Q=mc t
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This document provides examples of using the heat equation Q=m*c*ΔT to calculate heat (Q), mass (m), specific heat capacity (c), and change in temperature (ΔT). It gives the values for each variable in 7 example problems and shows the calculations to solve for the unknown variable based on the other given values. The heat equation is rearranged as needed in each example to isolate the variable being solved for.
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Q=mc t
- 1. Q=m.c.∆T Where Q= heat in Joules m= mass in grams c= specific heat capacity(J/g.˚c) ∆T=Tf-Ti
- 2. Q1. Q=23,400 J ∆T=14.2˚C C=2.46 J/g ˚C Q=m.c.∆T m=Q/c∆T
- 3. m= 23,400 J____________________________________________ 2.46 J/g ˚C x 14.2˚C m= 6.70 × 102 g
- 4. Q2. Q=255,000 J m=10,000 g C=4.18 J/g ˚C ∆T=Q/mc
- 5. ∆T= 255,000 J 10,000 g 4.18 J/g ˚C _________________________________________ x ∆T= 6.09°C
- 6. Q3. Q=? m=1,000,000 g C=4.18 J/g ˚C ∆T=6.5 ˚C
- 7. Q= 1,000,000 g x4.18 J/g ˚C x6.5 ˚C Q= 2.7 × 104 kJ
- 8. Q4. Q=-783 J m=34.8 g C=2.42 J/g ˚C ∆T=Q/m.c Tf=∆T+Ti
- 9. ∆T= -783 J____________________________________ 34.8 gx 2.42 J/g ˚C ∆T= -9.30 ◦ C Tf= -9.30 ◦ C+22.1◦ C Tf= 12.8 ◦ C
- 10. Q5 Q=? m=1500 g C=4.18 J/g ˚C ∆T=80.7 ˚C
- 11. Q=1500 g x 4.18 J/g ˚C x 80.7 ˚C Q=506 KJ
- 12. Q6 Q=8000 J m=? C=4.18 J/g ˚C ∆T=50 ˚C m=Q/c.∆T
- 13. m= 8000 J_______________ 4.18 J/g ˚Cx 50 ˚C m=38 g
- 14. Q7. Q=250,000 J m=4000 g C=3.5 J/g ˚C ∆T=Q/m.c
- 15. ∆T= 250,000 J_______________ 4000 g x 3.5 J/g ˚C ∆T=17.85◦ C