Here are the solutions to the word problems:
1. Since the radius bisects chord AB at midpoint Q, AQ and QB would each be 2 inches based on the definition of bisect.
2. Since the radius OA passes through chord BC at its midpoint D, radius OA must be perpendicular to chord BC based on the Bisected Chord Theorem.
3. If chord SB has an apothem of 2 inches and arc measure of 75°, and SB is congruent to CE, then the apothem of CE must also be 2 inches and the arc measure of CE must also be 75° based on the Congruent Chords Theorem.