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THE
PRESENTATIO
N BEGINS
Maths project surface area and volume_by_chirag_jain_ix_a_roll no 17
UMESH SIRUMESH SIR
Maths project surface area and volume_by_chirag_jain_ix_a_roll no 17
 INTRODUCTION
 CUBE
 CUBOID
 RIGHT CIRCULAR CYLINDER
 RIGHT CIRCULAR CONE
 SPHERE
 HEMISPHERE
 Have you ever wrapped a birthday gift?
If so, then you've covered the surface area
of a polyhedron with wrapping paper. 
 Have you ever poured a glass of milk?
If so, then you've filled the volume of a
glass with milk.
Not only this, but in day-to-day life, we
come across many activities which involve
the concept of surface areas and volume.
 Surface Area of an object refers to the total
area of all its surfaces.
 For example : The amount of paper
required to wrap a gift gives us an idea of
surface area of gift.
 Volume of a solid
object refers to the
amount of space it
occupies or contains.
 For example : The
amount of water a
swimming pool can
hold gives us an idea
of the volume of the
swimming pool.
Maths project surface area and volume_by_chirag_jain_ix_a_roll no 17
SURFACESURFACE
AREAAREAIf each edge of cube is a units, its
Total surface area = 6a2
sq. units
Area of the faces leaving the top
And the bottom ones is known as
Its L.S.A. (Lateral Surface Area).
L.S.A. of cube = 4a2
sq. units
VOLUMEVOLUME
 Volume of a
cube of edge
a units is a3
cubic units.
Maths project surface area and volume_by_chirag_jain_ix_a_roll no 17
TOTAL SURFACETOTAL SURFACE
AREAAREA Surface area of a
cuboid =
2 × lb Top and bottom
+ 2 × bh Front and back
+ 2 × lh Left and right side
= 2(lb + bh + lh)
h
l
b
LATERAL SURFACELATERAL SURFACE
AREAAREA
 L.S.A. of cuboid =
T.S.A. – Area of
top and base
= 2(lb + bh + lh)–
2(lb)
= 2 (bh + hl)
= 2 (l+b) × h
VOLUMEVOLUME
 Volume of a cuboid =
Length × Breadth × Height
Or
V = l × b × h
Where, V = volume
l = length, b = breadth
h = height
Maths project surface area and volume_by_chirag_jain_ix_a_roll no 17
WHAT IS A RIGHTWHAT IS A RIGHT
CIRCULARCIRCULAR
CYLINDER ?CYLINDER ? A cylinder is a
right circular
cylinder if :
 Its base is a circle
and
 Radius of the
base is
perpendicular to
its height.
SURFACE AREASURFACE AREA
 C.S.A. of cylinder
= Area of
rectangular sheet
= 2πrh
o T.S.A. of cylinder
= C.S.A. + Lid area
+ Base area
= 2πrh + πr2
+ πr2
= 2πr (h+r)
VOLUMEVOLUME
 Volume of a cylinder
= Area of base ×
height
= πr2
h
Maths project surface area and volume_by_chirag_jain_ix_a_roll no 17
WHAT IS A RIGHTWHAT IS A RIGHT
CIRCULAR CONE?CIRCULAR CONE?
 In a right circular
cone, the radius
of the circular
base is
perpendicular to
its height.
 Also, Slant Height
l =
Height h
Base
r
Slant Height
l
CURVED SURFACECURVED SURFACE
AREAAREA
l l
2πr
r
Area of sector = Circumference of arc
Area of circle Circumference of circle
Area of sector = 2πr × πl 2
= πrl
2πl
C.S.A. of cone = Area of sector = πrl
TOTAL SURFACETOTAL SURFACE
AREAAREA
 T.S. A. of Cone = C.S.A. + Base Area
= πrl + πr2
= πr (l +r)
l
2
B rπ=
r
VOLUMEVOLUME
 Volume of Cone
= 1 × Volume of Cylinder
3
= 1 × πr2
h
3
Maths project surface area and volume_by_chirag_jain_ix_a_roll no 17
SURFACE AREASURFACE AREA
AND VOLUMEAND VOLUME
 Surface area of sphere = 4 πr2
 Volume of sphere = 4 πr3
3
Maths project surface area and volume_by_chirag_jain_ix_a_roll no 17
SURFACE AREASURFACE AREA
AND VOLUMEAND VOLUME
 C.S.A. of hemisphere = 2πr2
 T.S.A. of hemisphere = C.S.A. + Base Area
= 2πr2
+ πr2
= 3πr2
 Volume of hemisphere = 2 πr3
3
Maths project surface area and volume_by_chirag_jain_ix_a_roll no 17
Maths project surface area and volume_by_chirag_jain_ix_a_roll no 17

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Maths project surface area and volume_by_chirag_jain_ix_a_roll no 17

  • 1. >> 0 >> 1 >> 2 >> 3 >> 4 >> 8
  • 2. >> 0 >> 1 >> 2 >> 3 >> 4 >> 7
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  • 8. >> 0 >> 1 >> 2 >> 3 >> 4 >>
  • 9. >> 0 >> 1 >> 2 >> 3 >> 4 >> THE PRESENTATIO N BEGINS
  • 13.  INTRODUCTION  CUBE  CUBOID  RIGHT CIRCULAR CYLINDER  RIGHT CIRCULAR CONE  SPHERE  HEMISPHERE
  • 14.  Have you ever wrapped a birthday gift? If so, then you've covered the surface area of a polyhedron with wrapping paper.   Have you ever poured a glass of milk? If so, then you've filled the volume of a glass with milk. Not only this, but in day-to-day life, we come across many activities which involve the concept of surface areas and volume.
  • 15.  Surface Area of an object refers to the total area of all its surfaces.  For example : The amount of paper required to wrap a gift gives us an idea of surface area of gift.
  • 16.  Volume of a solid object refers to the amount of space it occupies or contains.  For example : The amount of water a swimming pool can hold gives us an idea of the volume of the swimming pool.
  • 18. SURFACESURFACE AREAAREAIf each edge of cube is a units, its Total surface area = 6a2 sq. units Area of the faces leaving the top And the bottom ones is known as Its L.S.A. (Lateral Surface Area). L.S.A. of cube = 4a2 sq. units
  • 19. VOLUMEVOLUME  Volume of a cube of edge a units is a3 cubic units.
  • 21. TOTAL SURFACETOTAL SURFACE AREAAREA Surface area of a cuboid = 2 × lb Top and bottom + 2 × bh Front and back + 2 × lh Left and right side = 2(lb + bh + lh) h l b
  • 22. LATERAL SURFACELATERAL SURFACE AREAAREA  L.S.A. of cuboid = T.S.A. – Area of top and base = 2(lb + bh + lh)– 2(lb) = 2 (bh + hl) = 2 (l+b) × h
  • 23. VOLUMEVOLUME  Volume of a cuboid = Length × Breadth × Height Or V = l × b × h Where, V = volume l = length, b = breadth h = height
  • 25. WHAT IS A RIGHTWHAT IS A RIGHT CIRCULARCIRCULAR CYLINDER ?CYLINDER ? A cylinder is a right circular cylinder if :  Its base is a circle and  Radius of the base is perpendicular to its height.
  • 26. SURFACE AREASURFACE AREA  C.S.A. of cylinder = Area of rectangular sheet = 2πrh o T.S.A. of cylinder = C.S.A. + Lid area + Base area = 2πrh + πr2 + πr2 = 2πr (h+r)
  • 27. VOLUMEVOLUME  Volume of a cylinder = Area of base × height = πr2 h
  • 29. WHAT IS A RIGHTWHAT IS A RIGHT CIRCULAR CONE?CIRCULAR CONE?  In a right circular cone, the radius of the circular base is perpendicular to its height.  Also, Slant Height l = Height h Base r Slant Height l
  • 30. CURVED SURFACECURVED SURFACE AREAAREA l l 2πr r Area of sector = Circumference of arc Area of circle Circumference of circle Area of sector = 2πr × πl 2 = πrl 2πl C.S.A. of cone = Area of sector = πrl
  • 31. TOTAL SURFACETOTAL SURFACE AREAAREA  T.S. A. of Cone = C.S.A. + Base Area = πrl + πr2 = πr (l +r) l 2 B rπ= r
  • 32. VOLUMEVOLUME  Volume of Cone = 1 × Volume of Cylinder 3 = 1 × πr2 h 3
  • 34. SURFACE AREASURFACE AREA AND VOLUMEAND VOLUME  Surface area of sphere = 4 πr2  Volume of sphere = 4 πr3 3
  • 36. SURFACE AREASURFACE AREA AND VOLUMEAND VOLUME  C.S.A. of hemisphere = 2πr2  T.S.A. of hemisphere = C.S.A. + Base Area = 2πr2 + πr2 = 3πr2  Volume of hemisphere = 2 πr3 3