Python 1 liners

1st Impression
C Python

int i = 7; i = 7
int j = 11; j = 11

int temp; i, j = j, i
temp = i;
i = j;
j = temp;

1-Liner = 1 Line of Code
JavaScript Array Summation

a = [1, 1, 2, 3, 5, 8, 13];

for(var s=i=0;(b=a[i++])?s+=b:alert(s););

But NOT This Kind of 1 Line!
for(int i = 0; i < 100; i++) { printf
("hellon"); if(i == 42) break; }

Cause this is actually:

for(int i = 0; i < 100; i++) {
printf("hellon");
if(i == 42)
break;
}

Looping w/ List Comprehension
[x**2 for x in range(10)]

output:

[0, 1, 4, 9, 16, 25, 3, 49, 64, 81]

Sanitize w/ Map & Filter
[int(c) for c in '4f3c87' if c.isdigit()]

output:

[4, 3, 8, 7]

Use Shorthand If-Else
-x if x < 0 else x

r = [5, -2, 31, 13, -17]
[-x if x < 0 else x for x in r]

output:

[5, 2, 31, 13, 17]

Go For Functional
OOP doesn't return value!

a = [42, 8, 16, 15, 4, 23]
a.sort()
a.reverse()

Use this instead:

sorted([42, 8, 16, 15, 4, 23])[::-1]

Join Those String
' '.join(['hello', 'world'])

' < '.join(sorted('powerful'))

output:

'e < f < l < o < p < r < u < w'

Zip and Enumerate
[a+b for a, b in zip('hello', 'world')]

output:

['hw', 'eo', 'lr', 'll', 'od']

Hide Input w/ String Formatting
'{0} <3 {2}'.format('i', input(), 'u')

output:

'i <3 u'

Use Lambda
sorted([2, 1, 8, -7], key=lambda x: x**2)

output:

[1, 2, -7, 8]

Go For Combinator
(lambda i: (lambda f, a: f(f, a))(
lambda r, n:
n * (r(r, n-1) if n > 1 else 1),
i))(10)

output:

3628800

Reference
● Python 1-Liners - gist
● Powerful Python One-Liners - wiki.python
● Obfuscated one-liners in Python - effbot
● Stupid lambda tricks - p-nand-q

Python 1 liners

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Python 1 liners