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Industrial Engineering Letters                                                                  www.iiste.org
ISSN 2224-6096 (Print) ISSN 2225-0581(Online)
Vol 1, No.4, 2011


              Optimization by Heuristic procedure of Scheduling
                        Constraints in Manufacturing System

                           Bharat Chede1*, Dr C.K.Jain2, Dr S.K.Jain3, Aparna Chede4

1.     Reader, Department of Mechanical Engineering, Mahakal Institute of Technology and Management,

     Ujjain

2.     Ex Principal, Ujjain Engineering College, Ujjain

3.     Principal, Ujjain Engineering College, Ujjain

4.     Lecturer, Department of Mechanical Engineering, Mahakal Institute of Technology, Ujjain

*      Email of the corresponding author       : bharat_chede@rediffmail.com Phone 91-9827587234



Abstract
This article provides an insight for optimization the output considering combinations of scheduling
constraints by using simple heuristic for multi-product inventory system. Method so proposed is easy to
implement in real manufacturing situation by using heuristic procedure machines are arranged in optimal
sequence for multiple product to manufacture. This reduces manufacturing lead-time thus enhance profit.


Keywords: Optimization, Scheduling, Heuristic, Inventory, Layouts


1.    Introduction


      Constraints in industry lead to reduction of profit to industry especially some constraints like budgetary
and space when imposed on system. These constraints has impact on cost incurred in that product basically
considering the scheduling as constraints specially in case when we have to adopt in change in product mix,
demand and design.


2.    Traditional approach


      There are many relations for EOQ


                          Q =     √ 2 Ci .Yi       i = 1,2,3 _ _ _n -----------------   (i)
                         Bi
                     For ith product Ci = order cost per unit
              Yi = demand per unit


                                                         11
Industrial Engineering Letters                                                                                 www.iiste.org
ISSN 2224-6096 (Print) ISSN 2225-0581(Online)
Vol 1, No.4, 2011

          Bi = the stock holding cost per unit per unit time
     There are chances when all n products have to be replenished at same time. If restriction of maximum
capital investment (W) at any time in inventory is active, then (A) is valid if Q (i= 1.2. - - - n) satisfy the
constraints
               n
                           ∑ Vi. Qi      ≤     W            ------------------------------                     (ii)
               i =1


Where V is the value of unit of product            i otherwise Q ( i = 1,2, ---- n)


To satisfy (ii) Lagrange multiplier technique is used to obtain modified Q


                       Q    =     √ 2 Ci .Yi                  i = 1,2,3 _ _ _n     -----------------   (iii)
                   Bi + 2µVi


µ - Lagrange multiplier associated with capital investment constraints




But by these also we may not necessarily get optimality.


The proposed simple heuristic rule for staggering of the replenishments of product under equal order
interval method and provide a simple formula for obtaining the upper limit of maximum investment in
inventory we assume that each product is replenished at equal time interval during common order interval T,
i.e. for n product we order at a time interval of T/n and upper limit of maximum investment in inventory
can be obtained by making following arrangement.
     Arranging the item in descending order of demand of each item                    and its unit value (i.e. max [Vi,Yi] is
for i=I) If INV denote the capital investment required at time (j - 1) T/n j = 1,2, --- n then INVj can be
expressed as


                   n
         INVj          =    T/n ∑        rjk. V k . Y k                           j = 1,2----n
                             k=1
                       rjk = n+k-j        if k ≤ j
                       =    k-j          if k ≥ j


         MLUL = max (INVj) gives upper limit of maximum investment in cycle duration j.


To have exact utilization of invested budget the estimated value of T should be obtained from W = MLUL
Comparison of optimal result by both methods. It is clear that heuristic rule provide better cost performance

                                                               12
Industrial Engineering Letters                                                                 www.iiste.org
ISSN 2224-6096 (Print) ISSN 2225-0581(Online)
Vol 1, No.4, 2011

than Lagrange multiplier method.(Table1)


3.    Numerical example


      Considered the company nearby Indore (India) (Table2) for the Demand rate, order cost, stock holding
cost, Value and EOQ.
Maximum allowable investment W = Rs 15000/- If EOQ used ignoring budgetary constraint, the maximum
investment in inventory would be 17,120/- which is greater than W. To find optimal solution by Lagrange
multiplier technique which when applied gives(Table 3)
Q L1 =      88,   Q L2 =    139,   Q L3 =   98      Total cost =   Rs 3541   when   µ = 0.03
From the result it ensures that heuristic rule performs well. Also the proposed rule in easy to implement in
practice.


3.1    In case of Scheduling as constraints we can classify the Layout as


      •     Liner (single and double row machine layout) (Figure 1)
      •     Loop Layout (Figure 2)
      •     Ladder layout (reduces travel distance)(Figure 3)
      •     The Carousel Layout (Part flow in one direction around loop The Load and unload stations are
            placed at one end of loop)(Figure 4)
      •     The Open Field Layout (Consist of Ladder and Loop)(Figure 5)


Scheduling is considered as Static Scheduling where a fixed set of orders are to be scheduled either using
optimization or priority heuristics also as dynamic scheduling problem where orders arrives periodically.


 Process of Solution for problem
Pi be a partial schedule containing i schedule operations.
Si The set of Schedulable operation at stage i corresponding to given Pi
Pj    The earliest time at which operation j and s could be started.
Q     Earliest time at which operation J, sj could be completed.




4.        Priority Rule Used


      •     SPT (Select operation with minimum processing time)
      •     MWKR (Most work remaining)

                                                       13
Industrial Engineering Letters                                                                       www.iiste.org
ISSN 2224-6096 (Print) ISSN 2225-0581(Online)
Vol 1, No.4, 2011

     •     Random (Select operation at random)


4.1 Algorithm


Step 1 :          Let t=0 assume Pt = {Ǿ}
Step 2 :          Determine q* = min {q}and corresponding machine m* on which q* could be             realized.
Step 3 :       For operation which belongs to S that requires machine m* and satisfy the condition p < q*
               identify an operation according to specified priority add this operation to pi for next stage.
Step 4 :          For each new partial schedule    p t+1 created in step 3 update the data set as follows
                  i)       Remove operation j from Si.
                  ii)      From St+1 by adding the direct successor of operation j from si.
                  iii)     Increment by 1
Step 5     :     Repeat step 2 to step 4 for each      p t+1 created in steps and continue in this manner until all
               active schedules       are generated.
Step 6 :       From To chart is developed from routing data the chart indicated number of parts moves between
               the machines.
Step 7 :        Adjust flow matrix is calculated from frequency matrix, distance matrix and cost matrix.
Step 8 :          From to Sums are determined from the adjusted flow matrix.
Step 9     :     Assign the a machine to it on minimum from sums. The machine having the smallest sum is
               selected. If the minimum value is to sum, then the machine placed at the beginning of sequence.
               If the minimum value is from sum, then machine placed at end of sequence.


5.       Example


           Arrangements of machine are considered for Liner layout, loop layout and ladder layout. The input
data required in inter slot distance load unload distances and unit transportation cost, processing times for
different jobs, processing sequence of jobs on different machines.(Table 4)(Table 5)


     •     Inters lot distance and load, unload matrices for Liner layout (Table 6,7)
     •     Inter slot distance and load, unload matrix for Loop Layout(Table 8,9)
     •     Inter slot Distance and Load, Unload Matrices for Ladder Layout (Table 10,11)


6.   Results
     •     Waiting time of machine (Table 12)
     •     Waiting time for Job (Table 13) Production time for a batch of component = 2600 hrs
     •     Sequence of job manufactured on different machine for minimum production time.(table 14)
     •     Machine order and total cost for different types of layouts (Table 15)


7.   Conclusion



                                                           14
Industrial Engineering Letters                                                                 www.iiste.org
ISSN 2224-6096 (Print) ISSN 2225-0581(Online)
Vol 1, No.4, 2011

    The traditional method for determining optimal order quantities and the optimal reorder points in
multi-product inventory system with constraints are not easy to implement in reality but heuristic rule is not
only easy to implement but also give better result than traditional method. By using heuristic procedure
with scheduling as constraint layout is optimized. The other parameters such as flow time, job sequence to
manufactured, Machine sequence, total transportation cost, Machine and job waiting time are determined.




References


         Brown G.G, Dell R.F, Davis R.L and Dutt R.H (2002) “Optimizing plant line schedules and an
         application at Hidden valley Manufacturing Company”, INTERFACES INFORMS Volume 32
         No.-3,   pp 1-14.


         Oke S.A.,Charles E. and Owaba O.E.(2007) “A fuzzy linguistic approach of preventive
         maintenance scheduling cost optimization”, Kathmandu University Journal of science and
         Engineering and Technology Volume 1 No.3 January pp 1-13


         Osman K, Nagi R. Christopher R.M. (2001 “New Lot sizing formulation for less nervous
         production schedules”, Computers and Operation Research 27, pp 1325-1345.


         Pegels C.C and Watrous C. (2005) “Application of theory of constraints to bottleneck operation in
         manufacturing plant”, Journal of Manufacturing Technology Management. Vol 16 No-03, pp
         302-311.


         Solimanpar.M,Vrat .P and Shankar R,(2004) “ A heuristic          to minimize     make span of cell
         scheduling problem”,    International journal of Production Economics 88,pp 231-241.




First Author. Bharat Chede has received Bachelor’s degree from Amravati University, India and Masters
Degree in Mechanical Engineering (Production Engineering) from Shivaji University, India, He is currently
pursuing PhD from Rajiv Gandhi Proudyogiki Vishwavidyalaya Bhopal, India. He is working as Head of
Department (Mechanical Engineering) at Mahakal Institute of Technology and Management Ujjain India.
His Current area of research is Optimization in manufacturing techniques using fuzzy logics.

                                                     15
Industrial Engineering Letters                                                                 www.iiste.org
ISSN 2224-6096 (Print) ISSN 2225-0581(Online)
Vol 1, No.4, 2011


Second Author. Dr C.K.Jain            Phd in Production Engineering from IIT Rourkee. A renowned
academician, was responsible for making trendsetting transformations during his last stint as Principal,
UEC. Having received a Gold Medal in M.Tech and an award winning research scholar during his PhD. His
Current area of research is Casting methods optimization.


Third Author. Dr S.K.Jain. Phd from APS university Rewa India. He is principal Ujjain Engineering
College Ujjain, India . His current areas of research are Fuzzy logic Technique in Engineering


Fourth Author. Aparna Chede has received Bachelors and Masters Degree in Mechanical Engineering
from Rajiv Gandhi Proudyogiki Vishwavidyalaya Bhopal, India. She is currently working as Lecturer in
Mechanical Engineering at      Mahakal Institute of Technology and Science Ujjain India. Her current areas
of research are Industrial Engineering techniques.



    Method           of         T              Q1                 Q2            Q3            Total Cost
    solution
    Langrange                   ---            145                44           114            Rs 4063
    Multiplier
    Heuristic                 0.108            216                54           108            Rs 3919


                          Table No 1: (Comparison of optimal result by both methods)


         Product(i)                                         1             2              3
         Demand rate (units per year) Y                    2000         1000           1000
         Order cost C (Rs per unit per year)                50            50             50
         Stock holding cost B (Rs Per unit per              16            10             4
         year)
         Value V (Rs per unit)                              80           150             20
         EOQ                                                112          100           158


          Table 2:    (Demand rate, order cost, stock holding cost, value and EOQ.)



            Method of solution           T       Q1          Q2         Q3     Total Cost
            Langrange Multiplier        ---      98          88        139     Rs 3541
            Heuristic                  0.079    158          79         79     Rs 3716




                                                      16
Industrial Engineering Letters                                                                                       www.iiste.org
ISSN 2224-6096 (Print) ISSN 2225-0581(Online)
Vol 1, No.4, 2011

                      Table 3: (Optimal solution by Lagrange multiplier technique)




        Job number        J1            J2              J3            J4                      J5                J6
        Batch size        50            40              60            30                      30                70


                                             Table 4: (Job and Batch Size)


Job   First               Second               Third              Fourth                       Fifth                 Sixth
      Operation           Operation            Operation          Operation                    Operation             Operation
      M/C      Time       M/C       Time       M/C     Time       M/C              Time        M/C     Time          M/C     Time
A     M1       8          M2        7          M3      14         M4               9           M4      3             M4      4
B     M2       10         M3        17         M3      6          M5               13          M4      4             M1      3
C     M4       18         M3        16         M4      11         M1               12          M5      3             M2      2
D     M4       16         M1        7          M2      11         M3               4           M5      4             M4      13
E     M2       12         M2        15         M4      9          M1               11          M4      3             M1      4
F     M4       8          M5        7          M4      9          M1               6           M2      11            M2      12


                            Table 5: (Machines with Operation time)


                           Slots        S1      S2      S3        S4           S5         S6
                           S1           0       4       6         8            10         12
                           S2           4       0       4         6            8          10
                           S3           6       4       0         4            6          8
                           S4           8       6       4         0            4          6
                           S5           10      8       6         4            0          4
                           S6           12      10      8         6            4          0


                                   Table 6: (Inter slot distance for Liner Layout)

           Slots                        S1     S2            S3            S4                 S5            S6
           Load Station                 3      5             7             9                  11            13

           Unload Station               13     11            9             7                  5             3




                                                            17
Industrial Engineering Letters                                                                         www.iiste.org
ISSN 2224-6096 (Print) ISSN 2225-0581(Online)
Vol 1, No.4, 2011


                                  Table 7: (Load Unload Matrices for Liner layout)


                        Slots      S1       S2       S3       S4           S5            S6
                        S1         0        4        6        8            10            12
                        S2         4        0        4        6            8             10
                        S3         6        4        0        4            6             8
                        S4         8        6        4        0            4             6
                        S5         10       8        6        4            0             4
                        S6         12       10       8        6            4             0


                                Table 8: (Inter slot distance for Loop Layout)




                Slots               S1      S2           S3           S4            S5            S6
                Load Station        4       6            8            10            12            14
                Unload              14      12           10           8             6             4
                Station


                             Table 9: (Load Unload Matrices for Loop layout)



                          Slots        S1       S2       S3       S4           S5            S6
                          S1           0        6        8        10           12            14
                          S2           6        0        6        8            10            12
                          S3           8        6        0        6            8             10
                          S4           10       8        6        0            6             8
                          S5           12       10       8        6            0             6
                          S6           14       12       10       8            6             0




                                                         18
Industrial Engineering Letters                                                                                   www.iiste.org
ISSN 2224-6096 (Print) ISSN 2225-0581(Online)
Vol 1, No.4, 2011

                                Table 10: (Inter Slot distance for Ladder Layout)
             Slots                   S1          S2             S3              S4                S5             S6
             Load Station            1           5              7               9                 11             13
             Unload Station          13          11             9               7                 5              1



                               Table 11: (Load unload Matrices for Ladder Layout)



             Machine                        M1             M2          M3                M4            M5            M6
             No                             4              6           6                 8             8             6
             Waiting time in minutes        6              8           6                 8             6             4


                                          Table 12: (Waiting Time of machine)



             Job No                  J1          J2             J3                  J4            J5        J6
             Waiting    time    in   3210        3340           1740                3810          3840      1750
             minutes


                            Table 13: (Waiting time for job)


        M/C No                                             Job Sequence
        M1             J1            J6               J4             J3                      J5             J2
        M2             J2            J1               J4             J5                      J1             J3
        M3             J3            J2               J5             J1                      J4             J4
        M4             J3            J6               J4             J5                      J1             J2
        M5             J6            J2               J4             J1                      J3             J5
        M6             J6            J1               J2             J1                      J5             J1


                            Table 14: (Job Sequence for minimum production time)


Type of Layout         Machine arrangement Sequence                                          Total
                                                                                             Transportation
                                                                                             Cost
Liner                 M4       M6        M1      M5        M2              M1                3370
Loop                  M4       M6        M1      M5        M2              M1                3382
Ladder                M4       M1        M5      M6        M2              M1                6324
Open Field            M4       M1        M5      M6        M1              M1                4212


                                                           19
Industrial Engineering Letters                                                                     www.iiste.org
ISSN 2224-6096 (Print) ISSN 2225-0581(Online)
Vol 1, No.4, 2011


                           Table 15: (Machine order and cost for different layout)



Load           2                       2                            2                    2             Unload 2
2
l                                               1                               1                             1
1                  1 S1               S21           S3         S4         S5                 S6




                           Figure 1 Liner (single and double row machine layout)




                               S1                             S2


               1                 1                        2                 1


Load       1                                                                                  S3
2    1

Load                                                                                          S4
                       2
                   1                                                                 1


                               S6                                   S5




                                                     20

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Optimization by heuristic procedure of scheduling constraints in manufacturing system

  • 1. Industrial Engineering Letters www.iiste.org ISSN 2224-6096 (Print) ISSN 2225-0581(Online) Vol 1, No.4, 2011 Optimization by Heuristic procedure of Scheduling Constraints in Manufacturing System Bharat Chede1*, Dr C.K.Jain2, Dr S.K.Jain3, Aparna Chede4 1. Reader, Department of Mechanical Engineering, Mahakal Institute of Technology and Management, Ujjain 2. Ex Principal, Ujjain Engineering College, Ujjain 3. Principal, Ujjain Engineering College, Ujjain 4. Lecturer, Department of Mechanical Engineering, Mahakal Institute of Technology, Ujjain * Email of the corresponding author : bharat_chede@rediffmail.com Phone 91-9827587234 Abstract This article provides an insight for optimization the output considering combinations of scheduling constraints by using simple heuristic for multi-product inventory system. Method so proposed is easy to implement in real manufacturing situation by using heuristic procedure machines are arranged in optimal sequence for multiple product to manufacture. This reduces manufacturing lead-time thus enhance profit. Keywords: Optimization, Scheduling, Heuristic, Inventory, Layouts 1. Introduction Constraints in industry lead to reduction of profit to industry especially some constraints like budgetary and space when imposed on system. These constraints has impact on cost incurred in that product basically considering the scheduling as constraints specially in case when we have to adopt in change in product mix, demand and design. 2. Traditional approach There are many relations for EOQ Q = √ 2 Ci .Yi i = 1,2,3 _ _ _n ----------------- (i) Bi For ith product Ci = order cost per unit Yi = demand per unit 11
  • 2. Industrial Engineering Letters www.iiste.org ISSN 2224-6096 (Print) ISSN 2225-0581(Online) Vol 1, No.4, 2011 Bi = the stock holding cost per unit per unit time There are chances when all n products have to be replenished at same time. If restriction of maximum capital investment (W) at any time in inventory is active, then (A) is valid if Q (i= 1.2. - - - n) satisfy the constraints n ∑ Vi. Qi ≤ W ------------------------------ (ii) i =1 Where V is the value of unit of product i otherwise Q ( i = 1,2, ---- n) To satisfy (ii) Lagrange multiplier technique is used to obtain modified Q Q = √ 2 Ci .Yi i = 1,2,3 _ _ _n ----------------- (iii) Bi + 2µVi µ - Lagrange multiplier associated with capital investment constraints But by these also we may not necessarily get optimality. The proposed simple heuristic rule for staggering of the replenishments of product under equal order interval method and provide a simple formula for obtaining the upper limit of maximum investment in inventory we assume that each product is replenished at equal time interval during common order interval T, i.e. for n product we order at a time interval of T/n and upper limit of maximum investment in inventory can be obtained by making following arrangement. Arranging the item in descending order of demand of each item and its unit value (i.e. max [Vi,Yi] is for i=I) If INV denote the capital investment required at time (j - 1) T/n j = 1,2, --- n then INVj can be expressed as n INVj = T/n ∑ rjk. V k . Y k j = 1,2----n k=1 rjk = n+k-j if k ≤ j = k-j if k ≥ j MLUL = max (INVj) gives upper limit of maximum investment in cycle duration j. To have exact utilization of invested budget the estimated value of T should be obtained from W = MLUL Comparison of optimal result by both methods. It is clear that heuristic rule provide better cost performance 12
  • 3. Industrial Engineering Letters www.iiste.org ISSN 2224-6096 (Print) ISSN 2225-0581(Online) Vol 1, No.4, 2011 than Lagrange multiplier method.(Table1) 3. Numerical example Considered the company nearby Indore (India) (Table2) for the Demand rate, order cost, stock holding cost, Value and EOQ. Maximum allowable investment W = Rs 15000/- If EOQ used ignoring budgetary constraint, the maximum investment in inventory would be 17,120/- which is greater than W. To find optimal solution by Lagrange multiplier technique which when applied gives(Table 3) Q L1 = 88, Q L2 = 139, Q L3 = 98 Total cost = Rs 3541 when µ = 0.03 From the result it ensures that heuristic rule performs well. Also the proposed rule in easy to implement in practice. 3.1 In case of Scheduling as constraints we can classify the Layout as • Liner (single and double row machine layout) (Figure 1) • Loop Layout (Figure 2) • Ladder layout (reduces travel distance)(Figure 3) • The Carousel Layout (Part flow in one direction around loop The Load and unload stations are placed at one end of loop)(Figure 4) • The Open Field Layout (Consist of Ladder and Loop)(Figure 5) Scheduling is considered as Static Scheduling where a fixed set of orders are to be scheduled either using optimization or priority heuristics also as dynamic scheduling problem where orders arrives periodically. Process of Solution for problem Pi be a partial schedule containing i schedule operations. Si The set of Schedulable operation at stage i corresponding to given Pi Pj The earliest time at which operation j and s could be started. Q Earliest time at which operation J, sj could be completed. 4. Priority Rule Used • SPT (Select operation with minimum processing time) • MWKR (Most work remaining) 13
  • 4. Industrial Engineering Letters www.iiste.org ISSN 2224-6096 (Print) ISSN 2225-0581(Online) Vol 1, No.4, 2011 • Random (Select operation at random) 4.1 Algorithm Step 1 : Let t=0 assume Pt = {Ǿ} Step 2 : Determine q* = min {q}and corresponding machine m* on which q* could be realized. Step 3 : For operation which belongs to S that requires machine m* and satisfy the condition p < q* identify an operation according to specified priority add this operation to pi for next stage. Step 4 : For each new partial schedule p t+1 created in step 3 update the data set as follows i) Remove operation j from Si. ii) From St+1 by adding the direct successor of operation j from si. iii) Increment by 1 Step 5 : Repeat step 2 to step 4 for each p t+1 created in steps and continue in this manner until all active schedules are generated. Step 6 : From To chart is developed from routing data the chart indicated number of parts moves between the machines. Step 7 : Adjust flow matrix is calculated from frequency matrix, distance matrix and cost matrix. Step 8 : From to Sums are determined from the adjusted flow matrix. Step 9 : Assign the a machine to it on minimum from sums. The machine having the smallest sum is selected. If the minimum value is to sum, then the machine placed at the beginning of sequence. If the minimum value is from sum, then machine placed at end of sequence. 5. Example Arrangements of machine are considered for Liner layout, loop layout and ladder layout. The input data required in inter slot distance load unload distances and unit transportation cost, processing times for different jobs, processing sequence of jobs on different machines.(Table 4)(Table 5) • Inters lot distance and load, unload matrices for Liner layout (Table 6,7) • Inter slot distance and load, unload matrix for Loop Layout(Table 8,9) • Inter slot Distance and Load, Unload Matrices for Ladder Layout (Table 10,11) 6. Results • Waiting time of machine (Table 12) • Waiting time for Job (Table 13) Production time for a batch of component = 2600 hrs • Sequence of job manufactured on different machine for minimum production time.(table 14) • Machine order and total cost for different types of layouts (Table 15) 7. Conclusion 14
  • 5. Industrial Engineering Letters www.iiste.org ISSN 2224-6096 (Print) ISSN 2225-0581(Online) Vol 1, No.4, 2011 The traditional method for determining optimal order quantities and the optimal reorder points in multi-product inventory system with constraints are not easy to implement in reality but heuristic rule is not only easy to implement but also give better result than traditional method. By using heuristic procedure with scheduling as constraint layout is optimized. The other parameters such as flow time, job sequence to manufactured, Machine sequence, total transportation cost, Machine and job waiting time are determined. References Brown G.G, Dell R.F, Davis R.L and Dutt R.H (2002) “Optimizing plant line schedules and an application at Hidden valley Manufacturing Company”, INTERFACES INFORMS Volume 32 No.-3, pp 1-14. Oke S.A.,Charles E. and Owaba O.E.(2007) “A fuzzy linguistic approach of preventive maintenance scheduling cost optimization”, Kathmandu University Journal of science and Engineering and Technology Volume 1 No.3 January pp 1-13 Osman K, Nagi R. Christopher R.M. (2001 “New Lot sizing formulation for less nervous production schedules”, Computers and Operation Research 27, pp 1325-1345. Pegels C.C and Watrous C. (2005) “Application of theory of constraints to bottleneck operation in manufacturing plant”, Journal of Manufacturing Technology Management. Vol 16 No-03, pp 302-311. Solimanpar.M,Vrat .P and Shankar R,(2004) “ A heuristic to minimize make span of cell scheduling problem”, International journal of Production Economics 88,pp 231-241. First Author. Bharat Chede has received Bachelor’s degree from Amravati University, India and Masters Degree in Mechanical Engineering (Production Engineering) from Shivaji University, India, He is currently pursuing PhD from Rajiv Gandhi Proudyogiki Vishwavidyalaya Bhopal, India. He is working as Head of Department (Mechanical Engineering) at Mahakal Institute of Technology and Management Ujjain India. His Current area of research is Optimization in manufacturing techniques using fuzzy logics. 15
  • 6. Industrial Engineering Letters www.iiste.org ISSN 2224-6096 (Print) ISSN 2225-0581(Online) Vol 1, No.4, 2011 Second Author. Dr C.K.Jain Phd in Production Engineering from IIT Rourkee. A renowned academician, was responsible for making trendsetting transformations during his last stint as Principal, UEC. Having received a Gold Medal in M.Tech and an award winning research scholar during his PhD. His Current area of research is Casting methods optimization. Third Author. Dr S.K.Jain. Phd from APS university Rewa India. He is principal Ujjain Engineering College Ujjain, India . His current areas of research are Fuzzy logic Technique in Engineering Fourth Author. Aparna Chede has received Bachelors and Masters Degree in Mechanical Engineering from Rajiv Gandhi Proudyogiki Vishwavidyalaya Bhopal, India. She is currently working as Lecturer in Mechanical Engineering at Mahakal Institute of Technology and Science Ujjain India. Her current areas of research are Industrial Engineering techniques. Method of T Q1 Q2 Q3 Total Cost solution Langrange --- 145 44 114 Rs 4063 Multiplier Heuristic 0.108 216 54 108 Rs 3919 Table No 1: (Comparison of optimal result by both methods) Product(i) 1 2 3 Demand rate (units per year) Y 2000 1000 1000 Order cost C (Rs per unit per year) 50 50 50 Stock holding cost B (Rs Per unit per 16 10 4 year) Value V (Rs per unit) 80 150 20 EOQ 112 100 158 Table 2: (Demand rate, order cost, stock holding cost, value and EOQ.) Method of solution T Q1 Q2 Q3 Total Cost Langrange Multiplier --- 98 88 139 Rs 3541 Heuristic 0.079 158 79 79 Rs 3716 16
  • 7. Industrial Engineering Letters www.iiste.org ISSN 2224-6096 (Print) ISSN 2225-0581(Online) Vol 1, No.4, 2011 Table 3: (Optimal solution by Lagrange multiplier technique) Job number J1 J2 J3 J4 J5 J6 Batch size 50 40 60 30 30 70 Table 4: (Job and Batch Size) Job First Second Third Fourth Fifth Sixth Operation Operation Operation Operation Operation Operation M/C Time M/C Time M/C Time M/C Time M/C Time M/C Time A M1 8 M2 7 M3 14 M4 9 M4 3 M4 4 B M2 10 M3 17 M3 6 M5 13 M4 4 M1 3 C M4 18 M3 16 M4 11 M1 12 M5 3 M2 2 D M4 16 M1 7 M2 11 M3 4 M5 4 M4 13 E M2 12 M2 15 M4 9 M1 11 M4 3 M1 4 F M4 8 M5 7 M4 9 M1 6 M2 11 M2 12 Table 5: (Machines with Operation time) Slots S1 S2 S3 S4 S5 S6 S1 0 4 6 8 10 12 S2 4 0 4 6 8 10 S3 6 4 0 4 6 8 S4 8 6 4 0 4 6 S5 10 8 6 4 0 4 S6 12 10 8 6 4 0 Table 6: (Inter slot distance for Liner Layout) Slots S1 S2 S3 S4 S5 S6 Load Station 3 5 7 9 11 13 Unload Station 13 11 9 7 5 3 17
  • 8. Industrial Engineering Letters www.iiste.org ISSN 2224-6096 (Print) ISSN 2225-0581(Online) Vol 1, No.4, 2011 Table 7: (Load Unload Matrices for Liner layout) Slots S1 S2 S3 S4 S5 S6 S1 0 4 6 8 10 12 S2 4 0 4 6 8 10 S3 6 4 0 4 6 8 S4 8 6 4 0 4 6 S5 10 8 6 4 0 4 S6 12 10 8 6 4 0 Table 8: (Inter slot distance for Loop Layout) Slots S1 S2 S3 S4 S5 S6 Load Station 4 6 8 10 12 14 Unload 14 12 10 8 6 4 Station Table 9: (Load Unload Matrices for Loop layout) Slots S1 S2 S3 S4 S5 S6 S1 0 6 8 10 12 14 S2 6 0 6 8 10 12 S3 8 6 0 6 8 10 S4 10 8 6 0 6 8 S5 12 10 8 6 0 6 S6 14 12 10 8 6 0 18
  • 9. Industrial Engineering Letters www.iiste.org ISSN 2224-6096 (Print) ISSN 2225-0581(Online) Vol 1, No.4, 2011 Table 10: (Inter Slot distance for Ladder Layout) Slots S1 S2 S3 S4 S5 S6 Load Station 1 5 7 9 11 13 Unload Station 13 11 9 7 5 1 Table 11: (Load unload Matrices for Ladder Layout) Machine M1 M2 M3 M4 M5 M6 No 4 6 6 8 8 6 Waiting time in minutes 6 8 6 8 6 4 Table 12: (Waiting Time of machine) Job No J1 J2 J3 J4 J5 J6 Waiting time in 3210 3340 1740 3810 3840 1750 minutes Table 13: (Waiting time for job) M/C No Job Sequence M1 J1 J6 J4 J3 J5 J2 M2 J2 J1 J4 J5 J1 J3 M3 J3 J2 J5 J1 J4 J4 M4 J3 J6 J4 J5 J1 J2 M5 J6 J2 J4 J1 J3 J5 M6 J6 J1 J2 J1 J5 J1 Table 14: (Job Sequence for minimum production time) Type of Layout Machine arrangement Sequence Total Transportation Cost Liner M4 M6 M1 M5 M2 M1 3370 Loop M4 M6 M1 M5 M2 M1 3382 Ladder M4 M1 M5 M6 M2 M1 6324 Open Field M4 M1 M5 M6 M1 M1 4212 19
  • 10. Industrial Engineering Letters www.iiste.org ISSN 2224-6096 (Print) ISSN 2225-0581(Online) Vol 1, No.4, 2011 Table 15: (Machine order and cost for different layout) Load 2 2 2 2 Unload 2 2 l 1 1 1 1 1 S1 S21 S3 S4 S5 S6 Figure 1 Liner (single and double row machine layout) S1 S2 1 1 2 1 Load 1 S3 2 1 Load S4 2 1 1 S6 S5 20