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Physics Helpline
L K Satapathy
Set Theory 3
Physics Helpline
L K Satapathy
Set Theory 3
Question : Let A and B be two sets containing 4 and 2 elements respectively. Then
the number of subsets of the set A  B having at least 3 elements is
Answer :
( ) 219 ( ) 256 ( ) 275 ( ) 510a b c d
 Total number of subsets of (A  B) 8
2 256 
Given : n(A) = 4 & n(B) = 2
 n(A  B) = n(A)  n(B) = 8
We need to find the number of subsets having at least 3 elements
Method : Number of subsets having at least 3 elements
= (Total number of subsets)
– (number of subsets having at most 2 elements)
Physics Helpline
L K Satapathy
Set Theory 3
Correct option = (a)
Number of Subsets having 0 element 8
0 1C 
Number of Subsets having 1 element 8
1 8C 
Number of Subsets having 2 elements 8
2
8.7 28
1.2
C  
 Number of Subsets having at least 3 elements = 256 – 37 = 219 [Ans]
 Number of Subsets having at most 2 elements = 1+ 8 + 28 = 37
Physics Helpline
L K Satapathy
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Set Theory QA 3

  • 1. Physics Helpline L K Satapathy Set Theory 3
  • 2. Physics Helpline L K Satapathy Set Theory 3 Question : Let A and B be two sets containing 4 and 2 elements respectively. Then the number of subsets of the set A  B having at least 3 elements is Answer : ( ) 219 ( ) 256 ( ) 275 ( ) 510a b c d  Total number of subsets of (A  B) 8 2 256  Given : n(A) = 4 & n(B) = 2  n(A  B) = n(A)  n(B) = 8 We need to find the number of subsets having at least 3 elements Method : Number of subsets having at least 3 elements = (Total number of subsets) – (number of subsets having at most 2 elements)
  • 3. Physics Helpline L K Satapathy Set Theory 3 Correct option = (a) Number of Subsets having 0 element 8 0 1C  Number of Subsets having 1 element 8 1 8C  Number of Subsets having 2 elements 8 2 8.7 28 1.2 C    Number of Subsets having at least 3 elements = 256 – 37 = 219 [Ans]  Number of Subsets having at most 2 elements = 1+ 8 + 28 = 37
  • 4. Physics Helpline L K Satapathy For More details: www.physics-helpline.com Subscribe our channel: youtube.com/physics-helpline Follow us on Facebook and Twitter: facebook.com/physics-helpline twitter.com/physics-helpline