(Meta 5) ejemplo vectores 2 dev c++
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This document contains code snippets in C programming language for different programs. The first program uses nested for loops to print the number 3 in a triangular pattern. The second program prompts the user to input values into an array and then prints the values. The third program uses a for loop to input values into an array and print the final value of the counter. The last program uses a for loop to print numbers from 0 to the user-input value.
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![#include <stdio.h>
/*
int main() {
int i,j,n;
n =3;
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
if(j<=i)
{
printf("%d",n);
}
}
printf("n");
}
}/*/
/*
int main (){
int num [4];
printf (" valor posicion 0: n");
scanf (" %d ", &num[4]);
printf (" valor posicion 1: n");
scanf (" %d ", &num[1]);
printf (" valor posicion 2: n ");](https://image.slidesharecdn.com/meta5ejemplovectores2devc-140616213548-phpapp01/85/Meta-5-ejemplo-vectores-2-dev-c-1-320.jpg)
![scanf (" %d ", &num[2]);
printf (" valor posicion 3: n");
scanf (" %d ", &num[3]);
printf (" **VALORES: ** n");
printf (" 1- %d n ", num[4]);
printf (" 2- %d n ", num[1]);
printf (" 3- %d n ", num[2]);
printf (" 4- %d n ", num[3]);
}*/
/*
int main (){
int num [5],p;
for (p=0;p<5;p++){
printf ("valorposicion %d ", p);
scanf ("%d", &num[p]);
}
printf ("%d",p);
}
*/
int main (){
int num, n;](https://image.slidesharecdn.com/meta5ejemplovectores2devc-140616213548-phpapp01/85/Meta-5-ejemplo-vectores-2-dev-c-2-320.jpg)
(Meta 5) ejemplo vectores 2 dev c++
- 1. #include <stdio.h> /* int main() { int i,j,n; n =3; for(i=0;i<n;i++) { for(j=0;j<n;j++) { if(j<=i) { printf("%d",n); } } printf("n"); } }/*/ /* int main (){ int num [4]; printf (" valor posicion 0: n"); scanf (" %d ", &num[4]); printf (" valor posicion 1: n"); scanf (" %d ", &num[1]); printf (" valor posicion 2: n ");
- 2. scanf (" %d ", &num[2]); printf (" valor posicion 3: n"); scanf (" %d ", &num[3]); printf (" **VALORES: ** n"); printf (" 1- %d n ", num[4]); printf (" 2- %d n ", num[1]); printf (" 3- %d n ", num[2]); printf (" 4- %d n ", num[3]); }*/ /* int main (){ int num [5],p; for (p=0;p<5;p++){ printf ("valorposicion %d ", p); scanf ("%d", &num[p]); } printf ("%d",p); } */ int main (){ int num, n;
- 3. printf (" Dame el valor de *n*: "); scanf ("%d", &num); for (n=0;n<num;n++){ printf ("%d", n++); } }