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TOPIC
REFLECTION
(2D TRANSFORMATION)
PRESENTED BY:
RITESH VERMA (31401219005)
SUNNY KUMAR SAH (31401219002) Slide 1
CONTENTS
What is Reflection? And some of its example.
Different kinds of Reflection.
Any Questions?
References
Slide 2
Q. What is Reflection?
Reflection is a transformation that produces a mirror image.
• 2D reflection in computer graphics is a kind of rotation where the angle
of rotation is 180degree.
• The reflected object is always formed on the other side of mirror.
• The size of reflected object is same as that of original object.
Slide 3
Examples of Reflection
1 2 3
A microscope uses a mirror to
reflect light to the specimen
under the microscope.
An astronomical reflecting
telescope uses a large parabolic
mirror to gather dim light from
distant stars. A plane mirror is
used to reflect the image to the
eyepiece.
An overhead projector as in
figure uses a concave mirror to
reflect light from the object to
the screen.
Slide 4
Different kinds of Reflection
There are generally 4-5 kinds of reflection
1) Reflection of an object about an x-axis or (line y=0).
2) Reflection of an object about an y-axis or (line x=0).
3) Reflection of an object relative to an axis perpendicular to the xy plane and passing
through co-ordinate origin.
4) Reflection of an object with respect to the line y=x.
5) Reflection of an object with respect to the line y=-x.
Slide 5
1) Reflection of an object about an x-axis or (line y=0).
x
x
y
-y
x-axis
y-axis
Reflection along X-axis: In this kind of Reflection, the value of X is
positive, and the value of Y is negative.
We can represent the Reflection along x-axis by following equation-
Here, For point P1
X1 = X0 and Y1 = –Y0
We can also represent Reflection in the form of matrix–
Homogeneous Coordinate Representation: We can also represent the
Reflection along x-axis in the form of 3 x 3 matrix-
Original
Reflection
0
Slide 6
=
=
Example:-
A triangle ABC A(2,2), B(4,2) and C(4,4) is reflected about X-axis. Find its new co-ordinate of A1, B1 &
C1.
0 1 2 3 4
1
2
3
4
-4
-3
-2
-1
A(2,2)
B(4,2)
C(4,4)
A1(2,-2) B1(4,-2)
C1(4,-4)
Graphical Representation
X1
Y1
= 1 0
0 -1 Y
X
1 0
0 -1 2
2
=
1*2 + 0*2
0*2 + (-1*2)
=
-2
2
=
Solution:-
Here the given triangle ABC is reflected about X-axis.
For A (2,2)
Similarly, For B1 And C1 the points are
B1(4,-2) and C1(4,-4)
A1(2,-2)
y
x
-x
-y
Slide 7
A1 =
x
-x
y y
y-axis
Original
Reflection
x-axis
2) Reflection of an object about an y-axis or (line x=0).
Reflection along Y-axis: In this kind of Reflection, the value of X is
negative, and the value of Y is positive.
We can represent the Reflection along y-axis by following equation-
Here, For point P1
X1 = –X0 and Y1 = Y0
We can also represent Reflection in the form of matrix–
Homogeneous Coordinate Representation: We can also represent
the Reflection along y-axis in the form of 3 x 3 matrix-
0
Slide 8
=
=
1
2
3
4
-4
-3
-2
-1
0 1 2 3 4
-4 -3 -2 -1
A(2,2)
B(4,2)
C(4,4)
B1(-4,2) A1(-2,2)
C1(-4,4)
Example:-
A triangle ABC A(2,2), B(4,2) and C(4,4) is reflected about Y-axis. Find its new co-ordinate of A1, B1 &
C1.
X1
Y1
= -1 0
0 1 Y
X
-1 0
0 1 2
2
=
(-1*2) + 0*2
0*2 + 1*2
=
2
-2
=
Similarly, For B1 And C1 the points are
B1(-4,2) and C1(-4,4)
A1(-2,2)
Solution:-
Here the given triangle ABC is reflected about Y-axis.
For A (2,2)
y
x
-x
-y
Slide 9
A1 =
Graphical Representation
x-axis
y-axis
x
y
-y
-x
Original
Reflection
-y-axis
-x-axis
0
Reflection perpendicular to XY plane: In this kind of Reflection, the
value of both X and Y is negative.
We can represent the Reflection along origin by following equation-
Here, For point P1
X1 = –X0 and Y1 = –Y0
We can also represent Reflection in the form of matrix–
Homogeneous Coordinate Representation: We can also represent
the Reflection though the origin in the form of 3 x 3 matrix-
3) Reflection of an object relative to an axis perpendicular to the xy plane and
passing through co-ordinate origin.
Slide 10
=
=
1
2
3
4
-4
-3
-2
-1
0 1 2 3 4
-4 -3 -2 -1
A(2,2)
B(4,2)
C(4,4)
B1(-4,-2)
A1(-2,-2)
C1(-4,-4)
Example:-
A triangle ABC A(2,2), B(4,2) and C(4,4) is reflected about co-ordinate origin. Find its new co-ordinate
of A1, B1 & C1.
X1
Y1
= -1 0
0 -1 Y
X
-1 0
0 -1 2
2
=
(-1*2)+ 0*2
0*2 +(-1*2)
=
-2
-2
=
Similarly, For B1 And C1 the points are
B1(-4,-2) and C1(-4,-4)
A1(-2,-2)
Solution:-
Here the given triangle ABC is reflected to Origin.
For A (2,2)
-y
-x
x
y
Slide 11
A1 =
Graphical Representation
0 x-axis
y-axis
45
x
x
y
y
Original
Reflection
4) Reflection of an object with respect to the line y=x.
Reflection along with the line: In this kind of Reflection, the
value of X is equal to the value of Y.
We can represent the Reflection along the line Y=X by following
equation-
Here, For point P1
X1=Y0 and Y1=X0
We can also represent Reflection in the form of matrix–
Homogeneous Coordinate Representation: We can also represent the
Reflection along the line y=x in the form of 3 x 3 matrix-
Slide 12
=
=
5
8
9
10
1
2
3
4
0
-y
y
6
7
2
1 5
3 4 x
6 7 8 9 10
-x
A(7,2)
B(10,2)
C(10,5)
C1(5,10)
B1(2,10)
A
1
(2,7)
Example:-
A triangle ABC A(7,2), B(10,2) and C(10,5) is reflected with the respect to the line Y=X. Find its new
co-ordinate of A1, B1 & C1.
X1
Y1
= 0 1
1 0 Y
X
0 1
1 0 2
7
=
(0*7) + (1*2)
(1*7) + (0*2)
=
7
2
=
B1(2,10) and C1(5,10)
A1(2,7)
For A (7,2)
Similarly, For B1 And C1 the points are
Solution:-
Here the given triangle ABC is reflected through line Y=X.
Slide 13
A1 =
Graphical Representation
0
5) Reflection of an object with respect to the line y=-x.
-x
y
-y
x
y-axis
x-axis
-x-axis
-y-axis
p0(x0 , y0)
p1(x1 , y1)
Reflection along with the line: In this kind of Reflection, the
value of Y is equal to the value of -X.
We can represent the Reflection along the line Y=-X by following
equation-
Here, For point P1
X1=-Y0
Y1=-X0
We can also represent Reflection in the form of matrix–
x1
y1
=
0 -1
-1 0
x0
y0
y1 = y0
0 -1 0
-1 0 0
0 0 1
x0
x1
1 1
Homogeneous Coordinate Representation: We can also represent
the Reflection along the line y=-x in the form of 3 x 3 matrix-
Slide 14
5
8
9
10
1
2
3
4
0
-y
y
6
7
-9
-10 -6
-8 -7 -5 -4 -3 -2 -1
-x
2
1 3 4
-2
-6
-5
-4
-3
-1
x
C(4,6)
A(2,9)
B(2,6)
C1(-6,-4)
B1(-6,-2)
Example:-
A triangle ABC A(2,9), B(2,6) and C(4,6) is reflected with the respect to the line Y=-X. Find its new co-ordinate of A1, B1 &
C1.
X1
Y1
= 0 -1
-1 0 Y
X
0 -1
-1 0 9
2
=
(0*7) +(-1*2)
(-1*7)+ (0*2)
=
-2
-9
=
B1(-6,-2) and C1(-6,-4)
A1(-9,-2)
For A (2,9)
Similarly, For B1 And C1 the points are
Solution:-
Here the given triangle ABC is reflected through line Y=-X.
Slide 15
A1 =
Graphical Representation
Any Question?
Slide 16
REFERENCES
https://www.javatpoint.com/
www.geeksforgeeks.org
www.tutorialandexample.com
Slide 17
THANK YOU
Slide 18

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Presentation reflection

  • 1. TOPIC REFLECTION (2D TRANSFORMATION) PRESENTED BY: RITESH VERMA (31401219005) SUNNY KUMAR SAH (31401219002) Slide 1
  • 2. CONTENTS What is Reflection? And some of its example. Different kinds of Reflection. Any Questions? References Slide 2
  • 3. Q. What is Reflection? Reflection is a transformation that produces a mirror image. • 2D reflection in computer graphics is a kind of rotation where the angle of rotation is 180degree. • The reflected object is always formed on the other side of mirror. • The size of reflected object is same as that of original object. Slide 3
  • 4. Examples of Reflection 1 2 3 A microscope uses a mirror to reflect light to the specimen under the microscope. An astronomical reflecting telescope uses a large parabolic mirror to gather dim light from distant stars. A plane mirror is used to reflect the image to the eyepiece. An overhead projector as in figure uses a concave mirror to reflect light from the object to the screen. Slide 4
  • 5. Different kinds of Reflection There are generally 4-5 kinds of reflection 1) Reflection of an object about an x-axis or (line y=0). 2) Reflection of an object about an y-axis or (line x=0). 3) Reflection of an object relative to an axis perpendicular to the xy plane and passing through co-ordinate origin. 4) Reflection of an object with respect to the line y=x. 5) Reflection of an object with respect to the line y=-x. Slide 5
  • 6. 1) Reflection of an object about an x-axis or (line y=0). x x y -y x-axis y-axis Reflection along X-axis: In this kind of Reflection, the value of X is positive, and the value of Y is negative. We can represent the Reflection along x-axis by following equation- Here, For point P1 X1 = X0 and Y1 = –Y0 We can also represent Reflection in the form of matrix– Homogeneous Coordinate Representation: We can also represent the Reflection along x-axis in the form of 3 x 3 matrix- Original Reflection 0 Slide 6 = =
  • 7. Example:- A triangle ABC A(2,2), B(4,2) and C(4,4) is reflected about X-axis. Find its new co-ordinate of A1, B1 & C1. 0 1 2 3 4 1 2 3 4 -4 -3 -2 -1 A(2,2) B(4,2) C(4,4) A1(2,-2) B1(4,-2) C1(4,-4) Graphical Representation X1 Y1 = 1 0 0 -1 Y X 1 0 0 -1 2 2 = 1*2 + 0*2 0*2 + (-1*2) = -2 2 = Solution:- Here the given triangle ABC is reflected about X-axis. For A (2,2) Similarly, For B1 And C1 the points are B1(4,-2) and C1(4,-4) A1(2,-2) y x -x -y Slide 7 A1 =
  • 8. x -x y y y-axis Original Reflection x-axis 2) Reflection of an object about an y-axis or (line x=0). Reflection along Y-axis: In this kind of Reflection, the value of X is negative, and the value of Y is positive. We can represent the Reflection along y-axis by following equation- Here, For point P1 X1 = –X0 and Y1 = Y0 We can also represent Reflection in the form of matrix– Homogeneous Coordinate Representation: We can also represent the Reflection along y-axis in the form of 3 x 3 matrix- 0 Slide 8 = =
  • 9. 1 2 3 4 -4 -3 -2 -1 0 1 2 3 4 -4 -3 -2 -1 A(2,2) B(4,2) C(4,4) B1(-4,2) A1(-2,2) C1(-4,4) Example:- A triangle ABC A(2,2), B(4,2) and C(4,4) is reflected about Y-axis. Find its new co-ordinate of A1, B1 & C1. X1 Y1 = -1 0 0 1 Y X -1 0 0 1 2 2 = (-1*2) + 0*2 0*2 + 1*2 = 2 -2 = Similarly, For B1 And C1 the points are B1(-4,2) and C1(-4,4) A1(-2,2) Solution:- Here the given triangle ABC is reflected about Y-axis. For A (2,2) y x -x -y Slide 9 A1 = Graphical Representation
  • 10. x-axis y-axis x y -y -x Original Reflection -y-axis -x-axis 0 Reflection perpendicular to XY plane: In this kind of Reflection, the value of both X and Y is negative. We can represent the Reflection along origin by following equation- Here, For point P1 X1 = –X0 and Y1 = –Y0 We can also represent Reflection in the form of matrix– Homogeneous Coordinate Representation: We can also represent the Reflection though the origin in the form of 3 x 3 matrix- 3) Reflection of an object relative to an axis perpendicular to the xy plane and passing through co-ordinate origin. Slide 10 = =
  • 11. 1 2 3 4 -4 -3 -2 -1 0 1 2 3 4 -4 -3 -2 -1 A(2,2) B(4,2) C(4,4) B1(-4,-2) A1(-2,-2) C1(-4,-4) Example:- A triangle ABC A(2,2), B(4,2) and C(4,4) is reflected about co-ordinate origin. Find its new co-ordinate of A1, B1 & C1. X1 Y1 = -1 0 0 -1 Y X -1 0 0 -1 2 2 = (-1*2)+ 0*2 0*2 +(-1*2) = -2 -2 = Similarly, For B1 And C1 the points are B1(-4,-2) and C1(-4,-4) A1(-2,-2) Solution:- Here the given triangle ABC is reflected to Origin. For A (2,2) -y -x x y Slide 11 A1 = Graphical Representation
  • 12. 0 x-axis y-axis 45 x x y y Original Reflection 4) Reflection of an object with respect to the line y=x. Reflection along with the line: In this kind of Reflection, the value of X is equal to the value of Y. We can represent the Reflection along the line Y=X by following equation- Here, For point P1 X1=Y0 and Y1=X0 We can also represent Reflection in the form of matrix– Homogeneous Coordinate Representation: We can also represent the Reflection along the line y=x in the form of 3 x 3 matrix- Slide 12 = =
  • 13. 5 8 9 10 1 2 3 4 0 -y y 6 7 2 1 5 3 4 x 6 7 8 9 10 -x A(7,2) B(10,2) C(10,5) C1(5,10) B1(2,10) A 1 (2,7) Example:- A triangle ABC A(7,2), B(10,2) and C(10,5) is reflected with the respect to the line Y=X. Find its new co-ordinate of A1, B1 & C1. X1 Y1 = 0 1 1 0 Y X 0 1 1 0 2 7 = (0*7) + (1*2) (1*7) + (0*2) = 7 2 = B1(2,10) and C1(5,10) A1(2,7) For A (7,2) Similarly, For B1 And C1 the points are Solution:- Here the given triangle ABC is reflected through line Y=X. Slide 13 A1 = Graphical Representation
  • 14. 0 5) Reflection of an object with respect to the line y=-x. -x y -y x y-axis x-axis -x-axis -y-axis p0(x0 , y0) p1(x1 , y1) Reflection along with the line: In this kind of Reflection, the value of Y is equal to the value of -X. We can represent the Reflection along the line Y=-X by following equation- Here, For point P1 X1=-Y0 Y1=-X0 We can also represent Reflection in the form of matrix– x1 y1 = 0 -1 -1 0 x0 y0 y1 = y0 0 -1 0 -1 0 0 0 0 1 x0 x1 1 1 Homogeneous Coordinate Representation: We can also represent the Reflection along the line y=-x in the form of 3 x 3 matrix- Slide 14
  • 15. 5 8 9 10 1 2 3 4 0 -y y 6 7 -9 -10 -6 -8 -7 -5 -4 -3 -2 -1 -x 2 1 3 4 -2 -6 -5 -4 -3 -1 x C(4,6) A(2,9) B(2,6) C1(-6,-4) B1(-6,-2) Example:- A triangle ABC A(2,9), B(2,6) and C(4,6) is reflected with the respect to the line Y=-X. Find its new co-ordinate of A1, B1 & C1. X1 Y1 = 0 -1 -1 0 Y X 0 -1 -1 0 9 2 = (0*7) +(-1*2) (-1*7)+ (0*2) = -2 -9 = B1(-6,-2) and C1(-6,-4) A1(-9,-2) For A (2,9) Similarly, For B1 And C1 the points are Solution:- Here the given triangle ABC is reflected through line Y=-X. Slide 15 A1 = Graphical Representation