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MAGNETIC EFFECT OF CURRENT - III
1. Cyclotron
2. Ampere’s Circuital Law
3. Magnetic Field due to a Straight Solenoid
4. Magnetic Field due to a Toroidal Solenoid
Created by C. Mani, Principal, K V No.1, AFS, Jalahalli West, Bangalore
N
S
D1 D2
+
W
B
Cyclotron:
D1, D2 – Dees N, S – Magnetic Pole Pieces W
– Window B - Magnetic Field
H F
Oscillator
D2
D1
Working: Imagining D1 is positive and D2 is negative, the + vely charged
particle kept at the centre and in the gap between the dees get accelerated
towards D2. Due to perpendicular magnetic field and according to Fleming’s
Left Hand Rule the charge gets deflected and describes semi-circular path.
When it is about to leave D2, D2 becomes + ve and D1 becomes – ve.
Therefore the particle is again accelerated into D1 where it continues to
describe the semi-circular path. The process continues till the charge
traverses through the whole space in the dees and finally it comes out with
very high speed through the window.
W
B
Theory:
The magnetic force experienced by the charge provides centripetal force
required to describe circular path.
mv2
/ r = qvB sin 90° (where m – mass of the charged particle,
q – charge, v – velocity on the path of
radius – r, B is magnetic field and 90° is the
angle b/n v and B)
v =
B q r
m
If t is the time taken by the charge to describe the semi-circular path
inside the dee, then
t =
π r
v
or t =
π m
B q
Time taken inside the dee depends only on
the magnetic field and m/q ratio and not on
the speed of the charge or the radius of the
path.
If T is the time period of the high frequency oscillator, then for resonance,
T = 2 t or T =
2πm
B q
If f is the frequency of the high frequency oscillator (Cyclotron Frequency),
then
f =
2πm
B q
Maximum Energy of the Particle:
Kinetic Energy of the charged particle is
K.E. = ½ m v2
= ½ m (
B q r
m
)2 = ½
B2
q2
r2
m
Maximum Kinetic Energy of the charged particle is when r = R (radius of the D’s).
= ½
B2
q2
R2
m
K.E. max
The expressions for Time period and Cyclotron frequency only when
m remains constant. (Other quantities are already constant.)
m =
m0
[1 – (v2
/ c2
)]½
If frequency is varied in synchronisation with the variation of mass of the
charged particle (by maintaining B as constant) to have resonance, then the
cyclotron is called synchro – cyclotron.
If magnetic field is varied in synchronisation with the variation of mass of
the charged particle (by maintaining f as constant) to have resonance, then
the cyclotron is called isochronous – cyclotron.
NOTE: Cyclotron can not be used for accelerating neutral particles. Electrons can
not be accelerated because they gain speed very quickly due to their lighter mass
and go out of phase with alternating e.m.f. and get lost within the dees.
But m varies with v according to
Einstein’s Relativistic Principle as per
Ampere’s Circuital Law:
The line integral B . dl for a closed curve is equal to μ0 times the net
current I threading through the area bounded by the curve.
∫
∫ B . dl = μ0 I
∫ B . dl = ∫ B . dl cos 0°
∫ B . dl = B= ∫ dl
= B (2π r) = ( μ0 I / 2π r) x 2π r
∫ B . dl = μ0 I
I
B
B
r
O
dl
I
Current is emerging
out and the magnetic
field is anticlockwise.
Proof:
Magnetic Field at the centre of a Straight Solenoid:
I I
xxxxx xx
P Q
RS
∫ B . dl = μ0 I0
(where I0 is the net current
threading through the solenoid)
∫ B . dl = ∫ B . dl +
PQ
∫ B . dl +
QR
∫ B . dl +
RS
∫ B . dl
SP
B
B . dl cos 0° +∫ ∫ B . dl cos 90° + ∫ 0 . dl cos 0° + ∫ B . dl cos 90°=
= B ∫ dl = B.a and μ0 I0 = μ0 n a I
(where n is no. of turns per unit length, a is the length of the path and
I is the current passing through the lead of the solenoid)
a
a
B = μ0 n I
Magnetic Field due to Toroidal Solenoid (Toroid):
I
dl
B
P
O Q
B = 0
B = 0
∫ B . dl = μ0 I0
B . dl cos 0°∫
= B ∫ dl = B (2π r)
r
And μ0 I0 = μ0 n (2π r) I
B = μ0 n I
∫ B . dl =
NOTE:
The magnetic field exists only in the
tubular area bound by the coil and it does
not exist in the area inside and outside the
toroid.
i.e. B is zero at O and Q and non-zero at P.
End of Magnetic Effect of Current !
B ≠ 0

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Magnetic Effects Of Current Class 12 Part-3

  • 1. MAGNETIC EFFECT OF CURRENT - III 1. Cyclotron 2. Ampere’s Circuital Law 3. Magnetic Field due to a Straight Solenoid 4. Magnetic Field due to a Toroidal Solenoid Created by C. Mani, Principal, K V No.1, AFS, Jalahalli West, Bangalore
  • 2. N S D1 D2 + W B Cyclotron: D1, D2 – Dees N, S – Magnetic Pole Pieces W – Window B - Magnetic Field H F Oscillator D2 D1 Working: Imagining D1 is positive and D2 is negative, the + vely charged particle kept at the centre and in the gap between the dees get accelerated towards D2. Due to perpendicular magnetic field and according to Fleming’s Left Hand Rule the charge gets deflected and describes semi-circular path. When it is about to leave D2, D2 becomes + ve and D1 becomes – ve. Therefore the particle is again accelerated into D1 where it continues to describe the semi-circular path. The process continues till the charge traverses through the whole space in the dees and finally it comes out with very high speed through the window. W B
  • 3. Theory: The magnetic force experienced by the charge provides centripetal force required to describe circular path. mv2 / r = qvB sin 90° (where m – mass of the charged particle, q – charge, v – velocity on the path of radius – r, B is magnetic field and 90° is the angle b/n v and B) v = B q r m If t is the time taken by the charge to describe the semi-circular path inside the dee, then t = π r v or t = π m B q Time taken inside the dee depends only on the magnetic field and m/q ratio and not on the speed of the charge or the radius of the path. If T is the time period of the high frequency oscillator, then for resonance, T = 2 t or T = 2πm B q If f is the frequency of the high frequency oscillator (Cyclotron Frequency), then f = 2πm B q
  • 4. Maximum Energy of the Particle: Kinetic Energy of the charged particle is K.E. = ½ m v2 = ½ m ( B q r m )2 = ½ B2 q2 r2 m Maximum Kinetic Energy of the charged particle is when r = R (radius of the D’s). = ½ B2 q2 R2 m K.E. max The expressions for Time period and Cyclotron frequency only when m remains constant. (Other quantities are already constant.) m = m0 [1 – (v2 / c2 )]½ If frequency is varied in synchronisation with the variation of mass of the charged particle (by maintaining B as constant) to have resonance, then the cyclotron is called synchro – cyclotron. If magnetic field is varied in synchronisation with the variation of mass of the charged particle (by maintaining f as constant) to have resonance, then the cyclotron is called isochronous – cyclotron. NOTE: Cyclotron can not be used for accelerating neutral particles. Electrons can not be accelerated because they gain speed very quickly due to their lighter mass and go out of phase with alternating e.m.f. and get lost within the dees. But m varies with v according to Einstein’s Relativistic Principle as per
  • 5. Ampere’s Circuital Law: The line integral B . dl for a closed curve is equal to μ0 times the net current I threading through the area bounded by the curve. ∫ ∫ B . dl = μ0 I ∫ B . dl = ∫ B . dl cos 0° ∫ B . dl = B= ∫ dl = B (2π r) = ( μ0 I / 2π r) x 2π r ∫ B . dl = μ0 I I B B r O dl I Current is emerging out and the magnetic field is anticlockwise. Proof:
  • 6. Magnetic Field at the centre of a Straight Solenoid: I I xxxxx xx P Q RS ∫ B . dl = μ0 I0 (where I0 is the net current threading through the solenoid) ∫ B . dl = ∫ B . dl + PQ ∫ B . dl + QR ∫ B . dl + RS ∫ B . dl SP B B . dl cos 0° +∫ ∫ B . dl cos 90° + ∫ 0 . dl cos 0° + ∫ B . dl cos 90°= = B ∫ dl = B.a and μ0 I0 = μ0 n a I (where n is no. of turns per unit length, a is the length of the path and I is the current passing through the lead of the solenoid) a a B = μ0 n I
  • 7. Magnetic Field due to Toroidal Solenoid (Toroid): I dl B P O Q B = 0 B = 0 ∫ B . dl = μ0 I0 B . dl cos 0°∫ = B ∫ dl = B (2π r) r And μ0 I0 = μ0 n (2π r) I B = μ0 n I ∫ B . dl = NOTE: The magnetic field exists only in the tubular area bound by the coil and it does not exist in the area inside and outside the toroid. i.e. B is zero at O and Q and non-zero at P. End of Magnetic Effect of Current ! B ≠ 0