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By:
Zakaria Elsayed Hasaneen
Teaching Assistant at Faculty of Commerce
Accounting Department (English Section)
Kafrelsheikh University
OR
Section (2)
Graphic Solution of Linear Programming Problems
Grade 4 –Term 2
Zakaria Hasaneen
Zakaria Hasaneen
Zakaria Hasaneen
Graphic Solution of Linear Programming Problems
The straight (1) X1 + 2X2 = 100
(1) Transfer restrictions to equation as follows:
The straight (2) X1 + 5X2 = 150
(2) Determine of two points for each straight:
Can be drawn straight 1 and the straight 2:
3- The joint solution, an area ( A B C D ) shaded.
The objective function is tested at these points, ( A B C D )
- Extreme Points [Points (C)]
‫أنتاج‬ ‫سيتم‬ ‫اذن‬67‫و‬ ‫كرسي‬17‫ربح‬ ‫اكبر‬ ‫تحقيق‬ ‫اجل‬ ‫من‬ ‫طاولة‬(1335)‫المفروضة‬ ‫القيود‬ ‫ظل‬ ‫في‬.
Section 2 :Linear Programming: Graphical method
(1) Transfer restrictions to equation as follows:
The straight (1) 2 X1 +3 X2 =24
The straight (2) 2 X1 + X2 =16
The straight (3) X1 =7
The straight (4) X2 =6
(2) Determine of two points for each straight:
(3)Can be drawn as follows:
(5)Find Extreme Points (C D E)
(4 )The joint solution, an area (A B C D E F) shaded
Section 2 :Linear Programming: Graphical method
Section 2 :Linear Programming: Graphical method
Section 2 :Linear Programming: Graphical method
(1) Transfer restrictions to equation as follows:
Straight (1): 2X1 + 5X2 = 10
Straight (2): 4X1 - X2 = 12
Straight (3): X1 + X2 = 4
(2) Determine of two points for each straight:
Section 2 :Linear Programming: Graphical method
Section 2 :Linear Programming: Graphical method
Section 2 :Linear Programming: Graphical method

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Section 2 :Linear Programming: Graphical method

  • 1. By: Zakaria Elsayed Hasaneen Teaching Assistant at Faculty of Commerce Accounting Department (English Section) Kafrelsheikh University OR Section (2) Graphic Solution of Linear Programming Problems Grade 4 –Term 2 Zakaria Hasaneen Zakaria Hasaneen Zakaria Hasaneen
  • 2. Graphic Solution of Linear Programming Problems
  • 3. The straight (1) X1 + 2X2 = 100 (1) Transfer restrictions to equation as follows: The straight (2) X1 + 5X2 = 150
  • 4. (2) Determine of two points for each straight:
  • 5. Can be drawn straight 1 and the straight 2: 3- The joint solution, an area ( A B C D ) shaded. The objective function is tested at these points, ( A B C D )
  • 6. - Extreme Points [Points (C)] ‫أنتاج‬ ‫سيتم‬ ‫اذن‬67‫و‬ ‫كرسي‬17‫ربح‬ ‫اكبر‬ ‫تحقيق‬ ‫اجل‬ ‫من‬ ‫طاولة‬(1335)‫المفروضة‬ ‫القيود‬ ‫ظل‬ ‫في‬.
  • 8. (1) Transfer restrictions to equation as follows: The straight (1) 2 X1 +3 X2 =24 The straight (2) 2 X1 + X2 =16 The straight (3) X1 =7 The straight (4) X2 =6
  • 9. (2) Determine of two points for each straight:
  • 10. (3)Can be drawn as follows:
  • 11. (5)Find Extreme Points (C D E) (4 )The joint solution, an area (A B C D E F) shaded
  • 15. (1) Transfer restrictions to equation as follows: Straight (1): 2X1 + 5X2 = 10 Straight (2): 4X1 - X2 = 12 Straight (3): X1 + X2 = 4
  • 16. (2) Determine of two points for each straight: