025
Review of recent advances in non-invasive hemoglobin estimation
VMware vSphere Foundation How to Sell Presentation-Ver1.4-2-14-2024.pptx
Encapsulation theory and applications.pdf
The AUB Centre for AI in Media Proposal.docx

How To Do KS2 Maths SATs Paper A Division Questions (Part 1)

  • 1. How To Do KS2 Maths SATs Type Questions (Paper A – Calculator Not Allowed) Division 1: Finding a Missing Number Using Division For more maths help & free games related to this, visit: www.makemymathsbetter.com
  • 2. In a SAT paper you might be asked to find a missing number in a sum by using division.
  • 3. In a SAT paper you might be asked to find a missing number in a sum by using division. For example: write the missing number to make this calculation correct. 12 x = 1452
  • 4. In a SAT paper you might be asked to find a missing number in a sum by using division. For example: write the missing number to make this calculation correct. 12 x = 1452 To find the answer, you need to divide the number on the right hand side of the equation
  • 5. In a SAT paper you might be asked to find a missing number in a sum by using division. For example: write the missing number to make this calculation correct. 12 x = 1452 To find the answer, you need to divide the number on the right hand side of the equation (1452)
  • 6. In a SAT paper you might be asked to find a missing number in a sum by using division. For example: write the missing number to make this calculation correct. 12 x = 1452 To find the answer, you need to divide the number on the right hand side of the equation (1452) by the number on the left hand side
  • 7. In a SAT paper you might be asked to find a missing number in a sum by using division. For example: write the missing number to make this calculation correct. 12 x = 1452 To find the answer, you need to divide the number on the right hand side of the equation (1452) by the number on the left hand side (12).
  • 8. In a SAT paper you might be asked to find a missing number in a sum by using division. For example: write the missing number to make this calculation correct. 12 x = 1452 To find the answer, you need to divide the number on the right hand side of the equation (1452) by the number on the left hand side (12). 1452 divided by 12 = 121
  • 9. In a SAT paper you might be asked to find a missing number in a sum by using division. For example: write the missing number to make this calculation correct. 12 x = 1452 To find the answer, you need to divide the number on the right hand side of the equation (1452) by the number on the left hand side (12). 1452 divided by 12 = 121 Therefore: 12 x 121 = 1452
  • 10. A similar example is: write in the missing number. 4x = 200 (2007 Paper A) Again, to find the answer, you need to divide the number on the right hand side of the equation (200) by the number on the left hand side (4). 200 divided by 4 = 50 Therefore: 4x 50 = 200
  • 11. A similar example is: write in the missing number. 4x = 240 Again, to find the answer, you need to divide the number on the right hand side of the equation (200) by the number on the left hand side (4). 200 divided by 4 = 50 Therefore: 4x 50 = 200
  • 12. A similar example is: write in the missing number. 4x = 240 Again, to find the answer, you need to divide the number on the right hand side of the equation (200) by the number on the left hand side (4). 200 divided by 4 = 50 Therefore: 4x 50 = 200
  • 13. A similar example is: write in the missing number. 4x = 240 Again, to find the answer, you need to divide the number on the right hand side of the equation (240) by the number on the left hand side (4). 200 divided by 4 = 50 Therefore: 4x 50 = 200
  • 14. A similar example is: write in the missing number. 4x = 240 Again, to find the answer, you need to divide the number on the right hand side of the equation (240) by the number on the left hand side (4). 200 divided by 4 = 50 Therefore: 4x 50 = 200
  • 15. A similar example is: write in the missing number. 4x = 240 Again, to find the answer, you need to divide the number on the right hand side of the equation (240) by the number on the left hand side (4). 200 divided by 4 = 50 Therefore: 4x 50 = 200
  • 16. A similar example is: write in the missing number. 4x = 240 Again, to find the answer, you need to divide the number on the right hand side of the equation (240) by the number on the left hand side (4). 240 divided by 4 = 50 Therefore: 4x 50 = 200
  • 17. A similar example is: write in the missing number. 4x = 240 Again, to find the answer, you need to divide the number on the right hand side of the equation (240) by the number on the left hand side (4). 240 divided by 4 = 60 Therefore: 4x 50 = 200
  • 18. A similar example is: write in the missing number. 4x = 240 Again, to find the answer, you need to divide the number on the right hand side of the equation (240) by the number on the left hand side (4). 240 divided by 4 = 60 Therefore: 4x 60 = 240
  • 19. Now try some by yourself. Calculate the missing numbers in these equations. Click to see if you are correct:
  • 20. Now try some by yourself. Calculate the missing numbers in these equations. Click to see if you are correct: a) 6x = 420
  • 21. Now try some by yourself. Calculate the missing numbers in these equations. Click to see if you are correct: a) 6 x 70 = 420 70
  • 22. Now try some by yourself. Calculate the missing numbers in these equations. Click to see if you are correct: a) 6 x 70 = 420 70 b) x 7 = 630
  • 23. Now try some by yourself. Calculate the missing numbers in these equations. Click to see if you are correct: a) 6 x 70 = 420 70 b) 90 x 7 = 630 70
  • 24. Now try some by yourself. Calculate the missing numbers in these equations. Click to see if you are correct: a) 6 x 70 = 420 70 b) 90 x 7 = 630 70 c) 9x = 720
  • 25. Now try some by yourself. Calculate the missing numbers in these equations. Click to see if you are correct: a) 6 x 70 = 420 70 b) 90 x 7 = 630 70 c) 9 x 80 = 720 70
  • 26. Now try some by yourself. Calculate the missing numbers in these equations. Click to see if you are correct: a) 6 x 70 = 420 70 b) 90 x 7 = 630 70 c) 9 x 80 = 720 70 d) x 12 = 1452
  • 27. Now try some by yourself. Calculate the missing numbers in these equations. Click to see if you are correct: a) 6 x 70 = 420 70 b) 90 x 7 = 630 70 c) 9 x 80 = 720 70 d) 1217 x 12 = 1452 0
  • 28. Now try some by yourself. Calculate the missing numbers in these equations. Click to see if you are correct: a) 6 x 70 = 420 70 b) 90 x 7 = 630 70 c) 9 x 80 = 720 70 d) 1217 x 12 = 1452 0 e) x 17 = 7752
  • 29. Now try some by yourself. Calculate the missing numbers in these equations. Click to see if you are correct: a) 6 x 70 = 420 70 b) 90 x 7 = 630 70 c) 9 x 80 = 720 70 d) 1217 x 12 = 1452 0 e) 4567 x 17 = 7752 0
  • 30. Now try some by yourself. Calculate the missing numbers in these equations. Click to see if you are correct: a) 6 x 70 = 420 70 b) 90 x 7 = 630 70 c) 9 x 80 = 720 70 d) 1217 x 12 = 1452 0 e) 4567 x 17 = 7752 0 f) 26 x = 19578
  • 31. Now try some by yourself. Calculate the missing numbers in these equations. Click to see if you are correct: a) 6 x 70 = 420 70 b) 90 x 7 = 630 70 c) 9 x 80 = 720 70 d) 1217 x 12 = 1452 0 e) 4567 x 17 = 7752 0 f) 26 x 7537 = 19578 0
  • 32. That’s it for now...... For more help with your maths, try my book: mastering multiplication tables on amazon.com 5